# Physical Sciences Grade 12 Paper 2 NSC November 2012 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the NSC November Exam 2012, 11 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2012
- Exam period: NSC November Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 11

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Physical Sciences · Grade 12 · NSC November Exam · 2012. Memorandum, 11 pages. Read online or download the PDF.

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### Page 1

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                                       NATIONAL
                                  SENIOR CERTIFICATE
                                      NASIONALE
                                  SENIOR SERTIFIKAAT

                                        GRADE/GRAAD 12

                          PHYSICAL SCIENCES: CHEMISTRY (P2)
                           FISIESE WETENSKAPPE: CHEMIE (V2)

                                         NOVEMBER 2012

                                         MEMORANDUM

MARKS/PUNTE: 150

                             This memorandum consists of 11 pages.
                           Hierdie memorandum bestaan uit 11 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2    2                                DBE/November 2012
                                     NSC/NSS – Memorandum

SECTION A/AFDELING A

QUESTION 1/VRAAG 1

1.1       Ketones/Ketone                                                                      (1)

1.2       Ethene/Eteen                                                                        (1)

1.3       Activation (energy)/Aktiverings(energie)                                            (1)

1.4       Catalyst/katalistor                                                                 (1)

1.5       (saturated) sodium chloride solution 
          (versadigde) natriumchloried oplossing                                               (1)
                                                                                               [5]

QUESTION 2/VRAAG 2

2.1       B                                                                                  (2)

2.2       C                                                                                  (2)

2.3       A                                                                                  (2)

2.4       A                                                                                  (2)

2.5       D                                                                                  (2)

2.6       D                                                                                  (2)

2.7       B                                                                                  (2)

2.8       C                                                                                  (2)

2.9       D                                                                                  (2)

2.10      A                                                                                  (2)
                                                                                              [20]

                                                   TOTAL SECTION A/TOTAAL AFDELING A: 25

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Physical Sciences P2/Fisiese Wetenskappe V2    3                              DBE/November 2012
                                     NSC/NSS – Memorandum

SECTION B/AFDELING B
QUESTION 3/VRAAG 3
3.1
3.1.1     A                                                                                 (1)
3.1.2     D & F                                                                            (2)
3.1.3     D                                                                                 (1)
3.1.4     E                                                                                 (1)
3.1.5     B                                                                                 (1)
3.2
3.2.1     2-methylbut-1-ene 
          2-metielbut-1-een                                                                (2)
3.2.2
                 H    H     H   H       O
            H C       C     C   C       C   O H 
                 H    H     H   H                                                            (2)
3.3
3.3.1     Pleasant odour 
          Aangename geur                                                                     (1)
3.3.2     Ethanol 
          Etanol                                                                             (2)
3.3.3     Ethyl propanoate 
          Etielpropanoaat                                                                    (2)
                                                                                            [15]

QUESTION 4/VRAAG 4

4.1
4.1.1    Fuels 
         Brandstowwe                                                                         (1)

4.1.2     C n H 2n + 2                                                                      (1)

4.2
4.2.1     Boiling point/Kookpunt                                                            (1)

4.2.2     Chain length/Molecular size/Molecular mass 
          Kettinglengte/Molekulêre grootte/Molekulêre massa                                  (1)

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Physical Sciences P2/Fisiese Wetenskappe V2    4                                DBE/November 2012
                                     NSC/NSS – Memorandum

4.2.3

         Criteria for conclusion/Kriteria vir gevolgtrekking:                  Mark/Punt
         Dependent and independent variables correctly identified.
                                                                                     
         Afhanklike en onafhanklike veranderlikes korrek geïdentifiseer.
         Relationship between the independent and dependent variables
         correctly stated.
                                                                                     
         Verwantskap tussen die afhanklike en onafhanklike veranderlikes
         korrek genoem.

          Examples/Voorbeelde:
          • Boiling point increases with increase in chain length/molecular
             size/molecular mass.
             Kookpunt neem toe met toename in kettinglengte/molekulêre
             grootte/molekulêre massa.
          • Boiling point decreases with decrease in chain length/ molecular
             size/molecular mass.
             Kookpunt neem af met afname in kettinglengte/molekulêre
             grootte/molekulêre massa.
          • Boiling point is proportional to chain length/molecular size/molecular
             mass.
             Kookpunt is eweredig aan kettinglengte/molekulêre grootte/molekulêre
             massa .                                                                           (2)
4.3       Pentane/Pentaan 
          OR/OF
          Hexane/Heksaan                                                                      (1)

