# Physical Sciences Grade 12 P2 Eastern Cape Mock 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Eastern Cape Mock Exam 2018, 21 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physical-sciences-p2-memo/694067dd-009d-4594-b207-998a8d9d1735
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: Eastern Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 21

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Physical Sciences · Grade 12 · Eastern Cape Mock Exam · 2018. Memorandum, 21 pages. Read online or download the PDF.

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                             NATIONAL
                        SENIOR CERTIFICATE/
                         NASIONALE SENIOR
                            SERTIFIKAAT

                         GRADE/GRAAD 12

                         SEPTEMBER 2018

            PHYSICAL SCIENCES P2
          FISIESE WETENSKAPPE V2
       MARKING GUIDELINE/NASIENRIGLYN

MARKS/PUNTE:   150

                     This marking guideline consists of 21 pages.
                     Hierdie nasienriglyn bestaan uit 21 bladsye.

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2                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2            (EC/SEPTEMBER 2018)

 GUIDELINES FOR MARKING/RIGLYNE VIR NASIEN

 This section provides guidelines for the way in which marks will be allocated. The broad
 principles must be adhered to in the marking of Physical Sciences tests and examinations.

 Hierdie afdeling verskaf riglyne vir die manier waarop punte toegeken sal word. Die breë
 beginsels moet tydens die nasien van Fisiese Wetenskappe toetse en eksamens gevolg word.

 1.1    MARK ALLOCATION/PUNTETOEKENNING

        1.1.1     Definitions/Definisies: Two marks will be awarded for a correct
                  definition. No marks will be awarded for an incorrect or partially correct
                  definition. Twee punte sal vir ŉ korrekte definisie toegeken word. Geen
                  punte sal vir ŉ verkeerde of gedeeltelik korrekte definisie toegeken
                  word nie.

        1.1.2     Calculations/Berekeninge:
                  o    Marks will be awarded for: correct formula, correct substitution,
                       correct answer with unit. Punte sal toegeken word vir: korrekte
                       formule, korrekte substitusie, korrekte antwoord met eenheid.
                  o    No marks will be awarded if an incorrect or inappropriate formula
                       is used, even though there may be relevant symbols and
                       applicable substitutions. Geen punte sal toegeken word waar ŉ
                       verkeerde of ontoepaslike formule gebruik word nie, selfs al is
                       daar relevante simbole en relevante substitusies.

        1.1.3     Explanations and interpretations/Verduidelikings en
                  interpretasie:
                  Allocation of marks to questions requiring interpretation or explanation
                  e.g. AS 1.4, 2.2, 2.3, 3.1, 3.2 and 3.3, will differ and may include the
                  use of rubrics, checklists, memoranda, etc. In all such answers
                  emphasis must be placed on scientific concepts relating to the
                  question.
                  Toekenning van punte by vrae wat interpretasie of verduideliking
                  vereis bv. AS 1.4, 2.2, 2.3, 3.1, 3.2 en 3.3, sal verskil en mag die
                  gebruik van rubrieke, kontrolelyste, memoranda, ens. insluit. By al
                  hierdie antwoorde moet die wetenskaplike konsepte, met betrekking
                  tot die vraag, beklemtoon word.

 1.2    FORMULAE AND SUBSTITUTIONS/FORMULES EN SUBSTITUSIES

        1.2.1     Mathematical manipulations and change of subjects of appropriate
                  formulae carry no marks, but if a candidate starts with the correct
                  formula and then changes the subject of the formula incorrectly, marks
                  will be awarded for the formula and the correct substitutions. The mark
                  for the incorrect numerical answer is forfeited.
                  Wiskundige manipulering en verandering van die voorwerp van
                  toepaslike formules dra geen punte nie, maar as ŉ kandidaat begin
                  met die korrekte formule en dan die voorwerp van die formule verkeerd
                  uitwerk, sal punte vir die formule en korrekte substitusie toegeken
                  word.

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        1.2.2         When an error is made during substitution into a correct formula, a
                      mark will be awarded for the correct formula and for the correct
                      substitutions, but no further marks will be given.
                      Wanneer ŉ fout gedurende substitusie in ŉ korrekte formule
                      begaan word, sal ŉ punt vir die korrekte formule en vir korrekte
                      substitusie toegeken word, maar geen verdere punte sal toegeken
                      word nie.

        1.2.3         Marks are only awarded for a formula if a calculation has been
                      attempted, i.e. substitutions have been made or a numerical answer
                      given.
                      Punte sal slegs toegeken word vir ŉ formule as ŉ poging aangewend
                      is om ŉ berekening te doen d.w.s. substitusie is gedoen of ŉ
                      numerieke antwoord is verskaf.

        1.2.4         Marks can only be allocated for substitutions when values are
                      substituted into formulae and not when listed before a calculation
                      starts.
                      Punte kan slegs toegeken word vir substitusies wanneer waardes in
                      formules ingestel is en nie vir waardes wat voor ŉ berekening gelys is
                      nie.

        1.2.5         All calculations, when not specified in the question, must be done to
                      two decimal places.
                      Alle berekenings, wanneer nie in die vraag gespesifiseer word nie,
                      moet tot twee desimale plekke gedoen word.

