# Physical Sciences Grade 12 Paper 1 NSC June 2013 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the NSC June 2013, 11 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/physical-science-bill-p1-hg-2013-memo/8307a6e5-2dc5-4bdb-8d5d-f16160258425
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2013
- Exam period: NSC June
- Paper: 1
- Curriculum: CAPS
- Pages: 11

Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 Paper 1 NSC June 2013 Memo](https://www.hlayiso.com/library/physical-science-bill-p1-hg-2013-memo/8307a6e5-2dc5-4bdb-8d5d-f16160258425)

## About this document

Physical Sciences · Grade 12 · NSC June · 2013. Memorandum, 11 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

Text extracted from the PDF. Layout, diagrams and tables may not survive extraction.

### Page 1

Downloaded from hlayiso.com

basic education

Department:
Basic Education
REPUBLIC OF SOUTH AFRICA

SENIOR CERTIFICATE EXAMINATION
SENIORSERTIFIKAAT-EKSAMEN

PHYSICAL SCIENCE P1
NATUUR- EN SKEIKUNDE V1

HIGHER GRADE/HOER GRAAD

2013
POSSIBLE ANSWERS

Copyright reserved/Kopiereg voorbehou Please turn over/Biaai om asseblief

### Page 2

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1_ 2 DBE/2013
SCE/SSE — Memorandum

QUESTION 1/ VRAAG 1

11. =D 12 A 13° A 14°C 15 °C
16 A 17, A 18 8B 19 C 110 C
111. B 412 A 113 B 114 C 115 B
(15x 4) (60)
QUESTION 2/ VRAAG 2
24
OR/OF

Vwina
VplaneMiegtuig

OR/OF

O marks if not a complete vector diagram / geen punte as die
vektordiagram nie volledig is nie.

Y Vres horizontal and direction to left / V res horisontaal en na links
YY plane in correct direction / V viiegtuig in korrekte rigting
Y V wind in correct direction /V wing in korrekte rigting

¥ 135 ° between V wing aNd V res / Hoek tussen V wing ANC V es . (4)

2.2.1 Positive marking from 2.1
Calc:

vv
sini35° _ sind ¥
200% 50”
sin6 = 0,177
@ =10,19° north of west “
OR 280,2°

(Or 10,18 °) (5)

Copyright reserved/Kopiereg voorbehou Please tum over/Blaai om asseblief

R |

### Page 3

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1_ 3 DBE/2013
SCE/SSE ~ Memorandum

2.2.2 Positive marking from 2.1

other angle of triangle = 180°-135°-10,2° = 34,8°
sin135 ¥ sin34,8”
200 Vres

. v
Vres = 161, 42 km.h*

OF /OR

Vres 2 = Vwind” + Vpiane 2 — (2x Vwind XVplanex COS 34,8) ¥
= (50)* + (200) ? — (2 x 50 x 200 x 0,8211) v
= 26077,016

Ves = 161,48 km.h ¥ (3)

Positive marking to 2.2.3

OR: 2.2 tana 2.22 v Measure 2 cm /meet 2 cm
Y must be 45° (135°) / moet 45°
v wees
8 cm (200 km.h”) v Measure 8 cm from Vwina; Meet 8
cm vanaf Vwing
¥ Complete triangle with

v
2 cm (60 km.h")

ar) Horizontal / voitooi driehoek met
— . 7 horisontale lyn
¥ completion of: R: 6,4cm+0,2cm Measure angle 6 = 10,2° Vv
triangle (156 - 166 km.h" )v North of west” /meethoek 0

= 10,2° noord van wes
(range 10,2° + 2°)
vv measure and convert
R = 161,5 km.h'/ meet en skakel
om R = 161,5 km.h"

(range 161,5 km.h't 5 km.h")

Note !

