# Physical Sciences Grade 12 P1 Eastern Cape Mock 2018 Memo > Grade 12 Physical Sciences Paper 1 memorandum from the Eastern Cape Mock Exam 2018, 20 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/physical-sciences-p1-memo/ad180661-58e7-4e07-a83f-f5cb35493121 - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2018 - Exam period: Eastern Cape Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 20 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 P1 Eastern Cape Mock 2018 Memo](https://www.hlayiso.com/library/physical-sciences-p1-memo/ad180661-58e7-4e07-a83f-f5cb35493121) ## About this document Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2018. Memorandum, 20 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 SEPTEMBER 2018 PHYSICAL SCIENCES P1/ FISIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 20 pages./ Hierdie nasienriglyn bestaan uit 20 bladsye. ### Page 2 Downloaded from hlayiso.com 2 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) GENERAL GUIDELINES/ALGEMENE RIGLYNE 1. CALCULATIONS/BEREKENINGE 1.1 Marks will be awarded for: correct formula, correct substitution, correct answer with unit. Punte sal toegeken word vir: korrekte formule, korrekte substitusie, korrekte antwoord met eenheid. 1.2 No marks will be awarded if an incorrect or inappropriate formula is used, even though there are many relevant symbols and applicable substitutions. Geen punte sal toegeken word waar ʼn verkeerde of ontoepaslike formule gebruik word nie, selfs al is daar relevante simbole en relevante substitusies. 1.3 When an error is made during substitution into a correct formula, a mark will be awarded for the correct formula and for the correct substitutions, but no further marks will be given. Wanneer ʼn fout gedurende substitusie in ʼn korrekte formule begaan word, sal ʼn punt vir die korrekte formule en vir korrekte substitusies toegeken word, maar geen verdere punte sal toegeken word nie. 1.4 If no formula is given, but all substitutions are correct, a candidate will forfeit one mark. Indien geen formule gegee is nie, maar al die substitusies is korrek, verloor die kandidaat een punt. 1.5 No penalisation if zero substitutions are omitted in calculations where correct formula/principle is correctly given. Geen penalisering indien nulwaardes nie getoon word nie in berekeninge waar die formule/beginsel korrek gegee is nie. 1.6 Mathematical manipulations and change of subject of appropriate formulae carry no marks, but if a candidate starts off with the correct formula and then changes the subject of the formula incorrectly, marks will be awarded for the formula and correct substitutions. The mark for the incorrect numerical answer is forfeited. Wiskundige manipulasies en verandering van die onderwerp van toepaslike formules tel geen punte nie, maar indien ʼn kandidaat met die korrekte formule begin en dan die onderwerp van die formule verkeerd verander, sal die punte vir die formule en korrekte substitusies toegeken word. Die punt vir die verkeerde numeriese antwoord word verbeur. 