# Physical Sciences Grade 12 P1 Northern Cape Prelim 2024 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the Northern Cape Prelim Exam 2024, 40 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/nw-physical-sciences-grade-12-september-2024-p1-and-memo/d14be956-dd2a-44f0-bf09-55590c6d82ce
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2024
- Exam period: Northern Cape Prelim Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 40

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## About this document

Physical Sciences · Grade 12 · Northern Cape Prelim Exam · 2024. Memorandum, 40 pages. Read online or download the PDF.

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## Document text

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### Page 1

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                                             —————————————————————
                                             DEPARTMENT OF EDUCATION
                                             —————————————————————
                                             DEPARTEMENT VAN ONDERWYS
                                             —————————————————————
                                             LEFAPHA LA THUTO
                                             —————————————————————
                                             ISEBE LEZEMFUNDO
                                             —————————————————————

                 PROVINSIALE VOORBEREIDENDE EKSAMEN/
                  PROVINCIAL PREPARATORY EXAMINATION

                                    GRAAD/GRADE 12

                 FISIESE WETENSKAPPE/PHYSICAL SCIENCES

                                    VRAESTEL/PAPER 1

                                          FISIKA/PHYSICS
                                        (FISIKA/PHYSICS)
                                         SEPTEMBER 2024

PUNTE/MARKS: 150

TYD/TIME: 3 uur/hours

             Hierdie vraestel bestaan uit 16 bladsye en 3 gegewensblaaie./
             This question paper consists of 16 pages and 3 data sheets.

Kopiereg voorbehou/Copyright reserved                      Blaai om asseblief/Please turn over

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INSTRUCTIONS AND INFORMATION

1.      Write your name on the ANSWER BOOK.

2.      This question paper consists of 10 questions. Answer ALL the questions in the
        ANSWER BOOK.

3.      Start EACH question on a NEW page in the ANSWER BOOK.

4.      Number the answers correctly according to the numbering system used in this
        question paper.

5.      Leave ONE line between two subquestions, e.g. between QUESTION 2.1 and
        QUESTION 2.2.

6.      You may use a non-programmable calculator.

7.      You may use appropriate mathematical instruments.

8.      Show ALL formulae and substitutions in ALL calculations.

9.      Round off your FINAL numerical answers to a minimum of TWO decimal places.

10.     Give brief motivations, discussions, etc. where required.

11.     You are advised to use the attached DATA SHEETS.

12.     Write neatly and legibly.

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QUESTION 1: MULTIPLE-CHOICE QUESTIONS

Various options are provided as possible answers to the following questions. Each
question has only ONE correct answer. Choose the answer and write only the letter
(A–D) next to the question numbers (1.1 to 1.10) in the ANSWER BOOK, e.g. 1.11 E.

1.1     Which ONE of the following physical quantities is defined as the rate of
        change of velocity?

        A       Impulse

        B       Net force

        C       Inertia

        D       Acceleration                                                            (2)

1.2     According to Newton's Third Law of Motion, the reaction force to the weight
        of a book lying on a table is the …

        A       normal force.

        B       force of the book on Earth.

        C       force of Earth on the book.

        D       force of the book on the table.                                         (2)

1.3     A 300 kg bag of cement and a 30 kg iron sphere are dropped simultaneously
        from the roof of a building. Ignore the effects of air friction.

        When they are 9 m above the ground, they will have the same …

        A       momentum.

        B       acceleration.

        C       kinetic energy.

        D       potential energy.                                                       (2)

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1.4     A ball of mass m strikes a wall perpendicularly at a speed v. After the
        collision, the ball moves in the opposite direction at the same speed v, as
        shown in the diagram below.

                                                      wall

                                           v
                              m

                                       v
                                                m

        Which ONE of the following represents the magnitude of the change in
        momentum of the ball?

        A       0

        B       mv

        C       2mv

        D       2mv2                                                                    (2)

1.5     The kinetic energy of a car moving at a constant velocity of 2v is K. The
        velocity of the car then changes to a constant velocity of 4v.

        Which ONE of the following represents the kinetic energy of the car at a
        constant velocity of 4v?

        A       ⅛K

        B       ¼K

        C       4K

        D       8K                                                                      (2)

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1.6     The siren of a police car travelling at 20 m·s-1 emits sound waves of
        frequency f Hz.

        The frequency observed by a pedestrian standing on the road when the
        police car moves towards him, will be …

        A       0 Hz.

        B       smaller than f Hz.

        C       equal to f Hz.

        D       greater than f Hz.                                                  (2)

1.7     The diagram below represents a positive point charge.

        Points R, S and T are at different distances from the charge.

                                             R
                                             ●

                                       T
                                       ●                +

                                                        ●
                                                        S
        The magnitude of the electric field at a point is the …

        A       greatest at point R.

        B       greatest at point S.

        C       greatest at point T.

        D       same at point R, S and T.                                           (2)

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1.8     In the circuit represented below, the resistance of a variable resistor is
        INCREASED.

