# Physical Sciences Grade 12 Paper 2 NSC June 2013 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the NSC June 2013, 12 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/physical-science-bill-p2-hg-2013-memo/766c928b-576d-4b54-95d2-d51c99bd6ce5
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2013
- Exam period: NSC June
- Paper: 2
- Curriculum: CAPS
- Pages: 12

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## About this document

Physical Sciences · Grade 12 · NSC June · 2013. Memorandum, 12 pages. Read online or download the PDF.

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## Document text

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### Page 1

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basic education

Department:
Basic Education
REPUBLIC OF SOUTH AFRICA

SENIOR CERTIFICATE EXAMINATION
SENIORSERTIFIKAAT-EKSAMEN

PHYSICAL SCIENCE P2/NATUUR- EN SKEIKUNDE V2

CHEMISTRY/CHEMIE
HIGHER GRADE/HOER GRAAD

2013

POSSIBLE ANSWERS / MOONTLIKE ANTWOORDE

MARKSI/PUNTE: 200

This memorandum consists of 12 pages.
Hierdie memorandum bestaan uit 12 bladsye.

pe

mare

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 2 DBE/2013
SCE/SSE —- Memorandum

QUESTION 1/VRAAG 1

1.1 DvuvwYy (4)
1.2 Ave (4)
1.3 CY¥vwYY (4)
14 Buy (4)
1.5 A ¥vYY (4)
1.6 BYYYY (4)
17 Ae (4)
18 7 (4)
1.9 Curvy (4)
1.10 Dwr (4)
1.11 Dryvwr (4)
1.12 Dywyy (4)
1.13 Byyyy (4)
1.14 ® 4a (4)
1.15 — (4)
(15x 4) [60]
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or

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Physical Science/HG/P2/Natuur- en Skeikunde/41G/V2 3 DBE/2013
SCE/SSE —~ Memorandum

QUESTION 2/VRAAG 2

pV

2.1
PIM _P2V2 OR use/OF gebruik oak

T, T,

x Y
QO x10 «Va (if V converted to dm? etc., it has to b ct
= converte: im” etc., jas to be corre
C8) NE

V2 = 40,0 cm? ~ (40- 40,0335 cm? )
OR/OF

¢
vw

PIV ~P2V2y, SEORTOD 478" 40,0335 om?

T 7, G98) x 360 a

2.2.1. The pressure of an enclosed (fixed) mass (amount) of gas is inversely
proportional to its volume at constant temperature.
Die druk van 'n ingeslote (vaste) massa (hoeveelheid) gas is omgekeerd
eweredig aan die volume daarvan by konstante temperatuur.

Y correct variables (volume and pressure)/korrekte veranderlikes
(volume en druk)
“relationship correct(in words, not symbols)iverwantskap korrek
(in woorde, nie simbole nie)
v_enclosed (fixed) mass (amount) of gas AND constant temperature
ingeslote (vaste) massa (hoeveelheid) gas EN konstante

temperatuur ; :
If indirectly proportional — max 2/3 accept p directly proportional a
As indirek eweredig — maks 2/3 aanvaar p direk eweredig aan 1,

2.2.2

vo
(Gradient =) & = maT) Es 8,31 x(288)= 168,54 J
~
a Y
(Gradient =) =(0,07 x 83 (288) = 168,54 J”

formula/formule

calculate n/bereken n

substitute both n and R/substitueer beide nen R
substitute 288/substitueer 288

Answer = 168,5 J/ Antwoord = 168,5 J

eeeccee

If n= 0,07 mol had been used, answer = 167,5 J
As n= 0,07 mol gebruik is, antwoord = 167,5 J

6)

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un

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 4 DBE/2013
SCE/SSE — Memorandum

2.2.3
” straight line /reguitlyn

(Ignore origin/ignoreer oorsprong)
Y greater gradient / groter gradient

(2)

2.3 The hydrogen bonding ~“between the molecules of HF is stronger ~”
than the Van der Waals forces “ between molecules of Cf, therefore the

deviation from ideal gas behaviour (OR because it is a real gas)/smaller
volume/volume decreases ~”

Die waterstofbinding tussen die molekule van HF is sterker as die

Van der Waalskragte tussen die molekule van Cl, daarom die afwyking

van ideale gasgedrag (OF omdat dit ‘n ware gas is) /kleiner volume / (4)
volume neem af. [19]

we

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 5 DBE/2013
SCE/SSE — Memorandum

