# Physical Sciences Grade 12 P2 Eastern Cape Mock 2022 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape Mock Exam 2022 (Afrikaans), 19 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/phys-sciences-p2-gr12-memo-sept2022-afrikaans-english/47b9c80d-a42d-4f9d-8227-5d43622cb56b
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Language: Afrikaans
- Document type: Memorandum
- Year: 2022
- Exam period: Eastern Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 19

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## About this document

Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2022 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF.

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### Page 1

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                             NATIONAL
                        SENIOR CERTIFICATE/
                         NASIONALE SENIOR
                           SERTIFIKAAT

                            GRADE/GRAAD 12

                         SEPTEMBER 2022

                 PHYSICAL SCIENCES P2
                   MARKING GUIDELINE/
                FISIESE WETENSKAPPE V2
                      NASIENRIGLYN

MARKS/ PUNTE:   150

                      This marking guideline consists of 19 pages./
                       Hierdie nasienriglyn bestaan uit 19 bladsye.

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2                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2         (EC/SEPTEMBER 2022)

 QUESTION/VRAAG 1

 1.1    B ✓✓                                                                             (2)

 1.2    A ✓✓                                                                             (2)

 1.3    B ✓✓                                                                             (2)

 1.4    C ✓✓                                                                             (2)

 1.5    C ✓✓                                                                             (2)

 1.6    A ✓✓                                                                             (2)

 1.7    B ✓✓                                                                             (2)

 1.8    D ✓✓                                                                             (2)

 1.9    B ✓✓                                                                             (2)

 1.10 A ✓✓                                                                              (2)
                                                                                       [20]

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(EC/SEPTEMBER 2022)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                                 3

 QUESTION/VRAAG 2

 2.1      It is a series of organic compounds that can be described by the same
          general formula. ✓✓ (2 or 0)

          ŉ Reeks organiese verbindings wat deur dieselfde algemene formule
          beskryf kan word. (2 of 0)
                                       OR/OF

          A series/group of organic compounds in which one member differs from the
          next with -CH2- group. ✓✓ (2 or 0)

          ŉ Reeks organiese verbindings waarin die een lid van die volgende verskil
          met ŉ CH2-groep.                                                                       (2)

 2.2.1 D ✓                                                                                       (1)

 2.2.2 CnH2n-2 ✓                                                                                 (1)

 2.2.3                                  O         Marking criteria/ Nasienkriteria
                              H   H
                                            ✓        • Only functional group correct /
                          H   C   C     C   H   ✓       Slegs funksionele groep korrek:
                              H                         Max/ Maks ½
                              H   C     H
                                                     •   Whole structure correct/
                                  H                      Hele struktuur korrek: 2/2
                                                                                                 (2)

 2.3      3-ethyl-2-methylhexanoic acid / 3-etiel-2-metielheksanoësuur

         Marking criteria
            • Correct stem i.e hexanoic acid ✓
            • All substituents (ethyl and methyl) correctly identified ✓
            • IUPAC name completely correct including numbering, sequence and
               hyphens ✓
         Nasienkriteria
            • Korrekte stam d.i heksanoësuur
            • Alle substituente (etiel en metiel) korrek geїdentifiseer
            • IUPAC-naam heeltemal korrek insluitende nommering, volgorde en
               koppeltekens
                                                                                                 (3)

 2.4.1                                          Marking criteria/Nasienkriteria
                                  H                • Longest chain contains 3 carbons /
                              H   C     H             Langste koolstofketting bevat 3
                                                      koolstowwe ✓
                              H         H
                                                   • Two methyl substituents on C2 /
                          H   C   C     C   H         Twee metielsubstituente op C2 ✓
                              H                    • Whole structure is correct / Hele
                                        H
                                                      struktuur korrek ✓
                              H   C     H

                                  H                                                              (3)

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4                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2            (EC/SEPTEMBER 2022)

 2.4.2 C5H12 + 8 O2 ✓→ 6 H2O + 5 CO2 ✓ (bal ✓) Marking criteria/ Nasienkriteria
                                                      •   Reactants / Reaktanse
                                                      •   Products / Produkte
                                                      •   Balancing / Balansering           (3)
                                                                                           [15]

 QUESTION/VRAAG 3

 3.1.1 Marking criteria/Nasienkriteria
       If any of the underlined key words/phrases in the correct context are
       omitted: - 1 mark per word/phrase.
       Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
       word: - 1 punt per woord/frase.

