# Mathematical Literacy Grade 10 P2 2019 Memo (Eng)

> Grade 10 Mathematical Literacy Paper 2 memorandum from the North West November 2019 (English), 7 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/nw-gr-10-maths-lit-p2-eng-memo-nov-2019/0f824f72-ac8e-4f92-9366-2403aca9b880
- Updated: 2026-09-27
- Subject: Mathematical Literacy
- Grade: Grade 10
- Document type: Memorandum
- Year: 2019
- Exam period: North West November
- Paper: 2
- Curriculum: CAPS
- Pages: 7

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## About this document

Mathematical Literacy · Grade 10 · North West November · 2019. Memorandum, 7 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                        PROVINCIAL ASSESSMENT

                                     GRADE 10

                        MATHEMATICAL LITERACY P2

                                 NOVEMBER 2019

                             MARKING GUIDELINES

MARKS: 75

      Codes      Explanation
       M         Method
       MA        Method with Accuracy
       CA        Consistent Accuracy
        A        Accuracy
        C        Conversion
        D        Define
        J        Justification/Reason/Explain
        S        Simplification
       RT        Reading from a table OR a graph OR a diagram OR a map OR a plan
        F        Choosing the correct formula
       SF        Substitution in a formula
        O        Opinion
        P        Penalty, e.g. for no units, incorrect rounding off, etc.
        R        Rounding Off
       AO        Answer only
      NPR        No penalty for rounding off OR omitting units

                       These marking guidelines consist of 6 pages.
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Mathematical Literacy/P2                      2                          NW/November 2019
                               NSC– Grade 10 – Marking Guidelines

  KEY TO TOPIC SYMBOL:
  F = Finance; M = Measurement; MP = Maps, Plans and other
  Representations DH = Data Handling; P = Probability
  QUESTION 1 [12 MARKS]

   Q                              Solution                              Explanation           Topic
                                                                                               &
                                                                                              Level
  1.1.1    Purchases for the month                      M         2M Adding purchases         F
           = 476,00 + 135,50 + 99,50 + 77,50 + 129,50 + 57,00       1A Total purchases         L2
           = R975,00 A                                                                (3)
  1.1.2                                                            1M Divide by 12             F
           Interest per month = 0,31 M
                                   12                                                           L3
                               = 0,025833333 A                     1A Monthly interest
           Interest on outstanding amount
           = 0,025833333× 1215,80 M                                1M Multiply by
           = R31,40816667                                           1215,80
           ≈ R31,41 CA                                             1CA Interest amount
                                     OR
                                31                                 1M Multiply by
           Interest payable = 100 × 1215,80 M                      1215,80
                               376 M                               1A Annual interest
                           =                                        1M Divide by 12
                             12 M
                           ≈ R31,41 M                              1CA Interest amount
                                                                                       (4)
  1.1.3                 327,34  MA
                                                                    1MA Numerator and           F
           Percentage = 1636,71 × 100% M                            denominator                 L2
                                                                    1M Multiply by 100
                       = 19,9998778 %                               1CA Percentage (3)
                       = 20 % CA
  1.2      It cannot be said with certainty, because the days of the                            P
           week are not given in the graph.O                      2O Opinion         (2)     L4

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        Mathematical Literacy/P2                          3                             NW/November 2019
                                           NSC– Grade 10 – Marking Guidelines

QUESTION 2 [23 MARKS]

Q               Solution                                               Explanation                         Level
2.1.1                                                                                                       MP
                                     24                                1RT Total nr
                Number of screws =      
                                     6                                1M divide by nr of chair
                                   = 4 A
                                                                       1A answer                    (3)     L2
                  RT            RT                                                                    MP
2.1.2           Chair seat and stretcher                               1 RT chair
                                                                       seat
                                                                       2A stretcher                 (3)     L2
         AAAA

