# Physical Sciences Grade 12 P1 Eastern Cape June 2023 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the Eastern Cape June Exam 2023 (Afrikaans), 15 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physical-sciences-p1-gr12-memo-june2023-afrikaans-english/38d6a2ec-d61a-4ef7-9f06-6b4ddabddaad
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Language: Afrikaans
- Document type: Memorandum
- Year: 2023
- Exam period: Eastern Cape June Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 15

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## About this document

Physical Sciences · Grade 12 · Eastern Cape June Exam · 2023 · Afrikaans. Memorandum, 15 pages. Read online or download the PDF.

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### Page 1

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                            NATIONAL
                       SENIOR CERTIFICATE /
                            NASIONALE
                        SENIORSERTIFIKAAT

                        GRADE/GRAAD 12

                        JUNE/JUNIE 2023

                 PHYSICAL SCIENCES P1
                   MARKING GUIDELINE/
                FISIESE WETENSKAPPE V1
                      NASIENRIGLYN
MARKS/PUNTE:     150

                   This marking guideline consists of 15 pages.
                    Hierdie nasienriglyn bestaan uit 15 bladsye

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2                 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                    (EC/JUNE/JUNIE 2023

GENERAL GUIDELINES/ALGEMENE RIGLYNE

1.     CALCULATIONS/BEREKENINGE

       1.1    Marks will be awarded for: correct formula, correct substitution, correct
              answer with unit.
              Punte sal toegeken word vir: korrekte formule, korrekte substitusie, korrekte
              antwoord met eenheid.

       1.2    No marks will be awarded if an incorrect or inappropriate formula is used,
              even though there are many relevant symbols and applicable substitutions.
              Geen punte sal toegeken word waar ŉ verkeerde of ontoepaslike formule
              gebruik word nie, selfs al is daar relevante simbole en relevante substitusies.

       1.3    When an error is made during substitution into a correct formula, a mark will
              be awarded for the correct formula and for the correct substitutions, but no
              further marks will be given.
              Wanneer ŉ fout gedurende substitusie in ŉ korrekte formule begaan word,
              sal ŉ punt vir die korrekte formule en vir korrekte substitusies toegeken word,
              maar geen verdere punte sal toegeken word nie.

       1.4    If no formula is given, but all substitutions are correct, a candidate will forfeit
              one mark.
              Indien geen formule gegee is nie, maar al die substitusies is korrek, verloor
              die kandidaat een punt.

       1.5    No penalisation if zero substitutions are omitted in calculations where
              correct formula/principle is correctly given.
              Geen penalisering indien nulwaardes nie getoon word nie in berekeninge
              waar die formule/beginsel korrek gegee is nie.

       1.6    Mathematical manipulations and change of subject of appropriate formulae
              carry no marks, but if a candidate starts off with the correct formula and then
              changes the subject of the formula incorrectly, marks will be awarded for the
              formula and correct substitutions. The mark for the incorrect numerical answer
              is forfeited.
              Wiskundige manipulasies en verandering van die onderwerp van toepaslike
              formules tel geen punte nie, maar indien ŉ kandidaat met die korrekte formule
              begin en dan die onderwerp van die formule verkeerde verander, sal die punte
              vir die formule en korrekte substitusies toegeken word. Die punt vir die
              verkeerde numeriese antwoord word verbeur.

       1.7    Marks are only awarded for a formula if a calculation has been attempted,
              i.e. substitutions have been made or a numerical answer given.
              Punte word slegs vir ŉ formule toegeken indien ŉ poging tot ŉ berekening
              aangewend is, d.w.s. substitusies is gedoen of ŉ numeriese antwoord is gegee.

       1.8    Marks can only be allocated for substitutions when values are substituted into
              formulae and not when listed before a calculation starts.
              Punte kan slegs toegeken word vir substitusies wanneer waardes in formule
              ingestel word en nie vir waardes wat voor ŉ berekening gelys is nie.

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                          3

       1.9     All calculations, when not specified in the question, must be done to a minimum
               of two decimal places.
               Alle berekenings, wanneer nie in die vraag gespesifiseer word nie, moet tot ŉ
               minimum van twee desimale plekke gedoen word.