                                              rr

                                          V

                                            A

        How would this increase affect the readings on the voltmeter and ammeter?

                     VOLTMETER READING                  AMMETER READING

        A                 Increases                        Decreases

        B                Decreases                          Increases

        C                 Increases                         Increases

        D                Decreases                         Decreases
                                                                                       (2)

1.9     Which ONE of the energy conversions below takes place when an AC
        motor is in operation?

        A      Electrical energy to mechanical energy

        B      Mechanical energy to electrical energy

        C      Kinetic energy to mechanical energy

        D      Heat energy to mechanical energy                                        (2)

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1.10    When a clean metal plate is irradiated with red light of sufficient energy,
        photoelectrons are emitted.

        The red light is now replaced with blue light of the same intensity.

        This change will …

        A       increase the number of photoelectrons emitted per second.

        B       decrease the number of photoelectrons emitted per second.

        C       increase the kinetic energy of the emitted photoelectrons.

        D       decrease the kinetic energy of the emitted photoelectrons.                 (2)
                                                                                          [20]

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QUESTION 2 (Start on a new page.)

Two blocks of masses 9 kg and 4 kg are connected by a light, inextensible string. A
constant force, F, acting at 75° to the horizontal, is applied to the 9 kg block as shown
in the diagram below. The string runs over a frictionless pulley.

                                                              F

                                      4 m·s-1

                                                   75o
                                      9 kg

                                                                   4 kg

The 9 kg block moves at a CONSTANT velocity of 4 m·s-1 while experiencing a
frictional force of 2,5 N.

2.1     State Newton's First Law of Motion in words.                                         (2)

2.2     Draw a labelled free-body diagram for the 9 kg block.                                (5)

2.3     Calculate the magnitude of the force F acting on the 9 kg block.                     (5)
                                                                                            [12]

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QUESTION 3 (Start on a new page.)

Object A is projected vertically upwards from the ground. It takes 0,8 s to pass a
window which is 1,5 m high and 8 m above the ground. It strikes a balcony at a velocity
of 1,4 m·s-1 and falls back to the ground.

At the same time, object B is projected vertically downwards at a velocity of 8 m·s-1.

Ignore the effects of air friction.

                                          balcony
                                                 B

                                      1,5 m

                                           8m

                                 A
                                      ground

3.1     Define the term projectile.                                                          (2)

3.2     Calculate the:

        3.2.1        Velocity of object A at the bottom edge of the window when moving
                     upwards                                                                 (4)

        3.2.2        Velocity with which object A is projected from the ground               (3)

        3.2.3        Height above the ground at which object A and B will pass each
                     other                                                                   (6)

3.3     Draw a position-time graph (not to scale) for the entire motion of objects A
        and B on the same set of axes from the moment they are projected.

        Label the graphs and clearly indicate the following:

           Height where the objects pass each other
           Time the objects pass each other as t                                           (4)
                                                                                           [19]

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QUESTION 4 (Start on a new page.)

A toy trolley of mass 95 g is moving east at a speed of 2,45 m·s-1. It collides with a
stationary wooden block of mass 120 g, which is suspended with a rope, as shown
in the diagram below.

The impact causes the block to move to a maximum height of 0,15 m from its original
position, while the trolley continues moving eastwards.

Ignore the effects of friction and air friction.

      2,45 m·s-1                                      0,15 m
       95 g                      120 g

4.1       State the principle of conservation of linear momentum in words.                  (2)

4.2       Draw a force diagram for the block at a height of 0,15 m above the ground.        (2)

4.3       Calculate the speed of the trolley immediately after the collision.               (5)

4.4       The contact time between the trolley and the block is 0,08 s.

          Calculate the magnitude of the force applied on the trolley by the block.        (3)
                                                                                          [12]

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QUESTION 5 (Start on a new page.)

A skier of mass 100 kg starts from rest at point B, which is 30 m below point A, and
moves down a frictionless curve to point C.

The skier passes point C and moves up a rough plane inclined at 30° to the
horizontal. Ignore the effects of air friction.

             A
             ●
                         30 m

      50 m
                     B

                                                     30o
                                           ●
                                           C

5.1     Write down the energy conversion of the skier from point B to C.                  (1)

5.2     Define the term isolated system.                                                  (2)

5.3     Use ENERGY PRINCIPLES to calculate the speed of the skier at point C.             (4)

5.4     The skier experiences a frictional force of 200 N on the inclined plane.

        5.4.1        Calculate the maximum height reached by the skier from point C.      (6)

        5.4.2        If the angle is reduced to 20°, will the maximum height be
                     GREATER THAN, SMALLER THAN or EQUAL TO the maximum
                     height calculated in QUESTION 5.4.1?

                     Give a reason for the answer.                                       (2)
                                                                                        [15]

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QUESTION 6 (Start on a new page.)

