# Physical Sciences Grade 12 P2 NSC June 2025 Memo (Afrikaans)

> Grade 12 Physical Sciences Paper 2 memorandum from the NSC June Exam 2025 (Afrikaans), 22 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physical-sciences-p2-may-june-2025-mg-afr-eng/3225a5c0-3161-416b-a268-b1363034248d
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Language: Afrikaans
- Document type: Memorandum
- Year: 2025
- Exam period: NSC June Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 22

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Physical Sciences · Grade 12 · NSC June Exam · 2025 · Afrikaans. Memorandum, 22 pages. Read online or download the PDF.

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### Page 1

SENIOR CERTIFICATE EXAMINATIONS/
         NATIONAL SENIOR CERTIFICATE EXAMINATIONS
               SENIORSERTIFIKAAT-EKSAMEN/
          NASIONALE SENIORSERTIFIKAAT-EKSAMEN

                       PHYSICAL SCIENCES: CHEMISTRY (P2)
                       FISIESE WETENSKAPPE: CHEMIE (V2)

                            MAY/JUNE 2025/MEI/JUNIE 2025

                      MARKING GUIDELINES/NASIENRIGLYNE

                                                                   MARKS/PUNTE: 150

                      These marking guidelines consist of 22 pages.
                       Hierdie nasienriglyne bestaan uit 22 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2     2                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 1/VRAAG 1

 1.1      B  ACCEPT/AANVAAR 2                                                                        (2)

 1.2      D                                                                                          (2)

 1.3      D                                                                                          (2)

 1.4      A                                                                                          (2)

 1.5      B                                                                                          (2)

 1.6      C                                                                                          (2)

 1.7      D                                                                                          (2)

 1.8      B                                                                                          (2)

 1.9      C                                                                                          (2)

 1.10     C                                                                                          (2)
                                                                                                       [20]

 QUESTION 2/VRAAG 2

 2.1      Compounds with one or more multiple bonds between C atoms in the
          hydrocarbon chain.  (2 or 0)
          Verbindings met een of meer meervoudige bindings tussen C-atome in die
          koolwaterstofkettings. (2 of 0)

          OR/OF
          A hydrocarbon with two or more bonds between the C-atoms.
          'n Koolwaterstof met twee of meer bindings tussen die C-atome.

          OR/OF
          Hydrocarbons containing not only single bonds between C atoms.
          Koolwaterstowwe wat nie slegs enkelbindings tussen die C-atome bevat nie.

          ACCEPT/AANVAAR:
          Compounds with one or more double/triple bonds between C atoms in the
          hydrocarbon chain.
          Verbindings met een of meer dubbel/trippelbindings tussen C-atome in die
          koolwaterstofkettings.                                                                       (2)

 2.2
 2.2.1     E                                                                                          (1)

 2.2.2     F                                                                                          (1)

 2.3       Ketones/Ketone 
           Aldehydes/Aldehiede                                                                        (2)
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Physical Sciences P2/Fisiese Wetenskappe V2     3                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 2.4      Tertiary/Tersiêre 
          The hydroxyl group/functional group (-OH) is bonded to a C atom that is bonded
          to three other C atoms. 
          Die hidroksiel/funksionele groep (-OH) is gebind aan 'n C-atoom wat aan drie
          ander C-atome gebind is.
          OR/OF
          The functional group (        C    ) is bonded to three other C atoms.

                                        OH

          Die funksionele groep (       C     ) is gebind aan drie ander C-atome.

                                        OH                                                             (2)

 2.5
 2.5.1     Marking criteria:
           • Correct stem, i.e. hexane. 
           • Both substituent (ethyl and iodo) correctly identified. 
           • IUPAC name completely correct including numbering, sequence, hyphens and
              commas. 
           Nasienkriteria:
           • Korrekte stam, d.i. heksaan. 
           • Beide substituent (etiel en jodo) korrek geïdentifiseer. 
           • IUPAC-naam heeltemal korrek insluitende nommering, volgorde, koppeltekens en
              kommas. 

           3-ethyl-4-iodohexane/3-etiel-4-jodoheksaan                                                (3)

 2.5.2     Marking criteria/Nasienkriteria:
           • Correct stem and substituents: methyl and propanol 
             Korrekte stam en substituente: metiel en propanol
           • IUPAC name completely correct including numbering, sequence, hyphens and
             commas. 
              IUPAC-naam heeltemal korrek insluitende nommering, volgorde, koppeltekens
             en kommas.

           2-methylpropan-1-ol/ 2-methyl-1-propanol/ methylpropan-1-ol/
           methyl-1-propanol 
           2-metielpropan-1-ol/ 2-metiel-1-propanol / metielpropan-1-ol/
           metiel-1-propanol                                                                            (2)

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Physical Sciences P2/Fisiese Wetenskappe V2     4                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 2.6
 2.6.1     Esterification/Condensation/Verestering/Esterifikasie/Kondensasie                            (1)

 2.6.2                                                 Marking criteria/Nasienkriteria:
                 H   H    H   O             H   H       • Functional group correct. 
                                                          Funksionele groep korrek.
            H    C   C    C   C    O        C C     H   • Whole structure correct. 
                                                          Hele struktuur korrek.
                H    H H                    H   H 
          IF/INDIEN
          • More than one functional group/wrong functional group:
              Meer as een funksionele groep/foutiewe funksionele groep:             0�
                                                                                      2
          • If condensed structural formulae used/Indien gekondenseerde struktuurformules
              gebruik:                                                  Max./Maks. 1�2
                                                                                                        (2)

 2.7
 2.7.1     C2H4O                                                                                       (1)

