# Physical Sciences Grade 12 Paper 1 North West Mock 2025 Memo

> Grade 12 Physical Sciences Paper 1 memorandum from the North West Mock Exam 2025, 15 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/physics-grade-12-nsc-p1-memo-september-2025-north-west/6c02b942-919c-4c49-a052-8ae1f1471f39
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2025
- Exam period: North West Mock Exam
- Paper: 1
- Curriculum: CAPS
- Pages: 15

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## About this document

Physical Sciences · Grade 12 · North West Mock Exam · 2025. Memorandum, 15 pages. Read online or download the PDF.

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## Document text

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### Page 1

education

Department:

Education

North West Provincial Government
REPUBLIC OF SOUTH AFRICA

NATIONAL SENIOR CERTIFICATE
NASIONALE SENIOR SERTIFIKAAT

[ GRADE 12/GRAAD 12

PHYSICAL SCIENCES: PHYSICS (P1}
FISIESE WETENSKAPPE: FISIKA (V1)

SEPTEMBER 2025
MARKING GUIDELINES/NAS/ENRIGL YNE

MARKS/PUNTE: 150

These marking guidelines consist of 15 pages.
Hierdie nasienriglyne bestaan uit 15 bladsye.

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### Page 2

QUESTION/VRAAG 1

1.1
le
1.3
1.4
1.5
1.6
1.7
1.8
1.9

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Cc

on DO >

Qo 0 FO WO >

vv

vv

vv

vv

vv

vv

Vv

Vv

vv

vv

NW/September 2025

(2)
(2)
(2)
(2)
(2)
(2)
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NW/September 2025

QUESTION/VRAAG 2

2.1. The force that opposes the motion of a moving object relative to the
surface.” “/Die krag wat die beweging van ‘n bewegende voorwerp relatief

tot ‘n opperviak teenwerk. (2 orlof 0) (2)
Fr v¥
Fgo¥

Accepted labels/Aanvaarde bendemings

Fn_| N/Normal force/Normaatkrag _

Fr_| T/Tension force/Spanningskrag

Fy | Fw/w/gravitational force/weight/gravitasiekrag/gewig

Fr_| f/fk/(kinetic) friction/(kinetiese) wrywing

Notes/Aantekeninge:

e Mark awarded for label and arrow./Punt toegeken vir benoeming
en pylijie.

e Do not penalise for length of arrows since drawing is not to
scale./Moenie vir die lengte van die pyltjies penaliseer nie
aangesien die tekening nie volgens skaal is nie.

e Any other additional force(s)/Enige ander addisionele krag(te):
Max/Maks 3/4

e If everything correct, but no arrows/Indien alles korrek, maar
geen pyltjies: Max/Maks 3/4

e If force(s) do not make contact with the dot /Indien krag(te) nie
met die kolletjie kontak maak nie: Max/Maks 3/4

e If components drawn for Fg/Indien komponente van F, geteken:
Max/Maks 3/4 (4)

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2.3.1 | Fnet = ma P

v
Toft For=ma_{ Any onev/Enige een
T= 4,3 — (3 x 9,8 sin 30°) V= 3 x 2V
T=25NV (4)

POSITIVE MARKING FROM 2.3.1/POSITIEWE NASIEN VANAF 2.3.1

2.3.2 | Fnet = ma p
v,
5 Tn heome ib Any onev/Enige een

F-25-7,2=6x2v

F=44,2NV (3)
2.4 Increasev/Toeneem (1)
[14]
QUESTION/VRAAG 3

3.1 Marking criteria/Nasienkriteria:

If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in
die korrekte konteks uitgelaat is, trek 1 punt af.

If gravity/gravitation without force is used 1/2

Indien gravitasie sonder krag gebruik word 1/2

An object which has been given an initial velocity” and then moves under
the influence of the gravitational force only.~/’n Voorwerp waaraan ‘n
beginsnelheid_gegee word, wat daarna slegs onder die invloed van

gravitasiekrag beweeg. (2)

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3.2.1 Upwards as positive (note: vr and vi can be switched except for
OPTION 1)/Opwaarts as positief (nota: vr en vi kan omgeruil word

behalwe virOPSIE 1) —__ So —
OPTION/OPSIE 1 OPTION/OPSIE 2 OPTION/OPSIE 3
Ay =viAt+ Zad?tY | w=wtadt w= vit adt

=0+ %(-9,8)(1,5)?Y | O= vit (-9,8)(1,5) 0 = vi+ (-9.8)(1,5)

