# Mathematical Literacy Grade 11 P1 2024 Memo

> Grade 11 Mathematical Literacy Paper 1 memorandum from the North West November Exam 2024, 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/nw-11-mathematical-literacy-p1-mg-nov-2024/ae0fa78a-5a68-401a-82e4-294f9dd69d6c
- Updated: 2026-10-29
- Subject: Mathematical Literacy
- Grade: Grade 11
- Document type: Memorandum
- Year: 2024
- Exam period: North West November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 11

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Mathematical Literacy · Grade 11 · North West November Exam · 2024. Memorandum. Read online or download the PDF.

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### Page 1

PROVINCIAL ASSESSMENT/
                                  PROVINSIALE ASSESSERING

                                         GRADE/GRAAD 11

                          MATHEMATICAL LITERACY P1/
                         WISKUNDIGE GELETTERDHEID V1
                                NOVEMBER 2024
                       MARKING GUIDELINES/NASIENRIGLYNE

                                                                                 MARKS/PUNTE: 100

Symbol/Kode       Explanation/Verduideliking
    M             Method/Metode
    MA            Method with accuracy/Metode met akkuraatheid
    CA            Consistent accuracy/Volgehoue akkuraatheid
     A            Accuracy/Akkuraatheid
     C            Conversion/Herleiding
     S            Simplification/Vereenvoudiging
    RT            Reading from table/a graph/document/diagram/Lees vanaf
                  tabel/grafiek/document/diagram
     SF           Correct substitution in a formula/Korrekte vervanging in formule
     O            Opinion/Explanation/Reasonig/Opinie/Verduideliking/Redenasie
      P           Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen
                  eenhede/verkeerde afronding, ens.
     R            Rounding/Afronding
    NPR           No penalty for correct rounding/Geen penalisasie vir korrekte afronding nie
    AO            Answer only/Slegs antwoord
    MCA           Method with constant accuracy/Metode met volgehoue akkuraatheid
    RCA           Rounding consistent with accuracy/Afronding met volgehoue akkuraatheid

                            These marking guidelines consist of 11 pages./
                             Hierdie nasienriglyne bestaan uit 11 bladsye.

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### Page 2

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 2                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

NOTE:

   If a candidate answers a question TWICE, only mark the FIRST attempt.
   If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the
    solution, mark the crossed out (cancelled) version.
   Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops
    at the second calculation error.
   NOTE: consistent accuracy (CA) does not apply in cases of a breakdown.
   If the candidate presents any extra solution when reading from a graph, table, layout plan and
    map, then penalise for every extra item presented.
   As a general principle, if a candidate has incurred one mistake and there is evidence of sound
    mathematics thereafter, then that candidate should lose one mark only.
   Rounding is an independent mark.
   In order to award the verification/conclusion mark the candidate must have scored at least one
    mark in the calculation preceding the final conclusion.

LET WEL:

   As ‘n kandidaat ‘n vraag TWEE KEER beantwoord, sien slegs die EERSTE poging na.
   As ‘n kandidaat ‘n antwoord van ‘n vraag doodtrek (kanselleer) en nie oordoen nie, sien die
    doodgetrekte (gekanselleerde) poging na.
   Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou
    op by die tweede berekeningsfout.
   LET WEL: volgehoue akkuraatheid (CA) geld nie in die geval van ‘n afbreuk nie.
   Wanneer ‘n kandidaat aflesings vanaf ‘n grafiek, tabel, uitlegplan en kaart geneem en ekstra
    antwoorde gee, penaliseer vir elke ekstra item.
   ‘n Algemene nasienbeginsel is dat indien ‘n kandidaat een fout maak en daarna voortgaan met
    korrekte wiskunde, dat die kandidaat slegs een punt verloor.
   Afronding tel as ‘n afsonderlike punt.
   Ten einde die verifikasie/gevolgtrekking punt toe te ken moes die kandidaat ten minste een
    punt gekry het in die berekeninge wat lei tot die finale gevolgtrekking.

