# Physical Sciences Grade 12 P2 Eastern Cape Mock 2023 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape Mock Exam 2023 (English), 19 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/phys-sciences-p2-memo-sept-2023-afr-english/625c2473-7703-4acd-a6fb-10c9392e3245
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2023
- Exam period: Eastern Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 19

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## About this document

Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2023 · English. Memorandum, 19 pages. Read online or download the PDF.

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## Matching paper and memo

- [PHYS SCIENCES P2 GR12 QP SEPT2023 English](https://www.hlayiso.com/library/phys-sciences-p2-gr12-qp-sept2023-english/f017d6ca-bfcd-44e3-bc0c-14bcf23396c8) — QP · 2023 · Eng

## Document text

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### Page 1

NATIONAL
                SENIOR CERTIFICATE/
                    NASIONALE
                SENIORSERTIFIKAAT

                     GRADE/GRAAD 12

                 SEPTEMBER 2023

          PHYSICAL SCIENCES P2/ FISIESE
                WETENSKAPPE V2
         MARKING GUIDELINE/NASIENRIGLYN

MARKS:   150

               This marking guideline consists of 19 pages./
                Hierdie nasienriglyn bestaan uit 19 bladsye.

### Page 2

2                               PHYSICAL SCIENCES P2                  (EC/SEPTEMBER 2023)

QUESTION 1/VRAAG 1

1.1     D ✓✓                                                                            (2)

1.2     B ✓✓                                                                            (2)

1.3     A✓✓                                                                             (2)

1.4     D ✓✓                                                                            (2)

1.5     B ✓✓                                                                            (2)

1.6     C ✓✓                                                                            (2)

1.7     D ✓✓                                                                            (2)

1.8     A ✓✓                                                                            (2)

1.9     D ✓✓                                                                            (2)

1.10    B ✓✓                                                                           (2)
                                                                                      [20]

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### Page 3

(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                                   3

QUESTION 2/VRAAG 2
2.1.1    D✓                                                                                            (1)

2.1.2    F✓                                                                                            (1)

2.1.3    B✓                                                                                            (1)

2.2      UNSATURATED ✓

         It is an organic compound that contains double/triple/multiple bonds. ✓

         ONVERSADIG

         Dit is ŉ organiese verbinding wat dubbel/drievoudige/meervoudige bindings
         bevat.                                                                                        (2)

2.3.1
                                H
                                                             Marking criteria/Nasienkriteria
                              H C       H                     • Functional group correct ✓
              H       H   H                 O                    Funksionele groep korrek
                                                              • Whole structure correct ✓
         H     C      C   C     C           C                    Hele struktuur korrek

               H      H   H                     O        H
                          H     C       H

                                H                                                                      (2)

2.3.2    hept-3-yne ✓ ✓ / 3-heptyne             Marking criteria/ Nasienkriteria
                                                 • Parent name and suffix correct (heptyne)✓
         hept-3-yn / 3-heptyn                      Stam naam en agtervoegsel korrek (heptyn)
                                                 • Everything correct e.g. hyphens and
                                                    numbering ✓
                                                    Alles korrek bv koppeltekens en nommering
                                                                                                       (2)

2.4      Tertiary. ✓

         The carbon that is bonded to the hydroxyl group (-OH) is bonded to three
         other carbons. ✓
                                                    OR
         The carbon of the functional group is bonded to three other carbons.
         Tersiêre
         Die koolstof wat verbind is aan die hidroksielgroep (-OH) is verbind aan
         drie ander koolstowwe.
                                              OF
         Die koolstof van die funksionele groep is aan drie ander koolstowwe verbind.                  (2)

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### Page 4

4                               PHYSICAL SCIENCES P2                      (EC/SEPTEMBER 2023)

2.5     Butan-2-ol / 2-butanol ✓✓       NOTE/LET WEL: Butan-1-ol / 1-butanol (1/2)          (2)

2.6.1   Compounds with the same molecular formula ✓ but different functional
        groups ✓/belong to different homologous series.