        The temperature at which the vapour pressure of a liquid equals the
        atmospheric pressure. ✓✓

        Die temperatuur waarby die dampdruk van die vloeistof gelyk is aan die
        atmosferiese druk.                                                                  (2)

 3.1.2 As the number of C atoms increases:

        • The surface area/chain length/molecular mass of the alcohols
          increases ✓
        • The strength of London forces/induced dipole forces/dispersion forces
          increase. ✓

        Soos die aantal C-atome toeneem:

        • Die oppervlak-area/kettinglengte/molekulêre massa van die alkohole
          verhoog.
        • Die sterkte van die Londonkragte/geїnduseerde dipoolkragte/
          verspreidingskragte verhoog

                                             OR/OF

        As the number of C atoms decreases:

        •    The surface area/chain length/molecular mass of the alcohols
             decreases ✓
        •    The strength of London forces/induced dipole forces/dispersion forces
             decrease. ✓

        Soos die aantal C-atome afneem:

        •    Die oppervlak-area/kettinglengte/molekulêre massa van die alkohole
             verlaag.
        •    Die sterkte van die Londonkragte/geїnduseerde dipoolkragte/
             verspreidingskragte verswak                                                    (2)

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(EC/SEPTEMBER 2022)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                              5

 3.1.3 Marking criteria
       • Identify the intermolecular forces in both compounds. ✓✓
       • Compare the strength of the intermolecular forces. ✓

         Nasienkriteria
         • Die intermolekulêre kragte korrek geїdentifiseer in beide verbindings
         • Vergelyk die sterkte van die intermolekulêre kragte

         •     Alcohols have both (London forces) and hydrogen bonds ✓
         •     Ketones have both (London forces) and dipole-dipole forces ✓
         •     Hydrogen bonds in the alcohols are stronger than the dipole-dipole
               forces in ketones ✓

         •     Alkohole het beide (Londonkragte) en waterstofbindings
         •     Ketone het beide (Londonkragte) en dipool-dipool kragte
         •     Waterstofbindings in die alkohole is sterker as die dipool-dipoolkragte
               in ketone

                                            OR/OF

         •     Alcohols have both (London forces) and hydrogen bonds ✓
         •     Ketones have both (London forces) and dipole-dipole forces ✓
         •     the dipole-dipole forces in Ketones are weaker than the hydrogen
               bonds in the alcohols ✓

         •     Alkohole het beide (Londonkragte) en waterstofbindings
         •     Ketone het beide (Londonkragte) en dipool-dippol kragte
         •     Die dipool-dipoolkragte in ketone is swakker as die waterstofbindings
               in die alkohole                                                                (3)

 3.1.4 To have one independent variable✓ OR To have a fair test
       Om slegs een onafhanklike veranderlike te het OF Om ŉ regverdige toets
       te hê                                                                                  (1)

 3.1.5 Ketone ✓

         Lower boiling point / Laer kookpunt ✓                                                (2)

 3.2.1 Propanoic acid / Propanoësuur ✓                                                        (1)

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6                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2022)

 3.2.2 Marking criteria
       • Identify the intermolecular forces correctly in both compounds. ✓
       • Compare the strength of the intermolecular forces. ✓
       • Compare the energy required to overcome the intermolecular forces. ✓

        Nasienkriteria
        • Die intermolekulêre kragte is korrek in beide verbindings geїdentifiseer
        • Vergelyk die sterkte van die intermolekulêre kragte.
        • Vergelyk die energie wat benodig word om die intermolekulêre kragte te
           oorkom.

