# Physical Sciences Grade 11 P2 2018 QP & Memo

> Grade 11 Physical Sciences Paper 2 question paper and memo from the KwaZulu Natal June 2018, 16 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/phy-june-p2-qp-and-memo/8b86b08f-fd67-421a-8e00-ee1e7ef6b865
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2018
- Exam period: KwaZulu Natal June
- Paper: 2
- Curriculum: CAPS
- Pages: 16

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Physical Sciences](https://www.hlayiso.com/library/grade-11/physical-sciences) › [Physical Sciences Grade 11 P2 2018 QP & Memo](https://www.hlayiso.com/library/phy-june-p2-qp-and-memo/8b86b08f-fd67-421a-8e00-ee1e7ef6b865)

## About this document

Physical Sciences · Grade 11 · KwaZulu Natal June · 2018. Question paper and memorandum, 16 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

MARKS:

TIME

Copyright Reserved Please Turn Over |

education

Department:
Education
PROVINCE OF KWAZULU-NATAL

NATIONAL

SENIOR CERTIFICATE

GRADE 11

PHYSICAL SCIENCES P2 (CHEMISTRY) “
COMMON TEST i

JUNE 2018 a

Pa

100

: 2 Hours

This question paper consisis of 9 pages AND 2 data sheets.

### Page 2

Physical Sciences P2

Downloaded from hlayiso.com

NSC

Common Test June 2018

INSTRUCTIONS AND INFORMATION TO CANDIDATES

1.

Write your name on the ANSWER BOOK.

Answer ALL the questions in the answer book.

You may use a non-programmable calculator.

You may use appropriate mathematical instruments.

Number the answers correctly according to the numbering system
used in this question paper.

YOU ARE ADVISED TO USE THE ATTACHED DATA SHEETS.

Give brief motivations, discussions, et cetera where required.

Copyright Reserved Please Turn Over

### Page 3

Downloaded from hlayiso.com,

NSC

Physical Sciences P2 mmon Test June 2018

SECTION A

QUESTION 1: MULTIPLE- CHOICE QUESTIONS

Four options are provided as possible answers to the following questions.
Each question has only ONE correct answer. Write only the letter (A - D) next to the
question number (1.1 — 1.6) in the ANSWER BOOK. e.g. 1.7 A

1.1. Which one of the following is the best explanation for the high degree of solubility
of NaCl in water?

A Both molecules are polar.
B Both molecules are ionic.
Cc The electrostatic forces between the ions in NaCl are of the same order as

that of the intermolecular forces in water.

D Water is ionic and NaCl is polar.

1.2. The factor that does NOT affect bond length between two atoms is :

A Size of the atoms.

B Difference in electronegativity between the atoms.
Cc Number of bonds between the atoms.

D Valencies of the atoms.

1.3. The phenomenon that allows insects such as mosquitoes to walk on water is:

A Capillarity

B Adhesion

Cc Surface tension
D Evaporation

1.4. Which ONE of the following statements regarding the Kinetic Molecular Theory
of gases is INCORRECT?

All molecules have the same kinetic energy.

Gas molecules collide elastically.

Gas molecules are in random motion.

UO OW PY

Attractive and repulsive forces between the gas molecules can be neglected.

(2)

Copyright Reserved Please Turn Over

### Page 4

Downloaded from HlayiSO.COMonmon Tost June 2018

NSC

Physical Sciences P2

1.5. The number of nitrate ions in 2 moles of Ca(NOs)z is

A 4 x 6.02 x 1078
B 2x 6.02» 10
Cc 4

D 8 x 6.02 x 109

1.6. | Consider the combustion of methane gas in a closed rigid container
containing 30cm° of oxygen gas.

CHa) + 202) — CO2g + 2H20@)

What will be the total volume of gas in the container if 20cm? of oxygen gas reacts
with all the methane at a given temperature and pressure?

A 40 cm?