        Verbindings met dieselfde molekulêre formule, maar verskillende
        funksionele groepe / behoort aan verskillende homoloë reeks.                        (2)

2.6.2   CH3COCH3 ✓✓             OR/OF              O
                                                   II
                                                CH3CCH3                                     (2)
                                                                                           [17]

QUESTION 3/VRAAG 3

3.1     Marking criteria/ Nasienriglyne
        If any of the underlined key words/phrases in the correct context are
        omitted: -1 mark per word/phrase.
        Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
        word: -1 punt per woord/frase

        The temperature at which the vapour pressure of a liquid equals the
        atmospheric pressure ✓✓

        Die temperatuur waarby die dampdruk van ŉ vloeistof gelyk is aan die
        atmosferiese druk.                                                                  (2)

3.2.1   Molecular size ✓ / Surface area / Chain length / London forces
        Molekulêre grootte / Oppervlakte / kettinglengte / Londonkragte                     (1)

3.2.2   Functional group ✓/ Homologous series
        Funksionele groep / Homoloë reeks                                                   (1)

3.3     London forces / induced dipole forces / dispersion forces ✓
        Londonkragte / geїnduseerde dipoolkragte / verspreidingskragte                      (1)

3.4     129 °C ✓                                                                            (1)

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### Page 5

(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                          5

3.5      Marking criteria/Nasienkriteria
         • Compare the molecular size of 2-methylbutan-1-ol to butan-1-ol ✓
         • Relate the molecular size to London forces/induced dipole
            forces/dispersion forces. ✓

         •   Compare the chain length of 2-methylbutan-1-ol to pentan-1-ol ✓
         •   Relate the chain length to London forces/induced dipole
             forces/dispersion forces ✓

         •   Vergelyk die molekulêre grootte van 2-metielbutan-1-ol aan butan-1-ol
         •   Verwys die molekulêre grootte na die Londonkragte/ geїnduseerde
             dipoolkragte / verspreidingkragte

         •   Vergelyk die kettinglengte van 2-metielbutan-1-ol met pentan-1-ol
         •   Verwys die kettinglengte na die Londonkragte / geїnduseer
             dipoolkragte / verspreidingkragte

         •   2-methylbutan-1-ol has a larger molar mass/molecular size than butan-
             1-ol ✓
         •   London forces/induced dipole forces/dispersion forces of
             2-methylbutan-1-ol is stronger than that butan-1ol ✓
         •   The boiling point will higher than that of butan-1-ol

         •   2-methyl butan-1-ol has a shorter chain length than pentan-1-ol✓
         •   London forces of 2-methyl butan-1-ol is weaker than that of
             pentan-1-ol ✓
         •   The boiling point will be lower than that of pentan-1-ol

         •   2-metielbutan-1-ol het ‘n groter molekulêre massa/molekulêre grootte
             as butan-1-ol
         •   Londonkragte/geїnduseerde dipoolkragte/verspreidings van
             2-metielbutan-1-ol is sterker as dié van butan-1-ol
         •   Die kookpunt is hoër as dié van butan-1-ol

         •   2-metielbutan-1-ol het ‘n korter kettinglengte as pentan-1-ol
         •   Londonkragte van 2-metielbutan-1-ol is swakker as dié van
             pentan-1-ol
         •   Die kookpunt sal laer wees as dié van pentan-1-ol                                (4)

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### Page 6

6                               PHYSICAL SCIENCES P2                       (EC/SEPTEMBER 2023)

                                                OR /OF

        • Butan-1-ol has a smaller molar mass/molecular size than 2-methylbutan-1-ol
        • London forces/induced dipole forces/dispersion forces of butan-1-ol is
          weaker than that 2-methylbutan-1-ol
        • The boiling point will higher than that of butan-1-ol

        • Pentan-1-ol has a larger chainlength than 2-methyl butan-1-ol
        • London forces/induced dipole forces/dispersion forces of pentan-1-ol is
          stronger than that of 2-methyl butan-1-ol
        • The boiling point will be lower than that of pentan-1-ol

