# Mathematics Grade 12 P2 North West Mock 2019 Memo (English)

> Grade 12 Mathematics Paper 2 memorandum from the North West Mock Exam 2019 (English), 21 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/nw-maths-p2-memo-afr-and-english-september-2019/ce9babf4-e279-46d8-83af-7588bdcc1138
- Updated: 2026-09-27
- Subject: Mathematics
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2019
- Exam period: North West Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 21

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## About this document

Mathematics · Grade 12 · North West Mock Exam · 2019 · English. Memorandum, 21 pages. Read online or download the PDF.

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## Matching paper and memo

- [NW MATHS P2 ENGLISH SEPTEMBER 2019](https://www.hlayiso.com/library/nw-maths-p2-english-september-2019/f2f23402-6726-460e-bb8f-16840aaabbcc) — QP · 2019 · Eng

## Document text

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### Page 1

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                                        NATIONAL
                                   SENIOR CERTIFICATE/
                                        NASIONALE
                                    SENIOR SERTIFIKAAT

                                         GRADE/GRAAD 12

                               MATHEMATICS P2/WISKUNDE V2

                                          SEPTEMBER 2019

                         MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 150

                             This marking guideline consist of 18 pages./
                             Hierdie nasienriglyne bestaan uit 18 bladsye.

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 Mathematics P2/Wiskunde V2                                 2                              NW/September 2019
                                         NSC/NSS – Marking Guidelines/Nasienriglyne

 NOTE:
   · If a candidate answers a question TWICE, only mark the FIRST attempt.
   · If a candidate has crossed out an attempt of a question and has not redone the question,
      mark the crossed out version.
   · Consistent accuracy applies in ALL aspects of the marking memorandum. Stop marking at
      the second calculation error.
   · Assuming answers/values in order to solve a problem is NOT acceptable.

 NOTA:
   · As ‘n kandidaat ‘n vraag TWEE KEER beantwoord, merk slegs die EERSTE poging.
   · As ‘n kandidaat ‘n antwoord van ‘n vraag doodtrek en nie oordoen nie, merk die
      doodgetrekte poging.
   · Volgehoue akkuraatheid word in ALLE aspekte van die nasienriglyne toegepas.
      Hou op nasien by die tweede berekeningsfout.
   · Aanvaar van antwoorde of waardes om ‘n probleem op te los, word NIE toegelaat nie.

 QUESTION/VRAAG 1

1.1     k + 70 = 80                                                                    ü    k + 70 = 80
        \ k = 10                                                                                                   (1)
1.2     80 - 7 = p     OR / OF        63 + 10 = p                                      ü    73
        \ p = 73                      \ p = 73                                                                     (1)
1.3         75 ´ 2 + 105 ´16 + 135 ´ 28 + 165 ´17 + 195 ´10 + 225 ´ 7                  ümidpoints/
        x =                                                                            middelwaardes
                                        80
            11940                                                                      ü ¸ 80
          =
              80
                          Answer only: Full Marks                                      üanswer/antwoord
        \ x = 149, 25
                                                                                                                   (3)
1.4.1   x + s = 186,89                                                                 ümethod/metode
        s = 37, 64             Answer only: Full Marks                                 üanswer/antwoord
                                                                                                                   (2)
1.4.2   q = x - sx
        q = 149, 25 - 37, 64
        q = 111, 61                                                                    üanswer/antwoord
                                                                                                                   (1)
1.5     value of / waarde van m = 3 seconds / sekondes
        average time elapsed of day 2 will be 3 seconds less /                         üm=3
        gemiddelde tydsverloop van dag 2 is 3 sekondes min der                         ü xday / dag 2 = 146, 25
        xday/ dag 2 =146, 25

                                                                                                                   (2)
                                                                                                                  [10]

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Mathematics P2/Wiskunde V2                                 3                               NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 2

2.1      (68 ; 19)                                                                   ü (68 ; 19)
                                                                                                              (1)
2.2      yˆ = a + bx                                                                 ü a = 7,35
         a = 7,35 and / en b = 0,98                                                  ü b = 0,98
                                                                                     ü equation/
         \ yˆ = 7,35 + 0,98 x                                                        vergelyking
                                                                                                          (3)
2.3       yˆ = 7,35 + 0,98(83)                                                       ü substitute 83 into
          yˆ = 88, 69%                                                               eq. / vervang 83 in
                                                                                     vgl.
                                                                                     ü 88,69             (2)
         OR / OF
         yˆ = 88,35%     (calculator / sakrekenaar )                                 üü 88,35%