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### Page 3

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 3                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

QUESTION 1/VRAAG 1 [20 MARKS/PUNTE] AO – Full marks
Q/V Solution/Oplossing             Explanation/Verduideliking                                                T/L
1.1.1 5 items A                  2A answer number of items/antwoord                                         F
                                      aantal items                                                           L1
                                                                                                   (2)
1.1.2   September month/maand A                     2A answer month/antwoord maand                         F
                                                                                                             L1
        OR/OF                                         OR/OF

        9th month/9de maand A                       2A answer maand/Antwoord month
                                                                                                   (2)
1.1.3   VAT refers to a consumption tax on                                                                   F
        goods and services levied at each stage                                                              L1
        of the supply chain where value is
        added/BTW verwys na ‘n
        verbruikersbelasting op goedere en
        dienste gehef in elke stadium van die in
        die verskaffing van goedere en dienste        2A answer/antwoord
                                      A                                                          (2)

1.1.4                              15                                                                        F
        VAT/BTW = R186,60 ×              MA
                                   115                2MA multiply with 15 ÷115/                             L1
        VAT/BTW = R23,33913043                            vermenigvuldig met 15 ÷115
        VAT/BTW ≈ R23,24

        OR/OF
                                                      OR/OF
        TOTAL = R186,60 ÷ 1,15 MA
              = R162,2608696                          1MA divide with 1,15/deel met 1,15
              ≈ R162,26
        VAT/BTW = R186,60 – R162,26
                                MA                   1MA subtract/aftrek
        VAT/BTW = R24,34

        OR/OF                                         OR/OF

                                100                   1MA multiply with 100/115 /
        TOTAL = R186,60 ×             MA
                                115                       vermenigvuldig met 100/115
              = R162,2608696
              ≈ R162,26
        VAT/BTW = R186,60 – R162,26
                                MA                   1MA subtract/aftrek
        VAT/BTW = R24,34
                                                                                                   (2)
1.1.5   Paid with cash/Met kontant betaal             2A answer/antwoord                                     F
                                        A                                                        (2)       L1
1.1.6   One hundred eighty-six rand and sixty                                                                F
        cents/Eenhonderd ses en tagtig rand en                                                               L1
        sestig sent A                               2A answer in words/antwoord in woorde
                                                                                         (2)

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### Page 4

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 4                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

1.2.1   Pie chart/                                    2A answer type of graph/antwoord tipe                  D
        Sirkelgrafiekof sektorgrafiek A                grafiek                                             L1
                                                                                           (2)
1.2.2   Romance                                                                                              D
        = 100 – 28 – 20 – 14 – 12 – 8 MA             1MA subtract correct values/aftrek van                 L1
        = 100 – 82                                         korrekte waardes
        = 18% A                                      1A answer % romance/antwoord %
                                                         romanties
                                                                                                   (2)
1.2.3   Most watched = Comedy A                     2A answer/antwoord                                     D
                                                                                                   (2)       L1
1.2.4   P (true-life story)                                                                                  P
        = 0% OR 0,0 OR Impossible                                                                            L1

        W (ware lewensverhaal)
        = 0% OF 0,0 OF Onmoontlik A                 2A answer/antwoord
                                                                                                   (2)
                                                                                                             [20]

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### Page 5

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 5                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

