# Physical Sciences Grade 12 Paper 2 NSC November 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the NSC November Exam 2018, 18 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: NSC November Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 18

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Physical Sciences · Grade 12 · NSC November Exam · 2018. Memorandum, 18 pages. Read online or download the PDF.

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                                      NATIONAL
                                 SENIOR CERTIFICATE
                                     NASIONALE
                                 SENIOR SERTIFIKAAT

                                    GRADE/GRAAD 12

                      PHYSICAL SCIENCES: CHEMISTRY (P2)
                       FISIESE WETENSKAPPE: CHEMIE (V2)

                                        NOVEMBER 2018

                        MARKING GUIDELINE/NASIENRIGLYN

MARKS/PUNTE: 150

                      These marking guidelines consist of 18 pages.
                       Hierdie nasienriglyne bestaan uit 18 bladsye.

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Physical Sciences P2/Fisiese Wetenskappe V2   2                                DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 1/VRAAG 1

1.1      C                                                                                            (2)

1.2      C                                                                                            (2)

1.3      C                                                                                            (2)

1.4      A                                                                                            (2)

1.5      D                                                                                            (2)

1.6      B                                                                                            (2)

1.7      B                                                                                            (2)

1.8      D                                                                                            (2)

1.9      D                                                                                            (2)

1.10     B                                                                                             (2)
                                                                                                        [20]

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                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 2/VRAAG 2

2.1       ANY ONE/ENIGE EEN:
          • (Alcohol/ethanol) is flammable/catches fire easily. 
              (Alkohol/etanol) is vlambaar/slaan maklik aan die brand.
          • To heat it evenly./Om dit eweredig te verhit.
          • Water bath is used for low heat/low temperature./Waterbad word gebruik
              vir lae hitte/lae temperatuur.
          • Alcohol/ethanol will evaporate too quickly./(Alkohol/etanol) sal te vinnig
              verdamp.
          Accept/Aanvaar:
          (Alcohol/ethanol) is volatile./(Alkohol/etanol) is vlugtig.                                  (1)

2.2
2.2.1     Esterification/condensation 
          Verestering/esterifikasie/kondensasie                                                        (1)

2.2.2     H 2 SO 4                                                                                    (1)

2.2.3     Esters                                                                                      (1)

2.3        M(ester ) 144                     Marking guidelines/Nasienriglyne
                       =      =2             • If only answer given, award 2 marks on final
          M(C 4H8 O) 72 
                                                answer./Indien slegs antwoord gegee, ken 2
          ∴ 2 x C 4 H 8 O = C 8 H 16 O 2       punte toe vir finale antwoord.
                                             • If 72 g·mol-1 calculated without substituting,
                                                no mark is awarded./Indien 72 g·mol-1
                                                bereken is sonder om te vervang word geen
                                                punt toegeken nie.                                     (2)

2.4       Ethyl  hexanoate 
          Etielheksanoaat
          Note/Aantekening
          Accept any other ethyl ESTER from QUESTION 2.3.
          Aanvaar enige ander etiel ESTER vanaf VRAAG 2.3.                                             (2)

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Physical Sciences P2/Fisiese Wetenskappe V2   4                                  DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

2.5       POSITIVE MARKING FROM QUESTION 2.4.
          POSITIEWE NASIEN VANAF VRAAG 2.4.
              H    H  H    H  H    O        
          H      C     C    C     C     C     C     O     H         

                 H     H    H     H     H
          Marking criteria/Nasienriglyne
          • Whole structure correct/Hele struktuur korrek:                                2
                                                                                              2
          • Only functional group correct/Slegs funksionele groep korrek: Max/Maks.: 1
                                                                                           2
          • Accept/Aanvaar -OH as condensed/gekondenseerd.
          IF/INDIEN
          • More than one functional group/wrong functional group/Meer as een funksionele
              groep/foutiewe funksionele groep:                0
                                                             2
          • If condensed structural formulae used/Indien gekondenseerde struktuur-formules
            gebruik:                                       Max/Maks.: 1
                                                                        2                                (2)
                                                                                                        [10]

QUESTION 3/VRAAG 3

3.1       Marking guidelines/Nasienriglyne
          If any one of the underlined key phrases in the correct context is omitted, deduct 1
          mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
          trek 1 punt af.
         The temperature at which the vapour pressure of a substance equals
         atmospheric/external pressure.
         Die temperatuur waar die dampdruk van 'n stof gelyk is aan atmosferiese/
         eksterne druk.                                                                                 (2)

3.2
3.2.1     Carboxyl (group)/karboksiel(groep) 

          Accept/Aanvaar
          Carboxylic/Karboksiel                                                                         (1)