                                                                                                              (2)
2.4      r = 0.96                                                                    ü r = 0.96
         \ Very strong positive correlation / Baie Sterk positiewe
         korrelasie                                                                  üVery strong /
                                                                                      Baie sterk

                                                                                                              (2)
2.5      If the data points were to be plotted on a scatter plot diagram,
         the new plotted points will be shifted downwards with the                   üNew data points and
         same constant value. Hence the line of best fit will also shift             line of best fit shifted
         downwards with the new plotted points, but the slope of the                 downwards/Nuwe
         line will remain unchanged. Therefore it has NO influence on                datapunte en paslyn
         the gradient/                                                               word afwaarts geskuif
         As die datapunte op ‘n spreidiagram geplot moet word, sal die
         nuwe datapunte afwaarts geskuif word met dieselfde konstante                üNo influence on
         waarde. Vervolgens sal die paslyn ook saam met die nuwe                     gradient/Geen invloed
         datapunte afwaarts skuif, maar die helling van die lyn sal                  op helling
         onveranderd bly. Dus sal dit GEEN invloed op die helling hê
         nie.                                                                                                 (2)

                                                                                                         [10]

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Mathematics P2/Wiskunde V2                                 4                              NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne
                                                        y   R(1; 6)
QUESTION/VRAAG 3

                                                                  S

                       P(–5; 1)

                                                       O
                               L                 D                                           x

                                                                                     Q(7; –2)

3.1      x = –5                                                               ü x = –5
                                                                                                              (1)
3.2             -2 - 6                                                        üMethod/Metode
          mQR =
                 7 -1
                -8
              =
                6
                 4                                                            üAnswer/Antwoord
              =-
                 3                                                                                    (2)
3.3       PS ^ QR                                                             ü
         \ mPS ´ mQR = - 1                                                    mPS ´ mQR = - 1 [ PS ^ QR ]
                 3
         \ mPS =                                                                         3
                 4                                                            ü mPS =
          Through the point / Deur die punt ( -5;1)
                                                                                         4

               3
          y -1 = ( x + 5)                                                     üSubst./Vervang ( -5;1)
               4
            3      15
         y = x + +1
            4       4
              3      19                                                               3    19
         \y = x +                                                             üy =      x+
              4       4                                                               4     4
                                                                                                              (4)
3.4             1 - (-2)                                                                1
         mPQ =                                                                ü mPQ = -
                 -5 - 7                                                                 4
                  3
              =
                -12
                  1
              =-
                                                                                     ˆ = -1
                  4
                                                                              ü tan PDO
               ˆ = -1
         tan PDO                                                                         4
                      4
             ˆ
         \ PDO = - 14,04° +180° = 165,96°                                     ü165,96°
                                                                                                          (3)

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Mathematics P2/Wiskunde V2                                 5                              NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

3.5               -4                                                                       -4
          tan a =                                                             ü tan a =
                  3                                                                        3
         \ a = - 53,13° +180° = 126,87°
                                                  165,96°                     ü a = 126,87°
                              ˆ
         165,96° = 126,87° + PQR
                                                             126,87°
                                                                              ü
         \ ˆ
           PQR = 39.09°                                                                            ˆ
                                                                              165,96° = 126,87° + PQR
                                                                         Q

                                                                              ü39.09°
                                                                                                              (4)
3.6      area D PRS RS        4     1                                                area D PRS 1
                     =     =     =                                            üü               =
         area D PQS QS 16 4                                                          area D PQS 4
         [same height ;same base/dieselfde hoogte ; dieselfdebasis ]
         \ RS = a and / en QS = 4a

          Length of QR / Lengte van QR :

                    (1 - 7 ) + ( 6 - (-2) )
                           2                  2
          d QR =                                                              üMethod/Metode
          d QR = 100 = 10 units / eenhede                                     ü d QR = 10

          a + 4 a = 10
         \ 5a = 10
         \a = 2
         Length of QS / Lengte vanQS = 4(2) = 8 units / eenhede               ü QS = 8
                                                                                                          (5)
         OR/OF

