# Physical Sciences Grade 12 P1 NSC Supplementary 2013 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the NSC Supplementary 2013, 17 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2013
- Exam period: NSC Supplementary
- Paper: 1
- Curriculum: CAPS
- Pages: 17

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Physical Sciences · Grade 12 · NSC Supplementary · 2013. Memorandum, 17 pages. Read online or download the PDF.

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### Page 1

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                                      NATIONAL
                                 SENIOR CERTIFICATE
                                     NASIONALE
                                 SENIOR SERTIFIKAAT

                                   GRADE/GRAAD 12

                        PHYSICAL SCIENCES: PHYSICS (P1)
                        FISIESE WETENSKAPPE: FISIKA (V1)

                  FEBRUARY/MARCH/FEBRUARIE/MAART 2013

                                        MEMORANDUM

MARKS/PUNTE: 150

                        This memorandum consists of 18 pages.
                      Hierdie memorandum bestaan uit 18 bladsye.

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Physical Sciences P1/Fisiese Wetenskappe V1    2               DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

SECTION A

QUESTION 1/VRAAG 1

1.1       X-rays/X-strale                                                                        (1)

1.2       Momentum                                                                               (1)

1.3       Huygens (principle)/Huygens (se beginsel)                                              (1)

1.4       ampere/ampère                                                                          (1)

1.5       Isolated/closed                                                                        (1)
          Geïsoleerde/geslote                                                                     [5]

QUESTION 2/VRAAG 2

2.1       B                                                                                     (2)

2.2       A                                                                                     (2)

2.3       A                                                                                     (2)

2.4       D                                                                                     (2)

2.5       A                                                                                     (2)

2.6       D                                                                                     (2)

2.7       B                                                                                     (2)

2.8       A                                                                                     (2)

2.9       B                                                                                     (2)

2.10      C                                                                                      (2)
                                                                                                  [20]

                                          TOTAL SECTION A/TOTAAL AFDELING A:                      25

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Physical Sciences P1/Fisiese Wetenskappe V1    3                      DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

SECTION B/AFDELING B

QUESTION 3/VRAAG 3

3.1       50 N downwards/afwaarts                                                                     (2)

3.2
3.2.1     OPTION 1/OPSIE 1                                  Notes/Aantekeninge
          Downward positive:
          Afwaarts positief:                                Accept/Aanvaar: g or/of a
                                                            Accept/Aanvaar:
          v f = v i + 2a∆y 
             2     2

                                                            v 2f = v i2 + 2a∆x
          ∴ v f = 0 + 2(9,8)(0,8) 
              2    2
                                                            v 2 = u 2 + 2as
          ∴ v f = 3,96 m∙s-1  downward /afwaarts
          Downward negative:
          Afwaarts negatief:
          v f = v i + 2a∆y 
             2     2

          ∴ v f = 02 + 2(-9,8)(-0,8) 
              2

          ∴ v f = -3,96 m∙s-1
          ∴v f = 3,96 m∙s-1  downward /afwaarts
          OPTION 2/OPSIE 2                                  Notes/Aantekeninge
          (E p + E k ) top/bo = (E p + Ek) bottom/onder 
          mgh + 0 = 0 + ½mv2                                Accept/Aanvaar:
          (9,8)(0,8) = ½ v2                                (U + K) top/bo = (U + K) bottom/onder
          v = 3,96 m∙s-1  downward/afwaarts                                                           (4)

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Physical Sciences P1/Fisiese Wetenskappe V1    4                 DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

3.2.2     POSITIVE MARKING FROM QUESTION 3.2.1              Notes/Aantekeninge:
          POSITIEWE NASIEN VAN VRAAG 3.2.1                  Substitution: F app and v f must
          OPTION 1/OPSIE 1                                  have the same sign.
          Downward positive/Afwaarts positief:              Substitusie: F app en v f moet
          F net Δt = Δp OR F net Δt = m(v f – v i )        dieselfde tekens hê.
          (F app + mg)Δt = Δp
          (-50 + (0,2)(9,8)Δt  = 0,2(- 3,43 – 3,96) 
          ∴ Δt = 0,03 s  (3 x 10-2 s)
          Downward negative/Afwaarts negatief:
          F net Δt = Δp OR F net Δt = m(v f – v i ) 
          (F app + mg)Δt = Δp
          (50 - (0,2)(9,8)Δt = 0,2[3,43 – (-3,96)] 
          ∴ Δt = 0,03 s  (3 x 10-2 s)
          OPTION 2/OPSIE 2                                  Notes/Aantekeninge
          Downward positive/Afwaarts positief:              Accept/Aanvaar:
          F net = ma                                        v = u + at
          F app + mg = ma                                   v f = v i + a ∆t
          (-50 + (0,2)(9,8) = 0,2a  both formulae
          ∴ a = -240,2 m∙s-2         beide formules