B 30 cm®

Cc 20 cms

D 10 cms
(2)
[12]

Copyright Reserved Please Turn Over

### Page 5

Downloaded from hlayiso.com

Physical Sciences P2 Common Test June 2018

NSC
SECTION B
INSTRUCTIONS AND INFORMATION
1. Answer all questions.
2. Show the formulae and substitutions in ALL calculations.
3. Round off your numerical answers to a minimum of TWO decimal places.
QUESTION 2

2.1. Use only the substances from the list below when answering questions 2.1.1 to 2.1.7
HClig) HF) = PHaq) = Cus) )~— He =~ KFis)_—LiCKaqy «= CClaqy

Select one substance from the list that has:

(Write only the question number and the Formula of the substance next to it.

You may use a substance more than once).

2.1.1 Pure covalent bonds. (1)

2.1.2 A high melting point due to strong electrostatic attraction between

the cations and anions in the crystal lattice. (1)
2.1.3 Hydrogen bonding. (1)
2.1.4 Has dipole-dipole intermolecular forces. Gh)
2.1.5 Has ion-dipole forces. (1)
2.1.6 Has a trigonal pyramidal shape. (1)
2.1.7 Has polar covalent bonds, but the molecule is non-polar. (1)

2.2 Consider the table below, which shows the boiling points of the halogens.

| Halogen Fe Cle [ Bre [

[Boilingpoint(°C) 188 -35 59d

2.2.1 Name the type of Van de Waal force that exists between molecules of Cle. (1)

2.2.2 State the trend in the boiling points of the Halogens. (1)
2.2.3 Explain the trend in question 2.2.2 by making reference to the strength

of the intermolecular forces and the energies involved. (3)
2.2.4 Define vapour pressure. (2)

2.2.5 Which halogen has the lowest vapour pressure? Give a reason for your
answer. (2)
[16]

Copyright Reserved Please Turn Over

### Page 6

Physical Sciences P2

Downloaded from hlayiso.com

Common Test June 2018
NSC

QUESTION 3

Molecules such as HzO and HCN are formed by covalent bonding

3.1

3.2

3.3

3.4

35

Define a covalent bond. (2)

Use the VSEPR theory to compare the shape of the water molecule to that
of the HCN molecule. (4)

Draw the Lewis structure for the HCN molecule. (2)

Water is unique in that its solid state (ice) floats in its liquid state.
Explain fully why ice floats in water. (3)

Sodium chloride dissolves in water.
The ions are surrounded by water molecules as shown below.

é 9
o®., :

3.5.1 Is the ion shown in the diagram a sodium ion (Na*) or a chloride ion (Cl)?
Explain your choice. (2)

3.5.2. A relatively large amount of water is needed to dissolve a small amount of
sodium chloride.
Explain why this is so by referring to the structure of sodium chloride and

the strength of the forces involved. (3)
[16]

Copyright Reserved Please Turn Over

### Page 7

Downloaded from hlayiso.com

Physical Sciences P2 Common Test June 2018

NSC

QUESTION 4

The graph below indicates the relationship between the pressure (p) and the reciprocal

of volume (1/V) of an enclosed mass of helium (He) gas at 25°C. Assume that helium
behaves as an ideal gas.

450

p (kPa)

105

>
Xo K (dm?)

4.1. Give the name and state in words the Law that is illustrated by the graph. (3)
4.2 Calculate the volume of the He gas at a pressure of 450 kPa. (4)
4.3. Use the graph to calculate the mass of helium that was used. (5)

4.4 Copy the graph in your answer book. Label this graph A.
On the same set of axes draw the graph that will be obtained if:

4.4.1. The experiment is conducted at 35°C (Label this graph B). (2)

4.4.2 Areal gas such as ammoria is used instead of helium
(Label this graph C). (2)

4.5 Explain fully why the shape of the graph is different in question 4.4.2.

Copyright Reserved Please Turn Over

### Page 8

Downloaded fram hlayiso.com

NSC

Physical Sciences P2 Common Test June 2018

QUESTION 5

5.1. Agrade 11 learner dissolves 13,995 g of Cu(NOe)2 in water to make up a
standard solution with a concentration of 0,15 mol-dm®.

