# Physical Sciences Grade 12 P1 NSC November 2017 QP (Eng)

> Grade 12 Physical Sciences Paper 1 question paper from the NSC November Exam 2017 (English), 22 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Question paper
- Year: 2017
- Exam period: NSC November Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 22

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Physical Sciences · Grade 12 · NSC November Exam · 2017. Question paper, 22 pages. Read online or download the PDF.

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### Page 1

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                                  NATIONAL
                             SENIOR CERTIFICATE

                                     GRADE 12

                       PHYSICAL SCIENCES: PHYSICS (P1)

                                  NOVEMBER 2017

MARKS: 150

TIME: 3 hours

              This question paper consists of 19 pages and 3 data sheets.

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Physical Sciences/P1                         2                             DBE/November 2017
                                            NSC

INSTRUCTIONS AND INFORMATION

1.        Write your examination number and centre number in the appropriate spaces
          on the ANSWER BOOK.

2.        This question paper consists of 11 questions. Answer ALL the questions in
          the ANSWER BOOK.

3.        Start EACH question on a NEW page in the ANSWER BOOK.

4.        Number the answers correctly according to the numbering system used in this
          question paper.

5.        Leave ONE line between two subquestions, for example between
          QUESTION 2.1 and QUESTION 2.2.

6.        You may use a non-programmable calculator.

7.        You may use appropriate mathematical instruments.

8.        You are advised to use the attached DATA SHEETS.

9.        Show ALL formulae and substitutions in ALL calculations.

10.       Round off your FINAL numerical answers to a minimum of TWO decimal
          places.

11.       Give brief motivations, discussions, et cetera where required.

12.       Write neatly and legibly.

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Physical Sciences/P1                           3                         DBE/November 2017
                                              NSC

QUESTION 1: MULTIPLE-CHOICE QUESTIONS

Various options are provided as possible answers to the following questions. Choose
the answer and write only the letter (A–D) next to the question number (1.1–1.10) in
the ANSWER BOOK, for example 1.11 D.

1.1       The acceleration due to gravity on Earth is greater than that on the moon.

          Which ONE of the following statements is CORRECT?

          A     The weight of an object on Earth is the same as that on the moon.

          B     The mass of an object on Earth is the same as that on the moon.

          C     The mass of an object on Earth is greater than that on the moon.

          D     The weight of an object on Earth is less than that on the moon.                 (2)

1.2       The force diagram below shows the forces acting on a box.

                                          N
                                                         F
                                                    θ

                                           w
          Which ONE of the following equations for the magnitude of the normal
          force (N) is CORRECT?

          A     N = w + Fcosθ

          B     N = w + Fsinθ

          C     N = w – Fcosθ

          D     N = w – Fsinθ                                                                   (2)

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Physical Sciences/P1                          4                        DBE/November 2017
                                             NSC

1.3       A stone is projected vertically upwards from the top of a building at a speed
          of v m∙s-1. The position-time graph below represents the motion of the stone.
          Ignore the effects of air resistance.

                            y (m)

                                    0   t1               t (s)

          Which ONE of the combinations below regarding the magnitudes of the
          stone's velocity and acceleration, at time t 1 , is CORRECT?

                     MAGNITUDE OF VELOCITY         MAGNITUDE OF ACCELERATION
                            (m∙s-1)                          (m∙s-2)
          A                    0                               9,8
          B                    0                                0
          C                    v                                0
          D                    v                               9,8                            (2)

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Physical Sciences/P1                                       5                                     DBE/November 2017
                                                          NSC

1.4       A trolley of mass m is moving at constant velocity v to the right on a
          frictionless horizontal surface. A ball of clay, also of mass m, dropped
          vertically, falls onto the trolley at time t, as shown in the diagram below.

                                  Ball of clay m
                                                            v
                                              m

          The ball of clay sticks to the trolley.

          Which ONE of the velocity-time graphs below CORRECTLY represents the
          velocity of the trolley before and after time t?