A man is sitting in a train which is travelling at a constant velocity. The siren of the
train emits sound waves of frequency 2 000 Hz.

A detector placed on the railway line records a frequency of 2 450 Hz. The train takes
0,5 s to reach the detector. Assume the speed of sound in air is 342 m·s-1.

6.1     Define the phenomenon described above.                                              (2)

6.2     Name any medical instrument that makes use of the phenomenon in
        QUESTION 6.1.                                                                       (1)

6.3     Calculate the distance between the train and the detector.                          (5)

6.4     Draw a frequency versus time graph (not to scale) of the frequency heard by
        the man sitting in the train as it moves towards and away from the detector.

        Indicate the values of frequency and time on the graph.                             (2)

6.5     What is the significance of red shift?                                              (1)
                                                                                           [11]

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QUESTION 7 (Start on a new page.)

Three charged spheres, A, B and C, with charges of -6 nC, +9 nC and +12 nC
respectively, are placed on rubber stands as shown below.

                      A                   B                C
                     -6 nC               +9 nC             +12 nC

                              10 cm              15 cm

7.1     Can metal stands be used instead of rubber stands?

        Write down only YES or NO.

        Give a reason for the answer.                                                     (2)

7.2     State Coulomb's law in words.                                                     (2)

7.3     Calculate the net force acting on charge C.                                       (5)

7.4     Charge A and B are brought into contact and then separated.

        Charge A is returned to its original position, while charge B is removed.

        7.4.1    In which direction did electrons flow?

                 Choose from A to B or B to A.                                            (2)

        7.4.2    Calculate the number of electrons transferred to or from charge A.       (4)

        7.4.3    Point X is placed between charge A and C.

                 Calculate the distance between charge A and point X where the net
                 electric field is equal to zero.                                        (4)
                                                                                        [19]

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QUESTION 8 (Start on a new page.)

A battery of emf 12 V and an internal resistance of 0,8 Ω is connected to three
resistors of resistance R Ω, 6 Ω and 4 Ω. A high resistance voltmeter and an ammeter
of negligible resistance are also connected in the circuit, as shown below.

The reading on the ammeter is 0,5 A.

                                                V

                                                R

                                                     r

                     0,5 A   A

                                                6Ω           4Ω

8.1     Define the term internal resistance.                                            (2)

8.2     Calculate the:

        8.2.1        Reading on the voltmeter                                           (3)

        8.2.2        Resistance of resistor R                                           (6)

        8.2.3        Energy dissipated by resistor R in 3 minutes                       (4)

8.3     How would the reading on the voltmeter change if resistor R is removed?

        Write down INCREASES, DECREASES or REMAINS THE SAME.

        Explain the answer.                                                             (3)
                                                                                       [17]

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QUESTION 9 (Start on a new page.)

A simplified diagram of an electric machine is shown below.

9.1     Is this electric machine a generator or an electric motor?

        Give a reason for the answer.                                                    (2)

9.2     Write down the names of the components labelled A, B, C and D.                   (1)

9.3     Give a reason why carbon is preferred over iron for the brushes in electric
        machines.                                                                        (1)

9.4     In which direction is the current flowing?

        Choose from A to B or B to A.                                                    (2)

9.5     The graph below of voltage vs time was obtained from an alternating current
        generator.

        9.5.1        Calculate the frequency of this voltage.                            (2)

        9.5.2        Calculate the average power generated if the generator produces
                     a maximum current of 2 A.                                          (5)
                                                                                       [13]

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QUESTION 10 (Start on a new page.)

10.1    The table below shows different metals with their respective threshold
        frequencies.

                           Metal          Threshold frequency (Hz)
                             A                     2,06 × 1014
                             B                     1,18 × 1014
                             C                     0,06 × 1014
                             D                     8,52 × 1014

        Light of frequency 3,15 × 1014 Hz is radiated on each metal.

        10.1.1       Define the term threshold frequency.                                        (2)

        10.1.2       In which metal(s), A, B, C or D, will the photoelectric effect not take
                     place?

                     Give a reason for the answer.                                               (2)

        10.1.3       Calculate the highest maximum speed of the ejected electrons.               (5)

        10.1.4       If the intensity of light radiated is decreased, what will happen to the
                     speed of the electrons calculated in QUESTION 10.1.3?

