# Physical Sciences Grade 12 Paper 2 NSC June 2022 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the NSC June Exam 2022, 17 pages. Read online or download the free PDF.

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- Updated: 2026-10-29
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2022
- Exam period: NSC June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 17

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             SENIOR CERTIFICATE EXAMINATIONS/
         NATIONAL SENIOR CERTIFICATE EXAMINATIONS
               SENIORSERTIFIKAAT-EKSAMEN/
          NASIONALE SENIORSERTIFIKAAT-EKSAMEN

                      PHYSICAL SCIENCES: CHEMISTRY (P2)
                      FISIESE WETENSKAPPE: CHEMIE (V2)

                                          2022

                      MARKING GUIDELINES/NASIENRIGLYNE

                                                                  MARKS/PUNTE: 150

                     These marking guidelines consist of 16 pages./
                      Hierdie nasienriglyne bestaan uit 16 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2     2                                        DBE/2022
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

QUESTION 1/VRAAG 1

1.1      B                                                                                        (2)

1.2      D                                                                                        (2)

1.3      B                                                                                        (2)

1.4      D                                                                                        (2)

1.5      B                                                                                        (2)

1.6      D                                                                                        (2)

1.7      C                                                                                        (2)

1.8      A                                                                                        (2)

1.9      A                                                                                        (2)

1.10     B                                                                                         (2)
                                                                                                    [20]

QUESTION 2/VRAAG 2

2.1
2.1.1     E                                                                                        (1)

2.1.2     F                                                                                        (1)

2.1.3     C                                                                                        (1)

2.1.4     H                                                                                        (1)

2.2
2.2.1     2-bromo-2,4,5-trimethylhexane/2-broom-2,4,5-trimetielheksaan
          Marking criteria:                           Nasienkriteria:
           Correct stem i.e. hexane.                 Korrekte stam d.i. heksaan. 
           All substituents (bromo and trimethyl)     Alle substituente (bromo and trimetiel)
            correctly identified.                      korrek geïdentifiseer. 
           IUPAC name completely correct              IUPAC-naam heeltemal korrek
            including numbering, sequence,              insluitende volgorde, koppeltekens en
            hyphens and commas.                        kommas.                                    (3)

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Physical Sciences P2/Fisiese Wetenskappe V2      3                                            DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

2.2.2                 H                               Marking criteria/Nasienkriteria:
                                                       Five C atoms in longest chain + triple
                 H   C    H                             bond. 
                H                       H               Vyf C-atome in langste ketting +
                                                       drievoudige binding.
                                                      Two methyl substituents. 
         H      C     C    C     C      C    H 
                                                        Twee metielsubstituente.
                                                       Whole structure correct.
                H                       H               Hele struktuur korrek. 
                H    C    H

                     H
          IF/INDIEN
           More than one functional group/wrong functional group:
              Meer as een funksionele groep/foutiewe funksionele groep:                   0
                                                                                       3
             If condensed structural formulae used/Indien gekondenseerde struktuurformules
              gebruik:                                                    Max/Maks.: 2
                                                                                         3               (3)

2.3
2.3.1     Aldehyde/Aldehied                                                                             (1)

2.3.2     Formyl/Formiel                                                                                (1)

2.3.3           H    H     O H                       Marking criteria/Nasienkriteria:
                                                       Functional group. 
         H      C    C     C    C       H              Funksionele groep.
                                                       Whole structure correct.
                H    H          H                       Hele struktuur korrek. 
          IF/INDIEN
           More than one functional group/wrong functional group:
              Meer as een funksionele groep/foutiewe funksionele groep:                   0
                                                                                       2
             If condensed structural formulae used/Indien gekondenseerde struktuurformules
              gebruik:                                                    Max/Maks.: 1
                                                                                        2                (2)

2.4
2.4.1     Methylpropane/2-methylpropane/Metielpropaan/2-metielpropaan                                  (2)

2.4.2     2C4H10 + 13O2  → 8CO2 + 10H2O                   Bal. 