 2.7.2          H    H    H    H                        Marking criteria/Nasienkriteria:
                                                       • Correct functional group. 
           H    C    C    C    C       H                 Korrekte funksionele groep.
                                                        • Whole structure correct. 
                H    H                                    Hele struktuur korrek.
           IF/INDIEN
           • More than one functional group/wrong functional group:
               Meer as een funksionele groep/foutiewe funksionele groep:             0�
                                                                                       2
           • If condensed structural formulae used/Indien gekondenseerde struktuurformules
               gebruik:                                                  Max./Maks. 1�2                 (2)
                                                                                                        [19]

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Physical Sciences P2/Fisiese Wetenskappe V2     5                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 3/VRAAG 3

 3.1.1     (A series of organic) compounds that can be described by the same general
           formula.  (2 or 0)
           OR
           (A series of organic) compounds in which one member differs from the next by
           a CH2 group.

           (’n Reeks organiese) verbindings wat deur dieselfde algemene formule beskryf
           kan word.  (2 of 0)
           OF
           (’n Reeks organiese) verbindings waarin die een lid van die volgende verskil
           met 'n CH2-groep                                                                            (2)

 3.1.2
 (a)       Formyl (group)/Formiel(groep)                                                              (1)

 (b)       Marking criteria:                             Nasienkriteria:
           • Correct chain length, i.e. Meth.           • Korrekte kettinglengte d.i. Met. 
           • Everything else correct.                   • Alles verder reg 
           Methanal/Metanaal                                                                         (2)

 3.1.3
 (a)       Homologous series/Functional group/Type of intermolecular forces/Straight
           chain/Atmospheric pressure 
           Homoloë reeks/Funksionele groep/Tipe intermolekulêre kragte/ Reguitketting/
           Atmosferiese druk                                                                           (1)

 (b)       The boiling points of the carboxylic acids increase with an increase in the chain
           length/the number of carbon atoms/surface area/molecular mass./
           OR
           The boiling points of the carboxylic acids decrease with a decrease in the chain
           length/number of carbon atoms/surface area/molecular mass. 
           Die kookpunte van die karboksielsure neem toe met 'n toename in die
           kettinglengte/aantal koolstofatome/reaksieoppervlak/molekulêre massa./
           OF
           Die kookpunte van die karboksielsure neem af met 'n afname in die
           kettinglengte/aantal koolstofatome/reaksieoppervlak/molekulêre massa.                        (1)

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Physical Sciences P2/Fisiese Wetenskappe V2     6                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 (c)       Marking criteria:
           For increasing or decreasing number of C atoms
           • Compare the strength of intermolecular forces. 
           • Compare the energy required to overcome intermolecular forces. 
           Nasienkriteria:
           Vir toename of afname in aantal C-atome
           • Vergelyk die sterkte van intermolekulêre kragte. 
           • Vergelyk die energie benodig om intermolekulêre kragte te oorkom. 

           As the number of C atoms/chain length/surface area/contact area/molecular
           mass increases
           • The strength of intermolecular/London/dispersion forces increases. 
           • More energy is needed to overcome intermolecular forces/London/
             dispersion forces. 
           OR
           As the number of C atoms/chain length/surface area/contact area/molecular
           mass decreases
           • The strength of intermolecular/London/dispersion forces decreases. 
           • Less energy is needed to overcome intermolecular forces/London/
             dispersion forces. 
           Met toename in aantal C-atome/kettinglengte/reaksieoppervlak/kontakarea/
           molekulêre massa.
           • Die sterkte van die die intermolekulêre kragte/Londonkragte/
              dispersiekragte neem toe.
           • Meer energie word benodig om die intermolekulêre kragte/Londonkragte/
              dispersiekragte te oorkom/breek.
           OF
           Met afname in aantal C-atome/kettinglengte/reaksieoppervlak/kontakarea/
           molekulêre massa.
           • Die sterkte van die die intermolekulêre kragte/Londonkragte/
              dispersiekragte neem af.
           • Minder energie word benodig om die intermolekulêre kragte/
              Londonkragte/dispersiekragte te oorkom/breek                                             (2)

 3.1.4     75 °C                                                                                      (1)

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Physical Sciences P2/Fisiese Wetenskappe V2     7                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 3.2       Marking criteria:
           • Higher than 
           • State that carboxylic acids have more than one (two) site for hydrogen bonding
              and alcohols have one site for hydrogen bonding. 
           • Comparing the strength of IMFs. 
           • Comparing the number of molecules in a vapour phase at a given temperature/
              energy needed to overcome IMFs. 
           Nasienkriteria:
           •  Hoër as 
           •  Stel dat karboksielsure het meer as een (twee) plekke vir waterstofbindings en dat
              alkohole een plek het vir waterstofbinding. 
           • Vergelyk die sterkte van die IMK's/energie benodig om IMK's te oorkom. 
           • Vergelyk die hoeveelheid molekules in die dampfase by 'n gegewe temperatuur
              /energie nodig om die IMK te oorkom. 

           • Higher than 
           • Compound B/CH3CH2CH2COOH/Carboxylic acid/Butanoic acid has (in
             addition to London forces and dipole-dipole forces), more than one site (two)
             for    hydrogen     bonding    between      molecules     and    compound
             A/CH3CH2CH2CH2CH2OH/Alcohol/Pentan-1-ol has (in addition to London
             forces and dipole-dipole forces) one site for hydrogen bonding between
             molecules. 
           • Intermolecular forces in compound B/CH3CH2CH2COOH/Carboxylic
             acids/Butanoic acid are stronger. 
           • More energy needed to overcome/break intermolecular forces in compound
             B/ CH3CH2CH2COOH/Carboxylic acid/Butanoic acid.
           OR
           • At a given temperature there will be fewer molecules of compound
             B/CH3CH2CH2COOH/Carboxylic acids/Butanoic acid in the vapour
             phase. 

