# Physical Sciences Grade 12 Paper 2 Gauteng Mock 2025 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Gauteng Mock Exam 2025, 12 pages. Read online or download the free PDF.

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- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2025
- Exam period: Gauteng Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 12

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## About this document

Physical Sciences · Grade 12 · Gauteng Mock Exam · 2025. Memorandum, 12 pages. Read online or download the PDF.

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### Page 1

P(EBYSS GAUTENG PROVINCE

PREPARATORY EXAMINATION
VOORBEREIDENDE EKSAMEN

2025

MARKING GUIDELINES
NASIENRIGLYNE

10842

PHYSICAL SCIENCES: CHEMISTRY
FISIESE WETENSKAPPE: CHEMIE

(PAPER/VRAESTEL 2)

11 pages/bladsye

### Page 2

10842/25

QUESTION/VRAAG 1

11 D vv

12 DB vv

13 A vv

14 C vv

1.5 Accept all answers Vv

16 D vv

17 A vv

18 Bovv

19 C vv

110 D vv

QUESTION/VRAAG 2

2.1.1 Ketone/Ketoon ¥
2.1.2 Haloalkane VY or alkyl halide/Haloalkane of alkielhalied
2.2 1-bromo-3-chloro-4-methylpentane/

1-bromo-3-chloro-4-metielpentaan VV Vv

Marking criteria/Nasienriglyne:

° Correct stem (pentane) ¥/korrekte stamnaam (pentaan)

e All substituents (chloro, bromo and methyl) were correctly
identified. V/alle substituente (chloro, bromo en metiel) is korrek
geidentifiseer

e IUPAC name is completely correct including numbering, sequence,
hyphens and commas. ¥//UPAC naam is heeltemal korrek insluitend
nommering, volgorde, koppeltekens en kommas

2.3 AY
2.4.1 H H H O Marking criteria/Nasienriglyne:
u—¢—o_—¢__y e Functional group -COH on the first
r | | carbon ¥/Funksionele groep -COH op
H H H vv die eerste koolstof
e Correct whole structure V/Korrekte
volledige struktuur
2.4.2 Marking criteria/Nasienriglyne:
\ if e Functional group -COOC- “/Funksionele
H—C—O—C—H groep -COOC-
| e Correct whole structure /Korrekte
H vv volledige struktuur

2

(1)
(1)

(3)

(1)

(2)

(2)

### Page 3

2.43

2.5

2.6.1
2.6.2
2.7
2.8

10842/25

a Marking criteria/Nasienriglyne:
H oO oH e Correct stem — 3 carbons ¥/Korrekte
4} ty stam- 3 koolstowwe
HF | i e Functional group -OH and a methyl on
H-C—H the second carbon V the O must be
i Vv bonded on the C/Funksionele groep -OH
en metielgroep op tweede koolstof, die O
moet op die C gebind wees

Unsaturated indicates a mulitple bond between two C atoms. “
This compound has an oxygen atom, hydrocarbons do not have an Oxygen.
v

Onversadig dui aan om meervoudige bindings tussen C atome.
Hierdie verbinding het ‘n suurstofatoom, koolwaterstowwe moet nie ‘n
suurstof hé nie.

Ev

Av

CsHi2 “+ 802 > 5CO2 + 6H20 V v_balancing/balansering

Empirical forrmula/Empiriese formule = CH20
Molar mass/Molére massa = 150 g.mol*
M(CH20) = 30 g.mot?
Molecular formula/Molekulére formule = ?
gb0 8
30
Molecular formula/Molekulére formule = 5 x CH2O
=CsH1005 ¥

(2)

(2)
(1)
(1)
(3)

(2)
[21]

### Page 4

10842/25

QUESTION/VRAAG 3

3.1

3.2

3.3

3.4

3.5.1
3.5.2

3.5.3

The temperature at which the vapour pressure of a substance equals
atmospheric pressure. ¥ “/ (2 or 0)

Die temperatuur waarby die dampdruk van die stof gelyk is aan atmosferiese

druk. (2)

Different homologous series ¥ OR organic compounds with different functional
groups

Verskillende homoloé reekse OF organiese verbindings met verskillende
funksionele groepe (1)

e Both B and C have dipole-dipole forces. ¥
A has London forces. ¥

e The intermolecular forces in C are stronger than those in B and the weakest
inA. ¥

e Therefore, C will require more energy to overcome the forces between the
molecules thanin BorA. ¥

Beide B en C het dipool-dipoolkragte.

