# Physical Sciences Grade 10 Paper 1 KZN November 2023 Memo

> Grade 10 Physical Sciences Paper 1 memorandum from the KZN November Exam 2023, 18 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physical-science-grade-10-november-2023-p1-and-memo/f6cf5c0b-5796-47b3-bbce-d96df96e92f6
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 10
- Document type: Memorandum
- Year: 2023
- Exam period: KZN November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 18

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## About this document

Physical Sciences · Grade 10 · KZN November Exam · 2023. Memorandum, 18 pages. Read online or download the PDF.

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## Document text

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              KWAZULU-NATAL PROVINCE
              EDUCATION
              REPUBLIC OF SOUTH AFRICA

                                  NATIONAL
                             SENIOR CERTIFICATE

        ,,�--------------                                _________ �      _,,

                                                                                11
                                                                                II
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                                                                                II
                                                                                II
                                                                                II
                                                                                II

        ,,                                           -----------��.,
                                                                                II

         �.!!�!!!!!!�!!!!!!!!!�!!   -

MARKS: 100

DURATION: 2 hours
                                 Stanmorephysics

             This question paper consists of 11 pages and a data sheet.

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Physiewslanderdann) Stanmorerbysics.com November 2023
2
INSTRUCTIONS AND INFORMATION
i This question paper consists of EIGHT questions. Answer ALL the questions in

the ANSWER BOOK.

—=

H question on a NEW page in the ANSWER BOOK.

3 Numb r the answers correctly according to the numbering system used in this
question paper.
4. Leave ONE line between two sub-questions, for example between

QUESTION 2.1 and QUESTION 2.2.

5. You may use a non-programmable calculator.

6. You may use appropriate mathematical instruments.

G You are advised to use the attached DATA SHEET.

8. Show ALL formulae and substitutions in ALL calculations.

9: Round off your final numerical answers to a minimum of TWO decimal places.
10. Give brief motivations, discussions et cetera where required.

11. Write neatly and legibly.

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QUESTION 1: MULTIPLE-CHOICE QUESTIONS

Four options are provided as possible answers to the following questions. Each question

has only ONE correct answer. Choose the answer and write only the letter (A—D) next

to the questionAuimber (1.1-1.5) in the ANSWER BOOK, for example 1.6 E.

1.1 If th distance between two consecutive compressions in a wave is decreased,
which-ONE of the following will INCREASE when the wave speed is kept
constant?

A Amplitude

B_ Period

C Frequency

D Wavelength (2)
1.2 The position-time graph for a car travelling along a straight horizontal surface

is shown below.

GRAPH OF POSITION VERSUS TIME

Position (m)

0 t
Time (s)
Line PQ is a tangent to the curve at time t1.
Which ONE of the following is equal to the gradient of PQ?

A __ Average velocity over the period 0 to t1

B Instantaneous velocity at t1

C Average acceleration over the period 0 to t:

D Instantaneous acceleration at ti (2)

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1.3 The kinetic energy of a trolley is E. What will the kinetic energy of the trolley be
if its velocity is tripled?

A

B

Cc

D 9E (2)

1.4 The table below shows the changes in the velocity of a car in intervals of

4 seconds.
Time (s) 0 4 8 12 16 20 24 28 32
Velocity (m.s“) ie} 7 14 21 28 28 28 28 28

Which ONE of the following is CORRECT for the acceleration of the car?
The acceleration of the car ...

A _ increases initially for 16 s then remains constant.
B _ is initially constant for 16 s then becomes zero.
C _ is initially constant for 16 s and then decreases.

D _ increases initially for 16 s and then becomes zero. (2)

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1.5 Four identical resistors are connected as shown in the circuit diagram below.
Which ONE of the following relationships is correct for the readings on the
voltmeters?
©

Ra

Ri

R3

-©-

Bo VrHVi+V2+V3 + V4

A M=V2=V3

C Vr=V3 + V4

D Wt=V3 (2)

[2X 5=10]

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QUESTION 2 (Start on a new page.)