       1.10 If a final answer to a calculation is correct, full marks will not automatically be
            awarded. Markers will always ensure that the correct/appropriate formula is
            used and that workings, including substitutions, are correct.
            Indien ŉ finale antwoord van ŉ berekening korrek is, sal volpunte nie outomaties
            toegeken word nie. Nasieners sal altyd verseker dat die korrekte/toepaslike
            formule gebruik word en dat bewerkings, insluitende substitusies korrek is.

       1.11 Questions where a series of calculations have to be made (e.g. a circuit diagram
            question) do not necessarily always have to follow the same order. FULL
            MARKS will be awarded provided it is a valid solution to the problem. However,
            any calculation that will not bring the candidate closer to the answer than the
            original data, will not count any marks.
            Vrae waar ŉ reeks berekeninge gedoen moet word (bv. ŉ stroombaan-
            diagramvraag) hoef nie noodwendig dieselfde volgorde te hê nie. VOLPUNTE
            sal toegeken word op voorwaarde dat dit ŉ geldige oplossing vir die probleem
            is. Enige berekening wat egter nie die kandidaat nader aan die antwoord as die
            oorspronklike data bring nie, sal geen punte tel nie.

 2.    UNITS/EENHEDE

       2.1     Candidates will only be penalised once for the repeated use of an incorrect unit
               within a question.
               Kandidate sal slegs een keer gepenaliseer word vir die herhaaldelike gebruik
               van ŉ verkeerde eenheid in ŉ vraag.

       2.2     Units are only required in the final answer to a calculation.
               Eenhede word slegs in die finale antwoord op ŉ vraag verlang.

       2.3     Marks are only awarded for an answer, and not for a unit per se. Candidates
               will therefore forfeit the mark allocated for the answer in each of the following
               situations:
               • Correct answer + wrong unit
               • Wrong answer + correct unit
               • Correct answer + no unit
               Punte sal slegs vir ŉ antwoord en nie vir ŉ eenheid per se toegeken word nie.
               Kandidate sal die punt vir die antwoord in die volgende gevalle verbeur:
               • Korrekte antwoord + verkeerde eenheid
               • Verkeerde antwoord + korrekte eenheid
               • Korrekte antwoord + geen eenheid

       2.4     SI units must be used except in certain cases, e.g. V.m-1 instead of N.C-1, and
               cm.s-1 or km.h-1 instead of m.s-1 where the question warrants this.
               SI eenhede moet gebruik word, behalwe in sekere gevalle, bv. V.m-1 in plaas
               van N.C-1, en cm.s-1 of km.h-1 in plaas van m.s-1 waar die vraag dit regverdig.

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4                 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                    (EC/JUNE/JUNIE 2023

3.   GENERAL/ALGEMEEN

     3.1 If one answer or calculation is required, but two are given by the candidate, only
         the first one will be marked, irrespective of which one is correct. If two answers
         are required, only the first two will be marked, etc.
         Indien een antwoord of berekening verlang word, maar twee word deur die
         kandidaat gegee, sal slegs die eerste een nagesien word, ongeag watter een
         korrek is. Indien twee antwoorde verlang word, sal slegs die eerste twee nagesien
         word, ens.

     3.2 For marking purposes, alternative symbols (s, u, t etc) will also be accepted.
         Vir nasiendoeleindes sal alternatiewe simbole (s, u, t ens) ook aanvaar word.

     3.3 Separate compound units with a multiplication dot, no a full stop, for example,
         m.s-1.
         For marking purposes, m.s-1 and m/s will also be accepted.
         Skei saamgestelde eenhede met ŉ vermenigvuldigingspunt en nie met ŉ punt nie,
         byvoorbeeld m.s-1. Vir nasiendoeleindes sal m.s-1 en m/s ook aanvaar word.

4.   POSITIVE MARKING/POSITIEWE NASIEN

     Positive marking regarding calculations will be followed in the following cases:
     Positiewe nasien met betrekking tot berekeninge sal in die volgende gevalle geld:

     4.1 Subquestion to subquestion: When a certain variable is calculated in one
         subquestion (e.g. 3.1) and needs to be substituted in another
         (3.2 of 3.3), e.g. if the answer for 3.1 is incorrect and is substituted correctly in 3.2
         or 3.3, full marks are to be awarded for the subsequent subquestions.
         Subvraag na subvraag: Wanneer ŉ sekere veranderlike in een subvraag (bv.
         3.1) bereken word en dan in ŉ ander vervang moet word (3.2 of 3.3), bv. indien
         die antwoord vir 3.1 verkeerd is en word korrek in 3.2 of 3.3 vervang, word
         volpunte vir die daaropvolgende subvraag toegeken.

