# Physical Sciences Grade 12 P2 Eastern Cape June 2024 Memo > Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape June Exam 2024 (Afrikaans), 19 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/physical-sciences-p2-gr12-memo-june-2024-afrikaans-engl/ead7fe64-ea3b-4472-97c9-f94cbb9afe69 - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 12 - Language: Afrikaans - Document type: Memorandum - Year: 2024 - Exam period: Eastern Cape June Exam - Paper: 2 - Curriculum: CAPS - Pages: 19 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 P2 Eastern Cape June 2024 Memo](https://www.hlayiso.com/library/physical-sciences-p2-gr12-memo-june-2024-afrikaans-engl/ead7fe64-ea3b-4472-97c9-f94cbb9afe69) ## About this document Physical Sciences · Grade 12 · Eastern Cape June Exam · 2024 · Afrikaans. Memorandum, 19 pages. Read online or download the PDF. 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Layout, diagrams and tables may not survive extraction. ### Page 1 NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIORSERTIFIKAAT GRADE/GRAAD 12 JUNE/JUNIE 2024 PHYSICAL SCIENCES: CHEMISTRY P2/ FISIESE WETENSKAPPE: CHEMIE V2 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 19 pages./ Hierdie nasienriglyn bestaan uit 19 bladsye. ### Page 2 2 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) QUESTION 1/VRAAG 1 1.1 C  (2) 1.2 D  (2) 1.3 A  (2) 1.4 D  (2) 1.5 B  (2) 1.6 B  (2) 1.7 C  (2) 1.8 C  (2) 1.9 B  (2) 1.10 B  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 3 QUESTION 2/VRAAG 2 2.1 A series of organic compounds that can be described by the same general formula  ʼn Reeks organiese verbindings wat deur dieselfde algemene formule beskryf kan word. OR/OF A series of organic compounds in which one member differs from the next with a CH2 group  ʼn Reeks organiese verbindings waarin een lid van die volgende verskil met ʼn CH2 -groep (2) 2.2 2.2.1 B (1) 2.2.2 A (1) 2.2.3 B (1) 2.2.4 C (1) 2.3 Secondary alcohol / Sekondêre alkohol  The carbon that contains the hydroxyl group/ -OH is bonded to two carbon atoms.  Die koolstof wat die hidroksielgroep / -OH bevat is verbind aan twee ander koolstowwe OR/OF The hydroxyl group / -OH is bonded to a secondary carbon. Die hidroksielgroep / -OH is verbind aan ʼn sekondêre koolstof OR/OF The carbon that contains the hydroxyl group / OH contains one hydrogen atom Die koolstof wat die hidroksielgroep / OH bevat het een waterstof-atoom (2) 2.4 2.4.1 CnH2n  (1) 2.4.2 4-methylpent-2-ene  Marking criteria/Nasienkriteria: 4-metielpen-2-een • Pent-2-ene / 2-pentene OR/OF Pent-2-een / 2-penteen 4-methyl-2-pentene  • Whole name correct  4-metiel-2-penteen Hele naam korrek (2) 2.4.3 5,5-dimethylhexan-3-ol  Marking criteria/Nasienkriteria: 5,5-dimetielhexan-3-ol • Hexan-3-ol / 3-hexanol  OR/OF • Dimethyl / dimetiel  5,5-dimethyl-3-hexanol  • Whole name correct / hele naam 5,5-dimetiel-3-hexanol korrek  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 4 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) 2.5 2.5.1 Marking criteria/Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: -1 mark per word/phrase. Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: -1 punt per woord/frase. Compounds that have the same molecular formula but different functional groups.  