          v f = vi + a ∆t
          -3,43 = 3,96 + (-240,2)∆t 
          ∴ Δt = 0,03 s  (3 x 10-2 s)
          Downward negative/Afwaarts negatief:
          F net = ma
          F app + mg = ma
          (50 – (0,2)(9,8) = 0,2a  both formulae
          ∴ a = 240,2 m∙s  -2
                                    beide formules

          v f = vi + a ∆t
          3,43 = -3,96 + (240,2)∆t 
          ∴ Δt = 0,03 s  (3 x 10-2 s)                                                              (4)

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Physical Sciences P1/Fisiese Wetenskappe V1    5                                        DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

3.3       POSITIVE MARKING FROM QUESTION 3.2.
          POSITIEWE NASIEN VAN VRAAG 3.2.

          OPTION/OPSIE 1
          Ground as zero reference and downward negative:
          Grond as nulverwysing en afwaarts negatief:

                                                                                                Marks/
                                 Criteria for graph/Kriteria vir grafiek:
                                                                                                Punte
                                 Correct shape (both curves)
                                                                                                   
                                 Korrekte vorm (beide krommes)
                                 Graph starts at y = 0,8 m at t = 0 s
                                                                                                   
                                 Grafiek begin by y = 0,8 m at t = 0 s
                                 Second maximum height at y = 0,6 m
                                                                                                   
                                 Tweede maksimum by y = 0,6 m s
                                 Contact time shown as space on x axis between two curves.
                                 Kontaktyd aangetoon as spasie op x-as tussen twee                 
                                 krommes.
                                 Time at which ball leaves the floor shown as t = 0,434 s.
                                                                                                   
                                 Tyd wanneer die bal die vloer verlaat getoon as t = 0,434 s.

                                 0,8

          Position/Posisie (m)
                                 0,6

                                    0
                                              0,404 0,434          Time/tyd(s)

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Physical Sciences P1/Fisiese Wetenskappe V1    6                           DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

          OPTION/OPSIE 2
          Ground as zero reference and downward positive:
          Grond as nulverwysing en afwaarts positief:

                                                                                   Marks/
             Criteria for graph/Kriteria vir grafiek:
                                                                                   Punte
             Correct shape (both curves)
                                                                                      
             Korrekte vorm (beide krommes)
             Graph starts at y = -0,8 m at t = 0 s
                                                                                      
             Grafiek begin by y = -0,8 m at t = 0 s
             Second maximum height at y = -0,6 m
                                                                                      
             Tweede maksimum by y = -0,6 m s
             Contact time shown as space on x axis between two curves.
             Kontaktyd aangetoon as spasie op x-as tussen twee                        
             krommes.
             Time at which ball leaves the floor shown as t = 0,434 s.
                                                                                      
             Tyd wanneer die bal die vloer verlaat getoon as t = 0,434 s.

                                             0,404 0,43
                                         0         4

               Position/Posisie (m)
                                                          Time/tyd(s)

                                      -0,6

                                      -0,8
                                                                                                              (5)
                                                                                                              [15]

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Physical Sciences P1/Fisiese Wetenskappe V1    7                       DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 4/VRAAG 4
4.1       The total (linear) momentum remains constant/is conserved 
          in an isolated/a closed system/the absence of external forces. 