3.2.2     Propanoic acid/propanoësuur                                                                  (1)

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3.2.3           H            O                                         ACCEPT/AANVAAR
                                                                        (2 or/of 0)
          H     C     O      C     H 
                H                                                             O     H O
          Marking criteria/Nasienriglyne
          • Whole structure correct:                                   H      C          C       H 
              Hele struktuur korrek:                    2                    H
                                                            2
          • Only functional group correct:
              Slegs funksionele groep korrek: Max/Maks: 1                           O        H
                                                            2
          IF/INDIEN                                                    H      C      C       O    H 
           • More than one functional group/wrong functional
              group/Meer as een funksionele groep/foutiewe                   H
              funksionele groep:                            0
                                                                2
           • If condensed structural formulae used/Indien                    O    HO       H
              gekondenseerde struktuur-formules gebruik:                                         
                                                                       H     C       C       H
              Max/Maks: 1
                          2                                                                                   (2)

3.3       A
        - Lowest boiling point./Shortest chain length. 
          Laagste kookpunt./Kortste kettinglengte.                                                            (2)

3.4
3.4.1     The same molecular mass/molecular size. 
          Dieselfde molekulêre massa/molekulêre grootte.                                                      (1)

3.4.2     Primary/Primêre 
          -OH group is bonded to a C atom bonded to one other C atom. 
          -OH-groep is gebind aan 'n C-atoom wat aan een ander C-atoom gebind is.
          OR/OF
          -OH group is bonded to a C atom that has two H atoms.
          -OH-groep is gebind aan 'n C-atoom wat twee H-atome bevat.                                          (2)

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3.4.3     Marking guidelines/Nasienriglyne
          • BOTH have hydrogen bonding./BEIDE het waterstofbindings. 
          • Compare number of sites for hydrogen bonding./Vergelyk aantal punte vir
            waterstofbinding. 
          • Compare strength of IMFs./Vergelyk sterkte van IMKe. 
          • Compare energy required./Vergelyk energie benodig. 

          •   Both compounds/X and B have (in addition to London forces and dipole-
              dipole forces) hydrogen bonding./Beide verbindings/X en B het
              waterstofbindings (behalwe Londonkragte en dipool-dipoolkragte). 
          •   Compound X/CH 3 CH 2 CH 2 OH/propan-1-ol/alcohol has one site for
              hydrogen bonding and compound B/ethanoic acid/carboxylic acid has
              two/more sites for hydrogen bonding OR B/ethanoic acid/carboxylic acid
              has two/more sites for hydrogen bonding. 
              Verbinding X/CH 3 CH 2 CH 2 OH/propan-1-ol/alkohol het een punt vir
              waterstofbindings en verbinding B/etanoësuu/karboksielsuur het
              twee/meer punte vir waterstofbindings OF B/etanoësuu/karboksielsuur het
              twee/meer punte vir waterstofbindings.
          •   Intermolecular forces in compound B/ethanoic acid/carboxylic acid are
              stronger than intermolecular forces in compound X/CH 3 CH 2 CH 2 OH/
              propan-1-ol/alcohol. 
              Intermolekulêre kragte in verbinding B/etanoësuur/karboksielsuur is
              sterker as die intermolekulêre kragte in verbinding X/CH 3 CH 2 CH 2 OH/
              propan-1-ol/alkohol.
              OR/OF
              Intermolecular forces in compound X/CH 3 CH 2 CH 2 OH/ propan-1-
              ol/alcohol are weaker than intermolecular forces in compound B/ethanoic
              acid/carboxylic acid./Intermolekulêre kragte in verbinding
              X/CH 3 CH 2 CH 2 OH/propan-1-ol/alkohol is swakker as intermolekulêre
              kragte in verbinding B/etanoësuur/karboksielsuur.
          •   More energy is needed to overcome/break intermolecular forces in
              compound B/ethanoic acid/carboxylic acid than in compound
              X/CH 3 CH 2 CH 2 OH/ propan-1-ol/alcohol. 
              Meer energie word benodig om intermolekulêre kragte in verbinding
              B/etanoësuur as in verbinding X/CH 3 CH 2 CH 2 OH/ propan-1-ol/alkohol te
              oorkom/breek.
              OR/OF
              Less energy is needed to overcome/break intermolecular forces in
              compound X/CH 3 CH 2 CH 2 OH/propan-1-ol/alcohol than in compound
              B/ethanoic acid/carboxylic acid.
              Minder energie word benodig om intermolekulêre kragte in verbinding X/
              CH 3 CH 2 CH 2 OH/propan-1-ol/alkohol te oorkom/breek as in verbinding
              B/etanoësuur/karboksielsuur.                                                             (4)
                                                                                                      [15]

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                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 4/VRAAG 4