QUESTION 3/VRAAG 3
3.1.1: FeS/CuS/ PbS (or other sulphide) / (of ander sulfied)
(no marks for name / geen punt vir naam) (1)

3.1.2 colour changes from orange/yellow/brown > green ~

Kleur verander van oranje/geel/bruin > groen
(yellow/sulphur) suspension or precipitate/cloudy/milky / (2)

(geel/swawel) suspensie of neerslag/troebel/melkerig ~“
3.1.3 Fe?* (FeCt,/Iron(Il) ion / tron(II)chloride) “~~ and S (sulphur) “~~
Fe?* (FeCt,/ Yster{il)ion / yster(Ii)chloried) ““ and S (swawel) “” = (4)

3.1.4 eon v (1)

3.1.5 VHS >S+2H*+2e ~“ ANDIEN Fe*+e°'>Fe*

OR/OF

H2S is oxidised / loses e"/ H2S word geoksideer / verloore’ ~“
ANDI/EN Fe™ is reduced / gains e" / Fe** word gereduseer wen e “

OR/OF
Electrons are transferred ~’ from H2S to Fe** ~/
elektrone is oorgedra ~ van H2S na Fe* ~

(2)

ORIOF
H2S acts as RAY, Fe* acts as OAY

3.2.1 Cu is nota strong enough reducing agent “to reduce the dilute

sulphuric acid vto SO. “ /Cu is nie ‘n sterk genoeg reduseermiddel “
om die verdunde swawelsuur te reduseer” tot SO nie “
OR/ OF:

Dilute sulphuric acid is not a strong enough oxidising agent “to oxidise
the Cu”toCu= ~

Verdunde swawelsuurs nie ‘n sterk genoeg oksideermiddel “om Cu

tot Cu” te oksideer nie. (3)

: Cu = Cu* + 2e (1/2)
ag y ww
3.2.2 (a) Cu + Cu* + 2e Cu +26 = cu (012)
Cu* + 2e +Cu (0/2)
Cu** + 2e - Cu (1/2) | (@y

3.2.2 (b) SO,7 + 4H* + 2e°-—> SO, + 2H,0 vw

SO, + 4H* + 2e° = SOQ. + 2H,O (1/2)
SO, + 2H,0 ~ SO, + 4H* + 26 (1/2)
SOQ, + 2H20 — SO, + 4H* + 2e (0/2)
SO, + 2H.0 = SO,2+ 4H* + 26 (0/2) (2)

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Soe =
ae

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 6 DBE/2013

SCE/SSE — Memorandum

3.3.1 Catalyst / increase rate of reaction / provides medium for reaction to take
place / makes protons available ~“
katalisator | verhoog reaksietempo / verskaf medium waarin reaksie kan
plaasvind / maak protone beskikbaar. ~ (1)
3.3.2 Density (heavier) of SO2 higher ~~ (than H2S) / (2)
Digtheid van SOz2 groter (swaarder) (as H2S)
3.3.3. Yellow ~ (sulphur) precipitate “forms
Geel ~“(swawel) neerslag ~vorm (2)
3.3.4 sulphur dioxide / swaweldioksied “~~ (SO2”%) (2)
3.3.5 HS ~ :
OR: Hydrogen sulphide / OF: waterstofsulfied (1)
[25]
QUESTION 4/VRAAG 4
4.1.1 Yellow” precipitate/solid ~ forms / (2)
gee! “ presipitaat/neerslag/vaste stof “ vorm
4.1.2 Nal (aq) + AgNO3(aq) > Agl(s) + NaNOs(aq
~reactants/reaktante ~ products/produkte ~balancing/balansering (3)
OR/ OF: Ag*(aq) + I'(aq) — Agl(s)
4.1.3 (a) lodine (lz) / jodium (lz) (1)
(b) Sodium chloride (NaCé) “ = / natriumchloried (NaCé) (1)
41.4 purple “/pers “ (1)
4.2.1 Platinum (Pt) / Rhodium (Rh) (1)
4.2.2 Water (H2O) (1)
4.2.3 NO »“~ OR/ OF: Nitrogen oxide / stikstofoksied (2)
4.2.4 NO2 ~“ (nitrogen dioxide/stikstofdioksied) ~“ (2)
{14]
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(~~

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 a DBE/2013
SCE/SSE — Memorandum