 1.3    UNITS/EENHEDE

        1.3.1         Candidates will only be penalised once for the repeated use of an
                      incorrect unit within a question or sub-question.
                      ŉ Kandidaat sal slegs een keer gepenaliseer word vir die herhaaldelike
                      gebruik van ŉ verkeerde eenheid in ŉ vraag of subvraag.

        1.3.2         Units are only required in the final answer to a calculation.
                      Eenhede word slegs in die finale antwoord tot ŉ vraag verlang.

        1.3.3         Marks are only awarded for an answer, and not for a unit per se.
                      Candidates will therefore forfeit the mark allocated for the answer in
                      each of the following situations:
                       correct answer + wrong unit
                       wrong answer + correct unit
                       correct answer + no unit.
                      Punte word slegs vir ŉ antwoord en nie vir ŉ eenheid per se toegeken
                      nie. Kandidate sal derhalwe die punt vir die antwoord in die volgende
                      gevalle verbeur:
                       korrekte antwoord + verkeerde eenheid
                       verkeerde antwoord + korrekte eenheid
                          korrekte antwoord + geen eenheid

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4                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2               (EC/SEPTEMBER 2018)

        1.3.4     SI units must be used except in certain cases, e.g. V .m-1 instead of
                  N.C-1, and cm.s-1 or km.h-1 instead of m.s-1 where the question warrants
                  this. (This instruction only applies to Paper 1).
                  SI-eenhede moet gebruik word behalwe in sekere gevalle, bv. V.m-1 in
                  plaas van of N.C-1, en cm.s-1 of km.h-1 in plaas van m.s-1 waar die vraag
                  dit verlang. (Hierdie instruksie geld slegs vir Vraestel 1).

 1.4    POSITIVE MARKING/POSITIEWE NASIEN

        Positive marking regarding calculations will be followed in the following cases:
        Positiewe nasien met betrekking tot berekeninge sal in die volgende gevalle geld:

        1.4.1     Subquestion to subquestion: When a certain variable is calculated in
                  one subquestion (e.g. 3.1) and needs to be substituted in another (3.2 or
                  3.3), e.g. if the answer for 3.1 is incorrect and is substituted correctly in
                  3.2 or 3.3, full marks are to be awarded for the subsequent sub
                  questions.
                  Subvraag na subvraag: Wanneer ŉ sekere veranderlike in een
                  subvraag (bv. 3.1) bereken word en dan in ŉ ander vervang moet word
                  (3.2 of 3.3), bv. indien die antwoord vir 3.1 verkeerd is en word korrek in
                  3.2 of 3.3 vervang, word volpunte aan die daaropvolgende subvraag
                  toegeken.

        1.4.2     A multi-step question in a subquestion: If the candidate has to
                  calculate, for example, current in the first step and gets it wrong due to a
                  substitution error, the mark for the substitution and the final answer will
                  be forfeited.
                  ŉ Vraag met veelvuldige stappe in ŉ subvraag: Indien ŉ kandidaat
                  byvoorbeeld, die aantal mol verkeerd bereken in ŉ eerste stap as gevolg
                  van ŉ substitusiefout, verloor die kandidaat die punt vir die substitusie
                  sowel as die finale antwoord.

        1.4.3     If a final answer to a calculation is correct, full marks will not automatically
                  be awarded. Markers will always ensure that the correct/ appropriate
                  formula is used and that workings, including substitutions, are correct.
                  Indien ŉ finale antwoord tot ŉ berekening korrek is, sal volpunte nie
                  outomaties toegeken word nie. Nasieners sal altyd verseker dat die
                  korrekte toepaslike formule gebruik is en dat bewerkings, insluitende
                  substitusies, korrek is.

        1.4.4     Questions where a series of calculations have to be made (e.g. a circuit
                  diagram question) do not necessarily always have to follow the same
                  order. FULL MARKS will be awarded provided it is a valid solution to the
                  problem. However, any calculation that will not bring the candidate closer
                  to the answer than the original data, will not count any marks.
                  Vrae waar ŉ reeks berekeninge gedoen moet word
                  (bv. ŉ stroombaandiagram-vraag) hoef dieselfde volgorde nie
                  noodwendig gevolg te word nie. VOLPUNTE sal toegeken word mits dit
                  ŉ geldige oplossing tot die probleem is. Maar, enige berekening wat nie
                  die kandidaat nader aan die antwoord bring as die oorspronklike data
                  nie, sal egter geen punte nie tel nie.

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        1.4.5         If one answer or calculation is required, but two given by the candidate,
                      only the first one will be marked, irrespective of which one is correct. If
                      two answers are required, only the first two will be marked, etc.
                      Indien een antwoord of berekening verlang word, maar twee word deur
                      die kandidaat gegee, sal slegs die eerste een nagesien word, ongeag
                      watter een korrek is. Indien twee antwoorde verlang word, sal slegs die
                      eerste twee nagesien word, ens.

        1.4.6         Normally, if based on a conceptual mistake, an incorrect answer cannot
                      be correctly motivated. If the candidate is therefore required to motivate
                      in question 3.2 the answer given to question 3.1, and 3.1 is incorrect, no
                      marks can be awarded for question 3.2. However, if the answer for e.g.
                      3.1 is based on a calculation, the motivation for the incorrect answer for
                      3.2 could be considered.
                      Normaalweg, as dit gebaseer is op ŉ konsepfout, kan ŉ verkeerde
                      antwoord nie korrek gemotiveer word nie. As die kandidaat derhalwe
                      met ŉ vraag in 3.2 gevra word om die antwoord in vraag 3.1 te motiveer,
                      en 3.1 is verkeerd, sal geen punte vir vraag 3.2 toegeken word nie. As
                      die antwoord in bv. 3.1 egter gebaseer is op ŉ berekening, kan die
                      motivering vir die verkeerde antwoord oorweeg word.