4.1
4.1.1     (A series of organic) compounds that can be described by the same general
          formula/functional group.  (2 or 0)
          ('n Reeks organiese) verbindings wat deur dieselfde algemene formule/
          funksionele groep beskryf kan word. (2 of 0)
          OR/OF
          (A series of organic) compounds in which one member differs from the next
          by a CH 2 group./('n Reeks organiese) verbindings waarin een lid van die
          volgende verskil met 'n CH 2 -groep. (2 or/of 0)                                             (2)

4.1.2    Substitution/halogenation/bromination 
         Substitusie/halogenasie/halogenering/brominasie/brominering                                   (1)

4.1.3    HBr                                                                                          (1)

4.1.4                                              Marking criteria/Nasienriglyne
              Br       H   H    H
                                                   • Br on first C atom/Br op eerste C-
        H     C        C   C    C       H               atoom: Max/Maks: 1
                                                                               2
                                                    • Whole structure correct/Hele struktuur
              H        H   H    H                       korrek: 2
                                                                     2
                                                    IF/INDIEN:
                                                    Br 2 but rest of structure correct/Br 2 maar
                                                    res van struktuur korrek: 1
                                                                                    2                  (2)

4.1.5    C 5 H 12 + 8O 2   5CO 2 + 6H 2 O         Bal 

         Marking guidelines/Nasienriglyne
         •   Reactants         Products         Balancing 
             Reaktanse          Produkte          Balansering
         •   Ignore double arrows and phases./Ignoreer dubbelpyle en fases.
         •   Marking rule 6.3.10/Nasienreël 6.3.10.
         •   If condensed structural formulae used/Indien gekondenseerde struktuur-
             formules gebruik:                Max/Maks: 2
                                                           3                                           (3)

4.1.6     Marking guidelines/Nasienriglyne
          If any one of the underlined key phrases in the correct context is omitted, deduct 1
          mark./Indien enige van die onderstreepte frases in die korrekte konteks uitgelaat is,
          trek 1 punt af.
          The (chemical) process in which longer chain hydrocarbons/longer chain
          alkanes are broken down to shorter/more useful hydrocarbons/molecules/
          chains/alkanes and alkenes.
          Die (chemiese) proses waarin langketting koolwaterstowwe/langketting-
          alkane afgebreek word in korter/meer bruikbare koolwaterstowwe/molekule/
          kettings/alkane en alkene.                                                                   (2)

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4.1.7          H    H     H      H               Marking guidelines/Nasienriglyne
                                               • One or more H atoms omitted/Een of
         H     C    C     C     C       H           meer H-atome uitgelaat:       Max/Maks: 1
                                                                                                     2
                                                  • Condensed or semi-structural formula:
               H     H     H    H
                                                    Gekondenseerde of semi-struktuur-
                                                    formule:                      Max/Maks: 1
                                                                                                         2   (2)

4.2
4.2.1     Butan-2-ol  OR/OF 2-butanol            IF/INDIEN:
                                                     Butanol or/of butan-1-ol            1
                                                                                             2               (2)

4.2.2          H          H     H           Marking criteria/Nasienriglyne
                                            • Only functional group correct/Slegs
          H    C     C     C     C      H      funksionele groep korrek:         Max/Maks: 1
                                                                                                     2
               H     H           H           • Whole structure correct:
                                               Hele struktuur korrek:                            2
                                                                                                     2        (2)
                                                                                                             [17]

QUESTION 5/VRAAG 5

5.1       Temperature/Temperatuur                                                                           (1)

5. 2      NOTE/LET WEL
          Give the mark for per unit time only if in context of reaction rate.
          Gee die punt vir per eenheidtyd slegs indien in konteks met reaksietempo.
          ANY ONE/ENIGE EEN
          • Change in concentration  of products/reactants per (unit) time. 
            Verandering in konsentrasie van produkte/reaktanse per (eenheid) tyd.

          •   Change in amount/number of moles/volume/mass of products or reactants
              per (unit) time.
              Verandering in hoeveelheid/getal mol/volume/massa van produkte of
              reaktanse per (eenheid) tyd.
          •   Amount/number of moles/volume/mass of products formed/reactants used
              per (unit) time.
              Hoeveelheid/getal mol/volume/massa van produkte gevorm/reaktanse
              gebruik per (eenheid) tyd.