= 11,025 m vi= 14,7 ms? w= 14,7 m-s?
h=11,025+100Y |ve=vit 2ady ¥ Ay = viAt + % aAt? ¥
h= 111,03 mv 0 = 14,72 + (-9,8)Ay ¥ | =14,7(1,5)+ % (9,8)(1,5)2¥
OPTION/OPSIE 4 iAy = 11,025 Ay = 11,025 m
vi = vi t+ aAt _
O= wit (-9,8)(1,5) h=11,025+100“ | h=11,025 + 100 v
vi=14,7 ms? h= 111,03 m ¥ h= 111,03 m ¥

= VVE

Ay = — At v
Ay= SET isv
Ay = 11,025

h = 11,025 + 100 v

h= 111,03 m ¥

Downwards as positive (note: vr and vi can be switched except for
OPTION 5)/Afwaarts as positief (nota: vt en vi kan omgeruil word

behalwe vir OPSIE 5)

OPTION/OPSIE 5 OPTION/OPSIE 6 OPTION/OPSIE 7

Ay = viAt + % adt? ¥ Vi=vi+ adt VW= vit adt
=0+%(9,8)(1,5)% | 0 =vi+ (9,8)(1,5) 0 = vit (9,8)(1,5)
= 11,025 m vi= -14,7 ms? vi= -14,7 ms?

h = 11,025 + 100 v vi? = vi2+ 2ady ¥ Ay = viAt + % aAt? V

h= 111,03 mV O= -14,72 + (9,8)Ay v | = -14,7(1,5)+%(9,8)(1,5)2”

OPTION/OPSIE 8 Ay =-11,025 Ay = 11,025 m

ve = vi + aAt h=11,025+100Y | h=11,025 + 100 ¥

0 = vit (-9,8)(1,5) h=111,03 mv h= 111,03 mv

vi= 14,7 ms?

Ay = oat

0+14,7

v
z 15

Ay=

Ay = 11,025
h = 11,025 +100 v
h= 111,03 mV (4)

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3.2.2 Upwards as positive/Opwaarts as positief

OPTION/OPSIE 1 OPTION/OPSIE 2
Vi=vitadt POSITIVE MARKING FROM 3.2.1/
O=vit (-9,8)(1,5) POSITIEWE NASIEN VANAF 3.2.1
im vest
w= 14,7 ms iPmupe Banya
ve = viet Zady ¥ ve = 02+ 2(-9,8)(-111,03) ¥
= 14,7? + 2(-9,8)(-100) v vi = 46,65 m:s! ¥ downwards¥/
ve = 46,65 ms Ydownwardsv/ afwaarts
afwaarts
Downwards as positive/Afwaarts as positief
OPTION/OPSIE 3 OPTION/OPSIE 4
Vi = vi + adt POSITIVE MARKING FROM 3.2.1
0 = vit (9,8)(1,5) POSITIEWE NASIEN VANAF 3.2.1
= eel
vi= -14,7 ms Weare pany
ve = vit+ 2ady ¥ ve = 02+ 2(9,8)(111,03) ¥
= -14,72 + 2(9,8)(100) “” vs = 46,65 m:s! ¥ downwardsv/
vi = 46,65 m:s"! ~ downwardsy / afwaarts
afwaarts (4)

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3.2.3 Positive marking from/Positiewe nasien vanaf 3.2.1 and/en 3.2.2

Upwards as positive/Opwaarts as positief

OPTION/OPSIE 1
ve= vit adt

0 = vit (-9,8)(1,5)
vi= 14,7 ms"

Ay = viAt + % adt? ¥

OPTION/OPSIE 2
vi = vi + aAt
= vit (-9,8)(1,5)
vi= 14,7 ms"

Vr = vit adt Y

100 = 14,7At + % (-9,8)(At ¥ | 46,65 = 14,7 + (-9,8)At ¥

At = 6,26 s V

At=6,26 sv

OPTION/OPSIE 3

ve? = vit+ 2aAy

vie = 14,72+ 2(-9,8)(-100)
vi = 46,65 m-s"

v= vit adt ¥

-46,65 = 14,7 + (-9,8)At ¥
At=6,26s Vv

Downwards as positive/Afwaarts as positief

Ve = vit adt ¥

46,65 = -14,7 + (9,8)At ¥
At=6,26 s Vv

OPTION/OPSIE 4 OPTION/OPSIE 5
Ay = viAt + % aAt? ¥ VWe= vit adt
100 = -14,7At + % (9,8)(At)? ¥ 0 = vit (9,8)(1,5)
At=6,26s Vv vi= 14,7 ms
vi = vit adt ¥
46,65 = -14.7+ 9. 8At ¥
At= 6,26 s ¥
OPTION/OPSIE 6
ve = vi2+ 2aAy
ve = -14,72+ 2(9,8)(100)
vi = 46,65 m-st

