# Physical Sciences Grade 12 Paper 1 Free State Mock 2025 Memo > Grade 12 Physical Sciences Paper 1 memorandum from the Free State Mock Exam 2025, 15 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/physics-grade-12-nsc-p1-memo-september-2025-free-state/164f1c1c-d7e5-48ba-aba9-2753c4b709c1 - Updated: 2026-09-27 - Subject: Physical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2025 - Exam period: Free State Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 15 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Physical Sciences](https://www.hlayiso.com/library/grade-12/physical-sciences) › [Physical Sciences Grade 12 Paper 1 Free State Mock 2025 Memo](https://www.hlayiso.com/library/physics-grade-12-nsc-p1-memo-september-2025-free-state/164f1c1c-d7e5-48ba-aba9-2753c4b709c1) ## About this document Physical Sciences · Grade 12 · Free State Mock Exam · 2025. Memorandum, 15 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 education Department of Education FREE STATE PROVINCE PREPARATORY EXAMINATION VOORBEREIDENDE EKSAMEN GRADE/GRAAD 12 PHYSICAL SCIENCES P1 (PHYSICS) FISIESE WETENSKAPPE V1 (FISIKA) SEPTEMBER 2025 MARKS/PUNTE: 150 MARKING GUIDELINE NASIENRIGLYNE These marking guidelines consist of 15 pages. Hierdie nasienriglyne bestaan uit 15 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 FS/VS/September 2025 QUESTION/VRAAG 1 11. Cvv 12 Cvv 13° Byy 14 Byy 15 Avv 16 Avv 17 Cvv 18 Dvv 19 Bvv 1.10 Byv (2x10) [20] QUESTION/VRAAG 2 2.1 22 Marking Criteria/Nasienkriteria: If any of the underlined keywords/phrases in the correct context are omitted, deduct 1 mark. Indien enige van die onderstreepte sieutelwoorde/frases in die korrekte konteks weggelaat word, trek 1 punt af. When a net force acts on an object, the object will accelerate in the direction of the force, and the acceleration is directly proportional to the force and inversely proportional to the mass of the object. vv Wanneer 'n netto krag op 'n voorwerp inwerk, sal die voorwerp in die rigting van die krag versnel, en die versnelling is direk eweredig aan die krag en omgekeerd eweredig aan die massa van die voorwerp. (2) WV Acceptable Labels/Aanvaarbare byskrifte T Fr/ Ftension/spanning/ Tension force/Spanningskrag Fg weight / w/ mg / Fgravitation/gravitasie Notes/Notas: e Mark is awarded for label and arrow./Punt word toegeken vir etiket en pyl. wi" e Donot penalise for the lengths of vectors./Moenie penaliseer vir die lengtes van vektore nie. e If arrows do not touch the dot/As pyle nie aan die kolletjie raak nie: Max/Maks (1/5) e Any additional force(s)/Enige bykomende krag(te): Max/Maks (4/5) e No arrows drawn with correct labels/Geen pyle geteken met korrekte byskrifte nie: Max/Maks (1/5) (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 FS/VS/September 2025 2.3 w=mgv = (73)(9,8) V =715,4NY (3) 2.4 POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 2.3 Marking Criteria/Nasienkriteria: e Any correct formula for/Enige korrekte formule vir Fret ¥ e Correct substitution for/Korrekte substitusie vir Fret =ma e Correct substitution for/Korrekte substitusie vir Ay = v,At+ Yat? v e Correct substitution/Korrekte substitusie Vv e Correct final answer/Korrekte finale