# Physical Sciences Grade 12 P2 Eastern Cape June 2021 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape June 2021, 15 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physc-grd-12-p2-memo-june2021-eng-afr/76bfa660-e3c5-4ac4-9979-617cff5e3af9
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2021
- Exam period: Eastern Cape June
- Paper: 2
- Curriculum: CAPS
- Pages: 15

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Physical Sciences · Grade 12 · Eastern Cape June · 2021. Memorandum, 15 pages. Read online or download the PDF.

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### Page 1

NATIONAL SENIOR
                          CERTIFICATE/
                        NASIONALE SENIOR
                          SERTIFIKAAT

                          GRADE/GRAAD 12

                          JUNE/JUNIE 2021

         PHYSICAL SCIENCES: CHEMISTRY P2
                MARKING GUIDELINE/
         FISIESE WETENSKAPPE: CHEMIE V2
                  NASIENRIGLYN
             (EXEMPLAR/EKSEMPLAAR)

MARKS/PUNTE:   150

                     This marking guideline consists of 15 pages./
                      Hierdie nasienriglyn bestaan uit 15 bladsye.

### Page 2

2                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2          (EC/JUNE/JUNIE 2021)

QUESTION 1/VRAAG 1

1.1    D ✓✓                                                                           (2)

1.2    D ✓✓                                                                           (2)

1.3    A ✓✓                                                                           (2)

1.4    C ✓✓                                                                           (2)

1.5    C ✓✓                                                                           (2)

1.6    D ✓✓                                                                           (2)

1.7    B ✓✓                                                                           (2)

1.8    B ✓✓                                                                           (2)

1.9    B ✓✓                                                                           (2)

1.10   C ✓✓                                                                          (2)
                                                                                    [20]

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(EC/JUNE/JUNIE 2021)             PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                              3

QUESTION 2/VRAAG 2

2.1     2.1.1          Homologous series ✓
                       Homoloë reeks                                                                   (1)

        2.1.2          Unsaturated. ✓
                       Contains a triple bond ✓/multiple bonds
                       Onversadig
                       Bevat driedubbelbinding/veelvoudige bindings                                    (2)

        2.1.3          C5H9 ✓                                                                          (1)

        2.1.4          5-ethlyl ✓ -2-methyl ✓ hex-3-yne ✓
                       OR 5-ethlyl-2-methyl-3-hexyne          Marking Criteria/Nasien-
                       5-etiel-2-metielheks-3-yn                      kriteria
                       OF 5-etiel-2-metiel-3-heksyn
                                                                    •    Hexyne ✓
                                                                         heksyn
                                                                    •    Side chains (ethyl
                                                                         and methyl) ✓
                                                                    •    Syketting
                                                                         (etiel en metiel)
                                                                    •    Whole name
                                                                         correct ✓
                                                                         Volledige naam
                                                                         korrek
                                                                                                       (3)

        2.2.1                                                Marking criteria/Nasien-
                                               H             kriteria
                                                   ✓
                                 H      H      O                •       Functional group
                                                                        correct (1/2)
                         H      C       C      C        H✓
                                                                        Funksionele groep
                                 H      H      H                        korrek (1/2)
                                                                •       Whole structure
                                                                        correct (2/2)
                                                                        Volle struktuur
                                                                        korrek (2/2)
                                                                                                       (2)

        2.2.2          (Mild) heat ✓ in a water bath ✓
                       (Matige) hitte in ŉ waterbad                                                    (2)

        2.2.3          Esterification/ Condensation ✓
                       Esterifikasie/kondensasie                                                       (1)

        2.2.4          H2SO4 ✓                                                                         (1)

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4                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2              (EC/JUNE/JUNIE 2021)

       2.2.5                                          Marking
                                                      criteria/Nasien riglyne
                         O         H    H   H
                             ✓
                                                       • Functional group
                    H    C    O    C    C   C   H ✓      correct (1/2)
                                                         Funksionele groep
                                   H    H   H
                                                         (1/2)
                                                       • Whole structure
                                                         correct (2/2)
                                                         Volle struktuur
                                                         korrek (2/2)
                                                                                            (2)

2.3    2.3.1      Compounds with the same molecular formula. ✓
                  but different structural formula. ✓

                  Verbindings met dieselfde molekulêre formule maar verskillende
                  struktuurformule.                                                         (2)