                     Choose from INCREASES, DECREASES or REMAINS THE
                     SAME.                                                                       (1)

10.2    Explain the formation of the atomic emission spectrum.                                   (2)
                                                                                                [12]

                                                                                    TOTAL:      150

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                     DATA FOR PHYSICAL SCIENCES GRADE 12
                               PAPER 1 (PHYSICS)

                 GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
                            VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

          NAME/NAAM                SYMBOL/SIMBOOL     VALUE/WAARDE
Acceleration due to gravity
                                         g                 9,8 m·s-2
Swaartekragversnelling
Universal gravitational constant
                                         G           6,67 x 10-11 N·m2·kg-2
Universele gravitasiekonstante
Radius of the Earth
                                         RE              6,38 x 106 m
Radius van die Aarde
Mass of the Earth
                                         M              5,98 x 1024 kg
Massa van die Aarde
Speed of light in a vacuum
                                         c              3,0 x 108 m·s-1
Spoed van lig in 'n vakuum
Planck's constant
                                         h              6,63 x 10-34 J·s
Planck se konstante
Coulomb's constant
                                         k            9,0 x 109 N·m2·C-2
Coulomb se konstante
Charge on electron
                                         e-              -1,6 x 10-19 C
Lading op elektron
Electron mass
                                         me             9,11 x 10-31 kg
Elektronmassa

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TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

 v f  vi  a t                                     x  v i t  21 at 2 or y  v i t  21 at 2
                                                           v  vi              v  vi 
 v f 2  vi2  2ax or v f  v i  2ay
                                2        2
                                                     x   f       t or y   f       t
                                                           2                   2 

FORCE/KRAG

 Fnet  ma                                           p  mv
 fs max = μsN                                        fk = μkN
 Fnet t  p
                                                     w  mg
 p  mv f  mv i
          m1m 2                              m1m 2             M                         M
  FG                   or/of          F=G           g =G                or/of       g =G 2
           d2                                 r2               d2                        r

WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING

 W  Fx cos                                        U mgh               or/of      EP  mgh

                                                     Wnet  K            or/of      Wnet  Ek
    1                                   1
 K  mv 2            or/of          Ek  mv 2
    2                                   2
                                                     K  K f  K i       or/of      Ek  Ekf  Eki
                                                          W
 Wnc  K  U or Wnc  Ek  Ep                    P
                                                          t
 Pave = Fvave       /    Pgemid = Fvgemid

WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG

                                                          1
 vf                                                T
                                                          f
        v  vL                         v  vL                                    c
 fL           fs               fL           fb     E  hf         or   E h
        v  vs                         v  vb                                    

 E = Wo + Ek(max) or/of E = W o + K max where/waar
                                           1                    1
 E  hf and/en W0  hf 0 and/en E k (max) = mv max
                                               2                    2
                                                   or/of K max = mv max
                                           2                    2

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ELECTROSTATICS/ELEKTROSTATIKA

      kQ 1Q 2                                               kQ
 F                                                    E
        r2                                                   r2
       W                                                    F
 V                                                    E
       q                                                    q

       Q           or/of            Q
  n=                           n
       e                            qe

ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE

 R
       V                                               emf ( ε )= I(R + r)
       I

 R s  R1  R 2  ...
  1   1   1                                            q I t
           ...
 R p R1 R 2

 W = Vq                                                     W
                                                       P
                                                            Δt
 W = VI  t
                                                       P = VI
 W = I2R  t
                                                       P = I 2R
       V 2 Δt
 W=                                                         V2
        R                                              P
                                                            R

ALTERNATING CURRENT/WISSELSTROOM

                                                       Pav e  Vrms I rms       /   Pgemid  Vwgk I wgk
           I max                              I maks
 I rms                    /        I wgk 
             2                                   2
                                                       Pav e  Irms
                                                                2
                                                                   R            /   Pgemid  I 2wgk R

            Vmax                              Vmaks
 Vrms                     /        Vwgk                        2
                                                               Vrms
                                                                                                2
                                                                                               Vwgk
               2                                2      Pav e               /       Pgemid 
                                                                R                               R

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                                            —————————————————————
                                            DEPARTMENT OF EDUCATION
                                            —————————————————————
                                            DEPARTEMENT VAN ONDERWYS
                                            —————————————————————
                                            LEFAPHA LA THUTO
                                            —————————————————————
                                            ISEBE LEZEMFUNDO
                                            —————————————————————

                 PROVINCIAL PREPARATORY EXAMINATION/
                 PROVINSIALE VOORBEREIDENDE EKSAMEN

                                        GRADE/GRAAD 12

                             PHYSICAL SCIENCES: PHYSICS
                             FISIESE WETENSKAPPE: FISIKA

                                        PAPER/VRAESTEL 1

                                        SEPTEMBER 2024

                       MARKING GUIDELINES/NASIENRIGLYNE

MARKS/PUNTE: 150

                     These marking guidelines consist of 17 pages./
                      Hierdie nasienriglyne bestaan uit 17 bladsye.

Copyright reserved/Kopiereg voorbehou                      Please turn over/Blaai om asseblief

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Fisiese Wetenskappe/Graad 12 Marking Guidelines/Nasienriglyne

QUESTION 1/VRAAG 1

1.1       D                                                                             (2)

1.2       B                                                                             (2)

1.3       B                                                                             (2)

1.4       C                                                                             (2)

1.5       C                                                                             (2)

1.6       D                                                                             (2)

1.7       B                                                                             (2)

1.8       A                                                                             (2)

1.9       A                                                                             (2)

1.10      C                                                                             (2)
                                                                                         [20]

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Fisiese Wetenskappe/Graad 12 Marking Guidelines/Nasienriglyne

QUESTION 2/VRAAG 2

2.1       Marking criteria/Nasienkriteria
          If any of the underlined key words/phrases in the correct context is
          omitted, deduct one mark./Indien enige van die onderstreepte sleutel
          woorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.