        •   Butan-1-ol het ŉ kleiner molekulêre massa/molekulêre grootte as
            2-metielbutan-1-ol
        •   Londonkragte/geїnduseerde dipoolkragte/verspreidings van butan-1-ol is
            swakker as dié van 2-metielbutan-1-ol
        •   Die kookpunt is hoër as dié van butan-1-ol

        •   Pentan-1-ol het ŉ langer kettinglengte as 2-metielbutan-1-ol
        •   Londonkragte van pentan-1-ol is sterker as dié van 2-metielbutan-1-ol
        •   Die kookpunt sal laer wees as dié van pentan-1-ol

3.6.1   Marking criteria/Nasienkriteria
        If any of the underlined key words/phrases in the correct context are omitted:
        - 1 mark per word/phrase.
        Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
        word: - 1 punt per woord/frase

        The pressure exerted by a vapour at equilibrium with its liquid in a closed
        system. ✓✓

        Die druk uitgeoefen deur ŉ damp in ewewig met sy vloeistof in ŉ geslote sisteem.           (2)

3.6.2   Q✓                                                                                         (1)

3.6.3   Marking criteria/Nasienkriteria
        • Propan-1-ol has hydrogen bonds ✓(and London forces/induced dipole
           forces/dispersion forces
        • Propanal has dipole-dipole forces ✓( and London/induced dipole
           forces/dispersion forces
        • Compare the strength of the hydrogen bonds to dipole-dipole forces ✓
        • Relate strength of intermolecular forces to vapour pressure ✓

        •   Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
            dipoolkragte/verspreidingskragte)
        •   Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
            dipoolkragte/verspreidingskragte)
        •   Vergelyk die sterkte van die waterstofbindings met die dipool-dipoolkragte
        •   Verwys die sterkte van die intermolekulêrekragte met die dampdruk

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### Page 7

(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                      7

       •   Propan-1-ol has hydrogen bonds ✓(and London forces/induced dipole
           forces/dispersion forces)
       •   Propanal has dipole-dipole forces (and London forces/induced dipole
           forces/dispersion forces) ✓
       •   Hydrogen bonds are stronger than the dipole-dipole forces ✓
       •   Stronger intermolecular forces result in lower vapour pressure ✓

       •   Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
           dipoolkragte/verspreidingskragte)
       •   Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
           dipoolkragte/verspreidingskragte)
       •   Waterstofbindings is sterker as dipool-dipoolkragte
       •   Sterker intermolekulêrekragte het laer dampdruk

                                           OR / OF

       •   Propan-1-ol has Hydrogen bonds ✓ (and London forces/induced dipole
           forces/dispersion forces)
       •   Propanal has dipole-dipole forces ✓( and London/induced dipole
           forces/dispersion forces)
       •   Dipole-dipole forces are weaker than the hydrogen bonds✓
       •   Weaker intermolecular forces result in higher vapour pressure ✓

       •   Propan-1-ol het waterstofbindings (en Londonkragte/geїnduseerde
           dipoolkragte/verspreidingskragte)
       •   Propanal het dipool-dipoolkragte (en Londonkragte/geїnduseerde
           dipoolkragte/verspreidingskragte)
       •   Dipool-dipoolkragte is swakker as waterstofbindings
       •   Swakker intermolekulêrekragte het hoër dampdruk                                       (4)
                                                                                                [17]

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### Page 8

8                                    PHYSICAL SCIENCES P2                         (EC/SEPTEMBER 2023)

 QUESTION 4/VRAAG 4

 4.1.1 Hydrolysis / Hidrolise ✓                                                                           (1)

 4.1.2 Pentan-2-ol / 2-pentanol ✓✓                                                                        (2)

 4.1.3 Concentrated strong base✓ OR concentrated NaOH OR concentrated KOH OR
       concentrated LiOH
         Gekonsentreerde sterk basis OF gekonsentreerde NaOH OF gekonsentreerde KOH
         OF gekonsentreerde LiOH                                                                          (1)