           • Higher than 
           • Compound A/CH3CH2CH2CH2CH2OH/Alcohol/Pentan-1-ol has (in addition
             to London forces and dipole-dipole forces) one site for hydrogen bonding
             between molecules and compound B/CH3CH2CH2COOH/
             Carboxylic acid/Butanoic acid has, (in addition to London forces and dipole-
             dipole forces), more than one site (two) for hydrogen bonding between
             molecules. 
           • Intermolecular forces in compound A/CH3CH2CH2CH2CH2OH/Alcohol/
             Pentan-1-ol are weaker. 
           • Less energy needed to overcome/break intermolecular forces in compound
             A/CH3CH2CH2CH2CH2OH/Pentan-1-ol/Alcohol.
           OR
           • At a given temperature there will be more molecules of compound
             A/CH3CH2CH2CH2CH2OH/Alcohol/ Pentan-1-ol in the vapour phase. 

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Physical Sciences P2/Fisiese Wetenskappe V2     8                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

          •   Hoër as
          •   Verbinding B/CH3CH2CH2COOH/Karboksielsure/Butanoësuur         het,   (in
              toevoeging tot Londonkragte en dipool-dipoolkragte), meer as een posisie
              (twee) vir waterstofbinding tussen molekule en verbinding A/
              CH3CH2CH2CH2CH2OH/Alkohol/Pentan-1-ol het, (in toevoeging tot
              Londonkragte en dipool-dipoolkragte), een posisie vir waterstofbinding
              tussen molekule.
          •   Intermolekulêre kragte in verbinding B/CH3CH2CH2COOH/Karboksielsure/
              Butanoësuur is sterker.
          •   Meer energie word benodig om intermolekulêre kragte in verbinding
              B/CH3CH2CH2COOH/Karboksielsure/Butanoësuur te oorkom/breek
          OF
          • By 'n gegewe temperatuur sal daar minder molekules van verbinding
             B/CH3CH2CH2COOH/Karboksielsure/Butanoësuur in die dampfase wees.

          •   Hoër as
          •   Verbinding     A/CH3CH2CH2CH2CH2OH/Alkohol/Pentan-1-ol          het,   (in
              toevoeging tot Londonkragte en dipool-dipoolkragte), een posisie vir
              waterstofbinding tussen molekule en verbinding B/CH3CH2CH2COOH/
              Karboksielsure/Butanoësuur het, (in toevoeging tot Londonkragte en dipool-
              dipoolkragte), meer as een posisie (twee) vir waterstofbinding tussen
              molekule.
          •   Intermolekulêre kragte in verbinding A/ CH3CH2CH2CH2CH2OH/Alkohol/
              Pentan-1-ol is swakker.
          •   Minder energie word benodig om intermolekulêre kragte in A/
              CH3CH2CH2CH2CH2OH/Alkohol/Pentan-1-ol te oorkom/breek.
          OF
          • By 'n gegewe temperatuur sal daar meer molekules van verbinding A/
             CH3CH2CH2CH2CH2OH/Alkohol/Pentan-1-ol in die dampfase wees.                               (4)
                                                                                                       [14]

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Physical Sciences P2/Fisiese Wetenskappe V2     9                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 4/VRAAG 4

 4.1
 4.1.1     Hydrogenation/Hidrogenering/Hidrogenasie                                                   (1)

 4.1.2    Dehydration/Dehidrasie/Dehidratering                                                        (1)

 4.2       Marking criteria:                            Nasienkriteria:
           • Correct chain length, i.e. But.           • Korrekte kettinglengte d.i. But.
           • Everything else correct: IUPAC name • Alles verder reg: IUPAC-naam
              completely correct including numbering.     heeltemal korrek insluitende
                                                           nommering. 

           Butan-1-ol/1-butanol                                                                      (2)

 4.3
 4.3.1    Marking criteria/Nasienkriteria:
          • Whole condensed structural formula of alkene correct. 
             Hele gekondenseerde struktuurformule van die alkeen korrek.
          • H2O. 
          • Hydroxyl group/OH. 
             Hidroksielgroep/OH.
          • Whole condensed structural formula of alcohol correct (OH on second C-atom). 
             Hele gekondenseerde struktuurformule van alkohol korrek (OH op tweede C-
             atoom)
          IF/INDIEN
          • Any additional reactants or products /Enige addisionele reaktanse of produkte:
             Deduct 1 mark/Trek 1 punt af.
          • Structural formulae used/Struktuurformule gebruik.         Max./Maks. 3�4
          • Molecular formulae used/Molekulêre formule gebruik.       Max./Maks. 1�4
          • Only reactants without arrow/Slegs reaktanse sonder pyl Max/Maks. 2�4
          Marking rule 6.3.10/Nasienreël 6.3.10
                                        
          CH2CHCH2CH3  + H2O  → CH3CHOHCH2CH3 
          OR/OF                       OH 

          CH2=CHCH2CH3  + H2O  → CH3CHCH2CH3                                                        (4)

 4.3.2    Sulphuric acid/H2SO4/Phosphoric acid/H3PO4/Swawelsuur/Fosforsuur                            (1)

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Physical Sciences P2/Fisiese Wetenskappe V2    10                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 4.4       Marking criteria/Nasienkriteria:
           • X2 = Br2/Cℓ2. 
           • Whole structural formula of haloalkane correct. 
             Hele struktuurformule van haloalkaan korrek.
           • H2O/NaOH/KOH/LiOH. 
           • Whole structural formula of alcohol correct. 
             Hele struktuurformule van alkohol korrek.
           • HX/NaX/KX/LiX where/waar X = Br/Cℓ 

