# Physical Sciences Grade 12 P1 Eastern Cape Prelim 2024 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the Eastern Cape Prelim Exam 2024 (Sesotho), 18 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physical-sciences-sept-2024-p1-memo-sesotho/90c2d379-8662-4fcb-8902-c7604e37920b
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Language: Sesotho
- Document type: Memorandum
- Year: 2024
- Exam period: Eastern Cape Prelim Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 18

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## About this document

Physical Sciences · Grade 12 · Eastern Cape Prelim Exam · 2024 · sesotho. Memorandum, 18 pages. Read online or download the PDF.

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### Page 1

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                          NATIONAL
                     SENIOR CERTIFICATE

                                KEREITI 12

                          LOETSE 2024

                 FISIKALE SAENSESE P1
                TATAISO YA HO TSWAYA

MATSHWAO:     150

              Tataiso ena ya ho tswaya e na le maqephe a 18 .

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2               FISIKALE SAENSESE P1                                      (EC/LOETSE 2024)

DITATAISO KA HO PHATLALLA

1.   DIKHALEKULEISHENE

     1.1   Dimaraka di fanwa ha: fomulara            e   nepahetse,    substitution    e
           nepahetse,Karabo ya yuniti e nepahetse.

     1.2   Ha ho dimaraka tse tla fanwa ha fomulara e nepahetseng kapa fomulara e
           sebedisitsweng ka nepo, leha hona le disimpole tse ngata tse ka kenellang
           hantle.

     1.3   Ha phoso e etswa ha ho kenyeletswa fomulareng e nepahetseng,le moo ho
           kenyeletsang, ha hona fanwa ka dimaraka ho ya pele.

     1.4   Ha fomulara e sa fanwa, empa dikenyeletso di nepahetse, but all
           substitutions are correct, ngwana ya balang ha ana ho fuwa maraka.

     1.5   Ha ho na tingwa ngwana dimaraka ha dikekyeletso di siuwe moo
           khaltjhuleishene di nepahetseng/porinsipole e nepahetseng.

     1.6   Dimathemathikhale manipohuleishense le phetoho ya change of subject ya
           difomulara tse nepahetseng ha enke dimaraka, empa ha ngwa ya kolang a qala
           ka nfomulara e nepahetseng mme fetola subject of the formula hampe,
           dimaraka di tla fanwa bakeng sa fomulara le dikenyeletso tse nepahetseng.
           Maraka ya lenane le fosahetseng ha ena ho fanwa.

     1.7   Dimaraka di tla ajwa fela fomularang ha khaltjhuleishene e entswe, jwalo
           ka, dikenyeletso di entswe kapa manane a karabo a fanwe.

     1.8   Dimaraka di tla fanwa feela ha dikenyeletso tsa manane di kenyeleditswe
           fomulareng mme di sa thathamiswa pela khaltjhuleishene.

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(EC/LOETSE 2024)                         FISIKALE SAENSESE P1                              3

     1.9     Dikhaltjhuleishene kaofela, ha disa sepesifauwa potsong, di tlameha ho etswa
             ho detesimale tse pedi.

     1.10 Ha karabo ya ho qetela ya khaltjhuleishene e nepahetse, di maraca tse fleets
          ha di na fanwa the feela. Batswayi kamehla bat la etsa bonnete bah ore
          fomulara e nepahetseng/e tswanelehileng e ya sebediswa mme mesebetsi, le
          dikenyeletso, di nepahetse.

     1.11 Dipotso moo letoto la khaltjhuleishene di etswang(moghlala, potso ya sekete
          teyakeramo) ha ho hlokahale kamehla e latele tatatello. DIMARAKA TSE
          FELETSENG di tla fanwa ha karabo e nepahetse ho latela bothata. Empa,
          khalkhjuleishene e nnge fela e kekeng ya tlisa ngwana ngolang haufi le karabo
          ho feta data ya mathomo, ha ho palo ya dimaraka e tla fanwa..