1.7 Marks are only awarded for a formula if a calculation has been attempted, i.e. substitutions have been made or a numerical answer given. Punte word slegs vir ʼn formule toegeken indien ʼn poging tot berekening aangewend is, d.w.s. substitusies is gedoen of ʼn numeriese antwoord is gegee. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 3 1.8 Marks can only be allocated for substitutions when values are substituted into formulae and not when listed before a calculation starts. Punte kan slegs toegeken word vir substitusies wanneer waardes in formules ingestel word en nie vir waardes wat voor ʼn berekening gelys is nie. 1.9 All calculations, when not specified in the question, must be done to a minimum of two decimal places. Alle berekenings, wanneer nie in die vraag gespesifiseer word nie, moet tot ʼn minimum van twee desimale plekke gedoen word. 1.10 If a final answer to a calculation is correct, full marks will not automatically be awarded. Markers will always ensure that the correct/appropriate formula is used and that workings, including substitutions, are correct. Indien ʼn finale antwoord van ʼn berekening korrek is, sal volpunte nie outomaties toegeken word nie. Nasieners sal altyd verseker dat die korrekte/toepaslike formule gebruik word en dat bewerkings, insluitende substitusies korrek is. 1.11 Questions where a series of calculations have to be made (e.g. a circuit diagram question) do not necessarily always have to follow the same order. FULL MARKS will be awarded provided it is a valid solution to the problem. However, any calculation that will not bring the candidate closer to the answer than the original data, will not count any marks. Vrae waar ʼn reeks berekeninge gedoen moet word (bv. ʼn stroombaan- diagramvraag) hoef nie noodwendig dieselfde volgorde te hê nie. VOLPUNTE sal toegeken word op voorwaarde dat dit ʼn geldige oplossing vir die probleem is. Enige berekening wat egter nie die kandidaat nader aan die antwoord as die oorspronklike data bring nie, sal geen punte tel nie. 2. UNITS/EENHEDE 2.1 Candidates will only be penalised once for the repeated use of an incorrect unit within a question. Kandidate sal slegs een keer gepenaliseer word vir die herhaaldelike gebruik van ʼn verkeerde eenheid in ʼn vraag. 2.2 Units are only required in the final answer to a calculation. Eenhede word slegs in die finale antwoord op ʼn vraag verlang. 2.3 Marks are only awarded for an answer, and not for a unit per se. Candidates will therefore forfeit the mark allocated for the answer in each of the following situations: • Correct answer + wrong unit • Wrong answer + correct unit • Correct answer + no unit Punte sal slegs vir ʼn antwoord en nie vir ʼn eenheid per se toegeken word nie. Kandidate sal die punt vir die antwoord in die volgende gevalle verbeur: • Korrekte antwoord + verkeerde eenheid • Verkeerde antwoord + korrekte eenheid • Korrekte antwoord + geen eenheid Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com 4 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) 2.4 SI units must be used except in certain cases, e.g. V.m-1 instead of N.C-1, and cm•s-1 or km•h-1 instead of m•s-1 where the question warrants this. SI-eenhede moet gebruik word, behalwe in sekere gevalle, bv. V•m-1 in plaas van N•C-1, en cm•s-1 of km•h-1 in plaas van m•s-1 waar die vraag dit regverdig. 