          •   Rate of change in concentration/amount/number of moles/volume/mass.
              Tempo van verandering in konsentrasie/ hoeveelheid/getal mol/
              volume/massa.  (2 or/of 0)                                                                   (2)

5.3       14 (min)                                                                                         (2)

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5.4
5.4.1                   B
        - Graph/grafiek
          (Experiment 3) has the highest (acid) concentration/more particles/higher
          number of moles. 
          (Eksperiment 3) het die hoogste (suur)konsentrasie/meer deeltjies/groter
          aantal mol.                                                                                     (2)

5.4.2                     C
        - (Graph/grafiek)
          (Experiment 5) is at highest temperature/more particles with sufficient kinetic
          energy/HCℓ is at 35oC 
          (Eksperiment 5) is by die hoogste temperatuur/meer deeltjies met genoeg
          kinetiese energie/HCℓ is by 35oC.                                                               (2)

5.5
5.5.1     Speeds up the reaction./Increases the reaction rate./Provides alternate
          pathway./Lowers the (net) activation energy. 
          Versnel die reaksie./Verhoog die reaksietempo./Verskaf alternatiewe
          roete./Verlaag die (netto) aktiveringsenergie.                                                  (1)

5.5.2     Equal to/Gelyk aan                                                                             (1)

5.6                m                                  Marking guidelines/Nasienriglyne
          n( Zn) =                                    • Substitute/vervang 65 g∙mol-1 in
                   M
                   1,5                                      m
                                                        n= 
                 =                                          M
                   65 
                                                      • Substitute change in mol to calculate
                 = 0,023 mol
                                                        rate./Vervang verandering in mol om
                         ∆n                             tempo te bereken. 
          rate/tempo = −
                          ∆t                         • Substitute change in time to calculate
                          0 - 0,023                     rate./Vervang verandering in tyd om
                     =-(            )                   tempo te bereken. 
                           14- 0
                                                      • Final answer/Finale antwoord:
                     = 1,65 x 10-3 (mol·min-1)
                                                        1,65 x 10-3 mol∙min-1 
                                                       Range/Gebied:
                                                        1,43 x 10-3 to/tot 1,65 x 10-3 (mol∙min-1)
          Notes/Aantekeninge
          • Ignore if zeros omitted in calculation of reaction rate./Ignoreer indien nulle uitgelaat
            in berekening van reaksietempo.
          • Accept negative answer i.e. -1,65 x 10-3 mol·min-1/Aanvaar negatiewe antwoord
            d.i. -1,65 x 10-3 mol·min-1.                                                                   (4)
                                                                                                          [15]

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QUESTION 6/VRAAG 6

6.1         When the equilibrium in a closed system is disturbed, the system will re-
            instate a (new) equilibrium  by favouring the reaction that will cancel/oppose
            the disturbance. 
            Wanneer die ewewig in 'n geslote sisteem versteur word, sal die sisteem 'n
            (nuwe) ewewig instel deur die reaksie te bevoordeel wat die versteuring
            kanselleer/teenwerk.                                                                      (2)

6.2         Endothermic/Endotermies 
        -
            •   Decrease in temperature favours the exothermic reaction. 
                Afname in temperatuur bevoordeel die eksotermiese reaksie.
            •   The reverse reaction is favoured./Die terugwaartse reaksie word
                bevoordeel. 
                OR/OF
                Number of moles/amount/concentration of N 2 O 4 /colourless gas increases.
                Aantal mol/hoeveelheid/konsentrasie van N 2 O 4 /kleurlose gas neem toe.
                OR/OF
                Number of moles/amount of NO 2 /brown gas decreases./Aantal mol/
                hoeveelheid NO 2 /bruin gas neem af.                                                  (3)

6.3
6.3.1       Increases/Verhoog                                                                        (1)

6.3.2       Remains the same/Bly dieselfde                                                           (1)

6.3.3       Increases/Verhoog                                                                        (1)

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                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

6.4      CALCULATIONS USING NUMBER OF MOLES
         BEREKENINGE WAT GETAL MOL GEBRUIK
         Marking guidelines/Nasienriglyne
         • ∆n(N 2 O 4 ) = 20% of/van x/0,2x. 
         • USE ratio/GEBRUIK verhouding: N 2 O 4 : NO 2 : = 1 : 2. 
         • n(N 2 O 4 ) eq/ewe = n(N 2 O 4 ) initial/begin - ∆n(N 2 O 4 ).
             n(NO 2 ) eq/ewe = n(NO 2 ) initial/begin + ∆n(NO 2 ).
                                                                          
         • Divide equilibrium moles by 2 dm3/Deel ewewigsmol deur 2 dm3. 
         • Correct K c expression (formulae in square brackets). 
             Korrekte K c uitdrukking (formules in vierkanthakies).
         •  Substitution of K c value/Vervanging van K c -waarde. 
         • Substitution of concentrations into correct K c expression. 
             Vervanging van konsentrasies in korrekte K c -uitdrukking.
         •   Final answer/Finale antwoord: 1,6 (mol) 
          OPTION 1/OPSIE 1