5.1.1. Define a standard solution. (2)
5.1.2 Calculate the volume of water (in cm) required to prepare this solution. (4)

The learner then transfers some of the above solution to a volumetric flask,
and adds 150cmé® of water to dilute it to a concentration of 0.05mol-dm°*.

5.1.3 Calculate the volume of the original solution that must be transferred
to the volumetric flask to prepare the diluted solution. (4)

5.2 50g of a substance contains 24,68 g of K, 10,13 g of S and 15,19 g of O.

5.2.1 Define empirical formula. (2)
5.2.2 Determine the empirical formula of the compound. (4)
[16]

Copyright Reserved Please Turn Over

### Page 9

Physical Sciences P2

Downloaded from hlayiso.com

NSC

ommon Test June 2018

QUESTION 6

6.4

6.2

6.3

An impure sample containing tin dioxide (SnOz) is tested to determine how much
tin dioxide it contains. The sample weighs 4,50 g

Excess sulfuric acid is added to the sample and tin (IV) sulfate forms.

The equation for the reaction is:

SnOas) + 2H2SO4 (aq) Sn (SOa)2 (s) + 2 H2O
The mass of tin sulfate produced is 4,90 g.
Calculate the percentage purity of this sample. (6)
Magnesium burns in oxygen to form magnesium oxide according to the
following balanced reaction:

2Mgis) + O2g) > 2MgQOc)

The percentage yield of the reaction is 75%.
Calculate the mass of magnesium that must be burnt in excess oxygen

to produce 20 g of magnesium oxide. (6)

30 g of Al and 1,50 moles of oxygen gas at STP are placed in a reaction chamber and
allowed to react.
The balanced equation for the reaction is:

4Al + 302 ~~ 2Al20s

6.3.1 Explain what is meant by a limiting reactant. (2)
6.3.2 Calculate the volume of excess oxygen in the reaction chamber. (7)
[21]
TOTAL: 100

Copyright Reserved Please Turn Over

### Page 10

1SO.COM common Test June 2018

NSC

Downloaded from hlay

Physical Sciences P2

L

| ge (ANA
47 | ON | PW | Wd) sa] 30) 4a wo) wy} nd | ON] A | ed | UL
cOL zoL LOL 001 66 86 46 96 S6 v6 £6 (49) L6 06
SLL ell 691 L9L SOL e9L 6SL ZS/ cSt OSL vel Leb OvL
N71} GA | WL) 4a OH | AG | GL | PD | NY | Ws | Wd | PN | dd | 89 r Qzz
bd OL 69 89 249 99 g9 v9 £9 4) L9 09 6S gs ov ey 2) 44 2
6g | ae 18
602 L402 voz Loc Z6L S6L Z6L O6L 98b ysl L8L 6LL 6EL Zeb ce
Uy |W ROdS la sods aL ei6H |nv (jd | 4 iso joe |M el JHE PT eg esos
98 Ss v8 £8 (43) L8 08 62 82 ZZ 92 GL vl €Z eZ 2g 9S ss
Leb kA) 8ZL (cA) 6LL SUL ZLb 80L 90L £OL LOL 96 26 Lé 68 88 98
2X | SeL8 qs ziuss] ul 3 pos/6vs pas/yySMySpLsoWws an |4Zs} A g 4S siqus
vs jes |zs [ts (os | or | er |v | or | sh |v [ey | ty | be | ov | 6 ge Le
v8 08 6L GL el OL s9 seg 6S 6S 9S gs es LS 8P Sv ov 6¢
y (4g 8 OS FSW 3/99 s)/P9 SUZ SIND SIN BOD S| PSA SUW SOS AS Was BeOS MS
oe S¢ ve ee ze be o¢ r4 ET4 Le 9% ETA ve €@ (44 x4 02 61
op (sce | Ze be 8Z LZ BSSELIWIOOJE aMaNejas apsapeuag ve &%
IW ao21S 3 NiIS sav a SSPUI D1WOJe SAIeja/ ayeuIxoiddy BIN Rl eN 3
8b ZL Ob SL bL eb t zt LL
oz | 6b) | OF) | bE aed Se —»| s'eg 6 Z
ON Loe ¢ x R Jooquis nj 2 [*reympebeuo0yye/z agelnme
OL 6 8 L 9 S joquwAs pel AyanyyeGau0}99;4 ? ¢
v F b
3 x
H jejoBuoojy TALNATSIAIM H =
4 Jequinu o1wowy L
(lA) (A) MA) (A) CAD) (i) ()
gL Lb OL SL vl eb aL bb OL 6 8 Z 9 S v £ A L
SLNAWSATS JO 31aVL DIGOMAd AHL :€ FTaEVL

