# Physical Sciences Grade 12 P2 Eastern Cape June 2023 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape June 2023, 17 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physc-gr12-p2-memo-june-2023-eng-afr/c4135e17-9d53-41f6-a444-931d19a91210
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2023
- Exam period: Eastern Cape June
- Paper: 2
- Curriculum: CAPS
- Pages: 17

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## About this document

Physical Sciences · Grade 12 · Eastern Cape June · 2023. Memorandum, 17 pages. Read online or download the PDF.

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### Page 1

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                        NATIONAL SENIOR
                          CERTIFICATE/
                           NASIONALE
                       SENIORSERTIFIKAAT

                          GRADE/GRAAD 12

                          JUNE/JUNIE 2023

         PHYSICAL SCIENCES: CHEMISTRY P2
                MARKING GUIDELINE/
         FISIESE WETENSKAPPE: CHEMIE V2
                  NASIENRIGLYN

MARKS/PUNTE:   150

                     This marking guideline consists of 17 pages./
                      Hierdie nasienriglyn bestaan uit 17 bladsye.

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2                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2          (EC/JUNE/JUNIE 2023)

QUESTION 1/VRAAG 1

1.1     C                                                                              (2)

1.2     B                                                                              (2)

1.3     B                                                                              (2)

1.4     B                                                                              (2)

1.5     A                                                                              (2)

1.6     C                                                                              (2)

1.7     D                                                                              (2)

1.8     C                                                                              (2)

1.9     B                                                                              (2)

1.10    B                                                                              (2)
                                                                                        [20]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                         3

 QUESTION 2/VRAAG 2

 2.1     2.1.1     H                                                                           (1)

         2.1.2     D                                                                           (1)

         2.1.3     A                                                                           (1)

         2.1.4     F                                                                           (1)

         2.1.5     F                                                                           (1)

                   Marking criteria/Nasienkriteria
                   If any of the underlined key words/phrases in the correct context are
                   omitted: - 1 mark per word/phrase.
                   Indien enige van die sleutelwoorde/frases in die korrekte konteks
                   weggelaat word: - 1 punt per woord/frase.

 2.2     2.2.1     Compounds that have the same molecular formula but different
                   structural formulae. 

                   Verbindings wat dieselfde molekulêre formule maar verskillende
                   struktuurformules het.                                                       (2)

         2.2.2     POSITIONAL / POSISIONEEL                                                    (1)

         2.2.3     SECONDARY / SEKONDÊR 

                   The C bonded to OH is bonded to two other carbons/ C of functional
                   group bonded to two other carbons / C bonded to OH has 1 hydrogen/
                   C of functional group has one hydrogen 

                   Die C wat verbind is aan die OH is verbind aan twee ander koolstowwe
                   / C van die funksionele groep is verbind aan twee ander koolstowwe /
                   C wat verbind is aan die OH het 1 waterstof / C van die funksionele
                   groep het 1 waterstof.                                                       (3)

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4                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                       (EC/JUNE/JUNIE 2023)

 2.3.1      3,4-dimethylhept-3-ene / 3,4-dimethylhept-3-ene
            3,4-dimetielhept-3-een / 3,4-dimetiel-3-hepteen
              Marking criteria/Nasienkriteria:
              • Heptene / Hept-een 
              • Dimethyl / dimetiel 
              • Whole name correct / hele naam korrek                                                 (3)

 2.3.2
                                            Marking criteria/Nasienkriteria:
                               O
                                            • Whole structure correct/Hele struktuur korrek: 2/2
                                            •   Only functional group correct
                 CH3    CH2    CH            Slegs funksionele groep korrek Max./Maks. 1/2

                                                    OR / OF

            CH3CH2CHO                                                                                (2)

 2.4.1      C2H4O                                                                                     (1)

 2.4.2      Carboxyl (group) / Karboksiel (groep)                                                     (1)

 2.5.1      Ester                                                                                     (1)

 2.5.2            Methyl butanoate  / Metiel butanoaat

                           H     H      H       O               H
                                                    
                    H      C     C      C       C       O      C         H      

                          H     H       H       H              H
                                                Marking criteria/Nasienkriteria
                                                • Functional group/Funksionele groep  1/2
                                                • Whole structure correct/
                                                   Hele struktuur korrek           2/2
                                                                                                      (4)
                                                                                                     [23]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                         5

 QUESTION 3/VRAAG 3

           Marking criteria/Nasienkriteria
           If any of the underlined key words/phrases in the correct context are omitted:
           - 1 mark per word/phrase.
           Indien enige van die sleutelwoorde/frases in die korrekte konteks
           weggelaat word: - 1 punt per woord/frase.

