# Physical Sciences Grade 12 P1 Eastern Cape Mock 2022 Memo > Grade 12 Physical Sciences Paper 1 memorandum from the Eastern Cape Mock Exam 2022 (Afrikaans), 18 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/phys-sciences-p1-gr12-memo-sept2022-afr-engl/6a71d1a5-9b68-409f-941e-268aa5c9914c - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2022 - Exam period: Eastern Cape Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 18 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 P1 Eastern Cape Mock 2022 Memo](https://www.hlayiso.com/library/phys-sciences-p1-gr12-memo-sept2022-afr-engl/6a71d1a5-9b68-409f-941e-268aa5c9914c) ## About this document Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2022. Memorandum, 18 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 SEPTEMBER 2022 PHYSICAL SCIENCES P1/ FISIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 18 pages./ Hierdie nasienriglyn bestaan uit 18 bladsye. ### Page 2 Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) GENERAL GUIDELINES/ALGEMENE RIGLYNE 1. CALCULATIONS/BEREKENINGE 1.1 Marks will be awarded for: correct formula, correct substitution, correct answer with unit. Punte sal toegeken word vir: korrekte formule, korrekte substitusie, korrekte antwoord met eenheid. 1.2 No marks will be awarded if an incorrect or inappropriate formula is used, even though there are many relevant symbols and applicable substitutions. Geen punte sal toegeken word waar ʼn verkeerde of ontoepaslike formule gebruik word nie, selfs al is daar relevante simbole en relevante substitusies. 1.3 When an error is made during substitution into a correct formula, a mark will be awarded for the correct formula and for the correct substitutions, but no further marks will be given. Wanneer ʼn fout gedurende substitusie in ʼn korrekte formule begaan word, sal ʼn punt vir die korrekte formule en vir korrekte substitusies toegeken word, maar geen verdere punte sal toegeken word nie. 1.4 If no formula is given, but all substitutions are correct, a candidate will forfeit one mark. Indien geen formule gegee is nie, maar al die substitusies is korrek, verloor die kandidaat een punt. 1.5 No penalisation if zero substitutions are omitted in calculations where correct formula/principle is correctly given. Geen penalisering indien nulwaardes nie getoon word nie in berekeninge waar die formule/beginsel korrek gegee is nie. 1.6 Mathematical manipulations and change of subject of appropriate formulae carry no marks, but if a candidate starts off with the correct formula and then changes the subject of the formula incorrectly, marks will be awarded for the formula and correct substitutions. The mark for the incorrect numerical answer is forfeited. Wiskundige manipulasies en verandering van die onderwerp van toepaslike formules tel geen punte nie, maar indien ʼn kandidaat met die korrekte formule begin en dan die onderwerp van die formule verkeerd verander, sal die punte vir die formule en korrekte substitusies toegeken word. Die punt vir die verkeerde numeriese antwoord word verbeur. 1.7 Marks are only awarded for a formula if a calculation has been attempted, i.e. substitutions have been made or a numerical answer given. Punte word slegs vir ʼn formule toegeken indien ʼn poging tot berekening aangewend is, d.w.s. substitusies is gedoen of ʼn numeriese antwoord is gegee. 