       2.3.2      The C atom bonded to Br is bonded to one other C atom ✓✓ OR
                  The C atom bonded to Br is bonded to two hydrogen atoms
                  Die C atoom wat aan die Br gebind is, is aan een ander C atom
                  gebind
                                               OF
                  Die C atoom gebind aan die Br is aan twee waterstofatome
                  gebind.                                                                   (2)

       2.3.3      1-bromo-2-methylpropane ✓✓✓
                  1-bromo-2-metielpropaan             Marking Criteria/Nasien-
                                                              kriteria

                                                       • Propane ✓
                                                         Propaan
                                                       • (bromo and methyl) ✓
                                                         (bromo en metiel)
                                                       • Whole name correct ✓
                                                         Volle naam korrek
                                                                                            (3)
                                                                                           [22]

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(EC/JUNE/JUNIE 2021)           PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                        5

QUESTION 3/VRAAG 3

3.1       The temperature at which the vapour pressure of a liquid equals the
          atmospheric pressure. ✓✓

          Die temperatuur waarteen die dampdruk van ŉ vloeistof gelyk is aan die
          atmosferiese druk.                                                                (2)

3.2       A ✓ Compound A has the lowest boiling point. ✓

              Verbinding A het die laagste kookpunt.                                        (2)

3.3.1     Molar mass/ Molecular size/ Surface area ✓
          Molêre massa/ Molekulêre grootte/Oppervlakte                                      (1)

3.3.2     Hydrogen bond ✓
          Waterstofbinding                                                                  (1)

3.4       •   The molar mass/Molecular size/ surface area of the compounds
              increases from top to bottom in the table. ✓
          •   The compounds have London forces and (Hydrogen bonds) ✓
          •   The strength of London forces increases with an increase in molar
              mass/molecular size/surface area. ✓
          •   More energy is needed to overcome the intermolecular forces ✓

          •   Die molêre massa/molekulêre grootte/oppervlakte van die verbinding
              neem toe van bo na onder in die tabel.
          •   Die verbindings het Londonkragte en (waterstofbindings)
          •   Die sterkte in Londonkragte neem toe met ŉ toename in molêre
              massa/molekulêre grootte/oppervlakte
          •   Meer energie word benodig om die intermolekulêrekragte te oorkom              (4)

3.5.1
                                                           Marking criteria/Nasien
                           H
                                                           kriteria
                 H     H   C      H H                         •   3 Carbon atoms
                                                                  in longest chain
          H      C         C        C       O- H✓✓
                                                                  with correct
                                                                  functional group
                 H         H            H
                                                                  3 koolstofatome
                                                                  in die langste
                                                                  ketting en
                                                                  korrekte
                                                                  funksionele groep
                                                                                            (2)
                                                              •   Whole structure
                                                                  correct(2/2)
3.5.2     B ✓ It has the same molecular formula ✓
             Dit het dieselfde molekulêre formule                 Volle struktuur           (2)
                                                                  korrek (2/2)

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6                   PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2            (EC/JUNE/JUNIE 2021)

3.5.3    Lower than ✓
         Laer as.                                                                         (1)

3.5.4    •   2-methylpropan-1-ol has a smaller surface area than butan-1-ol. ✓
         •   Both compounds have London forces and (hydrogen bonds) ✓
         •   2-methylpropan-1-ol have weaker London forces than butan-1-ol ✓
         •   Less energy is needed to overcome the intermolecular forces in
             2-methylpropan-1-ol ✓

         •   2-metielpropan-1-ol het ŉ Kleiner oppervlakte as butan-1-ol
         •   Beide verbindings het Londonkragte en (waterstofbinding)
         •   2-metielpropan-1-ol het swakker Londonkragte as butan-1-ol
         •   Minder energie word benodig om die intermolekulêrekragte in
             2-metielpropan-1-ol te oorkom

                                          OR/OF

         •   Butan-1-ol has a larger surface area than 2-methylpropan-1-ol ✓
         •   Both compounds have London forces and (hydrogen bonds) ✓
         •   Butan-1-ol have stronger Londonforces than 2-methylpropan-1-ol ✓
         •   More energy is needed to overcome the intermolecular forces in
             butan-1-ol ✓

