# Physical Sciences Grade 12 Paper 2 EC June 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the EC June 2018, 11 pages. Read online or get the free PDF download, question paper linked when available.

- Page: https://www.hlayiso.com/library/physical-sciences-p2-memo-afr-eng/baa7a877-1522-4ab3-bc9c-70156b538542
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: EC June
- Paper: 2
- Curriculum: CAPS
- Pages: 11

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Physical Sciences · Grade 12 · EC June · 2018. Memorandum, 11 pages. Read online or download the PDF.

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                          NATIONAL SENIOR
                            CERTIFICATE/
                          NASIONALE SENIOR
                            SERTIFIKAAT

                         GRADE/GRAAD 12

                          JUNE/JUNIE 2018

 PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2
       MARKING GUIDELINE/NASIENRIGLYN

MARKS/PUNTE:   150

                     This marking guideline consists of 10 pages./ Hierdie
                             nasienriglyn bestaan uit 10 bladsye.

                                      1

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QUESTION/VRAAG 1

1.1     D                                                                                 (2)

1.2     C                                                                                 (2)

1.3     B                                                                                 (2)

1.4     D                                                                                 (2)

1.5     B                                                                                 (2)

1.6     D                                                                                 (2)

1.7     A                                                                                 (2)

1.8     A                                                                                 (2)

1.9     B                                                                                 (2)

1.10    D                                                                                  (2)
                                                                                            [20]

QUESTION/VRAAG 2

2.1.1   Organic compound that consist of carbon and hydrogen atoms only. 
        Organiese verbindings wat slegs uit koolstof- en waterstofatome bestaan.
        (2 or/of 0)                                                                         (2)

2.1.2   Alkanes /Alkane                                                                    (1)

2.1.3   C2H5                                                                               (1)
2.1.4   2C4H10 + 13O2  → 8CO2             + 10H2O              Bal 
        Notes/Aantekeninge:
         • Reactants         Products        Balancing
             Reaktanse         Produkte        Balansering
         • Ignore double arrows and phases./ Ignoreer dubbelpyle en fases.
         • Marking rule 6.3.10/Nasienreël 6.3.10.
         • If condensed structural formulae used:/Indien gekondenseerde struktuurformules
            gebruik:                       Max./Maks. 2/3
                                                                                            (3)
2.1.5   EXOTHERMIC /EKSOTERMIES                                                            (1)
2.1.6   The chemical process in which longer chain hydrocarbon molecules are
        broken into shorter more useful molecules. 
        Die chemiese proses waarin langer ketting koolwaterstofmolekules afgebreek
        word in korter meer bruikbare molekules.                                            (2)

                                             2

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2.1.7          H    H                   Marking criteria/Nasienriglyne:
                                         • Whole structure correct/ Hele struktuur korrek: 2/2
                                         • Only functional group correct.
               C       C                   Slegs funksionele groep korrek. Max./Maks.. 1/2

               H       H                                                                          (2)

2.1.8    CATALYTIC/KATALITIES                                                                    (1)

2.1.9    UNSATURATED/ONVERSADIG

         Contains double bonds OR multiple bonds between C atoms.
         Bevat dubbelbindings OF meervoudige bindings tussen C-atome.                             (2)

2.1.10   2,3-dimethylbut-2-ene/2,3-dimethyl-2-buteen
         2,3-dimetielbut-2-een/2,3-dimetiel-2-buteen

         Marking Criteria/Nasienriglyne:
          • Correct stem i.e but-2-ene/2-butene.
            Korrekte stam bv.but-2-een/2-buteen. 
          • Substituent dimethyl correctly identified. 
            Substituent dimetiel korrek geïdentifiseer.
          • Substituents correctly numbered, hyphens and commas correctly used. 
            Substituente korrek genommer, koppeltekens en kommas korrek gebruik.
                                                                                                  (3)

2.2.1                                          H

                                    H          C       H

                           H   H    H                                   H
                                                                    
                   H       C   C    C          C       C        C       C    H      
                                                       C
                           H   H               H                        H