          QR 2 = (1 - 7)2 + (6 - (-2)) 2                                      üMethod/Metode
                                                                              üQR = 10
          QR = 10
                        1
                          PQ.QS.sinQ
          area D PQS
                      = 2
          area D PQR    1
                          PQ.QR.sinQ
                        2
          16 x 2                                                                     area D PQS 4
                 =
                   QS                                                         üü               =
          20 x 2
                   10                                                                area D PQR 5

         4 QS
           =
         5 10
              4
         SQ = (10)
              5
            = 8 units / eenhede                                               üAnswer/Antwoord
                                                                                                          (5)
                                                                                                         [19]

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Mathematics P2/Wiskunde V2                                 6                                 NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 4
                                            y
                                        A

                                                                C(6 ; 3)

                                        O                                                        x

                                                            E

                                                                             B(2p ; –p)

4.1     x2 + y2 = r 2
        ( 6 ) + ( 3) = r 2
              2        2

        r 2 = 45                                                            ür2 = 45
        \ x 2 + y 2 = 45                                                    ü answer/antwoord
                                                                                                                 (2)
4.2
          (
        A 0; 45            )                                                ü0
                                                                            ü 45
                                                                                                                 (2)
4.3                   3 - 45                                                üMethod/Metode
        mAC =
                        6-0
                      3-3 5
                  =
                        6
                      1- 5                                                             1- 5
                  =                                                         ü mAC =
                        2                                                                2
        Through the point / Deur die punt 0; 45 (       )
                  1- 5
        y =            x+      45                                           üEquation/Vergelyking
                    2
                                                                                                                 (3)
4.4     - 45 < k < 45 or / of - 3 5 < k < 3 5                               ü - 45 and / en 45
        alternative notation / alternatiewe notasie                         üCorrect notation/ Korrekte
                                                                            notasie
        k Î (- 45 ; 45 ) or / of k Î (-3 5 ;3 5 )                                                      (2)
4.5.1   ( x - 2 p)2 + ( y + p)2 = 20                                        ü ( x - 2 p) 2 + ( y + p)2
                                                                            ü 20
                                                                                                       (2)

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Mathematics P2/Wiskunde V2                                         7                                  NW/September 2019
                                                NSC/NSS – Marking Guidelines/Nasienriglyne

4.5.2    d OB =       45 +       20                                               ü dOB = 45 +           20
               = 5 5 or / of              125                                     ü dOB = 5 5

         OB2 = (2 p ) 2 + ( p ) 2 [Pythagoras]

         (5 5 ) = 4 p + p
                  2
                         2            2

                                                                                  ü OB2 = (2 p)2 + ( p)2
         125 = 5 p 2
         25 = p 2
         \p =± 5                                                                  ü p 2 = 25
         But according / Maar vo lg ens diagram p > 0
         \p = 5
                                                                                  üp = 5
                                                                                                                      (5)
4.6     x 2 + 4 x cos q + y 2 + 8 y sin q = - 3                                  ü Complete the
                                                                                 square/Voltooi die vierkant
        x 2 + 4 x cos q + ( 2 cos q ) + y 2 + 8 y sin q + ( 4sin q ) =
                                            2                             2

        - 3 + ( 2 cos q ) + ( 4sin q )
                             2                  2

                                                                                 ü
        \ r = - 3 + 4 cos q + 16sin q
           2                     2                  2                            r 2 = -3 + 4 cos2 q + 16sin 2 q
        r 2 = - 3 + 4 cos 2 q + 16 (1 - cos 2 q )                                ü 16 (1 - cos 2 q )