                                                            N2O4             NO 2
           Initial amount (moles)                             x                0
           Aanvangshoeveelheid (mol)
           Change in amount (moles)
                                                           0,2x             0,4x        ratio 
           Verandering in hoeveelheid (mol)                                              verhouding
           Equilibrium amount (moles)                       0,8x             0,4x        
           hoeveelheid (mol)
           Equilibrium concentration (mol∙dm-3)                                          Divide by
                                                            0,4x             0,2x
           Ewewigskonsentrasie (mol∙dm-3)                                                2 dm3 

               [NO 2 ] 2                     No Kc expression, correct substitution/Geen Kc-
          Kc =                              uitdrukking, korrekte substitusie: Max./Maks. 7
               [N2 O 4 ]                                                                     8
                          2
                   (0,2x )                   Wrong Kc expression/Verkeerde Kc-uitdrukking:
           0,16 =          
                    (0,4x )                  Max./Maks. 5
                                                          8
              x = 1,6 (mol )
          OPTION 2/OPSIE 2
                          20
          ∆n(N 2 O 4 ) =     x  = 0,2x
                         100
          ∆n(NO 2 ) = 2∆n(N 2 O 4 ) = 0,4 x 
          n(N 2 O 4 ) eq/ewe = x – 0,2x = 0,8x AND n(NO 2 ) eq/ewe = 0 + 0,4x 
                                0,8x
          c(N 2 O 4 ) eq/ewe =       = 0,4x
                                  2           
                               0,4x
          c(NO 2 ) eq/ewe =          = 0,2x
                                 2
                 [NO 2 ] 2                   No Kc expression, correct substitution/Geen Kc-
          Kc =                              uitdrukking, korrekte substitusie: Max./Maks. 7
                 [N2 O 4 ]                                                                   8
                   (0,2x )2
                                            Wrong Kc expression/Verkeerde Kc-uitdrukking:
           0,16 =           
                    (0,4 x )                Max./Maks. 5
                                                         8
              x = 1,6 (mol )
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Physical Sciences P2/Fisiese Wetenskappe V2   12                               DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

         CALCULATIONS USING CONCENTRATION
         BEREKENINGE WAT KONSENTRASIE GEBRUIK
         Marking guidelines/Nasienriglyne
         • Initial n(N 2 O 4 )/x divide by 2 dm3. 
             Aanvanklike n(N 2 O 4 )/x gedeel deur 2 dm3.
         • ∆c(N 2 O 4 ) = 20% of initial concentration/0,1x. 
         • USE ratio/GEBRUIK verhouding: c(N 2 O 4 ) : c(NO 2 ) = 1 : 2. 
         • c(N 2 O 4 ) eq/ewe = c(N 2 O 4 ) initial/begin - ∆c(N 2 O 4 ).
            c(NO 2 ) eq/ewe = c(NO 2 ) initial/begin + ∆c(NO 2 ).         
         • Correct K c expression (formulae in square brackets). 
             Korrekte K c uitdrukking (formules in vierkanthakies).
         •  Substitution of K c value/Vervanging van K c -waarde. 
         • Substitution of concentrations into K c expression. 
             Vervanging van konsentrasies in K c -uitdrukking.
         •   Final answer/Finale antwoord: 1,6 (mol) 
         OPTION 3/OPSIE 3

                                                        N2O4           NO 2
          Initial concentration (mol∙dm-3)             x
                                                         = 0,5x          0      Divide by 2 dm3 
          Aanvanklike konsentrasie (mol∙dm-3)          2
          Change (mol∙dm-3)                                                       ratio 
                                                         0,1x         0,2x       verhouding
          Verandering (mol∙dm-3)
          Equilibrium concentration (mol∙dm-3)
                                                         0,4x          0,2x     
          Ewewigskonsentrasie (mol∙dm-3)

                                              No Kc expression, correct substitution/Geen Kc-
              [NO 2 ] 2
         Kc =                                uitdrukking, korrekte substitusie: Max./Maks. 6
              [N2 O 4 ]                                                                        8
                    (0,2x ) 2                 Wrong Kc expression/Verkeerde Kc-uitdrukking:
         0,16  =             
                     0,4x                     Max./Maks. 5
                                                           8
              x = 1,6 (mol )                                                                          (8)
                                                                                                      [16]

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Physical Sciences P2/Fisiese Wetenskappe V2   13                               DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 7/VRAAG 7
7.1
7.1.1    An acid is a proton donor. 
         'n Suur is 'n protondonor/skenker.                                                           (2)
7.1.2    H2O                                                                                         (1)
7.1.3    HSO −4                                                                                     (2)
7.2
7.2.1     Reaction of a salt with water/H 2 O. 
          Reaksie van 'n sout met water/H 2 O.

