# Technical Sciences Grade 12 P1 Eastern Cape June 2023 Memo

> Grade 12 Technical Sciences Paper 1 memorandum from the Eastern Cape June 2023 (English), 11 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/tech-sciences-p1-gr12-memo-jun2023-afr-english/18d5d6dd-0e87-4d04-88a2-beb3fa330a5f
- Updated: 2026-09-27
- Subject: Technical Sciences
- Grade: Grade 12
- Language: English
- Document type: Memorandum
- Year: 2023
- Exam period: Eastern Cape June
- Paper: 1
- Curriculum: CAPS
- Pages: 11

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## About this document

Technical Sciences · Grade 12 · Eastern Cape June · 2023 · English. Memorandum, 11 pages. Read online or download the PDF.

Read it free online on the page above; download the PDF from there.

## Matching paper and memo

- [TECHNICAL SC P1 GR12 QP JUNE 2023 English](https://www.hlayiso.com/library/technical-sc-p1-gr12-qp-june-2023-english/1df8dd81-509c-4d57-8cea-9115bf53a1d0) — QP · 2023 · Eng

## Document text

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                NATIONAL SENIOR CERTIFICATE/
                NASIONALE SENIOR SERTIFIKAAT

                           GRADE/GRAAD 12

                         JUNE/JUNIE 2023

 TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1
        MARKING GUIDELINE/NASIENRIGLYN

MARKS/PUNTE:   150

                     This marking guideline consists of pages 11./
                      Hierdie nasienriglyn bestaan uit 11 bladsye.

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2                TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1                            (EC/JUNE 2023)

QUESTION/VRAAG 1

1.1     B ✓✓

1.2     A ✓✓

1.3     A ✓✓

1.4     C ✓✓

1.5     B ✓✓

1.6     D ✓✓

1.7     A ✓✓

1.8     B ✓✓

1.9     B ✓✓

1.10    A ✓✓                                                                        (10 x 2)     [20]

QUESTION/VRAAG 2

2.1     The rate of change in velocity. ✓✓                                                         (2)

        2.2.1     Choose right as postive/Kies regs as positief
                  Learner A/Leerder A:

                  Fnet = ma
                  Fnet = Fa cos 𝜃 + F𝑓            Any one ✓
                  Fnet = −8 cos 60° + 0,3 ✓✓
                  Fnet = − 3,7 N
                  Fnet = 3,7 N ✓ to the right/na regs ✓

                                                OR/OF

                  Choose left as positive/Kies links as positief

                  Fnet = ma
                  Fnet = Fa cos 𝜃 + F𝑓       Any one ✓
                  Fnet = 8 cos 60° + (−0,3) ✓✓
                  Fnet = 3,7 N ✓ to the right/na regs ✓                                            (5)

        2.2.2     Fnet = ma ✓
                  3,7 = 12a ✓

                  a = 0,31 m. s−2 ✓                                                                (3)

        2.2.3     Newton’s Second Law/Newton se Tweede Wet ✓✓                                     (2)

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(EC/JUNE 2023)                  TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2                              3

          2.2.4    When the net force is exerted on an object with mass m, ✓ the object
                   will accelerate in the direction of the net force. ✓
                   Indien ŉ netto krag op voorwerp met massa m uitgeoefen word, ✓
                   versnel die voorwerp in die rigting van die netto krag. ✓                              (2)

          2.2.5
                              FN                                           FN
                                                                     FA
                  FA
                                                                     V
                                      Ff                        FA                  Ff
                                                   OR/OF        h

                                                                            Fg
                               Fg

                              Marking criteria/Nasienkriteria                Labels       Marks/
                                                                           /Byskrifte     Punte
                       Correct direction and label of Normal force
                                                                                 N/FN        1
                       Korrekte rigting en byskrif van Normale krag
                       Correct direction and label of gravitational
                       force                                                     Fg/w        1
                       Korrekte rigting en byskrif van gravitasiekrag
                       Correct direction and label of frictional force
                       Korrekte rigting en byskrif van die                       Ff/f        1
                       wrywingskrag
                       Correct direction and label of the applied force
                       by
                                                                             F/FT/FA         1
                       Korrekte rigting en byskrif van die toegepaste
                       krag                                                                               (4)

