# Physical Sciences Grade 11 P1 2020 Memo > Grade 11 Physical Sciences Paper 1 memorandum from the Eastern Cape November 2020, 10 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/phys-p1-gr11-memo-nov2020-eng-afr/975f9edf-6aeb-4e18-be14-b1f05dfacd5e - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 11 - Document type: Memorandum - Year: 2020 - Exam period: Eastern Cape November - Paper: 1 - Curriculum: CAPS - Pages: 10 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Physical Sciences](https://www.hlayiso.com/library/grade-11/physical-sciences) › [Physical Sciences Grade 11 P1 2020 Memo](https://www.hlayiso.com/library/phys-p1-gr11-memo-nov2020-eng-afr/975f9edf-6aeb-4e18-be14-b1f05dfacd5e) ## About this document Physical Sciences · Grade 11 · Eastern Cape November · 2020. Memorandum, 10 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL/NASIONALE SENIOR CERTIFICATE/SERTIFIKAAT GRADE/GRAAD 11 NOVEMBER 2020 PHYSICAL SCIENCES P1/ FISIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN (EXEMPLAR/EKSEMPLAAR) MARKS/PUNTE: 150 This marking guideline consists of 10 pages. Hierdie nasienriglyn bestaan uit 10 bladsye. ### Page 2 Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) QUESTION 1/VRAAG 1 1.1 C ✓✓ (2) 1.2 B ✓✓ (2) 1.3 A ✓✓ (2) 1.4 A ✓✓ (2) 1.5 D ✓✓ (2) 1.6 C ✓✓ (2) 1.7 D ✓✓ (2) 1.8 B ✓✓ (2) 1.9 D ✓✓ (2) 1.10 B ✓✓ (2) [20] QUESTION 2/VRAAG 2 2.1 The vector sum of two or more vectors. ✓✓ Die som van twee of meer vektore. OR/OF A single vector having the same effect as two or more vectors acting together. ✓✓ ʼn Enkele vektor wat dieselfde effek het as twee of meer vektore wat saam inwerk. (2) 2.2 2.2.1 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 T2X = Tcos𝜃 T2X = Tsin𝜃 T2X = 245 cos 30o ✓ T2X = 245 sin 60o ✓ T2X = 212,18 N ✓ T2X = 212,18 N ✓ T2Y = Tsin𝜃 T2Y = Tcos𝜃 T2Y = 245 sin 30o ✓ T2Y = 245 cos 60o ✓ T2Y = 122,5 N ✓ T2Y = 122,5 N ✓ (4) 2.2.2 T1 = T2X ✓ T1 = 212,18 N ✓ (2) 2.2.3 W = T2Y W = 122,5 N W = mg Any one/Enige een ✓ 122,5 = m x 9,8 ✓ m = 12,5 kg ✓ (3) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 QUESTION 3/VRAAG 3 3.1 The force that opposes the motion of a moving object relative to the surface. ✓✓ Die krag wat die beweging van ʼn bewegende voorwerp relatief tot die oppervlak teenwerk. (2) 3.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 FN ✓ FY FN ✓ ✓ F✓ T✓ T✓ Ff ✓ FX Ff ✓ Fg✓ Fg✓ Mark awarded for arrow and label./ Punt toegeken vir byskrif en pyltjie. Do not penalise for length of arrows since drawing is not drawn to scale./ Moenie vir die lengte van die pyltjie penaliseer nie aangesien diagram nie volgens skaal geteken is nie. Any other additional force(s)./ Enige ander addisionele krag(te). 4⁄5 If force(s) do not make contact with body. / As krag(te) nie kontak met die voorwerp maak nie. Max./ Maks. 4⁄5 (5) 3.3 3.3.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 N = Fg – F sin θ ✓ FY = F sin θ N = 25x 9,8 – 250 sin 25o ✓ = 250 sin 25° N = 139,35 N ✓ = 105,66 N N = Fg – FY ✓ N = 25x 9,8 – 105,66 ✓ N = 139,34 N ✓ (3) 3.3.2 POSITIVE MARKING FROM 3.1.1/POSITIEWE NASIEN VANAF 3.1.1 Fnet = ma Any one/Enige een ✓ Fnet = Fcos θ – T – f [250 cos 25° ✓ – T – (0,15 x 139,35) ✓ ] ✓ = 25a 25a = 205,6744468 – T ...