# Technical Sciences Grade 12 P1 North West Mock 2019 Memo > Grade 12 Technical Sciences Paper 1 memorandum from the North West Mock Exam 2019, 16 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/nw-tech-sc-p1-memo-afr-and-eng-sept-2019/869bfc5b-8072-4b88-ace3-d49b894bc570 - Updated: 2026-09-27 - Subject: Technical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2019 - Exam period: North West Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 16 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Technical Sciences](https://www.hlayiso.com/library/grade-12/technical-sciences) › [Technical Sciences Grade 12 P1 North West Mock 2019 Memo](https://www.hlayiso.com/library/nw-tech-sc-p1-memo-afr-and-eng-sept-2019/869bfc5b-8072-4b88-ace3-d49b894bc570) ## About this document Technical Sciences · Grade 12 · North West Mock Exam · 2019. Memorandum, 16 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com GRADE/GRAAD 12 TECHNICAL SCIENCES: P1 TEGNIESE WETENSKAPPE: V1 2019 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 This memorandum consists of 16 pages. Hierdie memorandum bestaan uit 16 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 2 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 A PP (2) 1.2 B PP (2) 1.3 D PP (2) 1.4 C PP (2) 1.5 A PP (2) 1.6 D PP (2) 1.7 C PP (2) 1.8 B PP (2) 1.9 A PP (2) 1.10 B PP (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 3 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 2.1 The rate of change of velocity. PP Die tempo van verandering in snelheid. PP (2) 2.2 Take Right/East as Positive Neem Regs/Oos as positief Fnet = Fk + Fa P Fnet = - 2 + 5 P Fnet = 3 N, (to the right/ na regs) P (3) NOTE/NOTA: accommodate other means of direction correctly used: e.g to the right depending on the choice of direction. akkomodeer ander rigtings as korrek: b.v. na regs afhangend van gekose rigting. 2.3 2.3.1 When a net force Fnet is applied to an object of mass (m) it accelerates in the direction of the net force PP. This acceleration is directly proportional to the net force and inversely proportional to the mass of the object. P Wanneer 'n netto krag op 'n voorwerp inwerk, versnel die voorwerp in die rigting van die netto krag Hierdie versnelling is direk eweredig aan die netto krag en omgekeerd eweredig aan die massa. P (2) 2.3.2 N/Fn P Note/Nota: fk / fP Fa P § Allocate mark for arrow and label. § Gee punt vir pylpunt en bemoem. Penalise if/ Penaliseer indien: Fg/W P § No arrow (Penalise ONCE) § Geen pyle (Penaliseer EENMAAL) § Gaps between the line and the dot § Spasie tussen die lyn en die kol § Dotted lines are used § Stippelyne gebruik is § Additional force is included (-1) § Addisionele kragte ingesluit (-1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 4 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne 2.4 2.4.1 (Take right as positive/Neem regs as positief) OPTION 1/OPSIE 1 For 2 kg block/ Vir die 2 kg blok For 4 kg block/Vir die 4 kg blok for any formula/ vir enige formule P one mark/een punt Fnet = ma Fnet = ma T = ma Fa + (-T) = ma T = 2a P 12 – T P= 4a P T = 2a …………..(1) 12 - T = 4a……………..(2) Addittion of equation: (1) and (2)/ Optel van vergelyking: (1) en (2) T = 2a …………..(1) 12 - T = 4a……………(2) 12 = 6a P a = 2 m.s-2 ; (to the right/na regs) P OPTION 2/OPSIE 2 Fnet = ma for any formula/vir enige formule FA + T+ (- T ) = (m2kg + m4kg)a P 12 P + 0 P = (2 + 4)a P 12 = 6a P -2 a = 2 m.s ; (to the right/ na regs) P (6) NOTE/NOTA: Accommodate other means of direction correctly used: e.g to the right depending on the choice of direction. Akkomodeer ander rigtings as korrek: b.v. na regs afhangend van gekose rigting. 