          Ignore phases./Ignoreer fases.
          Marking criteria/Nasienkriteria:
              Reactants          Products        Balancing: 
               Reaktanse           Produkte         Balansering
              Ignore double arrows./Ignoreer dubbelpyle.
              Marking rule 6.3.10/Nasienreël 6.3.10.
          IF: Structural formula for C4H10 Max. 2/3
          INDIEN: Structural formula for C4H10 Max. 2/3                                                   (3)
                                                                                                         [19]
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Physical Sciences P2/Fisiese Wetenskappe V2      4                                          DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

QUESTION 3/VRAAG 3

3.1       Marking criteria/Nasienkriteria
          If any one of the underlined key phrases in the correct context is omitted, deduct 1
          mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
          trek 1 punt af.
         The temperature at which the vapour pressure of a substance equals
         atmospheric/external pressure. 
         Die temperatuur waar die dampdruk van 'n stof gelyk is aan atmosferiese/
         eksterne druk.                                                                                 (2)

3.2
3.2.1     Increases/Neem toe                                                                           (1)

3.2.2     From A to C:
           Increase in molecular mass/size/chain length/surface area/number of C
             atoms. 
           Strength of the intermolecular forces increases/More sites for London
             forces. 
           More energy is needed to overcome/break intermolecular forces. 

          OR
          From C to A:
           Decrease in molecular mass/size/chain length/surface area/number of C
             atoms. 
           Strength of the intermolecular forces decreases/Less sites for London
             forces. 
           Less energy is needed to overcome/break intermolecular forces. 

          Van A na C:
           Verhoging in molekulêre massa/molekulêre grootte/kettinglengte/reaksie-
            oppervlak/aantal C-atome. 
           Sterkte van die intermolekulêre kragte verhoog./Meer punte vir
            Londonkragte. 
           Meer energie benodig om intermolekulêre kragte te oorkom/breek. 

          OF
          Van C na A:
           Verlaging in molekulêre massa/molekulêre grootte/kettinglengte/reaksie-
            oppervlak/aantal C-atome. 
           Sterkte van die intermolekulêre kragte verlaag./Minder punte vir
            Londonkragte. 
           Minder energie benodig om intermolekulêre kragte te oorkom/breek.                          (3)
3.3       No / Nee 
          More than one independent variable./Molar mass and chain length (surface
          area) are changing. 
          Meer as een onafhanklike veranderlike./Molêre massa (reaksie-oppervlak) en
          kettinglengte verander.                                                                       (2)

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Physical Sciences P2/Fisiese Wetenskappe V2      5                                          DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

3.4
3.4.1       Functional group/homologous series/type of intermolecular forces/type of                    (1)
            compound 
            Funksionele groep/homoloë reeks/soort intermolekulêre kragte/tipe verbinding

3.4.2       Dipole-dipole forces/Dipool-dipoolkragte                                                   (1)

3.5         D / methylbutane / metielbutaan 
        -
            Lower boiling point/Weaker intermolecular forces 
            Laer kookpunt/Swakker intermolekulêre kragte                                                 (2)
                                                                                                        [12]

QUESTION 4/VRAAG 4

4.1
4.1.1       Dehydrohalogenation/elimination/dehydrobromination 
            Dehidrohalogenering/eliminasie/dehidrobrominering                                           (1)

4.1.2       2-methylbut-2-ene / 2-methyl-2-butene         Marking criteria/Nasienkriteria
            2-metielbut-2-een / 2-metiel-2-buteen         Methylbutene/metielbuteen 
                                                            IUPAC name correct/IUPAC-naam
                                                            korrek                                     (2)
            IF/INDIEN
            Any error, e.g. hyphens omitted and/or incorrect sequence/Enige fout, bv.
            koppeltekens weggelaat en/of verkeerde volgorde: Max/Maks: 1
                                                                         2

4.1.3       Water/H2O                                                                                  (1)

4.1.4       Heat/Hitte                                       ACCEPT/AANVAAR:
            (Concentrated) sulphuric acid/catalyst           High temperature/
            (Gekonsentreerde) swawelsuur/katalisator          Hoë temperatuur                           (2)

4.1.5           H                                Marking criteria/Nasienkriteria
                                                 Whole structure correct/Hele struktuur
                O    H     H     H                 korrek: 2
                                                            2
            H   C    C     C    C       H         Only functional group correct:/Slegs
                                                    funksionele groep korrek: Max/Maks.: 1
                                                                                          2
                H     H    H    H                IF/INDIEN
                                                 More than one functional group/Meer as een
                                                 funksionele groep                            0
                                                                                                  2     (2)

4.2
4.2.1       Catalyst/Lowers the activation energy./Increases the rate of the reaction. 
            Katalisator/Verlaag die aktiveringsenergie./Laat reaksietempo toeneem.                      (1)

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Physical Sciences P2/Fisiese Wetenskappe V2      6                                            DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

4.2.2     The bromine water/Br2/solution decolourises. 
          Die broomwater/Br2/oplossing ontkleur.

          OR/OF
          Bromine water/Br2/solution changes from brown/reddish to colourless.
          Broomwater/Br2/oplossing verander van bruin/rooi na kleurloos.                                   (1)