3. GENERAL/ALGEMEEN 3.1 If one answer or calculation is required, but two are given by the candidate, only the first one will be marked, irrespective of which one is correct. If two answers are required, only the first two will be marked, etc. Indien een antwoord of berekening verlang word, maar twee word deur die kandidaat gegee, sal slegs die eerste een nagesien word, ongeag watter een korrek is. Indien twee antwoorde verlang word, sal slegs die eerste twee nagesien word, ens. 3.2 For marking purposes, alternative symbols (s, u, t, etc.) will also be accepted. Vir nasiendoeleindes sal alternatiewe simbole (s, u, t, ens.) ook aanvaar word. 3.3 Separate compound units with a multiplication dot, not a full stop, for example, m•s-1. For marking purposes, m•s-1 and m/s will also be accepted. Skei saamgestelde eenhede met ʼn vermenigvuldigingspunt en nie met ʼn punt nie, byvoorbeeld m•s-1. Vir nasiendoeleindes sal m•s-1 en m/s ook aanvaar word. 4. POSITIVE MARKING/POSITIEWE NASIEN Positive marking regarding calculations will be followed in the following cases: Positiewe nasien met betrekking tot berekeninge sal in die volgende gevalle geld: 4.1 Subquestion to subquestion: When a certain variable is calculated in one subquestion (e.g. 3.1) and needs to be substituted in another (3.2 of 3.3), e.g. if the answer for 3.1 is incorrect and is substituted correctly in 3.2 or 3.3, full marks are to be awarded for the subsequent subquestions. Subvraag na subvraag: Wanneer ʼn sekere veranderlike in een subvraag (bv. 3.1) bereken word en dan in ʼn ander vervang moet word (3.2 of 3.3), bv. indien die antwoord vir 3.1 verkeerd is en word korrek in 3.2 of 3.3 vervang, word volpunte vir die daaropvolgende subvraag toegeken. 4.2 A multistep question the a subquestion: If the candidate has to calculate, for example, current in die first step and gets it wrong due to a substitution error, the mark for the substitution and the final answer will be forfeited. ʼn Vraag met veelvuldige stappe in ʼn subvraag: Indien ʼn kandidaat bv. die stroom verkeerd bereken in ʼn eerste stap as gevolg van ʼn substitusiefout, verloor die kandidaat die punt vir die substitusie sowel as die finale antwoord. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 5 5. NEGATIVE MARKING/NEGATIEWE NASIEN Normally an incorrect answer cannot be correctly motivated if based on a conceptual mistake. If the candidate is therefore required to motivate in QUESTION 3.2 the answer given in QUESTION 3.1, and QUESTION 3.1 is incorrect, no marks can be awarded for QUESTION 3.2. However, if the answer for e.g. QUESTION 3.1 is based on a calculation, the motivation for the incorrect answer could be considered. ʼn Verkeerde antwoord, indien dit op ʼn konsepsuele fout gebaseer is, kan normaalweg nie korrek gemotiveer word nie. Indien ʼn kandidaat gevra word om in VRAAG 3.2 die antwoord op VRAAG 3.1 te motiveer en VRAAG 3.1 is verkeerd, kan geen punte vir VRAAG 3.2 toegeken word nie. Indien die antwoord op bv. VRAAG 3.1 egter op ʼn berekening gebaseer is, kan die motivering vir die verkeerde antwoord in VRAAG 3.2 oorweeg word. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com 6 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) QUESTION/VRAAG 1: MULTIPLE-CHOICE QUESTIONS/ MEERVOUDIGEKEUSE-VRAE 1.1 C  (2) 1.2 A  (2) 1.3 D  (2) 1.4 A  (2) 1.5 D  (2) 1.6 C  (2) 1.7 A  (2) 1.8 D  (2) 1.9 C  (2) 1.10 D  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 7 QUESTION/VRAAG 2 2.1.1 FN  FN F F  Ff  Ff Tx Ty T  Fg  Fg Mark awarded for arrow and label./Punt toegeken vir pyl en byskrif Do not penalise for length of arrows since drawing is not drawn to scale/ Moenie penaliseer vir lengte van pyle want skets nie volgens skaal nie. Any other additional force(s)/Enige addisonele krag(te) 4⁄5 If force(s) do not make contact with body./Indien krag(te) nie kontak maak met liggaam nie Max/Maks. 4⁄5 (5) 2.1.2 If the resultant/net force acts on an object, the object will accelerate in the direction of the resultant/net force with an acceleration that is directly proportional to the resultant/net force ✓ and inversely proportional to the mass  of the object. Indien ʼn resulterende/netto krag op ʼn voorwerp uitgeoefen word sal die voorwerp versnel in die rigting van die resulterende/netto krag met ʼn versnelling wat direk eweredig is aan die resulterende/netto krag ✓en omgekeerd eweredig aan die massa van die voorwerp. ✓ (2) 2.1.3 OPTION/OPSIE 1 OPTION/OPSIE 2 Fnet = ma ✓ -5,2a = - 46,5 + Tx + 12  Fnet = Fapp - Tx - f any one -5,2a = -34,5 + Tx . . . . . (1) ma = Fapp - Tx - f enige een -2a = Tx + 51  . . . . . (2) 5,2a = 46,5 - Tx - 12  a = -4,08m.s-2 5,2a = 34,5 - Tx . . . . . . . . . . (1) a = 4,08 m.s-2 2a = Tx - 5,1  . . . . . . . . . . .(2) a = 4,08m.s-2 2 x (4,08)  = Tx - 5,1 Tx = 13,26 𝑇𝑥 T = 𝑐𝑜𝑠25 𝑜 13,26 T = 𝑐𝑜𝑠25𝑜  T = 14,63 N  (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com 8 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) 2.2 𝐺𝑀 g = 𝑅2  6,67 10−11 𝑥 6,39 1023 g=  (3,39 106 )2 g = 3,71 m.s-2  (3) [16] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 9 QUESTION/VRAAG 3 3.1.1 UPWARD POSITIVE/ DOWNWARD POSITIVE / OPWAARTS POSITIEF AFWAARTS POSITIEF 1 1 ∆x = vi∆t + 2 a∆t2  ∆x = vi∆t + 2 a∆t2  1 1 - (48) = vi x 2,8+ 2 x(- 9,8) x 2,82  (48)  = vi x 2,8 + 2 x 9,8 x 2,82  Vi = -3,42 Vi = 3,42 m.s-1  Vi = 3,42 m.s-1  (4) OPTION/OPSIE 1 3.1.2 UPWARD POSITIVE/ DOWNWARD POSITIVE / OPWAARTS POSITIEF AFWAARTS POSITIEF Vf = Vi + a∆t  Vf = Vi + a∆t  Vf = -3,42 + (-9,8) (2,8)  Vf = 3,42 + (9,8) (2,8)  Vf = -30,86 m.s-1 Vf = 30,86 m.s-1  Vf = 30,86 m.s-1  (3) OPTION/OPSIE 2 UPWARD POSITIVE/ DOWNWARD POSITIVE / OPWAARTS POSITIEF AFWAARTS POSITIEF 2 2 𝑉𝑓 = 𝑉𝑖 + 2a∆x  𝑉𝑓2 = 𝑉𝑖2 + 2a∆x  𝑉𝑓2 = -3,422 + 2 (-9,8) (-48)  𝑉𝑓2 = 3,422 + 2 (9,8) (48)  Vf = 30,86 m.s-1  Vf = 30,86 m.s-1  OPTION/OPSIE 3 UPWARD POSITIVE/ DOWNWARD POSITIVE / OPWAARTS POSITIEF AFWAARTS