     4.2 A multistep question in a subquestion: If the candidate has to calculate, for
         example, current in die first step and gets it wrong due to a substitution error, the
         mark for the substitution and the final answer will be forfeited.
         ŉ Vraag met veelvuldige stappe in ŉ subvraag: Indien ŉ kandidaat bv. die
         stroom verkeerd bereken in ŉ eerste stap as gevolg van ŉ substitusiefout, verloor
         die kandidaat die punt vir die substitusie sowel as die finale antwoord.

5.   NEGATIVE MARKING/NEGATIEWE NASIEN

     Normally an incorrect answer cannot be correctly motivated if based on a conceptual
     mistake. If the candidate is therefore required to motivate in QUESTION 3.2 the answer
     given in QUESTION 3.1, and 3.1 is incorrect, no marks can be awarded for QUESTION
     3.2. However, if the answer for e.g. 3.1 is based on a calculation, the motivation for the
     incorrect answer could be considered.
     ŉ Verkeerde antwoord, indien dit op ŉ konsepsuele fout gebaseer is, kan normaalweg
     nie korrek gemotiveer word nie. Indien ŉ kandidaat gevra word om in VRAAG 3.2 die
     antwoord op VRAAG 3.1 te motiveer en 3.1 is verkeerd, kan geen punte vir VRAAG 3.2
     toegeken word nie. Indien die antwoord op bv. 3.1 egter op ŉ berekening gebaseer is,
     kan die motivering vir die verkeerde antwoord in 3.2 oorweeg word.

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                    5

QUESTION 1/VRAAG 1

1.1      C                                                                               (2)

1.2      D                                                                               (2)

1.3      B                                                                               (2)

1.4      B                                                                               (2)

1.5      B                                                                               (2)

1.6      A                                                                               (2)

1.7      C                                                                               (2)

1.8      A                                                                               (2)

1.9      C                                                                               (2)

1.10     D                                                                              (2)
                                                                                         [20]

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6                 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                  (EC/JUNE/JUNIE 2023

QUESTION/VRAAG 2

2.1   A body will remain in its state of rest or motion at constant velocity unless a non-
      zero resultant/net force acts on it. 

      ŉ Liggaam sal sy toestand van rus of beweging teen konstante snelheid behou,
      tensy ŉ nie-resulterende/netto krag daarop inwerk.                           (2)

2.2               OPTION 1/OPSIE 1                        OPTION 2/OPSIE 2

      Mark awarded for arrow and labelling./ Punt toegeken vir pyltjie en benoeming.
      Do not penalise for length of arrows since drawing is not drawn to scale. /
      Moenie vir die lengte van die pyltjies penaliseer nie aangesien die tekening nie
      volgens skaal is nie.

      Any other additional force(s) / Enige ander addisionele krag(te). Max./Maks. 3⁄4
      If force(s) do not make contact with body / Indien krag(te) nie met met die
      voorwerp kontak maak nie. Max./Maks. 3⁄4                                                 (4)

2.3   fk = μk N
      fk = μkmg cos θ       Any one / Enige een 
      fk = [(0,75) (60)(9,8 cos 15°) ] 
      fk = 425,97 N                                                                            (4)

2.4   DECREASE  As the angle increases the normal force decreases because
      (N ∝ cosθ). Frictional force will decrease since fk ∝ N. 

      VERLAAG. Soos die hoek toeneem sale die normaalkrag afneem aangesien
      (N ∝ cos𝜃). Wrywingskrag sal afneem aangesien fk ∝ N.                                     (2)

2.5   Positive marking from QUESTION 2.4/Positiewe nasien vanaf VRAAG 2.4
      Fnet = ma
      FApp + f// – ff = ma      Any one / Enige een 
      FApp + mg sin θ – ff = ma

      [120 + 60(9,8)(sin 15º)  - 425,97 ]= 60 x a 
      a = 4,44 m.s-2 (4,437) m.s-2                                                             (5)
                                                                                               [17]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                       7

QUESTION 3/VRAAG 3

3.1    Force of block downwards on table,  and force of table upwards on block. 

       Afwaartse krag van blok op tafel en opwaartse krag van tafel op blok.                  (2)