### Page 11

Physical science P2

Downloaded from hlayiso.com

une 2018 Common Test

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAKi SYMBOL/SIA SL | VALUEIWAARDE
Standard pressure i 4 5,
Standaarddruk P ge a EAP
Vm 22.4 dm*-mol’
Ni gas te 284 JeKmok!
Molar gas constant x acSihontr iat
Standard temperature x 479
| Standaarctemperatuts 7 ana
Avogadro s Constant N offor Ne 6.022102? mor
Charge on Electron . 5 sae
Lading op elektron © “LGC

TABLE 2: FORMULAE/TABEL 2: FORMULES

orlof

_f

V

_ Mm

MV

P4V1_ P2V2

Ty
pV=nRT

To

Copyright Reserved

### Page 12

Downloaded from hlayiso.com

### Page 13

Downloaded from hlayiso.com

J8N0 WIN} BSea\q

penesas yBuAdoQ

fou]
(2) 7 lod Buipog yeyBry ay sey y}— 2) oz
(2) + MWa}SAS PSSO|O e UL
be ye unodea e Aq payexe aunssaid aUL ZZ
(e) $9910} 12|Nd9/OUEyU! Buy yeasq
/ $9/N99|OW OU) ayesedas 0} papaau si ABuaue ai0/)
7 “$8SE910U! $8940} UOPUO] By} JO UJBUdyS By |
7 | 0} 24 WO SesesloU! susBojey a4) UI SUOMOEIa JO OU / JO Sse Je|OL! ayL EZ
(L) / SSEU Je/ND3/OlW Ui eseasoU! UB YIM SOSeOlOU! JUIOd Bu: 0g ey}
{ Sesze.0u! JUIod Oulj1oq au) dnosS sy umop seoh auo sy rarer a
() / $8010} UOISI8dsIp /a|odIp psonpul-sjodip paonpul /ssol0j UOpUCT | °Z'Z
cara
(2) {t) AMID LES
(t) APHd ObZ
(L) ZI GE?
(L) A®Hd/IOH LS
(L) f dH OLe
(L) 4 sy SL?
(L) 2 Hd VE?
Ve
@NOLSAND
(21) =ZxQ cr Ob
cr GL
SAM ODL
cSAD EL
SAQ AL
4rd VE
LNOILSAND

4

8102 eunp ys, uowOg Ly) YS-eujeping BupLeW-oSN

2d S8QUDIN [LOIS

— Sapet
J8AO LUN) aSPAIg

paniesa, 1yBUKdos

‘seed g jo s}s!suo auljapin6 Burywew sIUL

00L ‘SMUVW
Sanoy Z :SWIL

bE aaVved

ALVIISILYS9 YOINSS

TWNOLLWN

ANITAGINS ONDVN

8Loz ANN

1SS1 NOWAWOS

(AMLSIINSH9) Zd SHONSIOS TWOISAHd

Stee see eee eee eee ee?