Verbindings met dieselfde molekulêre formule maar verskillende funksionele groepe. (2) 2.5.2 H H H O  H C C C C H  Marking criteria/Nasienkriteria H H H • Functional group / funksionele groep  1/2 • Whole structure correct / Hele struktuur korrek 2/2 (2) 2.6 2.6.1 Esterification / Condensation / Esterifikasie / Kondensasie  (1) 2.6.2 Mol C : Mol H : Mol O Marking criteria/Nasienkriteria 58,82 : 9,81 : 31,37 • % C divide by M (C/)    12 : 1 : 16 % C gedeel deur M (C) • % H divide by M (H)/ 4,90 : 9,81 : 1,96 % H gedeel deur M(H) • % O divide by M (O)/ % O gedeel deur M (O) 2,5 : 5 : 1 • Simplest mole ratio/ Eenvoudigste molverhouding 5 : 10 : 2 • Molecular formula/ Molekulêre formule Empirical formula / Empiriese formule: C5H10O2 Molecular Formula / Molekulêre formule: C5H10O2  (5) 2.6.3 M (CXHYO2) = 74 g·mol-1 12n + 2n + 2(16) = 74  n=3 Propanoic acid/Propanoësuur  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 5 2.6.4 Marking criteria/Nasienkriteria • Determining the molar mass of alcohol P / Bepaal die molekulêre massa van alkohol P  • Identifying alcohol P / Identifiseer alkohol P  • Name of ester / Naam van ester  • Structural formula of the ester/ Struktuurformule van die ester  Propanoic acid + alcohol P → ester + H2O Propanoësuur + alkohol P→ ester + H2O M (Alcohol / Alkohol P) = 102 + 18 – 74 = 46 g·mol-1  Alcohol / Alkohol P = Ethanol / etanol  Marking criteria/Nasienkriteria • Functional group / Ester = ethyl  propanoate  funksionele groep  1/2 Ester = etielpropanoaat C6H12O2 • Whole structure correct / Hele struktuur korrek 2/2 H H O H H  H C C C O C C H H H H H (6) [34] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 6 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) QUESTION 3/VRAAG 3 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die sleutelwoorde frases in die korrekte konteks weggelaat word: -1 punt per woord/frase. 3.1 Boiling point is the temperature at which the vapour pressure of a liquid / substance equal the atmospheric pressure  Kookpunt is die temperatuur waarby die dampdruk van ʼn vloeistof/stof gelyk aan die atmosferiese druk is. (2) 3.2 Alcohols are flammable / Alkohole is vlambaar  (1) 3.3 140 (°C)  (1) 3.4 YES.  Compounds have the same molecular mass/ compounds are Isomers / only one independent variable.  JA. Verbindings het dieselfde molekulêre massa/ verbindings is isomere / slegs een onafhanklike veranderlike. (2) 3.5 2-methylbutan-1-ol  2-metielbutan-1-ol Marking criteria/Nasienkriteria: OR/OF • butan-1-ol  2-methyl-1-butanol  2-metiel-1-butanol • Whole name correct / hele naam korrek  (Accept/Aanvaar) 3-methylbutan-1-ol  3-metielbutan-1-ol OR/OF 3-methyl-1-butanol  3-metiel-1-butanol (2) 3.6 Alcohol 3  accept: 2,2-dimethylpropan-1-ol / 2,2-dimethyl-1-propanol Alkohol 3 aanvaar: 2,2-metielpropan-1-ol/ 2,2-dimetiel-1-propanol (1) 3.7 Marking criteria / Nasienkriteria • Chain length decreases from 1 to 3 Kettinglengte neem af vanaf 1 tot 3 • Decrease in the strength of the London forces/dispersion forces/induced dipole forces from 1–3 Afname in die sterkte van die Londonkragte/verspreidingskragte/ Geїnduseerde dipool-dipool kragte vanaf 1–3 • Relate the strength of London forces/dispersion forces/induced dipole to energy involved Vergelyk the sterkte van die Londonkragte/verspreidingskragte/ Geїnduseerde dipool-dipool kragte na die energie Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 7 From 1 to 3 • Surface area / chain length decreases / increased in the number of branches  Oppervlakte / kettinglengte neem af / toename in die aantal takke • Strength of London forces/dispersion forces/induced dipole forces decreases  Sterkte van die Londonkragte/verspreidingskragte/geїnduseerde dipool- dipool kragte neem af • Less energy is needed to overcome intermolecular forces  Minder energie word benodig om die intermolekulêre kragte te