# Physical Sciences Grade 12 Paper 1 North West Mock 2022 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the North West Mock Exam 2022, 39 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/nw-physical-science-grade-12-sept-2022-p1-and-memo/45245b39-74d3-4a90-9916-dbc1721214c4
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2022
- Exam period: North West Mock Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 39

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Physical Sciences · Grade 12 · North West Mock Exam · 2022. Memorandum, 39 pages. Read online or download the PDF.

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### Page 1

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                                  NATIONAL
                             SENIOR CERTIFICATE

                                      GRADE 12

                        PHYSICAL SCIENCES: PHYSICS (P1)

                                   SEPTEMBER 2022

MARKS: 150

TIME: 3 hours

              This question paper consists of 20 pages and 3 data sheets

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INSTRUCTIONS AND INFORMATION

1.      Write your name on the ANSWER BOOK.

2.      This question paper consists of TEN questions. Answer ALL the questions in
        the ANSWER BOOK.

3       Start EACH question on a NEW page in the ANSWER BOOK.

4.      Number the answers correctly according to the numbering system used in this
        question paper.

5.                                                                    s.
        Leave ONE line open between sub questions, e.g. between QUESTION 2.1 and
                                                                        co
        QUESTION 2.2.
                                                                          m
6.      You may use a non-programmable calculator.                  si c
7.                                        st
        You may use appropriate mathematical instruments.
                                             an
8.                                             m
        You are advised to use the attached DATA SHEETS.
                                                or
9.
                                                   ep
        Show ALL formulae and substitutions in ALL calculations.

10.                                                  hy
        Round off your FINAL numerical answers to a minimum of TWO decimal places.

11.                                  om
        Give brief motivations, discussions, etc. where required.

12.     Write neatly and legibly.   fr
                       oa
                         de
                           d
           do
             wn
               l

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QUESTION 1: MULTIPLE-CHOICE QUESTIONS

Various options are given as possible answers to the following questions. Each question
has only one correct answer. Choose the answer and write only the letter (A–D) next to
the question numbers (1.1 to 1.10) in the ANSWER BOOK, e.g.1.11 E.

1.1 Which ONE of the following is a conservative force?

      A    Frictional force

      B    An applied force

      C    Gravitational force                                     s.co
      D    Tension in a rope                                           m                       (2)
                                                              si c
1.2 An object with mass m moves with a constant velocity. It undergoes a displacement
                                        st
    fx in t seconds in the presence of a frictional force F. How much power is required
                                           an
    to keep the body in motion at this constant velocity?

      A     fx
                                             mor
             t
                                                 ep
      B     Fx                                     hy
             2
                                  om
      C      F( fx )2
                 t
                                 fr
      D          fx
                         oa                                                                   (2)
           F(
                  t
                    )      de
                             d
           do
             wn
               l

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1.3 Two forces, each of magnitude 300 N are simultaneously applied to a crate at rest
    on a frictionless horizontal surface as shown in the diagram below.

     Work will be done by the net force on the crate and the crate will...

       A     accelerate to the left

       B     be lifted off the surface

       C     accelerate to the right

       D     remain rest                                                                           (2)

1.4 A stone falls freely from rest from a certain height. Which one of the following
    quantities could be represented on the y-axis of the graph?

       A     Velocity

       B     Acceleration

       C     Momentum

       D     Position                                                                              (2)

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 1.5    The ball is released from rest at point A, h meters above the ground. It slides
        down and up on a smooth frictionless track ABC. See the diagram below.

        As the ball slides on the track ABC, it will …

        A     have maximum kinetic energy and zero potential energy at B

        B     roll up to a height of ‘z’ m on the opposite slope at C

        C     lose mechanical energy as it rolls up the opposite slope towards point C

        D     experience a gain in kinetic energy which is equal to its potential energy
              at C                                                                               (2)

 1.6    A source of sound moves away from a stationery observer. The frequency of the
        sound detected by the observer is different from the source frequency because:

        A    the volume of the sound decrease as the source moves away from the
             observer

        B    the speed of sound becomes smaller

        C the wave fronts received by the observer are further apart than the wave front
          from the source

        D the wave fronts received by the observer are closer than the wave front from
          the source                                                                             (2)

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 1.7    Two oppositely charged spheres P and Q carry charges of +3 C and -3 C
        respectively. An object is placed at point Y as indicated in the diagram below.

        The vector diagram representing the net electric field at point Y is:

                                                                                                   (2)
 1.8    The diagram below represents part of a circuit. The potential difference across P
        and Q is V

        Which ONE of the following gives the current through the 3 Ω resistor?