 3.1       Melting point is the temperature at which the solid and liquid substances are
           at equilibrium. 

           Smeltpunt is die temperatuur waarby die vastof- en vloeistoffases van ŉ stof
           in ewewig is.                                                                        (2)

 3.2       Marking criteria
           • Increase in molecular size from A to C
           • Increase in molecular size leads to increase in the strength of the London
             forces/Dispersion forces/Induced dipole forces
           • Relate the strength of London forces /dispersion forces/induced dipole to
             energy involved.
           Nasienkriteria
           • Toename in molekulêre grootte vanaf A na C
           • Toename in molekulêre grootte lei na ŉ toename in die sterkte van die
             Londonkragte/verspreidingskragte/geїnduseerde dipoolkragte
           • Verwys die sterktes van Londonkragte/Verspreidingskragte/
             Geїnduseerde dipoolkragte met energie betrokke.

           From A to C / Vanaf A na C
           • Surface area/molecular size/chain length increases 
           • Strength of London forces/dispersion forces/induced dipole forces
              increases 
           • More energy is needed to overcome intermolecular forces 

           • Oppervlakte/molekulêre grootte/kettinglengte neem toe
           • Sterkte van die Londonkragte/verspreidingskragte/geїnduseerde
             dipoolkragte neem toe
           • Meer energie word benodig om die intermolekulêrekragte te oorkom

                                              OR/OF

           Marking criteria
           • Decrease in molecular size from C to A
           • Decrease in molecular size leads to decrease in the strength of the
             London forces/dispersion forces/induced dipole forces
           • Relate the strength of London forces to energy involved.
           Nasienkriteria
           • Afname in molekulêre grootte vanaf C na A
           • Afname in molekulêre grootte lei na ŉ afname in die sterkte van die
             Londonkragte/verspreidingskragte/geїnduseerde dipoolkragte
           • Verwys die sterktes van Londonkragte/verspreidingskragte/
             geїnduseerde dipoolkragte met energie betrokke

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6                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                (EC/JUNE/JUNIE 2023)

       From C to A / Vanaf C na A

       • Surface area/molecular size/chain length decreases 
       • Strength of London forces/Dispersion forces/Induced              dipole    forces
         decreases 
       • Less energy needed to overcome intermolecular forces 

       • Oppervlakte/ molekulêre grootte/ kettinglengte neem af
       • Sterkte van Londonkragte/verspreidingskragte/geїnduseerde dipoolkragte
         neem af
       • Minder energie word benodig om die intermolekulêrekragte te oorkom                      (3)

3.3    A / Propane / Propaan 

       Lowest melting point / Laagste smeltpunt                                                 (2)

3.4    3.4.1                                               Marking criteria/Nasienriglyne
                              H     H       H   H          • 4 Carbons in longest chain 
                                                                ½
                         H    C     C       C   C   H         4 koolstowwe in die langste
                                                                ketting ½
                              H             H   H          •    Whole structure correct 2/2 
                                                                Hele struktuur korrek 2/2
                              H     C       H

                                        H                                                        (2)

       3.4.2    LESS THAN / MINDER AS - 129 °C                                                  (1)

       3.4.3    Yes / Ja 
                Compounds C and D have the same molecular mass/chain isomers 
                Verbindings C en D het dieselfde molekulêremassa/ketting-isomere.                (2)

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                       7

3.5    Marking criteria
       • E has dipole-dipole forces
       • F has hydrogen bonds
       • Correctly compare the strength of hydrogen bonds to dipole-dipole forces
       • Relate the strength of the intermolecular forces to energy involved.
       Nasienkriteria
       • E het dipool-dipoolkragte
       • F het waterstofbindings
       • Vergelyk die sterkte van die waterstofbindings korrek aan die dipool-
         dipoolkragte
       • Verwys die sterktes van intermolekulêrekragte met energie betrokke

