# Physical Sciences Grade 11 P1 NSC Prelim 2018 Paper & Memo

> Grade 11 Physical Sciences Paper 1 question paper and memo from the NSC Prelim Exam 2018, 30 pages. Read online or get the free PDF download.

- Page: https://www.hlayiso.com/library/phy-sept-p1-qp-memo/9ddfcbf3-f96b-4de6-9a2e-39cfdf3e8184
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 11
- Document type: Question paper and memo
- Year: 2018
- Exam period: NSC Prelim Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 30

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Physical Sciences · Grade 11 · NSC Prelim Exam · 2018. Question paper and memorandum, 30 pages. Read online or download the PDF.

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### Page 1

education

Department:
Education
PROVINCE OF KWAZULU-NATAL

NATIONAL
SENIOR CERTIFICATE

| (" GRADE 11 |

PHYSICAL SCIENCES P1 :
a (PHYSICS)
i SEPTEMBER 2018 :
. COMMON TEST :

| TIME: 3 hours

MARKS: 150

This question paper consists of 18 pages, two data sheets and a special answer sheet.

### Page 2

Physical Sciences /P1 2 September 2018 Common Test
NSC

INSTRUCTIONS AND INFORMATION TO CANDIDATES

1. Write your name on the ANSWER BOOK.

2. This question paper consists of EIGHT questions. Answer ALL the questions in the
ANSWER BOOK.

3. Questions 5.2.1 and 9.3 must be answered in the special answer sheet provided. Write
your name on this sheet and submit it together with your answer book.

4. Start EACH question on a NEW page in the ANSWER BOOK.

5. Number the answers correctly according to the numbering system used in this question
paper.

6. Leave ONE line between two subsections, for example between
QUESTION 2.1 and QUESTION 2.2.

7. You may use a non-programmable calculator.
8. You may use appropriate mathematical instruments.

9. You are advised to use the attached DATA SHEET.
10. Show ALL formulae and substitutions in ALL calculations.

11. Round off your final numerical answers to a minimum of TWO decimal places.

12. Give brief motivations, discussions, et cetera where required.

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### Page 3

Physical Sciences /P1 3 September 2018 Common Test
NSC

QUESTION 1 : MULTIPLE CHOICE QUESTIONS

Four options are provided as possible answers to the following questions. Each question has
only ONE correct answer. Write only the letter (A - D) next to the question number (1.1 — 1.10)
in the ANSWER BOOK, for example 1.11 D.

1.4 Which of the following pairs are both vector quantities?
A Displacement and energy
B Speed and force
Cc work and mass
D

Weight and acceleration (2)

2 Two forces A and B each of magnitude 15 N act on the same point O. If the resultant
of these forces is 15 N, what is the magnitude of the angle 0 between them?

A 60°
B 120° B
Cc 90°
D 30°

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### Page 4

1

1.4

Physical Sciences /P1 4 September 2018 Common Test

NSC

3. Three forces with magnitudes F;,F2 and Fs; act on the same point P in the same plane.

The system is in equilibrium.

v
The resultant of the Y components of the forces force is given by :

A

B
Cc
D

Fysin 0 + F2+Fs
F3-Fycos 0
F, + Fycos0
Fisin @- Fo

In which of the following cases is the resultant force acting on an object equal
to zero?

A An object is moving with constant acceleration.

B When the only force acting on the object is the gravitational force.

Cc An object undergoes equal displacements every second.

D An object is moving with increasing acceleration.

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### Page 5

Physical Sciences /P1 5 September 2018 Common Test
NSC

1.5 Two blocks, A and B, with masses m and 2m respectively, are in contact with

1.6

each other. The blocks are accelerated by a horizontal force F along a
frictionless, horizontal surface.

B

What is the magnitude of the force that B exerts on A?

A 2F
BOF

C 2/3

DF (2)

Which of the examples stated below best describes Weightlessness?

A An object accelerates downwards towards the Earth at an acceleration
of 9,8 mss”,

B An object moving at a constant velocity upwards away from the ground.
c An object moving at constant velocity downwards towards the ground.