             V
        A
             4

             V
        B
             6

             V
        C
             2

             V
        D                                                                                          (2)
             3

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 1.9    A multi plug enables us to plug many appliances in at the same time so they can
        function simultaneously. If a multi plug adaptor connected in parallel is
        overloaded with too many appliances, a trip switch cuts off the electrical supply.

        Which ONE of the following statements best explains the situation?

        A    The effective resistance increases and the current becomes too high

        B    More current is required that can be supplied

        C    The effective resistance decreases, resulting in a larger current being drawn

        D    The current is divided among all the appliances and is not enough for them all
             to operate                                                                          (2)

 1.10 Fluorescent lights are used for signage, advertising and coloured lighting. The
      fluorescent tubes consists of mainly argon, neon or krypton gas ...

        The type of spectrum formed by these types of lights is…

        A    an absorption spectrum

        B    a line emission spectrum

        C    continuous spectrum

        D    a transmission spectrum                                                              (2)
                                                                                                 [20]

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                                           NSC

 QUESTION 2 (Start on a new page)

 Elephants are being transported from Kruger National Park to Eastern Cape. They are
 loaded into crates that are pulled up an inclined plane on frictionless rollers.

 The diagram below shows a crate with an elephant being held stationery on the ramp by
 means of a rope parallel to the ramp. The angle of inclination is 15 ̊ and the tension of the
 rope is 5000 N.

 2.1    Draw a labelled free-body diagram of all the forces acting on the elephant and
        crate. (consider crate and elephant as one object)                                (3)

 2.2    The crate has a mass of 800 kg. Determine the mass of the elephant.               (4)

 2.3    The crate is now being pulled up the ramp at CONSTANT ACCELERATION.

        2.3.1    What effect does it have on the net force acting on the elephant and
                 the crate?
                 Choose from INCREASE, DECREASE OR REMAINS SAME.                      (1)

        2.3.2    Explain your answer in QUESTION 2.3.1                                    (1)

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 2.4    In another experiment, learners investigated the forces acting on an object on
        an inclined plane. The object had a gravitational force of 98 N. The ratio of the
        NORMAL force to that of parallel component force was 7:4

        2.4.1    Define normal force in words.                                              (2)

        2.4.2    Calculate the angle of inclination ø of the ramp                           (3)
                                                                                            [14]

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 QUESTION 3 (Start on a new page)

 Nomsa is standing on the ground floor of a building. She throws a pencil case vertically
 towards Mekwe, who is standing on the balcony of the first floor of the building, with
 an initial velocity, v.

 Mekwe fails to catch the pencil case as it moves upwards but catches it on its way
 back. Ignore the effects of air friction.

 The position time graph below, not drawn to scale, represents the motion of the pencil
 case when it was thrown up till it reaches Mekwe’s hand. Choose upwards as positive.

 3.1    Define the term free fall.                                                           (2)

 3.2    Use the graph and determine the:

        3.2.1    Time in which pencil case’s velocity is 0 m·s-1                             (1)

        3.2.2    Acceleration of the pencil case at 1,4 s?                                   (2)

        3.2.3    Time it takes for the pencil case to reach Mekwe’s hand from the
                 moment Nomsa threw it upwards.                                              (2)

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 3.3    Use equations of motion and information from the graph to calculate the:

        3.3.1    Initial velocity v of the pencil case.                                   (3)

        3.3.2    Height of the pencil case above the ground when Mekwe caught it.         (3)

 3.4    Draw an acceleration-time graph for the entire motion of the pencil case.
        Indicate the value of acceleration and time on the graph.                         (2)

 3.5    What does the area under the acceleration time graph represents?                  (1)
                                                                                         [16]

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 QUESTION 4 (Start on a new page)

 Tim is playing snooker and positions his cue so that the white ball is lined up with the black
 ball. A 0,6 kg white ball moving at a velocity 0,5 m·s-1 collides with a stationery black ball of
 mass 0,8 kg. On contact, the black ball exerts a force of 1,2 N on the white ball.