          An object will remain in its state of rest or motion at constant velocity
          unless a (non-zero) resultant force/net force acts on it. 
          'n Voorwerp sal in sy toestand van rus of beweging teen konstante
          snelheid bly, tensy 'n (nie-nul) resulterende krag/netto krag daarop
          inwerk.                                                                       (2)

2.2                N            FA                              N

             f                              OR
                                        T         f                               T

                                                      FA

                   w
                                                                w
          Force diagram 0/2./Kragte diagram 0/2.
          Accepted labels/Aanvaarde benoemings
          w        Fw /Fg/mg/88,2 N/Weight/gravitational force
                   Fw /Fg/mg/88,2 N/Gewig/gravitasiekrag
          T        FT /Tension/Spanning
          Fapplied F /Applied force/FA
                   F /Toegepaste krag/FA
          f        Ff / fk /frictional force/kinetic frictional force
                   Ff / fk /wrywingskrag/kinetiese wrywingskrag
          N        FN/Normal/Normaal
          Notes/Aantekeninge
         • Mark is awarded for label and arrow./Punt word toegeken vir byskrif en
             pyltjie.
         • Do not penalise for length of arrows/Moenie vir die lengte van die
             pyltjies penaliseer nie.
         • If arrows do not touch the dot/Indien pyle nie die kolletjie raak nie:
             Max/Maks 4
                              5
         • Any other additional force(s)/Enige ander addisionele krag(te) :
             Max/Maks: 4
                               5
         • If everything correct, but no arrows/Indien alles korrek, maar geen
             pyltjies Max/Maks: 4
                                        5                                                 (5)

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2.3       EAST AS POSITIVE                     EAST AS NEGATIVE
          OOS AS POSITIEF                      OOS AS NEGATIEF
          4 kg mass/4 kg massa                 4 kg mass/4 kg massa
          Fnet = ma                            Fnet = ma
          T – w = ma           (Any one)      T – w = ma             (Any one)
          T – mg = ma                          T – mg = ma
          T – (4)(9,8) = (4)(0)               T – (4)(9,8) = (4)(0) 
          T = 39,2 N                           T = 39,2 N

          9 kg mass/9 kg massa                 9 kg mass/9 kg massa
          Fnet = ma                            Fnet = ma
          Fx + T + f = ma                      Fx + T + f = ma
          -Fcos75o + 39,2 + 2,5 = (9)(0)     Fcos75o - 39,2 - 2,5 = (9)(0) 
          F = 161,12 N                        F = 161,12 N 
          OR/OF                                OR/OF
          -Fsin15o + 39,2 + 2,5 = (9)(0)     Fsin15o - 39,2 - 2,5 = (9)(0) 
          F = 161,12 N                        F = 161,12 N                             (5)
                                                                                         [12]

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Fisiese Wetenskappe/Graad 12 Marking Guidelines/Nasienriglyne

QUESTION 3/VRAAG 3
3.1    Marking criteria
       If any of the underlined key words/phrases in the correct context is
       omitted deduct 1 mark./Indien enige van die onderstreepte sleutel-
       woorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
       A projectile is an object which has been given an initial velocity and then
       it moves under the influence of gravitational force/gravity/weight only.
       'n Projektiel is 'n voorwerp wat 'n beginsnelheid snelheid gegee is en
       dan beweeg dit slegs onder die invloed van gravitasiekrag/swaartekrag/
       gewig.                                                                            (2)

3.2.1     UPWARDS AS POSITIVE                  DOWNWARDS AS POSITIVE
          OPWAARTS POSITIEF                    AFWAARTS POSITIEF
          ∆y = vi∆t + ½ a∆t2✓                  ∆y = vi∆t + ½ a∆t2✓
          1,5 ✓= vi (0,8) + ½ (-9,8)(0,8)2✓    -1,5 ✓= -vi(0,8) + ½ (9,8)(0,8)2✓
           vi = 5,80m.s-1upwards /opwaarts✓    vi = 5,80m.s-1upwards /opwaarts✓           (4)

3.2.2     POSITIVE MARKING FROM QUESTION 3.2.1
          POSITIEWE NASIEN VANAF VRAAG 3.2.1
          OPTION 1/OPSIE 1
          UPWARDS AS POSITIVE                  DOWNWARDS AS POSITIVE
          OPWAARTS POSITIEF                   AFWAARTS POSITIEF
          vf2 = vi2 + 2aΔy✓                   vf2 = vi2 + 2aΔy ✓
          (5,80)2 = ( vi)2+ 2 (-9,8)(8)✓      -(5,80)2 = -(vi)2 + 2 (9,8)8✓
          vi = 13,80m.s upwards/opwaarts✓ vi = 13,80m.s-1upwards/opwaarts✓
                          -1

