# Physical Sciences Grade 12 Paper 2 EC June 2019 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the EC June 2019, 16 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/phys-sciences-p2-memo-june-ea/5b65158d-af31-4e13-be19-b74842d7be56
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2019
- Exam period: EC June
- Paper: 2
- Curriculum: CAPS
- Pages: 16

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## About this document

Physical Sciences · Grade 12 · EC June · 2019. Memorandum, 16 pages. Read online or download the PDF.

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## Document text

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                          NATIONAL
                     SENIOR CERTIFICATE
                         NASIONALE
                     SENIOR SERTIFIKAAT

                         GRADE/GRAAD 12

                        JUNE/JUNIE 2019

                 PHYSICAL SCIENCES P2
                   MARKING GUIDELINE/
                FISIESE WETENSKAPPE V2
                      NASIENRIGLYN

MARKS/PUNTE:      150

                   This marking guideline consists of 10 pages.
                   Hierdie nasienriglyn bestaan uit 10 bladsye.

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2                                 PHYSICAL SCIENCES P2                       (EC/JUNE 2019)
 QUESTION 1/VRAAG 1

 1.1    B √√                                                                           (2)
 1.2    B √√                                                                           (2)
 1.3    C √√                                                                           (2)
 1.4    A √√                                                                           (2)
 1.5    D √√                                                                           (2)
 1.6    C √√                                                                           (2)
 1.7    A √√                                                                           (2)
 1.8    D √√                                                                           (2)
 1.9    A √√                                                                           (2)
 1.10   D √√                                                                           (2)
                                                                                      [20]
 QUESTION 2/VRAAG 2

 2.1    CONCENTRATED √
        GEKONSENTREERD                                                                (1)

 2.2    To prevent reagents escaping √ /To smell the ester/Acts as a condenser
        Om te voorkom dat reagense ontsnap / Om die esters te ruik√ / Dit tree as
        ŉ kondensor op                                                                (1)

 2.3    H2O √                                                                         (1)

 2.4    propan-1-ol √√ Accept 1-propanol          propanol (1/2)
        propaan-1-ol Aanvaar 1- propanol       propanol (1/2)                         (2)

 2.5    n= 54,55/12 √ = 4,55 n = 9,1/1 √= 9,1 n =(100-54.55-9.1) √ /16 √ = 2.27
                       =2        =4
        Empirical formula/Empiriese formule C2H4O √
        Molar mass(R)/Molêre massa(R) = 130 + 18 – 60= 88 √
        MMolar Mass (Empirical formula)/Molêre massa (Empiriese formule)= 2 x
        12 + 4 x 1 + 1 x 16 = 44 √
        Molecular formula/Molekulêre formule= C4H8O2 √                                 (8)
                                                                                      [13]

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(EC/JUNIE 2019)                         FISIESE WETENSKAPPE V2                                       3

 QUESTION 3/VRAAG 3

 3.1 3.1.1        (a)    Esters √                                                              (1)

                  (b)
                              H          O    H   H          Marking Criteria
                                                             Whole structure correct
                         H    C     O     C   C    C   H     2/2
                              H               H   H          Volle struktuur 2/2

                                                             Only functional group
                                                             correct ½
                                                             Slegs funksionele groep
                                                             korrek ½
                                                                                               (2)

        3.1.2     Same molecular mass √√ /Same molar mass
                  Dieselfde molekulêre massa / Dieselfde molêre massa                          (2)
        3.1.3     B has two sites for hydrogen bonding √. A has one site for hydrogen
                  bonding √
                  B het twee plekke vir waterstofbinding. √ A het een plek vir
                  waterstofbinding                                                             (2)

 3.2 3.2.1        Yes √
                  Ja
                  Same molecular formula √ but different structural formulae √
                  Dieselfde molekulêre formule maar verskillende struktuurformules             (3)

