# Mathematics Grade 11 P1 North West November 2025 QP & Memo

> Grade 11 Mathematics Paper 1 question paper and memo from the North West November Exam 2025, 22 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/nw-maths-grade-11-november-2025-p1-and-memo/9cb054c0-ec05-449a-b8c9-7f098d5b8a9f
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2025
- Exam period: North West November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 22

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## About this document

Mathematics · Grade 11 · North West November Exam · 2025. Question paper and memorandum, 22 pages. Read online or download the PDF.

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### Page 1

[oor POW IMOAMED TLONT STATMMOL EPI STCS. COM ns
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| education |
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i Department: i
i Education i
i North West Provincial Government ‘
i REPUBLIC OF SOUTH AFRICA i
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i ‘ MATHEMATICS P1 i i
4 " TY] 4
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| MARKS: 150 i
| TIME: 3 hours
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i This question paper consists of 9 pages and 1 information sheet. ‘
i Copyright reserved Please turn over i
Beane Treen cavers CrP UEr ER ruOREG Orava RE TRUER RH RFORP SDN > PEP PIN PS R RRDNRPIOSE

### Page 2

Mathematics/P1

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2 NW/November 2025
Grade 11

INSTRUCTIONS AND INFORMATION

Read the following instructions carefully before answering the questions.

1

2;

10.

This question paper consists of NINE questions.
Answer ALL the qu sstions.

Number the answers correctly according to the numbering system used in this question
paper.

Clearly show ALL caleulations, diagrams, graphs, etc. that you have used in determining
your answers.

Answers only will NOT necessarily be awarded full marks.

You may use an approved scientific calculator (non-programmable and non-graphical),
unless stated otherwise.

If necessary, round off answers to TWO decimal places, unless stated otherwise.
Diagrams are NOT necessarily drawn to scale.
An information sheet with formulae is included at the end of the question paper.

Write neatly and legibly.

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3

Mathematics/P1 NW/November 2025
Grade 11
QUESTION 1
1.1 Solve for x:
Ld x? -11y=-24 GB)
1.1.2 5x2—x—80 (correct to TWO decimal places) (3)
1:13 42 >x? Hx (4)
4. 10 1
1.1.4 5 =
a x -6 x42 (6)
1.2 Solve for x and y simultaneously:
2x-y-1=0 and x?—2xy+2x-y’? =0 (6)
1.3 Given: kx +5x+k=0.
For which integer values of k will the roots of the equation be rational? (4)
1.4 Calculate the value of x, without using a calculator.
x= 30+ 30+ 30+ ¥30+ 30+...
(5)
[31]
QUESTION 2
2.1 Simplify fully, without using a calculator:
273 3.9"
2 x-2 (3)
2.2 Solve for x, without the use of a calculator:
3
221 5 =-8 (2)
2.2.2 4°-9.2* =-8 (6)
y+
2.3 If it is given that: = 1796" , calculate the values of xand y. (5)
[16]

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Mathematics/P1 NW/November 2025
Grade 11

QUESTION 3

Given the finite linear pattern: 1; 3; 53; .... 3 119
Sol Determine T, , the formula for the n term of the pattern. (2)
3.2 Determine the 20" t ; of the pattern. (2)
33 Determine the a3 f terms in the pattern. (2)
3.4 Hence, determine the number of terms in the following pattern:

(0/110 -3:10:5:10:...:10: 119: 00 (2)

3.5 The linear pattern: 1; 3; 5; .... forms the row of first differences of a quadratic

number pattern. Q,,, term 99 of the quadratic pattern, is 9632. Determine the value
of Q,,, term 98 of the quadratic number pattern.

QUESTION 4
Consider the quadratic sequence: —7; —22; —35; —46; ...

4.1 Write down the fifth term of the sequence.
4.2 Determine T, , the n" term of the quadratic sequence.

4.3 Which term of the sequence has a value of 29?

4.4 Determine which two consecutive terms of the quadratic sequence differ with 29.

(3)
[11]

()
(4)

(4)

(3)
[12]

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Mathematics/P1 NW/November 2025
Grade 11
QUESTION 5
. 4
Given: f(x) =——~ +1
x+2
5.1 ns of the asymptotes of /.
52 ercept of f.
5.3 itercept of /.
5.4 f . Clearly label ALL the intercepts with the
(3)
5.5. Write down the domain of /. (2)
5.6 Determine the equation of the axis of symmetry of f in the form y=mx+c,
for m<0. (3)
[13]

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Mathematics/P1 NW/November 2025

Grade 11

QUESTION 6

Sketched below is the graph of g(x) = a.b* + q. The graph of g cuts the x —and
y —axis at (1;0) and (0;—4) respectively. The line y =—8 is the asymptote of g.