                                                                                                            M
2.1.3                                                                  1A multiply by 42
          Area = 41 × 42 cm  
                                                                       1A answer
         = 1772 cm2 
                                                                       1A unit                              L3
                                                                                                    (3)
2.2                                                                                                          M
(a)      94 + 2 × 1                                                   2D explanation
         = 96 cm 
(b)       42 + 2 × 1                                                   1A multiply by 10
         = 44 cm                                                      1A answer
                                                                                                    (4)     L3
          Dimension = 96 × 44 = 4224
2.3       The screw got a hole in the back where you fit the           2A explanation                      M
         Allen key to fasten or loosen the screw.                                                 (2)    L2
2.4.1     Material needed = 6 × 1,1                                   1A multiply by 1.1m                 M
                           = 6,6 m                                    1 A answer

                                                                                                     (2)    L2

2.4.2                                                                  1A Multiplication                    F
                Cost of material needed = 6,6 × R64,50                1A answer
                                        = R450,70
                                                                                                     (2)
                                                                                                            L2
2.4.3           Labour = 6 × R75                                      1M × R75                             F
                         = R450,00                                    1A answer
                Total cost = (R450,00) + R425,70                      1Madding
                           = R875,70                                  1A answer                     (4)    L3

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Mathematical Literacy/P2                        4                          NW/November 2019
                                 NSC– Grade 10 – Marking Guidelines

QUESTION 3 [23 MARKS]

   Q                                Solution                              Explanation            Topic
                                                                                                  &
                                                                                                 Level
  3.1      Guests to invite         = 112 – 2 M                     1RD Number of seats         MP
                                    = 110 guests CA                 1M Subtract 2               L3
                              OR                                      1CA Number of
                              13 x 8 = 104 + 6                        guests           (3)
                                     = 110

  3.2      For easy movement.  A                                    2O Reason                    MP
           OR                                                                                      L4
           Uncomfortable to sit on the short side. A
           Accept any other logical reason.                                              (2)
  3.3                           A                                     1A Pass dance floor          MP
           Walk pass the dance floor, pass the podium and turn        1A Direction                 L4
           left. A 
           OR
           Accept any other logical explanation.                                           (2)
  3.4      Probability of guest sitting at table with even number                                  P
                                                                                                   L4
           = 1 M
             7                                                        1CA Answer to 3
           = 0,142857142                                              decimal places   (2)
           = 0,143  CA                                               Answer must not be
                                                                      greater than 1

  3.5      Floor Area of hall = length × width                                                     M
                               = 16 m × 12 m SF                      1SF Substitution             L4
                               = 192 m2                            1CA Floor Area
           Area of Dance floor = 1 × 192 m2                          1M × by 1÷4
                                    4                                 1CA Area of dance
                                  = 48 m2                            floor
                                                                                          (4)
  3.6      Hiring of the venue:                                       CA from 3.1.1                 F
           R6 500,00                                                1M R6500                      L4
           Draping and décor: R7 750,00                              1M R7750
           Cost for DJ = R350 × 7 hours                              1CA Cost for DJ
                       = R2 450 CA                                   1MA 350 × 100 and
           Catering = (R350 × 100 guests) + (R200 × 12) MA           200 × 13
                    = R35 000 + R2 400                               1CA
                    = R37 400 CA

           Total cost
           = R6 500,00 + R7750 + R2450 + R37 400 M                   1M Adding all values
           = R54 100  CA                                             1CA Total cost

           Statement invalid  MA                                     1O Invalid
                                                                                        (10)
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        Mathematical Literacy/P2                      5                             NW/November 2019
                                       NSC– Grade 10 – Marking Guidelines

 QUESTION 4 [18 MARKS]
Q         Solution                                                          Explanation                   Level

4.1.1     25; 29; 30; 30; 32; 35; 35; 38; 56; 56; 58; 58; 58; 67; 67; 70; 1A correct central values
          74; 76; 84; 85 M                                               1M dividing