        r 2 = - 3 + 4 cos 2 q + 16 - 16 cos 2 q
        r 2 = 13 - 12 cos 2 q                                                    ü r 2 = 13 - 12 cos 2 q
        For / vir 13 - 12 cos 2 q to be a maximum /
        om ' n maksimum te wees :
        cos 2 q needs to be a minimum / moet ' n min imum wees
        minimum of / van cos 2 q = 0                                             ü cos 2 = 0
        \ r 2 = 13 - 12(0) = 13
        \ r = 13                                                                 ü r = 13
        OR / OF
        r 2 = - 3 + 4 (1 - sin 2 q ) + 16sin 2 q                                 ü 4 (1 - sin 2 q )
        r 2 = - 3 + 4 - 4sin 2 q + 16sin 2 q                                     ü
                                                                                 r 2 = -3 + 4 - 4 sin 2 q + 16 sin 2 q
                                                                                 ü r 2 = 1 + 12sin 2 q
        r 2 = 1 + 12sin 2 q
        For / vir 1 + 12sin 2 q to be a maximum /
        om ' n maksimum te wees :
                                                                                 ü sin 2 q = 1
        maximum of / maksimum van sin q =1              2

        \ r 2 = 1 + 12(1) = 13
                                                                                 ü r = 13
        \ r = 13                                                                                                    (6)
                                                                                                                   [22]
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Mathematics P2/Wiskunde V2                                 8                                 NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 5

5.1.1        sin(180° - 70°).tan 60°                                                 ü sin70°
         cos180°.tan(180° + 70°).sin 20°                                             ü cos180°
                                                                                     ü tan70°
            sin 70°.tan 60°
                                                                                     ü sin20°
         (-1) tan 70°.sin 20°
                                                                                       sin 70°
                                                                                     ü
                sin 70°. 3                                                             cos 70°
                sin 70°                                                              ü sin20° = cos70°
          (-1).         .cos 70°
                cos 70°                                                              ü- 3
          =- 3                                                                                                    (7)

5.1.2    1 - 2sin 2 22,5°                                                            ü 1 - 2sin 2 22,5°
         cos 2(22,5°)
                                                                                     ü cos 2(22, 5°)
         cos 45°
              1                                                                      ü cos 45°
         =
               2
               2                                                                         1
         =                                                                           ü
              2                                                                           2

                                                                                                                  (4)
5.2.1    sin x = 0 and where / en waar tan x is undefined / ongedefinieerd
              2

         \sin x = 0
                                                                                     ü x = 0°
         \ x = 0° or / of x = 180° or / of x = 90°
                                                                                     ü x = 180°
                                                                                     ü x = 90°
                                                                                                                  (3)
5.2.2    LHS / LK
         cos 2 x.tan x                                                               ü
            sin 2 x                                                                  cos 2 x = cos2 x - sin 2 x
                                                                                                sin x
             ( cos x - sin x ) æçè cos
                   2        2      sin x ö
                                       xø
                                         ÷
                                                                                     ü tan x =
                                                                                                cos x
         =
                        sin 2 x
                                 æ sin x ö æ 1 ö
         = ( cos 2 x - sin 2 x ) ç       ÷ç 2 ÷
                                 è cos x ø è sin x ø
           cos 2 x - sin 2 x                                                                 cos 2 x - sin 2 x
         =                                                                           ü
              sin x cos x                                                                      sin x cos x
              cos 2 x           sin 2 x                                              ü
         =               -
           sin x cos x sin x cos x                                                     cos 2 x     sin 2 x
                                                                                                -
                                                                                     sin x cos x sin x cos x
           cos x sin x
         =       -                                                                       cos x sin x
           sin x cos x                                                               ü        -
                                                                                         sin x cos x
           cos x
         =       - tan x = RHS / RK                                                                               (5)
           sin x

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Mathematics P2/Wiskunde V2                                 9                               NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

         OR/OF

         LHS / LK
         cos 2 x.tan x
            sin 2 x                                                                  ü
           ( cos x - sin x ) æçè cos
                2         2      sin x ö
                                     xø
                                       ÷                                             cos 2 x = cos2 x - sin 2 x
         =                                                                                      sin x
                     sin 2 x                                                         ü tan x =
                                                                                                cos x
                                                                                      cos x.sin x
                         sin 3 x                                                     ü
           cos x.sin x                                                                   sin 2 x
         =             - cos2 x                                                        sin 3 x
             sin 2 x     sin x
                                                                                     ü cos2 x
                                                                                       sin x

             cos x sin x                                                                 cos x sin x
         =        -                                                                  ü        -
             sin x cos x                                                                 sin x cos x

             cos x
         =         - tan x = RHS / RK                                                                           (5)
             sin x                                                                                            [19]