          2.3.1    INCREASE / VERHOOG ✓                                                                   (1)

          2.3.2    DECREASE / VERLAAG ✓                                                                  (1)
                                                                                                        [20]

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4                TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1                      (EC/JUNE 2023)

QUESTION/VRAAG 3

3.1     3.1.1    When object A exerts a force on object B, ✓ object B simultaneously
                 exerts an oppositely directed force of equal magnitude on
                 object A ✓

                 Wanneer voorwerp A ŉ krag uitoefen op voorwerp B, ✓ sal voorwerp
                 B gelyktydig ŉ gelyke maar teenoorgestelde krag op voorwerp A
                 indien. ✓                                                                     (2)

        3.1.2    For crate B/vir Krat B
                 (Let right be + / Regs is +)

                 𝐹𝑛𝑒𝑡 = 𝑚𝑎
                 𝐹𝑛𝑒𝑡 = 𝐹𝐴𝑜𝑛𝐵 − 𝐹𝑓𝑘        Any one/
                 𝐹𝐴𝑜𝑛𝐵 − 𝐹𝑓𝑘 = 𝑚𝑎          Enige een
                 𝐹𝐴𝑜𝑛𝐵 − 𝐹𝑓𝑘 = 𝑚𝑎          ✓

                 𝐹𝐴𝑜𝑛𝐵 − 25, 3 ✓ = 30 × 2,3 ✓
                 𝐹𝐴𝑜𝑛𝐵 = 94,3 𝑁

                 𝐹𝐵𝑜𝑛𝐴 = −𝐹𝐴𝑜𝑛𝐵       Any one ✓/Enige een
                 𝐹𝐵𝑜𝑛𝐴 = −94,3 𝑁
                 𝐹𝐵𝑜𝑛𝐴 = 94,3 𝑁 ✓ 𝑙𝑒𝑓𝑡/𝑙𝑖𝑛𝑘𝑠 ✓

                                                OR/OF

                 (Let left be + / Links is +)
                 𝐹𝑛𝑒𝑡 = 𝑚𝑎
                 𝐹𝑛𝑒𝑡 = − 𝐹𝐴𝑜𝑛𝐵 + 𝐹𝑓𝑘         Any one /
                 − 𝐹𝐴𝑜𝑛𝐵 + 𝐹𝑓𝑘 = 𝑚𝑎           Enige een
                 − 𝐹𝐴𝑜𝑛𝐵 + 𝐹𝑓𝑘 = 𝑚𝑎
                 − 𝐹𝐴𝑜𝑛𝐵 + 25, 3 ✓ = 30 × (−2,3)✓
                 𝐹𝐴𝑜𝑛𝐵 = 94,3 𝑁

                 −𝐹𝐵𝑜𝑛𝐴 = 𝐹𝐴𝑜𝑛𝐵        Any one ✓/Enige een
                 −𝐹𝐵𝑜𝑛𝐴 = 94,3 𝑁
                 𝐹𝐵𝑜𝑛𝐴 = 94,3 𝑁 ✓ left/links ✓                                                 (6)
                                                                                               [8]

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(EC/JUNE 2023)              TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2                       5

QUESTION/VRAAG 4

4.1      4.1.1   Impulse is the product of the net force acting on an object, ✓ and the
                 time the force acts on the object.✓
                 Impuls is die produk van die netto krag wat op ŉ voorwerp inwerk, ✓
                 en die tyd wat die netto krag op die voorwerp inwerk. ✓                       (2)