TWLIVN-NINZYMI SO ADNIAQUd
uoyeonp3
juewLedeq

uoneonps

### Page 14

Downloaded from hlayiso.com

Physical Sciences P2 NSC-Marking Guideline-GR. 11 Comm. est June 2018
3
QUESTION 3
3.1 Sharing of electrons between 2 atoms to form a molecule. ¥ ¥ (2)

3.2 Water has an angular shape” whereas hydrogen cyanide has a linear shape.”
Water has two lone pairs on the central atom whilst hydrogen cyanide has no lone pairs
on the central atom. ” The repulsion between the lone pairs and bond pairs is stronger
than that of the bond pairs and bond pairs, hence giving water an angular shape.” (4)

33 HXCMNE wv @)
He

3.4 The same mass of liquid water has a smaller volume than that of icev because of
(the predominance of) Hydrogen bonding in ice’,
hence ice has a smaller density than liquid water.”

(3)
OR

Ice has a lower density than water. “ The molecules are loosely arranged in a tetrahedral
structure with lots of space” within the structure. There are fewer molecules per volume
of ice than per volume of water. “

3.5.

Sodium ion (Na*).” The water molecules are orientated in such a way that the negative

ends of the dipoles are attracted by the positive ion. (2)

3.5.2. The electrostatic force holding the ions in the crystal lattice are much stronger than the
ion-dipole forces” between ions and the water molecule. Large numbers of water
molecules “ need to surround the ions in order to overcome the strong electrostatic
forces Y and pull the ions apart. (3)

[16]

Copyright reserved Please tum over

Physical Sciences P2 NSC-Marking Guideline-GR. 11 Common Test June 2018
4

QUESTION 4

4.4 Boyle’s Law.
The pressure exerted by an enclosed gas is inversely proportional to the volume ”

it occupies at constant temperature. ¥ (3)
42 pw = p2V2 ¥

105x50Y = 450¥ x V2

V2 = 11.67 dm ¥ (4)

POSITIVE MARKING FROM 4.2.

43 Gradient pV
450-105
iol
11,67 50
= 5251. 957 J

y

pV = nRTV (450 x 10 x 11.67x107 ) W=nx 8.31% 298¥

n=2.121 mol

5251.957 = n x8.31 x 298”

n= 2.121 /2.12 mol

n =miM Can use 105 x 10x 50 x 10?
2.121=mi4v
m = 8.484/ 8.483 /8.48 g v (5)

1/V (dv)

Please turn over

Copyright reserved

### Page 15

Downloaded from hlayiso.com

Jono win} oseaig

(9)

4 PSMBST EA SOT = 02 x (SH/et) = x
/OBW B02 <— Bx

POBWHSL <— BWHUL

St (OBI 50Z) PiaiA %OOL 40} pauinbas BW Udy
OBW S¢1 = 607 jo %Gz seni6 By 62} ing

%00b
SEM PIAA BU} J! Pesinbes aq pinom By Bz,

/Ber = ozxlog/er) = x

paniasar jyBuAdog

/ ‘paunBsT BW JOB OL = Ozx(S1/2i) = x
/60Z <— Bx
AOBWB SL — 66 21
(OBW 502) PIeK % 00} 40; papssu BY Jo sseyy
“(OBW 5g 1) pia %Gz Send By 6 Z) Ing
%OOLSeM pjaik ay} 4! pasinbas aq pinom By 6z,
6z,=w
Pei = 0S'0
yu = Su
/ ‘ow Q¢‘9 = Ofmu = Gwu

[OW 0¢‘0 S! pasinbes QByy jo sajow jo ‘oN,

Jow og‘9 =
POBW 6 0Z — By bx
/ Ov/0% =
/08N 5 og — BW 6 gy
W/u = ofwu
z9 YO
VNOUdO z9
SNLB 2G = AROSE)
os'y
(9) 1 0st * =x = Mund %
= und ; °
yp gaee qund % 00L gLy'z
6olr'zsw