          OPTION 2/OPSIE 2
          ½ m v2i + mghi = ½ m v2f + mghf ✓
          ½ mvi 2 + 0 = ½ m(5,80)2 + m(9,8)(8)✓
          vi =13,80 m.s-1upwards/opwaarts                                               (3)

3.2.3     POSITIVE MARKING FROM QUESTION 3.2.2
          POSITIEWE NASIEN VANAF VRAAG 3.2.2
          vf2 = vi2 + 2aΔy
          1,42 = 13,82 + 2 (-9,8)y✓
          y = 9,62 m

          OR/OF
          ½ m v2i + mghi = ½ m v2f + mghf
          ½ m(13,8 )2 + 0 = ½ m(1,4)2 + m(9,8)(y) ✓
          y = 9,62 m

          ∆y = vi∆t + ½ a∆t2✓
          ∆y = 13,8∆t + ½ (-9,8) ∆t2…………….(1)
          9,62 - ∆y = 8∆t + 4,9∆t2…………….(2)
          ∆t = 0,44 s

          ∆y = (13,8)(0,44) – (4,9)(0.44)2✓
          ∆y = 5,12 m ✓                                                                   (6)

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Fisiese Wetenskappe/Graad 12 Marking Guidelines/Nasienriglyne

3.3       POSITIVE MARKING FROM QUESTION 3.2.3
          POSITIEWE NASIEN VANAF VRAAG 3.2.3

             Position/Posisie
                            (m)
                                                         Marking guidelines
                                                         Nasienriglyne
                                  B                      • Shape of A/Vorm van A
                                            A
                                                         • Shape of B/Vorm van B
                           5,21                          • Position of t and 5,21/
                                                            Posisie van t en 5,21

                                        t
                                                time(s)/tyd(s)                                 (4)
                                                                                              [19]

QUESTION 4/VRAAG 4

4.1       Marking criteria/Nasienkriteria
          If any of the underlined key words/phrases in the correct context is
          omitted deduct 1 mark/Indien enige van die onderstreepte
          sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
          In an isolated/closed system the total (linear) momentum is
          conserved/remains constant. 
          In 'n geïsoleerde/geslote sisteem bly die totale (lineêre) momentum
          behoue/konstant.                                                                   (2)

4.2
                T

                          W

          If there is free-body diagram 0/2./As ñ vrye liggaam diagram get
          eken word 0/2

          Accepted labels/Aanvaarde benoemings
          w Fw /Fg /mg /gravitational force
              Fw /Fg /mg/gravitasiekrag
          T FT/Tension
              FT/spanning
          Notes/Aantekeninge
          • Mark awarded for label and arrow./Punt word toegeken vir byskrif en
             pyltjie.
          • Do not penalise for length of arrows./Moenie vir die lengte van die
             pyltjies penaliseer nie.                                                          (2)

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          •   Any other additional force(s)/Enige ander addisionele krag(te):
              Max/Maks ½
          •   If everything is correct, but no arrows /Indien alles korrek, maar geen
              pyltjies Max/Maks ½
          •   If force(s) do not make contact with the dot:/Indien krag(te) nie die
              kolletjie raak nie Max/Maks ½

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4.3        vf2 = vi2 + 2ay
           02 = vi2 + 2(-9,8)(0,15) 
           vi = 1,71 m·s-1

           OR/OF

           (Ek + Ep)i = (Ek + Ep)f
           ½ m v2i + mghi = ½ m v2f + mghf
           (½)(0,12)(vi 2) +0 = 0 + (0,12)(9,8)(0,15)✓
           vi = 1,71 m.s-1

           OR/OF
           Wnet = ½ m v2f - ½ m v2i
           (0,12)(9,8)(0,15)(cos180) = 0 – (½ )(0,12)( vi 2) ✓
           vi = 1,71 m.s-1

           OR/OF
           Wnc = mghf - mghi + ½ m v2f - ½ m v2i
            0 = (0,12)(9,8)(0,15) – 0 + 0 - (½ )(0,12)(vi 2) ✓
             vi = 1,71 m.s-1

           OPTION 1/OPSIE 1
           EAST/RIGHT AS POSITIVE/OOS/REGS AS POSITIEF
           Σpi = Σpf                      ✓Any one/Enige een
           m1vi+ m2vi = m1vf + m2vf
           (0,095)(2,45) + (0,12)(0) ✓ = (0,095)(vf) +(0,12)(1,71)✓
           vf = 0,29 m∙s-1✓