          Accept/Aanvaar
          Reaction of cations or anions with water
          Reaksie van katione of anione met water                                                     (2)
7.2.2     •   CO 32− (aq) + 2H 2 O(ℓ)  ⇌ H 2 CO 3 (aq) + 2OH − (aq) 
              OR/OF
              CO 32− (aq) + H 2 O(ℓ) ⇌ HCO 3− (aq) + OH − (aq)
              Accept/Aanvaar:
              Ca CO 3 (aq) + 2H 2 O(ℓ) ⇌ H 2 CO 3 (aq) + Ca(OH) 2 (aq)
          •   The formation of OH − (aq) neutralises the excess acid. 
              Die vorming van OH − (aq) neutraliseer die oormaat suur.
          Marking guidelines/Nasienriglyne
          •   Reactants          Products 
              Reaktanse           Produkte
          •   The formation of OH − (aq) neutralises the excess acid. 
              Die vorming van OH − (aq) neutraliseer die oormaat suur.
          •   Ignore single arrows and phases./Ignoreer enkelpyle en fases.
          •   Marking rule 6.3.10/Nasienreël 6.3.10.
          •   Ignore balancing./Ignoreer balansering.                                                 (3)

7.3
7.3.1    pH = -log[H 3 O+] 
         5  = -log[H 3 O+]
         [H 3 O+] = 1 x 10-5 mol·dm-3                                                                (3)

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Physical Sciences P2/Fisiese Wetenskappe V2   14                                 DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

7.3.2    POSITIVE MARKING FROM QUESTION 7.3.1.
         POSITIEWE NASIEN VAN VRAAG 7.3.1.
         Marking guidelines/Nasienriglyne
                                         n     m c a × Va  n       m
         • Any formula/Enige formule: c = /n =  /         = a /c =    
                                         V     M c b × Vb  nb      MV
                                           9    3
          •   Substitute/vervang V = 4 x 10 dm 
          •   Calculate n a (reacted) = n a (initial) – n a (final) 
              Bereken n a (reageer) = n a (begin) – n a (finaal)
          •   Use/Gebruik n(CaO) : n(H 3 O+) = 1:2 
          •   Substitution of/Vervanging van 56 g∙mol-1 
          •   Final answer/Finale antwoord: m = 1,08 x 106 g to/tot 1,09 x 106 g 
          IF final answer is negative:/INDIEN finale antwoord negatief is Max/Maks: 6
                                                                                        7
         OPTION 1/OPSIE 1                           OPTION 2/OPSIE 2
                                n                                    n
         c(H 3 O+) ini/aanv. =                     c(H 3 O+) fin =     
                                V                                    V
                           n                                        1,26 × 10 3
         1 x 10-5 =                                               =
                        4 × 10 9                                     4 × 10 9 
         n a = 4 x 104 mol                                        = 3,15 x 10-7 mol∙dm-3

         n(H 3 O+) react/rea                        c(H 3 O+) rea = 1 x 10-5 – 3,15 x 10-7 
                      = 4 x 104 – 1,26 x 103                    = 9,69 x 10-6 mol∙dm-3
                      = 3,87 x 104 mol
                                                    n(H 3 O+) rea = cV
         n(CaO) = ½n(H 3 O+)                                     = (9,65 x 10-6)(4 x 109)
                = ½ x 3,87 x 104                                = 3,87 x 104 mol
                = 1,94 x 104 mol                    n(CaO) = ½n(H 3 O+)
                                                              = ½ x 3,87 x 104 
                                                              = 1,94 x 104 mol

                                         OR/OF
                          m                                  1 mol : 56 g 
              n(CaO) =
                          M
                           m                        1,94 x 104 mol : m
         1,94 x 104 =                               ∴ m = 1,09 x 106 g 
                          56
                ∴ m = 1,09 x 106 g 
         OPTION 3/OPSIE 3
                          n
         c(H 3 O+) fin =     
                          V
                         1,26 × 10 3
                       =
                           4 × 10 9 
                       = 3,15 x 10-7 mol∙dm-3

         c(H 3 O+) rea = 1 x 10-5 – 3,15 x 10-7 
                       = 9,69 x 10-6 mol∙dm-3
         c(CaO) = ½c(H 3 O+)  = 4,845 x 10-6 mol∙dm-3
                m                              m
         c =           ∴ 4,845 x 10-6 =               ∴ m = 1,09 x 106 g 
               MV                       56( 4 × 10 )
                                                   9
                                                                                                         (7)
                                                                                                        [20]
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Physical Sciences P2/Fisiese Wetenskappe V2   15                                DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 8/VRAAG 8