        • Both have hydrogen bonds
        • Propan-1-ol has ONE site for hydrogen bonds
        • Propanoic acid has TWO sites for hydrogen bonds ✓
        • The intermolecular forces of propanoic acid are stronger than that of
          propan-1-ol ✓
        • More energy is needed to overcome the intermolecular forces of
          propanoic acid. ✓

        • Beide het waterstofbindings
        • Propan-1-ol het EEN plek vir waterstofbindings
        • Propanoësuur het TWEE plekke vir waterstofbindings
        • Die intermolekulêrekragte in propanoësuur is sterker as dié in
          propan-1-ol
        • Meer energie word benodig om die intermolekulêre kragte te oorkom in
          propanoësuur

                                            OR/OF

        • Both have hydrogen bonds.
        • Propan-1-ol has ONE site for hydrogen bonds
                                                               ✓
        • Propanoic acid has two sites for hydrogen bonds
        • The intermolecular forces of propan-1-ol are weaker than that of
          propanoic acid ✓
        • Less energy is needed to overcome the intermolecular forces of
          propan-1-ol. ✓

        • Beide het waterstofbindings
        • Propan-1-ol het EEN plek vir waterstofbindings
        • Propanoësuur het TWEE plekke vir waterstofbindings
        • Die intermolekulêrekragte in propan-1-ol is swakker as dié in
          propanoësuur.
        • Minder energie word benodig om die intermolekulêre kragte te oorkom
          in propan-1-ol.                                                                  (3)
                                                                                          [14]

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(EC/SEPTEMBER 2022)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                                    7

 QUESTION/VRAAG 4

 4.1.1 Esterification / condensation / Esterifikasie / konsensasie✓                                        (1)

 4.1.2 (Mild) heat / (Matige) hitte ✓                                                                      (1)

 4.1.3                      H     H     H               Marking criteria/ Nasienkriteria
                                                           • Only functional group correct
                      H     C     C     C   O      H✓ ✓       Slegs funksionele groep
                                                              korrek: Max/Maks ½
                            H     H     H
                                                              •     Whole structure correct/
                                                                    Hele struktuur korrek: 2/2
                                                                                                           (2)

 4.1.4 Propyl ✓ethanoate ✓ / Propiel etanoaat                                                              (2)

 4.1.5 Pentanoic acid / Propanoësuur ✓✓                                                                    (2)

 4.1.6 Substitution reaction / Substitusie-reaksie ✓                                                       (1)

 4.1.7 H2O ✓                                                                                               (1)

 4.1.8 CH3CH2CH2Cℓ ✓✓                              Marking criteria/ Nasienkriteria
                                                    • Only functional group correct / Slegs
                                                      funksionele groep korrek: Max/Maks ½

                                                     • Whole structure correct / Hele struktuur
                                                       korrek: 2/2                                         (2)

 4.2.1 (Concentrated / Gekonsentreerde) H2SO4 ✓                                                            (2)

 4.2.2 H2O in excess ✓ / catalyst/ (Add small amount of HCℓ/H3PO4)                                         (1)

 4.2.3        H       H H                            H   H H
          H   C C C             H✓ +   H2O ✓ → H     C C     C       H✓
                  ✓
                                                                     ✓
              H H                                    H O✓ H

                                                         H

         Marking criteria/ Nasienkriteria
         (Organic molecules / Organiese molekules)
          • Only functional group correct / Slegs funksionele groep korrek: Max/Maks ½

          •   Whole structure correct/ Hele struktuur korrek: 2/2
                                                                                                           (5)
                                                                                                          [20]

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8                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2022)

 QUESTION/VRAAG 5

 5.1      Marking criteria/ Nasienkriteria
          If any of the underlined key words/phrases in the correct context are
          omitted: - 1 mark per word/phrase.
          Indien enige van die sleutelwoorde/frases in die korrekte konteks
          weggelaat word: - 1 punt per woord/frase

          ANY ONE
          • Change in concentration ✓of reactant / product per (unit) time.✓

          •   Change in amount/number of moles/volume/mass of products or
              reactants per (unit) time.