 4.1    State Newton’s Second Law of motion in terms of momentum.                             (2)

 4.2    If the change in momentum of the white ball is -0,24 kg·m·s-1, calculate the
        time that the white ball is in contact with the black ball.                           (3)

 4.3    Calculate the velocity of the white ball after the collision.                         (3)

 4.4    On being struck, the black ball moves forward towards the bumper cushion on
        the sides of the snooker table and collided elastically with the bumper
        cushion. After collision, the kinetic energy of the black ball is 0,042 J.
        Calculate its velocity.                                                     (3)
                                                                                    [11]

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 QUESTION 5 (Start on a new page)

 Vickey a 75 kg learner, jumps off a bridge 60 m above the ground. She has a bungee cord
 tied to her ankles. She falls 25 m before the bungee cord begins to stretch, slowing down her
 fall. The cord stretches 20 m, before the jumper come to rest. Ignore air friction.

 5.1    Write down the work-energy theorem in words.                                           (2)

 5.2    Using energy principles calculate the kinetic energy of the jumper when she            (4)
        has fallen 25 m.

 5.3    Calculate the work done by the cord to bring her to rest.                              (3)

 5.4    How much energy is transferred from the jumper to the cord?                            (1)

 5.5    Calculate the average force exerted by the cord on the jumper if the cord
        stretches for 20 m before she comes to rest.                                           (4)

                                                                                          [14]

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 QUESTION 6 (Start on a new page)

 Scientists studying the social interaction of dolphins in captivity connected an
 underwater sound recorder to an oscilloscope and immersed it in the dolphin tank at
 an aquarium.

 They recorded the sound waves emitted by the dolphins as they approached the
 microphone. The waves they recorded on the oscilloscope are represented below:

 6.1    State the Doppler effect in words.                                                     (2)

 6.2    The average frequency of the social vocalisations of these dolphins is 38 kHz.
        Show by calculation that the frequency recorded is 2 kHz higher than the actual
        frequency.                                                                             (2)

 6.3    Explain why the recorded frequency is higher than the actual frequency.                (2)

 6.4    Calculate the speed at which the dolphins are approaching the recorder.
        The speed of sound in water is 1500 m·s-1.                                             (5)

 6.5    Astronomers have used Doppler effect to conclude that galaxies are moving
        away from the Earth. Write a reason to support their conclusion.                   (2)
                                                                                          [13]

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 QUESTION 7 (Start on a new page)

 Two small identical metal spheres, X and Y, each with a mass of 0,9 g hang from
 the same fixed point from threads of equal length. When the spheres receive equal
 charges, they repel each other and come to rest with their centres 40 mm apart and
 the threads making an angle of 45 ̊ with the vertical.

 7.1 State Coulomb’s law in words.                                                          (2)

 7.2 Draw a force diagram to show all the forces acting on Y.                               (3)

 7.3 Calculate the:

       7.3.1    Magnitude and direction of electrostatic force that X exerts on Y.          (3)

       7.3.2    Charge on each sphere.                                                      (3)

 7.4 Three charged particles A, B and C are arranged in a line as shown in the
     diagram.

       7.4.1    Calculate the magnitude and direction of net electrostatic force on
                particle C due to the other two charges.                                   (3)
                                                                                          [14]

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 QUESTION 8 (Start on a new page)

 Three identical unknown resistors each of resistance R are connected in circuit to
 a battery of emf 24 V and unknown internal resistance ‘r’. An ammeter registers a
 current of 3 A and voltmeter V1 reads 21 V when the switch ‘S’ is closed.

 8.1 Explain the term internal resistance.                                              (2)

 8.2 Write down a mathematical expression/formula which relates the voltmeter
     readings of V2 and V3.                                                             (1)

 8.3 What will be the reading on V2 and V3?                                             (2)

 8.4 Calculate the:

       8.4.1    Internal resistance of the battery.                                     (4)

       8.4.2    Resistance of the resistor R.                                           (3)

 8.5 A car lamp is marked ’12 V, 60 W’. Calculate the quantity of electric charge
     that passes through any point in the lamp in 2 minutes when operating
     according to the above mentioned specifications.                                  (4)
                                                                                      [16]

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 QUESTION 9 (Start on a new page)

 The diagram given below is a schematic representation of an AC generator.

 9.1 Write down the:

       9.1.1    Name of the part labelled ‘R’.                                             (1)

       9.1.2    Function of part labelled ‘R’.                                             (2)

 9.2 State ONE principle on which an AC generator works.                                   (2)

 9.3 If the armature is rotated in the direction as indicated in the diagram, which
     way will the current flow in the armature?

       Choose from A to B or B to A                                                        (1)

 9.4 What effect does changing the polarity of the magnets have on the output
     voltage?

       Choose from INCREASES, DECREASES OR REMAINS THE SAME.                               (1)

 9.5 What is the position of the coil, relative to the magnetic field, when the
     output voltage is at a minimum?                                                       (2)

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 9.6 The graph shows the potential delivered by an AC source to a light bulb
     which is dissipating 15 W.