If no arrow for R, loose 1 mark .
Arrows for other 2 vectors not
necessary/indien geen py! vir R,
verloor 1 punt. Pyle_nie nodig vir
ander 2 vektore nie

Incorrect scale /verkeerde skaal
max 6/8

(8)

Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

A f

### Page 4

Physical Science/Natuur- en Skeikunde HG/P1/V1

2.2.3

2.3

3.1

3.2

3.3

Downloaded from hlayiso.com

SCE/SSE -

4

DBE/2013

Memorandum

Positive marking from
2.2.1 and 2.2.2

Positive marking from 2.2.1 and 2.2.2
Construction in 2.2

Equations and symbols used in NCS and CAPS are accepted for all responses
Vergelykings en simbole gebruik in NCS en CAPS word aanvaar vir alle
antwoorde

(calculations) AS
A ht
-AS v
“a 151 =850"
161 42 850 ¥ t=5,28 hours /ure”
ty Range: 5,12hrs 5,45hrs (4)
t=5,27 hours/ure
oS ye
Also accept: Vee vere vey
As s Ax
Veg =—— =—: =—.: ==
res = Ay Also accept v t Vv At Vv
Y. v
180 = 850
t v
t= 5,67hours/ure a
0,4 hours longer/0,4 ure langer (4)
[20]
QUESTION 3/ VRAAG 3
Asv¥ 0,014” “a5 s
=— = =0,35 m. Allow v =— for 3.1 and 3.2
Ya “Vac At 2x0,02v""S oe (4)
if mm not converted to m,
~y., =A .9 0,034" 5% 85 loose 2 marks in 3.1, but
Yo = YEH Ar = 9 0av’ ms" do not penalise again in 3.2 (3)
and 3.3 / Indien mm nie
omskakel na m nie, verloor
2 punte in 3.1 maar verloor
7 nie weer punte in 3.2 en
AVY 0,85- %, 35 =5"n 5? 3.3 nie
“At 5x0,02v : (6)
[12]

Copyright reserved/Kopiereg voorbehou

LA

f

Please turn over/Biaai om asseblief

### Page 5

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1_ 5 DBE/2013
SCE/SSE —- Memorandum

QUESTION 4/ VRAAG 4

Candidates may use the symbols v;, v;, Ax, Ay, At, and g for gravitational acceleration.

4. Using g = 9,8 m.s?
; v?=u2+2as ¥
af ae v =u? + 2as
= 10° + 2(-10)(1,8) a Qo
= 64 = 10? + 2(-9,8)(1,8)
v=8ms" = 64,72
v=8,04m.s"
OR/OF
Using g = 9,8 m.s?
v’ = wt 2as 4 v2 =u2 +2as ¥
8? = 107+ 2(-10)xs 8? = 107 + 2(-9,8)xs
s=1,8m s=1,84m
(4)
42 v=u+ atv Using g = 9,8 m.s*
8210 +(-40)t ,
t=02s¥ eet
8=10 + (-9,8)t
v=utrat % t=02sy
O=u+ (-10)0,5
7 7 ) v=utat 7
u=5m.s v Y
O=u + (-9,8).0,5 (7)
u=4,9m.s"
43
Ap=mv-mu yv
v v
=0,5x5-05x8
= -1,5 kg.m.s™ (4)
v
-1,5 kg.m.s* downwards / afwaarts .
44 1,5 Kg.ms* upwards / opwaarts (Direction marked independently / rigting word
onafhankllik gemerk)
(2)

Rk voorbehou Please turn over/Biaai om asseblief

### Page 6

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1__ 6 DBE/2013
SCE/SSE - Memorandum