                             v                                                      v

                                                                        v (m∙s-1)
           A          v (m∙s-1)       t                         B                        t              t(s)
                                                   t(s)
                                                                        -½v
                            -v

                                                                                    2v

           C    v (m∙s-1)    v                                  D   v (m∙s-1)       v
                       ½v
                                          t                                                  t         t(s)
                                                   t(s)
                                                                                                                       (2)

1.5       A person lifts a crate vertically upwards at constant velocity through a
          distance h. The person does work x on the crate in time t.

          The person now lifts the same crate vertically upwards at constant velocity
          through the same distance, but in time 2t.

          The work done by the person on the crate will now be …

          A     ½x

          B     x

          C     2x

          D     4x                                                                                                     (2)

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Physical Sciences/P1                          6                             DBE/November 2017
                                             NSC

1.6       The wavelengths of light emitted by a distant star appear shorter when
          observed from Earth. From this we can conclude that the star is …

          A     moving towards Earth and the light is blue shifted.

          B     moving towards Earth and the light is red shifted.

          C     moving away from Earth and the light is red shifted.

          D     moving away from Earth and the light is blue shifted.                             (2)

1.7       Two identical light graphite-coated spheres, P 1 and P 2 , are suspended using
          identical thin insulated threads. P 1 is charged, but P 2 is neutral. The spheres
          are then brought into contact with each other, as shown in diagram I.
          Thereafter the spheres assume the positions, as shown in diagram II.

                           Diagram I                         Diagram II

                                                               θ        θ

                                                      P1                      P2
                      P1           P2

          Which ONE of the following statements concerning the charges on the
          spheres possibly explains why the spheres move apart after touching, as
          shown in diagram II?

                       SIGN OF            SIGN OF               MAGNITUDE OF
                     CHARGE ON P 1      CHARGE ON P 2        CHARGES ON P 1 AND P 2
          A                  +                 +                   Unequal
          B                  -                 -                   Unequal
          C                  +                 -                    Equal
          D                  +                 +                    Equal                         (2)

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Physical Sciences/P1                            7                              DBE/November 2017
                                               NSC

1.8       When a resistor of resistance R is connected to a battery of emf Ɛ and
          negligible internal resistance, the power dissipated in the resistor is P.

          If the resistor is replaced with a resistor of resistance 2R, without changing
          the battery, the power dissipated will be …

          A       ¼P

          B       ½P

          C       2P

          D       4P                                                                                 (2)

1.9       The diagram below shows a current-carrying conductor lying in a uniform
          magnetic field directed to the right. The current flows into the page.

                                               conductor
                                                              magnetic field

          Which ONE of the following arrows shows the direction of the force
          experienced by the conductor due to the magnetic field?
              A                     B                 C                 D

                                                                                                     (2)

1.10      Light of a certain frequency is shone onto a metal M and electrons are ejected
          from the surface. The same source of light is shone onto another metal N.

          The electrons ejected from the surface of metal N have a much higher kinetic
          energy than that from metal M.

          This means that …

          A       metal N has the same work function as metal M.

          B       metal N has a larger work function than metal M.

          C       the threshold frequency of metal N is higher than that of metal M.

          D       the threshold frequency of metal N is lower than that of metal M.                  (2)
                                                                                                     [20]

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Physical Sciences/P1                            8                            DBE/November 2017
                                               NSC

QUESTION 2 (Start on a new page.)

2.1       An 8 kg block, P, is being pulled by constant force F up a rough inclined plane
          at an angle of 30o to the horizontal, at CONSTANT SPEED.

          Force F is parallel to the inclined plane, as shown in the diagram below.

                                              P        F

                                              8 kg

                              30o

          2.1.1        State Newton's First Law in words.                                             (2)

          2.1.2        Draw a labelled free-body diagram for block P.                                 (4)

          The kinetic frictional force between the block and the surface of the inclined
          plane is 20,37 N.

          2.1.3        Calculate the magnitude of force F.                                            (5)

          Force F is now removed and the block ACCELERATES down the plane.
          The kinetic frictional force remains 20,37 N.

          2.1.4        Calculate the magnitude of the acceleration of the block.                      (4)

2.2       A 200 kg rock lies on the surface of a planet. The acceleration due to gravity
          on the surface of the planet is 6,0 m·s-2.