       9.6.1    What DC voltage would have to be supplied to keep the bulb
                burning at the same brightness?                                            (3)

       9.6.2    What is the peak current through the bulb while it is connected to the
                AC source?                                                                 (4)

       9.6.3    Draw a graph of current versus time for the same time period as the
                above graph. Indicate the values of Imax and Irms on the graph.           (2)
                                                                                         [19]

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 QUESTION 10 (Start on a new page)

 When ultraviolet light shines on the surface of an electrode of a photoelectric cell,
 electrons are ejected. The velocity of the ejected electrons is measured against the
 frequency.

 The graph below represents the results obtained.

 10.1   Name the physical quantity represented by ‘f1’ on the graph?                      (1)

 10.2   Use the information from the graph to calculate the value of f1                   (5)

 10.3   A grade 12 learner has a calculator that is powered by a photoelectric cell. The
        photoelectric cell consists of two conductive plates that are connected in a circuit
        as shown below. The lower plate consists of selenium.

        10.3.1       Define the term work function in words.                              (2)

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        A learner shone a blue light on the photoelectric cell and found that the calculator
        did not work. He finds that the calculator works in day light.

        Use the information given below and answer the questions that follow:

         Frequency of blue light        Frequency of                Work function of
                                        ultraviolet light           selenium
         3,32 X 1014 Hz                 1,54 X 1016 Hz              9,44 X 10 -19 J

        10.3.2       Calculate threshold frequency of selenium?                           (3)

        10.3.3       Write a reason why does the photoelectric cell work in day light
                     and not in blue light.                                               (2)
                                                                                         [13]

                                                                               TOTAL:    150

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                                        NSC

                         DATA FOR PHYSICAL SCIENCES GRADE 12
                                   PAPER 1 (PHYSICS)

                     GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
                                VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

            NAME/NAAM               SYMBOL/SIMBOOL      VALUE/WAARDE
 Acceleration due to gravity
 Swaartekragversnelling                    g                 9,8 m·s-2
 Universal gravitational constant
 Universele gravitasiekonstant             G           6,67 x 10-11 N·m2·kg-2
 Speed of light in a vacuum
 Spoed van lig in 'n vakuum                c              3,0 x 108 m·s-1
 Planck's constant
 Planck se konstante
                                           h              6,63 x 10-34 J·s
 Coulomb's constant
 Coulomb se konstante
                                           k            9,0 x 109 N·m2·C-2
 Charge on electron
 Lading op elektron
                                           e               1,6 x 10-19 C
 Electron mass
 Elektronmassa
                                           me             9,11 x 10-31 kg
 Mass of the Earth
 Massa van die Aarde                       M              5,98 x 1024 kg
 Radius of the Earth
 Radius van die Aarde                      RE              6,38 x 106 m

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                          TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

 v f  v i  a t                                         Δx  v i Δt  21 at 2 or/of Δy  v i Δt  21 at 2
                                                                v vf                 v  vf 
 v f  v i  2ax or/of v f  v i  2ay
      2       2                      2     2
                                                          Δx   i      Δt or/of Δy   i       Δt
                                                                2                     2 

FORCE/KRAG

 Fnet  ma                                                p  mv
              sN
      max
 fs                                                       fk   k N
 Fnet t  p
                                                          w  mg
 p  mv f – mv i
            m 1m 2                             m 1m 2               M                              M
  FG                  or/of             FG              g G                   or/of         g G 2
              d   2
                                                 r   2
                                                                    d2                             r

WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING

 W  Fx cos                                             U  mgh                 or/of        E P  mgh

                                                          Wnet  K              or/of        Wnet  E k
    1                                     1
 K  mv 2             or/of          E k  mv 2
    2                                     2
                                                          K  K f  K i         or/of    Ek  Ekf  Eki
                                                               W
 W nc  K  U or/of          Wnc  Ek  Ep            P
                                                               t

 Pave  Fv ave / Pgemid  Fv gemid

WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG

                                                               1
 vf                                                     T
                                                               f

          v  vL                     v  vL                                               c
 fL             fs           fL           fb            E  hf         or/of     E h
          v  vs                     v  vb                                               

 E  Wo  E k(max) or/of E  W o  K max where/waar
                                                         1
 E  hf and/en W0  hf 0 and/en E k (max)                    2
                                                           mv max    or/of K max  1 mv max
                                                                                        2