        1.4.7         If instructions regarding method of answering are not followed, e.g. the
                      candidate does a calculation when the instruction was to solve by
                      construction and measurement, a candidate may forfeit all the marks
                      for the specific question.
                      Indien instruksies aangaande metode van beantwoording nie gevolg
                      word nie, bv. die kandidaat doen ŉ berekening wanneer die instruksie
                      los op deur konstruksie en meting was, mag die kandidaat al die punte
                      vir die spesifieke vraag verbeur.

        1.4.8         For an error of principle, no marks are awarded (Rule 1) e.g. If the
                      potential difference is 200 V and resistance is 25 Ω, calculate the current.
                      Vir ŉ verkeerde beginsel, sal geen punte toegeken word nie (Reël 1)
                      bv. As die potensiaalverskil 200 V en die weerstand 25 Ω is, bereken die
                      stroom.

                      CORRECT        ANSWER         POSSIBLE       ANSWER           POSSIBLE
                      KORREK         (1)            MOONTLIK       (2)              MOONTLIK
                                     ANTW. (1)                     ANTW. (2)
                         V               V              V               V              V
                      I=            R=            R=    𝒙        R=              I=   
                         R                I             I               I              R
                         200             200            200            R             = 8A 
                       =              =      𝒙       =            I= 𝒙
                         25              25             25             V
                       = 8A           = 8A 𝒙         = 8A             25
                                                                    =
                                                                       200

                                                                   = 0,125 A 𝒙

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6                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2018)

 1.5    GENERAL PRINCIPLES OF MARKING IN CHEMISTRY/
        ALGEMENE BEGINSELS BY DIE NASIEN van CHEMIE

        The following are a number of guidelines that specifically apply to Paper 2.
        Die volgende is ŉ aantal riglyne wat spesifiek op Vraestel 2 van toepassing is.

        1.5.1     When a chemical FORMULA is asked, and the NAME is given as
                  answer, only one of the two marks will be awarded. The same rule
                  applies when the NAME is asked and the FORMULA is given.
                  Wanneer ŉ chemiese FORMULE gevra word en die NAAM word as
                  antwoord gegee, sal slegs een van die twee punte toegeken word.
                  Dieselfde reël geld wanneer die NAAM gevra word en die FORMULE
                  gegee word.

        1.5.2     When redox half-reactions are to be written, the correct arrow should
                  be used. If the equation
                                         H2S → S + 2H+ + 2e- (2/2)

                  is the correct answer, the following marks will be given:
                  Wanneer redokshalfreaksies geskryf moet word, moet die korrekte
                  pyltjie gebruik word. Indien die bostaande vergelyking die korrekte
                  antwoord is, sal die volgende punte toegeken word:

                  H2S ⇋ S + 2H+ + 2e- (1/2)
                  H2S ← S + 2H+ + 2e- (0/2)
                  S + 2H+ + 2e- ← H2S (2/2)
                  S + 2H+ + 2e- ⇋ H2S (0/2)

        1.5.3     When candidates are required to give an explanation involving the
                  relative strength of oxidising and reducing agents, the following is
                  unacceptable:

                      Stating the position of a substance on Table 4 only (e.g. Cu is
                       above Mg).
                      Using relative reactivity only (e.g. Mg is more reactive than Cu).
                      The correct answer would for instance be: Mg is a stronger
                       reducing agent than Cu, and therefore Mg will be able to reduce
                       Cu2+ ions to Cu. The answer can also be given in terms of the
                       relative strength as electron acceptors and donors.

                  Wanneer kandidate ŉ verduideliking moet gee oor die relatiewe sterkte
                  van oksideer- en reduseermiddels, is die volgende onaanvaarbaar:

                   Meld slegs die posisie van ŉ stof op tabel 4 (bv. Cu is bo Mg).
                   Gebruik slegs relatiewe reaktiwiteit (bv. Mg is meer reaktief as Cu).
                   Die korrekte antwoord sal byvoorbeeld wees: Mg is ŉ sterker
                    reduseermiddel as Cu en derhalwe sal Mg in staat wees om Cu 2+-
                    ione na Cu te reduseer. Die antwoord kan ook in terme van die
                    relatiewe sterkte van elektronakseptors of donors gegee word.

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        1.5.4         One mark will be forfeited when the charge of an ion is omitted per
                      equation.
                      Een punt sal verbeur word wanneer die lading van ŉ ioon per
                      vergelyking weggelaat is.

        1.5.5         The error carrying principle does not apply to chemical equations or
                      half-reactions. For example, if a learner writes the wrong
                      oxidation/reduction half-reaction in the subquestion and carries the
                      answer to another subquestion (balancing of equations or calculations
                      of Eθcell) then the learner is not credited for this substitution.
                      Die foutdraendebeginsel geld nie vir chemiese vergelykings of
                      halfreaksies nie. Byvoorbeeld, indien ŉ leerder die verkeerde
                      oksidasie/reduksie-halfreaksie vir die subvraag skryf en die antwoord
                      na ŉ ander subvraag dra (balansering van vergelyking vir of E𝜃sel) dan
                      word die leerder nie vir die substitusie gekrediteer nie.