21 A section of a wave is represented below.

time = x seconds

The frequency of the wave is 2,5 Hz.
2414 Is the above wave TRANSVERSE or LONGITUDINAL? (1)
21:2 Calculate the speed of the wave. (3)
2.1.3 Determine the time, “x”, between point A and point B on the graph. (3)

22 Ships use Sonar (Sound Navigation and Ranging) to map and measure the
depth of the ocean at different points. This is achieved by emitting sound waves
into the sea and detecting the reflected sound.

The sound wave emitted by the Sonar on a ship takes 0,8 seconds to reach
point P, which is on the seabed 1200 m below the ship. Q is a second point on
the seabed, as shown in the diagram below.

O*K

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2.2.1 Calculate the speed of sound in seawater at point P. (3)

It is estimated that the speed of sound in seawater increases by 4,5 m.s“ for
every me increase in temperature.

The temperature of the seawater at point Q is 2°C higher than at
point P. When a sound wave is emitted directly above point Q, the
reflected sound wave is detected 2,5 seconds later.

Determine the depth of the sea at point Q. (4)

[14]

QUESTION 3 (Start on a new page.)

A photon of wavelength 2 x 10” m is located within the x-ray range of the
electromagnetic spectrum.

3.1 Write down the speed of this photon in a vacuum. (1)
3.2 Calculate:
3.2.1 The frequency of the photon. (3)
5:3:2 The energy of the photon. (3)

3.3 The wavelength of the photon is doubled. Will the penetrating ability of this
photon INCREASE, DECREASE or REMAIN THE SAME?
Explain the answer. (3)

[10]

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QUESTION 4 (Start on a new page.)

Two small identical Spheres, X and Y, carrying charges of — 6 x 10 8Cand8x10°C
respectively, afeSuspended from a ceiling by means of light, insulated strings.

Qx =-6x10°C Qy =8 x10°C
4.1 State the principle of quantization of charge. (2)
4.2 Calculate the difference between the number of protons and electrons in
Sphere X. (3)

The spheres are brought into contact and are then separated.

4.3 State the principle of conservation of charge. (2)
4.4 Calculate the new charge on Sphere Y. (3)
[10]

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QUESTION 5 (Start on a new page)

A battery consisting of 3 identical cells of unknown emf is connected to four resistors, as
shown in the diagram below.

120
R2

The voltmeter reads 12 V, while ammeter A2 reads 2 A.
51 Define the emf of a battery in words. (2)

a2 Calculate the:

5.2.1 Effective resistance of the parallel combination (3)

5.2.2 The reading on ammeter Ai: (3)

5.2.3 Energy transferred to the resistor R3 in 2 minutes (5)

5.2.4 EMF of each cell (3)
5.3 A fifth resistor, Rs, is now connected in parallel to Ra.

5.3.1 Will the emf of the battery INCREASE, DECREASE OR REMAIN
THE SAME? (1)
5:3:2 Will the reading on Ai INCREASE, DECREASE
SAME? L

Give a reason for the answer. (2)
[19]

REMAIN THE

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QUESTION 6 (Start on a new page)

A forklift startingfrom Point X needs to pick up a package from Point Y, which is due
east from Point.

The package! is)/thereafter transported to a table, which lies 350 metres due west
of Point X. The-entire trip takes the driver 2 minutes to complete.

N
—
|_ :
>
350m X Y
6.1 Define the term average velocity in words. (2)
6.2 Calculate the average velocity of the forklift for the entire motion. (3)
63 The average speed of the forklift is 3,75 m-s".
Determine the position of Point Y relative to Point X. (4)
[9]
QUESTION 7 (Start on a new page)
7.1 Acar C and a van V are both travelling at a constant velocity of 25 m.s“' east,

on different lanes along the same horizontal road. The driver of the car follows
the van, keeping a distance of 5 metres between them. Seeing a box on his
lane, the driver of the van brakes and slows down uniformly to stop in 5

seconds.
N
Ds Box E

OO

Ss
iI
7.1.1 Calculate the acceleration of the van whilst slowing down. (3)
fAZ If the car continued at its original motion, how far ahead of the van
will the car be when the van stops? (5)

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7.2 After passing the box, the van takes off from rest and accelerates uniformly at

4m-s* for 8 seconds. It thereafter travels at a constant velocity of X m-s" for a
further 4 seconds as shown in the graph below.