POSITIEF 𝑉 𝑉 𝑉 𝑉 ∆x = 𝑓+2 𝑖 ∆t  ∆ x = 𝑓+2 𝑖 ∆t  𝑉 𝑉 -(48) = 𝑓−3,42 x 2,8  48 = 𝑓+3,42 x 2,8  2 2 𝑉𝑓 = - 30,87 𝑉𝑓 = 30,87 m.s-1 𝑉𝑓 = 30,87 m.s-1  OPTION/OPSIE 4 EMi = EMi 1 1 mgh1 + 2 𝑚𝑣𝑖2 = mgh + 2 𝑚𝑣𝑓2 Any one  1 1 gh1 + 2 𝑣𝑖2 = gh2 + 2 𝑣𝑖2 Enige een 1 1 9,8 x 48 + 2 x 3,422 = 0 + 2 𝑣𝑖2  Vf = 30,86 m.s-1 OPTION/OPSIE 5 Fnet ∆t = ∆p Fnet ∆t = m (vf – vi) Any one mg∆t = m (vf – vi) Enige een  g ∆t = vf – vi 9,8 x 2,8 = vf – 3,42  Vf = 30,86 m.s-1  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com 10 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) 3.1.3 UPWARD POSITIVE/ DOWNWARD POSITIVE / OPWAARTS POSITIEF AFWAARTS POSITIEF 𝑉𝑓2 = 𝑉𝑖2 + 2a∆X  𝑉𝑓2 = 𝑉𝑖2 + 2a∆x  0 = 𝑉𝑖2 + 2 (-9,8)(8)  0 = 𝑉𝑖2 + 2 (9,8)(--8)  VI = 12,52 m.s-1 VI = 12,52 m.s-1 upwards.  VI = 12,52 m.s-1 upwards.  (3) 3.2 Positive marking from/Positiewe merk vanaf 3.1.1, 3.1.2, 3.1.3 CRITERIA FOR MARKING/KRITERIA VIR MERK Initial velocity with which the ball was thrown.  (i) Beginsnelheid waarmee bal gegooi is. Final velocity with which the ball hit the ground  (ii) Eindsnelheid waarmee die bal die grond tref. Time taken to hit the ground.  (iii) Tyd om die grond te tref. The velocity with which the ball bounces off the ground.  (iv) Die snelheid waarmee die bal van die grond af bons. 12,5 2 V (m.s-1) 0 2,8 ∆t(s) 3,42 30,8 6 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 11 30,86 V (m.s-1) 0 2,8 ∆t(s) 12,52 (4) [14] QUESTION/VRAAG 4 4.1 (𝑚𝐴 + 𝑚𝐵 ) 𝑣𝑖 = 𝑚𝐴 𝑣𝑓𝐴 + 𝑚𝐵 𝑣𝑓𝐵  45 𝑥 1000 (1100 + 800) x( 3600 ) = 1100 𝑣𝑓𝐴 + 800 x 9,06  𝑣𝑓𝐴 = 15,00 m.s-1  (4) 4.2 4.2.1 The product of the net force acting on an object and the time the net force acts on the object.  Die produk van die netto krag wat op ʼn voorwerp inwerk en die tyd wat die netto krag op die voorwerp inwerk.  (2) Positive marking from QUESTION 4.1 / Positiewe merk vanaf VRAAG 4.1 4.2.2 OPTION/OPSIE 1 OPTION/OPSIE 2 𝐹𝑛𝑒𝑡 ∆t = m (𝑣𝑓 - 𝑣𝑖 )  𝐹𝑛𝑒𝑡 ∆t = m (𝑣𝑓 - 𝑣𝑖 )  𝐹𝑛𝑒𝑡 x 0,2 = 1100 (0 – (-15)  𝐹𝑛𝑒𝑡 x 0,2 = 1100 (0 – (15)  𝐹𝑛𝑒𝑡 = 1,65 x 104 N left/links  𝐹𝑛𝑒𝑡 = - 1,65 x 104 𝐹𝑛𝑒𝑡 = 1,65 x 104 N left/links  (4) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com 12 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) QUESTION/VRAAG 5 5.1 Fapp/Ftoeg ✓ Fapp/Ftoeg ✓ Fx wind   Fg ✓ Fg  (3) Mark awarded for arrow and label./Punt toegeken vir pyl en byskrif Do not penalise for length of arrows since drawing is not drawn to scale/ Moenie penaliseer vir lengte van pyle nie want skets is nie volgens skaal nie. Any other additional force(s)/Enige addisonele krag(te) 2⁄3 If force(s) do not make contact with body./Indien krag(te) nie kontak maak met liggaam nie Max/Maks. 2⁄3 5.2 5.2.1 OPTION/OPSIE 1 OPTION 2/OPSIE 2 WFg = Fg ∆X cos𝜃  WFg = -∆Ep Any one / WFg = - mg (h2 – h1) Enige een WFg = 245 x 9,8 x 12 cos180o  WFg = - 28812 J  WFg = - 245 x 9,8(12 – 0)  WFg = - 28812 J  (3) 5.2.2 OPTION/OPSIE 1 Fnet = FwindY + Fg + Fapp Fnet = - (1870 cos 50o ) – (245 x 9,8) + 3000  Fnet = - 603,01 N Any one / Wnet = Fnet .