         4.1.2   OPTION 1/OPSIE 1
                 Towards the batsman + / In die rigting van kolwer +

                 ∆𝑝 = 𝑚 𝑣𝑓 − 𝑣𝑖 ✓
                 ∆𝑝 = (0,175) (−30 − 12) ✓
                 ∆𝑝 = −7,35 𝑁 ∙ 𝑠 ✓
                 ∆𝑝 = 7,35 𝑁 ∙ 𝑠 ✓ 𝑎𝑤𝑎𝑦 𝑓𝑟𝑜𝑚 𝑡ℎ𝑒 𝑏𝑎𝑡𝑠𝑚𝑎𝑛 / weg vanaf kolwer ✓

                 OPTION 2/OPSIE
                 Towards the batsman - / in die rigting van die kolwer –

                 ∆𝑝 = 𝑚 𝑣𝑓 − 𝑣𝑖 ✓
                 ∆𝑝 = (0,175) (30 – ( −12) ✓
                 ∆𝑝 = 7,35 𝑁 ∙ 𝑠 ✓
                 ∆𝑝 = 7,35 𝑁 ∙ 𝑠 ✓ 𝑎𝑤𝑎𝑦 𝑓𝑟𝑜𝑚 𝑡ℎ𝑒 𝑏𝑎𝑡𝑠𝑚𝑎𝑛/weg vanaf die kolwer ✓                (5)

         4.1.3   POSITIVE MARKING FROM 4.1.2/ POSITIEWE MERK VAN 4.1.2

                 𝐹𝑛𝑒𝑡 ∆𝑡    = ∆𝑝 ✓
                 𝐹𝑛𝑒𝑡 (0,05) = 7,35 ✓
                 𝐹𝑛𝑒𝑡        = 147 𝑁 ✓

                                                OR/OF

                 𝐹𝑛𝑒𝑡 ∆𝑡    = ∆𝑝 ✓
                 𝐹𝑛𝑒𝑡 (0,05) = −7,35 ✓
                 𝐹𝑛𝑒𝑡        = −147 𝑁 ✓                                                        (3)

         4.1.4                  ∆𝑝
                 From 𝐹𝑛𝑒𝑡 = ∆𝑡 ✓
                 •     𝐹𝑛𝑒𝑡 ∝ ∆𝑝 if Δp is constant/ ✓
                 •     crumple zones increase the time ✓
                 •     Fnet decreases. ✓

                 •     𝐹𝑛𝑒𝑡 ∝ ∆𝑝 as Δp konstant is. ✓
                 •     vermeerder tyd a.g.v. frommelsones ✓
                 •     Fnet verminder ✓                                                        (4)

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6                 TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1                   (EC/JUNE 2023)

 4.2      4.2.1    The total linear momentum of an isolated system remains
                   constant (in magnitude and direction). (✓✓)
                   Die totale lineêre momentum van ŉ geïsoleerde sisteem bly
                   konstant/word behou (in grootte en rigting). (✓✓)                       (2)

          4.2.2    OPTION 1 Right + / OPSIE 1 Regs +
                   ∑ 𝑝𝑏𝑒𝑓𝑜𝑟𝑒                = ∑ 𝑝𝑎𝑓𝑡𝑒𝑟 ✓
                   𝑚1𝑣1𝑖 + 𝑚2𝑣2𝑖            = 𝑚1𝑣1𝑓 + 𝑚2𝑣2𝑓
                    (2)(3) + (3,5)(0) ✓     = (2)(−1) + 3,5𝑣 ✓
                   𝑣                        = 2,29 𝑚 ∙ 𝑠−1 ✓
                   𝑣                        = 2,29 𝑚 ∙ 𝑠−1; 𝑟𝑖𝑔ℎ𝑡/𝑟𝑒𝑔𝑠 ✓

                   OPTION 2 Left + / OPSIE 1 Links +
                   ∑ 𝑝𝑏𝑒𝑓𝑜𝑟𝑒 = ∑ 𝑝𝑎𝑓𝑡𝑒𝑟 ✓
                   𝑚1𝑣1𝑖 + 𝑚2𝑣2𝑖             = 𝑚1𝑣1𝑓 + 𝑚2𝑣2𝑓
                   (2)(−3) + (3,5)(0) ✓      = (2)(1) + 3,5𝑣 ✓
                   𝑣                         = −2,29 𝑚 ∙ 𝑠−1 ✓
                   𝑣                         = 2,29 𝑚 ∙ 𝑠−1; 𝑟𝑖𝑔ℎ𝑡/𝑟𝑒𝑔𝑠 ✓                 (5)
                                                                                         [21]