8.1
8.1.1     Loss of electrons./Verlies aan elektrone.  (2 or/of 0)                                     (2)

8.1.2     Fe → Fe3+ + 3e- 
          Marking guidelines/Nasienriglyne
          • Fe ⇌ Fe3+ + 3e-       1              Fe3+ + 3e- ⇌ Fe      0
                                   2                                    2
                3+    --
            Fe + 3e ← Fe          2                 3+    -
                                                 Fe + 3e → Fe         0
                                    2                                   2
          • Ignore if charge omitted on electron./Ignoreer indien lading weggelaat op elektron.
          • If charge (+) omitted on Fe3+/Indien lading (+) weggelaat op Fe3+:
            Example/Voorbeeld: Fe → Fe3 + 3e-                              Max./Maks: 1
                                                                                           2           (2)

8.1.3     Reducing agent/Reduseermiddel                                                               (1)

8.1.4     Fe is a stronger reducing agent  than Cu  and (Fe) will be oxidised 
          (to Fe3+)./Fe is 'n sterker reduseermiddel as Cu en (Fe) sal geoksideer word
          (na Fe3+).

          OR/OF
          Cu is a weaker reducing agent  than Fe and (Cu) will not be oxidised 
          (to Cu2+)./Cu is 'n swakker reduseermiddel as Fe en (Cu) sal nie geoksideer
          word nie (na Cu2+).                                                                          (3)

8.1.5
        - Zinc/Zn 
          Stronger reducing agent (than Fe)./Sterker reduseermiddel (as Fe). 

          OR/OF
          Zn will undergo oxidation (before Fe)./Zn sal oksidasie (voor Fe) ondergaan.

          OR/OF
          Cu is a weaker reducing agent (than Fe)./Cu is 'n swakker reduseermiddel
          (as Fe).                                                                                     (2)

8.2
8.2.1     3Cu2+ + 2Fe  → 3Cu + 2Fe3+              Bal. 
          Marking guidelines/Nasienriglyne
          •   Reactants         Products         Balancing 
              Reaktanse          Produkte          Balansering
          •   Ignore double arrows./Ignoreer dubbelpyle.
          •   Marking rule 6.3.10/Nasienreël 6.3.10.                                                   (3)

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Physical Sciences P2/Fisiese Wetenskappe V2   16                                       DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

8.2.2     OPTION 1/OPSIE 1                       Notes/Aantekeninge
            θ
          E cell     θ
                 = E reduction     θ
                               − E oxidation    • Accept any other correct formula from the data
                                                   sheet./Aanvaar enige ander korrekte formule
                 = 0,34  – (-0,06)               vanaf gegewensblad.
                 = 0,40 V                       • Any other formula using unconventional
                                                   abbreviations, e.g. E° cell = E° OA - E° RA followed
                                                   by correct substitutions:/Enige ander formule wat
                                                   onkonvensionele afkortings gebruik bv.
                                                   E° sel = E° OM - E° RM gevolg deur korrekte
                                                   vervangings : 3
                                                                     4
          OPTION 2/OPSIE 2
          Cu2+ + 2e- → Cu                       E θ = 0,34 V 
          Fe → Fe3+ + 3e-                        E θ = 0,06 V 
          3Cu2+ + 2Fe → 3Cu + 2Fe3+              E θ = +0,40 V                                               (4)
                                                                                                             [17]

QUESTION 9/VRAAG 9

9.1      A cell in which electrical energy is converted to chemical energy.  (2 or 0)
         'n Sel waarin elektriese energie omgeskakel word na chemiese energie.
         (2 of 0)

         OR/OF
         A cell in which electrical energy/electricity is used to obtain a chemical
         change/reaction. (2 or 0)
         'n Sel waarin elektriese energie/elektrisiteit gebruik word om 'n chemiese
         verandering/reaksie te veroorsaak. (2 of 0)                                                         (2)

9.2      Any soluble copper(II) salt e.g./Enige oplosbare koper(II)-sout bv.
         CuSO 4 /Cu(NO 3 ) 2 /CuCℓ 2                                                                        (1)

9.3       B
          Cu2+ + 2e- → Cu 
          Marking guidelines/Nasienriglyne
          • Cu ← Cu2+ + 2e-        (2 )                    Cu ⇌ Cu2+ + 2e- ( 0 )
                                       2                                        2
                  2+
              Cu + 2e ⇌ Cu-
                                     ( 1   )                       2+
                                                           Cu → Cu + 2e   -
                                                                             ( 0   )
                                         2                                       2
          •   Ignore if charge on electron is omitted./Ignoreer indien lading op elektron
              uitgelaat is.
                                                      2      -
          •   If a charge of an ion is omitted e.g. Cu + 2e → Cu /Indien lading op ioon
                                                     Max./Maks: 1
                                 2     -
              uitgelaat is bv. Cu + 2e → Cu                                                                  (3)
                                                                 2