          Die totale lineêre momentum bly konstant/behoue 
          in 'n geïsoleerde sisteem/geslote sisteem/die afwesigheid van eksterne
          kragte. 
          Notes/Aantekeninge:
          The mark for 'closed/isolated system' is only awarded if used in conjunction with
          momentum.
          Die punt vir 'geslote/geïsoleerde sisteem' word slegs toegeken indien saam met
          momentum gebruik.
          Accept: The total momentum before a collision equals the total momentum after a
          collision in a closed system.
          Aanvaar: Die totale momentum voor 'n botsing is gelyk aan die totale momentum na
          'n botsing in 'n geslote sisteem.                                                              (2)
4.2       To the right as positive/Na regs as positief:
          Σ p before/voor = Σ p after/na 
          (0,01)(300) + (1,99)(0) = (0,01 + 1,99)v f2 
          ∴ v f2 = 1,5 m·s-1 
          To the right as negative/Na regs as negatief:
          Σ p before/voor = Σ p after/na 
          (0,01)(-300) + (1,99)(0) = (0,01 + 1,99)v f2 
          ∴v f2 = -1,5 m·s-1
          ∴v f2 = 1,5 m·s-1 
          Other formulae/Ander formules:              Notes/Aantekeninge:
          m 1 v i1 + m 2 v i2 = m 1 v f1 + m 2 v f2                                    3
          or/of                                       If no formula/principle – Max.
                                                                                       4
          m 1u 1 + m 2u 2 = m 1v1 + m 2v2                                                     3
          or/of                                       Indien geen formule/beginsel – Maks.
          m 1 v i1 + m 2 v i2 = (m 1 + m 2 )v f2                                              4          (4)
4.3       Inelastic/Onelasties 
          Kinetic energy is not conserved./Kinetiese energie bly nie behoue nie.
          OR/OF
          Inelastic/Onelasties
          Objects stick together/Voorwerpe heg aan mekaar. 
          OR/OF
          Inelastic/Onelasties
          Structural damage to the block./Strukturele skade aan blok. 
          OR/OF
          Inelastic/Onelasties
          There is deformation to the block/bullet./Daar is vervorming van die blok.
          OR/OF
          Inelastic/Onelasties 
          Energy converted to other forms such as sound and heat./Energie word
          omgeskakel na ander vorms soos klank en hitte.                                                (2)

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Physical Sciences P1/Fisiese Wetenskappe V1    8                        DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

4.4       POSITIVE MARKING FROM QUESTION 4.2.
          POSITIEF NASIEN VAN VRAAG 4.2.
          Option 1/Opsie 1:                         Notes/Aantekeninge:
          W net = ΔK                               Accept/Aanvaar:
          OR /OF                                    Ek
                          1         1
          F net ∆xcos θ =   mv 2f − mv i2
                          2         2
                              1
          (8)Δxcos180°  =        (2)(02 − 1,52 ) 
                              2
          ∴ ∆x = 0,28 m 

          Option 2/Opsie 2:                           Notes/Aantekeninge:
          F net = ma                                  Accept/Aanvaar:
          ∴ (-8) = 2a                                v f = v i + 2a∆y
                                                         2    2

          ∴ a = - 4 m·s-2               Both         v 2 = u 2 + 2as
                                        formulae
          v f = v i + 2a∆x
            2     2
                                        Beide
          02 = (1,5)2 + 2(-4) ∆x       formules
          ∴ ∆x = 0,28 m 
                                                                                                         (4)
                                                                                                         [12]

QUESTION 5/VRAAG 5

5.1       The total mechanical energy remains constant/is conserved
          in an isolated/closed system. 
          Die totale meganiese energie bly konstant/bly behoue
          in 'n geïsoleerde/geslote sisteem

          OR/OF
          The sum of the potential and kinetic energy remains constant 
          in an isolated/closed system. 
          Die som van die potensiële en kinetiese energies bly konstant
          in 'n geïsoleerde/geslote sisteem

          Notes/Aantekeninge:
          The mark for 'closed/isolated system' is only awarded if used in conjunction with
          energy.
          Die punt vir 'geslote/geïsoleerde sisteem' word slegs toegeken indien saam met
          energie gebruik.                                                                                (2)

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Physical Sciences P1/Fisiese Wetenskappe V1    9                        DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

5.2
5.2.1     Free-body diagram                     Accept/Aanvaar: Force diagram/kragtediagram
          Vrye kragtediagram
                                                                           