∆x cos𝜃 Enige een Wnet = 603,01 x 12 cos 180o  Wnet = - 7236,12 J  Positive marking from QUESTION 5.2.1/ Positiewe merk vanaf VRAAG 5.2.1 OPTION/OPSIE 2 Wnc = ∆Ek + ∆Ep Any one / WF + W wind = ∆Ek + ∆Ep Enige een 3000 x 12 cos0o + 1870 x12 cos130o)  = 28812  + ∆Ek ∆Ek = - 7236,15 J Wnet = - 7236,12 J  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 13 Positive marking from QUESTION 5.2.1/ Positiewe merk vanaf VRAAG 5.2.1 OPTION/OPSIE 3 Wnet = W windY + W Fg + Wapp  Wnet = (1870 x 12 cos130o)  - 28812 + (3000 x 12 cos0o)  Wnet = - 7236,15 J  (4) 5.3 The net work done on an object is equal to the change in kinetic energy  Die netto arbeid verrig op ʼn voorwerp is gelyk aan die verandering in kinetiese energie  (2) 5.4 Wnet = ∆ Ek 1 1 Wnet = 2 m 𝑉𝑓2 - m 𝑉𝑖2 Any one/Enige een  2 1 1 -7236,15 = 2 x 245 𝑉𝑓2 - 2 x 245 x 152  𝑉𝑓 = 12,88 m.s-1  (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com 14 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) QUESTION/VRAAG 6 6.1 6.1.1 EQUAL TO.  There is no relative motion between the observers and the source of sound.  GELYK AAN.  Daar is geen relatiewe beweging tussen die waarnemers en die bron van die klank nie.  (2) 6.1.2 GREATER THAN / GROTER AS  (1) 6.1.3 Observer 1 Observer 2 Waarnemer 1 Waanemer 2 Criteria/Kriteria Mark/Punt Wave compressed towards observer 1  Golf saamgepers na waarnemer 1 Wave stretched away from observer 2  Golf saamgepers weg van waarnemer 2 Direction of motion indicated  Rigting van beweging aangedui (3) 6.1.4 Doppler effect / Doppler effek  (1) 6.1.5 𝑉±𝑉 𝑓𝐿 = 𝑉±𝑉 𝐿 𝑓𝑆  𝑆 340  1730 = 340−25  𝑓𝑆 𝑓𝑆 = 1602,79 Hz  (5) 6.1.6 Star C,  it shows a greater red shift.  Ster C,  dit toon ʼn groter rooi verskuiwing  (2) [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 15 QUESTION/VRAAG 7 7.1 The electrostatic force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.  Die elektrostatiese krag tussen twee puntladings is direk eweredig aan die produk van die ladings  en omgekeerd eweredig aan die kwadraat van die afstand tussen hulle.  (2) 7.2.1 OPTION/OPSIE 1 1920 Factor/Faktor =  = 16 120 OR/OF 120 1 Factor/Faktor = = 1920 16 Factor decreases by 16. /Faktor verminder met 16  Factor by which r increased/Faktor waarmee r toeneem = √16 = 4  X + 6 = 4X  X=2m OPTION/OPSIE 2 𝑘𝑄1 𝑄2 F=  𝑟2 9 𝑥109 𝑥 𝑄2 1920 =  𝑋2 1920 𝑥 𝑋 2 𝑄2 = . . . . . . . . . .. . . . . (1) 9 𝑥 109 9 𝑥 109 𝑥 𝑄2 120 =  (𝑋+6)2 120 𝑥 (𝑋+6)2 𝑄2 = . . . . . . . . . . . (2) 9 𝑥 109 1920 𝑥 𝑋 2 120 𝑥 ( 𝑋+6)2 = 9 𝑥 109 9 𝑥 109 x =2m (5) Positive marking from QUESTION 7.2.1/ Positiewe merk vanaf VRAAG 7.2.1 7.2.2 OPTION/OPSIE 1 OPTION/OPSIE 2 𝑘𝑄1 𝑄2 F= 𝑘𝑄1 𝑄2  F=  𝑟2 𝑟2 9 𝑥 109 𝑥 𝑄 2 1920  =  9 𝑥 109 𝑥 𝑄 2 22 120  =  82 Q = 9,24 x10 C  -4 Q = 9,24 x10-4 C  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 Downloaded from hlayiso.com 16 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) Positive marking from QUESTION 7.2.1/ Positiewe merk vanaf VRAAG 7.2.1 7.3.1 𝑘𝑄 E =  𝑟2 9 𝑥 102 𝑥 9,24 𝑥10−4 E1 =  2.22 E1 = 1718181,818 N.C-1 (1,72 X 106 N.C-1) Right/Regs 9 𝑥 102 𝑥 9,24 𝑥10−4 E2 =  0.22 E2 = 207900000 NC-1 (2,08 X 108 N.C-1) Right/Regs Enet = 1718181,818 + 207900000 (1,72 X 106 