        3.2.2     Y√
                  D has a larger surface area/chain length than E √
                  D het ŉ groter oppervlakte/ kettinglengte as E
                  London forces/Induced-dipole forces √/Dispersion forces stronger√
                  in D than in E
                  Londonkragte/geїnduseerde-dipool kragte/Dispersie-kragte is
                  sterker in D as in E
                  More energy needed to break/overcome forces in D√
                  Meer energie word benodig om die kragte te breek/oorkom in D
                  OR/OF
                  Y√
                  E has a smaller surface area/chainlength than D √
                  E het ‘n kleiner oppervlakte/ kettinglengte as D
                  London forces/Induced-dipole forces √/Dispersion forces weaker
                  in E than in D
                  Londonkragte/geїnduseerde-dipool kragte/Dispersie-kragte is
                  swakker in E as in D
                  Less energy needed to break forces in E √
                  Minder energie word benodig om intermolekulȇre kragte te
                  breek/oorkom in E
                                                                                               (4)
                                                                                              [14]

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4                                          PHYSICAL SCIENCES P2                                   (EC/JUNE 2019)

 QUESTION 4/VRAAG 4

 4.1    4.1.1    (a)         Addition √ /Halogenation/Bromination √
                             Addisie / Halogenasie √/Brominasie                                             (1)

                 (b)         Elimination √/Dehydrohalogenation √
                             Eliminasie / Dehidrohalogenering                                               (1)

        4.1.2    (a)
                                                       H

                             Cℓ      Cℓ        H       C       H       H√√

                     H       C        C                C               C       H

                              H        H               H               H

                     Marking criteria/Nasienriglyne
                        Whole structure correct 3/3
                        Volle struktuur korrek 3/3
                        Two Br atoms in structure 1/3
                        Twee Br atome in struktuur 1/3
                                                                                                            (3)

                 (b)     Chlorine √
                         Choor                                                                              (1)

        4.1.3    (a)
                                                   H       H       H       H
                                                                       √
                         R                 H       C       C = C           C       H√   but-2-ene√ √
                         `                                                          OR 2-butene
                                                   H                       H          but-2-een
                                                                                   OF 2-buteen
                             Marking criteria/Nasienriglyne
                             Whole structure correct 2/2
                             Vollestruktuur korrek 2/2
                             Only functional group correct ½
                             Slegs een funksionele groep korrek ½                                           (4)

                 (b)     Strong heat √ OR Concentrated strong base
                         Vurige hitte OF Gekonsentreerde sterk basis                                        (1)
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(EC/JUNIE 2019)                      FISIESE WETENSKAPPE V2                                        5

 4.2 4.2.1        ADDITION √
                  ADDISIE                                                                    (1)

        4.2.2     n = 1000 √                                                                 (1)

        4.2.3     Monomer √
                  Monomeer                                                                   (1)

        4.2.4     Make plastics√/ (Any other correct answer)
                  Vervaardiging van plastiek / (Enige ander korrekte antwoord)               (1)

 4.3 4.3.1        Breaking down of a long chain √ /hydrocarbon/alkane into more
                  useful shorter chains √
                  Breek van ŉ lang ketting / koolwaterstof / alkaan in nuttiger korter
                  kettings                                                                   (2)

        4.3.2     THERMAL CRACKING √
                  TERMIESE KRAKING                                                           (1)

        4.3.3
                         H      H     H      H     H    H

                   H     C      C     C      C     C    C     H √√    Hexane √√

                                                                       Heksaan
                         H      H     H     H      H    H

                   Marking criteria/Nasienriglyne
                      Whole structure correct 2/2
                      Volle struktuur korrek 2/2
                      If one or more hydrogens are omitted ½
                      Een of meer waterstofatoome uitgesluit ½
                                                                                             (4)
                                                                                            [22]

 QUESTION 5/VRAAG 5

 5.1 Temperature√/Concentration √ (of H2O2)/Add a catalyst √
     Temperatuur / Konsentrasie (van H2O2 ) / addisie van ŉ katalisator                      (3)

 5.2 Change in concentration per unit time/Rate of change of concentration √√
     OR change in amount/volume/mass of reactant/product per unit time.

        Verandering in konsentrasie per eenheidstyd / Tempo van verandering van
        konsentrasie
        OF ŉ verandering in hoeveelheid / volume / massa van reaktant / produk per
        eenheidstyd                                                                          (2)

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6                                  PHYSICAL SCIENCES P2                        (EC/JUNE 2019)

 5.3 5.3.1      Average rate/Gemiddelde tempo = - ∆c/∆t= - (1,45-1,9) √ /(15-0) √

                                                = 0,03√ (mol·dm-3·min-1)                  (3)

       5.3.2    High concentration √√ ( of H2O2 initially)
                Hoë konsentrasie ( van H2O2 oorspronklik)                                 (2)

