# Technical Sciences Grade 12 P1 Eastern Cape Mock 2022 Memo > Grade 12 Technical Sciences Paper 1 memorandum from the Eastern Cape Mock Exam 2022, 9 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/technical-sciences-p1-memo-gr12-sept2022-eng-afr/63e8758d-6c7e-4512-90dd-949637187c34 - Updated: 2026-09-27 - Subject: Technical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2022 - Exam period: Eastern Cape Mock Exam - Paper: 1 - Curriculum: CAPS - Pages: 9 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Technical Sciences](https://www.hlayiso.com/library/grade-12/technical-sciences) › [Technical Sciences Grade 12 P1 Eastern Cape Mock 2022 Memo](https://www.hlayiso.com/library/technical-sciences-p1-memo-gr12-sept2022-eng-afr/63e8758d-6c7e-4512-90dd-949637187c34) ## About this document Technical Sciences · Grade 12 · Eastern Cape Mock Exam · 2022. Memorandum, 9 pages. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE/ NASIONALE SENIOR SERTIFIKAAT SENIOR SERTIFIKAAT GRADE/GRAAD 12 SEPTEMBER 2022 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 MARKING GUIDELINE/NASIENRIGLYN MARKS/PUNTE: 150 This marking guideline consists of 9 pages. Hierdie nasienriglyn bestaan uit 9 bladsye. ### Page 2 Downloaded from hlayiso.com 2 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 1 1.1 B  (2) 1.2 B  (2) 1.3 C  (2) 1.4 A  (2) 1.5 D  (2) 1.6 C  (2) 1.7 B  (2) 1.8 D  (2) 1.9 C  (2) 1.10 D  (2) [20] QUESTION/VRAAG 2 2.1 The block has resistance to its state of rest (and/or) motion.  Die blok oefen weerstand uit op sy toestand van rus (en/of) beweging.  (2) 2.2 When a net force acts on an object, the object will accelerate in the direction of the net force.  Acceleration is directly proportional to the net force and inversely proportional to the mass of the object.  Indien ʼn netto krag op ʼn voorwerp inwerk, versnel die voorwerp in die rigting van die netto krag.  Die versnelling is direk eweredig aan die netto krag en omgekeerd eweredig aan die massa van die voorwerp.  (2) 2.3 OPTION/OPSIE 1 OPTION/OPSIE 2 FN FN f f FX Fapplied/toegepas Fapllied/toegepas Fapplied/toegepas FY Fg Fg Acceptable Forces and Labels Aanvaarbare Kragte en Byskrifte FN / N Normal Force FN / N Normaalkrag Fg / W / W g Weight Fg / W / W g Gewig Ff / f Frictional Force Ff / f Wrywingskrag Fapplied / Fa Applied Force Ftoeg / Fa Toegepaste krag (5) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 3 2.4 OPTION/OPSIE 1 OPTION/OPSIE 2 FAH = F cos θ  Fnet = ma  = 42 cos 60̊  (42cos60̊)  + (-10) + (-6)  = 2,4a  = 21 N a = 2,08 m.s-2  Fnet = FAH + FY + Ff = 21 + (-10) +(-6)  =5N Fnet = ma  5 = 2,4 a  a = 2,08 m.s-2  (5) [14] QUESTION/VRAAG 3 3.1 3.1.1 A system on which the net external force acting on the system is zero. / No net external forces  ʼn Sisteem waarop die netto eksterne kragte wat daarop inwerk nul is./ Geen netto eksterne kragte  (2) 3.1.2 NO / NEE  (1) 3.1.3 OPTION/OPSIE 1 OPTION/OPSIE 2 ∑pinitial = ∑pafter (Σ pvoor =Σ pna) pi = mv (Any formula/Enige formule)  miv1i + m2v2i = mfvf = (2 x 10 ) (140)  -3 = 0,28 kg m·s-1 (2x10-3)(140)  + 0 = (58x10- 3)v  f pafter/na = mv pafter/na = (56 + 2) x 10-3 vafter/na vf = 4,83 m.s-1 to the right / na regs  ∑pinitial = ∑pafter 0,28 = (56 + 2) x 10-3 vafter/na  vafter/na = 4,83 m.s-1 to the right/na regs  (5) 3.2 3.2.1 Impulse is the product of the net force acting on an object and the time the net force acts on the object.  