                                                         2                                2

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                                                            NSC

ELECTROSTATICS/ELEKTROSTATIKA

      kQ 1Q 2                                                   kQ
 F                                                       E 
        r   2
                                                                   r2

      W                                                        F
 V                                                       E
      q                                                        q

       Q                                  Q
  n                    or/of        n
       e                                  qe

ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE

                                                          emf ( ε )  I(R + r)
       V
 R
                                                          emk ( ε )  I(R + r)
       I

 R s  R 1  R 2  ...
  1   1   1                                               qI  t
           ...
 R p R1 R 2

 W  Vq                                                         W
                                                          P
                                                                Δt
 W  VI  t
                                                          P  VI
 W  I2R  t
                                                          P  I 2R
           V Δt 2

 W                                                            V2
            R                                             P
                                                               R

ALTERNATING CURRENT/WISSELSTROOM

        I                                         I
 I rms  max                     /         I wgk  maks   Pave  Vrms I rms   /   Pgemiddeld  Vwgk I wgk
          2                                         2

            Vmax                                          Pave  I rms
                                                                   2
                                                                       R      /   Pgemiddeld  I 2wgk R
 Vrms                           /
                    2                                                 2                            2
                                                                    Vrms                          Vwgk
 V wgk 
                Vmaks                                     Pave               /    Pgemiddeld 
                    2                                                R                             R

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                          NATIONAL SENIOR CERTIFICATE/
                          NASIONALE SENIOR SERTIFIKAAT

                                        GRADE/GRAAD 12

                            PHYSICAL SCIENCES: PHYSICS (P1)
                            FISIESE WETENSKAPPE: FISIKA (V1)

                                          SEPTEMBER 2022

                          MARKING GUIDELINES/NASIENRIGLYNE

 MARKS/ PUNTE: 150

    These marking guidelines consist of 16 pages including the cognitive table/
    Hierdie nasienriglyne bestaan uit 16 bladsye wat die kognitiewe tabel insluit.

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                             NSC/NSS – Marking Guidelines/ Nasienrigliyne

  QUESTION 1/VRAAG 1

  1.1            C                                                                                      (2)

  1.2            D                                                                                      (2)

  1.3            A                                                                                      (2)

  1.4            D                                                                                      (2)

  1.5            B                                                                                      (2)

  1.6            C                                                                                      (2)

  1.7            D                                                                                      (2)

  1.8            A                                                                                      (2)

  1.9            C                                                                                      (2)

  1.10           B                                                                                      (2)
                                                                                                         [20]

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  QUESTION 2 /VRAAG 2

  2.1

            Accept the following symbols
            N                    FN/Normal/Normal force
                                  Normaal/Normaalkrag
            F                    FA/Applied force force/ 5000 N
                                  FA/Toegepaste krag/ 5000 N
            w OR Fg‖ and Fg┴     Fg/mg/weight/ gravitational force
                                  Fg/mg/gewig/ gravitasiekrag                                         (3)

  2.2      Fg‖ = w sinθ 
           5000 = w sin 15 o 
           w = 19318,52 N
           ME = (19318,52) – 800 
                    9,8
               = 1171,28 kg                                                                          (4)

  2.3.1    Increases/Verhoog.                                                                        (1)

  2.3.2    Crate is moving at constant acceleration/Die krat beweeg teen `n konstante
           versnelling                                                                               (1)

  2.4.1    The force or the component of a force which a surface exerts on an object
           with which it is in contact, and which is perpendicular to the surface.
           /Die krag of die komponent van die krag wat `n voorwerp op `n oppervlakte
           uitoefen waarmee dit in kontak is, en wat loodreg op die oppervlakte is. 
           (2 or/of 0)                                                                                (2)

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  2.4.2    Fg‖ = w sinθ
               = (98) (sinθ)
           Fg┴ = w cosθ
                = (98) (cosθ)
           7 Fg‖ = 4 Fg┴ 
           7 (98) (sinθ) = 4 (98) (cosθ) 
            tanθ = 0,5714
             θ = 25,53 o 
           Note: By using tanθ - 2/3 marks
           Nota: Gebruik van tanθ - 2/3 punte
           tan θ = 4 
                   7
           θ = 25,53 o                                                                                (3)
                                                                                                      [14]

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  QUESTION 3/ VRAAG 3

  3.1      Motion during which the only force acting on an object is the force of gravity.
           Beweging waar die enigste krag wat op die voorwerp inwerk gravitasiekrag
           is. (2 or/of 0)                                                                           (2)