                        w                                                w
                                   Accepted labels/Aanvaarde benoemings
                   F g /F w /force of Earth on boy/weight/392 N/mg/gravitational force
          w
                   F g /F w /krag van Aarde op seun/gewig/392 N/mg/gravitasiekrag
                                                                                                           (1)

5.2.2
         Free-body diagram                                          Accept: Force diagram
         Vrye kragtediagram                                         Aanvaar: Kragtediagram
           f        N                                                f            N
                    
                                                                                

                     w                                                         w

              OR/OF                                                             OR/OF

              f                                                       f            N
                          N
                                                                               
                          w//                                                        w//
                                                                     w⊥         
              w⊥
                                          Accepted labels/Aanvaarde benoemings
                   F g /F w /force of Earth on girl/weight/215,6 N/mg/gravitational force
          w
                   F g /F w /krag van Aarde op meisie/gewig/215,6 N/mg/gravitasiekrag
                   F friction /F f /friction
          f
                   F wrywing /F f /F w /wrywing
          N        F N /F normal /normal force/force of slide or surface on girl
                                                                                                            (3)

5.3                                     1                 1                     Notes/Aantekeninge:
          K i + U i = K f + U f  OR      mv i2 + mgh i =   mv 2f + mgh f       Accept/Aanvaar
                                        2                 2
                                                                                Ep & Ek
                                     1
          0 + (40)(9,8)(1,5)  =       ( 40)v 2f + 0 
                                     2
          ∴ v f = 5,42 m·s-1                                                                              (4)

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Physical Sciences P1/Fisiese Wetenskappe V1   10                      DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

5.4      Option 1/Opsie 1                                                             Accept/
         W net = ΔK                                                                  Aanvaar:
                                1         1                                           ∆y/∆x
         w∆xcos θ + f∆xcos θ =    mv 2f − mv i2
                                2         2
                                  1         1
         mg∆xcos θ + f∆xcos θ =     mv 2f − mv i2
                                  2         2
                                                        1
         (22)(9,8)(3)cos60°  + (1,9)(3)cos180° =        (22)( v 2f − 02 ) 
                                                        2
         ∴ v f = 5,37 m·s-1 
         Option 2/Opsie 2                                                             Accept/
         W net = ΔK                                                                  Aanvaar:
         w//∆xcos θ + f∆xcos θ = ½ mv f 2 – ½ mv i 2                                  ∆y/∆x
                                     1         1
         mgsin θ xcos θ + f∆xcos θ =    mv 2f − mv i2
                                     2         2
                                                              1
         (22)(9,8)sin30°(3)cos0°  + (1,9)(3)cos180° =         (22)( v 2f − 02 ) 
                                                              2
         ∴ v f = 5,37 m·s-1 
         Option 3/Opsie 3                                                             Accept/
         W net = ΔK                                                                  Aanvaar
                                    1        1                                        h/∆y/∆x
         mghcos θ + f∆xcos θ =        mv 2f − mv i2
                                    2        2
                                                        1
         (22)(9,8)(1,5)cos0°  + (1,9)(3)cos180° =       (22)( v 2f − 02 ) 
                                                        2
         ∴v f = 5,37 m·s-1 

         Option 4/Opsie 4                                                             Accept/
         W net = ΔK                                                                  Aanvaar
         - ∆U + W f = ∆K                                                              h/∆y/∆x
         - (mgh f – mgh i ) + W f = ∆K
                                                        1
         - (0 – (22)(9,8)(1,5)  + (1,9)(3)cos180° =     (22)( v 2f − 02 ) 
                                                        2
         ∴ v f = 5,37 m·s-1                                                                            (5)

5.5       Equal to/Gelyk aan                                                                            (1)
                                                                                                        [16]

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Physical Sciences P1/Fisiese Wetenskappe V1   11                     DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 6/VRAAG 6

6.1       The approaching observer (higher f) passes the source at t = 6 s and moves
          away (lower f) from the source. 
          Die naderende waarnemer (hoër f) beweeg verby die bron by t = 6 s en
          beweeg weg (laer f) van die bron af.                                                         (1)