2.   DIYUNITI

     2.1     Ngwana ngolang u tla tingwa hangwwe fela maraka ha phitile phoso ya
             tshebediso ya yuniti kahara potso.

     2.2     Diyuniti di hlokahala feela karabong ya ho qetela ya khaltjhuleishene..

     2.3     Dimaraka di fanwa ha feela Karabo, e seng bakeng sa yuniti, eseng yuniti ho
             tjho fela. Bana ba ngolang hlahlobo batla tingwa maraka e fanwang karabong
             ye nngwe le e nngwe ya maema a latelang:
             • Karabo e nepahetseng + ho fosahetse yuniti
             • Karabo e fosahetseng + yuniti e nepahetseng
             • Karabo e nepahetseng + yunit e siyo
             •

     2.4     Diyuniti tsa SI di tlameha ho sebediswa ntle ho maemong a itsen, mohlala.
             V.m-1 ho na le N.C-1, le cm•s-1 kapa km•h-1 ho na le m•s-1 moo potso e hlokang
             jwalo.

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4               FISIKALE SAENSESE P1                                          (EC/LOETSE 2024)

3.   KA HO PHATLALLA

     3.1     Ha Karabo kapa khaltjhuleishene e hlokahala, empa Karabo tse pedi di fanwe
             ke ngwana ya ngolang, Karabo ya pele fela ke yona e tla tswauwa, ho sa
             tsotellehe hore e nepahetse. Ha eba karabo tse pedi di hlokahala, karabo tse
             pedi feela tse qalang di tla tswauwa jwalo jwalo.

     3.2     Bakeng sa ho tswaya, disimpole tsekgetholohileng(s, u, t, etc.) di tla amoheleya.

     3.3     Kompounte e arohanengya diyuniti tsa malethiupolekjheishene dote, mohlala,
             m•s-1. Bakeng sa ho tswaya, m•s-1 le m/s di tla amoheleya.

4.   HO TSWAYA HO POSETIFO
     Motswao o Positifo ho latela dikhaltjhuleishene di tla latelwa maemong ana:

     4.1     Potswana le potswana: Ha fariabole e khaltjhuleituwe potsong (mohlala 3.1)
             e hloka ho kenyeletswa ho potswana (3.2 ya 3.3), dimaraka tse feletseng di
             fanwa bakeng sa potswana e latelang.

     4.2     Potso e nang le dipotswana tse ngata: Ha ngwana ya ngolang a khaltjhulata,
             mohlala, karente setep;eng sa pele mme a thola karabo e fosahetseng ka lebaka
             la kenyeletso e fosahetseng, maraka ya kenyeletso le ya ho qetela u tla tingwa
             dimaraka.

5.   HO TSHWAYA HO NEKETIFO
     Maemong a tlwaeleileng karabo e fosahetseng ha ena ho nepahala ha e latela phoso
     ya konsepote. Ha ngwana ya ngolang a hlokwa ho fana ka tshehetso POTSONG ya
     3.2 karabo e fanweng POTSONG YA 3.1 e fosahetse, ha ho dimaraka tse tla fanwa
     ho POTSO YA 3.2. Leha ho le jwalo, ha karabo mohlala, ya POTSO YA 3.1 e amana
     ka khaltjhuleishene, tshehetso ya karabo e fosahetseng e ka shejwa ka ihlo le leng.

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(EC/LOETSE 2024)                         FISIKALE SAENSESE P1              5

POTSO YA 1:                       DIPOTSO TSA KGETHO

1.1      B                                                             (2)

1.2      C                                                             (2)

1.3      C                                                             (2)

1.4      A                                                             (2)

1.5      B                                                             (2)

1.6      A                                                             (2)

1.7      D                                                             (2)

1.8      D                                                             (2)

1.9      B                                                             (2)

1.10     A                                                             (2)
                                                                        [20]

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6               FISIKALE SAENSESE P1                                         (EC/LOETSE 2024)

POTSO YA 2

2.1     Ha nete fose e etsahala nthong, ntho e tla akeselerata lehlakoreng la nete
        fose ka akeselereishene e amanang ka kotloloho le fose hape e sa
        amamneng ka kotloloho le boima ba ntho. 

