# Physical Sciences Grade 11 P1 2013 Memo > Grade 11 Physical Sciences Paper 1 memorandum from the Eastern Cape November 2013, 8 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/physical-sciences-p1-memo/725172f3-ffdb-4a0d-a5af-99d9a2d5413a - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 11 - Document type: Memorandum - Year: 2013 - Exam period: Eastern Cape November - Paper: 1 - Curriculum: CAPS - Pages: 8 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 11](https://www.hlayiso.com/library/grade-11) › [Physical Sciences](https://www.hlayiso.com/library/grade-11/physical-sciences) › [Physical Sciences Grade 11 P1 2013 Memo](https://www.hlayiso.com/library/physical-sciences-p1-memo/725172f3-ffdb-4a0d-a5af-99d9a2d5413a) ## About this document Physical Sciences · Grade 11 · Eastern Cape November · 2013. Memorandum, 8 pages. Read online or download the PDF. 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Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 11 NOVEMBER 2013 PHYSICAL SCIENCES P1/ FISIESE WETENSKAPPE V1 MEMORANDUM MARKS/PUNTE: 150 This memorandum consists of 8 pages./ Hierdie memorandum bestaan uit 8 bladsye. ### Page 2 Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (NOVEMBER 2013) QUESTION/VRAAG 1 1.1 Normal force/Normaalkrag (1) 1.2 Refractive index/Brekingsindeks (1) 1.3 Critical angle/Kritiesehoek (grenshoek) (1) 1.4 Electric field (strength)/Elektriese veld (sterkte) (1) 1.5 Energy (Work) done/Energie (Arbeid) verrig (1) [5] QUESTION/VRAAG 2: 2.1 C (2) 2.2 D (2) 2.3 C (2) 2.4 C (2) 2.5 B (2) 2.6 A (2) 2.7 C (2) 2.8 C (2) 2.9 A (2) 2.10 B (2) [20] TOTAL SECTION/TOTAAL AFDELING A: 25 ### Page 3 Downloaded from hlayiso.com (NOVEMBER 2013) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 QUESTION/VRAAG 3 3.1 3.1.1 F = 60 mm √ = 55° √ X = 34 mm √ (accept/aanvaar 33 – 35) F = 60 mm 102 N √ (accept/aanvaar 99 N – 105 N) left/links Y = 49 mm (accept/aanvaar 48 – 50) √ 55º 147 N √ (accept/aanvaar 144 N – 150 N) down/af √ All 3 arrows correct/Al 3 pyle korrek √ (7) If a calculation was done instead of a construction – max 4 out of 7 Indien ʼn berekening gedoen is i.p.v. ʼn konstruksie – maks. 4 uit 7 Right angled triangle with information shown/Reghoekige driehoek met inligting getoon √ All 3 arrows correct/Al 3 pyle korrek √ X = 180 cos 55º = 103,24 N √ Y = 180 sin 55 º = 147,45 N √ Positive marking from Q3.1.1/Positiewe nasien vanaf Vr3.1.1 3.1.2 w = mg = 30(9,8) √ = 294 N √ normal force/normaalkrag = 294 + 147 = 441 N √ (3) 3.2 A single vector √ with the same effect as a number of vectors acting on an object. √ ʼn Enkel vektor √ wat dieselfde effek het as ʼn aantal vektore wat saam op ʼn voorwerp inwerk. √ (2) 3.3 3.3.1 one mark for correct vector diagram/een punt vir korrekte vektordiagram R=√ = 25 N √√ (3) 3.3.2 tan θ = θ = 36,87° √ thus/dus 6,87° √ (clockwise from the positive y-axis/ kloksgewys vanaf die y-as) OR/OF (2) 3.4 When three or more vectors drawn head to tail form a closed figure, √ their resultant is zero or they are in equilibrium/balanced. √ Wanneer drie of meer vektore kop-stert geteken word en ʼn geslote figuur