6.2

6.2.1     OPTION 1/OPSIE 1                          Notes:
          Approaching observer:                     • Any other Doppler formula, e.g.
          Naderende waarnemer:                              v − vL
                                                       fL =        - Max. 3
               v ± vL                 v + vL                v − vs          4
          fL =        f s OR/OF fL =         fs 
               v ± vs                    v
                                                    Aantekeninge:
                         340 + v L
          ∴ 900  =                (850)          • Enige ander Dopplerformule, bv.
                           340                              v − vL
          ∴ v L = 20 m∙s-1                            fL =        - Maks. 3
                                                            v − vs           4
          OPTION 2 / OPSIE 2
          Observer moving away:
          Waarnemer beweeg weg:
               v ± vL                 v − vL
          fL =        f s OR/OF fL =         fs 
               v ± vs                   v
                         340 − v L
          ∴800  =                 (850) 
                           340
          ∴ v L = 20 m∙s-1                                                                            (5)

6.2.2     POSITIVE MARKING FROM QUESTION 6.2.1
          POSITIEWE NASIEN van VRAAG 6.2.1
          Option 1/Opsie 1:                Notes/Aantekeninge
          Δx = v i Δt + 2 a∆t 
                        1    2             Accept/Aanvaar:
                                           s = ut / s = vt
             = (20)(6) + ½(0) ∆ t
          ∴ ∆ x = 120 m                   s = ut + 1 at 2
                                                     2
                                                    Δy = v i Δt + 1 a∆t 2
          Option 2/Opsie 2:                                       2
          Δx = vΔ t 
             = (20)(6) 
          ∴ ∆ x = 120 m 
                                                                                                       (3)
                                                                                                       [9]

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Physical Sciences P1/Fisiese Wetenskappe V1   12               DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 7/VRAAG 7

7.1       B                                                                                      (1)

7.2       Constructive  interference 
          Konstruktiewe interferensie                                                              (2)

7.3
7.3.1     c = fλ                                           Notes/Aantekeninge
          3 x 108 = 4,54 x 1014 λ                          Accept/Aanvaar v = f λ
          ∴ λ = 6,61 x 10-7 m                                                                     (3)

7.3.2    POSITIVE MARKING FROM QUESTION 7.3.1
         POSITIEWE NASIEN VAN VRAAG 7.3.1
         OPTION 1/OPSIE 1                                   Notes/Aantekeninge
                  1 central band                            Accept final answer in range:
         tan θ =   2                                        9,94 x10-6 to 9,95 x10-6 m
                 screen dis tan ce                          Aanvaar finale antwoorde in
                     1 (0,2)                               die gebied:
                                                            9,94 x10-6 to 9,95 x10-6 m
         ∴ tan θ = 2
                       1,5 
                                                            IF distance is not half of
         ∴ θ = 3,81°
                                                                                 4
                mλ                                          central band: Max
         sin θ =                                                                6
                 a                                          INDIEN afstand nie helfte van
                     (1)(6,61× 10 −7 )                                                 4
         sin3,81° =                                       sentrale band is nie: Maks
                            a                                                          6
         ∴ a = 9,95 x 10-6 m 
         OPTION 2/OPSIE 2                                   Notes/Aantekeninge
                  1 central band                            Accept final answer in range:
         tan θ =   2                                        9,94 x10-6 to 9,95 x10-6 m
                 screen dis tan ce                          Aanvaar finale antwoorde in
                     1 (0,2)                               die gebied:
                                                            9,94 x10-6 to 9,95 x10-6 m
         ∴ tan θ = 2
                       1,5 
                                                            IF distance is not half of
         ∴ θ = 3,81°
                                                                                 4
                                                            central band: Max
                   mλ                                                            6
         sin θ =      
                    a                                       INDIEN afstand nie helfte van
                       ( −1)(6,61× 10 −7 )                  sentrale band is nie: Maks
                                                                                       4
         sin(-3,81°) =                                                               6
                                a
         ∴ a = 9,95 x 10-6 m                                                                      (6)

7.4       Decreases/Verminder                                                                    (1)
                                                                                                  [13]

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Physical Sciences P1/Fisiese Wetenskappe V1   13                     DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 8/VRAAG 8

8.1       Stores (electric) charge/energy. 
          Stoor (elektriese) lading/energie.

          OR/OF
          Releases (stored) charge instantly/very fast. 
          Stel (gestoorde) lading onmiddellik vry/baie vinnig vry.                                    (1)

8.2       The brightness of the bulb decreases (gradually) 
          until it stops glowing/dies.
          Die helderheid van die gloeilamp verminder (geleidelik).

