# Physical Sciences Grade 11 P1 March Test 2018 Paper & Memo

> Grade 11 Physical Sciences Paper 1 question paper and memo from the March Test 2018, 14 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/phy-mar-p1-qp-memo/668ca3ab-2233-44d3-b391-b8c15b732ace
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2018
- Exam period: March Test
- Paper: 1
- Curriculum: CAPS
- Pages: 14

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## About this document

Physical Sciences · Grade 11 · March Test · 2018. Question paper and memorandum, 14 pages. Read online or download the PDF.

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## Document text

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Physical Sciences /P1 2 March 2018 Common Test

NSC

INSTRUCTIONS AND INFORMATION TO CANDIDATES

a

Write your name on the ANSWER BOOK.

This question paper consists of FIVE questions. Answer ALL the questions in the ANSWER
BOOK

Start EACH question on a NEW page in the ANSWER BOOK

Number the answers correctly according to the numbering system used in this question
paper

Leave ONE line between two subsections, for example between QUESTION
2.1 and QUESTION 2.2

You may use a non-programmable calculator.
You may use appropriate mathematical instruments.

You are advised to use the attached DATA SHEET.
Show ALL formulae and substitutions in ALL calculations.

Round off your final numerical answers to a minimum of TWO decimal places.

Give brief motivations, discussions, et cetera where required.

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Physical Sciences /P 1

March 2018 Common Test

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NSC

QUESTION 1 : MULTIPLE CHOICE QUESTIONS

Four options are provided as possible answers to the following questions. Each question
has only ONE correct answer. Write only the letter (A - D) next to the question number
(1.1 — 1.4) in the ANSWER BOOK, for example 1.5 D.

1.1. Two forces A and B act at the same point O as shown in the sketch below.

When the angle © between the forces changes, the resultant force
obtained varies between 12 N and 6 N. What is the possible magnitude of the
larger applied force?

A

B
Cc
D

3N
18.N
6N
ON (2)

1.2 A book of mass 80 g is at rest on a horizontal table.

Ground
The Reaction force to the book’s weight is .........
A The force exerted by the book on the table.
B The force exerted by the table on the book.
Cc The force of the Earth on the book
D The force of the book on the Earth. (2)

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Physical Sciences /P1 4 March 2018 Common Test
NSC

1.3. The velocity-time graph below represents the motion of a body along a
frictionless horizontal surface.

Which one of the statements below is INCORRECT for this motion?

A The acceleration is constant, and is opposite to the direction of motion.
B The acceleration is constant, and in the same direction to the motion.

Cc A constant net force acts on the body but in the opposite direction to
the motion.

D A constant applied force acts on the body in the opposite direction to
the motion. (2)

1.4 Two objects A and B are released from the same height(h) at the same time.
The weight of A is twice that of B.

If we ignore the effects of air resistance, we would notice that:

Object A strikes the ground first.

Object B strikes the ground first.

They both strike the ground at the same time.

They both strike the ground at the same time, but with different velocities.

0 OD >

(2)
[8]

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Physical Sciences /P1 5 March 2018 Common Test
NSC

QUESTION TWO

Three forces Fi, F2 and Fs act at a point, as shown on the Cartesian plane in the
diagram below

Yo
10
5
Fy
Fs
¢ —+ >
-10 5 10s
Vv
Scale: 1 square unit represents 1 N
2.1. Define the “resultant vector” (2)
2.2. Write down the X-component and Y-component for force Fo. (2)
2.3. Calculate the NET horizontal component for the forces F;, F2 and Fs (1)
2.4 Calculate the NET vertical component for the forces F;, Fz and Fs (1)

2.5 Calculate the magnitude and direction of the resultant force of these three
forces. (4)
[10]

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Physical Sciences PD OWNloaded from hlayiso.com

March 2018 Common Test
NSC

QUESTION THREE

A man stands on the scale in a stationary lift as shown in the diagram below.
The scale is calibrated in Newtons and reads 882 N.

(Image adapted from Fundamentals of Physics
Extended -10" edition)

3.1. Calculate the mass of the man. (2)
3.2 Draw and label a free body diagram to show the forces acting on the man. (2)
The Lift begins to move.
3.3 Calculate the reading on the scale when the lift is moving:
3.3.1 Downwards at constant velocity of 4 m:s'. (2)

3.3.2 Upwards with a uniform acceleration of 2 m:37 (3)

[9]

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Physical Sciences /P1 March 2018 Common Test

NSC

QUESTION FOUR

Two wooden blocks of mass 20 kg and 10 kg are placed on a rough horizontal surface.