vorm, √ is hul resultant nul of is hulle in ewewig/gebalanseerd √ (2) [19] ### Page 4 Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (NOVEMBER 2013) QUESTION/VRAAG 4 4.1 FN – normal force/normaalkrag w – weight/gewig fk – friction/wrywing (3) 4.2 4.2.1 The kinetic frictional force is the only force acting on the sled in x direction and opposes the motion of the sled so the net force is given by/Die kinetiese wrywingskrag is die enigste krag op die skild in x-rigting en staan die beweging van die slee teen sodat die krag gegee word deur: Fnet = ma √ OR/OF fk = μk N √ = 0,06 m (9,8) √ = 0,588 m N µkmg √ = ma Fnet = ma √ 0,588 m = m a µkg = a a = 0,588 m.s-2 √ or/of 0,59 m.s-2 -2 6 x10 x 9,8 = a √ a = 0,588 m.s-2 √ or/of 0,59 m.s-2 (4) 4.2.2 POSITIVE MARKING FROM QUESTION 4.2.1 POSITIEWE NASIEN VAN VRAAG 4.2.1 vf2 = vi2 + 2a∆x √ 02 = 62 + 2 (-0,588) ∆x √ (the sled decelerates/die slee vertraag) ∆x = 30,61 m √ (if/as a = 0,59 m.s-2 then/dan ∆x = 30,51 m) (3) [10] QUESTION/VRAAG 5 5.1 Bulie’s applied force/toegepaste krag/250 N √ friction/wrywing/500N √ Douglie’s applies force/toegepaste krag/400 N √ (3) 5.2 Fnet = ma = 400 + 250 + (-500) √ = 2000 a √ 150 = 2000 x a a = 0,075 m.s-2 √ to the right/na regs √ (4) 5.3 Fg//= Fg sin θ = mg sin θ √ = 2000 (9,8) sin 5˚ =1 708,25 N √ (2) 5.4 accelerate down the incline/versnel teen die steilte af √ (1) 5.5 Inertia is the tendency of an object to resist change √ Traagheid is ʼn voorwerp se vermoë om verandering teen te staan √ (1) ### Page 5 Downloaded from hlayiso.com (NOVEMBER 2013) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 5.6 A person will keep on moving forward in a straight line at constant velocity unless acted on by a resultant force √ The seatbelt acts as a net force √ which hold you safely in the seat. ʼn Liggaam sal aanhou beweeg in ʼn reguit lyn teen ʼn konstante snelheid tensy ʼn resultante krag daarop inwerk. √ Die veiligheidsgordel is die net krag √ wat jou veilig in die sitplek hou. OR/OF In an accident seatbelts hold you safely in place because of Newton’s First law of motion and inertia. √ When a car suddenly slows down the seatbelt acts as net force √ which helps the passengers from being hurt. In ʼn ongeluk hou die veiligheidsgordel jou veilig in plek a.g.v. Newton se eerste wet/traagheid. √ Wanneer ʼn motor skielik stadiger ry, tree die veiligheidsgordel as die netto krag op √ wat help dat die passasier nie seerkry nie. (2) 5.7 Newton’s third law of motion states that when object A exerts a force on object B, object B simultaneously exerts an oppositely directed force of equal magnitude on object B. √√ Volgens Newton se derde bewegingswet: as voorwerp A ʼn krag op voorwerp B uitoefen, oefen voorwerp B terselfde tyd ʼn teenoorgestelde krag van dieselfde grootte op A uit. √√ (2) 5.8 force of book on table – force of table on book √ krag van boek op tafel – krag van tafel op boek force of floor on table - force of table on floor √ krag van vloer op tafel – krag van tafel op vloer force of earth on table - force of table on earth √ krag van aarde op tafel – krag van tafel op aarde (3) [18] ### Page 