A het London kragte.

Die intermolekulére kragte in C is sterker as dié in B en die swakste in A.

Daarom sal C meer energie benodig om die kragte tussen die molekules te
oorkom as in B of A. (4)

Marking criteria/Nasienkniteria
Do not accept if the reason is given as inversely proportional.
Moet nie aanvaar indien die rede gegee word as omgekeerd eweredig nie.

Dv

The highest boiling point (will have the lowest vapour pressure). V

OR

D has the strongest intermolecular forces and will need the most energy to
weaken the intermolecular forces.

OR

D has the highest number of particles present in the vapour phase.

Die hoogste kookpunt (sal die laagste dampdruk hé).

OF

D het die sterkste intermolekulére kragte en sal dus die meeste energie
benodig om die intermolekulére kragte te verswak.

OF
D het die hoogste getal deeltjies in die dampfase. (2)
Liquid/Vioeistof ¥ (1)
(e}
I
—C—H

¥ (1)

2-Butanone OR butan-2-one OR butanone v/ 2-butanoon OF butan-2-oon
OF butanoon NO marks for but-2-one GEEN punte vir but-2-oon (1)
[12]
4

### Page 5

10842/25

QUESTION/VRAAG 4
4.4.1 Esterification OR Condensation/Verestering/Esterifikasie/Kondensasie V
4.1.2 Addition/AddisieY
Accept: bromination/halogenation
Aanvaar: brominering/halogenering
4.1.3 Elimination/Eliminasie V
Accept: dehydration
Aanvaar: dehidrasie
noe ety woooe
acenei 99-9994
H H H H HH OR/OF H H H HHH vv
Marking criteria/Nasienriglyne:
e Correct stem — six carbons “/Korrekte stam — ses koolstowwe
e Functional group -OH on the 2nd or 3rd carbon/funksionele groep-OH
op die 2de of 3de koolstof ¥
4.3 HH OH OH an P (a es
H-G-G——0 0" + Ht —e—e v— HE 6G 60-0 + H,0
haan ¥ ok on had d HHO
Y v
butan-1-ol / 1-butanol propanoic acid
butan-1-ol / 1-butanol propanoéuur
do not accept butanol/moenie butanol aanvaar nie
Marking criteria/Nasienriglyne:
e Whole structure correct for butan-1-ol ¥ /Korrekte volledige struktuur vir
butan-1-ol
e Correct name reactant 1/Korrekte naam reaktant 1
Whole structure correct for propanoic acid “/Korrekte volledige
struktuur vir propanoésuur
Correct name reactant 2/Korrekte naam reaktant 2
e Whole structure correct for ester “/Korrekte volledige struktuur vir ester
Correct formula for water/Korrekte formule vir water
4.4 To act as a catalyst/Dit dien as 'n katalisator ¥
4.5 Hydroxyl (group) /Hidroksiel(groep) ¥

(1)

(1)

(2)

### Page 6

4.6.1

4.6.2

4.6.3

4.6.4

10842/25

Water and a strong acid (suphuric acid/phosphoric acid) ~
Water en in sterk suur (swawelsuur/fosforsuur)

i
—¢—
H

i
He — H

=x
I-90-0-=Z

Marking criteria/Nasienriglyne:

e Functional group -OH on the 2nd carbon “/Funksionele groep -OH op
die 2de koolstof

e Correct whole structure ¥/Korrekte volledige struktuur

Hydration/Hidrasie ¥

By using their different boiling points. “/deur gebruik te maak van die
verskillende kookpunte.