» “Ous 6 6ze% = x

/ 4OS)us 6 08% — »¢QUS 5 x

, oss BLE “OU 61g)
APOS)US B(8Z}+ ¥O+ELL)— ZOUS 6(ze+ ELL)

19HO

/LGL/W = 9100
IW/w = 20vsu
/IOW 9L0‘O = e(Pos)usu = roUsU

[OW 9L0'0 =

Houw-6 Lie = (QLxe) + (2xZe) +6LL ="

BLOZ eunf ysey UoWWOD

9

LL “S-Sullepind Bupuen-OSN

7 Lee 7 =
A WW = arosies u ie)

9 NOLLSAND

2d S89U9IDS |edIshud

J8AO UN} ASESIq

lon]

paniasar yySukdog

A ®QSzy SI eINWUOY jeouIdW

[ £ { Lbe O/6r6'0 6h6'0 = 9L/6L'SL 6ESL ()
A> LT,~ = Ze ozo | A Zie0 = ccler OF el or Ss
Lz Cireoeego £€9'0 = 6E/80'be 89% x
__Oney | ou }semo} Aq apiniq (jou) Wis U | sseyw jusweyz

eos

(Z) ~~ “@uIquiog punodulos & UP SJUBLU8]/9 YOIYM Ul Od JaquuNu a]OYM IsejdWig res

os
/ ld G2 =A
(y) 7 UA+ 081) X S00 = 4 ‘AX SL'0
auo Aue p TAZ = Abo
AX = u ens
/ 442009 = <44P09'0 = A
/AN60'0 = SLO
(v) W4=9 |» wu9009 = cP 090 =A
Binwo} Aue » Jowgo'O = AX S'SST ‘
‘souiseo'el = |“ “sever = “S10
Ww =u ww
zis yO Aa 9 zis
(Z) 7s “Ki981001d UMOUY SI UOEJUEDUCD asoyM uonnjos Y LL
Vg
S NOLLS3ND
(61)
(¢) 7 “SuunjOA Ul Sseaioul Ue Ul DUAINSSL

INDI Oy SUIDeq Seb SUT» ‘aseaiou! pue jueoyiubis ewoosg sojed sy) usamjsq

UoHoeME Jo seo} SY| _» seYya60} Joso[ oue Sajoned seB ayy eunsseid ySIy iy Sb

S

8102 unr so) UoWL n> bE US-euyaping BupyeW-OSN

Zd seouans jeoIskyg

### Page 16

Downloaded from hlayiso.com

Physical Sciences P2 NSC-Marking Guideline-GR. 11 Comm. est June 2018
7

6.2 OPTION2
20 g Mg represents a 75% yield. ¥
Therefore, 100% yield would be 26,667 g. ~

Ngo = m/M

26,667/40 v

0,667 mol

Aig = Ngo = 0,667 mol

Nig = m/M

0,667 = m/i24v

m= 16g (16,03 g) (6)
6.3.1 The reactant that gets used up completely in a reaction. vv (2)

6.3.2 Criteria for marking.

« Converting 30 g of Al to moles (1,11 mol). “

« Establishing that Al is the limiting reagent. v

« Applying ratio (4:3) to determine moles of O2 used. “

+ Subtracting moles used from initial moles to determine excess moles of O2.
e Using the formulan = V/Vm ~

¢ Substituting 22,4 dm® in the above formula. ~

e Final answer.

Physical Sciences P2 NSC-Marking Guideline-GR. 11 Common Test June 2018

8

OPTION 2
nal =m/M
= 30/27 v (any one)
= 1.11 mol
aaa

Noz required to react = es 3 = 0.8325 mal (< 1.50 mol).

Limiting reactant is Al. v

OR
n(O2) = 1.50 mol

n(Al) required = =°x4 = 2 mol > 1.21 mo!)

