# Technical Sciences Grade 12 P2 Eastern Cape June 2023 Memo > Grade 12 Technical Sciences Paper 2 memorandum from the Eastern Cape June Exam 2023 (Afrikaans), 7 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/tech-sciences-p2-gr12-memo-june-2023-afr-engl/a92a2ab3-b6d1-4ead-8bae-bee3fa261d39 - Updated: 2026-09-27 - Subject: Technical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2023 - Exam period: Eastern Cape June Exam - Paper: 2 - Curriculum: CAPS - Pages: 7 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Technical Sciences](https://www.hlayiso.com/library/grade-12/technical-sciences) › [Technical Sciences Grade 12 P2 Eastern Cape June 2023 Memo](https://www.hlayiso.com/library/tech-sciences-p2-gr12-memo-june-2023-afr-engl/a92a2ab3-b6d1-4ead-8bae-bee3fa261d39) ## About this document Technical Sciences · Grade 12 · Eastern Cape June Exam · 2023. Memorandum, 7 pages. Read online or download the PDF. 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Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 JUNE/JUNIE 2023 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 75 This marking guideline consists of 7 pages./ Hierdie nasienriglyn bestaan uit 7 bladsye. ### Page 2 Downloaded from hlayiso.com 2 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2023) QUESTION/VRAAG 1 1.1 D ✓✓ (2) 1.2 B ✓✓ (2) 1.3 B ✓✓ (2) 1.4 A ✓✓ (2) 1.5 C ✓✓ (2) [10] QUESTION/VRAAG 2 2.1 Hydrocarbons are organic compounds that consist of hydrogen and carbon only.  Koolwaterstowwe is organiese verbindings wat slegs uit waterstof en koolstof bestaan.  (2) 2.2 2.2.1 C (1) 2.2.2 B (1) 2.2.3 F  and/en G  (2) 2.2.4 A, B and/en D  (1) 2.2.5 A and/en D (2) 2.3 2.3.1 Hex-3-ene / Heks-3-een  (1) 2.3.2 Propanone / Propanoon  (1) 2.3.3 Propyl propanoate / Propielpropanoaat  (2) 2.4 2.4.1  (2) 2.4.2  (1) 2.4.3 C6H14  (1) 2.4.4 Propanone / Propanoon  (1) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com EC/JUNE/JUNIE 2023) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 3 2.4.5  (2) [20] QUESTION/VRAAG 3 3.1 Homologous series: A series of organic compounds that can be described by the same general formula and where each member differs from the next by a CH2 group.  Homoloë reeks: ʼn Reeks organiese verbindings wat deur dieselfde algemene formule beskryf kan word en waar elke lid van die volgende lid deur ʼn CH2-groep verskil.  (2) 3.2 The greater the molecular mass of organic compounds/alkanes, the lower the vapour pressure.  Hoe groter die molekulêre massa van organiese verbindings/alkane, hoe laer is die dampdruk.  (2) 3.3 London forces/dispersion forces/dipole induced forces  Londen-kragte/Dispersie kragte/dipool-geïnduseerde kragte  (1) 3.4 3.4.1 Propane / Propaan  (1) 3.4.2 Butane / Butaan  (1) 3.4.3 Pentane / Pentaan  (1) 3.5 • Compound C / pentane has 5 carbon atoms which makes it to have a longer chain / greater molecular mass than compound B / butane which has 4 carbon atoms which makes it to have a shorter chain/less molecular mass than compound C. Verbinding C / pentaan het 5 koolstofatome wat maak dat dit ʼn langer ketting/groter molekulêre massa het as verbinding B (butaan) wat 4 koolstofatome het wat maak dat dit ʼn korter ketting/minder molekulêre massa as verbinding C het.  • The greater the molecular mass/longer the chain the stronger the intermolecular forces/London forces in compound C than in compound B, which are weaker.  Hoe groter die molekulêre massa/langer die ketting, hoe sterker is die intermolekulêre kragte/London-kragte in verbinding C as in verbinding B wat swakker is.  Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com 4 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2023) • More energy will be required to overcome intermolecular forces/London forces in compound C than in compound B where less energy will be required to overcome intermolecular forces.  Meer energie sal benodig word om intermolekulêre kragte/Londen kragte in verbinding C te oorkom as in verbinding B waar minder energie benodig sal word om intermolekulêre kragte te oorkom.  • Compound C / pentane will have lower vapour pressure than compound B / butane which will have a higher vapour pressure than compound C.  Verbinding C (pentaan) sal laer dampdruk hê as verbinding B (butaan) wat ʼn hoër dampdruk as verbinding C sal hê.  OR/OF • Compound B / butane has 4 carbon atoms which makes it to have a shorter chain / lesser molecular mass than compound C / pentane which has 5 carbon atoms which makes it to have a longer chain/greater molecular mass than compound B.  