         •   Butan-1ol het ŉ groter oppervlakte as 2-metielpropan-1-ol
         •   Beide verbindings het Londonkragte en (waterstofbinding)
         •   Butan-1-ol ol het sterker Londonkragte as 2-metielpropan-1-ol
         •   Meer energie word benodig om die intermolekulêrekragte in butan-1-ol
             te oorkom                                                                    (3)

3.6      •   Methanoic acid and propan-1-ol have both Hydrogen bond and
             (London forces) ✓
         •   Methanoic acid have two sites for hydrogen bonds while
             propan-1-ol have only one site for hydrogen bonds. ✓
         •   Methanoic acid has stronger intermolecular forces than
             propan-1-ol ✓
         •   More energy is needed to overcome the intermolecular forces in
             methanoic acid. ✓

         •   Metanoësuur en propan-1-ol het beide waterstofbinding en
             (Londonkragte)
         •   Metanoësuur het twee plekke vir waterstofbinding terwyl
             propan-1-ol slegs een plek het vir waterstofbinding
         •   Metanoësuur het sterker intermolekulêrekragte as propan-1-ol
         •   Meer energie word benodig om die intermolekulêrekragte te oorkom
             metanoësuur

                                          OR/OF

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(EC/JUNE/JUNIE 2021)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                        7

          •   Methanoic acid and propan-1-ol have both Hydrogen bond and
              (London forces) ✓
          •   Methanoic acid have two sites for hydrogen bonds while
              propan-1-ol have only one site for hydrogen bonds. ✓
          •   Propan-1-ol has weaker intermolecular forces than
              methanoic acid ✓
          •   Less energy is needed to overcome the intermolecular forces in
              propan-1-ol. ✓

          •   Metanoësuur en propan-1-ol het beide waterstofbinding en
              (Londonkragte)
          •   Metanoësuur het twee plekke vir waterstofbinding terwyl
              propan-1-ol slegs een plek het vir waterstofbinding
          •   Propan-1-ol het swakker intermolekulêrekragte as metanoësuur
          •   Minder energie word benodig om die intermolekulêrekragte te oorkom
              in propan-1-ol                                                              (4)
                                                                                         [22]

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8                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2              (EC/JUNE/JUNIE 2021)

QUESTION 4/VRAAG 4

4.1    Process of breaking down long chain hydrocarbons ✓/alkanes into
       smaller more useful chains ✓
       Proses van opbreek van lang ketting koolwaterstowwe/alkane na kleiner
       meer bruikbare kettings                                                                (2)

4.2    4.2.1         C4H10 ✓✓                                                                 (2)

       4.2.2         HIGH TEMPERATURE ✓ OR HIGH PRESSURE
                     HOË TEMPERATUUR OF HOË DRUK                                              (1)

4.3    4.3.1         Substitution ✓
                     Substitusie                                                              (1)

       4.3.2         Elimination ✓
                     Eliminasie                                                               (1)

4.4    Hydrogenation ✓
       Hidrogenasie                                                                           (1)

4.5    4.5.1         Br2/Bromine ✓
                     Br2/ Broom                                                               (1)

       4.5.2         Pt/Ni/Pd/Platinum/Nickel/Palladium ✓
                     Pt/Ni/Pd / Platinum/Nikkel/ Palladium                                    (1)

4.6    CH3CH2CH2CHBr ✓✓+ KOH                    CH3CH = CHCH3 ✓✓ + KBr + H2O
                 Marking criteria/Nasienkriteria
                 •      Organic reactant ✓✓
                        Organiese reaktant
                 •      Organic product ✓✓
                        Organiese produk
                 •      ALL Inorganic reagents correct ✓ (KOH, KBr and
                        H2O)
                        ALLE anorganiese reagense korrek (KOH, KBr
                        en H2O
                                                                                              (5)
                                                                                             [15]

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(EC/JUNE/JUNIE 2021)            PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                       9

QUESTION 5/VRAAG 5

5.1     Change in concentration (of reactant/products) per unit time ✓✓
        Verandering in konsentrasie (van reaktante/produkte) per eenheidstyd

                                             OR/OF

        Amount/Volume/Mass of reactant/product used/formed per unit time
        Hoeveelheid/volume/Massa van reaktante/produkte gebruik/gevorm per
        eenheidstyd                                                                            (2)