 5.4 5.4.1      ENDOTHERMIC √
                ENDOTERMIES                                                               (1)

       5.4.2    Catalyst increases rate of reaction√/Katalisator verhoog reaksietempo

                 By lowering activation energy /Deur aktiveringsenergie te verlaag √
                 More particles have sufficient Ek to react √/More particles have Ek
                  greater or equal to Ea/Meer deeltjies het genoeg Ek om te reageer
                  √ / meer deeltjies het ŉ Ek groter of gelyk aan Ea √
                 More effective collisions per unit time √/Meer effektiewe botsings
                  per eenheidstyd                                                         (4)

 5.5 5.5.1      Experiment 1 √ : More particles have higher Ek √
                Eksperiment 1 : Meer deeltjies het hoër Ek                                (2)

       5.5.2    EQUAL TO √
                GELYK AAN

                Same amount of H2O2 used in both experiments √
                Dieselfde hoeveelheid H2 O2 word in beide eksperimente
                gebruik                                                                   (2)

 5.6 nO2 = V/Vm = 0,2/24,8 √ = 8,065 x 10-3 mol
     nH2O2 = 2 √ x 8,065 x 10-3
           = 0,061 mol
     m H2O2 = nM √= 0,0161 x (2+32) √
                   = 0,547g√ (0,55 g )                                                    (5)

 5.7 5.7.1      Q√                                                                        (1)

       5.7.2    R√                                                                        (1)

       5.7.3    P√                                                                        (1)
                                                                                         [27]

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(EC/JUNIE 2019)                        FISIESE WETENSKAPPE V2                           7

 QUESTION 6/VRAAG 6

 6.1 Stage reached by a chemical reaction where the rate of forward reaction
     equals the rate of reverse reaction √√
     Fase word bereik deur ŉ chemiese reaksie waar die tempo van voorwaartse
     reaksie gelyk is aan die tempo van terugwaartse reaksie                          (2)

 6.2 6.2.1         REMAINS THE SAME √
                   BLY DIESELFDE                                                      (1)

        6.2.2      INCREASES √
                   TOENEEM                                                            (1)

        6.2.3      INCREASES √
                   TOENEEM                                                            (1)

 6.3 Decreasing pressure is opposed √
     Reaction which produces more gas moles is favoured √
     Forward reaction is favoured √
     Afnemende druk is word teengestaan
     Reaksie wat meer gasmol produseer, word bevoordeel
     Voorwaartse reaksie word bevoordeel                                              (3)

 6.4 6.4.1         REVERSE √
                   TERUGWAARTS                                                        (1)

        6.4.2      Catalyst √√ (added)
                   Katalisator (bygevoeg)                                             (2)

     OPTION 1/OPSIE 1
 6.5 CALCULATIONS USING NUMBER OF MOLES
     BEREKENINGE MET DIE GEBRUIK VAN AANTAL MOL

                 Divide by/Deel deur 44 in n = m/M √
                 Divide nCO2 equilm & nCO equilm by 2 √
                 ∆n(CO2) = ninitial -neq √
                 Ratio verhouding CO2 : CO 1 : 2 √
                 nequil CO = nCOinitial+ ∆n(CO) √
                 Kc expression/Uitdrukking √
                 Substituting/Substitusie cequilmCO en cequilimCO2 √
                 Final answer /Finale antwoord √

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8                                        PHYSICAL SCIENCES P2                            (EC/JUNE 2019)

 OPTION 1/OPSIE 1

       ninitial CO2= m/M = 104,72/44 √ = 2,38 mol

                                                  CO2               C              CO
        ninitial                                  2,38                              0
        ∆n                                       0,48 √                        0,96√(Ratio)

        n equilm                                  1,9                             0,96√
        cequilm                                   7,6                         3,84√(Division
                                                                                 by 0,25)

       Kc = [CO]2/[CO2] √
          = 3,842/7,6 √
          = 1,94 √

 OPTION 2/OPSIE 2

 CALCULATIONS USING CONCENTRATION
 BEREKENINGE MET DIE GEBRUIK VAN KONSENTRASIE

                  Substitute into / Substitusie in C=m/MV
                   Substitute into/ Substitusie in c=n/V√
                  ∆c(CO2) = cinitial -ceq √
                  Ratio/Verhouding CO2 : CO 1:2 √
                  cequil CO = cCOinitial+ ∆c(CO) √
                  Kc expression /Uitdrukking √
                  Substituting /Substitusie cequilmCO and cequilimCO2 √
                  Final answer /Finale antwoord √