4.4       C 3 H 8 + 5O 2 → 3CO 2 + 4H 2 O     bal                                           (3)
4.5       Lower than 
          • Structure:
             Isomers have more branching/ more compact or spherical molecules /
             smaller surface areas over which the intermolecular forces act. 
          • Intermolecular forces:
             Weaker intermolecular forces/less intermolecular forces 
          • Energy:
             Less energy needed to overcome intermolecular forces. 
          Kleiner as 
          • Struktuur:
               Isomere meer vertak/Molekule meer kompak of sferies./ Kleiner
              oppervlaktes waaroor intermolekulêre kragte werk. 
          • Intermolekulêre kragte
              Swakker intermolekulêre kragte/ minder intermolekulêre kragte 
          • Energie:
              Die minder energie benodig om intermolekulêre kragte te oorkom.                 (4)
                                                                                              [14]

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Physical Sciences P2/Fisiese Wetenskappe V2    5                                 DBE/November 2012
                                     NSC/NSS – Memorandum

QUESTION 5/VRAAG 5

5.1
5.1.1     Haloalkanes /Haloalkane                                                              (1)

5.1.2                        H
                        H    C   H
                H      H             H
           H    C      C     C       C      H 
                H     Br     H        H
                                                                                                (2)

5.2
5.2.1     Substitution/Substitusie 

          OR/OF
          Hydrolysis/Hidrolise                                                                 (1)
5.2.2                        H
                        H    C    H
                H      H                H
            H   C      C     C          C   H 
                H      O     H          H

                       H                                                                        (2)

5.3
5.3.1     Heat strongly 
          Verhit sterk                                                                          (1)

5.3.2     Elimination/dehydrohalogenation/dehydrobromination 
          Eliminasie/dehidrohalogenering/dehidrobrominering                                    (1)

5.3.3                        H
                           H C H
                H      H                H
            H   C      C     C          C   H 
                H                       H
                                                                                                (2)
5.4       2-methylbut-2-ene 
          2-metielbut-2-een                                                                     (2)
                                                                                               [12]

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Physical Sciences P2/Fisiese Wetenskappe V2    6                               DBE/November 2012
                                     NSC/NSS – Memorandum

QUESTION 6/VRAAG 6
6.1       Carbon dioxide 
          Koolstofdioksied/koolsuurgas                                                        (1)
6.2
6.2.1    (6 ; 3,1)                                                                           (1)
6.2.2     12 minutes/minute                                                                  (1)
6.2.3.    4 minutes/minute                                                                   (1)
6.3       More particles per unit volume 
          More effective collisions per unit time/second. 
          Meer deeltjies per eenheids volume deeltjies.
          Meer effektiewe botsings per eenheids tyd/sekonde.                                  (2)

6.4
6.4.1     Increases/Vermeerder                                                               (1)
6.4.2     Remains the same/Bly dieselfde                                                     (1)
6.4.3     Decreases/Neem af                                                                  (1)
6.5       •   Add a catalyst/Voeg 'n katalisator by 
          •   Increase surface area of calcium carbonate./Use calcium carbonate
              powder./Crush calcium carbonate chips. 
              Verhoog die oppervlakarea van kalsiumkarbonaat./Gebruik
              kalsiumkarbonaatpoeier./Maak die kalsiumkarbonaatstukkies fyn.                  (2)
6.6                  m
          n(CO 2 ) =    
                     M
                      4
                   =
                     44 
                   = 0,09 mol
          n(CaCO 3 ) = n(CO 2 ) = 0,09 mol
          m(CaCO 3 ) = nM
                     = (0,09) (100)                                                         (5)
                     =9g                                                                    [16]

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Physical Sciences P2/Fisiese Wetenskappe V2    7                                      DBE/November 2012
                                     NSC/NSS – Memorandum

QUESTION 7/VRAAG 7

7.1       The stage in a chemical reaction when the rate of forward reaction equals the
          rate of reverse reaction. 
          Die stadium in 'n chemiese reaksie wanneer die tempo van die voorwaartse
          reaksie is gelyk aan die tempo van die terugwaarste reaksie. 
                                                                                                     (2)

7.2       n(B)reacted/gereageer = 6 – 4 = 2 mol 
          n(C)formed/gevorm = n(B)reacted/gereageer
                             = 2 mol 
                 n    2
          c(C) =    =    = 0,4 mol·dm-3
                 V    5                                                                              (3)

7.3       Increases 
          •    3 mol/volumes (of gas) produces 2 mol/volumes (of gas)./The reaction
               which produces the smaller number of moles/volume is favoured. 
          •    Forward reaction is favoured. 
          Vermeerder 
          •   3 mol/volumes (gas) produseer 2 mol/volumes (gas)./Die reaksie wat die
              kleiner getal mol /volume vorm, word bevoordeel.
          •   Voorwaartse reaksie word bevoordeel.                                                   (3)