2.4.2 [Positive marking from 2.4.1 above] [Positiewe merk vanaf 2.4.1] OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Fnet = ma Fnet = ma T = 2a P 12 + T = 4a P T = 2(2) P 12 + T = 4(2) P T=4NP T=4NP (3) 2.5 Decrease/Afname P (1) [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 5 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1 3.1.1 Impulse is the product of the net/resultant force acting on an object and the time the net/resultant force acts on the object. PP Impuls is die produk van die netto krag wat op 'n voorwerp inwerk en die tyd wat die netto krag op die voorwerp inwerk. PP (2) 3.1.2 (Take towards the wall as positive/Neem na die muur as positief) Impulse/Impuls = ∆p Impulse/Impuls = mv f - mv i P any formula/vir enige formule Impulse/Impuls = m(v f - v i) Impulse/Impuls = 0,15 P (-16 - 20) P Impulse/Impuls = - 5, 4 Impulse/Impuls = 5, 4 N.s (Away from the wall/ Weg vanaf die muur) P (4) NOTE: Accommodate other means of direction correctly used: e.g towards the wall depending on the choice of direction. akkomodeer ander rigtings as korrek: b.v. na die muur afhangend van gekose rigting. 3.2 3.2.1 The total linear momentum of an isolated system remains constant/ is conserved (in magnitude and direction). PP Die totale lineêre momentum van 'n geïsoleerde sisteem bly konstant/(word behou) in grootte en rigting. PP ACCEPT/AANVAAR In an isolated system, the total linear momentum before the collision/explosion is equal the total linear momentum after the collision/explosion. In ‘n geïsoleerde sisteem is die totale lineêre momentum voor die botsing/ontploffing gelyk aan die totale lineêre momentum na die botsing/ontploffing. PP (2) 3.2.2 (Take east as positive/Neem oos as positief) ∆pnet = 0 pT(before/voor) = pT(after/na) P any formula/enige formule p1i + p2i = p1f + p2f m1 v i2 +m2 v i2 = m1 +m2 )vf1-2 (2500)(19) P + (1 000)(-33) P = (2500 + 800) v f1-2 P 47500 - 33000 = 3300vf1-2 14500 = 3300vf1-2 vf1-2 = 4, 39 m.s-1 ; (due east/ oos) P (5) NOTE: accommodate other means of direction correctly used: e.g due East depending on the choice of direction./akkomodeer ander rigtings as korrek b.v. oos afhangend van gekose rigting Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 6 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne 3.2.3 (Positive marking from 3.2.2 above) (Positiewe merk vanaf 3.2.2) any formula/enige formule ƩEkbefore/voor = Eki - 1 + Eki - 2 ü ƩEkafter/na = Ekf - 1 + Ekf - 2 ml v 2i -2 m2 v 2i - 2 = + ml v 2f -1 m2 v2f - 2 2 2 = + 2500 19 2 1000 33 2 2 2 = 2 + 2 ü 2500 4, 39 2 1000 4, 39 2 = + ü 2 2 = 995750 J ü = 33726, 175 J ü ƩEkbefore/voor ≠ ƩEkafter/na ∴ The collision is inelastic/Die botsing is onelasties ü (6) 3.2.4 According to the formula Fnet.∆t = ∆p, the contact time between the driver and the airbag will be longer, ü while the change in momentum remains constant or remains the same.ü Thus this effect will reduce the net/resultant force. ü Volgens die formule Fnet.∆t = ∆p, sal die kontaktyd tussen die bestuurder en die lugsak verleng, ü terwyl die verandering in momentum constant of dieselfde bly.ü Dus sal die effek die netto/resultante krag verlaag. ü (3) [22] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 7 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 4/VRAAG 4 4.1 The product of the applied force on an object and the displacement in the direction of the force. üü Die produk van die toegepaste krag op 'n voorwerp en die verplasing in die rigting van die krag. üü (2) 4.