5.2     RELEASED ✓
        VRYGESTEL
        ΔH < 0 ✓/Energy of products is less than the energy of reactants/
        Reaction exothermic
        ΔH < 0/ Energie van produkte is minder as die energie van die reaktante/
        Reaksie is eksotermies                                                                 (2)

5.3     5.3.1          INCREASES ✓
                       VERHOOG                                                                 (1)

        5.3.2          NO EFFECT ✓
                       GEEN EFFEK                                                              (1)

5.4     5.4.1          After 120 s ✓
                       Na 120 s                                                                (1)

        5.4.2          Concentration (of HCℓ) ✓ Surface area (of Zinc) ✓ OR
                       temperature
                       Konsentrasie (van HCℓ) Oppervlak (van Sink) OF temperatuur              (2)

5.5     5.5.1          Rate / Tempo = Δv/Δt= 300 -0✓ /120 – 0 ✓= 2,50 cm3∙s-1 ✓                (3)

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10                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2             (EC/JUNE/JUNIE 2021)

       5.5.2      n=V/Vm ✓         OR/OF                   pV = nRT
                  n= 250 × 10-3 ✓ (101,3×103)(250×10-6) = n (8,31)(20+273)✓
                       24
                  n= 0,01 mol H2 produced/geproduseer n = 0,01 mol H2
                  produced/geproduseer
                                               NOTE/LET WEL:
                  Mole ratio            HCℓ: H2    If the above formula was
                  Mol verhouding         2 :1      used to calculate the mole
                                                   of H2 then award formula
                  n((HCℓ) = 2 n (H2)               mark for m= nM
                  n((HCℓ) = 2(0,01) ✓
                  n((HCℓ) = 0,02 mol reacted       As die bostaande formule
                                                   gebruik was om die mol van
                                                   H2 te bereken, dan die
                                                   toekenningsformule- punt
                                                   vir m=nM
                  Mole Option/ Mol Opsie            Mass Option/Massa Opsie

                  n= cV                                m = nM
                  n = (0,5)( 50×10-3) ✓                m = (0,02)(36,5) ✓
                  n = 0,025 mol initially              m = 0,73 g reacted
                             aanvanklik                          reageer

                  n (left) = n (initially) – n (reacted) m = cMV
                  n (left) = 0,025 – 0,02 ✓             m = (0,5)(36,5)(50×10-3) ✓
                  n (left) = 0,005 mol                   m = 0,9125 g initially

                  m = nM                               m(left) = m (i) – m (r)
                  m = (0,005)(36,5) ✓                  m (left) = 0,9125 – 0,73 ✓
                  m = 0,1825 g ✓                       m (left) = 0,1825 g ✓                  (7)

5.6    5.6.1      Catalyst ✓ OR Increases reaction rate
                  Katalisator OF Toename in reaksie-tempo                                     (1)

       5.6.2       •     Catalyst lowers activation energy/provides an
                         alternative path of lower activation energy ✓
                         Katalisator verlaag die aktiveringsenergie/ bied ŉ
                         alternatiewe pad van laer aktiveringsenergie
                   •     More particles have sufficient Ek OR more particles
                         have Ek>Ea ✓
                         Meer deeltjies het genoeg Ek OF meer deeltjie het Ek>Ea
                   •     More effective collisions per unit time/Frequency of
                         effective collisions increase ✓✓
                         Meer effektiewe botsings per eenheidstyd/ Frekwensie
                         van die effektiewe botsings neem toe                                 (4)
                                                                                             [24]

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(EC/JUNE/JUNIE 2021)             PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                      11

QUESTION 6/VRAAG 6
6.1     Reaction in which products can be converted back to reactants ✓✓
        (2 or 0)
        Reaksie waarin produkte terug na reaktante oorgeskakel word (2 of 0)                    (2)
6.2     6.2.1      Decreases ✓
                   Verlaag                                                                      (1)
        6.2.2      Increases ✓
                   Verhoog                                                                      (1)
6.3     •    (When the temperature is decreased) the exothermic reaction is
             favoured ✓
        •    Forward reaction is favoured ✓
             (Wanner die temperatuur verlaag) word die eksotermiese reaksie
             bevoordeel
             Voorwaartse reaksie word bevoordeel                                                (2)