Impuls is die produk van die netto krag wat op ʼn voorwerp inwerk en die tyd waarin die krag op die voorwerp inwerk.  (2) 3.2.2 Fnet∆t = ∆p  OR/OF Fnet∆t = ∆p  -1,6 x 10 -3∆t  = 800 (0 – 20)  1,6 x 10 -3∆t = 800 (20–0 ) ∆t = 0,1 s  ∆t = 0,1 s  (2/4) (4) 3.2.3 SMALLER THAN/KLEINER AS  The mattresses offer a longer contact time  For the same change in momentum  the longer the time of contact the smaller the force  Die matrasse bied ʼn langer kontaktyd.  Vir dieselfde verandering in momentum,  hoe langer is die kontaktyd hoe kleiner is die krag.  (4) [18] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com 4 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 4 4.1 4.1.1 Ability to do work.  Vermoë om arbeid te verrig.  (2) 4.1.2 Weight /Gravitational force Normal  Gewig / Gravitasiekrag Normaal  (2) 4.1.3 Wgirl = F.∆x.cosθ  / Wmeisie = F.∆x.cos𝜃  W= (20)(0,2)cos 0˚  W=4J (3) 4.1.4 POSITIVE MARKING FROM QUESTION 4.1.3 POSITIEWE MERK VAN VRAAG 4.1.3 OPTION/OPSIE 1 OPTION/OPSIE 2 Ff = µ N = µ(mg)  Fnet = -f + F Any one / Enige een = 0,1 (6,5 x 9,8)  Fnet = µN + F  = 6,37 N Fnet = µmg + F W f = f.∆x.cosθ Fnet =(0,1)(6,5)(9,8) + 20  = (6,37)(0,2)cos 180o  Fnet = 13.63 N = - 1,27 J Wnet = Fnet. ∆x. cosθ Wnet = W girl + Wf Wnet = (13,63)(0,2) cos 0̊  = 4 + (- 1,27)  Wnet = 2,73J  = 2,73 J  (5) 4.2 4.2.1 The total mechanical energy (sum of gravitational potential energy and kinetic energy) in an isolated system remains constant.  Die totale meganiese energie (som van die gravitasie potensiële energie en kinetiese energie) in ʼn geïsoleerde sisteem bly konstant.  (2) 4.2.2 (Ek + Ep )top/bo = (Ek + Ep )bottom/onder  1 (0+(1500)(9,8)(3) = (1500)(9,8)(1)+ 2 (1500)v2  44100 =14 700+750v2 ∴v = 6,26 m s-1  (4) 4.3 P ave/gem =Fvave/gem  1 Pave/gem =(5×103 (72× 3,6 )  Pave/gem = 1 x 10 5 W 746 W = 1 hp (pk)  1× 105 𝑊 = 134,05 hp  134,05 pk (4) [22] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 5 QUESTION/VRAAG 5 5.1 5.1.1 Within the limit of elasticity,  stress is directly proportional to the strain.  Binne die grense van elastisiteit,  is druk direk eweredig aan die rekking.  (2) 5.1.2 𝐹 𝛿= 𝐴 6000  𝛿= 5 × 10−4 = 1,2 x 107 N.m-2/ Pa ∆𝑙 𝜀 = 𝐿  0,0024  𝜀 = 1 = 0,0024 δ K = ε 1,2 × 107 K =  0,0024 K = 5 × 109 N ∙ m−2 / Pa  (7) 5.2 5.2.1 B (1) 5.2.2 Viscosity is rated as 10 at 0°C  W is Winter  Viskositeit word gegradeer as 10 by 0° C  W is Winter  (2) 5.3 5.3.1 Pascal's law states that in a continuous liquid at equilibrium, the pressure applied at a point is transmitted equally to the other parts of the liquid.  Pascal se wet sê dat in ʼn kontinue vloeistof in ewewig die druk wat by enige punt toegepas word eweredig na die ander dele van die vloeistof versprei word.  (2) 5.3.2 OPTION/OPSIE 1 OPTION/OPSIE 2 F1 F2 F1 F2 =  =  A1 A 2 A1 A 2 260  F2 = π(80×10−3 )2  260  F2 π(20×10−3 )2  π (40×10−3 )2 = π (160×10−3 )2 F2 = 4160 N   4 4 F2 = 4160 N  OPTION/OPSIE 3 OPTION/OPSIE 4 A1 = π𝑟 2 = π(20 × 10−3 )2 A1 = 4 = π𝑑2 π (40×10−3 )2 = 1,257 × 10−3 𝑚2  4 = 1,257 × 10−3 𝑚2  2 π𝑑2 π (160×10−3 ) A2 = π𝑟 2 = π(80 × 10−3 )2 A2 = 4 = 4 = 0,02𝑚2 = 0,02𝑚2 F1 F2 F1 F = A2  =  A1 2 A1 A2 260 F2 = 0,02  260 F 1,257×10−3 2 = 0,02  F2 = 4160 N  1,257×10−3 F2 = 4160 N  (4) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com 6 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) 5.3.3 Bulldozer working system/ Stootskraper se werekende remme Any three Hydraulic power breaks Enige drie Hidroliese krag remme  Dentists chair /Tandarts-stoel Hydraulic lifts/Hidroliese hysers (3) [21] QUESTION/VRAAG 6 6.1 6.1.1 The amount of charge stored per volt.  