6.1 Write down the value of q¢. (1)
6.2 Determine the values of a and b. (4)
6.3 Write down the range of g. (2)

6.4 Determine the equation of k, if k obtained when g is reflected about the x —axis
and then shifted 2 units to the right.

Write your answer in the form of k(x) =b* + p. (4)
[11]

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Mathematics/P1 NW/November 2025
Grade 11
QUESTION 7
Sketched below are the graphs of g(x) =—-x-5 and f(x)=x° +6x+5.
e Dis the turning point of /.
e E and F are the y=intercepts of f and g respectively.
e Aand C are x —intereepts of f.
e Aisalso the x — intercept of g.
71 Calculate the co-ordinates of D, the turning point of /. (3)
7.2 Calculate the length of:
7.2.1 EF (2)
7.2.2 AC (3)
73 The graphs intersect at A and B.
7.3.1. Determine the co-ordinates of B. (4)
7.3.2 Hence, determine the values of ¢ for which the equation
(x+t)? +6(x+t)+5=-(x+1t)-5 has ONE positive and ONE
negative root. (2)
74 It is further given that MN is parallel to the y —axis between A and B, with M
a point on the graph of g and N a point on the graph of /.
7.4.1. Write down the length of MN in terms of x. (2)
7.4.2 Determine the maximum length of MN. (2)
7.4.3 Hence, or otherwise, find the values of k , for which f(x) +k = g(x)
will have non-real roots. (2)
1:5 Use the graph to determine for what value(s) of x, will f(x).g(x) <0 (2)
[22]

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Mathematics/P1 NW/November 2025
Grade 11
QUESTION 8
8.1 Lethabo has TWO investment option offers:

¢ Option A: 8,2% p.a. compounded daily (365 days per year)

¢ Option B: 8,3% p.a. compounded monthly

8.1.1 Calculate the effective interest rate of Option A. (2)

8.1.2 Which investment option is better for Lethabo to take? Justify your
answer with the necessary calculations. (2)

8.2 Sam wins R300000 in a lottery and decides to invest the full amount in to buy a
car for each of his two sons when they turn 21.
e His first son, Peter, turns 21 exactly 2 years after the investment was made.
On Peter’s 21" birthday, Sam withdraws R175 000 to buy Peter a car.

¢ The investment earns 9% p.a, compounded quarterly for the first four years.

« After that, the interest rate changes to 8.5% p.a, compounded monthly.

¢ The second son turns 21 six years from Sam’s initial investment.

8.2.1. How much money will Sam have available at the end of six years, when
his second son turns 21? (5)

8.2.2 The average inflation rate over this period is 8% p.a. Would Sam be fair
and consistent towards his two sons if the same amount calculated in
QUESTION 8.2.1 is used for his second son's car? Justify your answer
with the necessary calculations. (4)

8.2.3. Peter sells his car after 4 years for R79 120. What is the annual rate of
depreciation, if calculated using the reducing balance method? (4)

[17]

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Mathematics/P1 9
Grade 11

QUESTION 9

9.1 Baobab High School has 100 Grade 12 learners. Of these, 35 take Mathematics,
30 take Accounting, and 20 take both subjects.

9.1.1. Are the events "taking Mathematics” (M) and "taking Accounting” (A)
mutually exelusive events? Motivate your answer.

9.1.2 Are the events "taking Mathematics” (M) and "taking Accounting” (A)
independent? Justify your answer with the appropriate calculations.

9.1.3. Draw a Venn-diagram representing the above information.
9.1.4. Use the Venn-diagram to determine P((not M) or A).

9.2 A bag contains a total of 25 balls, which are red or blue. The exact number of

each colour is unknown. However, it is known that the probability of drawing a

red ball, setting it aside, and then drawing another red ball is =

Determine how many red and how many blue balls are in the bag.
(Hint: Let the number of red balls be x.)