          •   Amount/number of moles/volume/mass of products formed/reactants
              used reactants per (unit) time.

          ENIGE EEN
          • Verandering in konsentrasie van reaktanse/produkte per (eenheid)
             tyd

          •   Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of
              produkte per (eenheid) tyd.

          •   Hoeveelheid/getal mol/volume/massa van produkte gevorm/
              reaktanse gebruik per (eenheid) tyd

                                           OR/OF

          The rate of change in concentration / amount of moles / number of moles /
          volume / mass. (2 or 0).

          Die tempo van verandering in konsentrasie / hoeveelheid mol / getal
          mol/volume/massa (2 of 0)                                                        (2)

 5.2      Concentration / Konsentrasie (of/van HCℓ) ✓                                      (1)

 5.3      Equal to / Gelyk aan ✓

          The same amount of (the limiting reagent), Na2S2O3, is used. ✓
          Dieselfde hoeveelheid (van beperkde reagens) Na2S2O3 was gebruik.                (2)

 5.4.1    Experiment 3 / Eksperiment 3 ✓                                                   (1)

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(EC/SEPTEMBER 2022)                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                               9

 5.4.2    For T2
          • Higher temperature increases kinetic energy of particles ✓
          • Greater number of particles have sufficient energy. ✓
          • More effective collision per unit time ✓

          Vir T2
              • Hoër temperatuur verhoog die kinetiese energie van die deeltjies
              • Groter aantal deeltjies het genoeg energie
              • Meer effektiewe botsings per eenheidstyd

                                                                OR/OF

          For T1
          • Lower temperature decreases kinetic energy of particles
          • Fewer particles have sufficient energy.
          • Less effective collision per unit time

          Vir T1

              •            Laer temperatuur verlaag die kinetiese energie van die deeltjies
              •            Minder aantal deeltjies het genoeg energie
              •            Minder effektiewe botsings per eenheidstyd                                        (3)

              Number of particles/
 5.4.3                                                                    Marking criteria/Nasienkriteria
                                                                             •   X < Ea

              Aantal deeltjies
                                                           ✓✓

                                                           X Ea
                                     Kinetic energy / Kinetiese energie                                      (2)

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10                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2             (EC/SEPTEMBER 2022)

 5.5      Marking criteria

          •    Formula n = m/M
          •    Substitution into n = m/M
          •    Using ratio HCℓ: Na2S2O3 2 : 1
          •    Substitution into rate equation
          •    Final answer

          Nasienkriteria

          •    Formule n = m/M
          •    Vervanging in n = m/M
          •    Gebruik van verhouding HCℓ: Na2S2O3 2 : 1
          •    Vervanging in tempo vergelyking
          •    Finale antwoord

               m
          n=     ✓
               M

               0,7118
          n=          ✓
                158

          n (Na2S2O3) = 4,505 x 10-3 mol

          n (HCℓ) = 2 (4,505 x 10-3) ✓

          n (HCℓ) = 9,01 x 10-3 mol

                            Δn                   Accept / Aanvaar
          rate/ tempo = -
                            Δt
                                                                 Δn
                          0 - 9,01 x 10-3        rate/ tempo =
          rate/ tempo = -                 ✓                      Δt
                                 34
                                                             - 9,01 x 10-3
          rate/ tempo = 2,65 x 10-4 (mol·s-1) ✓ rate/tempo =      34
                                                                           ✓

                                                 rate / tempo = - 2,65 x 10-4
                                                 (mol·s-1) ✓                                 (5)

 5.6      REMAINS THE SAME / BLY DIESELFDE ✓                                                 (1)
                                                                                            [17]

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(EC/SEPTEMBER 2022)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                           11

 QUESTION/VRAAG 6

 6.1.1 (A reaction in which) products can be converted back to its reactants ✓✓
       (and vice versa)

         (Is ŉ reaksie waar) produkte terug na reaktanse, en omgekeerd,
         omgeskakel kan word.                                           (2 or/ of 0)            (2)