3.2    Fnet = ma
       T – Fg = ma Any one / Enige een 
       T – FH = ma
       Wooden box / Houtblok
       T = Fcos θ
       T = 24 cos 33,55˚ 
       T = 20 N
       T = 20 N
       Steel ball / Staalbal
       mg – 20 = 0
       m(9,8) – 20 = 0 
       m = 2,04 kg                                                                           (4)

3.3    ∆x = v∆t
       ∆x = 0,25 x 1,2 
       ∆x = 0,3 m                                                                            (2)

3.4    Δx = viΔt + ½ g Δt2                     Δx = viΔt + ½ g Δt2 
       0,55 = (0,25)Δt + ½(9,8)Δt2            -0,55 = (-0,25)Δt + ½(-9,8)Δt2 
       Δt = 0,31 s                             Δt = 0,31 s                                  (4)
                                                                                             [12]

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8                 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                 (EC/JUNE/JUNIE 2023

QUESTION/VRAAG 4

4.1   Each body in the universe attracts every other body with a force that is directly
      proportional to the product of their masses, and inversely proportional to the
      square of the distance between their centres. 

      Elke liggaam in die heelal trek elke ander liggaam aan met ŉ krag direk eweredig
      aan die produk van hul massas, en omgekeerd eweredig aan die kwadraat van
      die afstand tussen hul middelpunte.

      Each particle in the universe attracts every other particle with a force that is
      directly proportional to the product of their masses,  and inversely proportional
      to the square of the distance between them. 

      Elke deeltjie in die heelal trek elke ander deeltjie aan met ŉ krag direk eweredig
      aan die produk van hul massas, en omgekeerd eweredig aan die kwadraat van
      die afstand tussen hulle.                                                                (2)

4.2   F = GM1M2 
             r2
      1,34 x 10-10  = (6,67 x 10-11)(9 x 18)
                            r2
      r = 8,98 m (9 m)                                                                        (5)

4.3   LARGER / GROTER AS                                                                      (1)
                                                                                               [8]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                        9

QUESTION/VRAAG 5

5.1     Motion of an object where the only force acting on it is gravitational force/
        gravity. 

        Beweging waartydens die enigste krag wat op ŉ voorwerp inwerk, die
        gravitasiekrag is.                                                                     (2)

5.2.1 Downwards / Positive                       Upwards / Positive
      Afwaarts / Positief                        Opwaarts / Positief
      Δy = viΔt + ½ g Δt2                       Δy = viΔt + ½ g Δt2 
      Δy = (-15)(1,27) + ½(9,8)(1,27)2          Δy = (15)(1,27) + ½(-9,8)(1,27)2 
      Δy = -11,15 m                              Δy = 11,15 m
      Height / Hoogte = 11,15 x 2               Height / Hoogte= 11,15 x 2 
      = 22,3 m                                  = 22,3 m                                     (4)

5.2.2 Downwards / Positive                       Upwards / Positive
      Afwaarts / Positief                        Opwaarts / Positief
      vf = vi + gΔt                             vf = vi + gΔt 
      0 = -15 + 9,8Δt                           0 = 15 + -9,8Δt 
      Δt = 1,67 s                               Δt = 1,67 s                                  (3)

5.2.3 Downwards / Positive                       Upwards / Positive
      Afwaarts / Positief                        Opwaarts / Positief
      vf2 = vi2 + 2gΔy                          vf2 = vi2 + 2gΔy 
      vf2= (-15)2 + 2(9,8)(11,15)              vf2= (15)2 + 2(-9,8)(11,15) 
      vf = 21,06 m.s-1                          vf = 21,06 m.s-1                             (4)

5.3     DOWNWARDS POSITIVE/ AFWAARTS – POSITIEF
        v (m.s-1)                                        Marking criteria /
                                                         Nasienkriteria
                                                         • Shape / Vorm (straight
                 15                                         line / reguitlyn) 
                                                         • vi = -15 
                                                         • vground / grond = 21,06 
                                                         • Δt (B) = 1,67 s 

                              1,67
                                              Time (s)
                                              / Tyd

             21,06

                                                                                               (4)

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10                  PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1             (EC/JUNE/JUNIE 2023

       UPWARDS POSITIVE / OPWAARTS – POSITIEF
                                                     Marking criteria /
        V (m.s-1)                                    Nasienkriteria
            21,06                                    • Shape / Vorm (straight line /
                                                        reguitlyn) 
                                                     • vi = 15 
                                                     • vground / grond = - 21,06 
                                                     • Δt (B) = 1,67 s 

                                   1,67       Time (s)
                                              / Tyd

              15

                                                                                             (4)
                                                                                            [17]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                        11

QUESTION 6/VRAAG 6

6.1     In an isolated system, the total linear momentum is conserved.
                                                OR
        The total linear momentum before a collision is equal to the total linear
        momentum after a collision in a closed system. 