6 Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (NOVEMBER 2013) QUESTION/VRAAG 6 6.1 F sun earth = G Msun Mearth √ d2 = 6,67 x 10-11 √ (1,99 x 1030)(5,98 x 1024) √ (2 x 1011)2 + (4 x 108)2 √ = 1,98 x1022 N √ (5) 6.2 gmoon = GMmoon √ OR/OF F =mg=GmM 2 d d2 = 6,67 x10-11 (7,35 x 1022) √ (1,6 x 106)2 √ = 1,92 m.s-2 √ (4) 6.3 W = mg √ = 50 x 10-3 x 9,8 √ = 0,49 N √ (3) [12] QUESTION/VRAAG 7 7.1 7.1.1 n1sinӨ1 = n2sinӨ2√ 1,00 x sin 47°√ = 1,33 sinӨ2 √ sinӨ2 = 0,55 Ө2 = 33,36° √ (4) 7.1.2 n1sinӨ1 = n2sinӨ2 1,33 sin 47° √ = 1,00 sinӨ2 √ Ө2 = 76,58°√ (3) 7.2 n= √ 1,33 = 3 x 108 √ v v = 2,26 x 108 m.s-1 √ (3) 7.3 n1sinӨ1 = n2sinӨ2 1,33 sinӨ1 √ = 1,00 sin 90° √ Ө1 = 48,75° (2) 7.4 7.4.1 7.4.2 (2) (2) 7.5 (any of the following/enige van die volgende) -telecommunications/telekommunikasie √ -video communications/videokommunikasie -computer-data communications/rekenaardatakommunikasie -medicine - endoscope)/medisyne - endoskoop (1) [17] ### Page 7 Downloaded from hlayiso.com (NOVEMBER 2013) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 QUESTION/VRAAG 8 8.1 Every point in a wave front acts as the source of secondary wavelets √ that spread out in all directions with the same speed as a wave. √ Elke punt op die golffront dien as ʼn bron van sekondêre golwe √ wat uitsprei in alle rigtings met dieselfde spoed as die golf. √ (2) 8.2 A – Central bright broad band/breë sentrale ligte band √ B – dark band/donker bande √ (2) 8.3 A√ (1) 8.4 8.4.1 broader/breër √ (1) 8.4.2 broader/breër √ (1) 8.5 diff α wavelength/diff α golflengte √√ (2) [9] QUESTION/VRAAG 9 9.1 9.2 F12 = k q1q2 √ r2 = 9 x 109 (4 x 10-6)(6 x 10-6) √ (0,15)2 √ = 9,6 N √ (3) (4) 9.3 F13 = 9 x 109 (4 x 10-6)(5x10-6) √ (0,1)2 √ = 18 N √ Fnet = √ √ = 20,4 N √ tan θ = 9,6 √ 18 θ = 28,07° √ (anticlockwise from positive x-axis) (antikloksgewys vanaf die positiewe x-as) OR/OF = 61,93° (clockwise from the positive y-axis) (kloksgewys vanaf die positiewe y-as) (7) [14] ### Page 8 Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (NOVEMBER 2013) QUESTION/VRAAG 10 10.1 10.1.1 Current direction: up out of page/ Stroomrigtin: uit papier circular field/sirkelvormige veld √ anticlock wise/antikloksgewys √ (2) 10.1.2 shape/vorm √ position of north and direction N to S/ posisie van noord en rigting N na S√ (2) 10.2 10.2.1 Φ = BAcos θ √ = 0,72 (0,0176) cos 0° √ = 0,013 Wb √ (0,012672 Wb) (3) POSITIVE MARKING FROM Q10.2.1/POSITIEWE NASIEN VANAF VR10.2.1 10.2.2 ε = -N∆Φ √ = -450 (0 – 0,013) √ = 26,59 V √ ∆t 0,22 (3) [10] QUESTION/VRAAG 11 11.1 11.1.1 3V √ (1) 11.1.2 I = V/R √ = 3/5 √ = 0,6 A √ (3) 11.1.3 I = V/R = 3 √ /7 √ = 0,43 A V2 = IR √ = 0,43 x 4 √ = 1,72 V √ (accept/aanvaar 1,71 V) (5) 11.2 11.2.1 P = V2 √ OR/OF P = VI R 2600= 220 I √ both equations/ 2600 √= 2202 √ I = 11,82 A beide vergelykings R R = V/I √ R = 18,62 Ω √ = 220/11,82 √ = 18,62 Ω √ (4) 11.2.2 Cost = (2,6 x 3,5) √ x 1,04 √ = R9,46 √ OR/OF E = Pt = 2,6 kW x 3,5 h √ = 9,1 kWh Cost = 9,1 kWh x R1,04 √ = R9,46 √ (3) [16] TOTAL SECTION/TOTAAL AFDELING B: 125 GRAND TOTAL/GROOTTOTAAL: 150 ## Related documents - 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