 6.1.2   Turns more pink / Raak meer pienk ✓                                                    (1)

 6.1.3 Turns more blue / Raak meer blou ✓                                                       (1)

 6.1.4 Exothermic / Eksotermies ✓                                                               (1)

 6.1.5 • Increase in temperature shifted the equilibrium position left ✓/Reverse
         reaction is favoured
       • Increase in temperature favours the endothermic reaction ✓

         • Toename in temperatuur verskuif die ewewigsposisie na links/
           Terugwaartse reaksie word bevoordeel.
         • Toename in temperatuur bevoordeel ŉ endotermiese reaksie.                            (2)

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12                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                  (EC/SEPTEMBER 2022)

 6.2    OPTION 1: MOLE CALCULATIONS
        OPSIE 1: MOL BEREKENINGE

        Marking criteria:
                                         N
        a. Substitution into formula n = N ✓
                                             A
        b.   Using ratio N2O4 : NO2 = 1 : 2 ✓
        c.   n(NO2) equilibrium = n initial + Δn ✓
        d.   n(N2O4) equilibrium = n initial - Δn ✓
        e.   Divide equilibrium amounts of N2O4 and NO2 by 4 dm3 ✓
        f.   Correct KC expression (formulae in square brackets) ✓
        g.   Substitution into equilibrium concentration into KC expression ✓
        h.   Final answer ✓

        Nasienkriteria:
                                     N
        a. Vervanging in formule n = N
                                         A
        b.   Gebruik verhouding N2O4 : NO2 = 1 : 2 ✓
        c.   n(NO2) ewewig = n initial + Δn ✓
        d.   Deel ewewighoeveelhede van N2O4 en NO2 deur 4 dm3
        e.   Korrekte Kc-uitdrukking (formules met vierkanthakies)
        f.   Vervanging in ewewigskonsentrasies in Kc-uitdrukking
        g.   Finale antwoord

              N
        n= N
              A

              3,01 × 1023
        n=                  ✓ (a)
               6,02×1023

        n = 0,5 mol

                                                 N2O4 (g)               2 NO2 (g)
          Initial quantity (mol)
                                                   0,5                        -
          Aanvangshoeveelheid (mol)
          Change (mol)                                                                          ✓ (b)
                                                   0,4                       0,8
          Verandering (mol)                                                                     ratio
          Equilibrium (mol)
                                                   0,1 ✓ (d)                0,8                  ✓ (c)
          Ewewig (mol)
          Concentration (mol·dm-3)                                                              ✓ (e)
                                                  0,025                      0,2
          Konsentrasie (mol·dm-3)

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(EC/SEPTEMBER 2022)          PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                              13

                      [NO2]2             No Kc expression, correct substitution / Geen Kc-
          Kc     =               ✓ (f)   uitdrukking, korrekte, korrekte substitusie.
                      [N2O4]
                                         Max / Maks 7/8
                      (0,2)2             Wrong Kc expression/Verkeerde Kc – uitdrukking.
          Kc     =              ✓ (g)
                      (0,025)            Max. Maks. 5/8

        Kc       =     1,6      ✓ (h)

        OPTION 2: CONCENTRATION CALCULATIONS/
        OPSIE 2: KONSENTRASIEBEREKENINGE

        Marking criteria
                                         N
        a. Substitution into formula n = N ✓
                                                 A
        b.     Using ratio N2O4: NO2 = 1 : 2 ✓
        c.     c(NO2) equilibrium = c initial + Δc ✓
        d.     c(N2O4) equilibrium = c initial – Δc ✓
        e.     Divide n initial and Δn of N2O4 by 4 dm3 ✓
        f.     Correct KC expression (formulae in square brackets) ✓
        g.     Substitution into equilibrium concentration into KC expression ✓
        h.     Final answer ✓