7.4       OPTION 1/OPSIE 1
          Use x as the total initial amount of B(g) that must be used.
          Gebruik x as die totale aanvanklike hoeveelheid B(g) wat gebruik moet word.
                                                              A         B          C
                Initial quantity (mol)
                                                              3         x          0
                Aanvangshoeveelheid (mol)
                Change (mol)                                                              ratio 
                                                             -2        -4         +4
                Verandering (mol)                                                         verhouding
                Quantity at equilibrium (mol)/
                                                              1     x–4          4
                Hoeveelheid by ewewig (mol)
                Equilibrium concentration (mol∙dm-3)       1         x−4
                Ewewigskonsentrasie (mol∙dm-3)               = 0,2                0,8
                                                           5            5
                                [C] 2
                        KC =                                          Divide by/gedeel deur 5 
                              [ A ][B] 2
                               (0,8)2
               ∴ 0,625  =                    No KC expression, correct substitution/Geen Kc-
                                  x−4 2
                           (0,2)(     )
                                   5           uitdrukking, korrekte substitusie: Max./Maks. 8
                                                                                               9
                     ∴ x = 15,3 mol
                                               Wrong KC expression/Verkeerde Kc-uitdrukking:
                                               Max./Maks. 6
               ∴ n(B) added = 15,3 – 6                     9
                           = 9,3 (mol) 

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Physical Sciences P2/Fisiese Wetenskappe V2    8                                       DBE/November 2012
                                     NSC/NSS – Memorandum

          OPTION 2/OPSIE 2
          Use x as amount to be added to the amount of B(g) present initially i.e. 6 mol
          of B(g).
          Gebruik x as die hoeveelheid wat by die hoeveelheid van B(g) wat aanvanklik
          teenwoordig was gevoeg moet word d.i. 6 mol B(g).
                                                            A         B           C
                 Initial quantity (mol)                                           0
                                                            3      x+6
                 Aanvangshoeveelheid (mol)
                 Change (mol)                                                                ratio 
                                                            -2        -4          +4         verhouding
                 Verandering (mol)
                 Quantity at equilibrium (mol)/
                                                            1      x+2          4
                 Hoeveelheid by ewewig (mol)
                 Equilibrium concentration (mol∙dm-3)   1            x+2
                 Ewewigskonsentrasie (mol∙dm-3)           = 0,2                  0,8
                                                        5             5
                                   [C] 2
                          KC =              
                                 [ A ][B] 2                       Divide by/gedeel deur 5
                                                                  
                                  (0,8)2
                 ∴ 0,625  =               
                                     x+2 2
                              (0,2)(     )
                                      5
                         ∴x = 9,31 (mol) 

          OPTION 3/OPSIE 3
          Use x as amount to be added to the amount of B(g) present after first
          equilibrium was established i.e. 4 mol of B(g).
          Gebruik x as die hoeveelheid wat by die hoeveelheid van B(g) wat
          teenwoordig is nadat die eerste ewewig ingestel is, gevoeg moet word d.i. 4
          mol B(g).
                                                            A         B           C
                 Initial quantity (mol)
                                                            2      x+4           2
                 Aanvangshoeveelheid (mol)
                 Change (mol)                                                     +2       ratio 
                                                            -1        -2
                 Verandering (mol)                                                         verhouding
                 Quantity at equilibrium (mol)/
                                                            1      x+2          4
                 Hoeveelheid by ewewig (mol)
                 Equilibrium concentration (mol∙dm-3)   1            x+2
                 Ewewigskonsentrasie (mol∙dm-3)           = 0,2                  0,8
                                                        5             5
                                 [C] 2
                          KC =            
                               [ A ][B] 2                          Divide by /gedeel deur 5
                                          2
                                   (0,8)
                 ∴ 0,625  =                
                                      x+2 2
                               (0,2)(     )
                                       5
                         ∴ x = 9,31 (mol) 
                                                                                                    (9)
                                                                                                   [17]

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Physical Sciences P2/Fisiese Wetenskappe V2    9                                    DBE/November 2012
                                     NSC/NSS – Memorandum

QUESTION 8/VRAAG 8
8.1
8.1.1     Increases 
          The reaction is exothermic./Energy (or heat) is released /ΔH < 0.
          Vermeerder
          Die reaksie is eksotermies./Energie (of hitte) word vrygestel/ΔH < 0.                    (2)
8.1.2     Aluminium is a strong reducing agent/stronger reducing agent  than copper
          and will reduce the copper(II) ions to copper. 
          Aluminium is 'n sterk reduseermiddel / sterker reduseermiddel  as koper
          en sal die koper(II)-ione reduseer na koper.                                            (2)

8.1.3     2Aℓ(s) + 3Cu2+(aq)→ 2Aℓ3+(aq) + 3Cu(s)         bal.                                   (3)

8.2
8.2.1     Aℓ/Aluminium                                                                            (1)
                                               
8.2.2     Aℓ(s) | Aℓ3+(1 mol∙dm-3) || Cu2+(1 mol∙dm-3) | Cu(s)                                     (3)
8.2.3     Eo cell = Eo cathode – Eo anode 
                  = 0,34 - (-1, 66) 
           o
          E cell = 2,(00)V                                                                        (4)