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 N/Fn P N/Fn P Fa P Fy P fk / fP fk / fP Fx Fg/WP Fg/WP (4) Note/Nota: § Allocate a mark for the arrow and label. § Gee ‘n punt vir die pylpunt en bemoem Penalise if/ Penaliseer indien: § No arrow (Penalise ONCE)/Geen pyle (Penaliseer EENMAAL) § Gaps between the line and the dot/Spasie tussen die lyn en die kol § Dotted lines are used/Stippelyne gebruik is § Additional forces included (-1)/Addisionele kragte (-1) 4.3 4.3.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 W Fa = Fa.∆x.cosϴ W Fa = Fa.∆x.cosϴ W Fx = Fx.∆x.cosϴ P W Fx = (F.cosϴ).∆x.cosϴ P 0 W Fx = (F.cosϴ).∆x.cosϴ W Fx = 15.(5) cos0 P W Fx = (15. Cos300)(5) P cos00 P W Fx = 75 J W Fx = 64, 95 JP (4) Note/Nota:: (2 4) 4.3.2 W fk = fk.∆x.cosϴ W fk = 2,5.cos(1800) P W fk = -10 J P (2) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 8 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1 The total mechanical energy in an isolated system remains constant or is conserved. üü/Die totale meganiese energie in 'n geslote stelsel bly konstant. üü ACCEPT/AANVAAR: The sum of gravitational potential energy and kinetic energy of an isolated system remains constant or is conserved Die som van gravitasie potensiële energie en kinetiese energie in 'n geslote stelsel bly konstant. üü (2) 5.2 ME = Ep + Ek ME = mgh + mv 2 P any formula/enige formule ME = (1000)(9,8)(1,5) + 0 ü ME = 14700 J üor ME = 14, 7 kJ (3) 5.3 (Positive marking from 5.2 above) (Positiewe merk vanaf 5.2) OPTION 1/OPSIE 1 ME at/ by A = ME at/ by B ( Ek + Ep ) A = ( Ek + Ep )B P any formula/enige formule ME = ( mv 2 + mgh )B 14700 ü= (1000)(9,8)(0) ü+ (1000)v 2 ü 14700 = 0 + 500v2 v= 29,4 v = 5, 42 m.s-1 ü (5) OPTION 2/OPSIE 2 OPTION 3/OPSIE 3 (Take downwards as positive) vf = 2gDy (Neem afwaarts as positief) vf = (2)(9,8)(1,5) ü v f2 = v i2 +2g∆y ü vf = 29,4 v f2 = 02 ü+ 2(9,8)(1,5) ü vf = 5, 42 m.s -1 ü vf = 29,4 v f = 5, 42 m.s-1 ü Note/Nota: ( 2 5 ) Note/Nota: ( 3 5 ) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 9 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne 5.4 5.4.1 Power is the rate at which work is done or energy is transferred.üü Drywing is die tempo waarteen arbeid verrig of energie verbruik word.üü (2) 5.4.2 P = Fv ü 3 40 x 10 = F.25 ü F = 1 600 N/1,6 kN ü (3) [15] QUESTION 6/VRAAG 6 6.1 Strain is the ratio of change in the dimension/length of objects to the original dimension/length.üü Vervorming is die verhouding van verandering in dimensie tot die oorspronklike dimensie.üü Accept/Aanvaar: The change in length over the original length of an object.üü Die verandering in lengte van die voorwerp tot die oorspronklike lengte.üü (2) 6.2 Hooke's law states that, within the limit of elasticity, stress is directly proportional to the strain.üü Hooke se wet bepaal dat spanning, in die grens van elastisiteit, direk eweredig is aan die rekking.üü (2) 6.3 F 6.3.1 s = P 2 A x 1 x 106 P = 1 F P 0 -3 F = 2 000 N/2 kNP (4) 6.3.2 1 = P x L Δ ε 1 L 0 -3 ε = P 50 ε = 2 x 10-5 ü (3) NOTE/NOTA: Penalise if units are included (final answer). Penaliseer indien eenhede by finale antwoord gegee is σ 6.3.3 K = ü 1 ε x 1 0 6 K = 2 - 5 ü x 1 0 K = 5 x 1010 N.m-2/Pa ü (3) [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 10 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1 Viscosity is defined as the property of the fluid to oppose relative motion between the two adjacent layers.