           IF/INDIEN
           • Any additional reactants or products /Enige addisionele reaktanse of produkte:
              Max./Maks. 4�5
           • Condensed structural formulae used/Gekondenseerde struktuurformule gebruik:
              deduct 1 mark/trek 1 punt af.
           • If inorganic product does not correspond with inorganic reactant: no mark for
              inorganic product./Indien anorganiese produk nie met die anorganiese reaktans
              ooreenstem nie, geen punt vir anorganiese produk.
           • Molecular formulae used:/Molekulêre formule gebruik: Max./Maks. 3�5
           • Marking rule 6.3.10/Nasienreël 6.3.10

                H     H      H        H                          H        H       H       H
                                                                                              
           H    C     C      C      C      H + X2        H      C        C       C       C       H + HX

                H     H      H      H                            H        H       H       X

                H     H     H     H                              H      H     H       H
                                                                                          
           H    C     C     C     C       H + H2O       H       C      C     C       C    H + HX 
                                            OR/OF              H        H     H       O            OR/OF
                H     H     H     X
                                            NaOH/                                                  NaX/
                                            KOH/                                      H            KX/
                                            LiOH                                                   LiX     (5)

 4.5       2C4H10  + 13O2 → 8CO2 + 10H2O                    Bal. 

           Ignore phases./Ignoreer fases.
           Marking criteria/Nasienkriteria:
           •    C4H10             O2, CO2 and/en H2O          Balancing/Balansering 
           •    Ignore double arrows./Ignoreer dubbelpyle.
           •    Marking rule 6.3.10/Nasienreël 6.3.10.
           IF/INDIEN:
           • Structural formulae C4H10 used:/Struktuurformule C4H10 gebruik: Max./Maks. 2�3
           • Balancing mark only if everything else is correct/
              Balanseringspunt slegs indien alles korrek.                                                   (3)
                                                                                                           [17]

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Physical Sciences P2/Fisiese Wetenskappe V2    11                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 5/VRAAG 5

 5.1       NOTE/NOTA
           Give the mark for per unit time only if in context of reaction rate.
           Gee die punt vir per eenheidtyd slegs indien in konteks van reaksietempo.

           ANY ONE:
           • Change in concentration  of products/reactants per (unit) time. 
           •   Change in amount/number of moles/volume/mass of products or reactants
               per (unit) time.
           •   Amount/number of moles/volume/mass of products formed/reactants used
               per (unit) time.
           •   Rate of change in concentration/amount/number of moles/volume/
               mass.  (2 or 0)

           ENIGE EEN:
           • Verandering in konsentrasie  van produkte/reaktanse per (eenheid)tyd.
           • Verandering in hoeveelheid/getal mol/volume/massa van produkte of
             reaktanse per (eenheid)tyd.
           • Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse
             gebruik per (eenheid)tyd.
           • Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/ volume/
             massa.  (2 of 0)                                                                        (2)

 5.2       ANY ONE:
           Temperature /
           (Initial) amount/Mass of magnesium carbonate/Surface area
           ENIGE EEN:
           Temperatuur /
           (Aanvanklike) hoeveelheid/Massa van magnesiumkarbonaat/
           Reaksieoppervlak                                                                            (1)

 5.3       CO2/gas escapes from the reaction flask. 
           CO2 /gas ontsnap uit die reaksiefles.                                                      (1)

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Physical Sciences P2/Fisiese Wetenskappe V2    12                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 5.4       Marking criteria:                              m(CO2) = 144,5 – 143,87  (a)
          (a) Mass subtraction                                 = 0,63 g
                            m
          (b)Formula: n = or V = nVm                               m
                            M
          (c) Substitute M = 44 g·mol-1 in               n(CO2) =       (b)
                          m                                         M
               n(CO2) =        with m(CO2) from (a)                0,63
                          M                                       =       (c)
          (d)Substitute 24,5 dm3 in V = nVm with                     44
              n(CO2)                                             = 1,43 x 10-2 mol
          (e) Substitute VCO2 and 120 in rate formula   V(CO2) = nVm
          (f) Final correct answer:                             = (1,43 x 10-2)(24,5)  (d)
              2,92 x 10-3 (dm3·s-1) 
                                                                = 0,35 dm3
          Range: 2,08 x 10-3 to 3 x 10-3
           Nasienkriteria:                                Ave rate/   ΔV(CO2 )
          (a) Aftrek van massas.                         gem tempo =
                             m
          (b)Formula: n = or V = nVm                                    Δt
                             M
          (c) Vervang M = 44 g·mol-1 in
                                                                      0,35 - (0)
                          m
                                                                        =                (e)
                                                                            120 - (0)
               n(CO2) =       met m(CO2) van (a)
                          M                                                              (f)
          (d)Vervang 24,5 dm3 in V = nVm met                            = 2,92 x 10-3 (dm3·s-1)
              n(CO2)
          (e) Vervang VCO2 en 120 in tempoformule
          (f) Finale korrekte antwoord:
              2,92 x 10-3 (dm3·s-1) 
           Gebied: 2,08 x 10-3 tot 3 x 10-3                                                             (6)
 5.5       Marking criteria:
              • A
              • Comparison of the curves of the graph 
              • Comparison of concentration of HCℓ (from table) 
              • Explanation of collision theory for LOWER concentration 
           Nasienkriteria:
              • A
              • Vergelyk die kurwes van grafiek 
              • Vergelyk die konsentrasie van HCℓ (vanaf tabel) 
              • Verduidelik botsingsteorie vir LAER konsentrasie 
           A
          •     Gradient is least steep/lowest reaction rate/least amount of gas produced
                in 120 s. 
          •     Lowest concentration of HCℓ(aq). 
          •     Least/Less particles per unit volume. 
          •     Least/Less effective collisions per unit time/second.  OR
                Lowest/Lower frequency of effective collisions.
           •    Gradient is die laagste/laagste reaksietempo/minste hoeveelheid gas
                geproduseer in 120 s. 
           •    Laagste konsentrasie van HCℓ(aq). 
           •    Minste/Minder deeltjies per eenheidsvolume. 
           •    Minste/Minder effektiewe botsings per eenheidstyd/sekonde.  OF
                Laagste/Laer frekwensie van effektiewe botsings.                                       (5)
 5.6       The same/ Dieselfde 
           The same amount MgCO3 is used in each experiment. 
           Dieselfde hoeveelheid MgCO3 is gebruik in elke eksperiment.                                 (2)
                                                                                                       [17]