          2.2.1        State Newton's Law of Universal Gravitation in words.                          (2)

          2.2.2        Calculate the mass of the planet if its radius is 700 km.                      (4)
                                                                                                      [21]

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Physical Sciences/P1                            9                       DBE/November 2017
                                               NSC

QUESTION 3 (Start on a new page.)

Stone A is projected vertically upwards at a speed of 12 m∙s-1 from a height h above
the ground. Ignore the effects of air resistance.

3.1       Calculate the time taken for stone A to reach its maximum height.                      (3)

At the same instant that stone A is projected upwards, stone B is thrown vertically
downwards from the same height at an unknown speed, v. Refer to the diagram below.

                                    12 m∙s-1

                                        A            B

                                                     v

                                          h

                                                ground

When stone A reaches its maximum height, the speed of stone B is 3v.

3.2       Calculate the speed, v, with which stone B is thrown downwards.                        (4)

At the instant stone A passes its initial position on its way down, stone B hits
the ground.

3.3       Calculate the height h.                                                                (3)

3.4       Sketch velocity-time graphs for the complete motions of stones A and B on
          the same set of axes. Label your graphs for stones A and B clearly.

          Show the following on the graphs:

          •    The time taken for stone A to reach its maximum height
          •    The velocity with which stone B is thrown downwards                               (4)
                                                                                                 [14]

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Physical Sciences/P1                           10                            DBE/November 2017
                                              NSC

QUESTION 4 (Start on a new page.)

A 2 kg block is at rest on a smooth, frictionless, horizontal table. The length of the
block is x.

A bullet of mass 0,015 kg, travelling east at 400 m∙s-1, strikes the block and passes
straight through it with constant acceleration. Refer to the diagram below. Ignore any
loss of mass of the bullet and the block.

              BEFORE                          AFTER                                  N

                                            0,7 m∙s-1                        W
400 m∙s-1                                                                                    E

bullet               2 kg
                                                                                     S
                      x                          x

4.1       State the principle of conservation of linear momentum in words.                          (2)

The block moves eastwards at 0,7 m∙s-1 after the bullet has emerged from it.

4.2       Calculate the magnitude of the velocity of the bullet immediately after it
          emerges from the block.                                                                   (4)

4.3       If the bullet takes 0,002 s to travel through the block, calculate the length, x, of
          the block.                                                                                (5)
                                                                                                    [11]

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Physical Sciences/P1                         11                          DBE/November 2017
                                            NSC

QUESTION 5 (Start on a new page.)

In the diagram below, a 4 kg block lying on a rough horizontal surface is connected to
a 6 kg block by a light inextensible string passing over a light frictionless pulley.

Initially the blocks are HELD AT REST.

                       4 kg

                                                               6 kg

                                                                      1,6 m

                                                               6 kg

5.1       State the work-energy theorem in words.                                                (2)

When the blocks are released, the 6 kg block falls through a vertical distance of 1,6 m.

5.2       Draw a labelled free-body diagram for the 6 kg block.                                  (2)

5.3       Calculate the work done by the gravitational force on the 6 kg block.                  (3)

The coefficient of kinetic friction between the 4 kg block and the horizontal surface
is 0,4. Ignore the effects of air resistance.

5.4       Use energy principles to calculate the speed of the 6 kg block when it falls
          through 1,6 m while still attached to the 4 kg block.                                  (5)
                                                                                                 [12]

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Physical Sciences/P1                                     12               DBE/November 2017
                                                        NSC

QUESTION 6 (Start on a new page.)

A police car moving at a constant velocity with its siren on, passes a stationary listener.

The graph below shows the changes in the frequency of the sound of the siren
detected by the listener.

                            180

                            170

           Frequency (Hz)
                            160

                            150

                            140

                            130

                            120

                            110

                              0
                                                                        time (s)

6.1       State the Doppler Effect in words.                                                      (2)

6.2       Write down the frequency of the sound detected by the listener as the
          police car:

          6.2.1                   Approaches the listener                                         (1)

          6.2.2                   Moves away from the listener                                    (1)

6.3       Calculate the speed of the police car. Take the speed of sound in air to
          be 340 m∙s-1.                                                                           (6)
                                                                                                  [10]

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Physical Sciences/P1                                 13                  DBE/November 2017
                                                    NSC

QUESTION 7 (Start on a new page.)