        1.5.6         When a calculation of the cell potential of a galvanic cell is expected,
                      marks will only be awarded for the formula if one of the formulae
                      indicated on the data sheet (Table 2) is used. The use of any other
                      formula using abbreviations etc. will carry no marks.
                      Wanneer ŉ berekening van die selpotensiaal van ŉ gegalvaniseerde
                      sel verlang word, sal punte slegs vir die formule toegeken word as een
                      van die formules op die gegewensblad (Tabel 2) gebruik word. Die
                      gebruik van enige ander formule, die gebruik van afkortings, ens. sal
                      geen punte toegeken word nie.

        1.5.7         In the structural formula of an organic molecule all hydrogen atoms
                      must be shown. Marks will be deducted if hydrogen atoms are omitted.
                      In die struktuurformule van ŉ organiese molekuul moet alle
                      waterstofatome getoon word. Punte sal afgetrek word vir die
                      weglating van waterstofatome.

        1.5.8         When a structural formula is asked, marks will be deducted if the
                      candidate writes the condensed formula.
                      Wanneer ŉ struktuurformule gevra word, sal punte afgetrek word
                      indien die leerder die verkorte formule skryf.

        1.5.9         When an IUPAC name is asked, and the candidate omits the hyphen
                      (e.g. instead of 1-pentene the candidate writes 1 pentene), marks will
                      be forfeited.
                      Wanneer die IUPAC-naam gevra word en die koppelteken(s) in die
                      naam word uitgelaat (bv. in plaas van 1-penteen skryf ŉ kandidaat
                      1 penteen), sal punte verbeur word.

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8                        PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2        (EC/SEPTEMBER 2018)

 QUESTION/VRAAG 1

 1.1      C                                                                                     (2)

 1.2      B                                                                                     (2)

 1.3      A                                                                                     (2)

 1.4      B                                                                                     (2)

 1.5      D                                                                                     (2)

 1.6      D                                                                                     (2)

 1.7      B                                                                                     (2)

 1.8      A                                                                                     (2)

 1.9      C                                                                                     (2)

 1.10     C                                                                                      (2)
                                                                                                  [20]

 QUESTION/VRAAG 2

 2.1.1     Alkanes /Alkane                                                                          (1)
                          H        H
 2.1.2
                   H C H H C H                     Marking criteria/Nasienriglyne:
                 H      H      H                     Correct stem i.e pentane./
                                                      Korrekte stam d.i.pentaan.
                                                     Three methyl substituents
           H     C       C    C    C     C    H
                                                       Drie metielsubstituente.
                                                     Whole structure correct./
                 H          H      H     H
                                                      Hele struktuur korrek.     3/3
                     H   C H

                          H                                                                          (3)
 2.1.3     CO2  and/en H2O                                                                         (2)

 2.2.1     Compounds with the same molecular formula,  but different positions of the
           functional group.  / Verbindings met dieselfde molekulêre formule, maar
           verskillende posisies van die funksionele groep.                                          (2)

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 2.2.2                           H
                                                                 Marking criteria/Nasienriglyne:
                          H      C      H                          Correct functional group./
                                            O                       Korrekte funksionele groep.
                 H       H              O          H               Whole structure correct./
                                                                    Hele struktuur korrek.  2/2
           H     C       C       C      C C       C       H

                 H       H       H                H

           3-methyl pentan-2-one / 3-methyl-2- pentanone
           3-metiel pentan-2-oon / 3-metiel-2- pentanoon                                                (4)

 2.3.1     2-chloro-3,4-dimethylhexane / 2-chloor-3,4-dimetielheksaan

           Marking criteria/Nasienriglyne:
            Correct stem i.e.hexane  Korrekte stam d.i. heksaan
            First substituent, chloro, correctly identified 
              Eerste substituent, chloor korrek geïdentifiseer.
            Second substituent, dimethyl, correctly identified 
              Tweede substituent, dimetiel, korrek geïdentifiseer.
            Subtract a mark for missing hyphens, commas, incorrect numbering.
              Trek ŉ punt af vir enige koppelteken, komma wat uitgelaat is, verkeerde nommering.          (3)

  2.3.2    SECONDARY  / SEKONDȆR                                                                          (1)
                                                                                                          [16]

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10                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2018)

 QUESTION/VRAAG 3

 3.1      They are organic compounds that contain hydrogens and carbons only.
          Hulle is organiese verbindings wat slegs uit waterstof- en koolstofatome
          bestaan.                                                             (2 or/of 0)        (2)

 3.2      53,3  (kPa)

          From A to C/Van A na C
          Chain length decreases/surface area decreases/more branches. 
          Strength of intermolecular forces/London forces/dispersion forces/induced-
          dipole forces decreases. 
          Less energy needed to overcome/break intermolecular forces. 

          Kettinglengte neem af/oppervlaksarea neem af/meer vertakkings. Sterkte van
          intermolekulȇre kragte/Londonkragte/dispersiekragte/geїnduseerde-dipool
          kragte neem af.
          Minder energie word benodig om die intermolekulȇre kragte te oorkom/breek.