oorkom OR/OF Marking criteria/Nasienkriteria • Chain length increases from 3 to 1 Kettinglengte neem toe vanaf 3 na 1 • Increase in the strength of the London forces/dispersion forces/induced dipole forces from 3 to 1 Toename in die sterkte van die Londonkragte/Verspreidingskragte / geїnduseerde dipool-dipool kragte vanaf 3 na 1 • Relate the strength of London forces to energy involved. Vergelyk the sterkte van die Londonkragte/Verspreidingskragte/ geїnduseerde dipool-dipool kragte na die energie From 3 to 1 / Vanaf 3 tot 1 • Surface area / chain length increases/ decreased in the number of branches  Oppervlakte/ kettinglengte neem toe/ afname in die aantal takke • Strength of London forces/Dispersion forces/Induced dipole forces increases  Sterkte van die Londonkragte/Verspreidingskragte /Geїnduseerde dipool-dipool kragte neem toe • More energy needed to overcome intermolecular forces  Meer energie word benodig om die intermolekulêre kragte te oorkom (3) 3.8 3.8.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase. The pressure exerted by a vapour at equilibrium with its liquid in a closed system. / Die druk uitgeoefen deur ʼn damp in ewewig met sy vloeistof in ʼn geslote sisteem. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 8 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) 3.8.2 Marking criteria/Nasienkriteria • Butan-1-ol has hydrogen bonds ✓/ Butan-1-ol het waterstofbinding • Butanone has dipole-dipole forces ✓ / Butanoon het dipool-dipool kragte / • Compare the strength of the hydrogen bonds to dipole-dipole forces ✓/ Vergelyk die sterkte van die waterstofbinding met dipool-dipoolkragte / • Relate strength intermolecular forces to vapour pressure ✓/ Verwys die sterkte van die intermolekulêrekragte met die dampdruk • Butan-1-ol has hydrogen bonds (and London forces) / Butan-1-ol het waterstofbinding (en Londonkragte) • Butanone has dipole-dipole forces (and London forces) / Butanoon het dipool-dipoolkragte (en Londonkragte) • Hydrogen bonds is stronger than the dipole-dipole forces / Waterstofbinding is sterkter as die dipool-dipoolkragte • Stronger intermolecular forces result in lower vapour pressure / Sterker intermolekulêrekragte lei tot laer dampdruk OR/OF • Butan-1-ol has for hydrogen bonds (and London forces) / Butan-1-ol het waterstofbinding (en Londonkragte) • Butanone has dipole-dipole forces (and London forces) / Butanoon het dipool-dipoolkragte (en Londonkragte) • Dipole-dipole forces weaker than the hydrogen bonds / Dipool-dipoolkragte is swakker as die waterstofbinding • Weaker intermolecular forces result in higher vapour pressure / Swakker intermolekulêrekragte sal tot ʼn hoër dampdruk lei (4) 3.8.3 INCREASE / TOENEEM ✓ (1) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 9 QUESTION 4/VRAAG 4 4.1 4.1.1 Dehydration / Dihidratering / dihidrasie  (1) 4.1.2 Sulphuric acid / swawelsuur / H2SO4  (1) 4.1.3 Marking criteria/Nasienkriteria: Organic compounds only/ Slegs vir organiese verbinding • Functional group/ funksionele groep  1/2 • Whole structure correct / Hele struktuur korrek  (2/2) Hele struktuur korrek  2/2 H  H H O H H H H H H C C C C H H C C C C H H H H H H H + H2O (4) 4.1.4 Addition / hydrohalogenation / Addisie / hidrohalogenering/ hidrohalogenasie  (1) 4.1.5 2-bromobutane / Marking criteria/ Nasienkriteria 2-bromobutaan Name of compound / Naam van verbinding • Butane / butaan  1/2 H Br H H • Whole name correct  2/2  hele naam korrek H C C C C H Structure / • Functional group  1/2 H H H H funksionele groep • Whole structure correct /Hele struktuur korrek 