QUESTION 2/VRAAG 2 [31 MARKS/PUNTE]
Q/V Solution/Oplossing                         Explanation/Verduideliking                                    T/L
2.1.1 Litres petrol per month/Liter petrol per                                                                F
      maand                                    1MA divide with R23,25 per ℓ/deel met                         L1
      = R4 500 ÷ R23,25/ℓ MA                       R23,25 per ℓ
      = 193,5483871 litres                     1A answer litre petrol/Antwoord liter
      ≈ 193,55 litres A                          brandstof
                                                                                       (2)
2.1.2 Total groceries per month/Totale         1MA multiply with 4                                           F
      kruideniersware per month                     weeks/vermenigvuldig met 4 weke                          L1
      = R1 150 × 4 weeks MA                   1A answer total groceries/antwoord
      = R4 600 A                                 totale kruideniersware
                                                                                       (2)
2.1.3 Total expenses/Totale uitgawes           CA from QUESTION 2.1.2                                        F
      = R8 400 + R8 200 + R2 100 +                                                                           L3
      R4 600 + R4 500 + R2 000 + R4 850 + 1M adding all expenses/optel van alle
      R1 850 M                                   uitgawes
      = R36 500 CA                            1CA answer total expenses/antwoord
                                                   totale uitgawes
      Amount left over to safe/ Bedrag oor
      om te spaar
      = Income – Expenses
      = R47 000 – R 36 500 M                  1M subtract expenses/trek uitgawes af
      = R10 500 CA                            1CA answer savings/Antwoord spaargeld
                                                                                       (4)
2.1.4 % increase =   2024 − 2023               1SF correct values in fraction/korrekte                       F
                                 × 100
                        2023                       waardes in breuk                                          L2
        𝑅5 000−𝑅4 465                          1M multiply with 100/vermenigvuldig
      =                 SF × 100 M
            𝑅4 465                                 met 100
      = 11,98200828667%                        1RA answer rounded to whole
      ≈ 12% RA                                     number/antwoord afgerond tot
                                                    heelgetel
                                                                                       (3)
2.1.5 Other source of income:                                                                                F
      Earning interest of investment/ Verdien                                                                L4
      rente met belegging O                  2O explanation/verduideliking

           OR/OF
        Mr. Smith can word overtime to earn
        more money/Mnr. Smith kan oortyd
        werk om eer geld te verdien O

            OR/OF
        Mrs. Smith can teach extra classes for
        extra income/Mev. Smith kan estra
        klasse aanbied vir ekstra inkomste
        O

        Any relevant answer                                                                        (2)

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### Page 6

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 6                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

2.2.1   R24 999 in words:                                                                                    F
        Twenty-four thousand, nine hundred                                                                   L1
        and ninety-nine rand/
        Vier-en-twintig duisend,                      2A correct value in words/korrekte
        negehonderderd nege-en-negintig rand             waarde in woorde
        A
                                                                                                   (2)
2.2.2   Ratio nights at Sudwala to Sabie River        1MA correct ratio order/korrekte                       F
        2 : 4 MA                                         verhouding orde                                    L2
        1 : 2 CA                                     1CA simplified ratio/vereenvoudigde
                                                          verhouding
                                                                                                   (2)
2.2.3   ONE other expanse/ander uitgawe:                                                                     F
         Lunch meals that are not included in                                                               L4
          the package/Middagetes wat nie
          ingesluit in die packet nie O      2O ONE other expense/EEN ander
         Other forms of travel in the park       uitgawe
          then road/Ander vorme van Vervoer
          as padvervoer
         Other activities/Ander aktiwiteite
        Name any ONE other expanse/Noem
        EEN ander uitgawe

                                                                                         (2)
2.2.4   Deposits/Deponeer                             1M multiply with 12 months/                            F
        = R5 500 × 12 months/maande M                   vermenigvuldig met 12 maande                        L5
        = R66 000 A                                  1A answer deposits/antwoord deponeer

        Interest earn/Rente verdien
        = R5 500 × 7%                                 1A answer interest earn per month/
        = R385 A                                        antwoord rente verdien per maand
        = R385 × 12 months/maande                     1A answer total interest for the year/
        = R4 620 A                                      antwoord totale rente vir die jaar

        Total after a year/Totaal na ‘n jaar
        = R66 000 + R4 620
        = R70 620 CA                                 1CA total after a year/totale na ‘n jaar