6.4     CALCULATION USING MOLES/BEREKENINGE DEUR MOL TE
        GEBRUIK
        Marking guideline/Nasienriglyn
        •    Formula/formule n=m/M
        •    Substitution of/Substitusie van 28 g∙mol-1
        •    Use of ratio/Gebruik van verhouding N2:H2:NH3
        •    Equilibrium amounts of N2 and H2 formed/ Ewewigshoeveelheid van N2
             en H2 gevorm
        •    Division n equilibrium of N2, H2 and NH3 by 2 / Deel van n ewewig van N2, H2
             en NH3 deur 2
        •    Correct Kc expression/Korrekte Kc uitdrukking
        •    Substitution into Kc expression/substitusie in Kc uitdrukking
        •    Final answer/Finale antwoord

        n = m/M ✓
          = 7,84/28 ✓
          = 0,28 mol

                        N2   +      3 H2   ⇋    2 NH3

        ni (mol)        0,28         0,6       0
        Δn (mol)        0,06         0,18      0,12 Ratio ✓/Verhouding
        ne (mol)        0,22         0,42 ✓    0,12
        ce              0,22/2       0,42/2    0,12/2 Division by 2 ✓/Deel met 2
        (mol∙dm-3)      =0,11        0,21      0,06

        Kc = [NH3]2/[N2].[H2]3 ✓

             = 0,062/(0,11 x 0,213) ✓

             = 3,53 ✓

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12                  PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2               (EC/JUNE/JUNIE 2021)

       CALCULATION USING CONCENTRATION/BEREKENIGE DEUR
       GEBRUIK TE MAAK VAN KONSENTRASIE
       Marking guidelines/ Nasienriglyne
       •   Formula / Formule c=m/MV or c=n/v
       •   Substitution into/ Substitusie in c=m/MV or c=n/V
       •   Dividing by 2 for all concentration/ Deel deur 2 vir alle konsentrasies
       •   Use of ratio/ Gerbuik van verhoudings N2:H2:NH3
       •   Equilibrium concentrations of/ Ewewig konsentrasies van N2, H2 and
           NH3
       •   Correct Kc expression/Korrekte Kc uitdrukking
       •   Substitution into Kc expression/ Substitusie in Kc uitdrukking
       •   Final answer /Finale antwoord
                                ✓ (Any one/Enige een)
       c (N2) = m/MV            c (H2) = n/V          c (NH3) = n/V
       c (N2) = 7,84/(28)(2) ✓ c (H2) = 0,6/2           c (NH3) = 0,12/2
       c (N2) = 0,14 mol∙dm  -3 c (H2) = 0,3 mol∙dm c (NH3) = 0,06 mol∙dm-3
                                                   -3

       (dividing by/deel van 2) ✓
                     N2    + 3 H2 → 2 NH3
       ci            0,14        0,3   0
       Δc            -0,03      -0,9  +0,06 ratio ✓/verhouding
       ceq           0,11        0,21  0,06 ✓

       Kc = [NH3]2/[N2]∙[H2]3 ✓

           = 0,062/(0,11 x 0,213) ✓

           = 3,53 ✓                                                                        (8)

6.5    As pressure increases percentage yield increases. ✓✓
       As die druk toeneem, neem die persentasie opbrengs toe.                             (2)

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(EC/JUNE/JUNIE 2021)           PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                        13

6.6     MOLE OPTION / MOLOPSIE

        Ratio/Verhouding N2 : H2        Ratio/Verhouding N2 : H2
                              1: 3                          1 :3
        n(H2) = 3 (0,28) ✓                    n(N2) = 1/3 (0,6)
        n(H2) = 0,84 mol of H2 needed        n(N2) = 0,2 mol of N2 needed
        only 0,6 mol of H2 is available      0,28 mol of N2 is available

        0,84 mol van H2 word benodig          0,2 mol N2 word benodig
        Slegs 0,6 mol van H2 is beskikbaar    0,28 mol N2 is beskikbaar
        ∴ H2 is the limiting reagent ✓       ∴ H2 is the limiting reagent
        ∴H2 is die beperkende reagens          ∴ H2 is die beperkende reagens
        Theoretical yield/Teoretiese opbrengs = 0,6 x 2/3 = 0,4 mol ✓

        % Yield/Opbrengs = actual yield (werklike opbrengs)/theoretical
        yield(teoretiese opbrengs) × 100 %
                 = 0,12/0,4 x 100 ✓
                 = 30%
        Pressure / Druk= 100 (atmospheres/atmosfeer) ✓
        CONCENTRATION OPTION/KONSENTRASIE-OPSIE