 4.1.4                                                      Marking criteria/Nasienkriteria
                     H       H   H     H     H                 •    Functional group correct ✓
                                                                    Funksionele groep korrek
             H       C       C ✓C      C    C     H✓           •    Whole structure correct ✓
                                                                    Hele struktuur korrek
                     H                 H    H                                                             (2)

 4.1.5 Sulphuric acid / Swawelsuur ✓                                                                      (1)

 4.1.6 Dehydration / Dehidrasie / Dehidratering ✓                                                         (1)

 4.2.1 Esterification / Condensation / Esterifikasie / Verestering ✓                                      (1)

 4.2.2 Alcohols are flammable✓ /prevent fire
       Alkohole is vlambaar / om ŉ vuur te voorkom                                                        (1)

 4.2.3           H       H
                        O H H                               Marking criteria/Nasienkriteria
                       ✓                                       •    Functional group correct ✓
         H       C C O C C C H                                      Funksionele groep korrek
                 H       H          H H                        •    Whole structure correct ✓
                                                                    Hele struktuur korrek

         ethyl ✓propanoate ✓ / etiel-propanoaat                                                           (4)
                                                                                                         [14]

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(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                        9

QUESTION 5/VRAAG 5

5.1     Marking criteria/ Nasienriglyne
        If any of the underlined key words/phrases in the correct context are
        omitted: - 1 mark per word/phrase.
        Indien enige van die sleutelwoorde/frases in die korrekte konteks
        weggelaat word: - 1 punt per woord/frase

        ANY ONE
        Change in concentration ✓of reactant or product per (unit) time.✓

        Change in amount/number of moles/volume/mass of products or
        reactants per (unit) time.

        Change in amount/number of moles/volume/mass of products formed or
        reactants used reactants per (unit) time.

        ENIGE EEN
        Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd.

        Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of
        produkte per (eenheid) tyd.

        Verandering in hoeveelheid/getal mol/volume/massa van produkte
        gevorm/reaktanse gebruik per (eenheid) tyd.

                                          OR/OF

        The rate of change in concentration / amount of moles / number of moles /
        volume / mass. (2 or 0)

        Die tempo van verandering in konsentrasie/hoeveelheid mol/getal
        mol/volume/massa ✓✓ (2 of 0)                                                      (2)

5.2     Stopwatch ✓/Timer/ Measuring cylinder
        Stophorlosie / Tydhouer / Meetsilinder                                            (1)

5.3     Reaction is exothermic / reaction releases heat ✓
        Reaksie is eksotermies / reaksie gee hitte af                                     (1)

5.4     SHORTER / KORTER ✓                                                                (1)

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10                              PHYSICAL SCIENCES P2                     (EC/SEPTEMBER 2023)

5.5       For Exp. 2
          • Higher concentration results in more particles colliding with correct
               orientation✓
          • The number of effective collision per unit time increases / frequency
               of the effective collisions increases ✓
          Vir Eksp. 2
          • Hoër konsentrasie beteken meer deeltjies bots met die korrekte
               orientasie
          • Die aantal effektiewe botsings per eenheid tyd neem toe/ frekwensie
               van die effektiewe botsings neem toe.

                                                OR / OF
          For Exp. 1
          • Low concentration results in fewer particles colliding with correct
               orientation ✓
          • The number of effective collision per unit time decreases / frequency
               of effective collisions decreases ✓
          Vir Eksp. 1
          • Lae konsentrasie beteken minder deeltjies bots met die korrekte
               orientasie
          • Die aantal effektiewe botsings per eenheid tyd neem af / frekwensie
               van die effektiewe botsings neem af.                                       (2)

5.6.1     Rate/ Tempo = ∆c
                        ∆t
                      = 250-0 ✓                 Accept / Aanvaar     250
                        5,28-0 ✓                                     5,28
              = 0,95✓(cm3·min-1)                                                          (3)