A Ue
W = AE, = pm’ - gmu
A 1 x Accept positive or negative
= 5(0.8).5° - 5(0,5).8 oa
=-9,75J or 9,75) v
(5)
4.6 No./Neev
v v vv v v
Work done by bail in breaking glass / Not isolated system/ work done by glass on ball/
force exerted by glass on ball i! Arbeid verrig deur bal om die glas te breek / nie
geisoleerde sisteem nie / krag deur glas op bal toegepas
If Yes 0 marks / as ja dan geen punte (3)
[25]
QUESTION 5/ VRAAG 5
5.1 i 4 v
trailer T (cable) TT (cable)
( 1000kg ) 3800N
> car
ae >TrEeEs (5)
friction: 300 N ¥ friction: 500 N ¥
Accept free body diagrams, boxes,
Accept: Feapie, cable, T
Accept F;, f, Fw (Afrikaans) or 300N and 500 N
6.2
Frese =mMa ¥ v v
vYoev v 500.a ={- 30 (equation 1)
(3800 — 800) = 1500a as 2 v
1000.a = <0 — T = SB> (equation 2)
3000=1500.a 1500.a = 3000
a=2ms? v a=2ms?v
(5)
Fres=mxa ¥
vv v
OR | 3000 = 1500xa
a= 2ms? v
Copyright reserved/Kopiereg voorbehou Please turn over/Biaai om asseblief

A ik

### Page 7

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1_—7 DBE/2013

SCE/SSE — Memorandum

5.3 DO NOT MARK THIS QUESTION: OMMITED FROM QUESTION PAPER (TOTAL OF

PAPER ADJUSTED - 195)
MOENIE NASIEN/MERK NIE: VRAAG UITGELAAT IN ENGELSE VRAESTEL

(TOTAAL VIR VRAESTEL AANGEPAS - 195)

5.4

5.5

Fr=Fot Fv Fres = Frow—(T + Fy) ¥
v v
500.2 = Fo +(— 300) ¥ 1000.2 = 3800 — (T +500) ¥
Fo = 1300 NY T=1300NV¥
(4)

OR: from 5.2 equation 2
v

1000.a = 3800 — T - 500
v

1000.2 = 3800 ~-T — 500 ¥

T = 1300 NV

vv
Slows down (uniformly) (until it comes to a stop) / negative acceleration // Beweeg
(konstant) stadiger (totdat dit tot rus kom, negatiewe versnelling
(2)

v

Increase.
v v vv

; . F
Fengine the same, Mtotai Smaller / a inversely proportional to mass (aa— )

v v
/ F ves is larger and Fres directly proportional to a

Toeneem Fenjin dieselfde, Miotaa Kleiner / a omgekeerd eweredig aan m(: aon),

/F res iS groter en Fres direk eweredig aan a

(3)
[19]
QUESTION 6/VRAAG 6
6.1
Fr=0=Fecae + Fe
Fecate = 50.10
=500NVY
(2)
6.2 7
Fr= ma (52)
Fr = Fecale + Fo
100 = Fecate — 500 V (4)
Fecaie = 100 + 500
= 600 N¥
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

KK i

### Page 8

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1_ 8 DBE/2013
SCE/SSE — Memorandum

6.3 DO NOT MARK THIS QUESTION: OMMITED FROM QUESTION PAPER (TOTAL OF
PAPER ADJUSTED -195)
MOENIE NASIEN/MERK NIE: VRAAG UITGELAAT IN ENGELSE VRAESTEL
(TOTAAL VIR VRAESTEL AANGEPAS - 195)
zero (Newton) v (0 N) (1)
7]

QUESTION 7/ VRAAG 7

7.1
To left as positive / na links as positief To the right as positive / na regs as positief
Pbeforecollision = Pafter collision Pbeforecollision = Pafter collision
(ZP before collision = Patter collision ) } ~ (2Ppefore collision = 2Patter collision ) } we
mu =mMyVv4 + M2V2 y mur MmyV, + M2V2
(3% 2) = (1*8) + 2v (3%-2) = (1*-8) + 2v
v= -imstv v=etms? v totheright/naregs ”

v
v=1ms" tothe right /naregs

(6)

7.2
v v v

Law of conservation of momentum: The total momentum in a closed system
remains constant/ is conserved V (in magnitude and direction)
v v

OR: Law of conservation of momentum: The total momentum before a
v v

collision equals the total momentum after the collision in a closed system

v v v
Wet van behoud van momentum: Die totale momentum in ‘n geslote sisteem
is konstant/ bly behoue “
OF: Wet van behoud van momentum: die totale momentum voor ‘n botsing is
gelyk aan die totale momentum na die botsing in ‘n geslote sisteem.