QUESTION 5/IVRAAG 5
5.1.1 -“ 21kI ~ (2)
51.2 165k) ~ (1)
5.1.3 186kJ ~ (1)
5.1.4 Catalyst added / Katalisator bygevoeg ~“ (1)
5.1.5 exothermic ~/eksotermies “ (1)
5.2.1. Rise in temperature// exothermic / Styging in temperatuur/ eksotermies “
sutsce area becomes more exposed because of the corrosive action of the
acid / reaksieopperviak word meer blootgestel a.g.v vretende suur. (1)
5.2.2 Concentration of the acid decreases/Konsentrasie van die suur verminder~”
oe a becomes smaller (surface area) / Zn monster word kleiner
(reaksieopperviak) (1)

Reactants being used up / Reaktanse word opgebruik

5.2.3 ANY TWO/ENIGE TWEE: ~~
Zn powdered /Verpoeierde Zn
higher acid concentration / hoér konsentrasie suur

increase temperature of the acid / verhoog die temperatuur van die suur. ae
catalyst /katalisator

QUESTION 6/VRAAG 6

6.1 The pressure gauge will give a constant reading / Drukmeter gee
konstante lesing “ (1)

6.2
\%

“Ko

e shape of first part / vorm van eerste deel
e horizontal line / horisontale lyn” (2)

t

Ignore labels on axes/ignoreer asse

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Pr.

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 8 DBE/2013
SCE/SSE — Memorandum
6.3
(NHa)2CO3 2NH3 H,0 COz
ny 2 2 .
12,2 -0,52 = 11,68 ~
n=11,68/96 ~ a
= 0,12 (0,122) Ratio
An OF/OR 0,24 | o42 | 0,12
12,2-0,52 ~ (0,243)
or —s a
=0.12 2 subtraction
ne 0,24 0,12 0,12 v
n ee
c=— Divide by
Vv L649 | 02
(0,487) | °24 hoa 0.5
V=0,5 dm*
Ke = [NHs]*[H2O] [CO] ~
= (0,48)? (0,24) (0,24) ~
= 0,01327..(OR/OF: 0,014) ~“
e Subtraction (mass or mole) [12,2 — 0,52 = 11.68 or
e Divide by / dee! deur M = 96
e Mol ratio / molverhouding
e Subtraction / aftrek (4n)
e Divide by 0,5 / dee/ deur 0,5
e K, expression / uitdrukking
e Substitution /substitusie
© 0,01327.. (OR/OF: 0,014) (8)
6.4.1 Decreases /Neem af ~” (1)
6.4.2 Increases /neem toe ~ (1)
6.4.3 Decreases/Neem af ~ (1)
6.5 decrease in temperature favours the exothermic reaction “

reverse reaction is exothermic forward reaction is endothermic”

concentration of products decreases “
afname in temperatuur bevoordeel die eksotermiese reaksie ~

terugwaartse reaksie is eksotermies “
konsentrasie van produkte neem af ~ (3)
[17]

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OO000 0

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 9 DBE/2013
SCE/SSE — Memorandum

QUESTION 7/VRAAG 7
7.41.4 : _a
m= eMV ~OR/OF c = Vv © Formuta/formule
e 56g.mof?
v ° 0,4dm?
e Substitution / substitusie
=3, 36g” e 336g
ORI/OF:
n=cV

~ formula/formule

» substitution/substitusie

= 0,06 x66) ~
(8)
= 336g”
7.1.2 c, V, _n,
=— e formula/formule
Cy Vp My © 0,15x25
e C,x30
Ceax30K_ 1) * using ratio:na 7m = 1:2
G,15x25) 2 * 0,063 mol.dm®
Ca = 0,063 mol.dm® ~ — (0,0625 mol.dm’’)
ORIOF:
Mp = eV 0,00375 mol ”
ng = 0,5 x 0,00375 = 0,001875 mol » ratio (multiply by 0,5/ divide by 2)
n
c.=— ”
av
_ 0,001875
= 0,0625 mol.dm=> ~
(5)
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>
Cm

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 10 DBE/2013
SCE/SSE — Memorandum

7.1.3  [OH)[H*] = 10% OR [OH}.[H']=Kw ~
1,23 x 10% x[H*] = 104 %
8,13 x10 mol.dm? ~

pH =-log[H*] ~ [OH] = 1,23 x 10% = 10°
IH] = 10-"4 40714+3,91 _ 49-10,09

4973:91
2. pH # Jog[H*] = -l0g(10"°%) = 10,09

=~ log(8,13 x 10") ~

=10,09 ~
ORI/OF:
pOH

log [OH] ~

- log (1,23 x 104) ”