antwoord Vv OPTION/OPSIE 1 OPTION/OPSIE 2 Positive upwards: Positive downwards: Positief opwaarts: Positief afwaarts: Fret = ma i Y anyonefenige een | Fnt=™MA | v any onelenige een T+w=ma T+w=ma 780 — 715.4=73av —780 + 715.4 = 73aV a= 0,885 ms? ; a= — 0,885 ms? i Ay = vat eat v Ay = viAt Néadt? v |34=0+4 (0,885) (At?) ¥ —34 = 0 + %4(—0,885) (At?) v | At=8,77s Vv At=8,77s¥ (5) 2.5 When the man is at rest/Wanneer die man in rus is: T1 = w ¥ When he is moving up/Wanneer hy op beweeg: T2 = w + ma keh” T is greater when accelerating upwards. ” T is groter as versnelling opwaarts is. (3) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 FS/VS/September 2025 QUESTION/VRAAG 3 3.1. An object that has been given an initial velocity and then moves under the influence of the gravitational force ONLY. YY (2 or/of 0) ‘n Voorwerp wat 'n aanvanklike snelheid gegee is, en dan onder die invioed van SLEGS gravitasiekrag beweeg. a8A Marking Criteria/Nasienkriteria: e Correct formula for/Korrekte formule vir Ay = vi|At + % aAt? v e Correct substitution into the formula v Korrekte substitusie in die formule e Correct final answer/Korrekte finale antwoord OPTION/OPSIE 1 OPTION/OPSIE 2 Positive downwards: Positive upwards: Positief afwaarts: Positief opwaarts: Ay = viAt+ % at? v Ay = v,At+ %adt? ¥ 12,5=0+%(98(Ar)Y | =12,5 = 0 + 4(-9.8)(At®) v At=1,597sv At= 1,597 s 7 Accept/Aanvaar At= 1,6s Accept/Aanvaar At= 1,6 s (2) 3.2.2 Marking Criteria/Nasienkriteria: e Formula for/Formule vir Ay = v,At + %adt? V e Correct substitution into formula for ball A ¥ Korrekte substitusie in formule vir bal A e Correct substitution into formula for ball B vv Korrekte substitusie in formule vir bal B e Aya = AygY e Correct final answer./Korrekte finale antwoord. V OPTION/OPSIE 1 Positive downwards/Positief afwaarts: Ball A/Bal A: Ay = v,At + Yaat? ¥ =O+FYOB8)(At2)Y | aceesseaseeeeeeeeeee eq.1 = 4,9At . any one/enige een Ball B/Bal B: Ay = viAt+ Yast? = (30)(t — DY + V¥(9.B)(C- 12M oeeeeeeeeceeceee eq. 2 =4,9AP + 20,2t- 25,1 Aya = Ayn” Aya = Ays™ 4,9? = 4,917 + 20,2t— 25,1 t= 1,24 sv (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 FS/VS/September 2025 OPTION/OPSIE 2 Positive upwards/Positief opwaarts: Ball/Bal A: Ay = viAt + Yat ¥ Ball/Bal B: Ay = viAt+ Yat? Aya = Aya” [ 4(-9,8)(at2) = (-30y(t — 1) + 4(-9,8)(t- 1)? —4,9t? = — 4,9t? — 20,2t+ 25,1 t=1,24s v Ay = 0+ %(-98)(At2)Y% eeeeeeeeeee eq. 1 Ay =(— 30)(t- DY +%(-9,8)(t- 12M ee eq. 2 OPTION/OPSIE 3 Positive downwards/Positief afwaarts: Ball/Bal A: Aya = ViAt + Yaat? ¥ Ball/Bal B: Ayg= viAt + Yat? Ayg =(30)(t)Y +¥(9,8)(t)2¥ —aeeeeeeeeetees Aya = AysY [veatHe=cot) +4one | At = 0,24 “. time/tyd = 1+ 0,24 =1+0,24sv Ay, =O+%(9,8)(t+ 12% aceeceeeeseveeseeees eq. 1 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 FS/VS/September 2025 OPTION/OPSIE 4 Positive upwards/Positief opwaarts: Ball/Bal A: Ay =viAt + Yaat? v Ay =O + %(-98)t+D2Y eee eq. 1 Ball B/Bal B: Ay = v\At + Yaat? Ay =(—30)(t)Y +(-9,8)(t)2Y —haaseeeeeeeseees eq. 2 Aya = AypY” ( %(-9,8)(t + 1)? =(-30)(t)Y + Y(—9,8)(t)? | At = 0,24 t=0,24sv (6) 3.23 Marking Criteria/Nasienkriteria: ¢ Correct formula for/Korrekte formule vir v? = v?