(1) Any one of 25a or 10a/ Fnet = T – Fg Enige een van 25a of T – 98 ✓= 10a . . . (2) 10a ✓ Adding the two equations/Tel die twee vergelykings bymekaar: 35a = 107,6744468 a = 3,08 m.s-2 ✓ (7) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) QUESTION 4/VRAAG 4 4.1 When a resultant force acts on an object, the object will accelerate in the direction of the force. The acceleration is directly proportional to the resultant force ✓ and inversely proportional to the mass ✓of the object. Wanneer ‘n resulterende krag op ‘n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel. Die versnelling is direk eweredig aan die resulterende krag en omgekeerd eweredig aan die massa van die voorwerp. (2) 4.2 FN ✓ T✓ FN ✓ T✓ Ff ✓ Fg∥✓ Ff Fg✓ Fg⊥✓ (4) Mark awarded for arrow and label. / Punt toegeken vir pyltjie en byskrif. Do not penalise for length of arrows since drawing is not drawn to scale./ Moenie vir die lengte van die pyltjie penaliseer nie aangesien diagram nie volgens skaal geteken is nie. Any other additional force(s)./ Enige ander addisionele krag(te). 3⁄4 If force(s) do not make contact with body. / As krag(te) nie kontak maak met die voorwerp nie. Max/ Maks 3⁄4 4.3 4.3.1 Fnet = ma Fnet = T – Fg// - f T – Fg// - f = ma Any one/Enige een ✓ T – Fg// - f = 0 [T – (1,5 x 9,8 sin20o) ✓- 2] ✓ = 0 ✓ T = 7,03 N ✓ (5) 4.3.2 Fnet = ma Fnet = F – T – Fg// - f Any one/ Enige een ✓ F – T – Fg// - f = ma F – T – Fg// - f = 0 [24 – 7,03 – (3,2 x 9,8 sin20o) – fk] = 0 ✓ fk = 6,22425 N fk = µ k N ✓ [6,22425 = µk x 3,2 x9,8 cos 20o✓] ✓ µk = 0,21 ✓ (6) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 QUESTION 5/VRAAG 5 5.1 Every particle attracts every other particle in the universe with a gravitational force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres. ✓✓ Elke deeltjie lok enige ander deeltjie in die heelal met ‘n gravitasiekrag wat direk eweredig is aan die produk van hul massas en omgekeerd eweredig is aan die kwadraat van die afstand tussen hul middelpunte. (2) 5.2 GM1M2 F= ✓ r2 6,67 x10 -11 x 5,98 x10 24 x1000 ✓ F= (6,38 x10 6 +2 x105 )2 ✓✓ F = 9 212,45 N ✓ (5) 5.3 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 W = mg ✓ GM1M2 W= ✓ W = 1 000 x 9,8 ✓ r2 W = 9 800 N ✓ 6,67 x10 -11 x1000 x 5,98 x10 24 W= ✓ (6,38 x10 6 )2 W = 9 799,09 N ✓ (3) 5.4 900 W= ✓ = 2 450 N ✓ 4 When the distance doubles the force will decrease by a factor of 4 ✓. Wanneer die afstand verdubbel, sal die krag vier (4) keer verminder. (3) [13] QUESTION 6/VRAAG 6 6.1 The ratio of the sine of the angle of incidence in one medium to the sine of the angle of refraction in the other medium is constant. ✓✓ Die verhouding tussen die sinus van die invalshoek in die een medium en die sinus van die brekingshoek in die ander medium is konstant. (2) 6.2 6.2.1 n2 sinθ1 = ✓ n1 sinθ 2 1,52✓ sin40° = ✓ 1 sinθ 2 𝜃2 = 25,02o ✓ (4) 6.2.2 c n= ✓ v 3 x10 8 1,52 = ✓ v v = 1,97 x 108 m.s-1 ✓ (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 6.2.3 n2 sinθ1 = ✓ n1 sinθ 2 1,52 ✓ sin90° = ✓ 1 sinθ 2 𝜃2 = 41,14o ✓ (4) 6.3 A phenomenon that occurs when light travels from a denser medium to a less dense medium and the refracted