                   Initial Concentration of CO2 Equilibrium concentration of CO2
                   Aanvanklike konsentrasie van Ekwilibrium konsentrasie van CO2
                   CO2

                       m                                   n
                   c                                   c
                      MV                                   v
                        104,72                              1,9
                   c            √                      c         √
                      (44)(0,25)                           0,25
                   c  9,52mol  dm 3                  c  3,84mol  dm 3

                                          CO2                 C                   CO
                   Cinitial              9,52                 -                    0
                   ∆c                    1,90√                -               3,84√(Ratio)
                   c equilm              7,60                 -                  3,84√

                   Kc = [CO]2/[CO2] √
                      = 3,842/7,6 √
                      = 1,94 √                                                                    (8)
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(EC/JUNIE 2019)                      FISIESE WETENSKAPPE V2                                     9

 6.6 6.6.1        Low √ Yield/ Lae Opbrengs
                  Kc is low √/ Kc is less than 1/ [REACTANTS] > [PRODUCTS]
                  Kc is laag / Kc is minder as 1 / [REAKTANTE]> [PRODUKTE]               (2)

        6.6.2     Exothermic √ Eksotermies

                            As temperature decreases, Kc decreases, [Products]
                             decreases √
                             OR [Reactants increases]
                            Reverse reaction is favoured √
                            Decrease in temperature favours exothermic reaction √
                            Soos temperatuur afneem, verminder Kc, verminder
                             [Produkte] √
                             OF [Reaktante neem toe]
                            Omgekeerde reaksie word bevoordeel √
                            Afname in temperatuur bevoordeel eksotermiese
                             reaksie √                                                    (4)
                                                                                         [25]

 QUESTION 7
 7.1 7.1.1        Reaction of a salt with water √√
                  Reaksie van ŉ sout met water                                            (2)
 7.2 7.1.2        Can act as acid and as a base √√/Can donate H+ and accept H+
                  Kan as suur en as ŉ basis optree / kan H+ skenk en H+ aanvaar           (2)
        7.1.3     HCO3 √                                                                  (1)

        7.1.4     H2CO3 √                                                                 (1)

 7.2 7.2.1        Standard √ (solution)
                  Standaard (oplossing)                                                   (1)

        7.2.2     CH3COOH √√                                                              (2)

        7.2.3     c1V1=c2V2                          n=cV=(0,2)(0.02) √ =0,004 mol
                  0,2 x 20 √ = 0,16 x V2 √           V=n/c= (0,004)/(0,16) √
                  V2 = 25 cm3√ OR 0,025 dm3          V=25 cm3 √ OR/OF 0,025 dm3           (3)

 7.3 7.3.1        Neutralisation √
                  Neutralisasie                                                           (1)

        7.3.2     6,8 to 7,2 √
                  Titration between strong base and a strong acid √
                  Solution at endpoint is neutral √
                  Titrasie tussen sterk basis en ŉ sterk suur
                  Oplossing by eindpunt is neutraal                                       (3)

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10                                    PHYSICAL SCIENCES P2                 (EC/JUNE 2019)

       7.3.3    nNaOH reacting = cV = 0,1 x 30/1000 √= 0,003 mol
                nHCl reacting = 0,003 mol √
                cHCl = n/V = 0,003/(25/1000) √
                     = 0,12 mol.dm-3 √
                OR cAVA/cBVB= nA/nB
                     cA x 25/0,1 x30 = 1/1
                      cA = 0,12 mol.dm-3                                                (4)

       7.3.4    Point where an indicator changes colour √√
                Punt waar ŉ indikator van kleur verander                                (2)

       7.3.5    POSITIVE MARKING FROM 7.3.3
                nHCl excess = cV√ = 0,12 x 8/1000 √
                                  =9,6 x 10-4 mol
                cHCl= n/V = 9,6 x 10-4/(30 + 25 + 8) √/1 000 √
                     = 0,015 mol.dm-3

                pH = -log[H3O+] √
                   = - log (0,15) √
                   = 0,82 √                                                             (7)
                                                                                       [29]
                                                                   TOTAL /TOTAAL:      150

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