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(EC/JUNE 2023)                   TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2                      7

QUESTION/VRAAG 5

5.1    Work done is the product of the applied force on an object and the displacement
       in the direction of the force. ✓✓
       Die arbeid verrig is die produk van die toegepaste krag op die voorwerp en die
       verplasing in die rigting van die krag. ✓✓                                                  (2)

       5.2.1     𝐹𝑓 = 𝜇𝑘 𝐹𝑁 ✓
                 𝐹𝑓 = (0,14)(9,8)(8) ✓
                 𝐹𝑓 = 10,976 𝑁 ✓                                                                   (3)

       5.2.2     𝑊𝑓 = 𝐹𝑓 ∆𝑥𝑐𝑜𝑠∅ ✓
                 𝑊𝑓 = (10,976)(4) cos 0° ✓
                 𝑊𝑓 = 43,904 𝐽 ✓                                                                   (3)

5.3    0J✓                                                                                         (1)

5.4    5.4.1     Power is the rate at which work is done or expended. ✓✓
                 Drywing is die tempo waarteen arbeid verrig word of energie gebruik word.         (2)

       5.4.2          𝑊
                 𝑃 = ∆𝑡 ✓
                      480 000
                 𝑃=             ✓
                          30

                 𝑃 = 16 000 𝑊 ✓
                        16 000
                 ℎ𝑝 =            ✓
                          746

                 ℎ𝑝 = 21,45 ℎ𝑝 ✓                                                                   (5)
                                                                                                 [16]

QUESTION/VRAAG 6

6.1    Total mechanical energy remains constant in an isolated system. ✓✓
       Die totale meganiese energie in ŉ geïsoleerde sisteem bly konstant.                         (2)

6.2    ME = EK + Ep ✓
          = ½ mv2 + mgh
          = ½ (2,5)(0)2 ✓+ (2,5)(9,8)(10) ✓
          = 245 J ✓                                                                                (4)

6.3    6.3.1     No / Nee ✓                                                                        (1)

       6.3.2     The force applied and the direction of motion are perpendicular to each
                 other, ✓ so no work is done on the object. ✓
                 Die toegepaste krag en die rigting van beweging is loodreg op
                 mekaar, ✓ so geen arbeid word op die voorwerp verrig nie. ✓                       (2)
                                                                                                   [9]

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8                TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1                       (EC/JUNE 2023)

QUESTION/VRAAG 7

7.1   Strain is the ratio of change in the dimension/length of objects to the original
      dimension/length ✓✓
      Rekking is die verhouding van verandering in dimensie/lengte van voorwerpe
      tot die oorspronklike dimensie/lengte. ✓✓

      Accept/aanvaar
      The change in length over the original length of an object. ✓✓
      Die verandering in lengte van die voorwerp tot die oorspronklike lengte van ŉ
      voorwerp. ✓✓                                                                            (2)

7.2   Hooke’s law states that, within the limit of elasticity, stress is directly
      proportional to the strain. ✓✓
      Hooke se wet bepaal dat spanning, in die grens van elastisiteit, direk eweredig
      aan die rekking is. ✓✓                                                                  (2)

7.3   7.3.1           𝐹
                 𝛿 = 𝐴✓
                                    𝐹
                 1 × 106 ✓ = 2×10−3 ✓

                 𝐹 = 2 000 𝑁 / 2 𝑘𝑁 ✓                                                         (4)

      7.3.2           ∆𝐿
                 𝜀=        ✓
                      𝐿
                      1×10−3
                 𝜀=             ✓
                           50

                 𝜀 = 2 × 10−5 ✓
                 NOTE: Penalise if units are included (final answer).
                 LET WEL: Penaliseer indien eenhede by finale antwoord gegee is.              (3)