                               H    C      H       Marking criteria/Nasienriglyne:
                                                   • Functional group/Funksionele groep. 
                               H    C      H       • Methyl and ethyl substituents /
                                                      Metiel en etiel substituente 
                                    H              • Whole structure correct/
                                                      Hele struktuur korrek             3/3
                                                                                                  (3)

2.2.2    Pentan-2-one/2-pentanone
         Pentan-2-oon/2-pentanoon                                                                 (2)
                                                                                                 [23]

                                                   3

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QUESTION/VRAAG 3
3.1       A bond or an atom or a group of atoms that determine(s) the physical and
          chemical properties of a group of organic compounds. 
          ŉ Binding of ŉ atoom of ŉ groep atome wat die fisiese en chemiese
          eienskappe van ŉ groep organiese verbindings bepaal.         (2 or/of 0)   (2)
3.2.1     Aldehyde /Aldehied                                                        (1)

3.2.2     Carboxile group /Karboksiel-groep                                         (1)
3.3.1     185,4(°C)                                                                 (1)
  -
3.3.2     •  Compound B/carboxylic acid has hydrogen bonding (in addition to
             London forces/Dispersion forces/Induced dipole forces/dipole-dipole
             forces.).
             Verbinding B/karboksielsuur het waterstofbindings
             behalwe Londonkragte/Dispersiekragte/Geïnduseerde dipoolkragte
             en dipool-dipoolkragte)
           • Hydrogen bonds are stronger  than London forces/Dispersion
              forces/Induced dipole forces and dipole-dipole forces.
             Waterstofbindings is sterker as Londonkragte/Dispersiekragte/
             Geïnduseerde dipoolkragte en dipool-dipoolkragte.
          • More energy will be needed to overcome/break(intermolecular)
             forces. 
             Meer energie word benodig om (intermolekulȇre) kragte te oorkom/
             te breek.                                                               (3)
3.4.1     Organic molecules with the same molecular formula  but different
          structural formulae. 
          Organiese verbindings met dieselfde molekulȇre formule maar verskillende
          struktuurformules.                                                         (2)

3.4.2     CHAIN /KETTING                                                            (1)

3.4.3     SMALLER THAN /KLEINER AS
      -
          STRUCTURE/STRUKTUUR:
          Compound D are branched/more compact/more spherical/smaller contact
          area/smaller surface(over which intermolecular forces act.) 
          Verbinding D is meer vertak/meer kompak/meer series/kleiner kontak
          area/kleiner oppervlak(waaroor intermolekulȇre kragte werk.)
          INTERMOLECULAR FORCES/INTERMOLEKULȆRE KRAGTE
          Weaker/Less strength/Decrease in strength of Van der Waals forces/
          London forces/Dispersion forces. 
          Swakker/Afname in sterkte van Van der Waalskragte/Londonkragte/
          Dispersiekragte.

                                           4

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        ENERGY/ENERGIE:
        Less energy needed to overcome/break (intermolecular) forces. 
        Minder energie benodig om (intermolekulȇre) kragte te oorkom/breek.

                                           OR/OF
        STRUCTURE/STRUKTUUR:
        Compound C is a straight chain/less compact/less spherical/larger contact
        area/larger surface(over which intermolecular forces act.) 
        Verbinding C is ŉ reguitketting/minder kompak/minder sferies/groter
        kontakarea/groter oppervlak(waaroor intermolekulȇre kragte werk.)
        INTERMOLECULAR FORCES/INTERMOLEKULȆRE KRAGTE
        Stronger/More strength/Increase in strength of Van der Waals forces/
        London forces/Dispersion forces. 
        Sterker/Toename in sterkte van Van der Waalskragte/Londonkragte/
        Dispersiekragte.
        ENERGY/ENERGIE
        More energy needed to overcome/break (intermolecular) forces. 
        Meer energie word benodig om (intermolekulȇre) kragte te oorkom/breek.        (4)
                                                                                     [15]

QUESTION/VRAAG 4

4.1.1   Substitution /Substitusie                                                   (1)

4.1.2   Eliminasie /Dehydration
        Eliminasie/Dehidrasie/Dehidratering                                          (1)

4.2.1   Hydrogenation 
        Hidrogenasie/Hidrogenering                                                   (1)

4.2.2   Pt /Ni/Pd/Platinum/Nickel/Nikkel/Palladium                                  (1)
4.3          H   H H     H                            H   H   H    H