Limiting reactant is Al. ¥

OPTION 1
4Al + 302 2ALOs
4 3
411v 1,5
Change in moles | 1,11” 0,8325”
End moles 0 00,6675”
n=VNm ¥
0,6675 = V/22.4v (7)

V = 14,952 dm? v

Copyright reserved Please turn over

Therefore, no of moles of O2 in excess = 1,5—0,8325 = 0,6675 mol”
n=VNn¥
0,6675 = V/22.4v

V= 14,952 dms v

Copyright reserved

(7)
(21]

TOTAL : 10

## Related documents

- [PHY-NOV-P2-QP and MEMO](https://www.hlayiso.com/library/phy-nov-p2-qp-and-memo/18b69479-5bb0-43f1-b3c2-beb1ccecbd90) — Physical Sciences · QP + Memo · 2018
- [PHY-P2-JUNE-QP and MEMO](https://www.hlayiso.com/library/phy-p2-june-qp-and-memo/9e25beac-5ff8-4abc-8f45-5829ce83e759) — Physical Sciences · QP + Memo · 2016
- [Gr11 Phy P2 June 2018 Question Paper](https://www.hlayiso.com/library/gr11-phy-p2-june-2018-question-paper/47e18220-982b-4312-8d1a-23e4324550cb) — Physical Sciences · QP · 2018
- [Gr11 Phy P2 (Afrikaans) June 2018 Question Paper](https://www.hlayiso.com/library/gr11-phy-p2-afrikaans-june-2018-question-paper/fd9f92c8-f4d1-4104-926b-48e832bea015) — Physical Sciences · QP · 2018 · Afr
- [Physical Sciences P2 Grade 11 Nov 2018 Eng](https://www.hlayiso.com/library/physical-sciences-p2-grade-11-nov-2018-eng/d0518374-65a3-4ce2-9d2a-a1a55228d2e2) — Physical Sciences · QP · 2018 · Eng
- [Physical Sciences P2 Grade 11 Nov 2018 Memo Eng Afr final](https://www.hlayiso.com/library/physical-sciences-p2-grade-11-nov-2018-memo-eng-afr-final/7f7ed4bb-fb23-410e-8745-7bbc9bed4d0a) — Physical Sciences · Memo · 2018 · Eng

## More from Grade 11 Physical Sciences

- [Grade 11 Physical Sciences P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-11-physical-sciences-2026-november-mock-exam-2-question-paper-paper-2/4bd46b50-41c8-4670-83a6-c99f40ba7aa1) — QP · 2026 · Eng
- [PHYSICAL SCIENCES P2 GRADE 11 MEMO NOVEMBER 2025 ENG & AFR watermark](https://www.hlayiso.com/library/physical-sciences-p2-grade-11-memo-november-2025-eng-afr-watermark/fb381415-e8f2-4b7c-86d6-7d7c27b3a4f4) — Memo · 2025 · Eng
- [PHYSICAL SC P1 QP GR11 NOV 2025 AFRIK watermark](https://www.hlayiso.com/library/physical-sc-p1-qp-gr11-nov-2025-afrik-watermark/3757d93e-3b4a-4e27-9a6b-69591d990a97) — QP · 2025 · Afr
- [PHYSICAL SCIENCES P2 GR11 MEMO 2024 ENG AFR watermark](https://www.hlayiso.com/library/physical-sciences-p2-gr11-memo-2024-eng-afr-watermark/f8ef6058-1783-44bd-b372-4b15bc7c5c5c) — Memo · 2024 · Eng
- [PHYS SCIENCES P1 QP GR11 NOV 2024 AFR D watermark](https://www.hlayiso.com/library/phys-sciences-p1-qp-gr11-nov-2024-afr-d-watermark/918f95ae-174f-4a62-9066-40676642795b) — QP · 2024 · Afr
- [PHYSICAL Sc. P2 QP GR11 NOV 2024 mod 2 AFR D watermark](https://www.hlayiso.com/library/physical-sc-p2-qp-gr11-nov-2024-mod-2-afr-d-watermark/bbef0c4c-a5ac-4c63-b922-d8a9b7e96678) — QP · 2024 · Afr

## Collection

- [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.