      7.3.3           𝛿
                 𝐾= 𝜀✓
                       1×106
                 𝐾 = 2×10−5 ✓
                                    𝑚−2
                 𝐾 = 5 × 1010 𝑁 𝑃𝑎 ✓                                                         (3)
                                                                                            [14]

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(EC/JUNE 2023)              TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2                       9

QUESTION/VRAAG 8

8.1    Viscosity is a physical property of fluids. It shows the resistance to flow. ✓✓
       Viskositeit is ŉ fisiese eienskap van vloeistowwe. Dit toon die weerstand teen
       vloei.
       (Viskositeit is ŉ fisiese eienskap van vloeistof om die relatiewe beweging
       tussen twee aangrensende vlakke teen te werk.)                                          (2)

8.2    5W-30 SAE is the oil that behaves as an SAE 5 oil at low temperatures, ✓
       and behaves as an SAE 30 at high temperatures.✓
       5W-30 SAE is die olie wat as ŉ SAE 5 olie by lae temperature werk ✓ en sy
       gedrag by hoë temperature is soos ŉ SAE 30 olie. ✓

                                           OR/OF

       5: Viscosity grade at cold temperature, W: Winter 30: Viscosity rate at 100 °C
       5: Viskositeit grade by kouer temperatuur, W: Winter 30: Viskositeit by
       100 °C.                                                                                 (2)

8.3    B ✓✓                                                                                    (2)

8.4    In summer South Africa has high temperature; B has a higher viscosity ✓ at
       higher temperatures. ✓
       In die somer is Suid-Afrika se temperatuur hoog; B het ŉ hoër viskositeit ✓ by
       hoër temperature. ✓                                                                     (2)

8.5    Single/mono-grade oil is graded at one temperature, ✓✓ while multigrade oil is
       graded at two temperatures. ✓✓
       Enkel/mono-graad olie word gegradeer by een temperatuur, ✓✓ terwyl
       multigraad by twee temperature gegradeer word. ✓✓

                                           OR/OF

       • Single /Monograde oil is the engine oil that is designed to function at either
         low temperatures or high temperatures and is not be suitable for engines
         with changing temperatures. For example, SAE 40 oil is a monograde
         oil. ✓✓
       • Enkel/monograad olie is die enjin-olie wat ontwerp is om te funksioneer by
         of lae temperature of hoë temperature en is nie geskik vir enjintemperature
         wat baie verander nie. ✓✓
       • Multi-grade oil is an engine oil that is designed to cope with the increasing
         engine temperatures. It behaves as a low viscosity oil at lower
         temperatures and as a high viscosity oil at high temperatures. For
         example, 20W50 SAE is an engine oil that behaves as SAE 20 when the
         engine is cold, and as a SAE 50 when the engine heats up. ✓✓
         Multigraad-olie is ŉ enjin-olie wat ontwerp is om met die toenemende enjin-
         temperature te werk. Dit tree op as ŉ lae viskositeit olie by lae temperature
         en as ŉ hoë viskositeit olie by hoë temperature. Byvoorbeeld, 20W50 SAE
         is ŉ olie wat as SAE 20 werk wanneer die enjin koud is, en as ŉ SAE 50
         wanneer die enjin opgewarm is.                                                       (4)
                                                                                             [12]

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10                   TECHNICAL SCIENCES P1/TEGNIESE WETENSKAPPE V1                         (EC/JUNE 2023)

QUESTION/VRAAG 9

9.1   Hydraulics is a field in applied sciences and engineering ✓ dealing with
      mechanical properties of liquids. ✓
      Hidroulika is ŉ studieveld in toegepaste wetenskappe en ingenieurswese ✓ wat
      die meganiese eienskappe van vloeistowwe behandel. ✓

                                                 OR/OF
      The study of mechanical properties of liquids. ✓ (1 mark if this definition is given.)
      Die studie van meganiese eienskappe van vloeistowwe. ✓ (1 punt indien hierdie
      definisie gegee word.)                                                                           (2)