         H C     C   C   C   O H     + H-Br →     H   C   C   C    C    Br + H2O 

            H    H   H H                            H   H   H    H 
        Notes/Aantekeninge:
         • Ignore double arrows/Ignoreer dubbelpyle.
         • Accept/Aanvaar H2O
         • Any additional reactants and/ or products
            Enige addisionele reaktanse en/of produkte:       Max./Maks. 3/4
         • Accept any coefficients that are multiples:
            Aanvaar koëffisiente wat veelvoude is:
         • Incorrect balancing/Verkeerde balansering:         Max./Maks. 3/4
         • Molecular/Condensed formulae
           Molekulȇre/gekondenseerde formule:                Max./Maks. 2/4
           Accept/Aanvaar: -OH as condensed/-OH as gekondenseerd                      (4)

                                              5

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4.4.1   (Concentrated) sulphuric acid /hydrogen sulphate/H2SO4
        Gekonsentreerde swaelsuur/waterstofsulfaat/ H2SO4                                (1)

4.4.2            H      H        H    H
                                               

                 C       C       C    C   H

                 H               H    H

             Marking criteria/Nasienriglyne:
              • Whole structure correct/Hele struktuur korrek: 2/2
              • Only functional group correct
                Slegs funksionele groep korrek     Max./Maks. 1/2
                                                                                         (2)

4.5.1    •    Heat /mild temperature over waterbath.
              Verhit/matige temperatuur oor ’n waterbad.
         •    Add concentrated sulphuric acid/H2SO4 
              Voeg gekonsentreerde swawelsuur/waterstofsulfaat)/H2SO4 by.                (2)

4.5.2
                                                      Marking criteria/Nasienriglyne:
                             O                         Only functional group 
                                                       Slegs funksionele groep
                  H          C   O H                  Whole structure correct 
                                                     Hele struktuur korrek       2/2

                                                                                         (2)

4.5.3   Butyl  methanoate / butielmetanoaat                                             (2)
                                                                                         [17]

QUESTION/VRAAG 5

5.1.1   Use magnesium powder. 
        Gebruik magnesiumpoeier.                                                         (1)

5.1.2   Increase concentration (H2SO4) /Toename in konsentrasie (H2SO4)                 (1)

5.1.3   DECREASES /VERLAAG                                                              (1)

5.1.4   NO EFFECT /GEEN EFFEK                                                           (1)

                                                   6

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5.2.1     Surface area  (of Zn)/State of division(of Zn)
          Oppervlaksarea(van Zn) /Toestand van verdeeldheid(van Zn)                                (1)

5.2.2     Reaction stops /come to completion/no more hydrogen gas is produced
          since zinc is used up. 
          Reaksie stop/kom tot stilstand/geen waterstofgas word geproduseer want
          sink is opgebruik.                                                                       (2)

5.2.3     EQUAL TO /GELYK AAN
  -
          The same Volume of H2(g) was produced. 
          Dieselfde volume H2(g) is geproduseer.                                                   (2)

5.2.4     (a)   Average rate/Gemiddelde tempo = ΔV/Δt
                                              = (0,06 - 0) /(30 - 0) 
                                              = 2 x 10-3(mol.dm-3.s-1) or/of 0,002                (3)

          (b)   n = cV = 0,4 x 100/1000  = 0,04 mol                                             (3)

          (c)   Marking criteria/Nasienriglyne:
                 • Use 24,3 dm3.mol-1 substituted in the correct formula.
                    Gebruik 24,3 dm3.mol-1 vervang in die korrekte formule.
                 • Calculate n(HCl) reacted using the mol ratio 1 : 2. 
                     Bereken n(HCl)gereageer deur molverhouding 1 : 2 te gebruik.
                 • Calculate n(HCl) reacted 
                     Bereken n(HCl)gereageer
                 • Use 36,5 g.mol-1 substitute in correct formule. 
                     Gebruik 36,5 g.mol-1 vervang in die korrekte formule.
                 • Finale antwoord/Final answer. (1,28–1,31 g)