5.6.2     Marking criteria / Nasienkriteria
          • VCO2 remaining / oorbly = 150 cm3
          • Substitution into / Vervanging in n = V/Vm
          • Subst. into / Vervanging in n = m/M
          • Final answer / Finale antwoord

          V(CO2) remaining / oorbly = 250 – 100 = 150 cm3 ✓

          n = V/Vm = 150/25 000 ✓

                     = 6 x 10 -3 mol

              n(CO2) = m/M
                               6 x 10 -3 = m / 44 ✓
               m = 0,264 g ✓/0,26 g                                                       (4)

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### Page 11

(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                      11

5.7.1   P✓                                                                                (1)

5.7.2   C2H4O2 is a weaker acid ✓(than HCℓ) which will result in a LOWER
        reaction rate ✓ (for Expt. 3) / Lower gradient/Longer reaction time

        C2H4O2 is ŉ swakker suur (as HCℓ) wat sal lei na ŉ LAER reaksietempo
        (vir Eksp. 3) / laer gradiënt / langer reaksietyd

                                         OR / OF

        HCℓ is stronger acid ✓(than C2H4O2) which will result in a HIGHER
        reaction rate ✓ for Expt. 1/ Higher gradient/Shorter reaction time

        HCℓ is ŉ sterker suur (as C2H4O2) wat sal lei na ŉ HOЁR reaksietempo
        (vir Eksp. 1) / hoër gradiënt / korter reaksietyd                                 (2)

5.7.3   EQUAL TO ✓
        Final amount of CO2 is the same ✓ (in both experiments)

        GELYK AAN
        Finale hoeveelheid van CO2 is gelyk (in beide eksperimente)                       (2)
                                                                                         [19]

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### Page 12

12                                    PHYSICAL SCIENCES P2                        (EC/SEPTEMBER 2023)

QUESTION 6 / VRAAG 6

6.1.1   Reversible reaction ✓ /Products can be converted back to reactants
        Omkeerbare reaksie / Produkte kan na reaktanse omgeskakel word

        NOTE: Do not accept “Reaction is at equilibrium”
        LET WEL: Moenie “Reaksie is by ewewig” aanvaar nie.                                         (1)

6.1.2   (Chemical) Equilibrium / (Chemiese) Ewewig ✓                                                (1)

6.1.3   HEATED / VERHIT ✓                                                                           (1)

6.1.4   ENDOTHERMIC / ENDOTERMIES ✓                                                                 (1)

6.1.5   • Increase in temperature favoured the forward reaction ✓ / The rate of the
          forward reaction increased more than the rate of the reverse reaction.
        • Increase in temperature favours the endothermic reaction. ✓

        • Toename in temperatuur bevoordeel die voortwaartse reaksie / Die
          tempo van die voortwaartse reaksie is hoër as die terugwaartse reaksie
        • ŉ Toename in temperatuur bevoordeel die endotermiese reaksie                              (2)

6.1.6
             Reaksie tempo/

            Reaction rate

            (mol·dm-3·min-1)
                               Time (minutes) / Tyd (minute)
            Marking criteria/ Nasienkriteria
            •   Both rates increase; new equilibrium at a higher rate when P is
                increased ✓
                Beide tempos neem toe; nuwe ewewig is by ŉ hoër tempo wanneer
                P verhoog

        •             The increase in reverse reaction is HIGHER than for the forward
                      reaction and eventually there is horizontal section for both ✓
                      Die toename in die terugwaartse reaksie is HOЁR as die
                      voortwaartse reaksie en daar is horisontale gedeelte by die einde vir
                      beide.