                                         KAPA

        Nete fose/resaletente fose e etsahalang ho ntho e lekana le nako eo
        momentamo u fetofetohang ka ona. 
                                                                                        (2)

2.2
        Labele tse amohelehang
         w    Fg/Fw/weyiti/kerafitheishinale fose           
         T    FT/Thensene/Fosee e khwgeleng                 
         N    FN/N/Nomale Fose                              
         Fk   fk/Fose e mahwashe force                      

                                                                                        (4)

2.3.1   fk = μkN 

        fk   = μkFg

        fk = (0,25)(4)(9,8) 

        fk   = 9,8 N                                                                   (3)

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 (EC/LOETSE 2024)                          FISIKALE SAENSESE P1                          7

2.3.2 KGETHO YA 1
      Fnet = ma
       Fnet = T – f         E nngwe ✓
       Fnet = Fg – T
       Boloko ba 4 kg
       T – 9,8 = 4a
       T = 4a + 9,8
                                       E nngwe(4a kapa / 2a) ✓
       Boloko ba 2 kg
       (2)(9,8) – T✓ =2a
       T = 19,6 – 2a
       19,6 – 2a = 4a + 9,8
       a = 1,63 m∙s-2
       vf2 = vi2 + 2aΔy 
       vf2 = 02 + 2(1,63)(1) 
       vf = 1,81 m∙s-1                                                               (7)

2.4    Kerafitheishenale fose (weyiti) ha se yona fela e etsahalang ho 2 kg
       boloko. 
                                          KAPA

       Akeselereishene ha se 9,8 m.s-2. 
                                                                                     (2)
                                                                                    [18]

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      8               FISIKALE SAENSESE P1                                         (EC/LOETSE 2024)

POTSO YA 3

3.1   Tlase                                                                                      (1)

3.2       Hodimo ke positifo                    Tlase ke posetifo
          vf = vi + a t                       vf = vi + a t 
             = 30  + (-9,8)(2,135)                = - 30 + (9,8)(2,135)
             = 9,08 m·s-1, hodimo                 = - 9,078 m·s-1
                                                   = 9,08 m·s-1, hodimo 
                                                                                                  (3)

3.3   KGETHO YA 1
       Hodimo ke positifo                       Tlase ke posetifo
       Bolo ya A:
        Δy = v i Δt + 21 at 2                  Δy = v i Δt + 21 at 2 
       ∆y = -12(2,5) + ½(-9,8)(2,5)2           ∆y = 12(2,5) + ½(9,8)(2,5)2 
       ∆y = - 60,625 m                          ∆y = 60,625 m
       (Bophahamo = 29,375 m)                   (Bophahamo = 29,375 m)
       Bolo ya B:                               Bolo ya B:
        Δy = v i Δt + 21 at 2                   Δy = v i Δt + 21 at 2
                                                                                                  ..
           = 30(2,5) + ½(-9,8)(2,5)2               = -30(2,5) + ½(9,8)(2,5)2 
           = 44,375 m                               = - 44,375 m
       Sebaka = 44,375 - 29,375                Sebaka = 44,375 – 29,375 
                    = 15 m                                             = 15 m 

      KGETHO YA 1

      Bolo ya A
      vf = vi + a t
      vf = -12 + (-9,8)(2,135)
      vf = 32,923 m·s-1, tlase
      Δy = v i Δt + 21 at 2 
      ∆y = -32(2,5-2,135) + ½(-9,8)(2,5-2,135)2 
      ∆y = - 12,6696 m
      Bolo ya B
      Δy = v i Δt + 21 at 2
      ∆y = 9,08(2,5 – 2,135) + ½(-9,8)(2,5 – 2,135)2
      ∆y = 2,66 m
      Sebaka = 2,66 + 12,6696 
      15,33 m 

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 (EC/LOETSE 2024)                         FISIKALE SAENSESE P1              9