Two small spheres, X and Y, carrying charges of +6 x 10-6 C and +8 x 10-6 C
respectively, are placed 0,20 m apart in air.

                                           0,20 m

                     X   ● -6                               ●Y -6
               +6 x 10 C                                  +8 x 10 C

7.1       State Coulomb's law in words.                                                         (2)

7.2       Calculate the magnitude of the electrostatic force experienced by charged
          sphere X.                                                                             (4)

A third sphere, Z, of unknown negative charge, is now placed at a distance of 0,30 m
below sphere Y, in such a way that the line joining the charged spheres X and Y
is perpendicular to the line joining the charged spheres Y and Z, as shown in the
diagram below.

                                                0,20 m

                          6 x 10-6 C                            8 x10-6 C
                                  X
                                       ●                      ●Y

                                                                    0,30 m

                                                              ●Z
7.3       Draw a vector diagram showing the directions of the electrostatic forces and
          the net force experienced by charged sphere Y due to the presence of
          charged spheres X and Z respectively.                                                 (3)

7.4       The magnitude of the net electrostatic force experienced by charged sphere Y
          is 15,20 N. Calculate the charge on sphere Z.                                         (4)
                                                                                                [13]

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Physical Sciences/P1                               14                        DBE/November 2017
                                                  NSC

QUESTION 8 (Start on a new page.)

A and B are two small spheres separated by a distance of 0,70 m. Sphere A carries a
charge of +1,5 x 10-6 C and sphere B carries a charge of -2,0 x 10-6 C.

                                                0,70 m
                                       0,40 m
                         A●                              P
                                                                  ●  B
                       +1,5 x 10-6 C                         -2,0 x 10-6 C

P is a point between spheres A and B and is 0,40 m from sphere A, as shown in the
diagram above.

8.1       Define the term electric field at a point.                                               (2)

8.2       Calculate the magnitude of the net electric field at point P.                            (4)

8.3       A point charge of magnitude 3,0 x 10-9 C is now placed at point P.

          Calculate the magnitude of the electrostatic force experienced by this charge.           (3)
                                                                                                   [9]

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Physical Sciences/P1                                                    15                        DBE/November 2017
                                                                       NSC

QUESTION 9 (Start on a new page.)

9.1                              Learners investigated the relationship between potential difference (V) and
                                 current (I) for the combination of two resistors, R 1 and R 2 . In one experiment,
                                 resistors R 1 and R 2 were connected in parallel. In a second experiment,
                                 resistors R 1 and R 2 were connected in series.

                                 The learners then plotted graph X, the results of one of the experiments, and
                                 graph Y, the results of the other experiment, as shown below.

                                  GRAPHS OF POTENTIAL DIFFERENCE VERSUS CURRENT FOR THE
                                  COMBINATION OF TWO RESISTORS IN SERIES AND IN PARALLEL

                                   3,00

                                  2,50

      Potential difference (V)
                                   2,00
                                                                     X
                                  1,50

                                  1,00
                                                                                    Y
                                  0,50

                                         0               0,25                0,50          0,75
                                                                     Current (A)

                                 9.1.1        State Ohm's law in words.                                                   (2)

                                 9.1.2        What physical quantity does the gradient (slope) of the V-I graph
                                              represent?                                                                  (1)

                                 9.1.3        Calculate the gradient (slope) of graph X.                                  (2)

                                 9.1.4        Determine the resistance of resistor R 1 .                                  (4)

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                                                         NSC

9.2       The circuit below consists of three resistors, M, N and T, a battery with
          emf Ɛ and an internal resistance of 0,9 Ω. The effective resistance between
          points a and b in the circuit is 6 Ω. The resistance of resistor T is 1,5 Ω.

                                                                   V1

                                                a•      M               N      •
                                                                                b
                                                        V2

           Ɛ

                  r = 0,9 Ω

                                                               1,5 Ω
                                    ●       ●                  T
                                        S

          When switch S is closed, a high-resistance voltmeter, V 1 , across a and b
          reads 5 V.

          Calculate the:

          9.2.1                Current delivered by the battery                                    (3)

          9.2.2                Emf (Ɛ) of the battery                                              (4)

          Voltmeter V 2 reads 2,5 V when the switch is closed.