        In ŉ geїsoleerde sisteem is die totale lineêre momentum behoue.
                                                OF
        Die totale lineêre momentum voor botsing is gelyk aan die totale lineêre
        momentum na botsing in ŉ geslote sisteem.                                                (2)

6.2.1 mTvi + mcvi = mTvf + mcvf Any one / Enige een 
      mTvi + mcvi = (mT + mc)vf
      5600(10) + 1800(0) = (5600 + 1800) vf 
      vf = 7,57 m.s-1                                                                           (4)

      POSITIVE MARKING FROM QUESTION 6.2.1
      POSITIEWE NASIEN VANAF VRAAG 6.2.1
                 OPTION 1/OPSIE 1                 OPTION 2/OPSIE 2
6.2.2 Fnet.Δt= mvf - mvi               Fnet.Δt= mvf - mvi 
      Fnet x 0,59  = 5600(7,57 – 10)  Fnet x 0,59  = 1800(7,57 –0) 
      Fnet = -2,36 x 10 4               Fnet = 2,36 x 104 N  (23644,07 N)
      Fnet = 2,36 x 10 N  (23644,07 N)
                      4                 East(wards) / Oos(waarts)
      East(wards) / Oos(waarts)                                                                 (5)

6.3     DECREASE/AFNEEM                                                                         (1)

6.4     Fnet α 1 / the net force is inversely proportional the time 
               Δt
        Δv remains the same while Δt increases 
        ∴ Fnet decreases.

        Fnetto α 1 / die netto krag is omgekeerd eweredig aan die tyd
                Δt
        Δv bly konstant terwyl Δt toeneem
        ∴ Fnetto verlaag.                                                                        (2)

6.5     Crumble zones / Less rigid metal used / Frommelsone / minder rigiede metaal
        gebruik
        Head rests / Kopstut
        Safety belts / Veiligheidsgordel
        Air bags / lugsakke

        Any two / Enige twee (or any other relevant answer/ of enige ander relevante
        antwoord)                                                                              (2)
                                                                                                [16]

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12                PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                (EC/JUNE/JUNIE 2023

QUESTION 7/VRAAG 7

7.1 The total mechanical energy in a closed system  remains constant. 
    Die totale meganiese energie in ŉ geslote sisteem bly constant.                          (2)

7.2 (Ep + Ek)A = (Ep + Ek)B            Any one / Enige een 
                 2
    (mgh + ½mv )A = (mgh + ½mv )B 2

    (685)(9,8)(18 sin 9,50) + ½(685)(02) = (685)(9,8)(0) + ½(685)(vf2) 
    vf = 7,63 m.s-1                                                                         (4)

                OPTION 1/OPSIE 1                        OPTION 2/OPSIE 2
     W// = F//.Δx.cos θ                       W// = F//.Δx.cos θ       Any one 
     W// = mg sinθ.Δx.cos θ Any one          W// = mg sinθ.Δx.cos θ
     W// = [(685)(9,8)sin9,5ºx18cos 0º ]    W// = [(685)(9,8) x18cos80,5º ] 
     W// = 19 943,36 (1,99 x 104) J          W// = 19 943,36 (1,99 x 104) J                (4)

7.4 The net work done on an object is equal to the change in kinetic energy. 
    Die netto arbeid verrig op ŉ voorwerp is gelyk aan die verandering in kinetiese
    energie.                                                                                 (2)

7.5 Positive marking from QUESTION 7.2 / Positiewe nasien vanaf VRAAG 7.2
    Wnet = ΔEk
    Wf = ½m(vf2 – vi2)            Any one / Enige een
    Ff.Δx.cos θ = ½m(vf2 – vi2)   
    Ff.11.cos 180 = ½(685)(0 – 7,632) 
                  0             2