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Physical Sciences P2/Fisiese Wetenskappe V2    13                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 6/VRAAG 6
 6.1
 6.1.1     Remains the same/Bly dieselfde                                                                  (1)
 6.1.2     Decreases/Neem af                                                                               (1)
 6.1.3     Remains the same/Bly dieselfde                                                                  (1)
 6.2       • Decrease in pressure favours the reaction that produces a greater number
             of moles/amount of gas. 
             'n Verlaging in druk bevoordeel die reaksie wat 'n groter aantal
             mol/hoeveelheid gas produseer.
           • Forward reaction is favoured. / [CO] increases AND [CO2] decreases
             Voorwaartse reaksie word bevoordeel./ [CO] neem toe EN [CO2] neem af                           (2)
 6.3       Marking criteria:                              Nasienkriteria:
                                      m                                            m
           (a) Substitute 44 in n =                      (a) Vervang 44 in n =        
                                      M                                            M
           (b) Change in mass of carbon:                  (b) Verandering in massa:
               m(Ci) - m(Cf)/n(Ci) - n(Cf)                   m(Ci) - m(Cf)/n(Ci) - n(Cf) 
                                      m                                             m
           (c) Substitute 12 in n =                      (c) Vervang 12 in n =            
                                      M                                             M
           (d) Use mole ratio 1:1                        (d) Gebruik molverhouding 1:1 
           (e) n(CO2)eq = n(CO2)initial - n(CO2)used OR   (e) n(CO2)ewe = n(CO2)begin - n(CO2)gebruik OF
                m(CO2)eq = m(CO2)initial - m(CO2)used        m(CO2)ewe= m(CO2)begin - m(CO2)gebruik 
           (f) Final answer: 6,16 g                      (f) Finale anwtoord: 6,16 g 
                RANGE: 6 to 6,16 g                            GEBIED: 6 tot 6,16 g
            NOTE:                                         NOTA:
            If (b) ∆m(C) or ∆n(C) is not calculated        Indien (b) ∆m(C) of ∆n(C) nie bereken
            max 2�6                                        maks 2�6
            OPTION 1/OPSIE 1:                             OPTION 2/OPSIE 2:
             Δm(C) = 14 - 4,44  (b)                   Δm(C) = 14 - 4,44  (b)
                    = 9,56 g                                 = 9,56 g
                               m
             n(CO2)initially =                                         m
                               M                            n(C)used =
                               41,2                                    M
                             =                                          9,56
                                44  (a)                    n(C) used =
                             = 0,94 mol (0,936)                          12  (c)
                               m                                      = 0,80 mol (0,797)
                 n(C)used =
                               M
                               9,56                       n(CO2)used = n(C)
                 n(C)used =
                                12  (c)                              = 0,80 mol (0,797)  (d)
                             = 0,80 mol (0,797)
               n(CO2)used = n(C)                                        m
                                                            n(CO  2) =
                              = 0,80 mol (0,797)  (d)                  M
                                                                        m
           n(CO2)eq = n(CO2)initially - n(CO2)used             0,80 =
                                                                        44  (a)
                             = 0,94 – 0,80  (e)            m(CO2) = 35,05 g
                             = 0,14 mol
                                m                      m(CO2)eq = m(CO2)initially - m(CO2)used
                  n(CO2) =
                                M                                     = 41,2 – 35,05  (e)
                               m
                    0,14 =                                         X  = 6,15 (g)  (f)
                               44
              X = m(CO2) = 6,16 (g)  (f)

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Physical Sciences P2/Fisiese Wetenskappe V2    14                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

           OPTION 3/OPSIE 3:

                                  m
              n(CO2)initially =                                         9,56
                              M                           n(C)used =
                               41,2                                      12  (c)
                             =                                         = 0,80 mol (0,797)
                                44  (a)
                             = 0,94 mol (0,936)

                                                                C                CO2
                  Ratio/Verhouding                              1                 1
                  Initial quantity (mol)
                                                         1,17              0,936
                  Aanvangshoeveelheid (mol)
                  Change (mol)
                                                         0,8               0,8         (d)
                  Verandering (mol)
                  Quantity at equilibrium (mol)/
                                                         0,37  (b)        0,14        (e)
                  Hoeveelheid by ewewig (mol)

           n(CO2) = 0,139 mol
           m(CO2) = 0,139 (44)
               X = 6,16 (g)  (f)
                                                                                                          (6)