QUESTION/VRAAG 5

5.1

5.2.1

5.2.2

5.2.3

5.2.4

The energy absorbed or released in a chemical reaction. YY (2 or 0)
Die energie geabsorbeer of vrygestel in 'n chemiese reaksie.

The concentration (of the sodium thiosulfate/NazS203.) ~/Konsentrasie (van

die natriumtiosulfaat/Na2S2O3)

Average rate of reaction/Gemiddelde tempo van reaksie
_ 0,080 ¥

“35 v

= 0,0023 (moldm*.s')v (2,3x10°)

The sulphur/sulfur ¥ that forms is a solid and covers the visibility of the
cross/ Precipitaite is formed/murky solution

Die swawel wat vorm is 'n vaste stof en bedek die sigbaarheid van die kruis/
neersiag vorm/deinserige oplossing/ondeursigtige oplossing

e As the concentration increases, the number of particles per unit volume
increases Vv

e More effective collisions per unit time W

e The rate of reaction increase “

* Soos die konsentrasie toeneem, neem die aantal deeltiies per volume-
eenheid toe

e Meer effektiewe botsings vind per tydseenheid plaas
e Die reaksietempo neem toe

(1)

(2)
(1)

(1)
[18]

(2)

(1)

(3)

(1)

(3)

### Page 7

5.3.1

5.3.2

10842/25

The minimum energy needed for a reaction to take place. VY (2 OR 0)
Die minimum energie benodig vir 'n reaksie om plaas te vind.

Potential energy/Potensiéle energie

Course of reaction/Verioop van reaksie

Marking criteria/Nasienkriteria:

e The shape is endothermic. “/Die vorm is endotermies

e Axes labelled correctly AND Ea (Activation energy) or AH indicated vif
time on x-axis no marks /Asse korrek benoem EN Ea
(aktiveringsenergie) AH aangedui / indien tyd op x-as geen punte

QUESTION/VRAAG 6

6.1.1

It is a dynamic equilibrium when the rate of the forward reaction is equal to
the rate of the reverse reaction. vv

Dit is 'n dinamiese ewewig wanneer die tempo van die voorwaartse reaksie
gelyk is aan die tempo van die terugwaartse reaksie.

According to Le Chatelier’s principle:

e  Anincrease in temperature favours the endothermic reaction v
e The reverse reaction will be favoured v

e The colour of the solution changes to yellow v

Volgens Le Chatelier se beginsel:

e —_'n Toename in temperatuur bevoordeel die endotermiese reaksie
e Die terugwaartse reaksie sal bevoordee! word

e Die kleur van die oplossing word geel

(2)

(2)
[14]

(2)

(3)

### Page 8

6.2.1

6.2.2

10842/25

Increases ¥

« Adding concentrated HCl increases the concentration of the common ion
H* , the system will react to decrease the concentration of the H* ions by
favouring the forward reactionY

*® More dichromate ions form, the colour of the solution changes to orange.
v

Verhoog

e Die byvoeging van gekonsentreerde HCI verhoog die konsentrasie van
die gemeenskaplike H* ioon, die sisteem sal reageer om die
konsentrasie van die H* ione te verlaag deur die voorwaartse reaksie te
bevoordeel.

e Meer dichromaatione vorm, die kleur van die oplossing word oranje

= [0a]
Cc [co]2
(1,21 x 107) V

© (1 x 10-2)2
K, = 10
Since the Ke new = KC original therefore the system is in equilibrium. v Ke value
remains the same
Aangesien die Ke nuwe = KC corspronktixe iS die sisteem in ewewig/Kc waarde bly
dieselfde