2/2 hele struktuur korrek (4) 4.1.6 Mild heat  and dilute strong base /LiOH/KOH/NaOH / Matige hitte en verdunde sterk basis /LiOH/KOH/NaOH (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 10 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) 4.2 4.2.1 Breaking down of long chain hydrocarbon molecules into more useful shorter chains  (2 or 0) / Die proses waarin langer kettingkoolwaterstof-molekule afgebreek word in korter, meer bruikbare, molekule (2 of 0) (2) 4.2.2 Minimize the UV light present / No substitution reaction can occur in the saturated hydrocarbon / Verminder die teenwoordige UV-lig / Geen substitusiereaksie kan in die versadigde koolwaterstof plaasvind nie (1) 4.2.3 C4HZ.  It readily reacts with bromine (without the presence of UV- light)  C4HZ. Dit reageer geredelik met broom (sonder die teenwoordigheid van UV-lig) (2) 4.2.4 Marking criteria/Nasienkriteria H H H H • Functional group  ½ Funksionele groep  • Whole structure correct/  2/2 H C C C C H  Hele struktuur korrek H H (2) 4.2.5 2 C4H10 + 13 O2  → 8 CO2 + 8 H2O  ( bal.) Marking criteria / Nasienkriteria • Reactants / Reaktanse 1/3 • Products / Produkte 2/3 • Balancing / Balansering 3/3 (3) [23] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 11 QUESTION 5/VRAAG 5 5.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. / Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase ANY ONE Change in concentration ✓ of reactant or product per (unit) time. ✓ Change in amount/number of moles/volume/mass ✓of products or reactants per (unit) time. ✓ Change in amount/number of moles/volume/mass ✓ of products formed or reactants used reactants per (unit) time. ✓ ENIGE EEN Verandering in konsentrasie van reaktanse of produkte per (eenheid) tyd. Verandering in hoeveelheid/getal mol/volume/massa van reaktanse of produkte per (eenheid) tyd. Verandering in hoeveelheid/getal mol/volume/massa van produkte gevorm / reaktanse gebruik per (eenheid) tyd. OR/OF The rate of change in concentration/amount of moles/number of moles / volume / mass.  (2 or 0) Die tempo van verandering in konsentrasie / hoeveelheid mol / getal mol / volume / massa. (2 of 0) (2) 5.2 Temperature / Temperatuur  (1) 5.3 5.3.1 Experiment / Eksperiment 2  (1) 5.3.2 OPTION 1 / OPSIE 1 • In experiment 2 more particles are exposed / larger surface area  • More particles will collide with the correct orientation  • More effective collisions per unit time / Frequency of the effective collisions increases  • In eksperiment 2 word meer deeltjies blootgestel / groter oppervlakte • Meer deeltjies sal met die korrekte oriëntasie bots • Meer effektiewe botsings per tydseenheid / Frekwensie van die effektiewe botsings neem toe Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 12 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) OR/OF OPTION 2 / OPSIE 2 • In experiment 3 less particles are exposed / smaller surface area  • Less particles will collide with the correct orientation  • Less effective collisions per unit time / Frequency of the effective collisions decreases  • In eksperiment 3 word minder deeltjies blootgestel / kleiner oppervlakte • Minder deeltjies sal met die korrekte oriëntasie bots • Minder effektiewe botsings per tydseenheid / Frekwensie van die effektiewe botsings neem af (3) 5.4 5.4.1 Marking criteria / Nasienkriteria • Subst. Into the rate equation • Vervang in die tempo • Subst. into n = m/M vergelyking • Using the mol ratio CO2 : • Vervang in n = m/M MgCO3 • Gebruik die mol verhouding CO2 • Formula m = nM : MgCO3 • Subst. into m = nM • Formule m = n/M • Final answer • Vervanging in m = n/M • Finale antwoord Rate/ Δm = Tempo Δt m–0 0,25 =  10,44 m = 2,61 g M n = m 2,61 n =  44 n = 0,0593 mol n (CO2) = n (MgCO3) = 0,0593 mol  m = nM ✓ m = (0,0593)(84)  m = 4,9812 g  (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 13 5.4.2 V n =  Vm 1,47 0,0593 =  Vm Vm = 24,79 dm3  (3) 5.5 Marking criteria / Nasienkriteria B • Shape of B starting at the origin  Number of CO2 Vorm van B begin by oorsprong A • Curve of B is higher / Kurwe B is hoër  NOTE: A or B must be indicated molecules/Aantal CO2- Ignore the labels of the axes. molekules LET WEL: A of B moet aangedui word. Ignoreer die benoeming van die asse. Kinetic energy / Kinetiese energie (2) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 14 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) QUESTION 6/VRAAG 6 6.1 6.1.1 Marking criteria/ Nasienkriteria If any of the underlined key words/phrases in the correct context are omitted: - 1 mark per word/phrase. Indien enige van die sleutelwoorde/frases in die korrekte konteks weggelaat word: - 1 punt per woord/frase When the equilibrium in a closed system is disturbed, the system will re- instate a new equilibrium by favouring the reaction that will oppose/cancel the disturbance.  Wanneer die ewewig in ʼn geslote sisteem versteur word, sal die sisteem ʼn nuwe ewewig deur die reaksie wat die versteuring teenwerk, te bevoordeel (2) 6.1.2 EQUAL TO / GELYK AAN  Chemical equilibrium is reached / Chemiese ewewig word bereik  (2) 6.1.3 Y 2 mol of SO2 will react for every 1 mol of O2 / 2 mol van SO2 sal reageer met elke 1 mol van O2 OR/OF The rate at which SO2 is consumed is twice that of O2./ Die tempo waarteen SO2 verbruik word is twee keer as dié van O2 OR/OF 0,925 mol of SO2 reacted with 0,46 mol of O2 / 0,925 mol van SO2 reageer met 0,46 mol O2 (2) 6.1.4 NEGATIVE / NEGATIEF  (1) 6.1.5 • The amount/concentration of SO3 increased / SO2 and O2 decreased  • (According to Le Chatelier’s principle) A decrease in temperature favours the exothermic reaction.  • The forward reaction was favoured / The equilibrium position shifted towards the right  • Die hoeveelheid/konsentrasie van SO3 neem toe / SO2 en O2 verlaag • (Volgens Le Chatelier se beginsel) ʼn Afname in temperatuur bevoordeel die eksotermiese reaksie • Die voorwaartse reaksie word bevoordeel / Die ewewigsposisie verskuif na regs (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 15 6.2 6.2.1 OPTION 1: MOLE CALCULATIONS / OPSIE 1: MOLBEREKENINGE a. Determine the change in mol of NOCℓ / Bepaal die verandering in mol van NOCℓ b. Correct ratio NOCℓ : NO : Cℓ2 / Korrekte verhouding NOCℓ : NO : Cℓ2 c. Determine the equilibrium mol for NOCℓ , NO and Cℓ2 / Bepaal die ewewig mol van NOCℓ , NO en Cℓ2 d. Dividing by/ Deel deur 1,5 e. Correct Kc expression with square brackets / Korrekte Kc uitdrukking met vierkanthakkies f. Subst. into the correct Kc expression /Vervanging in korrekte Kc uitdrukking g. Final answer / Finale antwoord Δn (NOCℓ) = 2,5 x 28/100 = 0,7  (a) 2 NOCℓ 2 NO (g) Cℓ2 (g) Initial mol 2,5 - - Aanvangsmol Change in mol Verandering in 0,7 0,7 0,35 (b)  mol Equilibrium (c)  mol 1,8 0,7 0,35 Ewewigsmol Concentration =1,8 / 1,5 = 0,7 / 1,5 =0,35 / 1,5 (d)  Konsentrasie = 1,2 = 0,47 0,23 [NO]2[Cℓ2] Kc = (e)  [NOCℓ]2 (0,47)2(0,23) Kc = (f)  (1,2)2 Kc = 0,035  (g) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 16 16 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) OPTION 2: CONCENTRATION CALCULATIONS / OPSIE 2: KONSENTRASIE BEREKENINGE a. Determine the initial concentration NOCℓ / Bepaal die aanvanklike konsentrasie van NOCℓ b. Determine the change in conc of NOCℓ / Bepaal die verandering in konsentrasie van NOCℓ c. Correct ratio NOCℓ : NO : Cℓ2 / Korrekte verhouding NOCℓ : NO : Cℓ2 d. Determine the equilibrium conc. for NOCℓ , NO and Cℓ2 / Bepaal die ewewigs konsentrasie van NOCℓ , NO en Cℓ2 e. Correct Kc expression with square brackets / Korrekte Kc uitdrukking met vierkanthakkies f. Subst. into the correct Kc expression/ Vervanging in korrekte Kc uitdrukking g. Final answer / Finale antwoord ci (NOCℓ) = 2,5 ÷ 1,5 = 1,67 ✓ (a) Δc (NOCℓ) = 1,67 x 28 / 100 = 0,47 ✓ (b) 2 NOCℓ 2 NO (g) Cℓ2 (g) Initial concentration 1,67 - - Aanvangskonsentrasie Change in concentration 0,47 0,47 0,235 (c)  Verandering in konsentrasie Equilibrium concentration 1,2 0,47 0,235 (d)  ewewigskonsentrasie [NO]2[Cℓ2] Kc = (e)  [NOCℓ]2 (0,47)2(0,23) Kc = (f)  (1,2)2 a.Kc = 0,035  (g) (7) 6.2.2 REMAINS THE SAME / BLY DIESELFDE  Only temperature has an effect on the value of the equilibrium constant. / Slegs temperatuur het ʼn effek op die waarde van die ewewigskonstante (2) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 17 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 17 QUESTION 7/VRAAG 7 7.1 7.1.1 Acids produce hydrogen ions (H+/H3O+/ hydronium ions) in aqueous solutions. / ʼn Suur is ʼn stof wat waterstof-ione (H+/H3O+/ hydroniumione) vorm wanneer dit in water oplos (2) 7.1.2 H2O and / en HSO4–  (2) 7.1.3 H2SO4 + 2 KOH  → K2SO4 + 2 H2O  ( bal.) Marking criteria/ Nasienkriteria • Reactants / Reaktanse • Products /Produkte • Balancing / Balansering (3) 7.2 7.2.1 OPTION 1 / OPSIE 1 OPTION 2 / OPSIE 2 m m c =  n = MV M 3,812 3,812 c =  n = (40)(100x10-3) 40 c = 0,953 mol· dm-3  n = 0,0953 mol n c =  V 0,0953 c =  100x10-3 c = 0,953 mol·dm-3  (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 18 18 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2024) 7.2.2 OPTION 1 / OPSIE 1 Marking criteria/ Nasienkriteria • Subst. c and V of NaOH into n = cV / Vervang van c en V van NaOH in n = Cv • Use of ratio CH3COOH : NaOH • Gebriuk van verhouding CH3COOH : NaOH • Subst. of n and V of CH3COOH into c = n/V / Vervang van c en V van CH3COOH in n = cV • Formula / Formule m = cMV • Subst. into / Vervanging in m = cMV • Subst. into percentage formula / Vervanging in persentasie- formule • Final answer / Finale antwoord n (NaOH) = cV n (NaOH) = (0,953)(21,8 x 10-3)  n (NaOH) = 0,0207754 mol n (CH3COOH) = n (NaOH) = 0,0207754 mol  n c = V 0,0207754 c =  25 x 10-3 c = 0,831016 mol·dm-3 m = cMV  m = (0,831016)(60)(25 x 10-3)  m = 1,2465 g Percentage mass / 1,2465 = X 100 %  Persentasie massa 25 Percentage mass / Persentasie massa = 4,986 %  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 19 (EC/JUNE/JUNIE 2024) PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2 19 OPTION 2 / OPSIE 2 Marking criteria / Nasienkriteria c V n • Subst. into / Vervang in na and/ en nb ca Va = na b b b ca Va na • Subst. into / Vervang in Va c V = n b b b c V n • Subst. into / Vervang in cb and/ en Vb ca Va = na b b b • Formula /Formule m = cMV • Subst into / Vervanging in m = cMV • Subst into percentage formula / Vervanging in persentasie formule • Final answer / Finale antwoord caVa na = cbVb nb ca(25)  1 =  (0,953)(21,8)  1 ca = 0,831016 mol·dm-3 m = cMV  m = (0,831016)(60)(25 x 10-3)  m = 1,2465 g Percentage mass / 1,2465 = X 100%  Persentasie massa 25 Percentage mass / Persentasie massa = 4,986%  (7) [17] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - 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