       •    F has hydrogen bonds  (and London forces)
       •    E has dipole-dipole forces  (and London forces)
       •    Hydrogen bonds are stronger than dipole-dipole forces 
       •    More energy is needed to overcome intermolecular forces in E 
       •    F het waterstofbindings (en Londonkragte)
       •    E het dipool-dipoolkragte (en Londonkragte)
       •    Waterstofbinding is sterker as dipool-dipoolkragte
       •    Meer energie word benodig om die intermolekulêrekragte te oorkom
                                           OR/OF

       Marking criteria
       • E has dipole-dipole forces
       • F has hydrogen bonds
       • Correctly compare the strength of hydrogen bonds to dipole-dipole forces
       • Relate the strength of the intermolecular forces to energy involved
       Nasienkriteria
       • E het dipool-dipoolkragte
       • F het waterstofbindings
       • Vergelyk die sterkte van die waterstofbindings korrek aan die dipool-
         dipoolkragte
       • Verwys die sterktes van intermolekulêrekragte met energie betrokke

        •   F has hydrogen bonds  (and London forces)
        •   E has dipole-dipole forces  (and London forces)
        •   Dipole-dipole forces are weaker than hydrogen bonds 
        •   Less energy is needed to overcome intermolecular forces in F 

        •   F het waterstofbindings (en Londonkragte)
        •   E het dipool-dipoolkragte (en Londonkragte)
        •   Dipool-dipoolkragte is swakker as waterstofbinding
        •   Minder energie word benodig om die intermolekulêrekragte in F te oorkom            (4)
                                                                                              [16]

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8                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                          (EC/JUNE/JUNIE 2023)

QUESTION 4/VRAAG 4

4.1    4.1.1   Alcohol / Alkohol                                                                         (1)

       4.1.2   (Mild) heat / dilute base / (Matige) hitte / verdunde basis                               (1)

       4.1.3   H2O/KOH/NaOH/LiOH                                                                         (1)

       4.1.4   Dehydration/Dehidrasie / dehidratering/dehidrerend                                        (1)

       4.1.5                              Marking criteria/Nasienkriteria: Organic compounds only
                                          • Functional group/Funksionele groep.  1/2

                                          •   Whole structure correct/
                                              Hele struktuur korrek              2/2

                        H     H  H                                           H      H    H
                                                        Conc H2SO4                       
                    H    C   C        C O        H                           C     C    C      H

                        H     H       H                                       H      H     H

                          + H2O                                                                          (6)

       4.1.6    Addition  or halogenation and hydrohalogenation 
                Addisie of halogenering en hidrohalogenering                                              (1)

       4.1.7    HBr                                                                                      (1)

       4.1.8    1,2-dibromopropane                   Marking criteria/Nasienkriteria
                1,2-dibromopropaan                     • Functional group (2 Br
                                                          atoms)/Funksionele groep.  1/2
                                                       • Whole structure correct/
                                                          Hele struktuur korrek       2/2
                                  Br  Br       H

                         H        C       C     C     H

                                  H       H     H
                                                                                                          (4)
4.2    4.2.1    Breaking down of long chain hydrocarbon molecules into more useful
                shorter chains  (2 or 0)

                Afbreek van langer koolwaterstof-molekules in korter meer gebruikbare
                molekules (2 of 0)                                                                        (2)

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                        9

         4.2.2     Marking criteria/Nasienkriteria:
                   • Identifying compound Q / Identifisering van verbinding Q
                   • Identifying CxH6 / Identifisering van CxH6
                   • Identifying compound P / Identifisering van verbinding P
                   • Reactants / Reaktanse
                   • Products / Produkte
                   • Balancing / Balansering

                   Q = C2H4 
                   CxH6 = C3H6 
                   P = C8H18 

                   2 C8H18     + 25 O2           16 CO2 + 18H2O           Bal.              (6)
                                                                                              [24]

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10                  PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                (EC/JUNE/JUNIE 2023)

 QUESTION 5/VRAAG 5

 5.1    Marking criteria/Nasienkriteria
        If any of the underlined key words/phrases in the correct context are omitted:
        - 1 mark per word/phrase.
        Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
        word: - 1 punt per woord/frase

        ANY ONE
        Change in concentration ✓of reactant or product per (unit) time. ✓

        Change in amount/number of moles/volume/mass ✓of products or reactants
        per (unit) time. ✓

        Change in amount/number of moles/volume/mass ✓ of products formed or
        reactants used reactants per (unit) time. ✓

        ENIGE EEN
        Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd.

        Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of
        produkte per (eenheid) tyd.

        Verandering in hoeveelheid/getal mol/volume/massa van produkte
        gevorm/reaktanse gebruik per (eenheid) tyd.

                                            OR/OF

        The rate of change in concentration/amount of moles/number of moles /
        volume / mass. ✓✓ (2 or 0)

        Die tempo van verandering in konsentrasie/hoeveelheid mol/getal
        mol/volume/massa ✓✓ (2 of 0)                                                          (2)

 5.2    Marking criteria /Nasienkriteria
        Both variables correctly identified/ Beide veranderlike korrek geïdentifiseer
        (1/2)
        Question relates dependent and independent variables/ Vraag toon die
        verband tussen die afhanklike en onafhanklike veranderlike (1/2)

        What is the relationship between concentration and reaction rate? ✓✓
        OR How does concentration affect reaction rate?

        Wat is die verhouding tussen konsentrasie en reaksietempo? OF
        Hoe affekteer konsentrasie die reaksietempo?                                          (2)

 5.3    Sulphur / Swawel                                                                     (1)

 5.4    There must be ONE independent variable ✓/ The size of the cross is a control
        variable
        Daar moet slegs EEN onafhanklike veranderlike wees. / Die grootte van die
        kruis is ŉ beheerde veranderlike.                                            (1)

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                       11

5.5    Higher concentration
       • More particles per unit volume 
       • More particles collide with correct orientation 
       • Frequency of effective collisions increases /More effective collisions per
         unit time 

       Hoër konsentrasie
       • Meer deeltjies per eenheid volume
       • Meer deeltjies bots teen die korrekte oriëntasie
       • Frekwensie vir effektiewe botsings neem toe/Meer effektiewe botsings per
         eenheid tyd
                                          OR/ OF
       Lower concentration
       • Fewer particles per unit volume 
       • Fewer particles collide with correct orientation 
       • Frequency of effective collisions decreases/Fewer effective collisions per
          unit time 

       Lae konsentrasie
       • Minder deeltjies per eenheid volume
       • Minder deeltjies bots teen die korrekte oriëntasie
       • Frekwensie vir effektiewe botsings neem af/Minder effektiewe botsings per
           eenheid tyd                                                                          (3)

5.6    Marking criteria/Nasienkriteria
       • Reading the correct concentration of Na2S2O3/Korrekte lesing van die
          konsentrasie van Na2S2O3
       • Subst. into/Vervanging in n = cV
       • Using the mol ratio/Gebruik van mol verhouding Na2S2O3 : S
       • Formula/Formule m = nM
       • Subst. into/Vervanging m = nM
       • Final answer/Finale antwoord

       c (Na2S2O3) = 0,125 mol·dm-3 

       n(Na2S2O3) = cV
                   = 0,125 x 50/1000 
                   = 6,25 x 10-3 mol
       n(Na2S2O3) = n(S) = 6,25 x 10-3 mol 
        m = nM 
         = 6,25 x 10-3 x 32 
         = 0,2 g                                                                               (6)

5.7    5.7.1     Number of particles/molecules / Aantal deeltjies/molekules                    (1)

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12                  PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2            (EC/JUNE/JUNIE 2023)

      5.7.2                                          Marking criteria / Nasienkriteria
                                                        •   Shape of / Vorm van B
                                                        •   Peak of B lower / Piek van B
                                        A                   laer 
                   Q
                                                     NOTE: A or B must be indicated
                                             B
                                                        LET WEL: A of B moet aangedui
                                                        word
                       Kinetic energy / Kinetiese energie                                          (2)
                                                                                                  [18]

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(EC/JUNE/JUNIE 2023)            PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                       13

QUESTION 6/VRAAG 6

6.1    Marking criteria/ Nasienkriteria
       If any of the underlined key words/phrases in the correct context are omitted:
       - 1 mark per word/phrase.
       Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat
       word: - 1 punt per woord/frase

       When the equilibrium in a closed system is disturbed, the system will re-instate
       a new equilibrium by favouring the reaction that will oppose the
       disturbance. 