1.8 Marks can only be allocated for substitutions when values are substituted into formulae and not when listed before a calculation starts. Punte kan slegs toegeken word vir substitusies wanneer waardes in formules ingestel word en nie vir waardes wat voor ʼn berekening gelys is nie. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 1.9 All calculations, when not specified in the question, must be done to a minimum of two decimal places. Alle berekenings, wanneer nie in die vraag gespesifiseer word nie, moet tot ʼn minimum van twee desimale plekke gedoen word. 1.10 If a final answer to a calculation is correct, full marks will not automatically be awarded. Markers will always ensure that the correct/appropriate formula is used and that workings, including substitutions, are correct. Indien ʼn finale antwoord van ʼn berekening korrek is, sal volpunte nie outomaties toegeken word nie. Nasieners sal altyd verseker dat die korrekte/toepaslike formule gebruik word en dat bewerkings, insluitende substitusies korrek is. 1.11 Questions where a series of calculations have to be made (e.g. a circuit diagram question) do not necessarily always have to follow the same order. FULL MARKS will be awarded provided it is a valid solution to the problem. However, any calculation that will not bring the candidate closer to the answer than the original data, will not count any marks. Vrae waar ʼn reeks berekeninge gedoen moet word (bv. ʼn stroombaan- diagramvraag) hoef nie noodwendig dieselfde volgorde te hê nie. VOLPUNTE sal toegeken word op voorwaarde dat dit ʼn geldige oplossing vir die probleem is. Enige berekening wat egter nie die kandidaat nader aan die antwoord as die oorspronklike data bring nie, sal geen punte tel nie. 2. UNITS/EENHEDE 2.1 Candidates will only be penalised once for the repeated use of an incorrect unit within a question. Kandidate sal slegs een keer gepenaliseer word vir die herhaaldelike gebruik van ʼn verkeerde eenheid in ʼn vraag. 2.2 Units are only required in the final answer to a calculation. Eenhede word slegs in die finale antwoord op ʼn vraag verlang. 2.3 Marks are only awarded for an answer, and not for a unit per se. Candidates will therefore forfeit the mark allocated for the answer in each of the following situations: • Correct answer + wrong unit • Wrong answer + correct unit • Correct answer + no unit Punte sal slegs vir ʼn antwoord en nie vir ʼn eenheid per se toegeken word nie. Kandidate sal die punt vir die antwoord in die volgende gevalle verbeur: • Korrekte antwoord + verkeerde eenheid • Verkeerde antwoord + korrekte eenheid • Korrekte antwoord + geen eenheid 2.4 SI units must be used except in certain cases, e.g. V•m-1 instead of N•C-1, and cm•s-1 or km•h-1 instead of m•s-1 where the question warrants this. SI-eenhede moet gebruik word, behalwe in sekere gevalle, bv. V•m-1 in plaas van N•C-1, en cm•s-1 of km•h-1 in plaas van m•s-1 waar die vraag dit regverdig. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 3. GENERAL/ALGEMEEN 3.1 If one answer or calculation is required, but two are given by the candidate, only the first one will be marked, irrespective of which one is correct. If two answers are required, only the first two will be marked, etc. Indien een antwoord of berekening verlang word, maar twee word deur die kandidaat gegee, sal slegs die eerste een nagesien word, ongeag watter een korrek is. Indien twee antwoorde verlang word, sal slegs die eerste twee nagesien word, ens. 3.2 For marking purposes, alternative symbols (s, u, t, etc.) will also be accepted. Vir nasiendoeleindes sal alternatiewe simbole (s, u, t, ens.) ook aanvaar word. 3.3 Separate compound units with a multiplication dot, not a full stop, for example, m•s-1. For marking purposes, m•s-1 and m/s will also be accepted. Skei saamgestelde eenhede met ʼn vermenigvuldigingspunt en nie met ʼn punt nie, byvoorbeeld m•s-1. Vir nasiendoeleindes sal m•s-1 en m/s ook aanvaar word. 4. POSITIVE MARKING/POSITIEWE NASIEN Positive marking regarding calculations will be followed in the following cases: Positiewe nasien met betrekking tot berekeninge sal in die volgende gevalle geld: 4.1 Sub-question to sub-question: When a certain variable is calculated in one sub-question (e.g. 3.1) and needs to be substituted in another (3.2 of 3.3), e.g. if the answer for 3.1 is incorrect and is substituted correctly in 3.2 or 3.3, full marks are to be awarded for the subsequent sub-questions. Subvraag na subvraag: Wanneer ʼn sekere veranderlike in een subvraag (bv. 3.1) bereken word en dan in ʼn ander vervang moet word (3.2 of 3.3), bv. indien die antwoord vir 3.1 verkeerd is en word korrek in 3.2 of 3.3 vervang, word volpunte vir die daaropvolgende subvraag toegeken. 4.2 A multistep question the a sub-question: If the candidate has to calculate, for example, current in die first step and gets it wrong due to a substitution error, the mark for the substitution and the final answer will be forfeited. ʼn Vraag met veelvuldige stappe in ʼn subvraag: Indien ʼn kandidaat bv. die stroom verkeerd bereken in ʼn eerste stap as gevolg van ʼn substitusiefout, verloor die kandidaat die punt vir die substitusie sowel as die finale antwoord. 5. NEGATIVE MARKING/NEGATIEWE NASIEN Normally an incorrect answer cannot be correctly motivated if based on a conceptual mistake. If the candidate is therefore required to motivate in QUESTION 3.2 the answer given in QUESTION 3.1, and QUESTION 3.1 is incorrect, no marks can be awarded for QUESTION 3.2. However, if the answer for e.g. QUESTION 3.1 is based on a calculation, the motivation for the incorrect answer could be considered. ʼn Verkeerde antwoord, indien dit op ʼn konsepsuele fout gebaseer is, kan normaalweg nie korrek gemotiveer word nie. Indien ʼn kandidaat gevra word om in VRAAG 3.2 die antwoord op VRAAG 3.1 te motiveer en VRAAG 3.1 is verkeerd, kan geen punte vir VRAAG 3.2 toegeken word nie. Indien die antwoord op bv. VRAAG 3.1 egter op ʼn berekening gebaseer is, kan die motivering vir die verkeerde antwoord in VRAAG 3.2 oorweeg word. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 QUESTION/VRAAG 1: MULTIPLE-CHOICE QUESTIONS/ MEERVOUDIGEKEUSE-VRAE 1.1 B  (2) 1.2 B  (2) 1.3 C  (2) 1.4 C  (2) 1.5 D  (2) 1.6 A  (2) 1.7 C  (2) 1.8 C  (2) 1.9 B  (2) 1.10 D  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 2 2.1 (If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase) When a resultant/net force acts on an object, it accelerates in the direction of the force. The acceleration is directly proportional to the force and inversely proportional to the mass of the object.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Wanneer ʼn resulterende/netto krag op ʼn voorwerp inwerk, versnel dit in die rigting van die krag. Die versnelling is direk eweredig aan die krag en omgekeerd eweredig aan die massa van die voorwerp. (2) 2.2 OPTION 1/OPSIE 1 OPTION 1/OPSIE 2 N N F Fy f cc  f T T Fx  W W Alternative labels: Alternatiewe byskrifte W / Wg / Fg W / Wg / Fg N / FN / Fnormal N / FN / FNormaal f / Ff / Ffriction f / Fw / Fwrywing T / Fstring / Fs T / Ftou / FT F / Fapp F / Ftoegepas Marking criteria Nasienkriteria • Mark awarded for arrow and • Punt word vir byskrif en pyltjie label. toegeken. • Do not penalise for length of • Moenie vir die lengte van die pyltjies arrows since drawing not drawn penaliseer nie aangesien skets nie to scale. volgens skaal geteken is nie. • Any additional force(s) ¾ • Enige addisionele krag(te) ¾ • If force(s) do not make. contact • Indien krag(te) nie kontak met die with the body – max. ¾. voorwerp maak nie – maks. ¾. (5) 2.3.1 fk = µkN Any one/Enige een fk = µ(mg – Fsinθ)  fk = [0,16 (8 x 9,8 – 55sin15°) ]  fk = 10,27 N  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 2.3.2 Positive marking from QUESTION 2.3.1 / Positiewe nasien vanaf VRAAG 2.3.1 3-kg block / blok Fnet = ma Any one  T – f – F// = ma Enige een T – f – mg sin𝜃 = ma Fcosθ – T – f = ma T – 5 – (3 x 9,8 x sin 30°)  = 3a T – 19,7 = 3a T = 3a + 19,7… (1) Any one/  Enige een 8-kg block / blok F cos θ – T – f = ma [55 cos15o – T – 10,27] = 8a 42,8559 – T = 8a 42,86 – T = 8a … (2) (1) = (2) 42,86 – (3a + 19,7) = 8a a = 2,11 m.s-2 …(3) (3) in (1): T = 19,7 + 3 x 2,11  T = 26,03 N  (6) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 3 3.1 (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) Motion of an object upon which the only force acting is the force of gravity.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Beweging van ʼn voorwerp waarop die enigste krag wat daarop inwerk, die gravitasiekrag is. (2) 3.2.1 UPWARD POSITIVE/ UPWARD NEGATIVE/ OPWAARTS POSITIEF OPWAARTS NEGATIEF vf2 = vi2 + 2aΔy  vf2 = vi2 + 2aΔy  vf2 = 02 + 2(-9,8)(-8)  vf2 = 02 + 2(9,8)(8)  vf = 12,52 m.s-1  vf = 12,52 m.s-1  (3) 3.2.2 UPWARD POSITIVE/OPWAARTS POSITIEF vf = vi + aΔt -12,52 = 0 + (-9,8)(Δt)  Δt = 1,28 s Δy = viΔt + ½ aΔt2  -8= vi (1,28-0,6) + ½(-9,8)(1,28-0,6)  -8 = vi (0,68) + ½(-9,8)(0,68) ∴ vi = 8,43 m.s-1  UPWARD NEGATIVE/OPWAARTS NEGATIEF vf = vi + aΔt 12,52 = 0 + (9,8)(Δt)  Δt = 1,28 s Δy = viΔt + ½aΔt2  8 = vi (1,28-0,6) + ½(9,8)(1,28-0,6)2  8 = vi (0,68) + ½(9,8)(0,68)2 ∴ vi = 8,43 m.s-1  (5) 3.3 OPTION 1/OPSIE 1 UPWARD NEGATIVE/ UPWARD POSITIVE/ OPWAARTS NEGATIEF OPWAARTS POSITIEF vf2 = vi2 + 2aΔy  vf2 = vi2 + 2aΔy  02 = vi2 + 2(-9,8)(6,5)  02 = vi2 + 2(9,8)(-6,5)  vf = 11,29 m.s-1 upwards/opwaarts  vf = 11,29 m.s-1 upwards/opwaarts  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 9 OPTION 2/OPSIE 2 UPWARD POSITIVE/OPWAARTS POSITIEF Emech(f) = Emech(i) (Any one/Enige