4.2.3    Addition/halogenation/bromination                                                                (1)
         Addisie/halogenering/brominering

4.2.4    C2H6  (3 or/of 0)           OR/OF        C4H10        OR/OF        C6H14

         IF structural/condensed formulae: (2 or 0)
         INDIEN struktuurformules/gekondenseerde formules gebruik: (2 of 0)                                (3)

4.2.5     Marking criteria                               Nasienkriteria
           Correct functional group i.e. double          Korrekte funksionele groep d.i.
             bond.                                         dubbelbinding. 
           Correct number of C atoms in relation         Korrekte aantal C-atome na
             to answer in Q4.2.4.                          aanleiding van antwoord in V4.2.4. 
           Whole structure correct.                     Hele struktuur korrek. 
          IF condensed/molecular formulae                INDIEN gekondenseerde/molekulêre
          used: Max. 2⁄3                                 formules gebruik: Maks. 2⁄3
          IF C2H6 in QUESTION 4.2.4/INDIEN C2H6 in VRAAG 4.2.4:
               H            H                         H         H                    H
                                                                       
                                            
         H     C     C     C      C     H        OR/OF       H     C    C      C     C     H 

               H     H     H      H                                      H     H     H

          IF C4H10 in QUESTION 4.2.4/                    IF C6H14 in QUESTION 4.2.4:
          INDIEN C4H10 in VRAAG 4.2.4:                   INDIEN C6H14 in VRAAG 4.2.4:
                H             H                               H
                                                                  H
          H     C     C       C   H     
                                                         H    C     C    H 
                      H       H
                                                                                                          (3)
                                                                                                          [17]

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Physical Sciences P2/Fisiese Wetenskappe V2      7                                          DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

QUESTION 5/VRAAG 5

5.1       NOTE/LET WEL
          Give the mark for per unit time only if in context of reaction rate.
          Gee die punt vir per eenheidtyd slegs indien in konteks met reaksietempo.
          ANY ONE:
           Change in concentration  of products/reactants per (unit) time. 
             Change in amount/number of moles/volume/mass of products or reactants
              per (unit) time.
             Amount/number of moles/volume/mass of products formed/reactants used
              per (unit) time.
           Rate of change in concentration/amount/number of moles/volume/
            mass. (2 or 0)
          ENIGE EEN:
           Verandering in konsentrasie van produkte/reaktanse per (eenheid) tyd.
             Verandering in hoeveelheid/getal mol/volume/massa van produkte of
              reaktanse per (eenheid) tyd.
             Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse
              gebruik per (eenheid) tyd.
             Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/
              volume/massa. (2 of 0)                                                                    (2)

5.2        Surface area / state of division / particle size (of MgCO3) 
           Concentration (of HCℓ) 

           Reaksieoppervlak/toestand van verdeeldheid/deeltjie-grootte (van MgCO3)
           Konsentrasie (van HCℓ)                                                                      (2)

5.3          At a higher temperature particles move faster/have a higher kinetic
              energy. 
             More molecules have enough/sufficient kinetic energy for an effective
              collision. 
              OR More molecules have kinetic energy/Ek equal to or greater than the
              activation energy.
             More effective collisions per unit time/second. 
              OR Frequency of effective collisions increases.
             Reaction rate increases. 
             By 'n hoër temperatuur beweeg die deeltjies vinniger/het die deeltjies
              hoër kinetiese energie. 
             Meer molekule het genoeg/voldoende kinetiese energie/Ek vir 'n
              effektiewe botsing. 
              OF Meer molekule het kinetiese energie gelyk aan of groter as die
              aktiveringsenergie.
             Meer effektiewe botsings per eenheidtyd/sekonde. 
              OF Frekwensie van effektiewe botsings verhoog.
             Reaksietempo neem toe.                                                                   (4)

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Physical Sciences P2/Fisiese Wetenskappe V2      8                                                   DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

5.4.1     Marking criteria                                  Nasienkriteria
                         m                                                   m
           Formula: n =                                    Formule: n =     
                         M                                                   M
                                                m                                                m
           Substitution of 84 g∙mol-1 in n =               Vervanging van 84 g∙mol-1 in n =       

