# Physical Sciences Grade 12 Paper 2 EC June 2014 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the EC June 2014, 7 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/physical-science-p2-2014-memo/eadff6e1-9996-4fef-9cad-571097013c3b
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2014
- Exam period: EC June
- Paper: 2
- Curriculum: CAPS
- Pages: 7

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## About this document

Physical Sciences · Grade 12 · EC June · 2014. Memorandum, 7 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Document text

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### Page 1

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Physical Science/P2                            1                     June 2014 Common Test
                                       NSC – Memorandum

                              PHYSICAL SCIENCES P2

                                   MEMORANDUM

                                    COMMON TEST

                                       JUNE 2014

                                     NATIONAL
                                SENIOR CERTIFICATE

                                       GRADE 12

                N.B. This memorandum consists of 7 pages including this page.

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### Page 2

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Physical Science/P2                             2                        June 2014 Common Test
                                        NSC – Memorandum
SECTION A

QUESTION 1

1.1     A                                                                                (2)

1.2     C                                                                                (2)

1.3     B                                                                                (2)

1.4     D                                                                                (2)

1.5     D                                                                                (2)

1.6     D                                                                                (2)

1.7     B                                                                                (2)
                                                                                           [14]

SECTION B

QUESTION 2

2.1
        2.1.1 Carboxylic acid                                                             (1)

        2.1.2 Butanal                                                                     (1)

        2.1.3
                      H     H
                      l     l
                      C =   C 
                      l     l
                      H     H                                                               (2)

2.2     Tertiary                                                                          (1)

2.3     They have the same molecular formula but different functional groups.            (2)
                                                                                           [7]

QUESTION 3
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### Page 3

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Physical Science/P2                               3                                 June 2014 Common Test
                                          NSC – Memorandum

3.1     Hydrocarbons are organic compounds that consist of hydrogen and carbon
        only.                                                                                     (1)

3.2
        3.2.1 Boiling point increases as the surface area increases  OR
              Boiling point decreases as the chain become more branched                            (1)

        3.2.2 The more branches the smaller the surface area,  the weaker the
              intermolecular (Van der Waals) forces.  Lesser energy needed to
              separate the chains.  (the lower the boiling point).                                (3)

3.3     A.                                                                                        (1)
                                                                                                   [6]

QUESTION 4

4.1.1 CH3 CH2 CH2 CH2 -O-H                                                                       (2)
                                   heat                     
4.1.2   CH3 CH2 CH2 CH2 -O-H                          CH3CH2CH=CH2 + H2O.
                                 H2SO4 (conc)   
                                                            H2O      H2SO4 (conc)
                                                            Excess   heat             

                                                        CH3CH2CHCH3

                                                                 O -H                              (4)

4.2.1 Alcohol                                                                                      (1)
                                heat
4.2.2 CH3CH=CH2 + H2O          H2SO4 (conc)    CH3CHCH3                                           (3)

                                                    O -H

                               
                             heat                      
4.2.3 CH3CH2CH2Cℓ + NaOH (aq)                   CH3CH2CH2O-H + HCℓ                                 (3)
                                                                                                   [13]

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### Page 4

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Physical Science/P2                                  4                         June 2014 Common Test
                                             NSC – Memorandum

QUESTION 5

5.1     Exothermic 
        ΔH = energy of the products – energy of the reactants
        ΔH = –197 – 0
        ΔH = –197 kJmol–1                                                                    (2)

5.2     1580 kJmol–1                                                                         (1)

5.3     1777 kJmol–1                                                                         (1)

5.4     1537 kJmol–1                                                                         (1)
                                                                                              [5]

QUESTION 6

6.1     Zn(s) + 2HCℓ(aq)       → ZnCℓ2 (aq) + H2(g)           bal                          (3)

6.2     surface area  / state of division                                                    (1)