TOTAL:

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NW/November 2024

(2)

(4)
(3)
(2)

(6)
[17]

150

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Mathematics/P1 NW/November 2025

Grade 11

INFORMATION SHEET: MATHEMATICS GR11

ee be? -4ac

2a

A=P(l+ni) A= P(l-i)"

M % +X Ni +Y2
2° 2

y=mx+ YY, =mM(x-x,)

inddne: 2. 222” a? =b?
sinA sinB_ sinC

+c? —2be.cos A

area ABC = sab. sinC

= tit
n

P(A)= ra) P(A or B) = P(A) + P(B) — P(A and B)

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MARKS/PUNTE: 15

PCC UReCeP OOOO OCOCOCOUCOCOUOCO CCC e CPE Pee eee eee ee ee
e

See eee eee EERE ORO O ROR U POOR ORE EEO E RRO R ECR EEE

prwwmmmnmmmnwwwwwnn nn PYLON OAIE FLOM STAMMNOTEPNYSTCS. CONT 0

education

Department:

Education

North West Provincial Government
REPUBLIC OF SOUTH AFRICA

PROVINCIAL ASSESSMENT/

PROVINSIALE ASSESSERING

[ GRADE 11/GRAAD 11 |

, a \ ie he *
a MATHEMATICS P1/WISKUNDE V1 "
“ NOVEMBER 2025 :
" MARKING GUIDELINES/NASIENRIGLYNE "
ll 1"
. “«

0

These marking guidelines consist of 12 pages.
Hierdie nasienriglyne bestaan uit 12 bladsye.

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Mathematics P1/Wiskunde V1 2
Grade/Graad 11 — Marking Guidelines /Nasienriglyne

NW/November 2025

NOTE:

e Ifacandidate answered a question TWICE, only mark the FIRST attempt.
¢ Consistent accuracy applies in ALL aspects of the marking guideline.

LET WEL:

5
e Indien ’n kandidaat *n

e Volgehoue akkuraathei
toegepassing.

g TWEE keer beantwoord het, sien slegs die EERSTE poging na.
DEURGAANS op ALLE aspekte van die nasienriglyne van

QUESTION/ VRAAG 1

1.1.1 x? — 11x =-24 Y standard form/stdvorm
x? =1ix+ 24=0

* (x —8)(«— 3) =0

Answer only: 3/3 ¥ factors/faktore

¥ both answers/beide antwe

x =8 or |ofx=3 (3)
1.1.2 5x*-x-8=0
aye Pen. rounding (only | mark) 7 sabstitation
~(-1)+y (-1)?-4(5)(-8) Answer only: 3/3
25) VY each answ/elke antw (3)
«x= 1,37 or| of x= -1,17
T,b3

42>x7 +x
x? 4+x%+42<0
(x+7)(x-6) <0

Y standard form/vorm

Y critical values
7 6 kritiese waardes
vv answer/antw
-7<x<6

OR/OF

42>x? +x

-x?-x+42>0
(x+7)(6-—x) <0

—7<x<6

Y standard form/vorm
Y critical values
kritiese waardes

vv answer/antw

(4)

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Mathematics P1/Wiskunde V1 3

Grade/Graad 11 — Marking Guidelines /Nasienriglyne

NW/November 2025

Integer values for which A is perfect square:
Heelgetalle waarvoor A ‘n volkome vierkant is: k =0; +2

OR/OF

Answer only: 0/4

1.1.4
4 10 1
x -4 x? -x-6 x+2
4 0
(x=2)(x+2) (x-3)(x+2) (x +2) vv factors/faktore
A(x —3) —10(x=2) = (x-3)(x-2) v¥ x LCM/KGV
4x-12-1042¢ 20 x? —5x4+6 (eliminating denominator)
x? 4x-250/ ¥ standard form
(x +2)(x= )) =0 | Y factors/faktore
x=—2) gt or/of x=1 F answerlante (6)
1.2 25 — PT — Oereeeerscey
x? -2xyt+2x-y? Y y subject/onderwerp (3
pH 2s equation)
sub. equ. (3) into equ. (2) Y substitution
x? —2x(2x—1)+2x—(2x-1)? =0
= Ax + xt Da Ax" + Ax gala Y standard form/std vorm
-7x? +8x-1=0
Tx* -8x+1=0
(1x-1)(x-1) =0 Y factors/faktore
x= L or/of x=1
7 Y both x-values/beide x-w
1 5
= {>) =L= a a Aa 2()-1=1 Y both y-values/beide y-w
6
2™ mistake: BD ©)
Last mark independent of # mistakes
Leading to linear: Max. 2/6
13 ke +5x+k=0
A=b’ —4ac Y substitution (5)? — 4(k)(k)
= (5)? —4(k)(k
(5) ( Mk) 425-442
=25-4k?