Marking criteria

(a) Substitution of concentration into Kc expression. ¥
(b) n at equilibrium ¥

(c) Calculating the change in mole of CO v

(d) Using the mole ratio of 2CO:1COz. ¥

(e) Calculating the new initial n of CO2 ¥

(f) subtracting mol ~

(g) final answer ¥

Nasienkriteria:

(a) Vervanging van konsentrasie in Ke uitdrukking
(b) n by ewewig

(c) bereken die verandering in mol van CO

(d) gebruik die mol verhouding van 2CO:1COz.
(e) bereken die nuwe aanvanklike n van COz2

(f) aftrek van mol

(g)_finale Antwoord

OPTION 1/OPSIE 1

_ [C0]
°~ {coP
_ &
10 = ual (a)
x=0,1

[C02] = [CO] = 0,1 moledm?

(3)

(3)

(7)

### Page 9

10842/25

2CO COz
Ninital/ Neanvanklik 11x10 | 1,445x10-v(g
ANchange/ANverandering 0,089 v, (c) 0,0445v (ratio) (d)
Nequilibrium/Newewig 0,1 0,1 ¥(b)
Cequilibrium/Cewewig x x

Nadded/bygevoeg = Nnew initial/nuwe aanvanklik — Noriginal mole at eq/oorspronklike mol by ew.

1,445 x 107 —1,21x 10° v (f)
0,143 mol “ (g)

OPTION 2/OPSIE2
co CO2

Ratio 2 1

ni 1,1x10 1,21x10°3 + x
An 1,1x107 + 2y 1,21x10°3 +x -y
nt 0,1 0,1

c=n/V 0,1 0,1
1,1x10?%+ 2y = 0,1

2y = 0,089
y = 0,0445 moi
1,21x103 +x -y =0,1

1,21x103 + x — 0,0445 = 0,1
x = 0,14329 mol added

[18]

### Page 10

10842/25

QUESTION/VRAAG 7

7.4.1

7.2.1

W2i2

A concentrated sodium hydroxide solution contains a large amount of base

particles as compared to the water particles Vv

in Gekonsentreerde natriumhidroksiedoplossing bevat 'n groot hoeveelheid
basisdeeltiies in verhouding met die volume waterdeeltjies. (1)

Decreases. Vv
Since hydroxide ions increase, V the hydronium decreases because Kw is
constant Vv

Neem af.
Omdat die hidroksiedione toeneem moet die hidronium ione verminder
aangesien Ky konstant is (3)
OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
pH = —log[H30*] Wor [Hs0*] =10°4
pH + pOH = 14
12v = —log[H3 0*] 12+pOH =14v
pOH =2

{H,0*] = 1x107!
pOH = -log[OH] ¥

& Ky = [H30*][0H7] ar = agIe]
= 1xl04v
: 1x 10-14 [OH~] = 1x10-* mol.dm=3v
[OW] = Ty
[OH-] = 1x 10-2 mol.dm-#v (4)

20,05 + 20,15 + 20,10

Average/Gemiddeld = :
= 20,10 cm® ¥ (0,0201 dm) (1)

POSITIVE MARKING FROM7.2.1/POSITIEWE NASIEN VANAF 7.2.1

OPTION 1/OPSIE 1 OPTION 2/OPSIE 2
nici = cV CV, my
= 0,0958 (0,0201)v Vo To
= 1,92558 x10 mol (0,0958)(20,1) 1
(20) 1
since/aangesien NNaOH : NHC! C2 = 0,0963 mol-:dm*?
=1:1v

“+ 1 NaoH = 1,92558 x 10°

n
+ CNaOH = 5 v
-3
= 192558x10-3
0,02

= 0,0963 mol.dm*?