9.2   (Any 2/Enige 2) ✓✓

      Designing hydraulic systems, steering systems, brake systems, power assisted
      steering, etc. ✓
      Ontwerp van hidrouliese-stelsels, stuurstelsels, remstelsels, kragstuurstelsels,
      ens. ✓
      Presses: metal presses, wood presses, ceramic presses, plastic presses, etc. ✓
      Pers/Drukke: Metaalperse, houtperse, keramiekperse, plastiekperse, ens. ✓
      Machines for industries: metal, wood, textile, paper, etc. ✓
      Masjiene vir industrieë: Metaal, hout, tekstiel, papier, ens. ✓
      Processing machinery: wood processing, sheet metal processing, etc. ✓
      Verwerkingsmasjinerie: Houtverwerking, bladmetaal-verwerking, ens.. ✓
      Casting: foaming, blowing, extruding machines, etc. ✓
      Gieting: Skuim, blaas, ekstrudeer(onttrekkings)masjiene, ens.

      Component finishes: circular tables, revolving distributors, clamping systems,
      etc. ✓
      Komponent afrondings: ronde tafels, wentelende verspreiders, vasklampstelsels
      (saampers), ens. ✓                                                                               (2)

      9.3.1         Pressure at a particular point as the thrust(force) acting on the unit area
                    around that point ✓✓
                    Druk (in ŉ vloeistof) by ŉ spesifieke punt is die stukrag(krag) op die
                    eenheidsoppervlakte rondom daardie punt is.                                        (2)
      9.3.2              𝐹
                    𝑃 = 𝐴✓
                                     𝐹
                    1,2 × 105 = 8,4 × 10−3✓
                    𝐹 = 1 008 𝑁✓                                                                       (3)

      9.3.3         Perpendicular to the diver/Loodreg op die duiker ✓                                 (1)

9.4    𝐹𝑠      𝐹
         = 𝐴1 ✓
       𝐴𝑠       1

       130          𝐹
                    1
       0,002
               = 0,025 ✓

       𝐹 = 1,625 × 103 𝑁 ✓                                                                             (3)
                                                                                                      [13]

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(EC/JUNE 2023)              TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2                        11

QUESTION/VRAAG 10

10.1     10.1.1   Refraction/Refraksie (Breking) ✓                                               (1)

         10.1.2   Critical angle/Kritiese hoek ✓                                                 (1)

         10.1.3   Total Internal Reflection/Totale Interne Weeerkaatsing ✓                       (1)

         10.1.4   When light is approaching the less dense medium from the more
                  dense medium ✓✓
                  Wanneer die lig vanaf ŉ minder digte medium in ŉ meer digte
                  medium beweeg. ✓✓

                  If the incidence angle is larger than the critical angle. ✓✓
                  Indien die invalshoek groter as die kritiese hoek is. ✓✓                       (4)

         10.1.5   (Any 3/enige 3) ✓✓✓
                  • Fibre optic cables in telecommunications/Optiese veselkabels
                     in telekommunikasie.
                  • Medical applications/Mediese toepassings
                  • Decoration/Versiering
                  • Data transmission/Data oordrag
                  • Providing internet facilities to entire world/Verskaf
                     internetfasiliteite aan die hele wêreld.                                    (3)

         10.2.1   99,5 MHz = 99,5 x 106 (Hz) ✓✓                                                  (2)

         10.2.2   POSITIVE MARKING FROM 10.2.1/POSITIEWE NASIEN VANAF
                  10.2.1
                  𝑐 = 𝑓𝜆✓
                  3 × 108 = 99,5 × 106𝜆✓
                  𝜆 = 3,01 𝑚 ✓                                                                   (3)

         10.2.3   Shorter/Korter ✓
                  NEGATIVE MARKING/NEGATIEWE NASIEN
                  From
                  •              ✓ if c is the same/as c dieselfde is ✓
                  •       f108 > f99,5 ✓                                                        (4)
                                                                                               [17]

                                                                          TOTAL/TOTAAL:        150

Copyright reserved/Kopieregvoorbehou                             Please turn over/Blaai om asseblief

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