          9.2.3                Write down the resistance of N. (No calculations required.)
                               Give a reason for the answer.                                       (2)
                                                                                                   [18]

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Physical Sciences/P1                                17                     DBE/November 2017
                                                   NSC

QUESTION 10 (Start on a new page.)

10.1      The diagram below shows different positions (ABCDA) of the coil in
          a DC generator for a complete revolution. The coil is rotated clockwise at a
          constant speed in a uniform magnetic field.

          The direction of the magnetic field is shown in the diagram below.

                                  magnetic field

          10.1.1       Write down the energy conversion that takes place during the
                       operation of the DC generator.                                             (1)

          10.1.2       Sketch a graph to show how the induced emf of the generator
                       varies with time. Clearly indicate positions A, B, C, D and A on the
                       graph.                                                                     (2)

10.2      A small AC generator, providing an rms voltage of 25 V, is connected across
          a device with a resistance of 20 Ω. The wires connecting the generator to the
          device have a total resistance of 0,5 Ω. Refer to the diagram below.

                                                           generator
                           wire

                                               20 Ω device

          10.2.1       Write down the total resistance of the circuit.                            (1)

          10.2.2       Calculate the average power delivered to the device.                       (5)
                                                                                                  [9]

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Physical Sciences/P1                        18                      DBE/November 2017
                                           NSC

QUESTION 11 (Start on a new page.)

11.1      A teacher in a science class explains how different types of spectra are
          obtained. The teacher uses the simplified diagrams shown below for the
          explanation.

                                           light               Spectrum Y

                                 hot gas
                                             Diffraction grating

                                                               Spectrum Z

                                      cold gas
             hot, glowing bulb                Diffraction grating

          Name the type of spectrum of:

          11.1.1       Y                                                                  (1)

          11.1.2       Z                                                                  (1)

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Physical Sciences/P1                                        19                         DBE/November 2017
                                                           NSC

11.2      In an excited atom, electrons can 'jump' from lower energy levels to higher
          energy levels. They can also 'drop' from higher energy levels to lower energy
          levels.

          The diagram below (not drawn to scale) shows some of the transitions for
          electrons in an excited atom.

                                       E4                                  2,044 x 10-18 J

                                                                           1,937 x 10-18 J

                Increasing energy
                                      E3

                                       E2                                  1,635 x 10-18 J

          11.2.1                    Do the transitions indicated in the diagram lead to ABSORPTION
                                    or EMISSION spectra?                                                   (1)

          11.2.2                    Calculate the frequency of the photon produced when an electron
                                    in an excited atom makes a transition from E 4 to E 2 , as shown in
                                    the diagram.                                                           (4)

          The threshold frequency of a metal, Q, is 4,4 x 1014 Hz.

          11.2.3                    Calculate the kinetic energy of the most energetic electron ejected
                                    when the photon produced in QUESTION 11.2.2 is incident on the
                                    surface of metal Q.                                                    (4)

          Another metal, R, has a threshhold frequency of 7,5 x 1014 Hz.

          11.2.4                    Will the photon produced in QUESTION 11.2.2 be able to eject
                                    electrons from the surface of metal R? Write down only YES
                                    or NO.

                                    Give a reason for the answer.                                          (2)
                                                                                                           [13]

                                                                                              TOTAL:       150

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Physical Sciences/P1                     1                     DBE/November 2017
                                        NSC

                        DATA FOR PHYSICAL SCIENCES GRADE 12
                                  PAPER 1 (PHYSICS)

                     GEGEWENS VIR FISIESE WETENSKAPPE GRAAD 12
                                VRAESTEL 1 (FISIKA)