          POSITIVE MARKING from QUESTION 5.2.4 b
      +
          POSITIEWE NASIEN vanaf VRAAG 5.2.4 b

                n(H2)produced/berei = V/Vm= 0,06/24,3 = 2,47 x 10-3mol               (0,002)

                n( HCℓ)lreacted/gereageer = 2 x 2,47 x 10-3                    Ratio/Verhouding
                                          = 4,94 x 10 -3 mol                           (0,004)

                n(HCℓ )remaining/oorgebly = ninitial/begin - nproduced/berei
                                          = 0,04 – 4,94 x10-3
                                          = 0,03506 mol                                (0,036)

                m = nM = 0,03506 x 36,5= 1,28 g                    Range/Gebied (1,28–1,314 g)   (5)

5.2.5     The minimum energy required to start a chemical reaction. 
          Die minimum energie benodig om ŉ reaksie te begin.           (2 or/of 0)                 (2)

                                                       7

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5.2.6   Experiment/Eksperiment III                                                    (1)

5.2.7   • A catalyst  provides an alternative pathway of lower activation
          energy(EA). 
          ŉ Katalisator verskaf ŉ alternatiewe pad van laer aktiveringsenergie.
        • More particles will have sufficient/enough kinetic energy(Ek) to react. 
          /More particles with Ek ≥ EA.
          Meer deeltjies het voldoende(genoegsame) kinetiese energie(Ek) om te
          reageer./Meer deeltjies het Ek ≥ EA.
        • More effective collisions per unit time/second. 
          Meer effektiewe botsings per eenheidstyd/sekonde.
                                OR/OF
           Rate/frequency of effective collisions increases.
          Tempo/frekwensie van effektiewe botsings neem toe.                            (4)
                                                                                       [27]

QUESTION/VRAAG 6

6.1     Stage at which the rate of forward reaction equals the rate of reverse. 
        Die toestand/stadium in ŉ chemiese reaksie wanneer die tempo van die
        voorwaartse reaksie gelyk is aan die tempo van die terugwaartse reaksie.
                                          OR/OF
        The stage where the concentrations/quantities of reactants and products
        remain constant.
        Die toestand wanneer die konsentrasies/hoeveelhede van reaktanse en
        produkte konstant bly.                                           (2 or/of 0)   (2)

6.2     Closed system /Geslote sisteem
        Reversible reaction /Omkeerbare reaksie.                                      (2)

6.3.1   NO EFFECT /GEEN EFFEK                                                         (1)

6.3.2   INCREASES /TOENEEM                                                            (1)

6.4.1   REVERSE /TERUGWAARTSE                                                         (1)

6.4.2   Increase in pressure  /Decrease volume; Addition of a catalyst. 
        Verhoog druk/Afname in volume; Byvoeging van ŉ katalisator.                    (2)

6.5.1   LOW (yield) /LAE (opbrengs)
        Kc is low. /Kc is laag.                                                       (2)

                                           8

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6.5.2   Marking Criteria/Nasienriglyne:
        •  Divide by 34 to calculate n(H2S)equilibrium. 
           Verdeel deur 34 om n(H2S)ewewig te bereken.
        •  Use mole ratio H2:H2S/Gebruik mol verhouding H2:H2S            (1 : 1)
        •  Divide n(H2S) equilibrium by V./Verdeel n(H2S) ewewig deur V. 
        •  Correct Kc expression/Korrekte Kc uitdrukking. 
        •  Substitution of Kc -value./Vervanging van Kc waarde. 
        •  Substitution into Kc expression/Substitueer in Kc uitdrukking. 
        •  Calculate /Bereken n(H2)equilibrium/ewewig 
        •  Final answer/Finale antwoord n(H2) initial/begin = 2,45 mol 

        OPTION/OPSIE 1
        n(H2S)equilibrium/ewewig = m/M = 17/34 = 0,5 mol

                                         H2                      S   H2S
        ninitial/begin (mol)                                         0                   ratio/
        Δn (mol)                         0,5                     0,5 0,5             verhouding 
        nequilibrium/ewewig(mol)                                     0,5
        cequilibrium/ewewig (mol.dm-3)   nequilibrium/ewewig/V       0,5/V           ÷V 

                            Kc = [H2S]/[H2] 
            2,56 x 10-1  = (0,5/V)/(n(H2)equilibrium/ewewig/V) 
        n(H2)equilibrium/ewewig = 1,95 mol 
             n(H2)initial/begin = 0,5 + 1,95 = 2.45 mol                                            (8)

6.5.3   POSITIVE MARKING from QUESTION 6.5.2
  +
        POSITIEWE NASIEN vanaf VRAAG 6.5.2

        90/100 ni(S)  = ni(S) – 0,5 
                 ni(S) = 5 mol                                                                     (3)

6.5.4   Graph/Grafiek Q
  -
        • As temperature increases, Kc decreases. 
          Indien die temperatuur toeneem, neem Kc af.
        • [H2S] decreases/[H2] increases.
          [H2S] neem af/ [H2] verhoog.
        • Reverse reaction is favoured by an increase in temperature. 
          Terugwaartse reaksie word bevoordeel deur ŉ verhoging in
          temperatuur.                                                                               (4)
                                                                                                    [26]

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QUESTION/VRAAG 7

7.1.1   Hydrolysis /Hidrolise                                                        (1)

7.1.2   Transfer of proton(H+) occurs./ CO32- gains a proton / H2O loses a proton.
        Oordrag van proton(H+) vind plaas/CO32- ontvang ŉ proton/H2O verloor ŉ
        proton(H+).                                                                   (1)

7.1.3   OH-                                                                          (1)

7.1.4   Kb < 1 x 10 -14                                                              (1)

7.1.5   Substance that can act either as an acid or base./ 
        ŉ Stof wat as beide suur of basis kan optree.                                 (2)

7.1.6   H2CO3                                                                        (1)

7.1.7   CO3-2                                                                        (1)

7.2.1   An acid that donates TWO protons/H+/H3O+-ions. 
        ŉ Suur wat TWEE protone/H+/H3O+-ione vrystel.                                 (2)

7.2.2    pH = - log [H3O+]
        1,3= - log [H3O+]
         [H3O+]= 10-1,3
        [OH-][H3O+] = 1 x 10-14
        [OH-] x 10-1,3 =1 x 10-14
        [OH-] = 10-12,7 mol.dm-3 = 1,995 x 10-13 mol.dm-3                            (4)

7.3.1   POSITIVE MARKING FROM Q 7.2.2/POSITIEWE NASIEN VANAF V7.2.2
        OPTION /OPSIE 1
   +
        [H3O+] = 10-1,3 mol.dm-3
        [Acid] = ½ x10-1,3  = 0,0251 mol.dm-3

                     Dilution c1V1= c2V2
                        0,0251(8) = c2 x 100
                          c2(dilute) = 2,008 x 10-3 mol.dm-3

        n(acid reacting) = cV = 2,008 x 10-3 x 25/1000 = 5,02 x 10-5 mol

        n(base reacting) = 2 x 5,02 x 10-5 = 1,004 x 10-4 mol

        c(base) = n/V = 1,004 x 10-4/14,2 x 10-3  = 7,07 x 10-3 mol.dm-3            (6)

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        OPTION/OPSIE 2

        [H3O+] = 10-1,3 mol.dm-3
        [Acid] = ½ x10-1,3  = 0,0251 mol.dm-3

                    c1V1 = c2V2
        (0,0251)(8) = c2 x 100
                      c2 = 2,008 x 10-3 mol.dm-3

        caVa = na
        cbVb   nb

        2,008 x 10-3 ( 25)  = 1
        cb x 14,2             2

        cb = 7,07 x 10-3 mol.dm-3 

        Range/Gebied       ( 7,04 x 10-3 to/tot 7,07 x 10-3 mol.dm-3)

7.3.2   B
        Titration of a strong base and a strong acid  (solution at end point neutral.)
   -    Titrasie van ŉ sterk basis en ŉ sterk suur (oplossing is neutraal by
        eindpunt.)                                                                     (2)
                                                                                      [22]
                                                                        TOTAL/TOTAAL: 150

                                           11

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## Collection

- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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