  3.2.1    1,4 s                                                                                      (1)

  3.2.2    9,8 m·s-2  downwards / afwaarts                                                          (2)

  3.2.3    1,4 + 0,8 = 2,2 s                                                                         (2)

  3.3.1    vf = vi + aΔt 
           0 = vi + (-9,8) (1,4) 
           vi = 13,72 m·s-1                                                                           (3)

  3.3.2    POSITIVE MARKING FROM QUESTION 3.3.1 and 3.2.3/
           POSITIEWE NASIEN VANAF 3.3.1 and 3.2.3
           ∆y = vi∆t + ½ a∆t2 
           ∆y = (13,72)( 2,2) + ½ (-9,8 )( 2,22) 
              = 6,47 m                                                                                (3)
  3.4      POSITIVE MARKING FROM QUESTION 3.2.3
           POSITIEWE NASIEN VANAF 3.2.3

           Marking Criteria
            Labelling -9,8 and 2,2 on the graph 
            Shape and graph lies below x axis 
           Nasien kriteria
            Toon -9,8 en 2,2 op die grafiek 
            Vorm van grafiek en grafiek lê onder die x-as                                            (2)

  3.5      Change in the velocity 
           Verandering is die snelheid                                                                (1)
                                                                                                      [16]

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  QUESTION 4 / VRAAG 4

  4.1     The net force acting on an object is equal to rate of change of momentum of
          the object
          Die netto krag wat op `n voorwerp inwerk is gelyk aan die verandering in die
          momentum van die voorwerp
           (2 or/of 0)                                                                                 (2)

  4.2     Fnet ∆t = ∆P 
          (-1,2)(∆t) = (- 0,24) 
          ∆t = 0,2 s                                                                                  (3)

  4.3     OPTION 1                                   OPTION 2
          Fnet ∆t = ∆P = m(vf – vi )                 ∆P = m(vf – vi )
          (-1,2) (0,2) = 0,6 (vf - 0,5)             (-0,24) = 0,6 (vf - 0,5) 
          vf = 0,1 m·s-1 towards east               vf = 0,1 m·s-1 towards east                      (3)

  4.4     Ekbefore = Ekafter   any one / enige een
           Ek = ½ mv2
          0,042 = ½ (0,8)(vf)2 
          vf = 0,32 m·s-1.                                                                            (3)
                                                                                                      [11]

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  QUESTION 5 / VRAAG 5

  5.1     The net/total work done on an object is equal to the change in the object’s
          kinetic energy. 
           / Die netto werk verrig op `n voorwerp is gelyk aan sy verandering in
          kinetiese energie.
          OR
          The work done on an object by a resultant/net force is equal to the change in
          the objects kinetic energy. 
           / Die werk verrig op `n voorwerp deur `n netto/resultante krag is gelyk aan sy
          verandering in kinetiese energie.                                                            (2)

  5.2     Wnc = ∆EK + ∆Ep                      any one / enige een
          Wnc = ( EKf - EKi ) + ( Epf – Epi )
           0  = (EKf – 0) + ( 0 – (75)(9,8)(25)) 
           EKf = 18375 J 
                                                                                                       (4)

  5.3     POSITIVE MARKING FROM QUESTION 5.2
          POSITIEWE NASIEN VANAF 5.2
          Wnc = ∆EK + ∆Ep
          Wnc = ( EKf - EKi ) + ( Epf – Epi )
              = (0-18375) + (0 – (75)(9,8)(20) 
              = (- 18375) + (-14700)
              = - 33075 J                                                                             (3)
  5.4     33075 J                                                                                     (1)
  5.5     POSITIVE MARKING FROM QUESTION 5.3
          POSITIEWE NASIEN VANAF 5.3
          Wnc = F∆x cosθ 
          - 33075  = FT x 20 cos180̊ 
          FT = 1653,75 N 
                                                                                                       (4)
                                                                                                      [14]

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  QUESTION 6 / VRAAG 6

  6.1     The change in frequency (or pitch)  of the sound detected by a listener
          because the sound source and the listener have different velocities relative to
          the medium of sound propagation. / Die verandering in die frekwensie
          (toonhoogte) van die waargenome klank deur die luisteraar agv die klankbron
          en die luisteraar wat verskillende snelhede relatief tot mekaar het.
          OR/OF
          An (apparent) change in (observed/detected) frequency (pitch), as a result
          of the relative motion between a source and an observer  (listener).
          'n (Skynbare) verandering in(waargenome) frekwensie  (toonhoogte), as
          gevolg van die relatiewe beweging tussen die bron en 'n
          waarnemer/luisteraar.                                                                      (2)