+2aAy ¥ e Correct substitution into the formula v Korrekte substitusie in die formule e Correct final answer./Korrekte finale antwoord. v OPTION/OPSIE 1 OPTION/OPSIE 2 Positive downwards: Positive upwards: Positief afwaarts: Positief opwaarts: v? = ve+2ady ¥ vj = v? + 2ady ¥ v? = (307)+2(9,8)(25) ¥ vi = (307) + 2(—9,8)(25) ¥ Vy = 37,28 mst ¥ vp = —37,3 ms" Vp = 37,28 ms! ¥ (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 FS/VS/September 2025 3.3. POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 3.2.1 Positive downwards/ Positief afwaarts: A 25] Pry N > N Position/Posisie (m) \ i 1,24 1,74 2,28 t(s) Positive upwards/ Positief opwaarts: 1 1,24 1,74 2,26 . Position/Posisie (m) = N ~ N nN a (5) Marking Criteria/Nasienkriteria: ¢ Correct heights for balls A and B with the correct shape. Y Korrekte hoogtes vir balle A en B met korrekte vorm. e Correct times for balls A and B (B pass A). # Korrekte tye vir balle A en B (B beweeg verby A). e Both balls pass each other at the same point. V Albei balle gaan op dieselfde punt by mekaar verby. e Both balls end on the ground. v Albei balle eindig op die grond. e Labels ball A and ball B. V Benoem bal A en bal B. [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 FS/VS/September 2025 QUESTION/VRAAG 4 41 Marking Criteria/Nasienkriteria: If any of the underlined keywords/phrases in the correct context are omitted, deduct 1 mark. Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word, trek 1 punt af. The total linear momentum of an isolated_system remains constant (is conserved). vv Die totale lineére momentum van 'n geisoleerde stelsel bly konstant (word bewaar). (2) 4.2 Marking Criteria/Nasienkriteria: ¢ Correct formula for/Korrekte formule vir yp, = YP, ¢ Correct substitution to calculate > p, ¥ Korrekte substitusie om > p, te bereken ¢ Correct substitution to calculate 2p, v Korrtekte substitusie om Yp, te bereken e Correct final answer and direction. ” Korrekte finale antwoord en rigting. OPTION/OPSIE 1 Right as positive/Regs as positief: 2p, = DP; McVic +I MVit = McVic + MVet (1200)(25) + (6000)(15)” = (1200)(16) + (6000)(va) ¥ Vi = 16,8 mst east/oos ¥ | Y any one/enige een OPTION/OPSIE 2 Left as positive/Links as positief: >P; = >P, McVic + MVit = McVic + MVet (1200)(—25) + (6000)(—15)” = (1200)(—16) + (6000)(v_)v Ve = — 16,8 mst Vi = 16,8 ms" east/oos ¥ Y any one/enige een (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 43 4.4 FS/VS/September 2025 POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 4.2 | Marking Criteria/Nasienkriteria: ¢ Correct formula for/Korrekte formule vir Ex;/ Exp ¥ « Correct substitution to calculate Ex; Korrekte substitusie om Ex; te bereken « Correct substitution to calculate Ex, Korrekte substitusie om Ex te bereken e Correct calculation for/Korrekte berekening vir Exiose“ e Correct final answer./Korrekte finale antwoord. V OPTION/OPSIE 1 Right as positive/Regs as positief: Ek (before/voor) FY Yamevi, + Yamnyve M = %(1200)(25*) + %4(6000)(157) v = 105 0000 J Ex cafter/na) = vaneve + Yami, = ¥%4(1200)(16”) + %4(6000)(16,8") v = 1000320 J Ex ost) = Ex cafter/na) ~ Ex (before/voor) = 1000320 — 105 0000 Vv = 4980 J v OPTION/OPSIE 2 Left as positive/Links as positief: - 2 2 Ex(betore/voor = VMeVic + VAMLViE = %(1200)(—257) + %4(6000)(—15*) v = 105 0000 J = 2 2 Excafteryna) ~ AMG Vig + AMA = %(1200)(—167) + %(6000)(—16,87) v = 1000320 J Exctost) = Excatter/na) ~ Ek (oefore/ voor) = 1000320 — 105 0000 v = 4980 J v (5) Collision is inelastic./Botsing is onelasties. V Energy is lost as sound energy and heat during the collision with the ground. v Energie gaan verlore as klankenergie en hitte tydens die botsing met die grond. (2) [13] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 FS/VS/September 2025 QUESTION/VRAAG 5 5.1. A force for which the work done in moving an object between two points is independent of the path taken. vv (2 or/of 0) ‘n Krag waarvoor die werk verrig is om 'n voorwerp tussen twee punte te beweeg, is onafhanklik van die pad wat geneem word. (2) 5.2 Gradient/Gradiént = a= ee v According to/Volgens Wret = AE, AE, _ Wet = = v ee Frat (2) 5.3.1 Gradient/Gradiént = = 160 -— 24” 8-47 = 34NY (3) 5.3.2 POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 5.3.1 Marking Criteria/Nasienkriteria: e Correct formula for/Korrekte formule vir Fret/Wne /Wnet” e Correct substitution to calculate f/Korrekte substitusie om f te bereken Vv e Correct final answer./Korrekte finale antwoord. V OPTION/OPSIE 1 Fret = Fa =f Fay 34v =45 — f — (8)(9,8)sin25 v f = 22,13 NV OPTION/OPSIE 2 Whe = AEx + AE, Wra + Wy = AEx + AE, Y any one/enige een F,Axcos6 + F;Axcos@ = (Ymv? — Yamv?) + mgh; — mgh; (45)(4)cos0° + (f)(4)cos180°v = (160 — 24) + (8)(9,8)(8sin25°) — (8)(9,8)(4sin25°)v f = 22,13 NY OPTION/OPSIE 3 Wret = AEx ff 5 F,Axcos@ + F;Axcos@ + FyAxcos@ = AE any one/enige een (45)(4)cos0° + (f)(4)cos180° + (8)(9,8)sin25°(4) cos 180°V = 160 —24v f = 22,13 NV (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 FS/VS/September 2025 5.3.3 Ex = Ymv? 24 = %(8)v2 v v= 2,45m-s7 Pave/gom = FVave/gem v = (72)(2,45) v = 176,5Wv (4) 5.4 XY, v net force will decrease, when frictional force increases. Vv nettokrag sal afneem wanneer wrywingskrag toeneem. (2) [17] QUESTION/VRAAG 6 6.1. Doppler effect/Doppler-effek v (1) 6.2 Remains the same/Bly dieselfde V (1) 6.3 No relative motion between the listener and the source. vv Geen relatiewe beweging tussen die luisteraar en die bron nie. (2) 6.4 POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 6.4 Aircraft/Vlieqtuig A Vs = v fL Vs t+v fs _ 340 570 = g5-q 0” Va = 17,89 mstv Aircraft/Viiegtuig B i= Ve+ v's 340 = ———— v 450 3404 vg 600 Vg = 113,33 ms'¥ Total distance after 1 min Totale afstand na 1 min =d, + dg = (v- At) + (v- At) = (17,89 x 60) + (113,33 x 60)Y = 7873,4mv (7) [11] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 FS/VS/September 2025 QUESTION/VRAAG 7 7.1 2 7.3 7.4 Marking Criteria/Nasienkriteria: If any of the underlined keywords/phrases in the correct context are omitted, deduct 1 mark. Indien enige van die onderstreepte sleutelwoorde/frases in die korrekte konteks weggelaat word, trek 1 punt af. The magnitude of the electrostatic force exerted by one point charge on another point charge is directly proportional to the product ofthe magnitudes of the charges and inversely proportional _to_the square of the distance between them. vv Die grootte van die elektrostatiese_krag wat deur