Velocity (m-s)

Cg ee
=
Roaftsescnsnoeasew:

Time (s)

2a USE THE GRAPH to determine the value of X.

7.2.2 Sketch the acceleration vs time graph for the 12 seconds
represented in the graph above.
Indicate the relevant time and acceleration values on the graph.

QUESTION 8 (Start on a new page)

A 4kg steel ball is pushed from rest from the top of a frictionless ramp of unknown height,
h at point A. It passes point B, which is 1 metre above the ground at a velocity of
5,422 m-s". The ball eventually reaches the ground at point C.

Cc
8.1 Calculate the mechanical energy of the ball.

The magnitude of the velocity doubles as the ball rolls from Point A to Point C.

8.2 State the principle of conservation of mechanical energy in;words.
| T

8.3 Determine the height h of the ramp.

TOTAL: 100

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(3)

(3)

(3)
[17]

(4)

(2)

(5)
[11]

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DATA FOR PHYSICAL SCIENCES GRADE 10
PAPER 1 (PHYSICS)

TABLE 1: PHYSICAL CONSTANTS

NAME SYMBOL VALUE
Acceleration dué+to gravity g 9,8 m.s2
Speed of lightifla vacuum Cc 3,0 x 108 m-s*
Planck's constant h 6,63 x 10 J-s
Charge on electron de -1,6 x 1019C
Electron mass Me 9,11 x 10° kg

TABLE 2: FORMULAE

WAVES, SOUND AND LIGHT

1
v=fa or c=fa T=
ig
he
E=hf E=—
a
ELECTROSTATICS
1+ Q2
Q=n XG = a 2 ®
ELECTRIC CIRCUITS
=1xA poe
gern’ Rp Ri’ Re
Ww
R, = Ry +Ro te Vom
Q
MOTION
zg 1.2
Vy = vi + aAt Ax=viAt+ Sat
+y.
v2 = v2 + 2aax AK= (SS )at
WORK, ENERGY AND POWER
U=mgh or E,= mgh K= yp, mv? or Ex = Vy, mv2

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KWAZULU-NATAL PROVINCE

EDUCATION
REPUBLIC OF SOUTH AFRICA

NATIONAL
SENIOR CERTIFICATE

GRADE 10

MARKS: 100

DURATION: 2 hours

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QUESTION 1:
ni Cvv (2)
nd Byv (2)
13 Dvv (2)
14 BYY . (2)
15 Cv% (2)
i [10]
QUESTION
21 PA Transverse wave ¥ (1)
2.1.2 v=f xh v
=2,5*0,3 v
=0,75ms' v (3)
24.3 OPTION 1 OPTION 2
_4_ erent ee
T= F565 pee c= time
y = 0:825%
=04s QS =
time =0,4V x1,75v x = 0,7 (s)¥
time = 0,7 (s) ¥ (3)
2.2
distance
2.21 speed = : ¥
time
_ 1200 ff
~ 0,8
= 1500 m-s! ¥ (3)
2.2.2 POSITIVE MARKING FROM QUESTION 2.2.1
speed = 1500+ 2x4,5”
speed = 1509 m.s*
d= distance
speed = ime
distance
v =——_—
1509 1257
Distance = 1886,25 m V a (4)
[14]

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QUESTION 3
a 3x 10®mst v¥
32

3.2.1 c=fxA v.
[nat 3 x 108=fx2x107 v.
f=1,5x 10 Hz v

3.2.2 » OPTION 1 OPTION 2
E=hxf ¥. ne v
a
6,63 x 10734 x 3 x 10° v
= 6,63 x 1034x 15x10 v.|~ 9x 40-7
=9,945x1079J v. =9,945x1019J v.
33 Decrease. ¥