v A Perfect square

“k=0; £2

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Mathematics P1/Wiskunde V1 4

Grade/Graad 11 — Marking Guidelines /Nasienriglyne

NW/November 2025

kx? +5x+k=0
A2=0 and Ais perfectsquare Vv (5) —4(k\(k) > 0
b4acie0 V (5—2k)(5 + 2k) >0
(5)’ —4(k)(k) > 0
25-4k? >0 pF tA eee. KER
(5 —2k)(5 +2k)s 23
es! “k='0; £2
~<ncdle
2 4ai7 (4)
k=0;442 |
1k 20; Bim
14 : iin Y square both sides/kwadreer
Y substitution of ‘’ x”’
x= is0+ {30+ 30+ V¥30+ ¥30+...
¥ standard form/stdvorm
a =30+ 1304304, 30+ 304+ 30+... factors
x? =304+x V¥x=6 x#-5
x’? -x-30=0 (5)
(x -6)(x +5) =0 Answer only: 0/5
x=6; x#-5
[31]
QUESTION/VRAAG 2
2d Y Factorize/faktoriseer
2P33.2") _ 2421=3.28271 _ 2427 =3.24j ¥simpl & + exp/vereenv &
2° a a e207? +eksp
3-3 i v 26 (3)
we AG
1 2
4
3
221 | 2 __g
s Answer only: 2/2 Y power/mag 5
3 3

v -32 (2)

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Mathematics P1/Wiskunde V1 5 NW/November 2025
Grade/Graad 11 — Marking Guidelines /Nasienriglyne
222 4° 9.2" =-8 v 4*=2
2?* 9.2" 4+8=0 Y standard form/std vorm
(2* -8)(2* -1)=0 Y factors/faktore
2° =8=2' orfof 2*=1=2° Y both equation/beide vgl
x=3 or/of $= ven
eel (6)
PB}
37 ~
aa D5 * Y prime bases/priem
od A grondtalle
(2)3.3)"" = (2)7.8)s" Y exponential laws/ekspwette
5= 5 ne Y equating exponents/ eksp =
2 ¥x=-2
x=-2
vy =-2 (5)
yt+l=—x
y+1=+(2)
2
y=-2
[16]
QUESTION/VRAAG 3
3.1 13: 35: Sse, 119
T, =dn+c=2n+e v 2n
1=2(l)+e VY c=-l
c=-1=> T, =2n-1 2)
3.2 Tyg = 2(20) -1=39 Y substitution
7 Answer only: 2/2
v 39 (2)
3.3 =2n- Y substituti
tinal Answer only: 2/2 substation
n=60 ¥n=60 (2)
3.4 10; 1; 10; 3; 10; 5; 10; ... ; 10; 119; 10. v +61
Original sequence/oorspronklike ry: 13335; .... 3119 Vv 121 (2)

Number of terms in the combined sequence/aantal terme
in gekombineerde reeks: 60 +61 =121

Answer only: 1/2

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Mathematics P1/Wiskunde V1 6

NW/November 2025

Grade/Graad 11 — Marking Guidelines /Nasienriglyne

3.5 Ty, = 2(98) -1=195 Y substitution T,, = 2(98) —1
Qys = 9632 —195 = 9437 Vv 195
Y 9437 @)
5 [11]
QUESTION/VRAAG 4
4.1 y —7 ; —22; -35; -46; ...
IstD/leV: ©» ‘-15 ; -13 ; -11
2ndD/2eV: 2 2
Ts=— 55 vo -55 (1)
4.2
2a=2 Answer only: 1/4
a=1 Va=l
3a+b=-5
3(l) +b =-15 bani
b=-18
a+b+c=-7
1+-18+c=-7 ¥ c=10
c=10 YT, =n* -18n+10 (4)
T, =n’ -18n+10
a T, =n? -18n +10 =29 Vn’ —18n +10 = 29
n> —18n-19=0 Y standard form/std vorm
(n-19)(n+1)=0 Y factors/faktore
n=19 n#-l
Vslegs n=19 n¥-l1 (4)