(3)

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3.3

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POSITIVE MARKING FROM QUESTION 3.2.1 AND QUESTION 3.2.3/
POSITIEWE NASIEN VANAF VRAE 3.2.1 EN 3.2.3

OPTION 1: UPWARDS AS POSITIVE/OPSIE 1: OPWAARTS AS
POSITIEF
Velocity vs time graph/Snelheid teenoor tyd grafiek

<

=
a
my

© Velocity/Snetheid (m-s') *

Ball/Bal B

7,76 time/tyd (s)

Batl/Bal A

46,6

OPTION 2: DOWNWARDS AS POSITIVE/OPSIE 2: AFWAARTS AS
POSITIEF
Velocity vs time graph/Snetheid teenoor tyd grafiek

46,65 fF
£
2 Ball/Bal A
o
s
2
Z
>
s 7,76 time/tyd (s)
3
>
v 14,7 Ball/Bal B

Criteria/Kriteria:

e Same initial velocity for both ball A and B.~/Dieselfde aanvanklike
snelheid vir beide bal A en bal B.

e Graph of ball B starts at 1,5 s.~/Grafiek van bal B begin by 1,5 s.

e Both graphs end with the same final velocity.~/Beide grafieke eindig
met dieselfde eindsnelheid.

¢ Graph of ball B stops at 7,76 s.~/Grafiek van bal B eindig by 7,76 s.

e Correct shape and equal sizes for both graphs.“ /Korrekte vorm en
gelyke groottes vir beide grafieke.

(5)
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QUESTION/VRAAG 4

41

4.2

4.3

4.4

NW/September 2025

mva + mvs = mva + mvs ¥
(m x 12) + (3m x 0) Y= mva + (3m x 4,68) ¥
v=-0,86 ms*
v = 0,86 m:s" leftv/links

Ex=%mv?v

Before collision/Voor botsing
Ex = %4(m)(12)? + %(3m)(0)* ¥
Ex = 72m J

After collision/Na botsing
Ex = %4(m)(0,86)* + %4(3m)(4,68)? ¥
Ex = 14,83m J

Ex before is not equal to Ex afier¥ /Ek voor is nie gelyk aan Ex na
Thus, an inelastic collision./Dus ‘n onelastiese botsing.

Marking criteria/Nasienkriteria:

If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark/ indien enige van die onderstreepte sleutelwoorde/frases in
die korrekte konteks uitgelaai is, trek 1 punt af.

The product of the resultant/net force acting on an object “and the time the

net force acts on the object.“/Die produk van die resulterende/netto_krag
wat op ‘n voorwerp inwerk en die tyd wat die netto krag op die voorwerp

inwerk.

OPTION/OPSIE 1 OPTION/OPSIE 2

Fret x 0,03 = 0,05 (-0,86 — 12) v Fret X 0,03 = 0,15(4,68 — 0) ¥
Fret = 21,43 N ¥ Fret = 23,4 N ¥

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(4)

(4)

(2)

(3)
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QUESTION/VRAAG 5
5.1 (Kinetic) frictional force.”/(Kinetiese) wrywingskrag
5.2.1] mhgr+ %mve =mhgi + %mvi2 ¥
0+ % 4(w*) = (4 x 9,8 x 15) + % 4(32) v
vi = 17,41 mst v¥
522 FnetAx = Ye mv? - % mvi? Y
fk x 18cos 180° Y = 0 - % 4(17,417) v
fk = 33,68 N ¥
5.3 POSITIVE MARKING FROM 5.2.1/POSITIEWE NASIEN VANAF 5.2.1
fk = uxmg ¥
33,68 = pkx4x9,8 vw
Uk = 0,86 ¥
QUESTION/VRAAG 6
6.1 Marking criteria/Nasienkriteria:
If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in
die korrekte konteks uitgelaat is, trek 1 punt af.
The change in frequency (or pitch) of the sound detected by the listenery,
because the sound source and the listener have different velocities relative
to the medium of sound propagation.~/Die verandering in frekwensie (of
toonhoogte) van die klank waargeneem deur _'n luisteraar omdat die
klankbron en die luisteraar verskillende snelhede relatief tot die medium
waarin die klank voortgeplant word, het.
OR/OF
An (apparent) change in (observed/detected) frequency (pitch),“ as a
result of the relative motion between a source and an observer Vv (listener).
'n (Skynbare) verandering in (waargenome) frekwensie (toonhoogte), as
gevolg van die relatiewe beweging tussen die bron en 'n waarnemer
(luisteraar).
6.2.1 veMfv
343 = 350 x 10° f ¥
f =980 Hz v