The energy of the photon will decrease OR Energy of the photon is inversely
proportional to the wavelength. ”
A decrease in the energy of the photon decreases the penetrating ability “

QUESTION 4

41 All charges in the universe consist of an integer multiple Y of the charge of
one electron ¥
4.2 Q=nxq,¥%

6x10° =n x 1,610"? v
n=3,75x 10%v

4.3 The net charge of an isolated systemY remains constant” (during any
physical process).

44 a= Q1+Q2 x
2
Q=
- 6x10 + 8x10? v
2
=1x10°Cv

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(1)

(3)

(3)

(3)
[10]

(2)

(3)

(2)

(3)
[10]

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QUESTION 5
5.1 The work done per unit charge Y by the source (battery) ¥
5.2

5.2.2

5.2.3

5.2.4

5.3
5.3.1

5.3.2

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Using Ratio
liza = % len
=%(2)v
=1A
ltot = 1 + 2¥
=3AV

POSITIVE MARKING FROM 5.2.2

Using Ohms Law

V=IR

12=1x12v

I=1A

ltot = 1 + 2¥
=3AV

OPTION 1
Vr3=%(12)¥ OR V=IR
=6V =3x2v
=6V

Q=lIAt
=3x120vV
= 360 C

W=VQv
=6 x 360 ¥
= 2160 Jv

EMF of Battery =12+6+6VvV
=24V
EMF of ONE CELL = 24+3 ¥
=8VV

Remain the same Vv

Increase ¥
The total resistance decreases. ¥

OPTION 2

W =I? RAt ¥
=32Vx2Vx120V
=2160 Jv

(2)

(3)

(3)

(5)

(3)

(1)

(2)

[19]

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QUESTION 6
6.1 The rate of change of position VW (2)
6.2 ¥ (3)
v= Ber Vv
v= 2:92m.s* west V
6.3 distance
speed = —
time
distance
= v
3,75 120

distance = 450 m
450 = 2XY + 350V
Distance from point X to Point Y = 50 m

Position of Point Y = 50 m v east ¥ (4)
[9]
QUESTION 7
TAA OPTION 1 OPTION 2
Av
=— ¥ Ve = vi + adtv¥
a At f i
= SR v 0 = 25 + a(5)v
=-5m.s? a = -5ms2
= 5 ms? west ¥ = 5ms? west ¥ (3)
71.2 Van
POSITIVE MARKING FROM Q7.1.2
_ (“Atv
AE ( 2 atv OR) ax = viAt + %adt? ¥
_ (0425).
ax=(—=)xs = 25(5) + %(-5)(5) ¥
Ax = 62,5 m = 62,5m
Car
= 1 2
Ax=viAt+ aA OR Ax =viAt
AX = 25x 5 + 30x57 v Ax = 25x 5 vt
=125m =125m
Distance between vehicles = 125 —62,5-5 ¥
=57,5m v (5)

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2A ae Ve Va

4v =f v7
8-0
X=32m-stv

Acceleration (m.
bh

———
8

12.‘ Time(s)

Marking Criteria
1 Mark — Horizontal line at 4 m.s? from 0 to 8 seconds

1 Mark — Horizontal line at 0 m.s? from 8 to 12 seconds

1 Mark — Shape (2 parallel horizontal lines that are disjointed)

QUESTION 8
8.1 Er = mgh + “mv? v
=4x98x1V%+%x4x (5.422) Vv
=98 Jv
8.2 The total mechanical energy in an isolated system remains constant. Vv

8.3 POSITIVE MARKING FROM 8.1
Point C
Er =mgh + “mv?
98 VY =0+%x4xv2v
v=7m-s"

Point A

V=7+2=35msiv

Er = mgh + “%mv2

98 =4x98xh+%x4x352V
h=1,875 mv

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TOTAL:

(3)
(3)

(3)
[17]

(4)
(2)

(5)
[11]
100

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