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Mathematics P1/Wiskunde V1 7 NW/November 2025
Grade/Graad 11 — Marking Guidelines /Nasienriglyne
44 ¥2n-17
—15; —13; -11....
2n-17 =29 Y substitution 2n —17 = 29
n=23 Yanswer/antw T,, &T,; (3)
BetweenT,, and T,,
OR/OF ~~
Tate oa my y
(n +1)? —18(1 + 1)+10-(n? -18n +10)=29
n? +2n4+1—18n-18+10—n? +18n-10 = 29
2n-17=29 +
n=23
Between T,, and T,,
[12]
QUESTION/VRAAG 5
5.1 x =-2 and/en y=1 v¥ each answer/elke antw
(2)
$.2 v
f(0)= as +1=3 «.(0; 3) NB must be coordinates BRaEH ERENT @
+
Moet koGrdinate wees
5.3 vy=0
0= 4 +1 ¥
x+2 Vvx=-6
-x-2=4
x=-6 @)
5.4 nly ¥ both intercepts/beide
H afsnitte
¥ both asymptotes /beide
(03) asimptote
ee. a aren; Y shape/vorm
(6:0) \ 29)
@)
5.5 x#-2,xeER ¥x#-2 VxeER
Answer only: 2/2 (x # —2)
or/of OR/OF
x € (—00;-2) or/of (-2; 0) ¥v each()/elke hakie (2)

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Mathematics P1/Wiskunde V1 8 NW/November 2025
Grade/Graad 11 — Marking Guidelines /Nasienriglyne
5.6 y=-xt+e (-2;)) v m=-l
= ¥ subs (—2; 1)
Len re Answer only: 3/3 Y equation/vgl
c=-l
GB)
y=-x-l
i [13]
QUESTION/VRAAG 6 _
1 x
6.1 q=-8 ¥q=-8 (dl)
6.2 -~4=ab°-8 Y substitution (0; — 4)
=4 ¥ a=4
a Y substitution (1; 0)
g(x) =4.b* -8 Answer only: 2/4
0=45'-8 “p=2
b=2
(4)
g(x) = 4.2" -8
63 Ye 8, YER Answer only: 2/2 (y >-8) vy>-8vyeR
Q)
64 k(x) = -g(x-2)

k(x) =-4.2°? +8
A(x) =-27.2"? +8
k(x) =-2" +8

Answer only: 4/4

¥-4&+8

Y exponent x—2

¥ exponential laws/eksp wette
Y answer/antw

(4)

[11]

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Mathematics P1/Wiskunde V1 9 NW/November 2025
Grade/Graad 11 — Marking Guidelines /Nasienriglyne
QUESTION/VRAAG 7
Y
3
Ss {2} x
uM
B
D F
i
7A Vv x=-3
vib eam Y substitution: /(-3)
SE3)=C3y #6(-3)45=-4 ot 5p
D(-3; -4) (3)
72.1 E(0; 5) & F(O; —5) VY E&F
EF = 5 — (—5) = 10 units/eenhende v answer/antw
(2)
7.2.2 |For/Vir A & C:x?+6x+5=0
(x +5)(x+ 1) =0 v y=0
X,=—-5 orlof x¢=-1 Y x=-5 & x=-l
AC = —1— (—5) = 4 units/eenhende
v AC=4
@)
731 ge) =f) Y equating/gelykstel
—x-5=x°+6x45
x? +7x+10=0 Y factors/faktore
Orb Ae? Y choose x = —2 /kies x = -2
x, =-5 x, =-2
Ye = 8(-2)=-(-2)-5=-3 Yvya3 (4)
B(-2; -3)
132. -5<t<—2 Y interval
Y notation/notasie (2)
TAL | MN= g(x) — f(x) =-x-5—(a? + 6x45) ¥ a(x)— £0)
v /antw
=~»? _7x=10 answer
Q)
TA2 ae Vx=-3,5
x= BO -3,5
2(-1) 2 P
Vo—=
Max.=—(-3,5)? — 7(-3,5) —10 = - = 2,25 4 aes
(2)
743 9 v Vanswer/antw
k>—
4 (2)

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Mathematics P1/Wiskunde V1 NW/November 2025
Grade/Graad 11 — Marking Guidelines /Nasienriglyne
1S k>-1 or/of k=-5 Vvk>-1
Vvk=-5 (2)
[21]