           WEST/LEFT AS POSITIVE/WES/LINKS AS POSITIEF
           Σpi = Σpf
                                            ✓Any one /Enige een
           m1vi+ m2vi = (m1+ m2)vf
           (0,095)(-2,45) + (0,12)(0) ✓ = (0,095)(vf) + (0,12)(-1,71) ✓
           vf = - 0,29 m∙s-1
           vf = 0,29 m∙s-1✓
           Range (0,28 m∙s-1 - 0,29 m∙s-1)
           OPTION 2/OPSIE 2
           EAST/RIGHT AS POSITIVE/OOS/REGS AS POSITIEF
           ∆px = -∆py
                                         ✓Any one/Enige een
           m(vxf – vxi) = - m(vyf – vyi)
             0,095(vf – 2,45) ✓ = -0,12(1,71– 0) ✓
           vf = 0,29 m∙s-1✓

           WEST/LEFT AS POSITIVE/WES/LINKS AS POSITIEF
           ∆px = -∆py
           m(vxf – vxi) = - m(vyf – vyi)          ✓Any one/Enige een
           0,095(vf + 2,45) ✓= -0,12(-1,71 – 0) ✓
           vf = -0,29 m∙s-1
           vf = 0,29 m∙s-1✓                                                                     (5)

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4.4       POSITIVE MARKING FROM QUESTION 4.3
          POSITIEWE NASIEN VANAF VRAAG 4.3
          OPTION 1/OPSIE 1

          EAST AS POSITIVE/OOS AS POSITIEF
                 Fnet ∆t = ∆p           ✓Any one/Enige een
                Fnet ∆t = m(vf – vi)    /                              
           Fnet (0,08) = 0,095(0,29 – 2,45) ✓ OR/OF Fnet (0,08) = 0,012(1,71 – 0)
                        Fnet = -2,565 N                      Fnet = 2,57N
                        Fnet = 2,57 N✓

           WEST AS POSITIVE/WES AS POSITIEF
               Fnet ∆t = ∆p
                                         ✓Any one/Enige een
                 Fnet ∆t = m(vf – vi)                                  
            Fnet (0,08) = 0,095(-0,29 + 2,45)✓OR/OF Fnet (0,08) = 0,12(-1,71 – 0)
                      Fnet = 2,57 N✓                          Fnet = 2,57
                                                             Fnet = 2,57 N✓
          OPTION 2/OPSIE 2
          EAST AS POSITIVE                      WEST AS POSITIVE
          OOS AS POSITIEF                       WES AS POSITIEF
          vf = vi + a∆t                         vf = vi + a∆t
          0,29 = 2,45 + a(0,08) ✓               -0,29 = -2,45 + a(0,08) ✓
          a = -27 m∙s    -2                     a = 27 m∙s-2
          Fnet = ma✓                            Fnet = ma✓
                 = 0,095 (-27)                        = 0,095 (27)
                 = - 2,565 N                          = 2,57 N✓
                 = 2,57 N                                                                    (3)
                                                                                            [12]

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QUESTION 5/VRAAG 5

5.1       Potential energy to kinetic energy/Potensiële energie na kinetiese
          energie✓                                                                         (1)

5.2       Marking criteria/Nasienkriteria
          If any of the underlined key words/phrases in the correct context is
          omitted deduct 1 mark/Indien enige van die onderstreepte
          sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
          A system in which the net external forces acting on the system is zero.✓✓
          'n Sisteem waarin die netto eksterne kragte wat op die sisteem inwerk nul
          is                                                                               (2)

5.3       OPTION 1/OPSIE 1
          ½ m v2i + mghi = ½ m v2f + mghf✓
          (100)(9,8)(20) +0 ✓ = 0 + (½ )(100)( vf2 ) ✓
          vf = 19,80 m.s-1✓
          OPTION 2/OPSIE 2
          Wnet = ½ m v2f - ½ m v2i✓
          (100)(20)(9,8)(cos0)✓ = (½ )(100)( vf 2) ✓ - 0
          vf = 19,80 m.s-1✓
          OPTION 3/OPSIE 3
          Wnc = mghf - mghi + ½ m v2f - ½ m v2i✓
          0✓ = 0 – (100)(9,8)(20) + ½ (100) v2f - 0✓
          vf = 19,80 m.s-1✓                                                                (4)

5.4.1     POSITIVE MARKING FROM QUESTION 5.3
          POSITIEWE NASIEN VANAF VRAAG 5.3
          OPTION 1/OPSIE 1
          Wnet = ΔEk ✓
          Wnet = (½ )(100)(0)2 - (½ )(100)(19,80)2✓
          Wnet = -19 602 J
          Wnet = WG + Wf
          -19 602✓ = (100)(9,8)(sin30o)(x)(cos180o) + (200)(x)(cos180o)✓
          x = 28,41 m

          h = (28,41)(sin30o)✓
          h = 14,21 m✓
          OPTION 2/OPSIE 2
          Wnc = ΔEp + ΔEk                            ✓Any one/Enige een
          Wnc = mghf - mghi + ½ m v2f - ½ m v2i      /
                 h 
          (200)           ✓cos180o✓ = (100)(9,8)(h) – 0✓ + 0 – ½(100)(19,80)2✓
                 sin 30 
                        o

          h = 14,20 m✓

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          OPTION 3/OPSIE 3
          Fnet = ma ✓
          -(100)(9,8)(sin30o)✓ – 200 = 100a✓
          a = -6,9 m.s-2

           v f 2 = v i2 + 2aΔy
          02= 19,802 + 2 (-6,9)(x) ✓
          x = 28,41 m

          h = (28,41)(sin30o)✓
          h = 14,21 m✓                                                                     (6)