          OR/OF

          From C to A/Van C na A
          Chain length increases/surface area increases/less branches. 
          Strength of intermolecular forces/London forces/dispersion forces/induced-
          dipole forces increases. 
          More energy needed to overcome/break intermolecular forces. 

          Kettinglengte neem toe/oppervlaksarea neem toe/minder vertakkings.
          Sterkte van intermolekulȇre kragte/Londonkragte/dispersiekragte/
          geїnduseerde-dipool kragte neem toe.
          Meer energie word benodig om die intermolekulȇre kragte te oorkom/breek.                (4)

 3.3      E                                                                                      (1)

 3.3.1    Compound with lowest vapour pressure 
          Verbinding met die laagste dampdruk                                                     (1)

 3.3.2       Compound D(ethanol) has one site for hydrogen bonding, whereas
              compound E(methanoic acid) has two sites for hydrogen bonding. 
              Verbinding D(etanol) het een punt vir waterstofbindings, waar verbinding
              E(metanoësuur) twee punte het vir waterstofbindings.
             Compound E has stronger hydrogen bonds than compound D. 
              Verbinding E het sterker waterstofbindings as verbinding D.                          (2)
                                                                                                  [10]

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 QUESTION/VRAAG 4

 4.1       Substitution /Substitusie                                                                            (1)

 4.2.1     Waft your hand across the beaker/test tube toward your nose and sniff/smell
           (cautiously)./
           Waai met jou hand oor die beker of proefbuis en ruik (versigtig).

                                                             OR/OF

           Pour the ester into a bowl of water and this will help you to identify the smell
           of the ester./ Gooi die ester in ŉ glasbak met water om die reuk van die ester
           te kan identifiseer.                                                                                  (1)

 4.2.2     Esterification /Esterifikasie                                                                        (1)

 4.2.3     Ethanoic acid /Etanoësuur                                                                           (2)

 4.2.4
                       H    H       H        H           O       H            Marking criteria/Nasienriglyne:
                                                                               Functional group correct.
                                                                                 Funksionele groep korrek 1/2
               H       C    C       C    C   C   O       C       C    H
                                                                               Whole structure correct.
                                                              
                                                                                 Hele struktuur korrek.     2/2
                       H    H       H        H                  H
                                                                                                                 (2)

 4.3                   H    H       H H                              H    H   H     H
                                                                                         
               H       C        C    C    C O    H +HBr          H C      C   C     C   Br +        O

                       H    H       H    H                           H    H    H    H           H       H

           Accept/Aanvaar: H2O                                                                                   (4)

 4.4.1             H        H       H        H
                                                                Marking criteria/Nasienriglyne:
                                                                  Correct functional group.
           H       C        C       C      C     H                 Korrekte funksionele groep. 1/2
                                                                Whole structure correct.
                   H                        H                      Hele struktuur korrek.      2/2
                                                                                                                 (2)

 4.4.2     Concentrated H2SO4/Sulphuric acid 
           Gekonsentreerde H2SO4/Swaelsuur                                                                       (1)

 4.4.3     (Excess) water/H2O / Concentrated H2SO4
           (Oormaat) water/H2O /Gekonsentreerde H2SO4                                                             (1)
                                                                                                                 [15]

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12                     PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                   (EC/SEPTEMBER 2018)

 QUESTION/VRAAG 5

 5.1       ONLY ANY ONE OF / SLEGS ENIGE EEN VAN:
              Change in concentration  of reactants/products per (unit) time. 
                Verandering in konsentrasie van reaktanse en produkte per (eenheids)
                tyd.

                   Rate of change in concentration. 
                    Tempo van verandering in konsentrasie.

                   Change in the amount/number of moles.volume/mass of products or
                    reactants per (unit) time. 
                    Verandering in hoeveelheid/aantal mol/volume/massa van produkte of
                    reaktanse per (eenheids)tyd.

                   Amount / number of moles/volume/mass (of products) formed/
                    (reactants) used per (unit) time. 
                    Hoeveelheid / aantal mol /volume /masss (van produkte) gevorm/
                    (reaktantse) gebruik per (eenheids) tyd
                                                                                                           (2)

 5.2       EQUAL TO  / GELYK AAN                                                                          (1)

 5.3       Ave rate/Gem. tempo = ∆V = 28–0  = 1,87 (cm3.s-1) 
                                 ∆t 15–0                                                                   (2)

 5.4       Criteria for investigative question/Riglyne vir ondersoekende vraag:
           Dependent and independent variables correctly identified.                            
           Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer.
           Asks a question about the relationship between independent and dependent             
           variables./ Vra ŉ vraag oor die verwantskap tussen die afhanklike en onafhanklike
           veranderlikes.

           Examples/Voorbeelde:
       _
               What is the effect of a catalyst on the rate of the reaction?
                Wat is die effek van ŉ katalisator op die reaksietempo?
               What is the relationship between a catalyst and the rate of reaction? Wat
                is die verwantskap tussen ŉ katalisator en die reaksietempo?                               (2)

           Notes/Aantekeninge:
             IF the answer to the question is a “YES” or “NO”:/
             INDIEN die antwoord op die vraag “JA” of “NEE” is.             Max/Maks: 1/2
             Examples/Voorbeelde:
             Does the catalyst influence the rate of the reaction?
               Beïnvloed die katalisator die reaksietempo?
              Is there a relationship between the addition of a catalyst and reaction rate?
               Is daar ŉ verwantskap tussen die toevoeging van ŉ katalisator en reaksietempo?