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(1)

(3)

(4)

(3)
[11]

(2)

(3)

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6.2.2 POSITVE MARKING FROM 6.2.1/POSITIEWE NASIEN VANAF 6.2.1

viv
f= - fs v

ViVs

_ 343
980 v = 343-30 fv

fs = 894,29 Hz

veh
343 =A x 894,29 v
A= 0,39 m¥

(5)

6.3.1 TOWARDSYV/NA

6.3.2

(1)

The curve shows a blue shift~/Die kurwe toon ‘n blou verskuiwing , the star

moves towards the side of a higher frequency/lower wavelength.” /die ster

beweeg na die kant met 'n hoér frekwensie/korter golflengte.

QUESTION/VRAAG 7

FA

(2)
[13]

Criteria for sketch/Kriteria vir skets

Marks/
Punte

Correct direction of field lines./Korrekte rigting van veldlyne.

Correct shape of te electric field lines between the charges
and on the outside of the charges./Korrekte vorm van
elektriese veldlyne tussen ladings en aan die buitekant van
die ladings.

No field lines crossing each other. Field lines must touch the
charge, but not go inside the charge./Geen veldlyne wat
mekaar kruis nie. Veldlyne moet die lading raak, maar nie die
lading binnegaan nie.

Note: If learner draws field pattern of two like charges: 0/3
If only one charge is drawn: 0/3

Nota: Indien leerder elektriese veld van twee gelyke ladings
teken: 0/3
Indien slegs een lading geteken is: 0/3

(3)

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7.2 | Marking criteria/Nasienkriteria

If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark./Indien enige van die onderstreepte sleutelwoorde/frases in
die korrekte konteks uitgelaat is, trek 1 punt af.

If mass is used//ndien massa gebruik is: 0/2

If force is ommited/Indien krag weggelaat is: 0/2

The magnitude of the electrostatic force exerted by one point

charge on another point charge is directly proportional to the product of
the magnitudes of the charges” and inversely proportional to the square of
the distance between themv

Die grootte van die elektrostatiese_krag wat een puntlading op 'n ander
puntlading uitoefen, is direk eweredig aan die produk van die groottes van
die _ladings en omgekeerd eweredig aan die kwadraat van die_afstand

tussen hulle. (2)
73 | pu kay,
r2
9 -19 -19
peed x 1,6 x 10 ae VY
(3x 1071?) (3)
F=2,56x10°Nv
74.1| =x? + y? v (or any suitable equation/of enige geskikte formule)
r2 = (2,56 x 10°)? + (2,56 x 10°5)2 ¥
Fret = 3,62 x 10°°.N ¥
45° north west/west of north/north of west /noordwes/wes van noord/noord
van wes ORIOF 315° (4)
7.4.2 | OPTION/OPSIE 1 ACCEPT/IAANVAAR:
POSITIVE MARKING FROM 7.4.1/ B= kKQ Vv
POSITIEWE NASIEN VANAF 7.4.1 r
E=fv 5 = 2% 10x 1,6x 10°
Ie 5 (3x 10712)
3,62 x 10”
Sr rer E=1,6 x 10% N-C*
ves, HAWARITAER Ene? = (1,6 x 10")? + (1,6 x 10")? v
= 2,26 x 10! NC ¥ Enet = 2,26 x 104#N-C v (3)
[15]