3,917

pH = 14 3,91~ (6)
= 10,09”

u

7.2.4 Greater than 7 / groteras 7 “ (1)

7.2.2 \ (NH3/ NH,OH) is a base / OH ions in solution OR an alkaline solution” (1)

(NH / NH4OH) is ‘n basis/OH-ione in oplossing OF ‘n alkaliese
oplossing

7.2.3 NH3+H* —»NHZ (OF/OR NH3+H2O -> NH3 +. OH)
” reactants/reaktante “products/produkte “balancing/balansering (3)

7.2.4 ( Decrease / afneem (1)

7.25 NH; is a (weak) acid / proton donor ~~”

NH3 is ‘n (swak) suur/ protonskenker ““
OR/OF:
According to Le Chateliers principle an increase in INH4] will favour

the reverse reaction in 7.2.3, which will increase the [H*] and
therefore decrease the pH.

Volgens Le Chatelier se beginsel sal ‘n verhoging in [| NH3]

die terugwaartse reaksie in 5.2.2(b) bevoordeel, wat die [H*] vehoog
en dus die pH verlaag.
OR/OF:

NH; is a common ion, and according to the common ion effect,
the [H"] will increase, and therefore decrease the pH.
NH; is ‘n gemeenskaplike ioon, en volgens die gemeenskaplike

ioon-effek sal die [H*] vehoog word, en dus die pH verlaag. a

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ae

a

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 11 DBE/2013
SCE/SSE — Memorandum
QUESTION 8/VRAAG 8
8.1 Silver (Ag) / silwer (Ag) (1)
8.2.1 Cr—+Cr* +3e “~~ :
Cr = Cr* + 3e (1/2)
Cr* + 3e Cr (0/2)
Cu* + 2e * Cu (1/2)
crt + 3e = Cr (0/2)
(2)
8.22 Ag te > Ag ~~
Agi +e Ag (1/2)
Ag ~Ag + e& (0/2)
Ag~ Ag’ +e& (1/2)
Ag = Ag’ +e (0/2)
(2)
823 Cr+ 3Ag’ - Cr* + 3Ag ~~  (ignore/ignoreer =) (2)
8.3 Increases /toeneem ~“ (1)
8.4 AgNO; “O (1)
8.5 Se = E% oxidising agent ~ E% reducing agent ~~
E%sq) = E° oxsideermidde! ~ E*recuseermiddet
= 0,80”— (-0,74) ~
= 154V ~
ORIOF: = E%en = Evcathoae - Eanode /E%sor = E%katode ~ E*anode (4)

86 Cr+ 3Ag’ — Cr* + 3Aq , if LAg'lis increased ~ the forward
reaction is favoured. “/ as [ Ag"] toeneem word die voorwaartse reaksie

bevoordeel.
OR/OF:

Rate of the forward reaction increases ~ with increase in concentration

~

Tempo van reaksie neem toe met toename in konsentrasie.

ORIOF:

(2)

[Ag’Lis increased ~ equilibrium (position) shifts to the right ~“/

Ewewig(posisie) skuif na regs. “

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[15]

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Physical Science/HG/P2/Natuur- en Skeikunde/HG/V2 12

SCE/SSE — Memorandum

QUESTION 9/VRAAG 9
oo fe
9.1.2 addition / bromination / addisie/ brominering ~~“

9.1.3
9.2.1

9.2.2

9.2.3
9.3.1
9.3.2
9.3.3

propane / propaan “~~”

(They have the same molecular formula but) different structural
formulae. “~~

(Hulle het dieselfde molekulére formule maar) veskilfende
Struktuurformules. “~~

a
H .H H H
wy
OR/OF:
tt
mann
HG tH
H H
OR/OF:
H H
H—¢—F CH
hd
—C—
CaHan ~
methanol / methanol “~~

ethanoic acid / etanoésuur “~~

concentrated sulphuric acid“ / gekonsentreerde swawelsuur
sulphuric acid” / swawelsuur
concentrated H2SO,~” / gekonsentreerde H2SO,

HySO,4 (0/2)

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DBE/2013

(1)
(2)
(2)

(2)

(2)

(1)
(2)
(2)

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