3.4    KGETHO YA 1
       Hodimo ke positifo

       KGETHO YA 2
       Tlase ke posetifo

        Mokhwa wa ho tshwaya kerafo                   Dimaraka
        Sebopeho a bolo ya A ho zero position.
                                                          
        Sebopeho sa bolo ya B ho ya hodimo ho
        fihlela dilaene diteyana le nako. 2,135 s/        

        Nako ya 2,135 s e bontshitswe                     
        Fatshe ha se zero position (Ha ntho e
        nngwe le e nngwe e nepahetse): 2/3/
                                                                              (3)
                                                                             [12]

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10              FISIKALE SAENSESE P1                                  (EC/LOETSE 2024)

POTSO YA 4

4.1    Totale momentamo ✓o lineya ya aesolated sisitimi✓ e dula ele
       konsetente/konsefote.
                                                                                   (2)

4.2    Hlakore le letona ke positifo
       Σpi = Σpf
                                             E nngwe✓
       (mvi)1 + (mvi)2 = (mvf)1 + (mvf)2
       (5 000)(15) + (2 000)(-20 ✓ = (5 000)vf + (2 000)(5) ✓
       vi = 5 m·s-1✓
       Hlakore le letshehadi ke posetifo
       Σpi = Σpf
                                             E nngwe ✓
       (mvi)1 + (mvi)2 = (mvf)1 + (mvf)2
       (5 000)(-15) + (2 000)(20) ✓ = (5000)vf + ( 2000)(-5) ✓
       vi = -5 m·s-1
       Makenetjute ya felositi = 5 m∙s-1 ✓                                         (4)

4.3    KGETHO YA 1
       Fnet∆t = ∆p               E nngwe ✓
       Fnet Δt = mvf – mvi
       Fnet (0,4) ✓ = (5 000)(5) – (5 000)(15) ✓
       Fnet = -125 000 N
       Fnet = 125 000 N ho ya ho le letona ✓

       KGETHO YA 2
       Fnet∆t = ∆p
                                 E nngwe ✓
       Fnet Δt = mvf – mvi
       Fnet (0,4) ✓ = (2000)(-5) – (2000)(20) ✓
       Fnet = -125 000 N
       Fnet = 125 000 N ho ya ho le letona ✓                                      (4)
                                                                                 [10]

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(EC/LOETSE 2024)                             FISIKALE SAENSESE P1                      11

POTSO YA 5

5.1    Kamora monna                                                                  (1)

5.2    Newton’s third Law of motion
       Ha ntho e phusha fose ho ntho ya bobedi, ntho ya bobedi e phusha ka fose
       e lekanang ka makenetjute empa e ya kgahlanong malebana le ntho ya
       pele. 
                                                                                      (3)

5.3    KGETHO 1
       Wnet = ∆K
                                E nngwe✓
       Wg + Wf = ∆K
       Fg∆xcosӨ + f∆xcosӨ = ∆K
       (57)(9,8)(4)cos180°  + 40∆xcos180o = 0 – ½(57)(62) 
                                                   ∆x = - 30,21 m
                                                          4
                                               Sin Ө =
                                                         30,21

                                                    Ө = 7,61° 
       KGETHO YA 2
       Wnc = ΔU + ΔK / Wnc = ΔEp + ΔEk 
       40∆xcos180o  = (57)(9,8)(4) – (57)(9,8)(0)  + ½ (57)(0)2 – ½ (57)(6)2 
                 ∆x = -30,21 m
                                 4
                     Sin Ө =
                               30,21
                        Ө = 7,61°                                                    (5)

5.4    KGETHO YA 1
       Wnet = ∆K
                                        E nngwe ✓
       WT + Wg + Wf = ∆K
       (80)(5)(4)cos0° + (4)(9,8)sin30° •(5)cos180° + (15)(5)cos180° 
       = ½(4)vf2 – ½(4)(32) 
            vf     = 11,07 m·s-1 
       KGETHO YA 2
       Wnc = ΔU + ΔK
                                       E nngwe ✓
       WT + Wf = ΔU + ΔK