N.C-1 + 2,08 X 108 N.C-1)  Enet = 2,10 x 108 N.C-1  (5) Positive marking from QUESTION 7.3.1/ Positiewe merk vanaf VRAAG 7.3.1 7.3.2 OPTION/OPSIE 1 𝐹 E =𝑞 𝐹 2,10 x 108 =  1,6 𝑥 10−19 F = 3,36 x 10-11 N  OPTION/OPSIE 2 𝑘𝑄1 𝑄2 F=  𝑟2 9 𝑥 109 𝑥 9,24 𝑥 10−4 𝑥 1,6 𝑥 10−19 9 𝑥 109 𝑥 9,24 𝑥 10−4 𝑥 1,6 𝑥 10−19 F= +  2.22 0.22 F = 3,35 x 10-11 N  (3) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 17 QUESTION/VRAAG 8 8.1.1 Diagram A represents Exp 2/Diagram A verteenwoordig Eksp 2.  (1) 8.1.2 ε = I(R+r)  = 14,4 + 4,8r . . . . . . . . (1) = 20,58 + 1,71r .. . . . . .(2) 3,09 r = 6,18 ∴r = 2 Ω (4) 8.1.3 OPTION/OPSIE 1 OPTION/OPSIE 2 ε = I(R+r) ε = I(R+r) = 4,8 x 2 + 14,4  = 1,71 x 2 + 20,5  = 24 V  = 24 V  (2) Positive marking from QUESTION 8.2.1 and 8.2.2 / Positiewe merk vanaf VRAAG 8.2.1 en 8.2.2 8.1.4 OPTION/OPSIE 1 OPTION/OPSIE 2 𝑉 𝑉 R = 𝐼 R= 𝐼  14,4 R =  20,58 4,8 R=  R= 3Ω 1,71 R = 12 1 1 1 R = R1 + R2 = + R // R 1 R 2 12 = 2R1  1 1 1 R = 6Ω = + ✓ (R1=R2 = R) 3 R R R = 6Ω  OPTION/OPSIE 3 OPTION/OPSIE 4 𝜀 = I (R + r)  𝜀 = I (R + r)  24 = 4,8 (R + 2)  24 = 1,71(R + 2)  R=3Ω R = 12,04 Ω 1 1 1 R = R1 + R2 = + R // R 1 R 2 12,04 = 2R 1 1 1 R = 6,02 Ω  = + ✓ (R1 = R2 = R) 3 R R R = 6Ω  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 Downloaded from hlayiso.com 18 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) 8.1.5 OPTION/OPSIE 1 DECREASE,  total external resistance will increase, the current will decrease  P ∝ I2  therefore power decreases. AFNEEM, totale eksterne weerstand sal afneem, die stroom sal afneem P ∝ I2  dus sal drywing verminder. OPTION/OPSIE 2 DECREASE,  total external resistance will increase, the current will decrease, the lost volt will decrease.  2 P ∝ 𝑉𝑙𝑜𝑠𝑡  therefore power decreases. AFNEEM, totale eksterne weerstand sal afneem, die stroom sal afneem, die verlore volt sal verminder. 2 P ∝ 𝑉𝑣𝑒𝑟𝑙𝑜𝑟𝑒  dus sal drywing verminder. (3) 8.2 P = I2R  P = 165 x 52  P = 13 312 W kWh = 13,312 x 6 kWh = 79,872 Cost/Koste = 79,872 x 1,20  = R95,85  (4) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 19 Downloaded from hlayiso.com (EC/SEPTEMBER 2018) PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 19 QUESTION/VRAAG 9 9.1 9.1.1 Mechanical energy to Electrical energy.  Meganiese energie na Elektriese energie (2) 9.1.2 P to Q. / P na Q  (1) 9.2 9.2.1 Vmax 𝑉𝑚𝑎𝑘𝑠 Vrms  Vwgk =  √2 2  Vmax 230 = 2 Vmax/maks = 325,27 V  (3) 9.2.2 1 1 1 = + R // R 1 R 2  1 1 1 = + ✓ R // 12 24 R//= 8 Ω OPTION/OPSIE 1 V 2 rms P av erage =  / Pgem = V²wgk/R R (230 )2 Paverage =  8 Paverage / Pgem = 6612,5 W (6,61 kW)  (5) OPTION/OPSIE 2 OPTION/OPSIE 3 Vrms 𝑉𝑤𝑔𝑘 Vrms Irms = / Iwgk = 𝑅 Irms = R R Any one/  Any one/ Vrms = IrmsR Vrms = IrmsR Enige een Enige een 230 230 Irms = Irms = 8 8 = 28,75 A = 28,75 A Pavg = Vrms.Irms /Pgem = Vwgk.Iwgk Paverage = I2rms R / Pgem = I²wgk.R = (28,75)2(8)  = (230)(28,75)  = 6612,5 W (6,61 kW)  = 6612,5 W (6,61 kW)  (5) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 20 Downloaded from hlayiso.com 20 PHYSICAL SCIENCES P1/FISIESE WETENSKAPPE V1 (EC/SEPTEMBER 2018) QUESTION/VRAAG 10 10.1 The minimum energy (of incident photons) that can eject electrons from a metal (surface).  