    Ff = 1812,66 N                                                                          (4)

7.6 Positive marking from QUESTION 7.5 / Positiewe nasien vanaf VRAAG 7.5
    ff = μkN
    μk = 1812,66 
          (9,8 x 685) 
    μk = 0,27                                                                              (4)
                                                                                           [20]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                    13

QUESTION 8/VRAAG 8

8.1 Gravitational force / Gravitasiekrag                                                   (1)

8.2 Fnet = ma
    Fmotor - F// – ff = ma                 Any one / Enige een 
    Fmotor - mg sin θ – ff = ma
    Fmotor - (450)(9,8)(sin 22,5°) – 1 340 = (450)0 
    Fmotor = 3 027,63 N                                                                    (4)

    Positive marking from QUESTION 8.2 / Positiewe nasien vanaf VRAAG 8.2
8.3 Pave = F.v 
    Pave = 3 027,63 x 1,57 
    Pave = 4 758,39 W 
    Yes, it will be sufficient. / Ja dit sal genoeg wees.                                  (4)
                                                                                           [9]

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14                PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                  (EC/JUNE/JUNIE 2023

QUESTION 9/VRAAG 9

9.1     The change in frequency (or pitch) of the sound detected by a listener, because
        the sound source and the listener have different velocities relative to the
        medium of sound propagation. 
        Die verandering in frekwensie (of toonhoogte) van die klank waargeneem deur
        ŉ luisteraar omdat die klankbron en die luisteraar verskillende snelhede relatief
        tot die medium waarin die klank voortgeplant word het.

                                            OR / OF

        The apparent change in frequency when a source of sound and the listener
        move relative to each other.
        Die waargenome verandering in frekwensie wanneer die klankbron en die
        luisteraar relatief na mekaar beweeg.                                                  (2)

9.2     fL = v ± vL . fS 
             v ± vS

        307 =     340 .  285 
                 (340 – vs)

        vs = 24,36 m.s-1 
        vs = 87,7 km.h-1                                                                       (5)

9.3     HIGHER / HOЁR 
        As ambulance B moves faster,  the wavelength towards the doctor is
        shorter  and the frequency higher.

        As ambulans B vinniger beweeg, sal die golflengte na die dokter korter en die
        frekwensie hoër wees.                                                                  (3)

9.4     Measure the heartbeat of a foetus / Meet die hartklop van ŉ fetus Any one/ 
        Measure the rate of blood flow / Meet die tempo van bloedvloei Enige een               (1)

9.5.1   fL = v ± vL . fS 
             v ± vS

        fL = (340 + 15) .  625 
               340
           = 652,57 Hz                                                                        (4)

        Positive marking from QUESTION 9.5.1 / Positiewe nasien vanaf VRAAG
        9.5.1
9.5.2   v=fλ 
        340 = 652,57 x λ 
        ∴ λ = 0,54 m                                                                          (3)
                                                                                              [18]

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(EC/JUNE/JUNIE 2023)         PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1                       15

QUESTION 10/VRAAG 10

10.1
                                               Marking criteria / Nasienkriteria
                                               Direction / Rigting 
                                               Shape / Vorm 
                                               Lines all touching charges and not
                                               crossing / Lyne raak aan ladings
                                               en kruis nie 

                                                                                               (3)

10.2 To the right (Westwards) / Na regs (Weswaarts)                                           (1)

10.3 The magnitude of the electrostatic force exerted by one point charge (Q 1) on
     another point charge (Q2) is directly proportional to the product of the
     magnitudes of the charges and inversely proportional to the square of the
     distance (r) between them: 

       Die grootte van die elektrostatiese krag wat een puntlading (Q 1) op ŉ ander
       puntlading (Q2) uitoefen is direk eweredig aan die produk van hul ladings en
       omgekeerd eweredig aan die kwadraat van die afstand (r) tussen hulle.                   (2)

10.4 F = kQPQQ 
           r2
     4,55 x 10-2 = (9 x 109)(Q2 
                        (0,6)2 
     QP = QQ = (-)1,35 x 10-6 C                                                               (4)

10.5 QP = nqe 
     1,35 x 10-6 = n x (1,6 x 10-19) 
     n = 8,44 x 1012 electrons / elektrone                                                   (3)
                                                                                             [13]

                                                                    TOTAL/TOTAAL:            150

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