8.2.4     0 (V)/zero/nul 
          The circuit is open. 
          Die stroombaan is oop                                                                  (2)
                                                                                                 [17]

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Physical Sciences P2/Fisiese Wetenskappe V2   10                                     DBE/November 2012
                                     NSC/NSS – Memorandum

QUESTION 9/VRAAG 9

9.1       Electrical energy to chemical energy. 
          Elektriese energie na chemiese energie                                                   (1)

9.2       The polarity of the electrodes must remain constant during plating. 
          Die polariteit van die elektrodes moet konstant bly tydens elektroplatering.              (1)

9.3       Reduction/Reduksie                                                                       (1)

9.4
9.4.1     Ag → Ag+ + e-                                                                           (2)

9.4.2     Silver nitrate/Silwernitraat/AgNO 3 

          OR/OF
          Silver ethanoate/silver acetate/Silweretanoaat/silwerasetaat 
          CH 3 COOAg/AgC 2 H 3 O 2 /AgCH 3 CO 2                                                     (1)

9.5       Rate of oxidation is equal to the rate of reduction. 
          Tempo van oksidasie is gelyk aan die tempo van reduksie.                                  (2)

9.6       Protection/Beskerming
          Protects it from rusting / corrosion./Beskerm dit teen roes/korrosie. 

          OR/OF
          Appearance/Voorkoms
          Improve appearance of spoons. / Verbeter voorkoms van die lepels.                         (1)

9.7       Cost of electricity/ Koste van elektrisiteit. 
          Cost of silver/ Koste van silwer                                                         (2)
                                                                                                   [11]

QUESTION 10/VRAAG 10

10.1      Primary (cells)/Primêre (selle)                                                          (1)

10.2      (Equation/Vergelyking) 2 
          Reduction takes place (at the cathode)./Reduksie vind (by die katode)
          plaas.                                                                                   (2)

10.3      ANY ONE/ENIGE EEN:
          • The cell reaction reaches equilibrium. 
            Die selreaksie bereik ewewig. 
          • The rates of the forward and reverse reactions become equal. 
            Die tempo van die voorwaartse en terugwaartse reaksies is gelyk. 
          • Substances reach their equilibrium concentrations. 
            Stowwe bereik hul ewewigskonsentrasies.
                                                                                                    (1)

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Physical Sciences P2/Fisiese Wetenskappe V2   11                                   DBE/November 2012
                                     NSC/NSS – Memorandum

10.4
10.4.1    W = qV 
          ∴ 3 x 104 = q(1,5) 
          ∴ q = 2 x 104 (C)
                                          2 × 10 4
          Cell capacity/Selkapasiteit =             = 5,56 A∙h 
                                           3600                                                (4)
10.4.2    OPTION 1 / OPSIE 1                       OPTION 2 / OPSIE 2
          q = I∆t                                 q = I∆t 
          ∴2 x 104 = I(20)(3600)                  ∴5,56 = I(20) 
          ∴I = 0,28 A                             ∴I = 0,28 A                                (3)
                                                                                              [11]

QUESTION 11/VRAAG 11

11.1
11.1.1    Fractional distillation (of liquid air) 
          Fraksionele distillasie (van vloeibare lug)                                         (1)

11.1.2    N 2 + 3H 2 ⇌ 2NH 3          bal.                                                  (3)

11.1.3    Contact (process)/Kontak(proses)                                                    (1)

11.1.4    H 2 SO 4 + 2NH 3 → (NH 4 ) 2 SO 4  bal.                                           (3)

11.1.5    Neutralisation/Acid-base reaction 
          Neutralisasie/Suur-basisreaksie                                                     (1)

11.2
11.2.1    Nitric acid/HNO 3 / hydrogen nitrate /salpetersuur/ waterstofnitraat                (1)

11.2.2    •   Contains (a high percentage of) nitrogen/N/primary nutrient. 
              Bevat ('n hoë persentasie) stikstof/N/primêre voedingstof.                       (2)
          •   High solubility /Hoë oplosbaarheid                                             [12]

                                             TOTAL SECTION B/TOTAAL AFDELING B:               125
                                                    GRAND TOTAL/GROOTTOTAAL:                  150

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- [Physical Sciences Physics Grade 12 PS01 QP March 2025 Limpopo](https://www.hlayiso.com/library/physical-sciences-physics-grade-12-ps01-qp-march-2025-limpopo/482ee9af-e88a-4818-9120-11ab9e045a1c) — QP · 2025
- [Physics Grade 12 NSC P1 QP September 2025 Limpopo](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-qp-september-2025-limpopo/b65e9832-a6be-4312-8f5a-57425d647121) — QP · 2025

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- [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers)

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