                      56  58                                               1CA conclusion
          Median =              M
                         2

          = 57% A                                                                                        L3

                                                                                                  (3)

4.1.2      Range = 85% – 25% M                                             1M subtracting min and
                 = 60% CA                                                  max values
                                                                            1CA solution
                                                                                                 (2)        L2

4.1.3      Mode = 58%  A
                                                                            2A Correct mode        (2) L3

4.2.1     P = 0 RT                                                         1A Read
                                                                            from table
          Q = 6 RT                                                        2A Read                         L2
                                                                            from table
                                                                                                  (2)

4.2.2             M      M                                                  1M writing probability
                                                                            1M multiplying by
                 7 × 100                                                  100
          P=
                                                                            1CA answer
                 20                                                                                         L2
                                                                                                  (3)
             = 35%CA

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Mathematical Literacy/P2                            6                                                  NW/November 2019
                                     NSC– Grade 10 – Marking Guidelines

 Q       Solution                                                                                          Explanation      Level

 4.2.3                 NUMBER OF LEARNERS PER LEVEL
                      7
                      7
                      6
                      6               
                                       CA
                      5
                       5                                                                                   1CA correct

          FREQUENCY
                      4                                                                                    plotting of
                       4                                                           A                      L2
                      3
                      23                                                                                   1CA correct
                                                                                                           plotting of
                      12                                                                                   L3
                                                   CA
                      01                                                                                   1A correct

                           Level 1   Level 2     Level 3       Level 4   Level 5   Level 6   Level 7
                                                                                                           plotting of
                      0
                                                                                                           L6

                                                           LEVEL
                                                            LEVEL
                                                                                                                      (3)      L3
                   A
 4.2.4   Share = 3 of R500                                                                                 1A using
                 5                                                                                         ratio
               = R300 A                                                                                    1A
                                                                                                           simplifying
                                               R300
         Each learner’s share =
                                          2
                                                                                                           1CA answer
                                     = R150 A
                                                                                                           (3)                 L4

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Mathematical Literacy/P2                            7                                          NW/November 2019
                                     NSC– Grade 10 – Marking Guidelines

PROVINCIAL ASSESSMENT MATHEMATICAL LITERACY P2
GRADE 10 PAPER 2

QUESTION NO.                                                        MEASUREMENT                  DATA HANDLING       PROBABILITY
                                                          FINANCE                 MAPS/PLANS
                LEVEL 2    LEVEL 3         LEVEL 4

1.1.1          3                                         3
1.1.2                      4                             4
1.1.3          3                                         3
1.2.1                                      2                                                                          2
TOTAL          6           4               2             10         0             0                                   2
2.1.1          3                                                                  3
2.1.2          3                                                                  3
2.1.3          3                                                    3
2.2                        4                                        4
2.3            2                                                    2
2.4.1          2                                                    2
2.4.2          2                                         2
2.4.3                      4                             4
TOTAL          15          8                             6          12            5              0                  0
3.1                        3                                                      3
3.2                        2                                                      2
3.3                                        2                                      2
3.4                                        2                                                                        2
3.5                        4                                        4
3.6                                        10            10
TOTAL                      9               14            10         4             7              0                  2
4.1.1                      3                                                                     3
4.1.2          2                                                                                 2
4.1.3                      2                                                                     2
4.2.1          2                                                                                 2
4.2.2          3                                                                                 3
4.2.3          3                                                                                 3
4.2.4                                      3                                                     3
TOTAL          10          5               3             26         15            12             18                 4

GRAND          31          26               19             26       15            12             18                   4
TOTAL
TOTAL 75
%              41       35                 25       40%             31%   11%                    15%    4%
FINANCE        MEASUREMEN                  MAPS/PLANS               DATA 25% ±                   PROBABILIT
35% ± 5%       T 20% ± 5%                  15% ± 5%                 5%                           Y MIN 5%

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