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Physical Sciences P2/Fisiese Wetenskappe V2    15                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 6.4       POSITIVE MARKING FROM QUESTION 6.3:
           POSITIEWE NASIEN VANAF VRAAG 6.3:
          Marking criteria
          (a) Use of ratio n(CO2) : n(CO) = 1: 2. 
          (b) Divide by 3 dm3 
          (c) Correct Kc expression (formulae in square brackets). 
          (d) Substitute of concentration into KC expression. 
          (e) Final answer: 5,98 
              RANGE: 5,98 – 7,29
          Nasienkriteria:
          (a) Gebruik verhouding n(CO2) : n(CO) = 1: 2. 
          (b) Deel deur 3 dm3 
          (c) Korrekte Kc uitdrukking (formules in vierkantige hakies). 
          (d) Vervang konsentrasies in korrekte Kc uitdrukking. 
          (e) Finale antwoord: 5,98 
              GEBIED: 5,98 – 7,29

           NOTE/NOTA:
           Mark calculations of this question that may be done in QUESTION 6.3.
           Merk berekeninge van hierdie vraag wat in VRAAG 6.3 gedoen is.
           CALCULATIONS USING NUMBER OF MOLES
           BEREKENINGE WAT AANTAL MOL GEBRUIK
           OPTION 1/OPSIE 1:

                              m
           n(CO2) initial =
                              M
                              41,2
                        =
                              44
                           = 0,936 mol

                                                               CO2             CO
                   Ratio/Verhouding                              1              2
                   Initial quantity (mol)
                                                               0,936            0
                   Aanvangshoeveelheid (mol)
                   Change (mol)                                                           (a)
                                                                0,8            1,6
                   Verandering (mol)
                   Quantity at equilibrium (mol)/
                                                               0,14            1,6
                   Hoeveelheid by ewewig (mol)
                   Equilibrium concentration (mol∙dm-3)                                  Divide by/deel
                                                              0,047           0,53       deur 3  (b)
                   Ewewigskonsentrasie (mol∙dm-3)
                       2
                  [CO] (c)
           Kc =
                  [CO2 ]                     Wrong Kc expression
                                             Verkeerde Kc-uitdrukking: Max./Maks. 2�5
                  (0,53)2
              =               (d            No Kc expression/Geen Kc- uitdrukking: 4�5
                  0,047
              = 5,98  (e)

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Physical Sciences P2/Fisiese Wetenskappe V2    16                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

           CALCULATIONS USING CONCENTRATION
           BEREKENINGE WAT KONSENTRASIE GEBRUIK
           OPTION 2/OPSIE 2:
                     m                       n
           c(CO2) =                                     c=
                         MV             Divide by             V
                          41,2          3  (b)               0,8
                     =                                    =
                        (44)(3)                              3
                     = 0,31 mol∙dm-3                      = 0,27 mol∙dm-3 (0,267)

                                                                CO2              CO
            Ratio/Verhouding                                     1                2
            Initial concentration (mol∙dm-3)
                                                               0,31                0
            Aanvangskonsentrasie (mol∙dm-3)
            Change in concentration (mol∙dm-3)
                                                                0,27             0,54        (a)
            Verandering in konsentrasie (mol∙dm-3)
            Equilibrium concentration (mol∙dm-3)
                                                                0,04             0,54
            Ewewigskonsentrasie (mol∙dm-3)

                                               Wrong Kc expression
                 [CO]2 (c)
           Kc =                                Verkeerde Kc-uitdrukking: Max./Maks. 2�5
               [CO2 ]
                                               No Kc expression/Geen Kc- uitdrukking: 4�5
                 (0,54)2 (d)
             =
                 0,04
             = 7,29  (e)

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Physical Sciences P2/Fisiese Wetenskappe V2    17                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

           OPTION 3/OPSIE 3:

                                 m
           n(CO2)initial =
                                 M
                                  41,2
                             =
                         44
                     = 0,936 mol
           ∆n(CO2) = 0,8 mol

           n(CO2)eqm = n(CO2)initial - ∆n(CO2)
                       = 0,936 - 0,8
                       = 0,136 mol
                                     (a)
           n(CO)formed = 2∆n(CO2)used = 1,6 mol

           n(CO)eqm = ∆n(CO)formed = 1,6 mol

                             0,136
           [CO2]eqm =                = 4,53 x 10-2 mol∙dm-3
                        3                                     (b)
                     1,6
           [CO]eqm =     = 0,53 mol∙dm-3
                      3
                         2   (c)
                  [CO]
           Kc =                                        Wrong Kc expression
                  [CO2 ]                               Verkeerde Kc-uitdrukking: Max./Maks. 2�5
                    (0,53)2                            No Kc expression/Geen Kc- uitdrukking: 4�5
              =                      (d
                  4,53 x 10-2

              = 6,2       (e)                                                                             (5)

 6.5       Y                                                                                             (2)

 6.6       Remains the same/Bly dieselfde                                                                 (1)
                                                                                                           [19]

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Physical Sciences P2/Fisiese Wetenskappe V2    18                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 7/VRAAG 7

 7.1      An acid produces hydrogen ions /H+/hydronium ions/ H3O+ in aqueous
          solution/water.  (2 or 0)
          'n Suur is 'n stof wat waterstofione/H+/hidroniumione/H3O+ vorm in waterige
          oplossing/water. (2 of 0)                                                                    (2)

 7.2
 7.2.1    (COOH)2                                                                                     (1)

 7.2.2    NaCℓ                                                                                        (1)

 7.2.3    HCO3̄ 
          OR/OF NH3                                                                                    (1)