       (80)(5)(4)cos0° + (15)(5)cos180°  =
       (4)(9,8)(sin30°)(5) – (4)(9,8)(0)  + ½ (4)vf2 – ½ (4)(3)2 
       vf   = 11,07 m·s-1                                                           (6)
                                                                                    [15]

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 12               FISIKALE SAENSESE P1                               (EC/LOETSE 2024)

POTSO YA 6

6.1    Phetoho(e ka bang teng) ya forekwensi/pitjhi ya(modumo) wa weifo e
       utluwang ke modumo wa diweifo ha motsamo o bapiswang dipakeng tsa
       momamedi le sose e etsang modumo 
                                                                                (2)

       6.2.1 E ya eketseha                                                     (1)

       6.2.2 E ya fokotseha                                                    (1)
6.3         v  vL               v + vL
       fL =        f s  or fL =        𝑓𝑆 
            v  vs                 v

             330 + 30
       fL=               x 1 800 
             330 − 0

       fL = 1 963,6 Hz                                                         (5)

6.4

        Ma

        Dilabole tsa akesese                       

        Forekwensi e hodimo qalong                 

        Forekwensi e tlase ya nako e               
        eketsehang
                                                                                (3)

6.5    Bloodflow meter  / Doppler flow meter /
                                                                               (1)
                                                                              [13]

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(EC/LOETSE 2024)                          FISIKALE SAENSESE P1                      13

POTSO YA 7

7.1     Fose e hwehwelang kapa e phushang dipakeng tsa dithjatjhe tse pedi e
        amana ka kotloloho le tlhaiso ya makenetjute ya ditjhatjhe hape e ha e
        amane ka kotloloho le sebaka se dipakeng tsa stona.
                                                                                    (2)

7.2     Ka ha      FK on M = FG on M 
                   (Fnet)2 = (FK on M)2 + (FG on M)2
                    (2,864 x 10-6)2  = F2 + F2
                    F = 2,025 x 10-6 N                                             (4)

7.3     F = kQ1Q2 
               r2
        2,025 x 10-6       = 9 x 109 x 6 x 10-9 x 6 x 10-9 
                                         (X)2
        X   = 0,4 m                                                                (4)
                                                                                   [10]

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14                 FISIKALE SAENSESE P1                                (EC/LOETSE 2024)

POTSO YA 8

8.1

                                                                                  (3)
        Mokhwa wa ho tswaya
        Sebopeho se nepahetseng                      
        Lehlakore le nepahetseng                     
        Dilaene tse thetsanang le tse                
        fapanyetsanang

8.2    Eleketerosetatikese fose e etswang per unit posetifo tjhatje e beuweng
       ntlheng.
                                                                                  (2)

8.3    EP = kQ1 
              r2
       EP = 9 x 109 x 200 x 10-9 
                       (0,2)2
       EP = 45 000 N.C-1 ho ya ho le letona
       EQ = kQ2
             r2
       EQ = 9 x 109 x 200 x 10-9 
                         (0,4)2
       EQ = 11 250 N.C-1 ho ya ho le le tshehadi
       Enet = 45 000 + (-11 250) 
       Enet = 33 750 N.C-1 ho ya ho leletona                                    (5)
                                                                                [10]

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(EC/LOETSE 2024)                         FISIKALE SAENSESE P1                           15

POTSO YA 9

9.1     Ho netefatsa motsamao o potapotang wa khwele. 
                                                                                        (1)

9.2     (i) Repoleisa sose ya potenshiale diforense ka load/resisetara. 