           Use mole ratio:                                  Gebruik molverhouding:
            n(MgCO3)used = n(CO2)produced                    n(MgCO3)gebruik = n(CO2)berei 
                                                        m                                                m
           Substitution of 44 g∙mol-1 in n =                Vervanging van 44 g∙mol-1 in n =
            or to calculate rate in mol·min-1.               of om tempo te bereken in mol·min-1. 
           Correct substitution of 0,5 in rate              Korrekte vervanging van 0,5 in
            equation.                                        tempovergelyking. 
           Final answer: 5,238 to 5,28 min                 Finale antwoord: 5,238 tot 5,28 min 
                                                    m
                                 n(MgCO3) =             
                                                   5
                                                =
                                                  84 
                                                = 0,06 mol(0,0595 mol)
                                 n(CO2)produced/gevorm = n(MgCO3)  = 0,06 mol 
          

                   m                                        Ave rate/gem tempo in mol·min-1:
          n(CO2) =
                   M                                        0,5 
                                                                 = 0,0114 mol·min-1
                    m                                        44
            0,06 =
                   44                                                             n(CO2 )
          m(CO2) = 2,64 g                                  Ave rate/gem tempo =
                                                                                      t
                                    m(CO2 )                          0,06
          Ave rate/gem tempo =                              0,0114 =
                                       t                              t
                                   2,64                          ∆t = 5, 28 min 
                           0,5 =
                                    t
                              ∆t = 5,28 min                                                                    (6)

5.4.2     POSITIVE MARKING FROM QUESTION 5.4.1.
          POSITIEWE NASIEN VANAF VRAAG 5.4.1.
          Marking criteria                        Nasienkriteria
           Substitution of n(CO2) AND 1,5 dm3 in  Vervanging van n(CO2) EN 1,5 dm3 in
                   V                                              V
              n=      .                                     n=      .
                   Vm                                             Vm
           Final answer:                                    Finale antwoord:
           \25 to 25,21 dm3·mol-1                           25 dm3 tot 25,21 dm3·mol-1 
                  V
               n=
                 Vm
                 1,5 
          0,06 
                 Vm
          Vm = 25 dm3·mol-1 (25,21 dm3·mol-1)
          ACCEPT/AANVAAR: 25 dm3                                                                                (2)

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Physical Sciences P2/Fisiese Wetenskappe V2      9                                                     DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

5.5

          Number of CO2 molecules
                                            B

                                        1
                                                    A

            Aantal CO2-molekule
                                                        2

                                     Kinetic energy/Kinetiese energie
                               Marking criteria/Nasienkriteria
                                     Curve B has a higher peak to the left of curve A.
                                 1 Kurwe B het hoër piek aan die linkerkant van kurwe A.     
                                     Curve B is below curve A beyond the peak of curve
                                 2 A./Kurwe B is onder kurwe A na die piek van kurwe A.      
                               If BOTH graphs not labelled (A and B): no marks
                               Indien BEIDE grafieke nie benoem nie (A en B): geen punte
                                                                                                                    (2)
                                                                                                                   [18]
QUESTION 6/VRAAG 6
6.1.1    2 (mol·dm-3)                                                                                             (1)

6.1.2     Marking criteria/Nasienkriteria:
          If any one of the underlined key phrases in the correct context is omitted, deduct 1
          mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
          trek 1 punt af.
          When the equilibrium in a closed system is disturbed, the system will re-
          instate a (new) equilibrium  by favouring the reaction that will cancel/oppose
          the disturbance. 
          Wanneer die ewewig in 'n geslote sisteem versteur word, sal die sisteem 'n
          (nuwe) ewewig instel deur die reaksie te bevoordeel wat die versteuring
          kanselleer/teenwerk.                                                                                     (2)
6.1.3     Cooled/Afgekoel                                                                                         (1)

6.1.4                   A decrease in temperature favours the exothermic reaction./An increase in
                         temperature favours the endothermic reaction. 
                        The forward reaction is favoured./HI concentration increases./Equilibrium
                         (position) shifts to the right. 
                        The forward reaction is exothermic./Reverse reaction is endothermic. 

           Afname in temperatuur bevoordeel die eksotermiese reaksie./Toename in
            temperatuur bevoordeel die endotermiese reaksie. 
           Die voorwaartse reaksie word bevoordeel./ HI-konsentrasie neem toe./Die
            ewewigs(posisie) skuif na regs. 
           Voorwaatse reaksie is eksotermies./Die terugwaartse reaksie is
            endotermies.                                                                                          (3)

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                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

6.2
6.2.1     Products can be converted back to reactants. 
          OR
          Both forward and reverse reactions can take place.
          OR
          A reaction which can take place in both directions.