D An object that is accelerated upwards away from the ground by a constant (2)
applied force.

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### Page 6

1.7

1.8

1.9

Physical Sciences /P1 6 September 2018 Common Test
NSC

The diagram below represents a ray of monochromatic light passing from
air into quartz.
Normal

air

\

\

1

\

quartz '

\

'

i

\

F

Which path will the ray follow in the quartz?

iwRek
OnDOTV

The field generated around a current carrying conductor is

a magnetic field

an electric field

parallel to the conductor

greater further away from the conductor. (2)

0DOD>Y

In the diagram below, a unit positive charge q is located between two charged spheres,
A and B. Sphere A has a charge of +2q and is located x meter from charge q. Sphere B
a charge of —2q and is located ’% x meter from charge q.

+2q +q -2q

--- A> @ By --
x xX

If the magnitude of the force on charge q due to sphere A is F,
what is the magnitude of the force on charge q due to sphere B?

A “a F
B 2F
Cc AF
D 4F

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### Page 7

Physical Sciences /P1

NSC

1.10 Consider the circuit diagram below:

September 2018 Common Test

O-

)

2R

When switch S is closed, the readings on V and V2 (respectively) will

change as follows:

Mi V2
A_ | decreases increases
|B | increases decreases
C_ | decreases decreases
D | increases remains the same

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[20]

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### Page 8

2.1

2.2

2.3

2.4

Physical Sciences /P1 8
NSC

QUESTION 2

September 2018 Common Test

In the system below the two masses labelled m and 10 kg are connected to
each other by two light strings A and B at point O. Point O is kept stationary

by attaching it to a wall using string C.

The coefficient of static friction between the 10 kg mass and its surface is 0,51.

ra
SS
140°

‘ Cc
SS

~ e)

A

SS
es

Cr)
IS

Define static friction.

10 kg

Calculate the magnitude of the frictional force between the 10 kg mass and

its surface.

Determine the mass of m.

Will the force in string A increase, decrease or stay the same if string B

is detached from the 10 kg mass?

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### Page 9

Physical Sciences /P1 9 September 2018 Common Test

NSC

QUESTION 3

3.1

3.1.3

A force of magnitude 40N is applied to a 3 kg block at an angle of 60° to
the horizontal along a rough surface (surface1) as shown below. A second
2kg block is placed on the rough upper surface (surface 2) of the first
block. The two blocks are joined by a string of negligible mass running
through a frictionless pulley. The kinetic frictional force between the 3 kg
block and surface 1 is 2 N whilst the kinetic frictional force between the
2kg block and surface 2 is 1,2 N. Let T be the tension in the strings
connecting the two blocks as the 3kg block accelerates to the

right.

Surface 2 F=40N

Cee ]
Surface 1

Define Newtons Second law of motion. (2)

Draw a labelled free body diagram showing all the forces acting on the

3 kg block. (5)
Calculate the Tension(T) in the string (7)
[14]

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### Page 10

Physical Sciences /P1 10 September 2018 Common Test
NSC
QUESTION 4
4.1 State Newton’s Law of Universal Gravitation in words. (2)

4.2 The velocity - time graph shown below describes the motion of an object
of mass m thrown upwards and then falling downwards on Planet X for 5s.
Assume that the only force acting on the object is the gravitational force of planet X.

Velocity(ms”) vs time(s)

am T t a iia T 7
Teh ay ter | i i T Eee Cee CT COP rr

i f | rt COE
ala on it L I im i

Tit

The radius of planet X is 6,22x10° m. Using the graph above and relevant formulae, (5)
calculate the mass of planet X.

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### Page 11

Physical Sciences /P1 1 September 2018 Common Test
NSC

4.3. Asatellite is orbiting planet X. When the satellite is on the line joining the
centres of planet X and planet Y, the net gravitational force acting on the
satellite due to planet X and planet Y is zero.