A rope connects the two blocks.
When a horizontal force, F, of magnitude 55 N is applied to the blocks as shown,

the blocks accelerate to the right at 0,36 ms?

20 kg F=55 N
10 kg }——>

The kinetic frictional force between the 20 kg block and the surface is TWICE
‘hat between the 10 kg block and the surface.

4.1. State Newton’s Second law of motion in words. (2)

4.2. Drawa labeled free body diagram to show all the HORIZONTAL
FORCES acting on the 10 kg block as it moves. (3)

4.3 By applying Newton’s 2” law of motion separately to each of the blocks,
calculate:

4.3.1. The magnitude of the frictional force between the 10 kg block and the
surface. (5)

4.3.2 Ux the coefficient of kinetic friction between the blocks and the surface. (3)
The rope connecting the two blocks is now cut.

4.4 How will this affect the acceleration of the 10 kg block?
(Choose from: INCREASES, DECREASES or REMAINS THE SAME.)

Explain. (3)
[16]

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Physical Sciences /P1 8 March 2018 Common Test
NSC

QUESTION FIVE

5.1. State Newton's Law of Universal Gravitation in words (2)

5.2 A satellite of mass 225 kg orbits the Earth at an altitude of 6370 km.

7
we Gp Satellite
x Nile ¥
va Ripe
a ve
/ $ .
%
‘ S \
/ oO N
f \
\
i
\
i \
!
\
!
|
|
1
t
\ i
‘ i
‘ i
‘ é
\ f
\ va
‘ ra
5 f
, ft
‘ f
* “
x a
“Bs Fd

If the gravitational force of attraction between the Earth and the satellite is
551,33 N, calculate the mass of the Earth. (5)

[7]
TOTAL MARKS :50

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Physical Sciences /P1

NSC

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March 2018 Common Test

DATA FOR PHYSICAL SCIENCES GRADE 11

PAPER 1 (PHYSICS)

GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 11

VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

NAME/NAAM SYMBOL/SIMBOOL VALUE/WAARDE
Soni von Aurel Re 6,38 x 10° m

TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING

Vv, =v,+aat

Ax =v At+fadt?

vo =v? +2aAx

ae (SY a
2 |

FORCE/KRAG
Fie = ma w=mg
Gm,m 1,
F= 2 2 by = i.
f,
Hy = 7

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Physical Sciences P1 3
NSC-~(Grade 11)

QUESTION THREE

3.1 W =mg
882 = m.9,8 v
m =90kg v
3.2

Fecate / Fromei!Fu ¥

Foravity / Fweight Fg ~

Take downward motion as positive

3.3.1 Fer = ma NB: Fecale = m-g
Fy +( —Fecate ) = m-a
882— Fecale = 0 ¥
Fecale = 882 N v

= 90-98
= 882 Nv
Max mark : 1/2
3.3.2 Take upward motion as positive
Fret = m-a
v (any one}
Fscate + (— Fg) = m-(a)
scale + (— 882) = 90(2)v
Fecale = 1062 N ¥

Copyright reserved

Maren 2018 Common Test Physical Sciences P1 4 March 2018 Common Test

NSC-(Grade 11)

QUESTION FOUR

4.1. Ifa non zero NET force acts on an object, then the object accelerates in the
direction of the NET force where the acceleration of the object is directly proportional

(2) to the NET force and inversely proportional to the mass of the object.“ (2 or 0)
(2)
4.2 10kq block
od Fv
By eS
1 mark - label and vector (3)

4.3.1 Consider the 10kg mass

(2) Fer = ma
¥ (any one]

F + (-T) +(-fa) = m-a
55—-T-f = 10(0,36)
T=514-f v..

If masses are added , then

maximum 3/5

(1)

Consider the 20kg mass
Fret = m-a
T + (-2f) = 20(0,36)

T=7.2+2f v... weve)

Equating (1) and (2)

51,4-fk =7.2+2f v (1 mark for equating the two equations)

(3) fx =14,73 N
(9] The Kinetic frictional force on the 10kg block = 14,73N ¥ / fkioxg = 14,73N¥ (5)
43.2 f= pK N Qe —

fic = px mg) oa

2(14,73) = ux-(20}(9,8) or
bk = 0,15”

4.4 or vy

hen the string is cut, the accelerating mass decreases ¥ and since the
acceleration is inversely proportional to mass, the acceleration increases. ”

414,73 = pe (109.8) ¥
pe = 0,15 ¥ (3)

or the mass of the system decreases” and by Newton's second law,

the acceleration increase” (3)

[16]
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