ray does not emerge from the medium, but is reflected back into the medium. ✓✓ ʼn Verskynsel wat voorkom wanneer lig van ʼn digter medium na ʼn minder digte medium beweeg en die gebreekte straal nie uit die medium kom nie, maar weer terug in die medium weerkaats. (2) 6.4 The light must travel from a denser medium to a less dense medium. ✓ The angle of incidence must be greater than the critical angle of the denser medium. ✓ Die lig moet van ʼn digter medium na ʼn minder digte medium beweeg. Die invalshoek moet groter wees as die grenshoek van die digter medium. (2) [17] QUESTION 7/VRAAG 7 7.1 Diffraction/ Diffraksie ✓ (1) 7.2 ✓✓ ✓✓ (4) 7.3 The coloured bands for red light are broader than those of blue light. ✓ The wavelength for red light is longer than that of a blue light. ✓ Die gekleurde bande vir rooi lig is breër as dié van blou lig. Die golflengte vir rooi lig is langer as dié van blou lig. (2) 7.4 Light has a wave nature / Lig het golf-aard ✓ (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 7.5 The coloured bands will become broader./ Die gekleurde bande sal breër word. ✓ The slit width is inversely proportional to the degree of diffraction. ✓✓ Die spleetwydte is omgekeerd eweredig aan die mate van diffraksie. OR/OF Smaller width gives broader diffraction./ Kleiner breedte gee breër diffraksie. ✓✓ (3) [11] QUESTION 8/VRAAG 8 8.1 CRITERIA FOR MARKING/ KRITERIA VIR NASIEN Correct shape/ Korrekte vorm. ✓ Direction of field lines./ Rigting van veldlyne ✓ Field lines not crossing each other./ Veldlyne kruis nie ✓ mekaar nie. (3) 8.2 kQ1Q 2 F= ✓ r2 9 x109 x Q 2 5,09 ✓= ✓ 0,12 Q = 2,38 x 10-6 C ✓ (4) 8.3 kQ E= ✓ r2 9 x109 x 2,38 x10 -6 E1 = ✓ 0,15 2 E1 = 952 000 NC-1 right / regs 9 x109 x 2,38 x10 -6 E2 = ✓ 0,05 2 E2 = 8 568 000 NC-1 right / regs Enet = E1 + E2 Enet = 952 000 + 8 568 000 ✓ Enet = 9 520 000 NC-1 right / regs ✓ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 8.4 kQ1Q 2 F= ✓ r2 9 x109 x 2,38 x10 -6 x 2,38 x10 -6 F1 = ✓ 0,12 F1 = 5,10 N right 9 x109 x 2,38 x10 -6 x 2,38 x10 -6 F2 = ✓ 0,05 2 F2 = 42,84 N left / links Fnet = F1 + F2 Fnet = 42,84 – 5,10 ✓ Fnet = 37,74 N left / links ✓ (5) [17] QUESTION 9/VRAAG 9 9.1 X CRITERIA FOR MARKING/ KRITERIA VIR NASIEN Circular shape/ Korrekte vorm ✓ Field direction/ Veldrigting ✓ (2) 9.2 9.2.1 The magnitude of the induced emf across a conductor is directly proportional to the rate of change in the magnetic flux linkage with the conductor. ✓✓ Die grootte van die geïnduseerde emk oor die geleier is direk eweredig aan die tempo van verandering in die magnetiese vloed met die geleier. (2) 9.2.2 Φ = B A cos𝜃 Any one/Enige een ✓ Φ = B (𝜋r2 ) cos 𝜃 Φ = 3,5 (𝜋 x 0,052 ) cos0o ✓ Φ = 0,03 Wb ✓ (0,027 Wb) (3) 9.2.3 -NΔΦ ε= ✓ Δt -350(0 - 0,03) ε= ✓ 0,1 𝜀= 105 V ✓ (3) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com (EC/NOVEMBER 2020) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 9 QUESTION 10/VRAAG 10 10.1 10.1.1 The inverse of the resistance / Die omgekeerde van die weerstand 1 OR/ OF ✓ R (1) 10.1.2 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 ΔI V Gradient/ Gradiënt = R= ✓ Δv I 1,0 - 0,2 3.0 Gradient/ Gradiënt = ✓ R= ✓ 3,0 - 0,6 1,0 Gradient/ Gradiënt = 1 R=3Ω✓ 3 1 1 Gradient/ Gradiënt = = ✓ R 3 R=3Ω✓ (3) 10.2 10.2.1 OPTION 1/ OPSIE 1 OPTION 2/ OPSIE 2 R1 = R2 V R= I1 = I 2 = 1 A ✓ I I = I 1 + I2 ✓ R = 6 + 6 = 12 Ω I=1+1=2A✓ Vp 12 = 1 Vp = 12 V 12 12 = I I=1A✓ I = I1 + I2 ✓ I=1+1=2A✓ (3) 10.2.2 V R= ✓ I Vp 12 = ✓ 1 Vp = 12 V V = V s + Vp 15 = Vs + 12 ✓ Vs = 3 V 𝑉 R= 𝐼 3 R= 2✓ R = 1,5 Ω ✓ (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/NOVEMBER 2020) 10.3 Increase, ✓ the total resistance decreases and the current increases. ✓ Verhoog, die totale weerstand verlaag en die stroom verhoog. (2) 10.4 W = P∆t ✓ W = 1,5 x 3,5 ✓ W = 5,25 kWh Cost = 5,25 x 1,15 Cost = R6,04 ✓ (3) [17] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - [PHYS P1 GR11 QP MEMO NOV2020 ENG D](https://www.hlayiso.com/library/phys-p1-gr11-qp-memo-nov2020-eng-d/bd115ce8-87af-4690-9fe1-4874548f73aa) — Physical Sciences · Memo · 2020 · Eng - [PHYS P1 GR11 QP MEMO NOV2020 AFR D](https://www.hlayiso.com/library/phys-p1-gr11-qp-memo-nov2020-afr-d/bf347714-2d55-4e0d-b6e0-231b5d4c38c2) — Physical Sciences · Memo · 2020 · Afr - [PHYS P1 GR11 MEMO NOV2020 EA D - Copy](https://www.hlayiso.com/library/phys-p1-gr11-memo-nov2020-ea-d-copy/d298680e-1a37-47a2-8ec4-76d04c1b2e22) — Physical Sciences · Memo · 2020 - [PHYS P1 GR11 QP NOV2020 AFR D](https://www.hlayiso.com/library/phys-p1-gr11-qp-nov2020-afr-d/219f2b34-9903-4f73-9c5b-4730d5aec610) — Physical Sciences · QP · 2020 · Afr - [PHYS P1 GR11 QP NOV2020 Afrikaans](https://www.hlayiso.com/library/phys-p1-gr11-qp-nov2020-afrikaans/d4278775-0f30-4e0c-960c-6cee080cc536) — Physical Sciences · QP · 2020 · Afr - [PHYS P1 GR11 QP NOV2020 English .docx](https://www.hlayiso.com/library/phys-p1-gr11-qp-nov2020-english-docx/55f26d69-fb3c-4693-acd6-05d133531976) — Physical Sciences · QP · 2020 · Eng ## More from Grade 11 Physical Sciences - [Grade 11 Physical Sciences P2 November 2026 Mock 2](https://www.hlayiso.com/library/grade-11-physical-sciences-2026-november-mock-exam-2-question-paper-paper-2/4bd46b50-41c8-4670-83a6-c99f40ba7aa1) — QP · 2026 · Eng - [PHYSICAL SC P1 QP GR11 NOV 2025 AFRIK watermark](https://www.hlayiso.com/library/physical-sc-p1-qp-gr11-nov-2025-afrik-watermark/3757d93e-3b4a-4e27-9a6b-69591d990a97) — QP · 2025 · Afr - [KZN Physical Sciences Grade 11 November 2025 P1 and Memo](https://www.hlayiso.com/library/kzn-physical-sciences-grade-11-november-2025-p1-and-memo/82b3d6a5-9e71-4efe-a8e0-f2a63d6aff58) — QP + Memo · 2025 - [KZN Physical Sciences Grade 11 November 2025 P2 and Memo](https://www.hlayiso.com/library/kzn-physical-sciences-grade-11-november-2025-p2-and-memo/f6f699c6-e985-44e2-9d36-d660697bd6fe) — QP + Memo · 2025 - [LP Physical Sciences Grade 11 June 2025 P2 and Memo](https://www.hlayiso.com/library/lp-physical-sciences-grade-11-june-2025-p2-and-memo/b76990f6-708a-47e3-a903-95cc3c58534d) — QP + Memo · 2025 - [MP Physical Sciences Grade 11 June 2025 P1 and Memo](https://www.hlayiso.com/library/mp-physical-sciences-grade-11-june-2025-p1-and-memo/4c5694d8-7cdc-4fd9-90b4-55bbb8969872) — QP + Memo · 2025 ## Collection - [Grade 11 past papers](https://www.hlayiso.com/grade-11/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.