        (ii) Repolaisa sepoliti reng (commutator) ka (tse pedi) selipo reng
                                                                                        (2)

9.3            I
        I rms = max 
                 2
                   0,54
        Irms =            
                   √2
        Irms = 0,38 A
        Pave = VrmsIrms 
        60 = Vrms x 0,38 
        Vrms = 157,89 V                                                                (5)
                                                                                        [8]

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 16                     FISIKALE SAENSESE P1                                   (EC/LOETSE 2024)

POTSO YA 10

10.1   Potensheale diforense e amana ka kotloloho le karente,ha motjheso u sa
       fetohe.
                                        KAPA
       Reshio ya potensheale diforense ho karente ha motjheso u sa fetohe.
                                                                                            (2)

10.2    KGETHO YA 1                            KGETHO YA 2
             V2                                P = VI 
        P =                                   IR = P/V = 13,5/18  = 0,75 A
             R
               (18)2                           V = IR
        13,5 =                                R = V/IR = 18/0,75 = 24 Ω 
                 R

        R = 24 Ω                                                                           (3)

10.3    KGETHO YA 1                            KGETHO YA 2
            V                                  1             1       1
        R =                                        =            +        
            I                                  Rp           𝑅1       R2
                                                1       1             1
                                                   =        +            
        24 = (18)                              RP       12           24
                                               RP = 8 Ω 
                    I                          V = IRP
                                               18 = I (8) 
        I = 0,75 A                             I = 2,25 A 
             Vp
        R=
             I12
                   18
        12 = I12
        I12 = 1,5 A 
        ITotal = 1,5 + 0,75 = 2,25 A                                                       (5)

10.4   Resisetense ya kahare e kgahlanong le ho phalla ha tjhaetjhe kahara betiri.
       
                                                                                            (2)

10.5   V10 = IR10 
       V10 = 2,25 x 10 
       V10 = 22,5 V                                                                        (3)

 Boqapi ba sengodi bo hlontjhwe                                                  Ka kopo phetla
                                  Hosted by www.ecexams.co.za.

### Page 17

Downloaded from hlayiso.com
 (EC/LOETSE 2024)                         FISIKALE SAENSESE P1                                         17

10.6   KGETHO1
       V1 = Vext
       V1 = VP + V10
       V1 = 18 + 22,5 
       V1 = 40,5 V
       Ha switjhi e butswe Emf = 45,9 V
       Folete tse lahlehileng ‘lost volts’ ke: Vlost = emf – Vext
                                                         = 45,9 – 40,5  = 5,4 V
          V
       r= L 
           I
              5,4
       r=         
             2,25

       r = 2,4 Ω 

       KGETHO YA 2
                                                           1            1        1
       Emf = I (R + r)                                         =            +
                                                           Rp           r1       r2
                                                            1       1                 1
       45,9 = (2,25) (8 + 10 + r)                             =            +            
                                                           RP       12               24
        r   = 2,4 Ω                                        RP = 8 Ω                                   (5)

10.7    E ya eketseha                                                                                  (1)
                                                                                                      [21]

 Boqapi ba sengoli bo hlontjhwe                                                               Ka kopo phetla
                                  Hosted by www.ecexams.co.za.

### Page 18

Downloaded from hlayiso.com
 18               FISIKALE SAENSESE P1                                           (EC/LOETSE 2024)

POTSO YA 11

11.1   c = f x λ
       Amohela v = f λ
       3 x 108 = f x 229 x 10-9
       f = 1,31 x 1015 Hz                                                                          (3)

11.2   Threshold forekwensi                                                                        (1)

11.3   Work function ya boleng bo bonyanyananyanyana ba eneji bo hlokahala ho ntsha
       eleketerone safeise e thata e fanweng, hangata ke tshepe.                                  (2)

11.4   E = Wo + Ek ( max ) 

       hf = Wo + ½ mv2

       6,63 x 10-34 x f  = (6,63 x 10-34 x 1,31 x 1015) + ½ (9,11 x 10-31) (1,57 x 106)2 
                        f = 3 x 1015 Hz                                                            (4)

11.5   E YA EKETSEHA 
       Ho fokotseha ha weifolenfo ho fana ka sephetho sa ho nyoloha ha forekwensi. 
       Work function e ya nyoloha. 
       KAPA
             1
       Wo ∝ λ                                                                                   (3)
              o
                                                                                                [13]

                                                                                  TOTALE: 150

 Boqapi ba sengodi bo hlontjhwe                                                    Ka kopo phetla
                               Hosted by www.ecexams.co.za.

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