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(EC/SEPTEMBER 2018)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                         13

 5.5       EXOTHERMIC/EKSOTERMIES 
       _   (Net) Energy is absorbed./More energy is released than absorbed. / Energy
           of reactants > Energy of products.
           (Netto) Energie word geabsorbeer./Meer energie word vrygestel as
           geabsorbeer./Energie van reaktante > Energie van produkte.                               (2)

 5.6       Experiment II /Eksperiment II                                                           (1)

 5.7          A catalyst provides an alternative pathway of lower activation energy. 
              More particles will have sufficient/enough (kinetic) energy / Ek ≥ EA. 
              More effective collisions per unit time /second. /Frequency of effective
               collisions increases.

              ŉ Katalisator verskaf ŉ alternatiewe pad van laer aktiveringsenergie.
              Meer deeltjies het genoegsame (kinetiese) energie / Ek ≥ EA.
              Meer effektiewe botsings per eenheidstyd/sekonde. / Frekwensie van
               effektiewe botsings neem toe.                                                         (3)
                                                                                                    [13]

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14                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2018)

QUESTION/VRAAG 6

6.1        The stage in a chemical reaction when the rate of the forward reaction equals
           the rate of the reverse reaction.                   (2 marks or no marks)

           Die stadium in ŉ chemiese reaksie wanneer die tempo van die voorwaartse
           reaksie gelyk is aan die terugwaartse reaksie. (2 punte of geen punte nie)

                                              OR/OF

           The state where the concentrations/quantities of reactants and products
           remain constant.                               (2 marks or no marks)

           Die toestand wanneer die konsentrasie/hoeveelhede van reaktanse en
           produkte konstant bly.                   (2 punte of geen punte nie)
                                                                                                  (2)

6.2.1      DECREASES/AFNEEM                                                                      (1)

6.2.2      NO EFFECT/GEEN EFFEK

           Kc will only change with a change in temperature./Kc is temperature
           dependent
           Kc sal slegs verander met ŉ verandering in temperatuur./ Kc is temperatuur
           afhanklik                                                                              (2)

6.3.1      Mark Allocations/Puntetoekenning:
            Correct Kc expression (formulae in square brackets).  Exp/Eksp 1 or/of 2
             Korrekte Kc uitdrukking (formules in vierkanthakies).
            Substitution of concentrations into Kc expression.
             Vervanging van konsentrasies in Kc uitdrukking.
            Substitution of Kc-value/Vervanging van Kc uitdrukking. Exp/Eksp 3
            Substitution of concentrations into Kc expression.
             Vervanging van konsentrasies in Kc uitdrukking.
            Formula/Formule: n = cV
            Calculate/Bereken n(N2O4)eq/ewe
            Calculate/Bereken n(NO2)eq/ewe. 
            Calculate/Bereken ∆ n(NO2) = n(NO2)eq/ewe - n(NO2)initial/begin 
            Use ratio n(N2O4) : n( NO2) = 1 : 2 to calculate ∆n(N2O4) 
             Gebruik verhouding: n(N2O4) : n( NO2) = 1 : 2 om ∆n(N2O4) te bereken.
            Calculate/Bereken n(N2O4)initial/begin= n(N2O4)eq/ewe + ∆n(N2O4) = 0,12 mol 

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(EC/SEPTEMBER 2018)             PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                      15

           OPTION/OPSIE 1                        OR/OF      OPTION/OPSIE 2
           Kc = [NO2]2                                     Kc = [NO2]2
                [N2O4]                                           [N2O4]

            = (0,0125)2                                     = (0,0107)2
                 0,0336                                         0,0246
              = 0,00465                                      = 0,00465

           Kc = [NO2]2
                [N2O4]

           0,00465 = (0,0156)2
                      [N2O4]

            [N2O4]eq = 0,052 mol.dm-3

                                    N2O4          2NO2
            ninitial/begin         0,1202        0
            ∆n                      0,0156        0,0312          Ratio/Verhouding
            neq/ewe                 0,1046       0,0312
            ceq                     0,052         0,0156

           OPTION/OPSIE 3                        OR/OF   OPTION/OPSIE 4
           Kc = [NO2]2                                  Kc = [NO2]2
                [N2O4]                                        [N2O4]

             = (0,0125)2                                    = (0,0107)2
                0,0336                                          0,0246
             = 0,00465                                       = 0,00465

           Kc = [NO2]2
                [N2O4]

           0,00465 = (0,0156)2
                      [N2O4]

            [N2O4]eq = 0,052 mol.dm-3

            n(N2O4)eq = cV = (0,052)(2)= 0,1046 mol

           n(NO2)eq = cV = (0,0156)(2)= 0,0312 mol

           ∆n(NO2) = n(NO2)eq - n(NO2)i= 0,0312 – 0 = 0,0312 mol

           ∆n(N2O4) = ½(0,0312)= 0,0156 mol                            Ratio = 1:2

            n(N2O4)i = n(N2O4)eq + ∆n(N2O4)

                             = 0,1046 + 0,0156
                             = 0,12 mol                                                               (9)

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16                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2         (EC/SEPTEMBER 2018)