The distance between the centres of planet X and planet Y is 1x10’m

Planet Y

If the mass of planet Y is twice the mass of planet X, calculate the distance of the
satellite from planet X. (4)

[11]

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### Page 12

Physical Sciences /P1 12 September 2018 Common Test
NSC

QUESTION 5
5.1 Define refraction of light. (2)

5.2. A ray of light is incident upon the surface of a semi-circular glass block as
shown in the sketch below.

Air Glass Air

5.2.1 Using the diagram sheet provided, complete the diagram
by showing the path taken by the light ray as it passes from air to glass and then to
air. Label the angle of incidence, the refracted ray, the emergent ray and draw the
normal at each surface. (4)

5.2.2 If the refractive index of glass is 1,50, calculate the speed of light through glass
given that the speed of light in air is 3x10° ms“
Take the refractive index of air to be 1,00. (3)

5.3. The drawing shows a ray of light travelling through a gas (n = 1.00), then through a
solid (n = 1.55), and then into a liquid (n = 1.45).
The surfaces are parallel and the angle of refraction at the first surface is 25,42°.

Gas Solid
5.3.1 State Snell’s law. (2)
5.3.2, Calculate f ,the angle of refraction at the second surface. (4)
A
5.3.3 [Ifthe size of ii is increased, will the size of angle ty increase, decrease or remain
the same? (2)
[17]

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### Page 13

Physical Sciences /P1 13 September 2018 Common Test
NSC

QUESTION 6

6.1 The sketch below shows a phenomenon that takes place when parallel wave fronts
approach a narrow opening in a barrier.

Direction of wave motion

! J |

6.1.1 State and define the above phenomenon. (3)

6.1.2 Sketch the wave pattern that occurs when the wave fronts pass through
the opening in a barrier. (2)

6.1.3 The wave pattern that forms is explained by Huygens principle.
State this principle. (2)

6.2 When monochromatic blue light is passed through a narrow single slit, a pattern is
observed on a screen.
Describe the diffraction pattern which is observed on the screen. (3)

[10]

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### Page 14

Physical Sciences /P1 14 September 2018 Common Test

NSC

QUESTION 7

fal

7.2

7.3

74

75

7.6

7.7

A small, conducting sphere, X, with a charge of +5 nC is suspended by an insulated
inelastic thread of negligible mass, which is tied to point P. Another small
conducting sphere, Y, on an insulated stand, with a charge of —3 nC, is brought
closer to X until their centres are 15 mm apart on the

same horizontal line.

Draw the resultant electric field pattern produced by spheres X and Y. (3)
State Coulomb's law in words. (2)

Calculate the magnitude of the electrostatic force that sphere Y exerts on

sphere X. (4)
Define Electric field at a point. (2)
Calculate the magnitude of the electric field 15mm away from sphere X (4)

Sphere Y is now moved closer and makes contact with sphere X
and moved back to its original position, that is 15mm from X.

Will electrons be transferred from spheres X to Y or from spheres Y to X? Give a

reason for your answer.
* (2)
Calculate the number of electrons transferred upon contact. (4)
[21]

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### Page 15

Physical Sciences /P1 15 September 2018 Common Test
NSC
QUESTION 8
8.1 The sketch below shows a current carrying solenoid that is wrapped around a soft
iron core.

( C

~~.

iron core

ss
ae

Does A represent the North pole or the South pole of the magnetic iron core?

8.1.1 Is the magnetic field direction outside the iron core from A to B or from

Bto A?
_. ; _ (1)
8.1.2 A coil is moved into or out of a magnetic field of a bar magnet as shown below so
that the rate of change of magnetic field, AB = 0,6 Tes~'

8.2
N Ss
N iS)
The area through which the field links with the coil is given by A = 0,4 m?.
8.2.1 State Faraday’s law of electromagnetic induction in words. (2)
8.2.2 Calculate the magnitude of the average emf generated in the coil, if the coil has 8
turns. (4)
8.2.3 If the experiment is repeated with a new coil that has twice as many turns, what
would the new emf be? (2)
[10}

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### Page 16

Physical Sciences /P1 16
NSC

QUESTION 9

September 2018 Common Test

Learners conduct an investigation to verify Ohm’s law. They measure the current
through a resistor for different potential differences across its ends, i.e. the potential
difference was chosen as the independent variable.