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QUESTION/VRAAG 8

8.1 To measure the total current of the circuit.“~/ Om die totale stroomsterkte in
die stroombaan te meet.

(If only current: 0/1/Indien slegs stroomsterkte: 0/1) (1)
Zl aa
821 Sv xiv =3,33AV (3)
8.2.2 | EmffEmk = I(R +r) ¥
26 = 5(R + 0,6) ¥
Re =4,60
1 1.1
eos gees qos
Re 2R R
lt, v= zl. + i v
4,6 2R_ R
R=69QV¥ (5)
8.2.3 | OPTION/OPSIE 1 OPTION/OPSIE 2
POSITIVE MARKING FROM Velr
8.2.2/POSITIEWE NASIEN =5x06
VANAF 8.2.2 =3V
V=IRV
= Emf = Vext + Vint/Emk =Vekstem + Vinten ¥
=5x4,6v
= 26=V+3V
=23VVv
V=23VVY (3)
8.2.4 POSITIVE MARKING FROM 8.2.1; 8.2.2 AND 8.2.3/
POSITIEWE NASIEN VANAF 8.2.1; 8.2.2 EN 8.2.3
OPTION/OPSIE 1 OPTION/OPSIE 2 OPTION/OPSIE 3
W = PRAt ¥ W = V7/RAt ¥ W = VIAt ¥
= 3,33? x 6,9 x 120 ¥ = 237/6,9 x 120 v = 23 x 3,33 x 120 V
= 9181,61 Jv = 9200 J ¥ = 9190,8 J ¥ (3)
8.3.1 DECREASEY/AFNEEM (1)

8.3.2 Total external resistance increase, current decreases. ¥
Vint decreases as current decreases/Vint is directly proportional to current ¥
Emf remains constant v’, thus Viost decreases.
Totale eksterne weerstand vermeerder, stroom verminder.
Vint verminder soos stroom verminder/Vint is direk eweredig aan die stroom
Emk bly konstant, dus neem Vvertore af. (3)
[19]

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QUESTION/VRAAG 9

9.1
9.2

9.3

9.4

9.5.1

9.5.2

Copyright reserved/Kopiereg voorbehou

Mechanical to electrical energyY V/Meganiese na elektriese energie.
BtoAYvV/BnaA

« Use stronger magnets./Gebruik sterkter magnete. ¥

e Increase frequency of the rotationY/Verhoog die frekwensie van die
rotasie

e Increase the number of coils/surface area/Meer windings/vergroot
oppervlak
(any two/enige twee)

Marking criteria/Nasienkriteria:

If any of the underlined key words/phrases in the correct context is omitted
deduct 1 mark/ Indien enige van die onderstreepte sleutelwoorde/frases in
die korrekte konteks uitgelaat is, trek 1 punt af.

The AC current which dissipates/produces the same amount of
energy/heatY as an equivalent direct current (DC).~ Die wgk-stroom is die
wisselstroom wat dieselfde hoeveelheid energie verbruik/oordra as 'n
ekwivalente gelykstroom (GS).

Imax imaks
lms =—— ¥ / I, ete
rms Va / wgk Vo

23

==Vv
v2

= 16,26A Vv

OPTION/OPSIE 74 OPTION/OPSIE 2
V=IRV POSITIVE MARKING FROM 9.5.1/
=23x13Vv POSITIEWE NASIEN VANAF 9.5.1
= 299 V v V=IR
= 16,26 x 13
Vimsiugk = 211,38 V ¥

v, v,
Vims = 2 / Vucok = mais

v2 v2

= Vmaximats
211,38 = = v

| Viaximans = 298,94 V ¥

(2)
(2)

(2)

(2)

(3)

(3)
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QUESTION 10/VRAAG 10

10.1

10.2

10.3

10.4

10.5

10.6

Photon” /Foton

Marking criteria/Nasienkriteria:

if any of the underlined key words/phrases in the correct context is
omitted deduct 1 mark/ Indien enige van die onderstreepte
>lwoorde/frases in die korrekte konteks uitgelaat is, trek 1 punt af.
minimum frequency requiredY to eject an electron from a metal
surface.~/Die minimum _frekwensie benodig om ‘n elektron uit ‘n

metaalopperviak vry te stel.

OPTION/OPSIE 1 OPTION/OPSIE 2
NOvV/NEE NOv/NEE
Wo = hfo ¥ E=hfv
= 6,63 x 10% x8,1x10%Y | 4,8 x 1079 =6,63 x 10™4f v
=5,37x 10% Jv f=7,24 x 104 Hz ¥
Wo>E fo > f

POSITIVE MARKING FROM 10.3/POSITIEWE NASIEN VANAF 10.3

E = Wot % mvVmawmaks? ¥
7,68 x 10-19 = 5,37 x 10°19 V+ % 9,11 X 10°! Vmaximaks* Y
Vmaximaks = 712 134,13 ms? ¥

REMAIN THE SAMEv/BLY DIESELFDE

e Intensity does not affect the maximum speed.v

e Only achange in frequency affects the maximum speed.

e Intensiteit het geen effek op die maksimum spoed nie.

e Slegs ‘n verandering in die frekwensie sal die maksimum spoed
beinvloed.

(any one/enige een)

TOTAL/TOTAAL:

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(1)

(2)

(4)

(4)
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