Verbinding B / butaan het 4 koolstofatome wat dit ʼn korter ketting maak/kleiner molekulêre massa het as verbinding C (pentaan) wat 5 koolstofatome het wat veroorsaak dat dit ʼn langer ketting/groter molekulêre massa as verbinding B het.  • The lesser the molecular mass / shorter the chain the weaker the Intermolecular forces / London forces in compound B than in compound C which are stronger.  Hoe kleiner die molekulêre massa/korter die ketting hoe swakker is die Intermolekulêre kragte/London-kragte in verbinding B as in verbinding C wat sterker is.  • Compound B / butane will have higher vapour pressure than compound C / pentane which will have lower vapour pressure than Compound B.  Verbinding B (butaan) sal hoër dampdruk hê as verbinding C (pentaan) wat 'n laer dampdruk as verbinding B sal hê.  (4) 3.6 3.6.1 C (1) 3.6.2 A (1) 3.6.3 C (1) [15] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com EC/JUNE/JUNIE 2023) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 5 QUESTION/VRAAG 4 4.1 A / butane/butaan  (1) 4.2 It is a gas at room temperature / at 25 °C. Dit is ʼn gas by kamertemperatuur / by 25 °C.  (2) 4.3 Lower than/Laer as:  2-methylpropane/2-metielpropaan: • More branching/Molecules more compact /Smaller surface area (over which the intermolecular forces act.)  • Meer vertakking/Molekules meer kompak/Kleiner oppervlakte (waaroor die intermolekulêre kragte inwerk.)  • Weaker/less intermolecular forces.  • Swakker/minder intermolekulêre kragte.  • Less energy needed to overcome intermolecular forces. • Minder energie benodig om intermolekulêre kragte te oorkom. OR/OF Lower than/Laer as:  Compound A/butane / Verbinding A/butaan: • Is less branched/has less compact molecules/has larger surface area (over which intermolecular forces act).  • Is minder vertak/het minder kompakte molekules/het groter oppervlakte (waaroor intermolekulêre kragte inwerk). / • Stronger/more intermolecular forces.  • Sterker/meer intermolekulêre kragte • More energy needed to overcome intermolecular forces.  • Meer energie benodig om intermolekulêre kragte te oorkom. (4) 4.4 Butane and 2-methylpropane are chain isomers because they have the same molecular formula, but different types of chains.  Butaan en 2-metielpropaan is ketting-isomere  omdat hulle dieselfde molekulêre formule het, maar verskillende tipes kettings.  (2) 4.5 4.5.1 • Compound B has weaker dipole-dipole intermolecular forces whereas compound C has a stronger hydrogen bond.  • Verbinding B het swakker dipool-dipool intermolekulêre kragte terwyl verbinding C ʼn sterker waterstofbinding het. • Compound B contains a carbonyl group/O atom (bonded to C atom) and is a polar (molecule)/dipole whereas compound C has one site for hydrogen bonding.  • Verbinding B bevat ʼn karbonielgroep/O-atoom (gebind aan C- atoom) en is ʼn polêre (molekule)/dipool, terwyl verbinding C een plek vir waterstofbinding het. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com 6 TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 (EC/JUNE/JUNIE 2023) • More energy will be required to overcome stronger hydrogen bond in compound C whereas less energy will be required to overcome weaker dipole-dipole intermolecular forces in compound B.  • Meer energie sal benodig word om sterker waterstofbinding in verbinding C te oorkom, terwyl minder energie benodig sal word om swakker dipool-dipool intermolekulêre kragte in verbinding B te oorkom. • Therefore, compound C will have a lower vapour pressure than compound B.  • Daarom sal verbinding C ʼn laer dampdruk as verbinding B hê. (4) 4.5.2 B (1) 4.5.3 C (1) 4.5.4 B (1) [16] QUESTION/VRAAG 5 5.1 5.1.1 Addition reaction/hydrohalogenation  Addisiereaksie/hidrohalogenering  (1) 5.1.2 Substitution reaction/hydrolysis  Substitusiereaksie/hidrolise  (1) 5.1.3 Addition reaction/hydration  Addisiereaksie/hidrasie  (1) 5.2 5.2.1 Alcohol / Alkohol  (1) 5.2.2 Mild heat / Ligte/matige hitte  (1) 5.2.3  balanced (3) 5.3  (2) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com EC/JUNE/JUNIE 2023) TECHNICAL SCIENCES P2/TEGNIESE WETENSKAPPE V2 7 QUESTION/VRAAG 6 6.1 6.1.1 p-type material / p-tipe materiaal  (1) 6.1.2 n-type material / n-tipe materiaal  (1) 6.1.3 Free holes that are positively charged.  Vry holtes wat positief gelaai is . (1) 6.1.4 Free electrons that are negatively charged. 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