       Wanneer die ewewig in ŉ geslote sisteem versteur word, sal die sisteem ŉ
       nuwe ewewig instel deur die reaksie te bevoordeel wat die versteuring
       teenwerk.                                                                                (2)

6.2    Closed system / container / Geslote sisteem/houer                                       (1)

6.3    6.3.1      OPTION 1: MOLE CALCULATIONS/
                  a.   Substitute into n = m/M ✓
                  b.   Determine Δn = 2x ✓
                  c.   Correct ratio PCℓ5 : PCℓ3 : Cℓ2 ✓
                  d.   Divide the equilibrium md by 2 dm3 ✓
                  e.   Correct KC expression (formulae in square brackets) ✓
                  f.   Substitution into the correct equilibrium expressions (KC) ✓

                  OPSIE 1: MOL BEREKENINGE
                  a.   Vervanging n = m/M ✓
                  b.   Bepaal Δn = 2x ✓
                  c.   Korrekte verhouding PCℓ5 : PCℓ3 : Cℓ2 ✓
                  d.   Deel deur 2 dm3 ✓
                  e.   Korrekte Kc uitdrukking (formule met viekant hakkies) ✓
                  f.   Vervanging in korrekte Kc uitdrukking ✓

                                m
                   n        =
                                M

                                 83,4
                   n        =             (a) ✓
                                208,5

                   n    =       0,4 mol

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14                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                           (EC/JUNE/JUNIE 2023)

          Δn (PCℓ5) = (x)(2) = 2x ✓ (b)
                                           PCℓ5                    PCℓ3                     Cℓ2
           Initial mol                      0,4                                               -

           Change in mol                    -2x                    +2x                       2x       ✓ (c)
           Equilibrium mol                 0,4-2x                   2x                      2x
                                         0,4-2x / 2                2x / 2                  2x / 2 ✓ (d)
           Concentration
                                          0,2 – x                    x                        x

                          [PCℓ3][ Cℓ2]
             Kc     =                        (e) ✓
                             [PCℓ5]

                              (x)(x)
             Kc     =                        (f) ✓
                            (0,2 – x)

                               x2
             Kc     =
                             0,2 - x                                                                          (6)

        6.3.1     OPTION/OPSIE 2: CONCENTRATION
                  CALCULATIONS/KONSENTRASIE BEREKENINGE
                  a. Substitute into n = m/M ✓
                  b. Substitute into c = n/V ✓
                  c. Correct ratio PCℓ5 : PCℓ3 : Cℓ2 ✓
                  d. Equilibrium conc correct ✓
                  e. Correct KC expression (formulae in square brackets) ✓
                  f. Substitution into the correct equilibrium expressions (KC) ✓

                  n = m/M
                     = 83,4/208,5 (a) ✓
                     = 0,4 mol
                  ci (PCℓ5) = n/V
                            = 0,4/2 (b) ✓
                            =0,2 mol.dm-3

                                                  PCℓ5                   PCℓ3                 Cℓ2
                   Initial                                                                        -
                                                    0,2
                   concentration
                   Change in                                              +x                          ✓ (c)
                                                      -x                                          x
                   concentration
                   Equilibrium                                                                    x   ✓ (d)
                                                  0,2-x                   x
                   concentration

                                 [PCℓ3][ Cℓ2]
                     Kc      =                         (e) ✓
                                    [PCℓ5]

                                     (x)(x)
                     Kc      =                             (f) ✓
                                   (0,2 – x)

                                         x2
                     Kc      =
                                       0,2 – x

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(EC/JUNE/JUNIE 2023)              PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                   15

       6.3.2     Marking criteria/Nasienkriteria
                 • Determine the value of x / Bepaal die waarde van x
                 • Subst. into Kc expression / Vervanging in Kc uitdrukking

                 0,2 – x = 0,001 

                 x = 0,1999

                 Kc = x2/ (0,2 – x)

                       = 0,1992/(0,001) 

                       = 39,601                                                                 (2)

       6.3.3     HIGH YIELD / HOЁ OPBRENGS 

                 Kc > 1/ Kc is large / groot                                                   (2)