een puntlading op 'n ander puntlading uitgeoefen word, is direk eweredig aan die produk van die groottes van die ladings en omgekeerd eweredig aan die kwadraat van die _afstand tussen hulle. (2) NB: If reference to masses/lf the word FORCE in context is omitted: °/, LW: As na massas verwys word/As die woord KRAG in konteks weggelaat word: 9/, To ensure that charges do not leak to the ground. v Vv Om te verseker dat ladings nie grond toe lek nie. (2) Q=nev Q = (4,625 x 10')(1,6 x 10719) v Q=+7,4 x 10-°CY Accept/Aanvaar: +7,4 nC (3) POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 7.3 E= 2 - (910°) (7,4x10°) (0,9)? E= 82,22 N.C'v (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 FS/VS/September 2025 KQ,Q 75 Fake Y r _ (9%10°}(7,4x1079)(5x10~°) ~ 0,92 =4,1 “yN F = 4,1 x 1077 — (0,15 x 4,1 x 1077) ¥ = 3,49 x 1077N (15% less/minder) F= Ros r 9 -9 —9 3,49 x 10-7 = (9x10 Meanie (5x10 dy r=1,01m distance/afstand = 1,01 -0,9 ~ = 0,11 m¥ (6) [16] QUESTION/VRAAG 8 8.1. The potential difference across a conductor is directly proportional to the current in the conductor at constant temperature. VY (2 or/of 0) Die potensiaalverskil oor 'n geleier is direk eweredig aan die stroom in die geleier by konstante temperatuur. (2) 8.2.1 O(V)¥ (1) 8.2.2 10VVv (1) 8.3.1 7,5VV (1) 1 1 1 Se Sf” 6.312 Rp Ra +E 1 1 = -+-v 6 + 3 Rp = 20 Rr 4 Rsg+Rp =1+2v = 30 %o =—Vv 3 | |= 2,5Av (6) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 FS/VS/September 2025 8.3.3 POSITIVE MARKING FROM/POSITIEWE NASIEN VANAF 8.4 OPTION/OPSIE 1 OPTION/OPSIE 2 re Vy E = |I(R+r) ¥ _ 25 ! 10 = 2,5(3+r) v =35 v r= 10OV =10QV 8.4 Half vv Accept: Smaller/Aanvaar: Kleiner QUESTION/VRAAG 9 9.1.1 Change in magnetic flux linkage “ Verandering in magnetiese vioedkoppeling 9.1.2 Ato/tot B v (Flemmings) Right-hand rule/Regterhandreél Vv 9.1.3 Split-ring (commutator)/Spiitring (kommutator) V 9.1.4 Use stronger magnet/Gebruik sterk magneet V OR/OF Increase emf/number of cells/Verhoog emk/aantal selle 9.2 Py=120+100 = 220W Daily energy consumption when S; and Sz are closed: Daaglikse energieverbruik wanneer S; en S2 gesluit is: E gaily daagliks = PAtv 220 Too0 * 12 hrs = 2,64 kWh Weekly energy consumption/Weeklikse energieverbruik: Egaily/daagliks = 2,64 x 7¥ = 18,48 kWh Weekly cost ectricity/Weeklikse koste van elektrisiteit: Cost/Koste = E x tarrif/tarief = 18,48 x 9 ¥ = R166,32 To save R36,00 per week/Om R36,00 per week te spaar: Energy saving/Krag gespaar = = = 4 kWh per week/per week ¥ (3) (2) [16] (1) (2) (1) (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 15 FS/VS/September 2025 How long S; should be open/Hoe /ank S; oop moet wees: 120 Energy saved per hour/Krag per uur gespaar = wo 0,12 kW v Hours required per week/Ure per week vereis: 4 h= a 33,33 hours per week/ure per week Daily duration to keep S; open/Daaglikse duur om S; oop te hou: = v = 4,76 hours per day/uur per week V (7) [12] QUESTION/VRAAG 10 10.1 The process whereby electrons are ejected from a metal surface when light of suitable frequency is incident on that surface. vv (2 or 0) Die proses waardeur elektrone uit '‘n metaalopperviak gestoot word wanneer lig van geskikte frekwensie op daardie opperviak inval. (2) 10.2 B=