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Mathematics P2/Wiskunde V2                                  10                              NW/September 2019
                                         NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 6
      y

                   f

 1
                                                                      x
     0°                          90°                                  180°

                                                          g

                                                                     P(180° ; –3)

6.1       a = 3 and/en b = 2                                                 üa = 3
                                                                             üb = 2
                                                                                                               (2)
6.2       360°                                                               ü360°
                                                                                                     (1)
6.3       2 £ y £ 4 or / of y Î [2; 4]                                       ü values/waardes 2 and/en 4
                                                                             ü notation / notasie.   (2)

6.4       0° < x < 45° or / of 90° < x < 135°                                ü 0° and/en 45°
          alternative notation / alternatiewe notasie                        ü 90° and/en 135°
                                                                             ü notation / notasie
          x Î (0° ; 45°) È (90° ;135°)                                                                         (3)
6.5       y = cos x - sin x
                   2        2

                                                                             ü y = cos 2x
          y = cos 2 x
          to coincide with g / om saam te val met g :
          y = sin (90° + 2 x)                                                ü sin (90 + 2x)
          y = sin 2 ( x + 45°)
          \ q = 45°                                                          ü 45°
                                                                                                           (3)
                                                                                                          [11]

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Mathematics P2/Wiskunde V2                                 11                                   NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 7

 7.1

                                                y
                       C (bcosA ; bsinA)

                                                         a
                                   b

                                                                                            x
                                                A(0 ; 0)         c                   B(c ; 0)

        Coordinates of /Koördinate van B(c ; 0)                       ü coordinates of / koördinate van B
                                                                      ü correct subst. into distance
                      ( b cos A - c ) - ( b sin A - 0 )
                                       2                     2
        BC = a =
                                                                      formula / korrekte vervanging in
                                                                      afstandsformule
        \ a 2 = b 2 cos 2 A - 2bc cos A + c 2 + b 2 sin 2 A           ü
                                                                      b2 cos 2 A - 2bc cos A + c 2 + b 2 sin 2 A
              = b 2 ( cos 2 A + sin 2 A) - 2bc cos A + c 2            ü b 2 ( cos 2 A + sin 2 A )

              = b 2 (1) + c 2 - 2bc cos A
              = b 2 + c 2 - 2bc cos A                                                                         (4)
 7.2

                                                     R
                                                    60°

                                           50                    60

                                   Q
                                 10
                                  60°                                 60°
                             T                                              P

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Mathematics P2/Wiskunde V2                                   12                              NW/September 2019
                                          NSC/NSS – Marking Guidelines/Nasienriglyne

7.2.1   Rˆ = Tˆ = Pˆ = 60°                                          ü 60°
                                                                    ü 10 or/of 50
        QT = 10 and / en QR = 50

        PQ2 = 60 2 + 502 - 2(50)(60) cos 60°                        ü correct subst in cosine-rule/
                                                                    korrekte vervanging in cosreël
             = 3100                                                 ü 3100
        OR / OF
        PQ2 = 102 + 60 2 - 2(10)60) cos 60°
            = 3100
        \ PQ = 55, 68                                                                                     (4)

7.2.2
                                      R

                         50                      60

                     Q
                         x
                10                S
            T                                             P

                                                                    ü Diagram
        S is the nearest to R where RS is the
        perpendicular heigt / S is die naaste aan R waar
        RS die loodregte hoogte is.

        Let / Laat QS = x
        \ PS = 55, 68 - x
        ( 50 - x ) = ( 60 - [55, 68 - x] ) = RS
            2        2        2              2        2             ü Pythagoras

        2500 - x 2 = 3600 - 3100, 26 + 111,36 x - x 2               ü Simplify / vereenvoudig
        2000, 26 = 111,36 x
        \ x = 17,96 units / eenhede                                 ü answer / antwoord
                                                                                                          (4)
                                                                                                         [12]

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Mathematics P2/Wiskunde V2                                 13                              NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

                                        GEOMETRY/MEETKUNDE

Please read carefully through the following table before marking QUESTION 8 – 10 /
Lees asseblief sorgvuldig deur die volgende tabel alvorens VRAAG 8 –10 nagesien word.