             •    V is constant/V is konstant
             •    Concentration ratio    N2 : H2   Concentration ratio N2 : H2
                  Konsentrasie-verhouding 1: 3     Konsentrasie-verhouding
                                                                         1: 3
              c(H2) = 3 (0,14) ✓                       c(N2) = 1/3 (0,3)
              c(H2) = 0,42 mol∙dm-3 of H2 required     c(N2) = 0,1 mol∙dm-3
                                       H2 benodig
              only 0,3 mol∙dm-3 is available         0,14 mol∙dm-3 is available
              slegs 0,3 mol∙dm-3 is beskikbaar       0,14 mol∙dm-3 is beskikbaar

              ∴ H2 is the limiting reagent/is die beperkende reagens ✓

             Theoretical yield/teoretiese opbrengs = 0,3×2/3 ✓= 0,2 mol∙dm-3

                 % yield/opbrengs = actual yield (werklike opbrengs)/theoretical
                 yield/teoretiese opbrengs ×100 %
                 % yield/opbrengs = 0,06/0,2 ×100 % ✓
                 % yield/opbrengs = 30 %
                 Pressure/druk 100 (atmosphere/atmosfeer) ✓                                     (5)
                                                                                               [21]

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14                  PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                (EC/JUNE/JUNIE 2021)

QUESTION 7/VRAAG 7

7.1    7.1.1     Reaction of a salt with water ✓✓
                 Reaksie van ŉ sout met water                                                 (2)

       7.1.2     (Excess) Hydroxide/OH- ions are formed ✓
                 Hydroxide/ OH- is basic/alkaline ✓

                 (Oormaat) Hidroksied/ OH- ione word gevorm
                 Hidroksied/ OH- is basies/alkalies                                           (2)

       7.1.3     H2O ✓ and HCO3- ✓                                                            (2)

       7.1.4     HCO3- can accept a proton (H+) (to form H2CO3) ✓
                 HCO3- can donate a proton (H+) (to form CO32-) ✓

                 HCO3- kan ŉ proton (H+) aanvaar (om H2CO3 te vorm)
                 HCO3- kan ŉ proton (H+) skenk (om CO32- te vorm)                             (2)

7.2    7.2.1     Acid is a proton donor ✓✓
                 Suur is ŉ protonskenker                                                      (2)

       7.2.2     pH = - log [H3O+] ✓
                  1 = - log [H3O+] ✓
                 [H3O+] = 0,1 mol∙dm -3 ✓
                 [X] = 2 [H3O+]
                 [X] = 2(0,1)
                 [X] = 0,2 mol∙dm -3 ✓                                                        (4)

       7.2.3     It is a solution of known concentration ✓✓
                 Dit is ŉ oplossing met bekende konsentrasie.                                 (2)

       7.2.4     Bromothymol blue ✓
                 Acid X is a strong acid.
                 KOH is a strong base. ✓
                 There is no hydrolysis of the salt produced, therefore the
                 equivalence point of the titration would be within the range of
                 indicator. ✓

                 Broomtimolblou
                 Suur X is ŉ sterk suur.
                 KOH is ŉ sterk basis.
                 Daar is geen hidrolisereaksie van die sout wat vorm, dus sal
                 ekwivalente punt van die titrasie binne die grense van die indikator
                 wees.                                                                        (3)

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### Page 15

(EC/JUNE/JUNIE 2021)             PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                        15

        7.2.5          c1V1=c2V2
                       0,049 x 15 ✓ = c2 x 90 ✓
                       c2 = 8,17 ×10-3 mol∙dm-3

                       nAcid/suur = cV ✓
                       = 8,17 ×10-x 25×10-3 ✓
                       = 2,04×10-4 mol                  caVa/cb.Vb = na/nb ✓

                       n(KOH) = 2 x 2,04×10-4 ✓         8,17 ×10-3 x 25 ✓/ cb.28,5 ✓
                            = 4,08 x 10-4 mol           =½✓

                       c = n/V                          cb = 0,014 mol∙dm-3 ✓
                         = 4,08 x 10-4/ 28,5 x 10-3 ✓
                         = 0,014 mol∙dm-3 ✓                                                        (7)
                                                                                                  [26]

                                                                       TOTAL/TOTAAL:              150

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