(4)

7.3 Some Ex converted into heat/work sound done by the spring/deformation of
spring /other forms of energy” “”

Van die Ex omgesit in hitte/ klank werk verrig deur die veer/ vervorming van
veer/ ander vorme van energiew”

(2)
[12]

Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

KK

### Page 9

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1V1_ 9 DBE/2013
SCE/SSE — Memorandum

QUESTION 8/ VRAAG 8

8.1 v
The force of attraction or repulsion which one charge exert on the other is
v

directly proportional to the product of the charges and is inversely
v
proportional to the square of the distance between them.

Die aantrekkende of afstotende krag wat een lading op ‘n ander uitoefen is
direk eweredig aan die produk van die ladings en omgekeerd eweredig aan
die kwadraat van die afstand tussen hulle.

(3)

8.2 Curved electric field
lines important on
outside

Geboé elektriese veld
en lyne belangrik op
buitekant

If opposite charges 1 mark: last mark of rubric
As teenoorgestelde ladings 1 punt: laaste punt
in rubriek

Y field lines between charges / veldlyne tussen die ladings

Y field lines outside the charges / veldlyne buite die ladings

Y direction / rigting

Y field lines not going into spheres but touching surface and without touching each other
/ veldlyne nie binne sfere nie, maar raak opperviak en sonder om aan mekaar te raak

(4)
8.3 =
w= 0,1NYY (2 or zero)
(2)
8.4
Positive marking from Q 8.3
k
W=Fe= a2 v
r
¥_(9x10°)q?
" (0,03)? ¥
q=1x10 oC
v
Each ball carries half the original charge /elke bal dra helfte van oorspronklike lading
5)
“twice of 1x10°’C is 2x10°7C ®)
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief

EK i

### Page 10

Physical Science/Natuur- en Skeikunde HG/P1/V1

8.5
8.5.1

8.5.2

Downloaded from hlayiso.com

10 DBE/2013
SCE/SSE - Memorandum

new charge =

2x107 +(-1x107) 1
QV 7

gx107C ¥ or5,0x10*C

(2 marks for answer if no calculation shown / twee punte vir antwoord
indien geen berekening getoon word nie)

\

charged Vv

altwee + gelaai.

After contact, each has a charge of + 0,5x107 C -. repel as both +

Na kontak het elk ‘n lading van + 0,5x1 07 C - stoot mekaar af omdat

8.5.3 Closer”. Q smallerv’, Fweign the samev / rs S thus r smaller vv

kQq

Nader aan mekaar Q kleiner, Fyewig dieselfde/ r? = - dus r kleiner

QUESTION 9/VRAAG 9

9.1

9.2

ele ly
Rparalle! Ry Ro
viv
= +
6 12
Rparallel = 40 ¥

1 gow
Roarallel Ry

Rparallel = 13.0 x

R sora 7 Rea +Riza
6x12 v
~64+12%

R paraltel =40Ov

¥
= Rea xRio'd

Acceptable / aanvaarbaar:
1 14
R =(—- +=)
parallel Ry Ro

1
If Roarailel =>-+=>— : Omarks

Ri Re

i

v
Rrot 74+2= 60
“Vy SIR =3x6=18VY

Copyright reserved/Kopiereg voorbehou

LS

v

VpsiR = (3x4) = 12
Vig =IR = (3x2) =6V¥
Viti = 1246 =18VV

(2)

(2)

(3)
[21]

(4)

(4)