The results obtained are tabulated below:

Potential Current
Difference (V) | Strength (A)
21,4 0.80
35,8 1,20
56,0 1,90
72,04 2,30
98,04 3,20
124,04 4,13

a1 State Ohm’s law in words.

g.2 The dependant variable in this investigation was the current.

9.2.1 Name one quantity that was controlled in this investigation.

9.2.2 State how the quantity in Q 9.2.1 was kept constant

9.3. Using the information in the table and the graph sheet provided, draw a graph of (5)

Current versus Potential difference.

9.4 Calculate the gradient of the graph.

9.5 What quantity does the gradient of the graph represent?

9.6 Hence determine the resistance of the resistor.

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### Page 17

Physical Sciences /P1 17 September 2018 Common Test
NSC

QUESTION 10

10.1 You are given four identical resistors, each of magnitude ‘R’ and a
battery of emf ‘V’ volts.

10.1.1. Sketch an appropriate circuit diagram, using all the above components,
to show how you would connect them to obtain a total resistance of R in the
circuit. (2)

10.1.2 Use relevant calculations to show that the total resistance in your circuit in
Q10.1.1 is equal to R. (2)

10.2 The circuit diagram below shows a battery of unknown EMF with negligible internal
resistance, connected as shown below.

The reading on the voltmeter is 4 V.

Calculate:
10.2.1 the effective resistance in the circuit. (3)
10.2.2 the current flowing through the 1 resistor. (3)
10.2.3 the reading on the ammeter. (4)
10.2.4 the EMF of the battery (3)

10.3 The switch S is now opened.

10.3.1 How will the energy dissipated by the 4 Q resistor change if the time it is in
operation remains constant? State whether it will increase, decrease or remain

the same. (1)
10.3.2 Briefly explain your answer using relevant formulae . (2)
[20]
TOTAL : 150

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### Page 18

Physical Sciences /P1 18 September 2018 Common Test
NSC

DATA FOR PHYSICAL SCIENCES GRADE 11
PAPER 1 (PHYSICS)

TABLE 1: PHYSICAL CONSTANTS

NAME SYMBOL VALUE
Acceleration due to gravity

9,8 ms?

Gravitational constant 6,67 x 10°11 N-m2-kg2

Coulomb's constant 9,0 x 109N-m2-C2

aO;xX,o!] a

Speed of light ina vacuum 3,0 x 108 m-st

Charge on electron -1,6x107C

oO

Electron mass 9,11 x 1031 kg

Radius of earth Re 6,38 x 108m

Mass of earth

Me 5,98 x 1074 kg

TABLE 2: FORMULAE
MOTION

Vv, =v, +adt Ax = v,At+ daat?

2

v, tv
Vy =v, + 2aAx Ax = (“ga

FORCE

Fret = Ma w=mg

A
Gm,m, f
— s(max)

f, = 14.N
WAVES, SOUND AND LIGHT

va=far T=

F= =n,N

g--—~
R

; ; c
n, sind; =n, sin@, n=—

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### Page 19

Physical Sciences /P1

19

September 2018 Common Test

NSC
ELECTROSTATICS
kQ,Q E
FS 2 s (k = 9,0 x 10° N-m?-C*) wart
E= LS (k = 9,0 x 10°N-m?-C-?) vet
ELECTROMAGNETISM
e--No@ ®=BAcos0
At
CURRENT ELECTRICITY
j=-8 Ra”
At |
At yt t Ret fp +Ig+
Rh & ee ease
W=Vq Ww
~ At
W=VIAt
W=PRAt Pew
> P=PR
wy = _ ; ve
R