  6.2     OPTION 1                                  OPTION 2
          f(recorded) = (4)                        f(recorded) = (2)         
                              -4
                       (1 x 10 )                                 (5 x 10-5)
                    = 40000 Hz                                = 40000 Hz
                    = 40 kHz                                  = 40 kHz
          40-38 = 2 kHz                            40-38 = 2 kHz                                     (2)

  6.3     When the dolphin is moving towards the recorder, there is a compression of
          the wave fronts, more waves are arriving per second. 
          Wanneer die dolfyn na die klankopnemer beweeg vind `n kompressie van
          golffronte plaas  en meer golwe arriveer per sekonde                                       (2)

  6.4     OPTION 1 / OPSIE 1

                           

          40000 = (1500+0)  38000 
                     (1500-vs)
          Vs = 71,43 m·s-1                                                                            (5)

  6.5     The light coming from the distant planet observed from the Earth has a lower
          frequency and therefore a longer wavelength. 
          Therefore it is shifted towards the red end of the spectrum. 
          Die lig vanaf verafgeleë planete wat observeer word van die aarde het `n laer
          frekwensie en langer golflengte , daarom vind `n verskuiwing na die rooi
          gedeelte van die speltrum plaas                                                             (2)
                                                                                                      [13]

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  QUESTION 7 / VRAAG 7

  7.1       The magnitude of the electrostatic force exerted by one point charge (Q 1) on
            another point charge (Q2) is directly proportional to the product
            of the magnitudes of their charges and inversely proportional to the square
            of the distance (r) between them 
            / Die grootte van die elektrostatiese krag wat deur een puntlading (Q1) op 'n
            ander puntlading (Q2) uitgeoefen word, is direk eweredig aan die produk van
            die groottes van die ladings  en omgekeerd eweredig aan die kwadraat van
            die afstand (r) tussen hulle                                                             (2)

  7.2

             Accept the following symbols
             T     Tension in the spring / Spanning in die tou
             F     Electrostatic force of repulsion / Elektrostatiese
                    afstotingskrag
             w     Fg/mg/weight/Fearth on sphere/gravitational force
                    Fg/mg/gewig/F aarde op sfeer/gravitasiekrag force
                                                                                                      (3)

  7.3.1     Forces are in equilibrium / Kragte is in ewewig
            w = mg
               = (0,0009)(9,8) 
               = 0,0088 N
            tan 45 ̊ = (F ) 

                       (0,0088)

                     =0,008 N repulsion to the right. / afstotend na regs                            (3)

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  7.3.2     POSITIVE MARKING FROM QUESTION 7.1.3
            POSITIEWE NASIEN VANAF 7.1.3
                 kQ1Q 2
            F=             
                   r2
            0,0088 = (9x 109) ( Q)2 
                          (0,04)2
            Q = 3,8 x 10-8 C  Accept the range 3,8 to 3,9 x 10-8 C
            Q = 3,8 x 10-8 C  Aanvaar omvang 3,8 tot 3,9 x 10-8 C                                     (3)

  7.4.1          kQ1Q 2
            F=
                   r2
            ‘F’ at ‘C’ due to A
            FCA =( 9,0 x 109) (4 x 10-6 ) (8 x 10-6 ) 
                              0,52
                 = 1,152 N to the right / na regs
            ‘F’ at ‘C’ due to B
            FCB =( 9,0 x 109) (4 x 10-6 ) (3x 10-6 ) 
                              0,22
                 = 2,7 N to the left / na links
            Net electrostatic force at C =1,152 -2,7 = - 1,548 N· to the left 
            Netto elektrostatiesekrag by C =1,152 -2,7 = - 1,548 N· na links                          (3)
                                                                                                      [14]

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  QUESTION 8 / VRAAG 8

  8.1      Internal resistance is the resistance found inside the battery due to the
           movement of charges. 
           Interne weerstand is die weestand in die battery as gevolg van die beweging
           van lading                                                                                  (2)

  8.2      V2 = 2V3
           OR
           V3 = ½ V2                                                                                   (1)

  8.3      V1 = V 2 + V 3
           21 = V2 + ½ V2
           V2 = 14 V 
           V3 = 7 V                                                                                   (2)