üü Viskositeit is die eienskap van die vloeistof om relatiewe beweging tussen die twee aangrensende vlakke te opponeer.üü ACCEPT/AANVAAR: Measure of resistance to flow of a liquid.üü Mate van weerstand teen vloei van ‘n vloeistof.üü (2) 7.2 If the temperature of the fluid increases, its viscosity decreases.üü As die temperatuur van die vloeistof toeneem, neem die viskositeit af üü ACCEPT/AANVAAR: Viscosity increase with a decrease in temperature of the liquid. üü)\ Viskositeit neem toe met ‘n afname in temperatuur van die vloeistof.üü (2) 7.3.1 Pascal's law states that in a continuous liquid at equilibrium, the pressure applied at a point is transmitted equally to the other parts of the liquid.üü Pascal se wet bepaal dat in 'n kontinue vloeistof by ewewig, die druk by enige punt eweredig oorgedra word na al die ander dele van die vloeistof. üü (2) A A F A F 2 2F = F 0 F A 7.3.2 ,5 A A AF 1 1 B B = ü any formula/enige formule 1 0 0 ==== 0 ü ü 2 A = 250 N ü (4) 7.3.3 · bulldozer's working systems · stootskraper se sisteme · hydraulic power brakes on · hidrouliese kragremme van automobiles motorvoertuie · dentists' chairs · tandartstoele · hydraulic lifts used to lift heavy · hidrouliese hysers om swaar loads voorwerpe op te lig · car jacks, lift · Voertuig hyser · Forklifts · Vurkhyser · Jack Hammer · “Jack Hammer” · Office chairs · Kantoorstoele · Hydraulics press · Hidrouliese pers · Hydraulic Excavator · Hidrouliese laaigraaf Any Three üüü Enige drie (3) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 11 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne QUESTION 8/VRAAG 8 8.1 Doping is the process of adding impurities to intrinsic semiconductors. üü Doepatoevoeging/Dotering is die proses waardeur onsuiwerhede by 'n suiwer halfgeleier gevoeg word. üü (2) 8.2 Intrinsic semiconductors have very little current conduction capacity. However, if a very small amount of impurity is added, the conductivity is increased significantly. üü Intrinsieke halfgeleiers het min geleidingsvermoë. Maar wanneer klein hoeveelhede onsuiwerhede bygevoeg word, vermeerder die geleidingsvermoë aansienlik. üü (2) 8.3 8.3.1 Capacitor is a device that stores electrical charge.üü (2) Kapasitor is 'n toestel wat elektriese lading stoor.üü (2) ε A 8.3.2 C= o ü d ( ü 8 ,8 5 C= x 1 0 0-1 ,0 2 0 ) 1 (2 x ü 1 0 ) -4 12 C = 1, 77 × 10– F or C = 1, 77 pFü (4) 8.3.3 · The total surface area of the plates. ü · Die totale oppervlakte van die plate. ü · The distance between the TWO plates. ü · Die afstand tussen die TWEE plate · The types of dielectric material. ü · Die tipe diëlektriese medium. ü (3) 8.4 8.4.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 OPTION 3/OPSIE 3 P = VI ü P = I2.R ü V2 P= ü R P = (240) (24)ü P = 242.10 ü 2 P = 5760 W ü P = 5760 W ü P = 2 1 4 ü 0 0 P = 5760 W ü (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 12 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne 8.4.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 1 2 W = I .Rt ü W = VI.Rt ü W = ( 242 ) (10) ü (10 × 3600)ü W = ( 240)(24) ü (10 × 3600)ü W = 2, 074 x 10 8 J ü W = 2, 074 x 10 8 J ü OPTION 3/OPSIE 1 V 2 Δt W= ü R (240 2 )(10x3600) ü W= 10 ü W = 2, 074 x 10 8 J ü (4) [20] QUESTION 9/VRAAG 9 9.1 Faraday's law states that when the magnetic flux linked with the coil changes, an emf is induced in the coil.ü The magnitude of the induced emf is directly proportional to the rate of change of magnetic flux.