          OR/OF
          The bulb glows dimmer 
          until it stops glowing/dies.
          Die gloeilamp gloei flouer totdat dit ophou gloei/uitbrand.                                 (1)

8.3
8.3.1     0 (V)                                                                                      (1)

8.3.2     12 V                                                                                       (1)

8.4       POSITIVE MARKING FROM QUESTION 8.3.2.
          POSITIEWE NASIEN VAN VRAAG 8.3.2.
             V
8.4.1     E=    
              d
                 12
           =              
             5,4 × 10 − 3
           = 2,22 x 103 V·m-1  (2 222,22 V·m-1)                                                      (3)

8.4.2     POSITIVE MARKING FROM QUESTION 8.4.1.
          POSITIEWE NASIEN VAN VRAAG 8.4.1.
              F
          E= 
              q
                              F
          ∴ 2,22 x 103 =              
                         1,6 × 10 −19
          ∴ F = 3,56 x 10-16 N                                                                       (3)

8.5
8.5.1     5,4 mm – 3,8 mm = 1,6 mm                                                                   (1)

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Physical Sciences P1/Fisiese Wetenskappe V1   14                    DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

8.5.2     POSITIVE MARKING FROM QUESTION 8.4.2 & 8.5.1.
          POSITIEWE NASIEN VAN VRAAG 8.4.2 & 8.5.1.
          W = FΔxcosθ 
            = (3,56 x 10-16)(1,6 x 10-3)cos 0°
            = 5,69 x 10-19 J 

                                                                                                       (4)
                                                                                                      [15]

QUESTION 9/VRAAG 9

9.1
9.1.1     Potential difference/Potensiaalverskil                                                     (1)

9.1.2     Temperature/Temperatuur 
          Resistance/Weerstand                                                                        (1)

9.1.3     Current is directly proportional to potential difference. 
          Stroom is direk eweredig aan potensiaalverskil

          OR/OF
          The ratio of potential difference to current is constant. 
          Die verhouding van potensiaalverskil tot stroom is konstant.
          IF/INDIEN:
          Current is proportional to potential difference. 
          Stroom is eweredig aan potensiaalverskil.                                                   (2)

9.1.4                    0,18 − 0                         Notes/Aantekeninge:
          Gradient/m =             = 0,36                  Accept any set of correct values
                          0,5 − 0 
                                                           from the graph.
                 1                                         Aanvaar enige stel waardes vanaf
          R=        = 2,78 Ω 
               0,36                                        die grafiek.                               (4)

9.2
9.2.1      1   1   1
             =   +   
          R p R1 R 2
                1 1
               =  +    
                6 10
          ∴ R p = 3,75 Ω                                                                             (3)

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Physical Sciences P1/Fisiese Wetenskappe V1   15               DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

9.2.2     POSITIVE MARKING FROM QUESTION 9.2.1.
          POSITIEWE NASIEN VAN VRAAG 9.2.1.
          OPTION 2 / OPSIE 2                                 Notes/Aantekeninge
          V p = I 10 Ω R                                     Do not penalise for
              = 0,6 x 10                                    subscripts.
              = 6V                Any one                   Moenie penaliseer indien
                                  Enige een                  onderskrifte weggelaat is
                Vp
          Ip =                                               nie.
                Rp
                 6
             =       
               3,75
             = 1,6 A 

          OPTION 1/OPSIE 2                                   Notes/Aantekeninge
          V 10 Ω = I 10 Ω R                                  Do not penalise for
                 = 0,6 x 10                                 subscripts.
                 = 6V                     Any one           Moenie penaliseer indien
                                           Enige een         onderskrifte weggelaat is
                  V
          I 6Ω =                                             nie.
                  R
                 6
               =    
                 6
               =1A

          I tot = 1 + 0,6 = 1,6 A                                                                (4)