  8.4.1    Vlost = 24-21
                 =3V
           Vlost = Ir 
           3 = 3r 
           r     =1 Ω                                                                                 (4)

  8.4.2    OPTION 1                                   OPTION 2
           R= V                                     R= V 
               I                                         I
           V2 = 14 V                                 V3 = 7 V
           14 = 3R                                  7 = 3RT
            R = 4,67 Ω                              7 = (3)(R) 
                                                             2
                                                      R = 4,67 Ω 
                                                                                                       (3)

  8.5      P = VI
           60 = 12 x I 
            I=5A
           Q = It 
             = 5x2x60 
             = 600 C                                                                                  (4)
                                                                                                      [16]

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  QUESTION 9 / VRAAG 9

  9.1.1    Slip rings / Sleepringe                                                                   (1)

  9.1.2    Slip rings keep the armature in contact with the brushes, and thus ensure
           flow of current to the external circuit. 
           Sleepringe hou die spoel in kontak met die koolstofborsels en verseker die
           vloei van stroom na die eksterne stroombaan                                              (2)

  9.2      Induction of an electromotive force by the motion of conductor across a
           magnetic field.
           OR
           Whenever there is a change in the magnetic flux linkage with a conductor an
           emf is induced. 
           Induksie van 'n elektromotoriese krag deur die beweging van 'n geleier oor 'n
           magnetiese veld.
           OF
           Wanneer daar `n verandering in die magnetiese vloedkoppeling is met `n
           geleier waarin `n emk dan geïnduseer word                                                  (2)

  9.3      A to B / A na B                                                                           (1)

  9.4      Remains the same  Bly dieselfde                                                          (1)

  9.5      Coil will be parallel to the field / Spoel sal parallel aan die veld wees                (2)

  9.6.1             V max
           Vrms =           
                      2
                     17
           Vrms =       
                     2
           Vrms = 12,02 V 
                   V max
           Vwgk =
                      2
                     17
           Vwgk =
                     2
           Vwgk = 12,02 V
                                                                                                      (3)

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  9.6.2    POSITIVE MARKING FROM                     POSITIEWE NASIEN VANAF
           QUESTION 9.2.1                            VRAAG 9.2.1
           Pave = Irms x Vrms                       Pgem = Iwgk x Vwgk 
           15 = Irms x 12,02                        15 = Iwgk x 12,02 
           Irms = 1,25 A                             Iwgk = 1,25 A
                                                               I max
                                                     I rms            
                     I max                                       2
           I rms            
                       2                                       I max
                     I max                           1,25 =            
           1,25 =                                               2
                       2                             Imaks = 1,77 A 
           Imax = 1,77 A                                                                                     (5)

  9.6.3    POSITIVE MARKING FROM QUESTION 9.2.2
           POSITIEWE NASIEN VANAF VRAAG 9.2.2

           Marking Criteria / Nasien kriteria
            Labelling Imax on the graph / Imaks aangedui op die grafiek
            Labelling Irms on the graph / Iwgk aangedui op die grafiek
                                                                                                              (2)
                                                                                                             [19]

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 QUESTION 10 / VRAAG 10

 10.1       Threshold frequency / Drumpelfrekwensie                                               (1)

 10.2      E = W o + Ek(max)    any one / enige een 
           E = hfo + ½ mv2
           (6,63 x 10-34) (5 x 1015) = (6,63 x 10-34)( fo) + (½ x 9,1 x 10-31)(5 x 105)2
           f0 = 4,8 X 1015 Hz                                                                     (5)

 10.3.1    The work function of a metal is the minimum energy that an electron needs
           to be emitted from the metal surface 
           Die werksfunksie van `n metaal is die minimum hoeveelheid energie
           benodig om elektrone uit die oppervlakte van die metaal vry te stel
           (2 or/of 0)                                                                             (2)

 10.3.2    Wo = hfo 
           9,44 X 10 -19 = (6,63 x 10-34)( fo) 
           fo = 1,42 X 1015 Hz                                                                    (3)

 10.3.3    The frequency of blue light is less than that of threshold frequency of
           selenium,and the frequency of ultraviolet light (found in day light) is
           greater than threshold frequency of selenium.
           Die frekwensie van blou lig is laer as die drumpelfrekwensie van
           selenium,en die frekwensie van unltraviolet lig (wat in die dag gekry
           word) is groter as die drumpelfrekwensie van selenium.                                 (2)
                                                                                                  [13]

                                                                            TOTAL/TOTAAL:         150

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- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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