6.3     To make the investigation fair  / To have 1 independent variable                     (1)

6.4     Volume of H2(g) is dependant on the amount of zinc used.                             (1)

                                       ΔV
6.5     Average reaction rate       =
                                        Δt
                                       48  30
                                    =           
                                       40  20
                                    = 0,9 cm3.s-1                                            (3)

6.6     Greater than                                                                         (1)

6.7     Zn is powder, the more finely divided (greater surface area) the
        greater the contact area.  This will result in more effective collision
        occur simultaneously per unit time.                                                  (2)

6.8
        6.8.1 Remains the same.                                                              (1)

        6.8.2 Steeper.                                                                       (1)

6.9     Copper is a catalyst. Increase the rate of reaction.                                (2)
                                                                                              [16]

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### Page 5

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Physical Science/P2                                   5                         June 2014 Common Test
                                              NSC – Memorandum

QUESTION 7

7.1     Homogenous,  reactants and products are in the same phase.                           (2)

7.2     Catalyst                                                                              (1)

7.3     The equilibrium in graph C is reached faster than in graph A while the
        concentration of the products in graph A and C are equal and also the
        concentration of the reactants in both graphs A and C are equal.                     (2)

7.4     Exothermic.                                                                           (1)

7.5     If the temperature is increased from 5000C to 6000C the concentration of the
        products decreases and the reactants concentration increases.  The reverse
        reaction is thus favoured. According to Le Chateliers’ principle endothermic
        reaction is favoured when temperature is increased.  Thus the forward
        reaction is exothermic.                                                                (2)

7.6     H2(g)    +    I2(g)   ⇌      2HI(g)
        n(H2) = 1
                2
                = 0,5 mol
        n(I2) = 127
                254
                = 0,5 mol

                      Mole Ratio                            H2       I2       2HI
                      Initial mol                          (0,5    0,5)       0
                      Change (used/ formed)                (0,4     0,4     0,8) 
                      Equilibrium mol                      (0,1    0,1)     0,8 
                      Equilibrium Concentration            0,1      0,1       0,8
                      C= n/v                                 2       2         2
                                                          (0,05)   (0,05)   (0,4) 

        Kc =         [ HI ]2
                 [ H2 ] . [ I2 ] 
        Kc =       (0,4)2
                 (0,05) (0,05) 
        Kc =     64                                                                           (8)
                                                                                               [16]

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### Page 6

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Physical Science/P2                         6          June 2014 Common Test
                                    NSC – Memorandum

QUESTION 8

8.1
        8.1.1 C                                                      (1)

        8.1.2 A                                                      (1)

        8.1.3 E                                                      (1)

        8.1.4 B                                                      (1)

8.2     H2SO4 + 2H2O      → 2H3O+ + SO42–
        pH = –log [ H3O+] 
        pH = – log (2 x 0,1) 
        pH = 0,698                                                   (3)

8.3     Na2CO3 → Na+ + CO32- 

        CO32- + H2O  → HCO3– + OH–                                  (3)
                                                                      [10]

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### Page 7

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Physical Science/P2                                   7                      June 2014 Common Test
                                              NSC – Memorandum

QUESTION 9

9.1     Dilute acid contains a small number of moles of acid in proportion to the
        volume of water.                                                                   (1)

9.2     Standard solution is the solution of known concentration.                          (1)

9.3     c =     m
                MV         
        0,2  =           m
                      56 x 0,3 
        m = 3,36g                                                                          (4)

9.4     To change the colour at the end point of titration.  OR
        To indicate/show when equivalent number of moles of acid and base
        have reacted.                                                                       (1)

9.5     Bromothymol blue,  because the equivalent point will be approximately
        pH = 7 since H2SO4 is a strong acid and KOH is a strong base.                      (2)

9.6
        Ca x Va                    na
                          
        Cb x Vb                    nb 
        Ca x 20,15                1
                     
        15,04 x 0,2                2 
        Ca                        0,075 mol.dm
                                                3

                                                                                            (4)
                                                                                            [13]

                                                                   TOTAL SECTION B: 86
                                                                      GRAND TOTAL: 100

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