          Produkte kan omgeskakel word na reaktanse. 
          OF
          Beide voor-en terugwaartse reaksies kan plaasvind.
          OF
          ’n Reaksie wat in beide rigtings kan plaasvind.                                                (1)

6.2.2     Marking criteria                            Nasienkriteria:
          a) Δn(N2O4) = n(N2O4)eq – n(N2O4)ini.     (a) Δn(N2O4) = n(N2O4)ewe – n(N2O4)aanv.
          b) USING ratio:                            (b) GEBRUIK verhouding:
             n(NO2) : n(N2O4) = 2 : 1                   n(NO2) : n(N2O4) = 2 : 1 
          c) n(NO2)eq = n(NO2)ini - ∆n(NO2)         (c) n(NO2)ewe = n(NO2)aanv - ∆n(NO2) 
          d) Divide BOTH by 1 dm3                   (d) Deel BEIDE deur 1 dm3 
          e) Correct Kc expression (formulae in      (e) Korrekte Kc uitdrukking (formules in
             square brackets).                          vierkantige hakies). 

                                                            NO2            N2O4
           Initial amount (moles)
                                                             x                 0
           Aanvangshoeveelheid (mol)
           Change in amount (moles)                                                (a)   ratio 
                                                            1,62          0,81          verhouding
           Verandering in hoeveelheid (mol)
           Equilibrium amount (moles)                              (c)
           Ewewigshoeveelheid (mol)                     x – 1,62             0,81
           Equilibrium concentration (mol∙dm-3)
                                                          x – 1,62            0,81
           Ewewigskonsentrasie (mol∙dm-3)

                [N2 O 4 ] (e)               Wrong or no Kc expression/Verkeerde of geen Kc-
          Kc                              uitdrukking: Max./Maks.
                [NO2 ] 2
                    (0,81)                     4⁄
              =                                  5
                 ( x  1,62) 2                                                                           (5)

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Physical Sciences P2/Fisiese Wetenskappe V2     11                                            DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

6.2.3       POSITIVE MARKING FROM QUESTION 6.2.2
            POSITIEWE NASIEN VAN VRAAG 6.2.2.
            Marking criteria                            Nasienkriteria:
            a) Add 0,79 mol to n(N2O4)ini.             (a) Voeg 0,79 mol by n(N2O4)aanv. 
            b) USING ratio: n(NO2) : n(N2O4) = 2 : 1    (b) GEBRUIK verhouding:
               to calculate ∆n(N2O4) as 0,6 mol.           n(NO2) : n(N2O4) = 2 : 1
            c) n(NO2)eq = n(NO2)ini + ∆n(NO2)               om ∆n(N2O4) as 0,6 mol te bereken. 
               n(N2O4)eq = n(N2O4)ini - ∆n(N2O4)       (c) n(NO2)ewe = n(NO2)aanv + ∆n(NO2)
            d) Substitution of concentrations into          n(N2O4)ewe = n(N2O4)aanv - ∆n(N2O4) 
               correct Kc expression.                  (d) Vervanging van konsentrasies in
            e) Equating Kc expresssion from Q6.1.3          korrekte Kc-uitdrukking.
               and Q6.2.3.                             (e) Stel Kc-uitdrukking van Q6.1.3 en
            f) Final answer: 12,42                         Q6.2.3 gelyk aan mekaar. 
               (Range: 11,27 – 12,42)                   (f) Finale antwoord: 12,42 
                                                            (Gebied: 11,27 – 12,42)

                                                           NO2                N2O4
             Initial amount (moles)                                       0,81 + 0,79 
                                                         x – 1,62
             Aanvangs hoeveelheid (mol)                                       = 1,6
             Change in amount (moles)
                                                            1,2               0,6 
             Verandering in hoeveelheid (mol)
             Equilibrium amount (moles)                                               (c)
                                                       x – 1,62 +1,2             1
             Ewewigshoeveelheid (mol)
             Equilibrium concentration (mol∙dm-3)
                                                         x – 0,42                1
             Ewewigskonsentrasie (mol∙dm-3)
                               [N2 O 4 ]        Wrong Kc expression/Verkeerde Kc- uitdrukking:
                       Kc 
                               [NO2 ] 2
                                                Max./Maks. 4⁄6
                          (e)
                (0,81)            1            No Kc expression/Geen Kc- uitdrukking: 6⁄6
                                        (d)
             ( x  1,62) 2 ( x  0,42) 2
                           x = 12,42 (mol) (f)                                                            (6)
                                                                                                          [19]
QUESTION 7/VRAAG 7
7.1
7.1.1       An acid is a proton (H+ ion) donor. 
            'n Suur is 'n protondonor/skenker of H+-ioon donor/skenker.                                   (2)
7.1.2       HY 
        -
            For the SAME acid concentration:
            Lower pH / higher H+ or H3O+ concentration / more ionised. 
            Vir DIESELFDE suurkonsentrasie:
            Laer pH / hoër H+/H3O+ konsentrasie / meer geïoniseer.                                        (2)
7.1.3       Lower than./Laer as 
        -
            Ka < 1 / HX ionises incompletely. / HX has a small Ka value. / HX is a weak
            acid. 
            Ka < 1 / HX ioniseer onvolledig. / HX het 'n klein Ka-waarde. / HX is 'n swak
            suur.                                                                                         (2)