TABLE 1: PHYSICAL CONSTANTS/TABEL 1: FISIESE KONSTANTES

          NAME/NAAM                SYMBOL/SIMBOOL     VALUE/WAARDE
Acceleration due to gravity
                                         g                 9,8 m·s-2
Swaartekragversnelling
Universal gravitational constant
                                         G           6,67 x 10-11 N·m2·kg-2
Universele gravitasiekonstante
Radius of the Earth
                                         RE              6,38 x 106 m
Radius van die Aarde
Mass of the Earth
                                         ME             5,98 x 1024 kg
Massa van die Aarde
Speed of light in a vacuum
                                          c             3,0 x 108 m·s-1
Spoed van lig in 'n vakuum
Planck's constant
                                         h              6,63 x 10-34 J·s
Planck se konstante
Coulomb's constant
                                          k           9,0 x 109 N·m2·C-2
Coulomb se konstante
Charge on electron
                                         e               -1,6 x 10-19 C
Lading op elektron
Electron mass
                                         me             9,11 x 10-31 kg
Elektronmassa

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Physical Sciences/P1                                  2                                        DBE/November 2017
                                                     NSC

TABLE 2: FORMULAE/TABEL 2: FORMULES

MOTION/BEWEGING
v f = vi + a ∆t                                     Δx = v i Δt + 21 a∆t 2 or/of Δy = v i Δt + 21 a∆t 2
                                                          v + vf                 v + vf 
  2        2                    2
v f = v i + 2a∆x or/of v f = v i + 2a∆y
                                        2
                                                    Δx =  i       Δt or/of Δy =  i       Δt
                                                          2                      2 

FORCE/KRAG

Fnet = ma                                           p = mv
f s max = μ sN                                      fk = μk N
Fnet ∆t = ∆p
                                                    w = mg
∆p = mv f – mv i
        m1m 2                               m1m 2             M                              M
 F=G 2           or/of              F=G             g =G                   or/of         g =G 2
          d                                  r2               d2                             r

WORK, ENERGY AND POWER/ARBEID, ENERGIE EN DRYWING

W = F∆x cos θ                                       U = mgh                 or/of        EP = mgh

                                                    Wnet = ∆K              or/of         Wnet = ∆Ek
   1                                     1
K = mv 2             or/of          E k = mv 2
   2                                     2
                                                    ∆K = K f − K i          or/of        ∆Ek = Ekf − Eki
                                                         W
Wnc = ∆K + ∆U or/of Wnc = ∆Ek + ∆Ep                 P=
                                                         ∆t
P ave = Fv ave / P gemid = Fv gemid

WAVES, SOUND AND LIGHT/GOLWE, KLANK EN LIG

                                                         1
v=fλ                                                T=
                                                         f
       v ± vL                       v ± vL                                          hc
fL =          fs             fL =          fb       E = hf         or/of     E=
       v ± vs                       v ± vb                                           λ
E = Wo + Ek(max) or/of E = Wo + K max where/waar
                                                     1                     1
E = hf     and/en    W0 = hf0 and/en Ek (max) =           2
                                                       mv max                  2
                                                              or/of K max = mv max
                                                     2                     2

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Physical Sciences/P1                                     3                                        DBE/November 2017
                                                        NSC

ELECTROSTATICS/ELEKTROSTATIKA

     kQ 1Q 2                                                kQ
F=                                                     E=
       r2                                                   r2

     W                                                      F
V=                                                     E=
     q                                                      q
      Q                            Q
n=                or/of       n=
      e                            qe

ELECTRIC CIRCUITS/ELEKTRIESE STROOMBANE

                                                       emf ( ε ) = I(R + r)
      V
R=
      I                                                emk ( ε ) = I(R + r)

R s = R1 + R 2 + ...
 1     1     1                                         q = I∆t
    =    +      + ...
R p R1 R 2

W = Vq                                                      W
                                                       P=
                                                            ∆t
W = VI ∆ t
                                                       P = VI
W = I2R ∆ t

          2
                                                       P = I 2R
      V ∆t
W=                                                          V2
       R                                               P=
                                                            R

ALTERNATING CURRENT/WISSELSTROOM

                                                       Pave = Vrms I rms       /   Pgemiddeld = Vwgk I wgk
         Imax                                 I maks
Irms =                    /         I wgk =
              2                                  2              2
                                                       Pave = I rms R          /   Pgemiddeld = I 2wgk R
          Vmax                              Vmaks
Vrms =                    /        Vwgk =                       2
                                                              Vrms
                                                                                                    2
                                                                                                   Vwgk
              2                                2       Pave =              /       Pgemiddeld =
                                                               R                                    R

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