            NOTE: Do not penalise if axes are not labelled.
            LET WEL: Moenie penaliseer as asse nie benoem is nie.
                                                                                                    (2)

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### Page 13

(EC/SEPTEMBER 2023)             PHYSICAL SCIENCES P2                                         13

6.2      MOLE CALCULATIONS / MOL BEREKENINGE

         a. Correct KC expression (formula in square brackets) ✓
         b. Substitution of equilibrium concentration of CO2 into KC expression ✓
         c. Determining the nequilibrium CO ✓
         d. Determining the n CO reacted
         e. Correct mol ratio for CO:C ✓
         f. Determining the initial mol of C✓
         g. Correct substitution into percentage formula ✓
         h. Final answer ✓

         a. Korrekte Kc-uitdrukking (Formule formule tussen vierkanthakies)
         b. Vervanging van ewewigkonsentrasie van CO2 in KC – uitdrukking
         c. Bepaal die newewig CO
         d. Bepaal n CO reageer
         e. Korrekte molverhouding vir CO : C
         f. Bepaal die aanvanklike mol van C
         g. Korrekte vervanging in persentasie formule
         h. Finale antwoord

                                            •    No Kc expression, correct
                                                 substitution / Geen Kc-uitdrukking,
            Kc = [CO]2 ✓ (a)                     korrekte, korrekte substitusie.
                 [CO2]                           Max. / Maks. 7/8
                                            •    Wrong Kc expression / Verkeerde
            0,05 = [CO]2 (b)                     Kc-uitdrukking. Max. Maks. 5/8
                    0,05 ✓
              [CO] = 0,05 mol.dm-3

                                                 C (s)         CO2 (g)        2 CO (g)
          Initial mol /Aanvangs-                                                 0
                                                 0,45 ✓(f)
          hoeveelheid (mol)
          Change/ Verandering in mol             0, 05✓(e)                     0,1✓ (d)
          Equilibrium/ Ewewig mol                0,40                          0,1✓ (c)
          Concentration/ Konsentrasie
                                                    -                          0,05
          (mol·dm-3)

         % C reacted = ∆n/ninitial x 100

                       = 0,05/0,45 x 100 ✓ (g)

                       = 11,11%✓ (h)                                                            (8)
                                                                                              [16]

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### Page 14

14                              PHYSICAL SCIENCES P2                       (EC/SEPTEMBER 2023)

QUESTION 7/VRAAG 7

7.1.1   An acid is a proton (H+ -ion) donor ✓✓
        ŉ Suur is ŉ proton (H+ -ioon) skenker                                                     (2)

7.1.2   HC2O4 – ✓                                                                                 (1)

7.1.3   Weak acid / Swaksuur ✓                                                                    (1)

7.1.4   The acid did not fully/completely ionise ✓✓ (in water). OR ionised
        incompletely.
        Die suur ioniseer nie volledig (in water) nie OF Suur ioniseer onvolledig                 (2)

7.2.1   Marking criteria/Nasienkriteria
        • n = cV
        • Subst. into / Vervanging in n = cV
        • Final answer / Finale antwoord

        n (CH3COOH) = cV ✓
                    = 0,1 x 25 x 10-3 ✓
                    = 2,5 x 10-3 mol ✓                                                            (3)

7.2.2   Marking criteria/Nasienkriteria          Marking criteria/Nasienkriteria

        •    Formula pH = - log [H3O+] ✓         •   Formula pOH + pH = 14 ✓
        •    pH value substituted into           •   pH value substituted into
             formula ✓                               formula ✓
        •    Substitution in Kw formula ✓        •   Substitution in pOH formula ✓
        •    Final answer ✓                      •   Final answer ✓

        •    Formule pH = - log [H3O+]           •   Formule pOH + pH = 14
        •    pH waarde vervang in formule        •   pH waarde vervang in formule
        •    Vervang in KW formule               •   Vervang van pOH waarde in
        •    Finale antwoord                         formule
                                                 •   Finale antwoord

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### Page 15

(EC/SEPTEMBER 2023)              PHYSICAL SCIENCES P2                                          15

         OPTION 1 / OPSIE 1                            OPTION 2 / OPSIE 2

         pH = - log [H3O+] ✓                           pOH + pH = 14 ✓

         12 ✓ = - log [H3O+]                           pOH + 12 ✓ = 14

         [H3O+] = 1 × 10-12 mol·dm-3                   pOH = 2

         Kw = [OH–][H3O+] = 1 × 10-14                  pOH = - log [OH–]