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Physical Sciences P2/Fisiese Wetenskappe V2     12                                           DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

7.2
7.2.1    pH = -log[H3O+] OR/OF [H3O+] = 10-pH 
         2  = -log[H3O+]
         [H3O+] = 0,01 mol∙dm-3  (1 x 10-2 mol∙dm-3)                                                    (3)

7.2.2    POSITIVE MARKING FROM QUESTION 7.2.1.
         POSITIEWE NASIEN VAN VRAAG 7.2.1.
         Marking criteria for OPTION 1:                Nasienkriteria vir OPSIE 1:
          Substitute c(HCℓ)excess and 0,35 dm
                                                  3
                                                        Vervang c(HCℓ)oormaat en 0,35 dm3 om
           to calculate n(HCℓ)excess.                   n(HCℓ)oormaat te bereken.
          Substitute to calculate n(HCℓ)initial       Vervang om n(HCℓ)aanv te bereken. 
          n(HCℓ)react = n(HCℓ)ini – n(HCℓ)excess.    n(HCℓ)rea = n(HCℓ)aanv – (HCℓ)oormaat
          Use ratio:                                   Gebruik verhouding:
           n(NaOH) = n(HCℓ)                             n(NaOH) = n(HCℓ) 
                                        n                                          n
          Substitute 0,15 dm3 in c = .                Vervang 0,15 dm3 in c = . 
                                                                                   V
          Final answer: 0,02 mol∙dm-3                 Finale antwoord: 0,02 mol∙dm-3 
           or 0,0167 mol∙dm-3 or 0,017 mol∙dm-3          of 0,0167 mol∙dm-3 of 0,017 mol∙dm-3
         OPTION 1/OPSIE 1
         n(HCℓ)excess/oormaat = cV
                                = 0,01 x 0,35 
                                = 3,5 x 10-3 mol
         n(HCℓ)initial/aanv = cV
                            = 0,03 x 0,2 
                            = 0,006 mol

         n(HCℓ)reacted/reageer = 0,006 – 3,5 x 10-3 
                             = 0,0025 mol
         n(NaOH)reacted/reageer = n(HCℓ)reacted/reageer = 0,0025 mol 
                      n
         c(NaOH) =
                      V
                     0,0025
                   =
                       0,15 
                   = 0,02 mol∙dm-3        (0,0167 mol∙dm-3 or/of 0,017 mol∙dm-3)

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Physical Sciences P2/Fisiese Wetenskappe V2     13                                              DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

         OPTION 2/OPSIE 2                            Marking criteria
         Concentration ratio in final solution:       Ratio HCℓ : H3O+ = 1 : 1 
         Konsentrasie verhouding in finale            c(HCℓ)excess = 0,01 (mol·dm-3) 
         oplossing:                                   n(HCℓ)react = n(HCℓ)ini –(HCℓ)excess.
         HCℓ : H3O+ = 1 : 1                          Use ratio:
                                                       n(NaOH) = n(HCℓ) 
         Thus/dus [HCℓ] = 0,01 mol·dm-3             Final answer: 0,02 mol∙dm-3 
                                                     Nasienkriteria
         [HCℓ]react = [HCℓ]initial - [HCℓ]excess      Verhouding HCℓ : H3O+ = 1 : 1 
                                                      c(HCℓ)oormaat = 0,01 (mol·dm-3) 
                    = 0,03 – 0,01 
                                                      n(HCℓ)reag = n(HCℓ)aanv –(HCℓ)oormaat.
                    = 0,02 mol·dm-3
                                                      Gebruik verhouding:
                                                       n(NaOH) = n(HCℓ) 
         Concentration ratio in final solution:       Finale antwoord: 0,02 mol∙dm-3 
         Konsentrasie verhouding in
         oorspronklike oplossing:
         HCℓ : NaOH = 1 : 1 