              The order in which the candidate answer a geometry question must follow logically/
              Die volgorde waarin ‘n kandidaat ‘n meetkundevraag beantwoord moet logies volg.

              Example/Voorbeeld

              Given/Gegee AB || CD and/en ACˆ E = 105°
                                               A                         D
                                              65°

                                                            x
                                                                y
                              B                            C                               E

              The candidate first need to calculate x BEFORE he/she can calculate y/Die kandidaat
              moet eerste vir x bereken VOORDAT hy/sy vir y kan bereken.

              A mark for a correct statement
              (A statement mark is independent of a reason)
     S
              ‘n Punt vir ‘n korrekte bewering
              (‘n Punt vir ‘n bewering is onafhanklik van die rede)
              A mark for the correct reason
              (A reason mark may only be awarded if the statement is correct)
    R
              ‘n Punt vir ‘n korrekte rede
              (‘n Punt word slegs vir die rede toegeken as die bewering korrek is)
              Award a mark if the statement AND reason are both correct
   S/R
              Ken ‘n punt toe as die bewering EN rede beide korrek is

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Mathematics P2/Wiskunde V2                                 14                              NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 8

                                            D                                        E
                                                                            1
                                            1 2
                                                                             2

                                          68o       2
                                                1       3
                          C                         B                       A

8.1.1    ˆ = 68° [ ext.Ð cyclic quad / buiteÐ van kvh ]
        DEA                                                                                    üSüR
                                                                                                              (2)
8.1.2   Â = 112° [ co-interior Ðs / ko - binne Ðe ; DE / / CA]                                üS/R           (1)
8.1.3   D̂ 2 = 68° [ oppÐs of cyclic quad / teenoorst.Ðe van kvh ]                             üSüR
        OR/OF
        D̂ 2 = 68° [ alt Ðs / verwiss Ðe ; DE / /CA]                                           üSüR
                                                                                                              (2)
8.1.4   B̂2 = 68° [ Ðs opp. = sides / Ðe teenoor = sye]                                        üS/R           (1)
8.1.5   Ê1 = 44° [ sum of Ðs of D /som van binneÐe van D ]                                    üS/R

        D̂1 = 44° [ tangent chord theorem / raaklyn - koordstelling ]                          üSüR

                                                                                                              (3)
8.2     Ĉ = 68° [ sum of Ðs of D /som van binneÐe van D ]                                     üS/R

        But / maar ˆB1 = 68° [given / gegee]
        DC = DB [ sides opp.= Ðs / sye teenoor = Ðe ]                                          üS/R
        \D BDC is isosceles / gelykbenig                                                                      (2)
8.3          ˆ = 68°
        D̂ = C                                                                                 üS
          2

                                       éconverse tangent chord theorem / ù
        \ DE is a tangent / 'n raaklyn ê                                   ú
                                       ëomgekeerde raaklyn - koordstelling û                   üR
                                                                                                          (2)
                                                                                                         [13]

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Mathematics P2/Wiskunde V2                                  15                              NW/September 2019
                                         NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 9
                                                    E
                                                  1 2

                            G
                                 2
                             1

                                                    1
                                                     2F
          2
D
          1                                         2
                                                   1 C                                             2
                                                                                                         A
                                                                                             1

                                     2    1
                                     B

    9.1       tangent-chord theorem / raaklyn-koordstelling                                      PR
                                                                                                               (1)
    9.2       In DABC and/en DADB:
               Â1 = Â1   [common/gemeenskaplik]                                                PS

              B̂ = D̂        [proven/bewys in 9.1]                                               PS
                1    1
              \ DABC | | | DADB [Ð ; Ð ; Ð]                                                      PR
              OR/OF
              In DABC and/en DADB:
              Â = Â       [common/gemeenskaplik]                                               PS
                1     1
              B̂1 = D̂1      [proven/bewys in 9.1]                                               PS
                ˆ
              BCA = ˆ
                   ABD [Ðs of D = 180°/Ðe van D = 180°]                                          PS
              \ DABC | | | DADB
                                                                                                               (3)

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Mathematics P2/Wiskunde V2                                  16                               NW/September 2019
                                         NSC/NSS – Marking Guidelines/Nasienriglyne

9.3        Ê = F̂
             2       1
                               [alternate Ðs/ verwiss Ðe ; EA | | GF]                            P S PR