Please turn over/Blaai om asseblief

### Page 11

Downloaded from hlayiso.com

Physical Science/Natuur- en Skeikunde HG/P1/V1 1 DBE/2013
SCE/SSE - Memorandum
Positive marking from 9.2 Positive marking from 9.2 (6 Q)
93 | 6a)
Emf =IR + Ir ¥
“6 A oA
= Mes”. 8 Log v 24 =3(6+r)
| 3v 6
r=3 (4)
=20V%
9.4
= : Positive marking from 9.2 (18 V)
Positive marking from 9.1(4Q) ORIOF | Vog=3x2 ¥
md VV iv =6VY
V2 =RI=3x4=12V v
bd Vi20 = 18-6 (4)
=12VVY
a Decrease Y , Rrot larger ¥
Afneem , Rrot groter (2)
ee Increase/ Toeneem “
v
} smaller, lost volts less,
~ 1 minder, veriore volts minder “ @)
9.5.3
Increase/Toeneem. “
I smaller Vv, V across 2Q smaller, ¥
1 minder, V oor 2Q minder
(3)
[24]

RN

Copyright reserved/Kopiereg voorbehou

TOTALITOTAAL: Ra

19 s-

## Related documents

- [Physical Science P1 (HG) 2013 QP](https://www.hlayiso.com/library/physical-science-p1-hg-2013-qp/2d73ae33-e783-4ff5-9a3f-bb6feca1676d) — Physical Sciences · QP · 2013
- [Physical Science P1 (SG) (English) 2013 QP](https://www.hlayiso.com/library/physical-science-p1-sg-english-2013-qp/ed268f35-b433-4e08-9d31-c9740a72299f) — Physical Sciences · QP · 2013 · Eng
- [Physical Science Bill P2 (HG) 2013 Memo](https://www.hlayiso.com/library/physical-science-bill-p2-hg-2013-memo/766c928b-576d-4b54-95d2-d51c99bd6ce5) — Physical Sciences · Memo · 2013
- [Physical Sciences P1 Nov 2013 Memo Afr Eng](https://www.hlayiso.com/library/physical-sciences-p1-nov-2013-memo-afr-eng/b8f92a42-9c73-4898-adeb-03f8dd258340) — Physical Sciences · Memo · 2013 · Eng
- [Physical Science P1 (SG) (English) June 2012 QP](https://www.hlayiso.com/library/physical-science-p1-sg-english-june-2012-qp/0c084a64-a915-451d-b115-ecf0fdc0bc4b) — Physical Sciences · QP · 2012 · Eng
- [Physical Science P2 (SG) (English and Afrikaans) June 2012 Memo](https://www.hlayiso.com/library/physical-science-p2-sg-english-and-afrikaans-june-2012-memo/230c1a41-a0da-4842-92a1-abb8df5e31ac) — Physical Sciences · Memo · 2012 · Afr

## More from Grade 12 Physical Sciences

- [PHYSICAL SCIENCE P1 QP JCT 2025 AFR D watermark](https://www.hlayiso.com/library/physical-science-p1-qp-jct-2025-afr-d-watermark/b9429ac5-acbb-4fae-989d-af9e1478a96b) — QP · 2025 · Afr
- [PHYSICAL SC P2 QP GR12 SEPTEMBER 2025 AFR1 watermark](https://www.hlayiso.com/library/physical-sc-p2-qp-gr12-september-2025-afr1-watermark/37cff2db-7c1a-4ec8-8ac5-07ec5bcf87a9) — QP · 2025
- [Physics Grade 12 NSC P2 QP September 2025 Gauteng](https://www.hlayiso.com/library/physics-grade-12-nsc-p2-qp-september-2025-gauteng/4d3cbea6-10ec-47ff-98ee-50646165ae9f) — QP · 2025
- [Physics Grade 12 NSC P1 QP September 2025 KZN](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-kzn/6d225dc8-24c6-4c28-a181-df906d5a2c0e) — QP · 2025
- [Physical Sciences Physics Grade 12 PS01 QP March 2025 Limpopo](https://www.hlayiso.com/library/physical-sciences-physics-grade-12-ps01-qp-march-2025-limpopo/482ee9af-e88a-4818-9120-11ab9e045a1c) — QP · 2025
- [Physics Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-limpopo/b65e9832-a6be-4312-8f5a-57425d647121) — QP · 2025

## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

---

Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. When citing, link the page URL above, not a PDF or /api/ URL.