         [OH–][H3O+] = 1 × 10-14                       2 = - log [OH–] ✓

         [OH–](1 × 10-12) = 1 × 10-14 ✓                [OH–] = 0,01 mol·dm-3 ✓

         [OH–] = 0,01 mol·dm-3 ✓                                                                    (4)

 7.2.3 Positive marking from / Positiewe nasien vanaf 7.2.1 and/ en 7.2.2
       Marking criteria / Nasienkriteria

             •   Using ratio Acid : Base 1 : 1
             •   Subst. of base values into nNaOH excess = cV
             •   Addition of n remaining and n initial (NaOH)
             •   Subst. into c = n/V
             •   Multiplication of cdilute by 10
             •   Final answer

             •   Gebruik verhouding Suu r: Basis = 1 : 1
             •   Vervanging van basis waarde in nNaOH oormaat = cV
             •   Addisie van n oorbly en n aanvanklik (NaOH)
             •   Vervanging in c = n / V
             •   Vermenigvulding van cverdun met 10
             •   Finale antwoord

         n (NaOH) reacting/ reageer = 2,5 x 10-3 mol ✓ From/Vanaf 7.2.1

         n (NaOH) in excess/ oormaat = cV

         n (NaOH) excess/ oormaat = (0,01)(60 x 10-3) ✓

         n (NaOH) excess/ oormaat = 6 x 10-4 mol

         n (NaOH)total/ totaal = 2,5 x 10-3 + 6 x 10-4 ✓

         n (NaOH) = 3,1 x 10-3 mol                                                                  (6)

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### Page 16

16                                  PHYSICAL SCIENCES P2                  (EC/SEPTEMBER 2023)

                       n
 cdilute/verdun    =
                       V

                       3,1 x 10-3
 cdilute/verdun    =                    ✓
                       35 x 10-3

 cdilute/verdun    =   0,08857 mol· dm-3

 cconcentrated /       = 0,08857 x 10 ✓
 gekonsentreerd        = 0,8857 mol·dm-3✓/0,89 mol· dm-3
                                                                                           [19]

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### Page 17

(EC/SEPTEMBER 2023)              PHYSICAL SCIENCES P2                                             17

QUESTION 8/VRAAG 8

8.1      Chemical energy is converted into electrical energy ✓✓
         Chemiese energie word na elektriese energie omgeskakel.                                       (2)

8.2.1    Fe2+ → Fe3+ + e- ✓✓                                                                           (2)

         Marking criteria / Nasienkriteria
         • Fe3+ + e- ← Fe2+           2/2
         • Fe ⇌ Fe + e
              2+       3+     -       ½
         • Fe + e- → Fe
              3+               2+     0/2
         • Fe3+ + e - ⇌ Fe2+          0/2

         •    Ignore if the charge omitted on electron
              Ignoreer indien lading op elektron weggelaat is

         •    If a charge of an ion is omitted
              As lading weggelaat is op ŉ ioon.
              e.g. / bv. Fe2 → Fe3 + e- Max. / Maks. ½

8.2.2    Ag ⎸Ag+✓ ⎸⎸✓ Fe3+,Fe2+✓⎸Pt ✓                                                                  (3)

             Marking criteria/Nasienkriteria
         •    Ag ⎸Ag+ ✓
         •    Fe3+,Fe2+ ⎸Pt ✓
         •    ⎸⎸ ✓

8.2.3    Concentration: 1 mol·dm-3 ✓ and temperature: 25 °C ✓ / 298 K
         Konsentrasie: 1 mol·dm-3 en temperatuur: 25 °C / 298 K                                        (2)