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### Page 21

Air

September 2018 Common Test

20
NSC

Glass

Air

Physical Sciences /P1
NAME OF LEARNER :

Question 5.2
Question 9.3
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L33HS sdO-NVAL

### Page 23

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### Page 24

Physical Sciences

OR

tan50°= W_v OR

49,98
We 59.564 N

Wem-g
59,5644 m-9,8¥
m = 6,08 kgv

2.4 Stay the samev

QUESTION THREE

3 September — .8 Common Test
NSC

Fe / 49,98 N

WIFg

tan 40°= 49,98 ¥

3.1.1 Ifa non-zero NET force acts on an object, then the object accelerates in
the direction of the NET force where the acceleration of the object is
directly proportional to the NET forceY and inversely proportional to the

mass of the object. v

3.1.2
v

‘the /Fatriction/:

<——___

TTension — fs/F riicion1,4

Ww

W = 59,564 N

W=mg

59,564 =m.9,8v (5)
(4)
[11]
(2)

F=40 NY

NB : 1 mark for all 3 vertical forces present.

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Physical Sciences 4

3.1.3. Take the motion of the system to the right as being positive.

NSC

Consider the 3 kg block

Fx = F-cos®
= 40 cos60°
= 20NY

Fver = ma

Fx #(T) + (fcr) + (fla) =3.a [ % anyone
20-T-2-1,2=3a

18 8-T= 38% cceccsce(1)
Consider the 2 kg block
Fuer = ma

fk + (-T) = 2- a)
1,2-T=-2a

TH 2atd 2%. vee(2)

Substitute equation (2) in equation (1)

16,8-(2a+12)=3a

a=312

T =aietoy vet av
= 7,44NV

QUESTION FOUR

44

September 2018 Common Test

7)
[14]

Every body in the universe attracts every other body with a gravitational
force that is directly proportional to the product of their masses” and

versely propo!
centres. ¥

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### Page 25

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### Page 26

Physical Sciences 7 September .. d Common Test

6.2.2 n= cv

v

1,50 =3x108 v
v

v= 2x10? mst v (3)
5.3.1 The ratio of the sine of the angle of incidence in one medium to the sine of
the angle of refraction in the other medium is a constant. VV (2 or 0) (2)
A
5.3.2 iz = 25,420
nisin8; = nesin@2v
1,55-sin 25,42 = 1,45 sin 62¥
a (4)
O2 = 2 = 27,319 v
(2)
5.3.2 Increases vv
[17]
QUESTION SIX
6.1.1 Single slit diffraction. v
It is the ability of a wave to spread out in wave fronts as they
pass through a small aperture or around a sharp edge’ v (2 or O marks) (3)
6.1.2
ha i as
Ne
Ee vv
(2)
If shape is asymmetrical, minus 1 mark.
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Physical Sciences 8 September 2018 Common Test
NSC
6.1.3 According to Huygens’ principle each point on a wave front forms (2)
secondary wavelets” that spreads out in all directions” forming the above
pattern.

6.2 A broad central blue band” is observed flanked on either side by
alternating narrower” dark and blue bands. “ (3)

[10]

QUESTION SEVEN

Fat

Marking Rubric : Electric field pattern

Criteria Mark allocation |
Correct direction of field lines 4 mark

Correct shape of the field 1 mark

pattern

Field lines do not touch, evenly | 1 mark
spaced, and perpendicular to
surface and touches the

surface (3)

7.2 The magnitude of the electrostatic force exerted by two point charges on
each other is directly proportional to the product of the magnitudes of the
charges” and inversely proportional to the square of the distance between
them.” (2)

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### Page 27

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Physical Sciences 11 September ~ 18 Common Physical Sciences 12 Sepiember 2018 Common

Test Test
NSC NSC
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Criteria Mark allocation y
v
° Suitable scale used on x and y 1 mark
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* Xand Y axes correctly labelled 1 mark |
with correct units
* Correct plotting of points 2 marks
Best fit curve drawn joining points | 1 mark (2)
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### Page 29

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