        OR/OF                                         OR/OF
        Interest earn/Rente verdien
        = R5 500 × 7%                                 1A answer interest earn per month/
        = R385 A                                        antwoord rente verdien per maand

        Total per month/Totaal per maand              1M adding deposit plus interest/bytel van
        = R5 500 + R385 M                                deposito by rente
        = R5 885 A                                   1A answer total per month/antwoord
                                                         totaal per maand
        Total after a year/Totaal na ‘n jaar          1M multiply with 12 months/
        = R5 885 × 12 months/maande M                    vermenigvuldig met 12 maande
        = R70 620 CA                                 1CA total after a year/totaal na ‘n jaar
                                                                                               (5)
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### Page 7

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 7                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

2.2.5   Investment 6 months/maande                    CA from QUESTION 2.2.4/CA vanaf                        F
                      0,092                           VRAAG 2.2.4                                            L3
        = R30 000 ×           MA
                        2                             1MA multiply with correct interest rate
        = R1 380 A                                        per half year/vermenigvuldig met
        = R30 000 + R1 380                                 korrekte rentekoers halfjaarliks
        = R31 380 A                                  1A answer interest 6 months/antwoord
                                                         rente 6 maande
        Investment 12 months/maande                   1A answer balance after 6 months/
                      0,092                              antwoord saldo na 6 maande
        = R31 380 ×
                        2
        = R1 443,48
        = R31 380 + R1 443,48                         1A answer balance after 12 months/
        = R32 823,48 A                                  antwoord saldo na 12 maande

        Total of both investments/Totaal vir
        beide beleggings
        = R70 620 + R32 823,48                        1CA answer total of both investments/
        = R103 443,48 CA                                 antwoord total beleggings

        Travel cost for 4 people/Reiskoste vir 4
        mense
        = R24 999 × 4 OR/ R103 443,48 ÷ 4 1A answer cost for 4 people/antwoord
        = R99 996        OF = R25 860,87 A      koste vir 4 mense

        ⸫ Her claim is correct, because the
        travel cost will be R99 996 and the
        investments will be R103 443,48, thus
        they will have enough money for the
        vacation by R3 447,48./
        Haar bewering is korrek, want die
        reiskoste beloop R99 996 en die
        beleggings sal R103 443,48 wees, dus
        sal hulle genoeg geld het vir die
        vakansie met R3 447,48. O                    1O conclusion/gevolgtrekking
                                                                                                   (7)
                                                                                                             [31]

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### Page 8

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 8                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

QUESTION 3/VRAAG 3 [28 MARKS/PUNTE]
Q/V Solution/Oplossing             Explanation/Verduideliking                                                T/L
3.1.1 4th fastest/4de vinnigste                                                                               D
      = Henricho Bruintjies RT   2RT read from table/aflees van tabel                                      L1
                                                                                                   (2)
3.1.2   Arrange/Rangskik                                                                                     D
        1) 14 May 1986                                                                                       L2
        2) 03 April 1992
        3) 15 July 1992
        4) 16 July 1993
        5) 21 September 1993             RT          1RT correct dates/korrekte datums
        6) 26 September 1995             A           1A correct descending order/korrekte
        7) 12 May 1998                                   dalende orde
        8) 27 February 2000
        9) 01 February 2001
        10) 19 December 2003
                                                                                                   (2)
3.1.3   Modal place of birth/Modale plek van                                                                 D
        geboorte                                      2A answer modal place of birth/antwoord                L1
        = Pretoria A                                   modale geboorte plek
                                                                                           (2)
3.1.4   Average (mean) / Gemiddeld                                                                           D
        = Sumtotal ÷ amount of numbers                                                                       L3