8.3      Eθcell = Eθcathode/reduction/oxidising agent – Eθanode/oxidation/reducing agent ✓
                                                         Marking criteria/Nasienkriteria
         Eθcell = (0,80) ✓ – (0,77) ✓              • Any other formula using unconventional
                                                       abbreviation , e.g.
         Eθcell = 0,03 V ✓                             Enige ander formule wat
                                                       onkonvensionele afkortings gebruik bv.
                                                   • Eθcell = EθOA –Eθ RA followed by the
                                                       correct substitution./ gevolg deur
                                                       korrekte vervangings ¾
                                                                                                       (4)

8.4      Decrease / Afneem ✓                                                                           (1)

8.5      Cℓ– would form an insoluble salt/precipitate with the Ag+✓✓ / AgCℓ will
         precipitate out. The Ag+ half-cell would no longer be neutral / Circuit would
         be incomplete / Not enough electrolyte in half cell.

         Cℓ – sal ŉ neerslag vorm/presipiteer met Ag+/ AgCℓ vorm ŉ neerslag / Die
         Ag+halfsel sal nie meer neutraal wees nie / Stroombaan sal onvoltooїed
         wees / Nie genoeg elektroliet in die halfsel nie.                                           (2)
                                                                                                    [16]
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### Page 18

18                              PHYSICAL SCIENCES P2                    (EC/SEPTEMBER 2023)

QUESTION 9/VRAAG 9

9.1     Marking criteria/ Nasienriglyne
        If any of the underlined key words/phrases in the correct context are
        omitted: - 1 mark per word/phrase.
        Indien enige van die sleutelwoorde/frases in die korrekte konteks
        weggelaat word: - 1 punt per woord/frase

        The chemical process in which electrical energy is converted to chemical
        energy. ✓✓
        Die chemiese proses waarin elektriese energie word na chemiese
        energie omgeskakel.
                                          OR / OF
        The use of electrical energy to produce a chemical change. ✓✓
        Die gebruik van elektriese energie om chemiese energie te produseer               (2)

9.2     ENDOTHERMIC / ENDOTERMIES ✓                                                       (1)

9.3     2 Cℓ – → Cℓ2(g) + 2e− ✓✓                  Ignore phases / Ignoreer fases          (2)
        Marking criteria / Nasienkriteria
           • 2 Cℓ – ⇌ Cℓ2(g) + 2e− ½
           • Cℓ2(g) + 2e− ← 2 Cℓ – 2/2
           • Cℓ2(g) + 2e− ⇌ 2 Cℓ – 0/2

        Ignore if the charge omitted on electron /
        Ignoreer as lading op elektron weggelaat is

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### Page 19

(EC/SEPTEMBER 2023)               PHYSICAL SCIENCES P2                                         19

 9.4
                          m                         Marking criteria/Nasienkriteria
                  n   =
                          M
                                                      • Subst. into n = m/M
                          0,369                       • Use of mole ratio Cu : e-
                  n   =             ✓                 • Subst. into n = N/NA
                          63,5
                                                      • Subst. into n = Q/qe
                  n =     5,811 x 10-3                • Formula Q = IΔt
                                                      • Subst. into Q = IΔt
          n (e-) = 2 x 5,811 x 10-3 ✓
                                                      • Final answer with unit
          n (e-) = 0,01162
                                                          •   Vervang in n = m/M
                                                          •   Gebruik van mol-
                          N                                   verhouding Cu : e-
                  n   =
                          NA                              •   Vervang in n = N/NA
                                                          •   Vervang in n = Q/qe
          0,01162 =          N         ✓                  •   Formule Q = IΔt
                          6,02 x 10 23                    •   Vervang in Q= IΔt
                                                          •   Finale antwoord met
                 N =      6,9964 x 1021                       eenheid

                 Q =      Nq

                 Q =      6,9964 x 1021 x 1,6 x 10-19 ✓

                 Q =      1 119,4310 C

                  I =     Q
                             ✓
                          Δt

                  I =     1 119,4310
                                           ✓
                          27 x 60

                  I =     0,69 A ✓                                                              (7)
                                                                                               [12]

                                                                     TOTAL/TOTAAL:             150

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