        Nasienkriteria:
                                     N
        a. Vervanging in formule n = N
                                             A
         b. Gebruik verhouding N2O4 : NO2 1 : 2
         c. Ewewig c(NO2) = begin c + Δc
         d. Ewewig c (N2O4) = begin c – Δc                                                       ✓(b)
         e. Deel aanvangs en verandering hoeveelhede van N2O4 en NO2 deur 4
            dm3
         f. Korrekte Kc-uitdrukking (formules met vierkanthakies)                                ✓ (e)
         g. Vervanging in ewewigskonsentrasies in Kc-uitdrukking
         h. Finale antwoord

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14                      PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2               (EC/SEPTEMBER 2022)

               N
        n= N
               A

               3,01 × 1023
        n=                   ✓ (a)
               6,02 × 1023

        n = 0,5 mol

                                                          N2O4 (g)           2 NO2 (g)
         Initial concentration (mol·dm-3)                  0,125                -
         Aanvangs konsentrasie (mol·dm-3)                                ✓ (d)
         Change in concentration (mol·dm-3)
                                                             0,1                0,2
         Verandering in konsentrasie(mol·dm-3)
         Equilibrium concentration (mol·dm-3)
                                                           0,025✓ (c)              0,2
         Ewewig konsentrasie (mol·dm-3)

                       [NO2]2            No Kc expression, correct substitution / Geen Kc-
          Kc       =             ✓ (f)   uitdrukking, korrekte substitusie.
                       [N2O4]
                                         Max / Maks 7/8
                       (0,2)2            Wrong Kc expression / Verkeerde Kc -uitdrukking.
          Kc       =             ✓ (g)
                       (0,025)           Max. Maks. 5/8

          Kc       =    1,6      ✓ (h)                                                                 (8)
                                                                                                      [15]

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(EC/SEPTEMBER 2022)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                           15

 QUESTION/VRAAG 7

 7.1.1 An acid is a proton (H+ ion) donor / ŉ Suur is ‘n proton (H+-ioon) skenker ✓✓            (2)

 7.1.2 HCℓ and/en Cℓ- ✓✓ OR/OF          H3O+ and/en H2O ✓✓                                      (2)

 7.1.3 Solution I. ✓
       • HCℓ is a stronger acid than CH3COOH / HCℓ has a higher Ka ✓ (than
           CH3COOH)
       • HCℓ will produce a higher concentration of H3O+ ✓ (than CH3COOH)
                                         OR
       • CH3COOH is a weaker acid than HCℓ / CH3COOH has a lower Ka (than
           HCℓ)
       • CH3COOH will produce a lower concentration of H3O+ (than HCℓ)

         Oplossing I.
         • HCℓ is ŉ sterker suur as CH3COOH / HCℓ het ŉ hoër Ka-waarde as
            CH3COOH
         • HCℓ sal ŉ hoër konsentrasie van H3O+ produseer as CH3COOH
                                          OF
         • CH3COOH is ŉ swakker suur as HCℓ / CH3COOH het ŉ laer Ka-waarde
            as HCℓ
         • CH3COOH sal ŉ laer konsentrasie H3O+ produseer as HCℓ                                (3)

 7.2.1 n = cV ✓
         = 1 x10 / 1 000 ✓
         = 0,01 mol ✓                                                                           (3)

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16                      PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2          (EC/SEPTEMBER 2022)

 7.2.2 Marking criteria                          Marking criteria

        •    Formula pH = - log [H3O+] ✓          • Formula pOH + pH = 14 ✓
        •    pH value substituted into            • pH value substituted into
             formula ✓                              formula ✓
        •    Substitution in Kw formula✓         • Substitution in pOH formula✓
        •    Substitution into n = cV✓           • Substitution into n = cV✓
        •    Final answer✓                       • Final answer✓
                                                 Nasienkriteria
        Nasienkriteria                           • Formule pOH + pH = 14
        • Formule pH = - log [H3O+]              • pH-waarde vervang in formule
        • pH-waarde vervang in formule           • Vervanging in pOH formule
        • Vervanging in Kw formule               • Vervanging in n = cV
        • Vervanging in n = cV                   • Finale antwoord
        • Finale antwoord