 7.2.4    NaOH 
          OR/OF Mg(OH)2                                                                                (2)

 7.3      Marking criteria:                           Nasienkriteria:
          (a) Calculate n(HxY)                      (a) Bereken n(HxY) 
          (b) Calculate n(NaOH)                     (b) Bereken n(NaOH) 
          (c) Final answer: x = 2                   (c) Finale antwoord: x = 2 
          (d) Reactants  Products  Balancing      (d) Reaktanse Produkte Balansering
          NOTE: Ignore ⇌ and phases                   NOTA: Ignoreer ⇌ en fases
                  Marking rule 6.3.10                      Nasienreël 6.3.10
          OPTION 1/OPSIE 1:                          OPTION 2/OPSIE 2:
             n = cV                                             ca Va       na
          nacid = (0,11)(0,02364)  (a)                                  =
                                                                  cb Vb     nb
                = 2,6 x 10-3                          (a)
                                                          (23,64)(0,11)      1
                                                                          =
          nbase = (0,26)(0,02)  (b)                   (b)(20)(0,26)        nb
                = 5,2 x 10-3 (0,0052)                                  nb = 2
                                                                     ∴ x = 2  (c)
            n(HxY)            na
                          =
          n(NaOH)             nb
                     -3                                        HxY : NaOH
           2,6 x 10           1                           2,6 x 10-3 : 5,2 x 10-3
                    =
          5,2 x 10-3 nb                                           1:2
                 nb = 2
                ∴ x = 2  (c)

          H2Y(aq) + 2NaOH(aq) → Na2Y (aq) + 2H2O(ℓ)               Bal  (d)                          (6)

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Physical Sciences P2/Fisiese Wetenskappe V2    19                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 7.4       Marking criteria:
          (a) Any formula: pH = -log[H3O+]/pH = -log[H+]/[H3O+] = 10-pH 
          (b) Substitute 1,61 in pH = -log[H3O+] 
                                                      n
          (c) Calculate n(HCℓ)unused using c =            
                                                      V
                                                  n
          (d) Calculate n(HCℓ)initial using c =       
                                                  V
          (e) Calculate n(HCℓ)used = n(HCℓ)initial - n(HCℓ)unused 
          (f) Using ratio 1:2 with USED HCℓ from of (e) to calculate n(CaCO3) 
                                                                      m
          (g) Substitute 100 AND n(CaCO3) from (f) in n =                 
                                                                      M
          (h) Mass of impurity = msample – m(CaCO3) 
          (i) Final answer: 0,25 g  (Range: 0,2 g to 0,3 g)
           Nasienkriteria:
          (a) Enige formule: pH = - log[H3O+]/pH = - log[H+] /[H3O+] = 10-pH 
          (b) Vervang 1,61 in pH = -log[H3O+] 
                                                      n
          (c) Bereken n(HCℓ)ongebruik using c =           
                                                      V
                                              n
          (d) Bereken n(HCℓ)begin using c =       
                                              V
          (e) Bereken n(HCℓ)gebruik = n(HCℓ)begin - n(HCℓ)ongebruik 
          (f) Gebruik ratio 1:2 van HCℓ GEBRUIK van (e) om n(CaCO3) te bereken 
                                                              m
          (g) Vervang 100 EN n(CaCO3) van (f) in n =              
                                                              M
          (h) Massa of onsuiwerheid = mmonster – m(CaCO3) 
          (i) Finale antwoord: 0,25 g  (Gebied: 0,2 g tot 0,3 g)

              pH    = -log[H3O+]  (a)
       (b)  1,61   = -log[H3O+]
            [H3O+] = 10-1,61
                   = 2,45 x 10-2 mol∙dm-3 (0,0245)
            n(HCℓ)unused = n(H3O+) = cV
                                   = (2,45 x 10-2)(0,2)  (c)
                                   = 4,9 x 10-3 mol (0,0049)
            n(HCℓ)initial = cV
                          = (0,15)(0,2)  (d)
                          = 3 x 10-2 mol (0,03)

            n(HCℓ)used = 3 x 10-2 – 4,9 x 10-3  (e)
                       = 2,51 x 10-2 mol (0,0251)
            Reaction ratio nCaCO3: nHCℓ = 1:2
                             (f)
            n(CaCO3) = ½(2,51 x 10-2) = 1,25 x 10-2 mol
                          m
            n(CaCO3) =
                          M
                           m
            1,25 x 10-2 =
                          100  (g)
            m(CaCO3) = 1,25 g
            m of impurity in the sample = 1,5 – 1,25  (h)
                                        = 0,25 g  (i)                                                              (9)
                                                                                                                    [22]

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Physical Sciences P2/Fisiese Wetenskappe V2    20                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 8/VRAAG 8

 8.1      H+/H3O+ ions/hydrogen ions/hydronium ions/oxonium ions 
          Waterstofione/hidroniumione/oksoniumione                                                     (1)

 8.2      0,77 V                                                                                      (1)

 8.3      A                                                                                           (1)
                                                    -
 8.4      H2 is a stronger reducing agent than Fe2+/Fe(II) ions  and will reduce
          Fe3+/Fe(III) ions  (to Fe2+/Fe(II) ions).
                                                -
          H2 is 'n sterker reduseermiddel as Fe2+/Fe(II)-ione en sal Fe3+/Fe(III)-ione
          reduseer (na Fe2+/Fe(II)-ione).
          OR/OF
                                                   -
          Fe2+-ion is a weaker reducing agent than H2 and therefore Fe3+/Fe(III) ions
          (to Fe2+/Fe(II) ions) will be reduced. 
                                                        -
          Fe2+-ioon is 'n swakker reduseermiddel as H2 en sal Fe3+/Fe(III)-ione reduseer
          (na Fe2+/Fe(II)-ione).                                                                       (3)