een) (mghf + ½mvf2) = (mghi + ½mvi2)  m(-9,8)(6,5) + ½m(0 ) = m(-9,8)(0) + ½m vi  2 2 vi = 11,29 m.s-1  UPWARD NEGATIVE/OPWAARTS NEGATIEF Emech(f) = Emech(i) (Any one/Enige een) (mghf + ½mvf2) = (mghi + ½mvi2)  m(9,8)(-6,5) + ½m(0 ) = m(9,8)(0) + ½m vi  2 2 vi = 11,29 m.s-1  OPTION 3/OPSIE 3 UPWARD POSITIVE/OPWAARTS POSITIEF WNC = ΔEK + ΔEP Any one/Enige een) 2 2 0 = (½mvf - ½mvi ) + (mghf + mghi)  0 = (½m + ½m(02) = m(-9,8)(6,5) + m(-9,8) 0  vi = 11,29 m.s-1  UPWARD NEGATIVE/OPWAARTS NEGATIEF WNC = ΔEK + ΔEP Any one/Enige een) 2 2 0 = (½mvf - ½mvi ) + (mghf + mghi)  0 = (½m 02 + ½m(vi2) = m(9,8)(-6,5) + m(9,8) 0  vi = 11,29 m.s-1  OPTION 4/OPSIE 4 UPWARD POSITIVE/OPWAARTS POSITIEF WNETT = ΔEK Any one/Enige een) FG.Δx.cos Θ = (½mvf2 – ½mvi2) mg.Δx.cos Θ = (½mvf2 – ½mvi2)  m(-9,8)(6,5) cos 180 = ½m(0 – vi )  ° 2 2 vi = 11,29 m.s-1  UPWARD NEGATIVE/OPWAARTS NEGATIEF WNETT = ΔEK Any one/Enige een) FG.Δx.cos θ = (½mvf – ½mvi ) 2 2 mg.Δx.cos θ = (½mvf2 – ½mvi2)  m(9,8)(-6,5) cos 180° = ½m(02 – vi2)  vi = 11,29 m.s-1  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 3.4 MARKING CRITERIA/NASIENKRITERIA  Correct shape (Straight line) Korrekte vorm (Reguitlyn)  Similar gradients Dieselfde gradiënte  Final velocity indicated and Eindsnelheid aangedui en bounce off velocity indicated terugbons-snelheid aangedui UPWARDS POSITIVE/OPWAARTS POSITIEF Velocity/Snelheid (m.s-1) 10,84 Time/Tyd(s) -12,52 DOWNWARDS POSITIVE/AFWAARTS POSITIEF 12,52 Velocity/Snelheid (m.s-1) Time/Tyd(s) -10,84 (3) [17] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 11 QUESTION/VRAAG 4 4.1 Zero/nul or/ of 0 m.s-1  (1) 4.2 ∑pi = ∑pf Any one/Enige een  mAvi + mBvi = (mA + mB)vf 52 vig + 5 x 0 = (52 + 5) x 2,4  vi = 2,63 m.s-1  (4) 4.3 Force of hands-on brick upwards,  force of brick on hands downwards.  Force of girl on earth/weight of girl downwards,  force of Earth on girl upwards.  Krag van hand op baksteen opwaarts, krag van baksteen op hande afwaarts. Krag van meisie op aarde/gewig van meisie afwaarts, krag van Aarde op die meisie opwaarts. (2) 4.4 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 𝑣𝑓 +𝑣𝑖 2 = v 2 + 2aΔy Δy = 2 Δt v f i 0+(2,4) 02 = 2,42 + 2 x a x 2  2 = 2 x Δt a = -1,44 m.s-2 Δt = 1,67 s Fnet = ma  Fnet∆t = ∆p Any one/Enige een  Fnet = (52 + 5)  (-1,44)  Fnet∆t = m(vf – vi) Fnet = - 82,08 Fnet x 1,67 = (52 + 5) (0 – 2,4)  Fnet = 82,08 N  Fnet = - 81,92 Fnet = 81,92 N  (5) [12] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com 12 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 5 5.1 (If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase) The net work done on an object is equal to the change in the object’s kinetic energy.  The work done on an object by a net force is equal to the change in kinetic energy of the object.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Die netto arbeid verrig op ʼn voorwerp is gelyk aan die verandering in die kinetiese energie van die voorwerp. Die arbeid verrig op ʼn voorwerp deur ʼn netto krag is gelyk aan die verandering in kinetiese energie van die voorwerp. (2) 5.2 T/Fapp / toegepas /Ftension/spanning  f/fair /lug W/Wg/Fg  (3) 5.3 Tension force (of the rope) / Spanningskrag (van die tou) Any one/Enige een  Air resistance / Lugweerstand (1) 5.4 OPTION 1/OPSIE 1 WFg = Fg.