Die minimum energie (van invallende fotone) wat elektrone kan vrystel vanuit ʼn metaal (oppervlakte)  (2) 10.2 Wo = 3,51 x 10-19 J  (1) 10.3 EQUAL to  The gradient is Plank’s constant.  GELYK AAN  Die gradiënt (helling) is Plank se konstante  (2) Positive marking from QUESTION 10.1.2/ Positiewe merk vanaf VRAAG 10.1.2 10.4 Wo = hfo  3,51 x 10-19 = 6,63 x 10-34 fo  fo = 5,29 x 1014 Hz  (3) Positive marking from QUESTION 10.1.2/ Positiewe merk vanaf VRAAG 10.1.2 10.5 E = W o + Ek Any one / ℎ𝑐 1 = W o + 2 mv2 Enige een 𝜆 6,63𝑥 10−34 𝑥 3 108 1  = 3,51 x 10-19 + 2 x 3,83 x 10-19  𝜆 𝜆 = 2,71 x 10-7m  (5) [13] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - [GP 2018 Paper 1 Memorandum](https://www.hlayiso.com/library/gp-2018-paper-1-memorandum/23750489-743e-47ce-ab89-fb6303430e77) — Physical Sciences · Memo · 2018 - [Physical Sciences P1 Feb March 2018 Memo Afr Eng](https://www.hlayiso.com/library/physical-sciences-p1-feb-march-2018-memo-afr-eng/4d0a2b36-b101-4443-aa19-d5c8b0d293a0) — Physical Sciences · Memo · 2018 · Eng - [PHYS SCIENCES P1 GR12 MEMO SEPT2021 Xho English B Copy](https://www.hlayiso.com/library/phys-sciences-p1-gr12-memo-sept2021-xho-english-b-copy/813b1849-8c40-4d71-92b0-1f6a8e44c4f9) — Physical Sciences · Memo · 2021 · Eng - [Physical Sciences P1 Memo](https://www.hlayiso.com/library/physical-sciences-p1-memo/2d2b7939-aa98-49f1-afa7-ca27e7f59489) — Physical Sciences · Memo · 2017 - [PHYS SC P1 MEMO ENGAFR](https://www.hlayiso.com/library/phys-sc-p1-memo-engafr/da9b9ae0-718d-442a-95bc-aa0bfbf308f3) — Physical Sciences · Memo · 2014 - [PHYSICAL SCIENCES P2 GR12 QP SEPT 2018 Afrikaans](https://www.hlayiso.com/library/physical-sciences-p2-gr12-qp-sept-2018-afrikaans/851ef73d-62a5-4b19-b6cb-e009163ddf34) — Physical Sciences · QP · 2018 · Afr ## More from Grade 12 Physical Sciences - [PHYSICAL SCIENCE P1 QP JCT 2025 AFR D watermark](https://www.hlayiso.com/library/physical-science-p1-qp-jct-2025-afr-d-watermark/b9429ac5-acbb-4fae-989d-af9e1478a96b) — QP · 2025 · Afr - [PHYSICAL SC P2 QP GR12 SEPTEMBER 2025 AFR1 watermark](https://www.hlayiso.com/library/physical-sc-p2-qp-gr12-september-2025-afr1-watermark/37cff2db-7c1a-4ec8-8ac5-07ec5bcf87a9) — QP · 2025 - [Physics Grade 12 NSC P2 QP September 2025 Gauteng](https://www.hlayiso.com/library/physics-grade-12-nsc-p2-qp-september-2025-gauteng/4d3cbea6-10ec-47ff-98ee-50646165ae9f) — QP · 2025 - [Physics Grade 12 NSC P1 QP September 2025 KZN](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-kzn/6d225dc8-24c6-4c28-a181-df906d5a2c0e) — QP · 2025 - [Physical Sciences Physics Grade 12 PS01 QP March 2025 Limpopo](https://www.hlayiso.com/library/physical-sciences-physics-grade-12-ps01-qp-march-2025-limpopo/482ee9af-e88a-4818-9120-11ab9e045a1c) — QP · 2025 - [Physics Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-limpopo/b65e9832-a6be-4312-8f5a-57425d647121) — QP · 2025 ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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