Marking criteria:
(a) Calculating mol of HCl
(b) Use ratio

(c) Formula mark for cNaoH = =
(d) Substitution of correct values (4)

10

### Page 11

10842/25

Nasienkriteria:

(a) Bereken mol HCI

(b) Gebruiksverhouding
(c) Formulepunt cnaon = =

(d)_Vervanging van korrekte waardes

7.2.3 N NaOH used/gebruik = CV
= 0,0963 (0,02445) v
= 2,354 x 10° mol

7 : _ 2,354x 1073
Ratio MnaoH : N H3P04 “+ NH3P04 used/gebruik = ——-——

3
ied = 7,848 x 10“ mol

in 10 cm? of solution/oplossingY

. N H3Po4 in 250 cm of solution/oplossing
= 2° (7,848 x 104)v

~ 10,
= 0,01962 mol
~ m=nM
= 0,01962(98) ¥
= 1,92276 g
* % purity/suiwerheid =~" x 100% v
= 19,23 %Y
(Range/Reeks 19,11 — 19,30) (7)
[20]
QUESTION/VRAAG 8

8.1 (i) Mg/magnesium rod/magnesiumstaaf ¥
(ii) Cu/copper rod/koperstaaf Vv
(iii) MgSO4/magnesium sulphate solution/magnesiumsulfaatoplossing V
(iv) CuSO4/copper(Il)sulphate solution/koper(I!)sulfaatoplossing V (4)

8.2 Cu2* + 2e — Cuvv
-1 mark if double arrow used/-7 indien dubbelpyle gebruik is (2)

8.3 E° ceil/se! = E°cathode/katode - E°anode/anode Y (any one of the three as on data sheet)
=+0,34v - (-2,36)v
= 2,7VV (4)

8.4 The salt bridge completes the circuit V OR
It maintains the electrical neutrality of the two solutions by providing a pathway
for the ions to be exchanged. OR separates the two half cells
Die soutbrug voltooi die stroombaan OF
Dit handhaaf die elektriese neutraliteit van die twee oplossings deur 'n pad te
verskaf vir die ione om uitgeruil te word. OF skei die twee halfselle (1)

8.5.1 DECREASE/VERLAAG vv (2)

8.5.2 REMAINS THE SAME/BLY DIESELFDE ¥ (1)
[14]

11

### Page 12

QUESTION/VRAAG 9

9.1

9.2

9.3

9.4

9.5

10842/25

A substance whose aqueous solution contains ions OR a substance that
dissolves in water to form a solution that conducts electricity. vv

in Stof waarvan die oplossing in water ione bevat OF 'n Stof wat in water oplos

om 'n oplossing te vorm wat elektrisiteit gelei.

Copper(Il)sulfate or copper(Il)chloride solution or any other copper(II)
solution /koper(I)sulfaat of koper(II)chloride of enige ander koper‘(II)

oplossing ¥

Cu — Cu? + 2e vv

-1 mark if double arrow used/-1 indien dubbelpyle gebruik is

Silver/Ag is a weaker reducing agent v than copper, v and silver will not be

oxidised at the anode. Vv
OR

Copper is a stronger reducing agent than silver and silver will not be oxidised

at the anode.

Silwer/Ag is 'n swakker reduseermiddel as koper, en daarom sal silwer sal nie

by die anode geoksideer word nie.
OF

Koper is ‘n sterker reduseermiddel as silwer en daarom sal silwer nie by die

anode geoksideer word nie.

If Cu2* is used/As Cu?+ gebruik word

= 0,02519 mol

Since 1 Cu atom gives off 2e/Aangesien 1
Cu-atoom 2e- afgee

“ Ne- = 0,02519 (2) v
= 0,05039 mol

N
1 NA
N = (0,05039)(6,02 x 1023)”
= 3,034 x 102? electrons/elektrone Vv

12

Marking criteria:

Y formula for calculating n

Y substitution of molar mass
63,5

v¥ mole ratio used

Y substitution of Na in formula

v final answer

Nasienkriteria:

Y formule vir die berekenin
van n

¥ vervanging van molére
massa van 63,5

¥ mol verhouding gebruik

Y vervanging van Na in formule

Y finale antwoord

TOTAL/TOTAAL:

(2)

(1)

(2)

(3)

(5)
[13]
150

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