∆x cos θ  WFg = (75 x 9,8) x 12 cos 180°  WFg = - 8 820 J  OPTION 1/OPSIE 2 WFg = - ∆Ep Any one/Enige een  WFg = -[mg(h2 – h1)] WFg = -mg∆h WFg = -[75 x 9,8 (12 – 0)]  WFg = - 8 820 J  (3) 5.5 Positive marking from QUESTION 5.2/Positiewe nasien vanaf VRAAG 5.2 OPTION 1/OPSIE 1 Wnet = ∆Ek Wf + WF + WFg = ∆Ek Any one/Enige een  f x ∆x cos θ + F∆xcos θ + Fg∆xcosθ = ∆Ek 1 1 540 x 12cos180o + 2 400 x 12cos0o + (-8 820)  = 2 x 75 x vf2 – 0  vf = 6,32 m.s-1  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 13 OPTION 2/OPSIE 2 Wnc = ∆Ep + ∆Ek Wf + WF = ∆Ep + ∆Ek Any one/Enige een  f x ∆x cos θ + F∆xcos = mg(h2 – h1) + ∆Ek 1 62,5 x 24 cos180o 2 400 x 12 cos0o = 75 x 9,8(12 – 0) + 2 x 75 x vf – 0  m = 6,32 m.s-1  (5) [14] QUESTION/VRAAG 6 6.1 (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) The (apparent) change in frequency observed by a listener because the listener and source of sound have different velocities relative to the medium of sound propagation  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Die (skynbare) verandering in frekwensie wat deur ʼn luisteraar waargeneem word want die luisteraar en die klankbron verskillende snelhede het relatief tot die medium wat die klank veroorsaak. OR/OF The (apparent) change in frequency observed by a listener due to relative motion between the sound source and the listener.  Die (skynbare) verandering in die frekwensie wat ʼn luisteraar waarneem as gevolg van relatiewe beweging tussen die klankbron en die luisteraar. (2) 6.2 When the source moves towards a stationary observer, the wave in front of the source is compressed  resulting in a shorter wavelength and a higher frequency  (speed of sound constant). Wanneer die bron nader aan ʼn stilstaande waarnemer beweeg word die golf voor die bron saamgepers wat veroorsaak dat die golflengte korter is en die frekwensie hoër is terwyl die (spoed van klank konstant bly). (2) 6.3 v ± vL fL = fs  v ± vs 1,02 fs  = 343  x fs  343 – vs vs = 6,73 m.s-1  (Accept any set of values for frequency that indicates that fL is 2% higher than fs ) (Aanvaar enige stel waardes vir frekwensie wat aandui dat fL 2% hoër is as fs) (5) 6.4 v = λ f  343 = λ x 720  ∴ λ = 0,48 m (0,476 m)  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com 14 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 6.5 Used to measure the direction and speed of blood flow in arteries and veins. Used to measure the heartbeat of a foetus in the womb. (Any one)  Gebruik om die rigting en spoed van bloedvloei in die are te meet. Word gebruik om die hartklop van ʼn fetus in die baarmoeder te meet. (Enige een) (1) [13] QUESTION/VRAAG 7 7.1 (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) The electrostatic force per unit positive charge placed at the point.