         [NaOH] = 0,02 mol·dm-3 
         OPTION 3/OPSIE 3                            Marking criteria
                                                                             c      n
         c1 1 n1                                      Substitute 350 cm3 in c1 1 = n1 
             =                                                                   2 2        2
         c2 2 n2                                        Ratio of HCℓ : H3O+ = 1 : 1 
           c1 (200)    1                                n(HCℓ)react = n(HCℓ)ini –(HCℓ)excess.
                      =                                Use ratio: n(NaOH) = n(HCℓ) 
         (0,01)(350)  1                                                          c    n
                                                        Substitute 150 cm3 in c1 1 = n1 
         c1 = 0,0175 mol·dm-3                                                    2 2        2
                                                      Final answer: 0,02 mol∙dm-3 
                                                                   or 0,0167 mol∙dm-3
         c(HCℓ)react = c(HCℓ)ini – c(HCℓ)excess                    or 0,017 mol∙dm-3
                        = 0,03 – 0,0175            Nasienkriteria
                        = 0,0125 mol·dm-3                                  c V    n
                                                      Vervang 350 cm3 in c1 V1 = n1 
         ca a na                                                               2 2      2
             =                                        Verhouding HCℓ : H3O+ = 1 : 1 
         cb b nb
                                                      n(HCℓ)reag = n(HCℓ)aanv –(HCℓ)oormaat.
                                                      Gebruik verhouding:
         (0,0125)(200) 1                               n(NaOH) = n(HCℓ) 
                      = 
            cb (150)  1                                                    c V   n
                                                      Vervang 150 cm3 in 1 1 = 1 
                                                                              c2 V2    n2

         c(NaOH) = 0,0167 mol·dm        -3           Finale antwoord: 0,02 mol∙dm-3 
                                                                      of 0,0167 mol∙dm-3
                                                                      of 0,017 mol∙dm-3
         (0,0167 mol∙dm-3
         or/of 0,017 mol∙dm-3)                                                                              (7)
                                                                                                           [16]

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Physical Sciences P2/Fisiese Wetenskappe V2     14                                                 DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

QUESTION 8/VRAAG 8

8.1
8.1.1     Temperature/Temperatuur: 25 °C/298 K 
          Pressure/Druk: 101,3 kPa/1 atmosphere 
          Concentration/Konsentrasie: 1 mol·dm-3                                                              (3)

8.1.2    OPTION 1/OPSIE 1                            Notes/Aantekeninge
             
           E cell    
                   Ereduction     
                                E oxidation         Accept any other correct formula from the
                   
                                                       data sheet./Aanvaar enige ander korrekte
          2,89 = Ereduction – (-1,66)                formule vanaf gegewensblad.
          
         Ereduction = 1,23 (V)                       Any other formula using unconventional
                                                       abbreviations, e.g. E°cell = E°OA - E°RA followed
                                                       by correct substitutions:/Enige ander formule
         X is O2/oxygen/suurstof                      wat onkonvensionele afkortings gebruik bv.
                                                        E°sel = E°OM - E°RM gevolg deur korrekte
         [X marked independently/
                                                       vervangings:      4
         X onafhanklik nagesien]                                           5
         OPTION 2/OPSIE 2
         O2(g) + 4H+ + 4e  2H2O                                   E  = +1,23 V 
                                                 
         Aℓ(s) → Aℓ3+(aq) + 3e-                                     E  = +1,66 V 
         4Aℓ(s) + 3O2(g) + 12H+  4Aℓ3+(aq) + 6H2O                  E  = +2,89 (V) 

         X is O2/oxygen/suurstof 

         [X marked independently/X onafhanklik nagesien]                                                       (5)

8.1.3     Aℓ                                                                                                  (1)

8.1.4    O2(g) + 4H+ + 4e → 2H2O 

         Ignore phases./Ignoreer fases.
          Marking criteria/Nasienkriteria:
           2H2O ← O2(g) + 4H+ + 4e     (2 )        O2(g) + 4H+ + 4e ⇌ 2H2O  (1 )
                                            2                                      2
                                         0                                      0
                       +
            O2(g) + 4H + 4e ← 2H2O (          )      2H2O ⇌ O2(g) + 4H + 4e
                                                                        +
                                                                                (     )
                                            2                                       2
           Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op
            elektron.
           If charge (+) omitted on H+/ Indien lading (+) weggelaat op H+: Max./Maks: 1
                                                                                         2
                                                   
            Example/Voorbeeld: O2(g) + 4H + 4e → 2H2O                                                         (2)
                             