6.3.2      EQUAL TO  / GELYK AAN                                                               (1)

6.3.3      Decrease in concentration of N2O4. / Decrease in [ N2O4 ]
           Afname in konsentrasie van N2O4 / Afname in [N2O4 ]                                 (1)
                                                                                              [16]

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(EC/SEPTEMBER 2018)       PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                           17

 QUESTION/VRAAG 7

 7.1.1    WEAK ACID/SWAK SUUR

          It has a low Ka value / The ionisation is NOT complete/incomplete.
          Dit het ŉ lae Ka waarde./ Die ionisasie is NIE volledig nie/onvolledig.                     (2)

 7.1.2    C2O42-                                                                                     (1)

 7.2.1    Hydrolysis is the reaction (of a salt) with water
          Hidrolise is die reaksie (van ŉ sout) met water                                             (2)

 7.2.2    CH3COOH and/en OH-                                                                        (2)

 7.3.1    pH = - log[H3O+]
            1 = - log[H3O+]
          [H3O+] = 0,1 mol.dm-3                                                                      (3)

 7.3.2    POSTIVE MARKING FROM QUESTION 7.3.1
          POSITIEWE NASIEN VANAF VRAAG 7.3.1
   +      OPTION/OPSIE 1               OPTION/OPSIE 2

          n(NaOH) = cV                            na = caVa 
                  = (0,025)(0,0322)               nb cbVb
                  =8,05 x 10-4 mol
                                                   1 = (0,1)Va
          n(HCℓ)excess/oormaat = n(NaOH)           1 (0,025)(32,2) 
                               = 8,05 x 10-4mol
                                                   V(HCℓ)excess/oormaat = 8,05 cm3

                                                   n(HCℓ)excess/oormaat = cV
                                                                        =0,1(0,00805)
                                                                        = 8,05 x 10 -4 mol
                                                                                                      (3)

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18                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2              (EC/SEPTEMBER 2018)

 7.3.3    POSTIVE MARKING FROM QUESTION 7.3.2
          POSITIEWE NASIEN VANAF VRAAG 7.3.2
          OPTION/OPSIE 1                        Marking guidelines/Nasienriglyne:
     +
          V(HCℓ)excess/oormaat = n/c             Subtract 0,00805 from 0,005
                               = 0,000805 / 0,1   Trek 0,00805 van 0,005 af
                               = 0,00805 dm  3   Substitution into/ Vervanging in
                                                       n(HCℓ) reacted/gereageer =cV 
          V(HCℓ)reacted/gereageer                     Use ratio/Gebruik verhouding 1 : 2
                    = 0,050 – 0,00805                Substitution into / Vervanging in
                   = 0,04195 dm3                         m(CaCO3)= nM
                                                        Calculate/Bereken: %
          n(HCℓ) reacted/gereageer = cV                  purity/suiwerheid
                                  = (0,1)(0,04195)     Final answer/Finale antwoord: 69,92%
                                  = 0,004195 mol
                                                     RANGE (69,92 TO 70%)
          n(CaCO3) = ½ n(HCℓ) reacted/gereageer
                  = 0,0020975 mol

          m(CaCO3) = nM
                   = (0,0020975 )(100) 
                   = 0,20975 g

          % purity/suiwerheid = 0,20975x100
                                  0,3
                              = 69,92%

          OPTION/OPSIE 2

          [HCl] = [H3O+] = 0,1 mol.dm-3

          nHCl initial = cV = 0,1 x 50/1000 
                         = 5 x 10 -3 mol

          nHCl excess = 8,05 x 10 -4 mol (From
          7.3.2)

          nHCl reacted = 5 x 10 -3 - 8,05 x 10 -4

                     = 4,195 mol

          nCaCO3 = ½ x 4,195

                  = 2,097 x 10 -3 mol

          m = nM= 2,097 x 10 -3 x 100
                = 0,20975 g

          %Purity = mpure/m impure x 100
                  = 0,20975/0,3 x100 
                  = 69,92%                                                                           (6)
                                                                                                     [19]

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(EC/SEPTEMBER 2018)         PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                              19

 QUESTION/VRAAG 8
 8.1      A solution / liquid / dissolved substance that conducts electricity through the
          movement of ions 
          ŉ Oplossing / vloeistof / opgeloste stof wat elektrisiteit gelei deur die
          beweging van ione                                                                               (2)

 8.2.1    Pressure: 1 atmosphere (atm) /101,3 kPa / 1,013 x 105 Pa
          Druk: 1 atmosfeer (atm) / 101,3 kPa / 1,013 x 105 Pa                                            (1)

 8.2.2    Platinum is a conductor of electricity 
          Platinum is ŉ geleier van elektrisiteit                                                         (1)
 8.3      ANODE                                                                                          (1)

 8.4       OPTION/OPSIE 1                             Notes/Aantekeninge:
           E0cell/sel = E0cathode/katode - E0anode    Accept any other correct formula from the
             1,5= E0cathode/katode - (-0,14)           data sheet.
           E0cathode/katode = 1,36V                     Aanvaar enige ander korrekte formule
                                                         vanaf gegewensblad.
           X2 = Cℓ2/Chlorine(gas)/Chloor(gas)         Any other formula using unconventional
                                                         abbreviations, e.g. E0cell = E0OA – E0RA
                                                         Enige ander formule wat onkonvensionele
           Accept/Aanvaar:
                                                         afkortings gebruik, bv.
           Cℓ2 / Cℓ- half reaction / halfreaksie
                                                         E0sell = E0OM – E0RM gevolg deur korrekte
                                                         vervangings:         Max/Maks: 3/4