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Die elektrostatiese krag per eenheid positiewe lading wat by die punt geplaas word. (2) 7.2 Marking criteria /Nasienkriteria  Correct shape Korrekte vorm  Direction of field lines Rigting van veldlyne  Field lines touch surface of point Veldlyne raak oppervlakte van charge and do not cross puntlading en kruis nie (3) 7.3 kQ E=  r2 E1 = (9 x 109)(5 x 10-6)  (0,1)2 E1 = 4,5 x 106 N.C-1 left E2 = (9 x 109) x Q  left (0,4)2 Enet = E1 + E2 4,70 x 106 = 4,5 x 106 + (9 x 109) x Q  (0,4)2 2 x 105 = (9 x 109) x Q  (0,4)2 QT = 3,56 x 10-6 C  (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 15 7.4 OPTION 1/OPSIE 1 E=F  q 4,70 x 106 = F -2 x 10-6  F = - 9,4 F = 9,4 N to the right  OPTION 2/OPSIE 2 kQ1Q2 FE =  r2 F1 = (9 x 109)(5 x 10-6)(2 x 10-6)  right (0,1)2 F1 = 9 N F2 = (9 x 109)(3,56 x 10-6)(2 x 10-6)  right (0,4)2 F2 = 0,4 Fnet = F1 + F2 Fnet = 9 + 0,4  Fnet = 9,4 N to the right  (4) [15] QUESTION/VRAAG 8 8.1 (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) The total energy per coulomb of charge that a battery can supply.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase) Die totale energie per coulomb lading wat ʼn battery kan lewer. (2) 8.2.1 1,4 V  (1) 8.2.2 ∆V 1,4 – 0 Gradient/Gradiёnt = ∆I =  = -0,56 0 – 2,5 Gradient/Gradiёnt = - r = -0,56  r = 0,56 Ω  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Downloaded from hlayiso.com 16 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 8.3.1 Vint = ε – V Vint = 15 – 13,5  Vint = 1,5 V 𝑉 r= 𝐼  1,5 0,5 = 𝐼  I=3A Vs = IRs Vs = 3 x 3 = 9 V Vp = 13,5 – 9 = 4,5 V 𝑉 R= 𝐼 4,5 4= 𝐼  I = 1,125 A  (6) 8.3.2 OPTION 1/OPSIE 1 Positive marking from QUESTION 8.3.1/Positiewe nasien vanaf VRAAG 8.3.1 I = 3 – 1,125  = 1,875 A 𝑉 R= 𝐼 R = 4,5  1,875 R = 2,4 Ω  OPTION 2 / OPSIE 2 Positive marking from QUESTION 8.3.1/Positiewe nasien vanaf VRAAG 8.3.1 Vext / eks = I Rext / eks 13,5 = 3 x Rext/ eks ∴ Rext/eks = 4,5 Ω  Rext/eks = Rp + 3 4,5 = Rp + 3 3 ∴ Rp = 1,5 Ω = 2 Ω  1 =1+1 Rp R 4 2 =1 + 1 3 R 4 ∴ R = 2,4 Ω  (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 17 QUESTION/VRAAG 9 9.1 AC generator.  It has slip rings.  WS generator. Dit het sleepringe. (2) 9.2 Y to/na X  (2) 9.3 9.3.1 The rms potential difference is the AC potential difference which dissipates/produces the same amount of energy as an equivalent DC potential difference.  (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) Die wgk potensiaalverskil is die WS-potensiaalverskil wat dieselfde hoeveelheid energie produseer/opwek as ʼn ekwivalente GS- potensiaalverskil. (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/frase). (2) 2 9.3.2 𝑉𝑟𝑚𝑠/𝑤𝑔𝑘 Paverage/gem =  2 R 220 1 200 =  R R = 40,33 Ω  (3) 9.3.3 Paverage/gem = Vrms/ wgk Irms/wgk  1 200 = Irms/ wgk x 220  Irms/wgk = 5,45 A 𝐼𝑚𝑎𝑥/𝑚𝑎𝑘𝑠 Irms/wgk =  √2 𝐼𝑚𝑎𝑥 /𝑚𝑎𝑘𝑠 5,45 =  √2 Imax/maks = 7,71 A  (5) [14] QUESTION/VRAAG 10 10.1 (If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase) The photo-electric effect is the process where electrons are released from a (metal) surface when light of appropriate frequency is shone on the surface.  (Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 per woord/fase) Die foto-elektriese effek is die proses waardeur elektrone uit ʼn (metaal) oppervlak vrygestel word wanneer lig van geskikte frekwensie invallend op die oppervlak is. (2) 10.2 The minimum energy of light needed to emit (photo) electrons from a metal surface.  Die minimum energie van lig wat nodig is om (foto) elektrone uit ʼn metaal oppervlakte vry te stel. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 Downloaded from hlayiso.com 18 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 10.3 OPTION 1/OPSIE 1 ℎ𝑐 W0 =  𝜆0 W0 = (6,63 x 10-34)(3 x 108)  (555 x 10-9) W0 = 3,58 X 10-19 J  OPTION 2/OPSIE 2 E = W0 + Ek(max)/(maks) ℎ𝑐 Any one/Enige een  = W 0 + Ek(max)/(maks) 𝜆 (6,63 x 10-34)(3 x 108) = W0 + 0  (555 x 10-9) W0 = 3,58 x 10-19 J  (3) 10.4 Increases.  With light of higher intensity more photons strike the metal surface per second. Thus more (photo) electrons are emitted per second, resulting in a bigger current  Neem toe. Indien die lig ʼn hoër intensiteit het, sal meer fotone die metaal oppervlate per sekondes tref. Dus word meer (foto) elektrone per sekonde vrygestel wat ʼn groter stroom gee. (2) 10.5 E = W0 + Ek(max)/ (maks) Any one/Enige een  hf = W0 + Ek(max)/ (maks) 1 hf = W0 + + 2 mv(max/maks)2 1 6,63 x 10-34 f  = 3,58 x 10-19 + 2 x 9,11 x 10-31 x (5 x 106)2  f = 1,72 x 1016 Hz  (4) [13] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - [PHYS SCIENCES P1 GR12 QP SEPT2022 English](https://www.hlayiso.com/library/phys-sciences-p1-gr12-qp-sept2022-english/ef216851-4105-40f6-9cb0-f3146d776699) — Physical Sciences · QP · 2022 · Eng - [PHYS SCIENCES P1 GR12 MEMO SEPT2021 Xho English B Copy](https://www.hlayiso.com/library/phys-sciences-p1-gr12-memo-sept2021-xho-english-b-copy/813b1849-8c40-4d71-92b0-1f6a8e44c4f9) — Physical Sciences · Memo · 2021 · Eng - [Physical Sciences P1 Memo](https://www.hlayiso.com/library/physical-sciences-p1-memo/2d2b7939-aa98-49f1-afa7-ca27e7f59489) — Physical Sciences · Memo · 2017 - [PHYS SC P1 MEMO ENGAFR](https://www.hlayiso.com/library/phys-sc-p1-memo-engafr/da9b9ae0-718d-442a-95bc-aa0bfbf308f3) — Physical Sciences · Memo · 2014 - [PHYSICAL SCIENCES P1 GR12 QP JUNE2022 Afrikaans](https://www.hlayiso.com/library/physical-sciences-p1-gr12-qp-june2022-afrikaans/7da2a467-33ba-4d42-9de8-a501165ff1e0) — Physical Sciences · QP · 2022 · Afr - [PHYS SCIENCES P1 QP GR12 SEPT 2023 Xhosa](https://www.hlayiso.com/library/phys-sciences-p1-qp-gr12-sept-2023-xhosa/2bbd2fc3-2b94-4d0c-9012-591942a529e4) — Physical Sciences · QP · 2023 ## More from Grade 12 Physical Sciences - [PHYSICAL SCIENCE P1 QP JCT 2025 AFR D watermark](https://www.hlayiso.com/library/physical-science-p1-qp-jct-2025-afr-d-watermark/b9429ac5-acbb-4fae-989d-af9e1478a96b) — QP · 2025 · Afr - [PHYSICAL SC P2 QP GR12 SEPTEMBER 2025 AFR1 watermark](https://www.hlayiso.com/library/physical-sc-p2-qp-gr12-september-2025-afr1-watermark/37cff2db-7c1a-4ec8-8ac5-07ec5bcf87a9) — QP · 2025 - [Physics Grade 12 NSC P2 QP September 2025 Gauteng](https://www.hlayiso.com/library/physics-grade-12-nsc-p2-qp-september-2025-gauteng/4d3cbea6-10ec-47ff-98ee-50646165ae9f) — QP · 2025 - [Physics Grade 12 NSC P1 QP September 2025 KZN](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-kzn/6d225dc8-24c6-4c28-a181-df906d5a2c0e) — QP · 2025 - [Physical Sciences Physics Grade 12 PS01 QP March 2025 Limpopo](https://www.hlayiso.com/library/physical-sciences-physics-grade-12-ps01-qp-march-2025-limpopo/482ee9af-e88a-4818-9120-11ab9e045a1c) — QP · 2025 - [Physics Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-limpopo/b65e9832-a6be-4312-8f5a-57425d647121) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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