           F̂1 = D̂ 2          [ext Ð of cyc quad DGFC/buite Ð v kdvh DGFC]                      P S PR
           \ Ê 2 = D̂ 2
                                                                                                                (4)
9.4        In DAEC and/en DADE:
            Â 2 = Â 2 [common/gemeenskaplik]                                                   PS

           Ê 2 = D̂ 2         [proven/bewys in 9.3]                                             PS
           \ DAEC | | | DADE [Ð ; Ð ; Ð]                                                         PR
             AE AC
           \    =        [from ||| Ds / uit ||| De]
             AD AE                                                                               PS
                     2
           \ AE = AD ´ AC                                                                        PS
           \ AE = AD×AC

           OR/OF

           In DAEC and/en DADE:
            Â 2 = Â 2 [common/gemeenskaplik]
                                                                                                 PS
           Ê 2 = D̂ 2         [proven/bewys in 9.3]                                             PS
            ˆ = AED
           ACE   ˆ  [Ðs of D = 180°/Ðe van D = 180°]                                             PS

           \ DAEC | | | DADE
             AE AC
           \    =        [from ||| Ds / uit ||| De]                                              PS
             AD AE
           \ AE 2 = AD ´ AC                                                                      PS
           \ AE = AD×AC                                                                                         (5)
  9.5      AB AC
             =                 [from |||Ds / uit ||| De]   from/van 9.2                          PS
           AD AB
                 2
           AB = AD ´ AC                                                                          PS
                           2
               = AE            [from/van 9.4]                                                    PS
           \AB = AE                                                                                         (3)
                                                                                                           [16]

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Mathematics P2/Wiskunde V2                                 17                              NW/September 2019
                                        NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION/VRAAG 10

10.1
                                             A

                                                 h

                                                     k
                             D
                                                                         E

                        B
                                                                                     C

          Construction: Connect DC and BE and draw the altitudes k and h                     P constr/
          Konstruksie: Verbind DC en BE en trek hoogtelyne k en h.                           konstr

          Area ΔADE 2 ´ AD ´ k AD
                     1
                   =          =
          Area ΔBDE 1 ´ BD ´ k BD                                                            PS
                      2

           Area ΔADE 2 ´ AE ´ h AE
                       1
                    =          =
           Area ΔDEC 1 ´ EC ´ h EC                                                           PS
                       2
          but/maar: Area DBDE = Area DDEC                                                    PS PR
          [DE common base/ gemeenskaplike basis with/met DE | | BC]
              Area ΔADE Area ΔADE                                                            Pconclusion/
          \              =
              Area ΔBDE Area ΔDEC                                                            afleiding
                     AD AE
          \              =
                     BD EC
                                                                                                              (6)

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Mathematics P2/Wiskunde V2                                  18                                        NW/September 2019
                                         NSC/NSS – Marking Guidelines/Nasienriglyne

                                                  A

                                                            3b
                                    3a
                                                                 S
                                                                     2b
                                                                          P
                   R

                                                                                5b
           2a                            T

     B
                                                                                          C
 10.2.1     AS AR
              =               [line | | side of D/ lyn | | sy van D]                          PS PR
            SP RB
                              OR/OF [ RS | | BP]
               3                                                                                3
             =                                                                                P
               2                                                                                2
           AS 3                                                                                 3
             =                [AP = PC]                                                       P
           SC 7                                                                                 7
                                                                                                                  (4)
10.2.2      RT SP
              =               [line | | side of D/ lyn | | sy van D]                          PS PR
            TC PC
                              OR/OF [RS | | TP]
                  2
                =                                                                             Panswer/antwoord
                  5                                                                                         (3)
10.2.3     Area of ΔRAS AS 3
                         =     =                                                              P
                                                                                                  3
           Area of ΔRSC SC 7                                                                      7
           [common height /
           gemeenskaplike hoogte]                                                             PR
                                                                                                               (2)
10.2.4      Area ΔTPC          1  ˆ
                        TC.PC.sinTCP                                                          PCorrect subst
                      =        2
                                                                                               into area rule/
                                  ˆ
            Area ΔRSC 1 RC.SC.sinTCP
                               2                                                              Korrekte vervang.
                            TC PC                                                             in area-reël
                          =    ´
                            RC SC
                            5 5                                                                 5
                          = ´                                                                 P
                            7 7                                                                 7
                            25                                                                Panswer/antwoord
                          =                                                                                 (3)
                            49                                                                             [18]