9.2.3     POSITIVE MARKING FROM QUESTION 9.2.1.
          POSITIEWE NASIEN VAN VRAAG 9.2.1.
          E = I(R + r) 
          30  = 1,6(3,75 + 5 + 8 + r) 
          ∴r=2Ω                                                                                   (4)
                                                                                                  [19]

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Physical Sciences P1/Fisiese Wetenskappe V1   16                   DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 10/VRAAG 10

10.1      Q/split ring commutator/commutator 
          Q/splitringkommutator/kommutator                                                           (1)

10.2      Replace Q/split ring commutator with slip rings. 
          Vervang Q/splitringkommutator met sleepringe.                                              (1)

10.3      AC can be stepped-up at power stations/WS kan by die kragstasie verhoog
          word 
          to reduce energy loss during transmission./om energieverlies tydens
          transmissie te verminder.                                                                 (2)

10.4                                                     Notes/Aantekeninge
10.4.1               I                                   If subscripts omitted: no mark for
          I rms/wgk = max/maks                          formula
                          2                              Indien onderskifte weggelaat is:
                    0,35                                 geen punt vir formule
                 =        
                       2
          ∴ I rms/wgk = 0,25 A                                                                      (3)

10.4.2    OPTION 1/OPSIE 1                        Notes/Aantekeninge
                           2
                         Vrms/wgk                 Do not penalise if subscripts are omitted.
          Pave / gemid =                         Moenie penaliseer indien onderskrifte
                            R                     weggelaat is nie
                   240 2
          60 =            
                     R
          ∴ R = 960 Ω 

          OPTION 2/OPSIE 2
          P ave/gemid = I2 rms/wgk R 
          60 = (0,25)2R 
          ∴ R = 960 Ω 
          OPTION 3/OPSIE 3                        Notes/Aantekeninge
               Vrms/wgk                           Accept/Aanvaar:
          R=                                          V
                Irms/wgk                          R=     as formula/formule
                                                       I
               240
            =      
              0,25
            = 960 Ω                                                                                  (3)
                                                                                                     [10]

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Physical Sciences P1/Fisiese Wetenskappe V1   17                    DBE/Feb.–Mar./Feb.–Mrt. 2013
                                     NSC/NSS – Memorandum

QUESTION 11/VRAAG 11

11.1      Quantum/packet of energy/Kwantum/pakkie energie
          found in light/In lig gevind                                                            (2)

11.2
11.2.1    OPTION 1/OPSIE 1
              hc
          E=     
               λ                            
                  -19    (6,63 × 10 −34 )(3 × 108 )
          6,9 x 10  =
                                λ
          ∴ λ = 2,9 x 10-7 m 

          OPTION 2 / OPSIE 2                              Notes/Aantekeninge
          E = hf                                          Accept/Aanvaar: v = f λ
          6,9 x 10-19  = 6,63 x 10-34f        Both
                                               formulae
          ∴ f = 1,04 x 1015 Hz                 Beide
                                               formules
          c = fλ
          3 x 108 = 1,04 x 1015 λ 
          ∴ λ = 2,88 x 10-7 m                                                                     (5)

11.2.2    E = Wo + Ek 
          6,9 x 10-19 = 6,4 x 10-19 + E k 
          ∴ E k = 5 x 10-20 J                                                                     (3)

11.3
11.3.1    Increases/Vermeerder 
          • More photons (packets of energy) strike the surface of the metal per unit
             time./Meer fotone (pakkies energie) tref die oppervlakte van die metaal per
             eenheid tyd. 
          • More (photo)electrons ejected per unit time./Meer (foto)elektrone vrygestel
             per eenheid tyd.                                                                     (3)

11.3.2    Increases/Vermeerder 
          • (Photo)electrons are emitted with higher kinetic energy/move faster./
             (Foto)elektrone word vrygestel met hoër kinetiese energie/beweeg
             vinniger. 
           • Increase in rate of flow of charge./Same number of charges pass a point
             in a shorter time./Toename in tempo van vloei van lading/dieselfde
             aantal lading beweeg verby 'n punt in 'n korter tyd.                                  (3)
                                                                                                   [16]

                                               TOTAL SECTION B/TOTAAL AFDELING B:                  125
                                                      GRAND TOTAL/GROOTTOTAAL:                     150

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