           OPTION/OPSIE 2
              X2 + 2e- → X2      + 1,36(V) 
            Sn → Sn + 2e-
                       +2        + 0,14(V) 
             X2 + Sn → X2 + Sn+2 1,50 (V) 

           X2 = Cℓ2/Chlorine(gas)/Chloor(gas)

           Accept/Aanvaar:
           Cℓ2 / Cℓ- half reaction / halfreaksie                                                          (5)

 8.5      BECOMES ZERO/ WORD NUL

          The electrical circuit is incomplete /
          Die elektriese stroombaan is onvolledig                                                         (2)
 8.6      3Mg(s) + 2Aℓ +3(aq)  → 3Mg+2(aq) + 2Aℓ (s)  Bal 

          Notes/Aantekeninge:
            Reactants             Products                     Balancing
            Reaktanse              Produkte                      Balansering
            Ignore double arrows/Ignoreer dubbelpyle
            Marking rule 6.3.10/Nasienreël 6.3.10
                                                                                                       (3)
                                                                                                      [15]

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20                    PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2           (EC/SEPTEMBER 2018)

 QUESTION/VRAAG 9

 9.1.1   Battery /Energy source/Power source
         Battery/Kragbron                                                                         (1)

 9.1.2   Chlorine /Chloor/Cℓ2                                                                    (1)

 9.1.3   2H2O(ℓ) + 2e- → H2(g) + 2OH-(aq) 

         Ignore phases/Ignoreer fases

         Notes/Aantekeninge:
         H2(g) + 2OH-(aq)← 2H2O(ℓ) + 2e- (2/2)   2H2O(ℓ) + 2e- ⇌ H2(g) + 2OH-(aq) (1/2)
         H2(g) + 2OH-(aq) ⇌2H2O(ℓ) + 2e- (0/2)   2H2O(ℓ) + 2e- ← H2(g) + 2OH-(aq) (1/2)           (2)

 9.1.4   Cℓ  OR/OF NaCℓ                                                                          (1)

 9.2     [H3O+] > 1 x 10-7

         Solution is alkaline/NaOH is formed
         Oplossing is alkalies/NaOH word gevorm                                                   (2)

 9.3     Cu+2 is a stronger oxidising agent (than Na+) and will be reduced  to Cu. 
         Cu+2 is ŉ sterker oksideermiddel (as Na+) en sal gereduseer word (na Cu).              (3)
                                                                                               [10]

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(EC/SEPTEMBER 2018)        PHYSICAL SCIENCES P2/FISIESE WETENSKAPPE V2                                  21

 QUESTION/VRAAG 10
 10.1.1     Vanadium pentoxide/Vanadiumpentoksied /V2O5                                                  (1)
 10.1.2     H2SO4                                                                                        (1)
 10.1.3     Water                                                                                        (1)

 10.1.4     Contact (process) / Kontak (proses)                                                          (1)

 10.1.5     NH3(g) + H2SO4(aq)  → ( NH4)2SO4                              Bal.                         (3)
            Notes/Aantekeninge:
             Reactants               Products                      Balancing 
               Reaktante               Produkte                      Balansering
             Ignore/Ignoreer     ⇌   and phases/en fases
             Marking rule 6.3.10/Nasienreёl 6.3.10

 10.1.6     HIGHER THAN 450 0C / HOÊR AS 450 0C
            Mark independently/Merk onafhanklik:
               For all pressure values 
                  Vir alle waardes vir druk
               Yield is lower for graph Q 
                  Opbrengs vir Q is laer
               Reverse reaction which is endothermic will be favoured 
                  Terugwaartse reaksie wat endotermies is, word bevoordeel                                (4)
 10.2.1     Ensures quality seeds, fruit, vegetables and flowers. 
            Verseker kwaliteit saad, vrugte, groente en blomme.
            OR/OF
            Help plants fight frost and resist diseases. 
            Help plante veg teen ys en bied weerstand teen siektes.                                       (1)
 10.2.2     OPTION/OPSIE 1                             OPTION/OPSIE 2
            % fertiliser = 100 – 76 = 24%             % fertiliser = 100 – 76 = 24%
            % K = 24 – (4+8) = 12                     % K = 24 – (4+8) = 12

            m(K) = 12                                  m(K) = 12 x m(fertiliser) = 6 kg 
                                                                 24
            x m(bag) = 6 kg                           m(fertiliser) = 12 kg 
                   100
            m(bag) = 50 kg                            m(filler) = 12 x 76 = 38 kg        (24 : 76)
                                                                   24
                                                       m(bag) = 12 + 38 = 50 kg
            Marking criteria/Nasienriglyne:
             Subtract to obtain % fertiliser.
               Aftrekking om % kunsmis te kry.
             -(4+8) for % K in bag of fertiliser/in sak kunsmis 
             Calculate mass m /Bereken massa m 
             Final answer/Finale antwoord: 50 kg                                                        (4)
                                                                                                         [16]

                                                                                 TOTAL/TOTAAL:           150

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