8.1.5    Aℓ (s) | Aℓ3+(aq) || O2(g) | H+(aq) | H2O(ℓ) | Pt(s)

                                            
         OR/OF
         Aℓ (s) | Aℓ3+(aq) || O2(g) | H+(aq) | H2O(ℓ) | C(s)

         OR/OF
         Aℓ | Aℓ3+ || O2 | H+ | H2O | Pt                                                                       (3)

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Physical Sciences P2/Fisiese Wetenskappe V2     15                                          DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

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Physical Sciences P2/Fisiese Wetenskappe V2     16                                          DBE/2022
                           SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

8.2      Copper/Koper 

            Cu is a weaker reducing agent than Ni and will not reduce Ni2+ (to Ni). /
             Cu will not be oxidised (to Cu2+).
            Zn is a stronger reducing agent than Ni and will reduce Ni2+ (to Ni). / Zn
             will be oxidised (to Zn2+).

            Cu is 'n swakker reduseermiddel as Ni en sal nie Ni2+ (na Ni) reduseer nie.
             / Cu sal nie geoksideer word nie na (Cu2+).
            Zn is 'n sterker reduseermiddel as Ni en sal Ni2+ (na Ni) reduseer. / Zn sal
             geoksideer word (na Zn2+).

         NOTE/LET WEL:
         The mark for 'reduce' can be awarded at any ONE of the two comparisons.
         Die punt vir 'reduseer' kan toegeken word by ENIGEEN van die twee
         vergelykings.                                                                                   (4)
                                                                                                        [18]

QUESTION 9/VRAAG 9

9.1      Marking criteria/Nasienkriteria:
         If any one of the underlined key phrases in the correct context is omitted, deduct 1
         mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
         trek 1 punt af.
         ANY ONE/ENIGE EEN:
          The chemical process in which electrical energy is converted to
            chemical energy. 
          The use of electrical energy to produce a chemical change.
          Decomposition of an ionic compound by means of electrical energy.
          The process during which an electric current passes through a
            solution/ionic liquid/molten ionic compound.
             Die chemiese proses waarin elektriese energie omgeskakel word na
              chemiese energie. 
             Die gebruik van elektriese energie om 'n chemiese verandering te weeg
              te bring.
             Ontbinding van 'n ioniese verbinding met behulp van elektriese energie.
             Die proses waardeur 'n elektriese stroom deur 'n oplossing/ioniese
              vloeistof/gesmelte ioniese verbinding beweeg.                                             (2)

9.2
9.2.1    X                                                                                             (1)

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Physical Sciences P2/Fisiese Wetenskappe V2    17                                       DBE/2022
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

9.2.2    2H2O(ℓ) + 2e-  H2(g) + 2OH─(aq) 

         Ignore phases/Ignoreer fases
         Marking criteria/Nasienkriteria:
           H2(g) + 2OH─(aq) ← 2H2O(ℓ) + 2e- ( 2 ) 2H2O(ℓ) + 2e- ⇌ H2(g) + 2OH─(aq) ( 1 )
                                                   2                                       2
                         ─                       0                                ─      0
            H2(g) + 2OH (aq) ⇌ 2H2O(ℓ) + 2e ( -                    -
                                                     ) 2H2O(ℓ) + 2e ← H2(g) + 2OH (aq) (     )
                                                   2                                       2
          Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op
            elektron.
          If charge (-) omitted on OH- /Indien lading (-) weggelaat op OH─:
            Example/Voorbeeld: 2H2O(ℓ) + 2e-  H2(g) + 2OH(aq)              Max./Maks: 1
                                                                                           2       (2)

9.2.3    X to/na Y                                                                                (1)

9.2.4    2H2O(ℓ) + 2Cℓ─(aq)  → Cℓ2(g) + H2(g) + 2OH─(aq)                   Bal 

         OR/OF
         2H2O(ℓ) + 2NaCℓ(aq) → Cℓ2(g) + H2(g) + 2NaOH(aq)

         Ignore phases/Ignoreer fases
         Marking criteria/Nasienkriteria:
            Reactants         Products         Balancing: 
             Reaktanse          Produkte          Balansering
            Ignore double arrows./Ignoreer dubbelpyle.
            Marking rule 6.3.10/Nasienreël 6.3.10.                                                (3)

9.3      Increases / Toeneem                                                                      (1)

9.4      Solution becomes basic / alkaline OR NaOH / OH─ (ions) form 
         Oplossing word basies / alkalies OF NaOH / OH─(-ione) vorm                                 (1)
                                                                                                   [11]

                                                                             TOTAL/TOTAAL:         150

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