                                                                                      TOTAL/TOTAAL:                 150
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Mathematics P2/Wiskunde V2                                                             19                                                 NW/September 2019
                                                                              NSC/NSS – Memorandum

                                                GRID-Analysis (According to BLOOMS TAXONOMY)
                                                   KNOWLEDGE              ROUTINE               COMPLEXED     PROBLEM
                                                                         PROCEDURES             PROCEDURES    SOLVING
 Question       Description                 Low     Mod   High     Low    Mod      High   Low    Mod   High   Low       Mod   High
                Statistics(Gr.11)
 1.1            Frequency                           1
 1.2            Cumulative Frequency        1
 1.3            Mean average                                       3
 1.4.1          Standard deviation                                                 2
 1.4.2          Within standard deviation           1
 1.5            Adjusted mean average                                                                         2
 2              Regression(Gr.12)
 2.1            Outlier                     1
 2.2            Regression line                                    3
 2.3            Application regr. Line                             2
 2.4            Correlation Coefficient                   2
 2.5            Application slope                                                                             2
 3              Analytical (Gr.11)
 3.1            Equation vertical line              1
 3.2            Gradient of line            2
 3.3            Equation of line                                                          4
 3.4            Inclination                                               3
 3.5            Angle between straight ln                                                 4
 3.6            Integrating geometry                                                             5
 4              Analytical(Gr.12)
 4.1            Eq circle (0;0)                     2
 4.2.           y-intercept                         2
 4.3            Equation of line                                                   3
 4.4            Roots opposite signs                                                                          2

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Mathematics P2/Wiskunde V2                                                20                                            NW/September 2019
                                                                NSC/NSS – Memorandum

 4.5.1          Eq. of circle midpt(a;b)        2
 4.5.2          Value of p                                                        5
 4.6            Max length of radius                                                                       6
                                                               ROUTINE         COMPLEX
                                              KNOWLEDGE      PROCEDURES       PROCEDURES    PROBLEM SOLVING
 Question       Description                 Low Mod High   Low Mod High     Low Mod High   Low     Mod High
 5              Trigonometry
 5.1.1          Reduction                                            7
 5.1.2          Double angles                                  4
 5.2.1          Undefined                                      3
 5.2.2          Identity                                                          5
 6              Trig Graphs
 6.1            Parameters                      2
 6.2            Period                      1
 6.3            Range                               2
 6.4            Integration interval                                              3
 6.5            Integration of parameters                                                          3
 7              2D/3D Trig
 7.1            Formulae                                             4
 7.2.1          Application cos-rule                                        4
 7.2.3          Integration                                                                            4
 8              Geometry
 8.1            Ext angle cyclic quad               2
 8.2            Co-interior                     1
 8.3            Opp. Angle Cyclic quads         2
 8.4            Angles of triangle              1
 8.5            Tangent-chord                       3
 8.6            Isoceles                                   2
 8.7            Prove tangent                                  2

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Mathematics P2/Wiskunde V2                                                     21                                     NW/September 2019
                                                                      NSC/NSS – Memorandum

                                                               ROUTINE             COMPLEX             PROBLEM
                                            KNOWLEDGE        PROCEDURES          PROCEDURES            SOLVING
 Question       Description                Low Mod High    Low Mod High         Low Mod High       Low   Mod High
 9              Geometry
 9.1            Tangent problems           1
 9.2            Similar triangles                          3
 9.3            From similar triangles                                  4
 9.4            Proportionality                                                       5
 9.5            Conclusion                                                      3
 10             Geometry
 10.1           Bookwork                                        6
 10.2.1         Ratio                                                           4
 10.2.2         Ratio                                           3
 10.2.3         Ratio of areas                                          2
 10.2.4         Ratio of areas                                                3
                                           6   15    9     13   21      22    22      23     0     6    7     6
                % Breakdown of cognitive        30   20%         56     37,3%          45    30%         19   12,7%
                levels
                Expected %                           20%                 35%                 30%              15%

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