        OPTION 1 / OPSIE 1                       OPTION 2 / OPSIE 2

        pH = - log [H3O+] ✓                      pOH + pH = 14 ✓

        13 ✓ = - log [H3O+]                      pOH + 13 ✓ = 14

        [H3O+] = 1 × 10-13 mol·dm-3              pOH = 1

        Kw = [OH-][H3O+] = 1 × 10-14             pOH = - log [OH-]

        [OH-][H3O+] = 1 × 10-14                  1 = - log [OH-] ✓

        [OH-](1 × 10-13) = 1 × 10-14 ✓           [OH-] = 0,1 mol·dm-3

        [OH-] = 0,1 mol·dm-3                     [NaOH] = 0,1 mol·dm-3

        [NaOH] = 0,1 mol·dm-3

                    n             OR/OF
        c
              =     V                            c1V1 = c2V2
                                   From 7.2.1
                  0,01             Vanaf 7.2.1   (1)(10) = (0,1)V2 ✓
        0,1 =          ✓
                   V
                                                 V2 = 100 cm3

        V     = 0,1 (dm3)✓                       V = 0,1 (dm3) ✓                                 (5)

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(EC/SEPTEMBER 2022)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                                  17

 7.2.3 Marking criteria                          Marking criteria /
                                                               c V       n
       • Formula n = cV✓                         • Formula ca Va = na ✓
       • Substitution of acid values into n = cV                b b       b
                                                                            c V
                               AND               • Substitution LHS ca Va ✓
                                             ✓                               n
                                                                              b b
       Using ratio Acid : Base = 1 : 2           • Substitution RHS na ✓
       • Substitution of V and c into                                         b

       n = cV for V base reacting ✓              •  Subtracting
                                                 Vremaining = Vinitial ‒ Vreacting ✓
       • Subtracting
       Vremaining = Vinitial ‒ Vreacting ✓       • Final answer ✓
       • Final answer ✓
                                                 Nasienkriteria
         Nasienkriteria                                                   c V    n
         • Formule n = cV                                   • Formule ca Va = na
                                                                           b b     b
         • Vervanging van suur waardes in                   •
                                                                           c V
                                                                Vervang LK ca Va
                                                                            b b
             formule n = cV                                                n
                                EN                          •   Vervang RK na
                                                                             b
         Gebruik verhouding Suur : Basis = 1 : 2            • Aftrekking
         • Vervanging van V en c in            n            Voorbly = Vaanvangs – Vreageer
             = cV vir V basis wat reageer                   • Finale antwoord
         • Aftrekking
         Voorbly = Vaanvangs - Vreageer
         • Finale antwoord

         OPTION 1/OPSIE 1                                   OPTION 2/OPSIE 2
         n acid reacting = cV✓                              ca V a  na
                                                                   = ✓
                         = 0,09 x 15/1 000                  cb V b n b
                         = 1,35 x 10-3 mol  ✓
                                        -3
         n base reacting= 2 x 1,35 x 10 mol                 (0,09)(15)   1
                         = 2,7 x 10 -3 mol                             ✓= ✓
                                                              (0,1)Vb    2
         n = cV
                                                            Vb = 27 cm3
         2,7 x 10 -3 = 0,1 Vbase reacting /basis reageer✓
                                                            Vb = 0,027 dm3
         0,027 dm3 = Vbase reacting/ basis reageer

         Vremaining/oorbly = 0,1 – 0,027 ✓
                           = 0,073 dm3 ✓                                                                  (5)
                                                                                                         [20]

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18                       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                         (EC/SEPTEMBER 2022)

 QUESTION/VRAAG 8

 8.1      Loss of electrons / Verlies aan elektrone ✓✓ (2 or/of 0)                                                (2)

 8.2.1 1 mol·dm-3 ✓                                                                                               (1)