        09,919 =
        09,82+09,86+09,87+09,89+09,93
         +09,94+09,94+ 𝑨 +09,98+10,01                 1SF substitute formula/vervang formule
                                      SF
                      10
                 89,24 + 𝑨
        09,919 =             S                       1S simplification/vereenvoudiging
                      10
        09,919 × 10 = 89,24 + A                       1MA changing the subject of the
        99,19 = 89,24 + A                                  formula/verander die onderwerp
        99,19 – 89,24 = A                MA               van die formule
        09,95 seconds = A A                          1A answer A/Antwoord A
                                                                                                   (4)
3.1.5   Range = biggest – smallest/                                                                          D
        Omvang =grootste – kleinste                                                                          L2
                          MA                         1RT correct values/korrekte waardes
        Range = 10,01 sec – 09,82 sec RT             1MA subtract values/trek waardes af
        Range = 0,19 seconds CA                      1CA answer range/antwoord omvang
                                                                                                   (3)

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### Page 9

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 9                                     NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

3.2.1   Gauteng medals in total/medalje in            1M adding three values/tel drie waardes                D
        totaal                                           bymeakaar                                           L1
        = 17 + 23 + 29 M                             1CA answer total medals USA/Antwoord
        = 69 CA                                          totale medaljes
                                                                                            (2)
3.2.2   Difference/Verskil NW – Free State            1RT correct values/korrekte waardes                    D
        = 18 – 9 RT M                               1M subtract values/waardes aftrek                      L2
        = 9 CA                                       1CA answer difference/antwoord verskil
                                                                                            (3)
3.2.3   Western Cape % bronze medals/                                                                        D
        Wes-Kaap % brons medaljes                     1MA correct fraction values/korrekte                   L2
                  25                                      waardes in breuk
        =                 MA × 100 M
            25+18+20                                  1M multiply with 100/vermenigvuldig
            25                                           met 100
        =
            63
        = 39,68253968%
        = 39,68% CA                                  1CA answer %/antwoord %
                                                                                                   (3)
3.2.4   P (provinces more than 20 gold)/                                                                     P
        W (provinsies meer as 20 goud)                1A numerator/noemer                                    L2
          2 A                                        1A denominator/teller
        =                                             1RCA answer decimal number – rounded
          9 A
        = 0,222222222                                       to two decimal places/antwoord
        = 0,22 RCA                                         desimale getal – afgerond tot twee
                                                            desimale plekke
                                                                                            (3)
3.2.5   Limpopo total 2024 = 6 + 6 + 4                                                                       D
        Limpopo total 2024 = 16                                                                              L4

        % growth/% groei
            𝑛𝑒𝑤−𝑜𝑙𝑑               𝑛𝑢𝑤𝑒−𝑜𝑢
        =               × 100 /             × 100     1MA correct values/korrekte waardes
                 𝑜𝑙𝑑                𝑜𝑢
            16−8                                      1M multiply with 100/vermenigvuldig
        =              MA × 100 M                       met 100
             8
        = 100% A                                     1A answer % increase/antwoord %
                                                         gestyg
        ⸫ The claim is valid/Die bewering is
        geldig O                                     1O conclusion/gevolgtrekking

        OR/OF                                         OR/OF

        Total medals 2024 = 6 + 6 + 4 = 16 A         1A total medals 2024/totale medaljes
        8 × 50% = 4 M                                   2024
        8 + 4 = 12 A                                 1M multiplied with 50%/vermenigvuldig
        16 is more than 12 (50% growth)                   met 50%
                                                      1A answer added value/answer
        ⸫ The claim is valid/Die bewering is             vermeerderde waarde
        geldig O                                     1O conclusion/gevolgtrekking
                                                                                           (4)
                                                                                                             [28]