9.4      Platinum/Pt  AND/EN silver/Ag/silwer                                                              (2)
                                                                                                             [8]

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Physical Sciences P2/Fisiese Wetenskappe V2   17                                 DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

QUESTION 10/VRAAG 10

10.1
10.1.1    Haber (process)/Haber(proses)                                                                (1)

10.1.2    Ostwald (process)/Ostwald(proses)                                                            (1)

10.2
10.2.1    Ammonium nitrate/Ammoniumnitraat/NH 4 NO 3                                                   (1)

10.2.2    Iron/iron oxide/Fe/FeO 
          Yster/ysteroksied/Fe/FeO                                                                      (1)

10.3      2NH 3   + H 2 SO 4  → (NH 4 ) 2 SO 4      Bal 
                                                                                                        (3)
         Marking guidelines/Nasienriglyne
         • Reactants           Products          Balancing 
           Reaktanse            Produkte           Balansering
         • Ignore double arrows./Ignoreer dubbelpyle.
         • Marking rule 6.3.10./Nasienreël 6.3.10.

10.4      Marking guidelines/Nasienriglyne
          • Any ONE molar mass correct/Enige EEN molêre massa korrek:
            80 g∙mol-1/164 g∙mol-1/74,5 g∙mol-1 
          • m(N) = 7 (kg) OR/OF 0,14 
          • m(P) = 2,27 (kg) OR/OF 0,045 
          • m(K) = 9,42 (kg) OR/OF 0,188 
          • Final answer/Finale antwoord: 3 : 1 : 4 
            ACCEPT/AANVAAR: 3,08 : 1 : 4,15 OR/OF 7 : 2,27 : 9,42
          OPTION 1/OPSIE 1                          OPTION 2/OPSIE 2
          NH 4 NO 3 :                                                m
                                                    n(NH 4 NO 3 ) =
          80 g → 28 g N                                             M
                      28                                            20 000
          20 kg →        x 20                                    =          = 250 mol
                      80                                              80 
          ∴ m(N) = 7 kg                            n(N) = 2n(NH 4 NO 3 ) = 500 mol
          Na 3 PO 4 :                               m(N) = 500 x 14
          164 g → 31 g P                                 = 7 000 g = 7 kg 
                       31
          12 kg →         x 12                                   12 000
                      164                           n(Na 3 PO 4 ) =      = 73,17 mol
                                                                   164
          ∴ m(P) = 2,27 kg 
                                                    m(P) = 73,17 x 31
          KCℓ:                                           = 2 268 g = 2,27 kg 
          74,5 g → 39 g K
                                                               18 000
                      39                            n(KCℓ) =          = 241,61 mol
          18 kg →         x 18                                  74,5
                     74,5
          ∴ m(K) = 9,42 kg                         m(K) = 241,61 x 39
                                                         = 9 423 g = 9,42 kg 
          ∴ N : P : K
                                                    ∴ N : P : K
            7 : 2,27 : 9,42
                                                      7 : 2,27 : 9,42
            3 : 1 : 4 
                                                       3 : 1 : 4 

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Physical Sciences P2/Fisiese Wetenskappe V2   18                              DBE/November 2018
                       NSC/NSS – NSC/NSS – Marking Guidelines/Nasienriglyne

          OPTION 3/OPSIE 3                         OPTION 4/OPSIE 4
                             28                    NH 4 NO 3 :
          NH 4 NO 3 : %N =       x 100 = 35%
                             80                           28
                                                   %N =         x 100 = 35%
                     35                                    80 
          m(N) =         × 20 = 7 kg              Na 3 PO 4 :
                   100
          Na 3 PO 4 :                                       31
                                                   %P =         x 100 = 18,9%
                  31                                      164
          %P =          x 100 = 18,9%              KCℓ:
                 164
                   18,9                                     39
          m(N) =         × 12 = 2,27 kg           %K =          x 100 = 52,34%
                   100                                     74,5
          KCℓ:                                          20
                                                   N:       x 35 = 0,14 
                  39                                    50
          %K =          x 100 = 52,34%
                 74,5                                 12
                                                   P:      x 18,9 = 0,045 
                   52,34                              50
          m(K) =           × 18 = 9,42 kg 
                     100                              18
                                                   K:      x 52,34 = 0,188 
          ∴ N : P : K = 7 : 2,27 : 9,42               50
                            =3: 1 :4              N : P : K = 0,14 : 0,045 : 0,188
                                                                = 3 : 1 :4                        (5)
                                                                                                  [12]

                                                                          TOTAL/TOTAAL:           150

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