 8.5
 8.5.1    Pt/Platinum                                                                                 (1)

 8.5.2    H2  2H+ + 2e- 

          NOTE/NOTA:
          • 2H+ + 2e- ← H2 ( 2 )
                               2
              H2 ⇌   2H+ + 2e-
                             1
                           ( )
                              2
              2H + 2e ⇌ H2 ( )
                +    -      0
                              2
              2H + 2e  H2 ( )
                +    -      0
                               2
          •   Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.
          •   If charge (+) omitted on H+/Indien lading (+) weggelaat op H+:
              Example/Voorbeeld: H2  2H + 2e- Max/Maks: 1
                                                                    2                                  (2)

 8.5.3                                        
          Pt(s) | H2(g) | H+(aq) || Fe3+(aq),Fe2+(aq) | Pt(s)
          OR/OF
          Pt(s) | H2(g) | H+(1 mol∙dm-3) || Fe3+(1 mol∙dm-3),Fe2+(1 mol∙dm-3)       | Pt(s)
          ACCEPT/AANVAAR:
          Pt | H2 | H+ || Fe3+,Fe2+ | Pt                                                               (3)

 8.6      The reaction reaches equilibrium/no charges/electrons flow. 
          Die reaksie bereik ewewig/geen ladings/elektrone vloei.                                      (1)
                                                                                                       [13]

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Physical Sciences P2/Fisiese Wetenskappe V2    21                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 QUESTION 9/VRAAG 9

 9.1      ANY ONE:
          • The (chemical) process in which electrical energy is converted to
            chemical energy.  (2 or 0)
          • The use of electrical energy to produce a chemical change.
          • Decomposition of an ionic compound by means of electrical energy.
          • The process during which an electric current passes through a solution/ionic
            liquid/molten ionic compound.

          ENIGE EEN:
          • Die (chemiese) proses waarin elektriese energie omgeskakel word na
            chemiese energie.  (2 of 0)
          • Die gebruik van elektriese energie om 'n chemiese verandering teweeg te
            bring.
          • Ontbinding van 'n ioniese verbinding met behulp van elektriese energie.
          • Die proses waardeur 'n elektriese stroom deur 'n oplossing/ioniese
            vloeistof/gesmelte ioniese verbinding beweeg.                                              (2)

 9.2      2H2O(ℓ) + 2e-  H2(g) + 2OH¯(aq) 

          NOTE/NOTA:
           • H2(g) + 2OH¯(aq) ← 2H2O(ℓ) + 2e- ( 2 )
                                                   2
           • 2H2O(ℓ) + 2e ⇌ H2(g) + 2OH¯(aq) ( 1 )
                          -
                                                   2
          • H2(g) + 2OH¯(aq) ⇌ 2H2O(ℓ) + 2e (  -  0   )
                                                    2
          • 2H2O(ℓ) + 2e- ← H2(g) + 2OH¯(aq) ( 0 )
                                                   2
          • Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.
          • If charge (-) omitted on OH¯ /Indien lading (-) weggelaat op OH¯
              Example/Voorbeeld: 2H2O(ℓ) + 2e-  H2(g) + 2OH(aq)               Max./Maks: 1
                                                                                                2
          •   Ignore phases/Ignoreer fases                                                             (2)

 9.3      X to Y/X tot Y                                                                              (1)

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Physical Sciences P2/Fisiese Wetenskappe V2    22                      DBE/May/June/Mei/Junie 2025
                          SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne

 9.4      Marking criteria:                           Nasienkriteria:
          (a) Substitute 300 x 10-3 and 24 dm3 into   (a) Vervang 300 x 10-3 en 24 dm3 in
                     V                                         V
              n=                                         n=        
                   Vm                                          Vm
          (b) Using ratio 1:2 to calculate n(e-)     (b) Gebruik verhouding 1:2 om n(e-) te
          (c) Substitute 6,02 x 1023 mol-1 in             bereken 
                     N                                (c) Vervang 6,02 x 1023 mol-1 in
              n=           
                   NA                                          N
                                                          n=        
          (d) Final correct answer:                            NA
              1,505 x 1022 electrons       (d) Finale korrekte antwoord:
          Range: 1,505 x 10 to 2,41 x 10
                               22        22     1,505 x 1022 elektrone 
          electrons                         Gebied: 1,505 x 1022 tot 2,41 x 1022
                                                elektrone
          OPTION 1/OPSIE 1:                 OPTION 2/OPSIE 2:
                     V                                  V
          n (Cℓ2) =                         n (Cℓ2) =
                    Vm                                 Vm
                           300 × 10-3                               300 × 10-3
                   =                    (a)                   =                  (a)
                               24                                        24
                   = 0,0125 mol (0,01)                         = 0,0125 mol (0,01)

            n(e-) = 2n(Cℓ2)                                         N
                                                      n (Cℓ2) =
                  = 2(0,0125) (b)                                  NA
                  = 0,025 mol                                            N
                                                      0,0125 =
                                                                6,02 x 1023 (c)
                       N
          n (e-) =                                          N = 7,525 x 1021 (Cℓ2)
                     NA
                               N                      N(e-) = 2n(Cℓ2)
          0,025 =                   23 (c)
                   6,02 x 10                                 = 2(7,525 x 1021) (b)
               N = 1,505 x 1022 (electrons) (d)             = 1,505 x 1022 (electrons) (d)         (4)
                                                                                                     [9]
                                                                                 TOTAL/TOTAAL:       150

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