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### Page 10

QUESTION 4/VRAAG 4 [21 MARKS/PUNTE]
Q/V Solution/Oplossing                   Explanation/Verduideliking                                   T/L
4.1.1 Opening balance – 1st day amounts/                                                               F
      Openingsaldo – 1ste dag bedrae     1M subtract debit amounts/aftrek debiet                      L2
      = R42 952,19 – R2 100 – R8 800 M       bedrae
      – R6,00 – R6,00 M                 1M subtract transactions costs/aftrek
      = R42 952,19 – R10 912                  transaksiekoste
      = R32 040,19 A                    1A answer balance/antwoord saldo
                                                                               (3)
4.1.2 Transaction cost/Transaksiekoste   CA from QUESTION 4.1.1/CA vanaf                              F
      = 1,15% × R1 150 MA               VRAAG 4.1.1                                                  L3
      = R13,225                          1MA multiplying correct values (1,15%
      ≈ R13,23 A                               and R1 150)/vermenigvuldig
                                                 korrekte waardes (1,15% en
      Balance – 2nd day amounts/                 R1 150)
      Saldo – 2de dag bedrae             1A answer transaction cost/Antwoord
      = R32 040,19 – R1 150 – R13,23 M      transaksiekoste
      = R32 040,19 – R1 163,23           1M subtracting 2nd day amounts/trek 2de
      = R30 876,96 CA                       dag bedrae af
                                         1CA answer balance/Antwoord saldo
                                         [Accept: R30 876,97 if rounded only at
                                         the end]
                                                                                            (4)
4.2.1   P (loan factor more than 19,00)/                                                              P
        W (leningsfaktor meer as 19,00)                                                               L2
            3 A                                 1A numerator/noemer
        =                                        1M denominator/teller
            7 A
                                                 1R answer % - rounded to whole number/
        = 42,85714285%                              antwoord % - afgerond tot heelgetal
        ≈ 43% R                                                                      (3)
4.2.2   Loan amount = selling price – deposit/                                                        F
        Leningsbedrag = Verkoopprys –                                                                 L2
        deposito                                 1M subtracting deposit/trek deposito af
        = R198 000 – R29 700 M                  1A answer loan amount/antwoord
        = R168 300 A                               leningsbedrag
                                                                                        (2)
4.2.3   Monthly payment                          CA from QUESTION 4.2.2/CA vanaf                      F
        = loan amount ÷ 1 000 × loan factor      VRAAG 4.2.2                                          L3
        = R168 300 ÷ 1 000 × 25,60 
        = R4 308,48                             1SF substitute formula/vervang formule
                                                 1A answer monthly payment/antwoord
        Total monthly payment                       maandelikse paaiement
        = R4 308,48 + R65,00 admin
        = R4 373,48 CA                          1CA answer total monthly payment/
                                                     antwoord totale maandelikse
                                                     paaiement
                                                                                            (3)

Copyright reserved/Kopiereg voorbehou                           Please turn over/Blaai om asseblief

### Page 11

Mathematical Literacy/P1/Wiskundige Geletterdheid/V1 11                              NW/November 2024
                                 Grade 11 – Marking Guidelines/Nasienriglyne

4.2.4   Total repayment/Totale terugbetaling          CA from QUESTION 4.2.3/CA vanaf            F
        = Deposit + monthly payments                  VRAAG 4.2.3                                L4
        = R29 700 + (R4 373,48 × 48 MA)              1MA multiply months with repayment/
        = R29 700 + R209 927,04 M                         vermenigvuldig maande met
        = R239 627,04 CA                                  terugbetaling
                                                      1M adding deposit/bytel van deposito
        Interest/Rente                                1CA answer total repayment/antwoord
        = total repayment – selling price                  totale terugbetelaing
        = R239 627,04 – R198 000 M                   1M subtract selling price/aftrek
        = R41 627,04 CA                                 verkoopsprys
                                                      1CA answer interest amount/antwoord
        ⸫ His statement is correct, his interest          per maand
        will be more than R40 000/Sy stelling is
        korrek, sy rente sal meer as R40 00
        wees O                                  1O conclusion/gevolgtrekking
                                                                                           (6)
                                                                                                 [21]
                                                                               TOTAL/TOTAAL:     100

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