QUESTION/VRAAG 8 _ >

Tt

Y substitution in correct

8.1.1 , = 6
1 ent = (a rs: formula
. 4 082) 365 Vig 9
As 1+ iogp =(1 +22)” = 1,085445813 i= 854% (2)
igre = 0,085445813 = 854%
‘ 7° 12 a ty
812 | Bt Figg = (14+ 2%)” = 1,086231401 —
¥B (2)
ie¢p = 0,086231401 = 8,62%
- Bis better/beter
8.2.1 To Ti T2 T3 T4 Ts To
300 000 (175 000) 6
¥ 300000, 1+ 22
9% p.a. comp quat 35% p.a. c.month 4
Money from investment/Geld van belegging: 0.085)!
A=P(1+i)" «(140% }
16 24
A= 300004 + 1) ( _ } 0.09.
4 12 175004 + oe)
0,09)'(, 0,085)" \
= 75009 + oe ( + oe 7
4 12 Ay « 0085)
1+——
= R259 652,50 12
OR/OF V R259 652,50 o/of
8
v
AtT,: A= 300004 + | —175000 = 183449,34 ,
sooonr{ 1+ °°) —175000
0,09)°(, 0,085)"
AtT; : A=18344gay{14+ 7 ic = } ¥ 183449 34
= R259 652,50 8
v1 8349.41 + a”)
24
“( ‘ ass)
12
V R259 652,50 (5)

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### Page 21

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Mathematics P1/Wiskunde V1 11
Grade/Graad 11 — Marking Guidelines /Nasienriglyne

NW/November 2025

8.2.2 A= P(i+i)" vi & n indep. of formula
A = 175000(1 + 0,08)*
= 238 085,57 ¥ substitution in correct
Difference = 259 652,50 — 238 085,57 = R21 566,93 formula
Not fair, younger brother gets effectively more Y¥ R238 085,57
Nie regverdig nie, jonger broer kry effektief meer Y conclusion/gevolgtrekking
(4)
8.2.3 A=P(Q=i)” ¥ substitution in correct
formula/subst in regte form
79 120 = 175 000(1 — i)#
79120 © ei) y 19120 =(1-i)'
175000 175000
4/ 79120 .
Py Ree va 7120 a -
175000 (2s
- t= 0,180003389 = 18%
Y answer/antw (4)
[17]
QUESTION/VRAAG 9
9.1.1 | No, M and A are NOT mutually exclusive/ Nee, M en A is NIE VY No/Nee
onderling uitsluitend nie
¥ reason/rede
b P(M dae a tozee
cause P(M and A) = Too Ee (2)
9.1.2 = BS.xgy 80 —
P(M) x P(A) = 100 * 100 ~ 0,105 GED g AD! ¥ 0,105
100 100
P(M and A) = 0,2 v¥ 0,2
0,2 + 0,105
- Mand Aare not independent events/nie onafhanklik nie v . .
conclusion/gevolgtrekking
(4)
M A v 15
9.1.3 Cu) 55 ¥ 10
v55
(3)

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Mathematics/Wiskunde/P1/V1 12 NW/November 2025
Grade/Graad 11
Marking Guidelines / Nasienriglyne

9.1.4 , v 85
P(M’ or Ay = 20410455 _ 85 _17 _o95
100 100 20 Y answer/antw
OR/OF OR/OF
P(M’ or A) = P(M’)+ P(A)— P(M’ and A) = 65 + 30 10 _ 0,85 | “ Substitution in correct
100 100 100 formula
OR/OF Answer only: 2/2 Y answer/antw
P(M/ or A) = 1 — P(Mand A’) = 1-—~ = 0,85 OR/OF
(aa Y substitution in correct
formula
Y answer/antw (2)
9.2 | Let numberr of red balls be = x/ Stel aantal rooi balle = x x x-l
- 25 24
PR = Bh
25 24 60 ll
2 Y prod = —
x “Kot po 60
600 60 “¥ fa
-—x-110=0 actors/faktore
(x-11)(x +10) =0 v 11 red balls/rooi balle
x=l1 x#-10 ¥ 14 blue balls/b/ou balle.
11 red balls/rooi balle and 14 blue balls/blou balle. (6)
Answer only: 0/6
[17]
TOTAL: 150
TOTAAL : 150

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