ü Faraday se wet bepaal dat, wanneer die magnetiese vloed wat met die spoel verbind is verander, 'n emk in die spoel geïnduseer word.üDie grootte van die geïnduseerde emk is direk eweredig aan die tempo van verandering van die magnetiese vloed.ü (2) N 9.2 ε = - Δ Δ ü t φ ( 0 0 ü = - ε 5 0 ,0 6 ,3 - 0 0 ,0 5 ) ü ℇ = − 16.67 V ü (4) 9.3 V V =N N ü p s p s 2 V 4 s 0 ü= ü Vs = 120 V ü (4) 9.4 9.4.1 Slip ring/Sleepring ü (1) 9.4.2 Carbon Brushes/Koolstofborsel ü (1) 9.4.3 Mechanical energy to electrical energy Meganiese energie na elektriese energie. ü (1) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 13 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne Question 1 Content Levels Marks 1 2 3 4 1.1 Newton’s laws ü 2 1.2 Momentum ü 2 1.3 Energy ü 2 1.4 Power ü 2 1.5 Electronic Properties ü 2 1.6 Viscosity ü 2 1.7 Hydraulics ü 2 1.8 Electric circuit ü 2 1.9 Capacitors ü 2 1.10 Electric machine ü 2 Total 12 4 2 2 20 Question 2 Content Levels Marks 1 2 3 4 2.1 Newton’s laws ü 2 2.2 Newton’s laws ü 3 2.3.1 Newton’s laws ü 2 2.3.2 Newton’s laws ü 4 2.4.1 Newton’s laws ü 6 2.4.2 Newton’s laws ü 3 2.5 Newton’s laws ü 1 Total 8 6 6 1 21 Question 3 Content Levels Marks 1 2 3 4 3.1.1 Momentum ü 2 3.1.2 Momentum ü 4 3.2.1 Momentum ü 2 3.2.2 Momentum ü 5 3.2.3 Momentum ü 6 3.2.4 Momentum ü 3 Total 4 4 5 9 22 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 14 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne Question 4 Content Levels Marks 1 2 3 4 4.1 Work ü 2 4.2 Work ü 4 4.3.1 Work ü 4 4.3.2 Work ü 2 Total 6 2 4 0 12 Question 5 Content Levels Marks 1 2 3 4 5.1 Energy ü 2 5.2 Energy ü 3 5.3 Energy ü 5 5.4.1 Power ü 2 5.4.2 Power ü 3 Total 4 6 5 0 15 Question 6 Content Levels Marks 1 2 3 4 6.1 Elasticity ü 2 6.2 Elasticity ü 2 6.3.1 Elasticity ü 4 6.3.2 Elasticity ü 3 6.3.3 Elasticity ü 3 Total 4 10 0 0 14 Question 7 Content Levels Marks 1 2 3 4 7.1 Viscosity ü 2 7.2 Viscosity ü 2 7.3.1 Hydraulics ü 2 7.3.2 Hydraulics ü 4 7.3.3 Hydraulics ü 3 Total 7 2 4 0 13 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 15 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne Question 8 Content Levels Marks 1 2 3 4 8.1 Electronic Properties ü 2 8.2 Electronic Properties ü 2 8.3.1 Capacitors ü 2 8.3.2 Capacitors ü 4 8.3.3 Capacitors ü 3 8.4.1 Electric circuits ü 3 8.4.2 Electric circuits ü 4 Total 7 13 0 0 20 Question 9 Content Levels Marks 1 2 3 4 9.1 Electromagnetism ü 2 9.2 Electromagnetism ü 4 9.3 Electromagnetism ü 4 9.4.1 Electromagnetism ü 1 9.4.2 Electromagnetism ü 1 9.4.3 Electromagnetism ü 1 Total 5 4 4 0 13 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Downloaded from hlayiso.com Technical Sciences P1/Tegniese Wetenskappe V1 16 NW/September 2019 NSC/NSS – Grade 12/Graad 12 – Marking Guidelines/Nasienriglyne SUMMARY OF THE LEVELS OF THINKING (COGNITIVE LEVELS) Question Level 1 Level 2 Level 3 Level 4 Total 1 12 4 2 2 20 2 8 6 6 1 21 3 4 4 5 9 22 4 6 2 4 0 12 5 4 6 5 0 15 6 4 10 0 0 14 7 7 2 4 0 13 8 9 13 0 0 20 9 5 4 4 0 13 Overall total 57 51 30 12 150 % 38.00 % 34.00 % 20.00 % 8.00 % 100 % Weighting of prescribed content (Adapted from CAPS p. 60) (Expected) Paper 1 Weighting of questions Content Marks Total Duration % across cognitive levels Mechanics 108 72 150 Electricity and 3 hours 40 30 20 10 42 28 marks Magnetism Exam(Actual) Mechanics 108 72, 00 150 38, 34, 20, Electricity and 3 hours 8, 00 42 28, 00 marks 00 00 00 Magnetism Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - 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