 8.2.2 Platinum ✓                                                                                                 (1)

 8.2.3 Cu ✓                                                                                                       (1)

 8.2.4 O2 + 4H+ + 4e- → 2 H2O ✓✓
       Marking criteria / Nasienkriteria
       • O2 + 4H+ + 4e- ⇌ 2 H2O      ½
       • 2 H2O ← O2 + 4H + 4e
                           +    -    2/2
       • 2 H2O ⇌ O2 + 4H + 4e
                            +    -   0/2
       • 2 H2O → O2 + 4H+ + 4e- 0/2

          •    Ignore if the charge omitted on electron / Ignoreer indien lading op
               elektron weggelaat is.                                                                             (2)

 8.2.5 2 Cu + O2 + 4 H+ ✓→ 2 Cu2+ + 2 H2O ✓ (✓ bal)
        Marking criteria/Nasienkriteria
          • Reactants/ Reaktanse
          • Products / Produkte
          • Balancing / Balansering
                                                                                                                  (3)

 8.3.1 Eθcell = Eθcathode/reduction/oxidising agent – Eθanode/oxidation/reducing agent ✓
                                             Notes/Aantekeninge
          Eθcell = (1,23) ✓ – (0,34) ✓
                                                • Any other formula using unconventional
                                                   abbreviation , e.g.
          Eθcell = 0,89 V ✓
                                                   Eocell = EoOA – Eo RA followed by the correct
                                                   substitution : ¾
                                                • Enige ander formule wat onkonvensionele
                                                   afkortings gebruik bv.
                                                • Eosel = EoOM – Eo RM gevolg met korrekte
                                                   vervangings: ¾
                                                                                                                  (4)

 8.3.2 Concentration of the reactants decreases ✓
       Rate of the forward reaction decreases ✓

          Konsentrasie van reaktanse verlaag
          Tempo van voortwaartse reaksie verlaag                                                                  (2)

 8.3.3 Equilibrium / Ewewig ✓                                                                                     (1)
                                                                                                                 [17]

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(EC/SEPTEMBER 2022)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                              19

 QUESTION/VRAAG 9

 9.1.1 Marking criteria/ Nasienriglyne
       If any of the underlined key words/phrases in the correct context are
       omitted: - 1 mark per word/phrase.
       Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
       word: - 1 punt per woord/frase

         (It is a cell in which) electrical energy ✓ is converted into chemical energy ✓

         (Dit is ŉ sel waarin) elektriese energie omgeskakel word na chemiese
         energie.                                                                                   (2)

 9.1.2 2 Cℓ- → Cℓ2(g) + 2e− ✓✓

         Ignore phases / Ignoreer fases                                                             (2)
         Marking criteria / Nasienkriteria
         • 2 Cℓ- ⇌ Cℓ2(g) + 2e− ½
         • Cℓ2(g) + 2e− ← 2 Cℓ- 2/2
         • Cℓ2(g) + 2e− ⇌ 2 Cℓ- 0/2

         Ignore if the charge omitted on electron / Ignoreer indien lading weggelaat
         is op elektron

 9.1.3 H2 / Hydrogen gas / Waterstofgas                                                             (1)

 9.1.4 H2O is a stronger oxidising agent than Na+ ✓
       H2O is reduced to H2 ✓

         H2O is ŉ sterker oksideermiddel as Na+
         H2O word gereduseer na H2                                                                  (2)

 9.2.1 Cathode / Katode ✓                                                                           (1)

 9.2.2 nCu     =½x6✓
                                              Marking criteria
               = 3 mol
                                              • Use of ratio of electrons to Cu
         mCu = nM = 3 x 63,5✓                 • Subst. into n = m/M
                                              • Division by 0,95
              = 190,5 g                       • Final answer
         0,95 ✓m IMPURE sample = 190,5        Nasienkriteria
                                              • Gebruik van verhouding van
         m IMPURE sample = 200,53 g ✓
                                                 elektrone tot Cu
                                              • Vervanging in n = m/M
                                              • Deel deur 0,95
                                              • Finale antwoord
                                                                                                    (4)
                                                                                                   [12]

                                                                     TOTAL/TOTAAL:                 150

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