Die hoeveelheid lading wat per volt gestoor word.  (2) 6.1.2 𝜀0 𝐴 𝐶=  𝑑 (8,85 × 10−12 )(4 × 10−4 ) 𝐶=  0,06 = 5 x 10 -14 V  (3) 6.1.3 Size of the conductors/plates/Grootte van die geleiers/plate The size of gap between conductors/plates/Grootte van spasie tussen geleiers/plate The type of dielectric material/Tipe diëlektriese materiaal (ANY TWO / ENIGE TWEE ) (2) 6.2 6.2.1 Rate of doing work / Tempo waarteen arbeid verrig word  (2) OR/OF Work done per unit time/werk verrig per eenheidtyd 6.2.2 OPTION/OPSIE 1 OPTION/OPSIE 2 1 1 1 R1 ×R2 = +  RP =  Rp R1 R2 R1 +R2 1 1 1 12×14 = +  RP =  Rp 12 4 12+14 Rp =3 Ω  Rp = 3 Ω  (3) 6.2.3 P = I2R  50 = I2 (3)  I = 4,08 A 𝑉 R=  𝐼 8 R=  4,08 R = 2,01 Ω  (5) 6.2.4 INCREASES  Total resistance of the circuit decreases  TOENEEM  Totale weerstand van die stroombaan neem af.  (3) 6.2.5 EMF/emf EMK/emk  (1) [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 7 QUESTION/VRAAG 7 7.1 7.1.1 The number of field lines perpendicular to a given surface area.  Die aantal veldlyne loodreg tot die gegewe oppervlak area.  (2) 7.1.2 Φ = ∆BA  Accept/Aanvaar = (Bf - Bi)A = (1-0,5)(0,5 x 0,5)  = 0,125 Wb ∆Φ 𝜀 = −𝑁  Δ𝑡 0,125  𝜀 = −5 10  = 0,06 V  Accept/Aanvaar 6,25 x 10-2 V (6) 7.2 7.2.1 DC motor/GS-motor  Accept Motor/Aanvaar Motor (1) 7.2.2 Electrical energy to mechanical energy  Elektriese energie na meganiese energie  (2) 7.2.3 Ensure electrical contact  Verseker elektriese kontak  (1) 7.2.4  Shape/Vorm  Direction/Rigting (2) [14] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com 8 TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 (EC/SEPTEMBER 2022) QUESTION/VRAAG 8 8.1 8.1.1 Breaking of white light into its component colours.  Die opbreek van witlig in sy saamgestelde (komponent) kleure.  (2) 8.1.2 Red (light) / Rooi (lig)  (1) 8.1.3 When speed decreases wavelength decreases proportionally.  Wanneer die spoed afneem, verlaag die golflengte proporsioneel.  (2) 8.2 8.2.1 Converging (lens) / Konvergerende (lens)  (1) 8.2.2 F 2F 2F F Image/Beeld Object/Voorwerp Marking criteria/Nasienkriteria Mark allocation Punte- toekenning Focal length is 40mm  Brandpunt afstand is 40 mm Object height and distance  Voorwerp hoogte (40 mm) en afstand (25 mm) Ray line through midpoint of a lens  Ligstraal deur middelpunt van die lens Ray line through focal point on the other side of a  lens/Ligstraal deur die brandpunt aan die anderkant van die lens Correct range of image/Korrekte gebeid vir beeld  Height/Hoogte (105‒110 mm) Distance from lens/Afstand vanaf lens (68‒73 mm) Arrows (at least one per light ray)  Pylpunte (ten minste een per ligstraal) (7) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com (EC/SEPTEMBER 2022) TECHNICAL SCIENCES P1/ TEGNIESE WETENSKAPPE V1 9 8.3 8.3.1 Radio waves/Radiogolwe  (1) 8.3.2 X-rays/X-strale  (1) 8.3.3 Packets of energy of light / Pakkies ligenergie.  (1) 8.4 8.3.4 hc E=  λ (6,63×10-34 )(3×108 )  E= 1 000×10-9  E=1,989×10-19 J ≈ 1,99×10-19 J  (4) [20] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ## Related documents - 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