6.4    6.4.1     NO EFFECT/ GEEN EFFEK                                                         (1)

       6.4.2     DECREASES / VERLAAG                                                           (1)

6.5    6.5.1     Equilibrium/ Stage where rate of forward reaction equals rate of reverse
                 reaction 

                 Ewewig / die plek waar die tempo van die voorwaartse reaksie gelyk is
                 aan die tempo van die terugwaartse reakse.                                     (1)

       6.5.2     HEATED / VERHIT                                                               (1)

       6.5.3     • Increase in temperature favours the endothermic reaction. 
                 • Concentration of PCℓ5 decreases while concentration of Cℓ2
                   increases 
                 • The forward reaction was favoured/ equilibrium position shifted
                   towards the right 

                 • Toename in temperatuur bevoordeel die endotermiese reaksie.
                 • Konsentrasie PCℓ5 neem af terwyl die konsentrasie van Cℓ2 toe
                   neem
                 • Die voorwaartse reaksie word bevoordeel/ ewewigsposisie verksuif
                   regs.                                                                        (3)
                                                                                               [20]

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16                  PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2             (EC/JUNE/JUNIE 2023)

 QUESTION 7/VRAAG 7

 7.1 7.1.1     A substance that forms hydrogen ions (H+)/ hydronium ions (H3O+) in
               water 
               ŉ Stof wat waterstofione (H+)/hydroniumione (H3O+) in water vorm              (2)

       7.1.2   Good electrical conductor / Inert 
               Goeie elektriese geleidingsvermoë / Inert                                     (1)

       7.1.3   CH3COOH 
               Higher ammeter reading / Hoër ammeterlesing
               Undergoes higher degree of ionisation / Ondergaan ŉ hoër graad van
               ionisasie 
               Higher concentration of ions in solution / Hoër konsentrasie van ione
               in die oplossing                                                             (3)

       7.1.4   H2O and/ en HCO3̄                                                           (2)

       7.1.5   CO32-                                                                        (1)

 7.2 7.2.1     Reaction of a salt with water  (2 or 0)
               Reaksie van ŉ sout met water (2 of 0)                                         (2)

       7.2.2   ACIDIC / SUUR 

               NH4+     + H2O           NH3 + H3O+ 

               (reactants and products) / (reaktanse en produkte)

               Excess H3O+ are formed / Oormaat H3O+ vorm                                   (4)

 7.3 7.3.1     pH = - log [H3O+] 
                  = - log 1 
                  =0                                                                        (3)

       7.3.2   n = cV 
                 = 1 x 250/1000 
                 = 0,25 mol                                                                 (3)

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### Page 17

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                      17

         7.3.3 Positive marking from 7.3.2/ Positiewe nasien vanaf 7.3.2
               Marking criteria/Nasienkriteria
               • Formula / Formule n = cV
               • Subst. of NaOH conc. and vol. into/ Vervanging van NaOH kons. En
                 vol. in n = cV
               • Mol ratio / Mol verhouding NaOH : HCℓ
               • Subtract initial mol (from 7.3.2) from mol reacting with NaOH /
                 Aftrek van aanvanklike mole (vanaf 7.3.2) van regerende mol NaOH
               • Mol ratio / Mol verhouding CaCO3 : HCℓ
               • Subst. into / Vervanging in m = nM for CaCO3
               • Multiply mass of/ Vermenigvuldig massa van CaCO3 by/met
                 100/99,3
               • Final answer/ Finale antwoord

                 n(NaOH) = cV 
                         = 0,5x 103/1000 
                         = 0,0515 mol

                 n (HCℓ reacting with / reageer met NaOH) = 0,0515 mol 

                 n (HCℓ reacting with / reageer met CaCO3) = 0,25 – 0,0515 

                 n (HCℓ reacting with / reageer met CaCO3) = 0,1985 mol

                 n(CaCO3) = ½ (0,1985) 

                 n(CaCO3) = 0,09925 mol

                 m(CaCO3)= nM
                         = 0,0925 x 100 
                         = 9,925 g

                 m = 9,925 x 100/99,3 

                 m = 9,99 g 
                 (RANGE / GEBIED: 9,99 to 10,07 g)                                            (8)
                                                                                             [29]

                                                                     TOTAL/TOTAAL: 150

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