5.4.2     Smaller than/kleiner as ✓
          The net force acting on the object will decrease./Die netto krag wat op die
          voorwerp inwerk sal verminder ✓                                                  (2)
                                                                                          [15]

QUESTION 6/VRAAG 6
6.1    Marking criteria/Nasienkriteria
       If any of the underlined key words/phrases in the correct context is
       omitted deduct 1 mark./Indien enige van die onderstreepte
       sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
       The change in frequency (or pitch) of the sound detected by a listener
       because the sound source and the listener have different velocities
       relative to the medium of sound propagation. 
       Die verandering in frekwensie (of toonhoogte) van die klank waargeneem
       deur 'n luisteraar omdat die klankbron en die luisteraar verskillende
       snelhede relatief tot die medium waarin die klank voortgeplant word, het.

          OR/OF
          An (apparent) change in observed/detected frequency (pitch), as a result
          of the relative motion between a source and an observer (listener).
          'n Skynbare verandering in waargenome frekwensie (toonhoogte), as
          gevolg van die relatiewe beweging tussen die bron en 'n waarnemer
          (luisteraar).                                                                    (2)

6.2       Doppler ultrasound machine or Doppler flow meter/Doppler-
          ultraklankmasjien of Doppler-vloeimeter (Any one/Enige een). ✓                   (1)

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6.3            v  vL                    v
           fL =       fs OR/OF fL =          fs ✓
               v  vs                 v − vs
                         342
          2 450  =              (2 000 ) 
                       342 − v s
          vs = 62,82 m·s-1

                  x                                      v + vf 
          Δv =                                      ∆x =  i      t
                  t                                      2 
                  x
          62,82 =                                        62,82 + 62,82 
                  0,5                               Δx =                (0,5)
                                                                2       
          Δx = 31,41 m 
                                                    Δx = 31,41 m                               (5)

6.4       Marking guidelines/Nasienriglyne
          • Shape of graph/Vorm van grafiek
          • 2000 Hz and/en 0,5 s 

                    f(Hz)
                    2000

                                            0,5                     t(s)

                                                                                               (2)

6.5       Shows that the Universe is expanding/Toon dat die heelal besig is om uit
          te brei ✓                                                                            (1)
                                                                                              [11]

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QUESTION 7/VRAAG 7

7.1       NO/NEE✓

          The spheres will lose their charge./The metal stands are electrical
          conductors./Die sfere sal hul lading verloor./Die metaalstaanders is
          elektriese geleiers.                                                                    (2)

7.2       Marking criteria/Nasienkriteria
          If any of the underlined key words/phrases in the correct context is
          omitted deduct 1 mark Indien enige van die onderstreepte
          sleutelwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
          The (magnitude of the) electrostatic force exerted by one point charge on
          another point charge is directly proportional to the product of the
          (magnitudes of the) charges and inversely proportional to the square of
          the distance between them./Die (grootte van die) elektrostatiese krag
          wat een puntlading op 'n ander puntlading uitgeoefen, is direk eweredig
          aan die produk van die (groottes van die) ladings en omgekeerd eweredig
          aan die kwadraat van die afstand tussen hulle                                           (2)
          If mass is used 0/2./Indien massa gebruik word in plaas van lading
          0/2

7.3       OPTION 1/OPSIE 1
             kQ 1Q 2
          F=          ✓
                r2
                (9  10 9 )(12  10 −9 )(6  10 −9 )
          FCA =                     2
                                                      = 1,04 x 10-5 N
                             (0,25)
                 (9  10 9 )(12  10 −9 )(9  10 −9 )
          FCB =                      2
                                                      = 4,32 x 10-5 N
                              (0,15)
          Fnet =4,32×10 N - (1,04×10-5 N ) 
                          -5

               = 3,28×10-5 N due East/ Right/reg/ Oos ✓

          OPTION 2/OPSIE 2
              kQ
          E= 2 
              r
                (9  10 9 )(6  10 −9 )
          ECA =                          = 864 N·C-1
                      (0,25) 2
                 (9  10 9 )(9  10 −9 )
          ECB =                           = 3 600 N·C-1
                       (0,15) 2
          Enet =3 600 - 864 = 2 736 N.C-1due East

          F = EQ ✓
            = (2 736 × 12 × 10-9)✓
            = 3,28×10-5 N due East/Right/reg/Oos✓
                                                                                                  (5)

7.4.1     A to B /A na B                                                                        (2)
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- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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