# Technical Sciences Grade 12 Paper 1 NSC November 2023 Memo > Grade 12 Technical Sciences Paper 1 memorandum from the NSC November Exam 2023, 14 pages. Read online or download the free PDF. - Page: https://www.hlayiso.com/library/technical-sciences-p1-nov-2023-mg-eng-afr/3b5468b8-fa34-4c00-bf14-e84b41c3e576 - Updated: 2026-10-29 - Subject: Technical Sciences - Grade: Grade 12 - Document type: Memorandum - Year: 2023 - Exam period: NSC November Exam - Paper: 1 - Curriculum: CAPS - Pages: 14 Breadcrumbs: [Home](https://www.hlayiso.com/) › [Library](https://www.hlayiso.com/library) › [Grade 12](https://www.hlayiso.com/library/grade-12) › [Technical Sciences](https://www.hlayiso.com/library/grade-12/technical-sciences) › [Technical Sciences Grade 12 Paper 1 NSC November 2023 Memo](https://www.hlayiso.com/library/technical-sciences-p1-nov-2023-mg-eng-afr/3b5468b8-fa34-4c00-bf14-e84b41c3e576) ## About this document Technical Sciences · Grade 12 · NSC November Exam · 2023. Memorandum. Read online or download the PDF. Read it free online on the page above; download the PDF from there. ## Document text Text extracted from the PDF. Layout, diagrams and tables may not survive extraction. ### Page 1 Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12 /GRAAD 11 TECHNICAL SCIENCES P1 TEGNIESE WETENSKAPPE V1 NOVEMBER 2023 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 These marking guidelines consist of 14 pages. Hierdie nasienriglyne bestaan uit 14 bladsye. Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 2 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 2 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 1/VRAAG 1 1.1 B/D  (2) 1.2 B  (2) 1.3 A  (2) 1.4 B  (2) 1.5 D  (2) 1.6 D  (2) 1.7 C  (2) 1.8 B  (2) 1.9 C  (2) 1.10 B  (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 3 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 3 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 2/VRAAG 2 2.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2  N  N TH/Tx 165 N fk  165 N fk   for both T TV/Ty components/ vir beide Fg komponente Fg ACCEPTABLE LABELS/ NOTES/ AANVAARBARE ETIKETTE: AANTEKENINGE: N/FN: Normal/Normaal ONE mark for each force Fg/w: Force due to gravity/weight/ represented by an arrow with a Krag weens swaartekrag/ correct label. gewig Penalise ONCE for each of the following:/EEN punt vir elke krag wat FA/165 N: Applied force/Toegepaste deur 'n pyltjie met 'n korrekte byskrif krag aangedui word. T/tension/spanning/FT: Force in Penaliseer EEN KEER vir elk van die string/ Krag in tou volgende: fk,f,Ff,fw : kinetic friction/frictional  No arrows/Geen pyltjies force/ kinetiese wrywing/  There is no dot./Daar is nie 'n kol wrywingskrag nie.  Gap between the line and the dot/Gaping tussen die lyn en die kol  Dotted lines are used./Stippellyne word gebruik.  A force diagram is given./ 'n Kragtediagram word gegee. (5) 2.2 When a net/resultant force is applied to an object of mass, m, it accelerates the object in the direction of the net force. The acceleration is directly proportional to the net/resultant force and inversely proportional to the mass of the object./ Wanneer 'n netto/resulterende krag op 'n voorwerp met massa, m, toegepas word, versnel dit die voorwerp in die rigting van die netto krag. Die versnelling is direk eweredig aan die netto/resulterende krag en omgekeerd eweredig aan die massa van die voorwerp. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 4 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 4 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 2.3 For 220 kg block/Vir 'n 220 kg-blok: Fnet/netto = ma  165 – Tcos30° − 35 = 220 × 0,4  T = 48,498 or 48,50 N  Accept/Aanvaar: 48,28 N (4) 2.4 POSITIVE MARKING FROM 2.3/POSITIEWE NASIEN VANAF 2.3 For a 75 kg block/Vir 'n 75 kg-blok: Fnet/netto = ma T H – fk = ma any one/enige een 48,50 cos 30° – fk = (75)(0,4)  fk = 12 N fk = µkN fk = µk (Fg – Tsin30°)  any one/enige een 12= µk (735 – 24,25)  µk = 0,02/0,017  (7) 2.5 Increases/Toeneem (1) NEGATIVE MARKING FROM 2.5/NEGATIEWE NASIEN VANAF 2.5 2.6 If the string joining the blocks is horizontal/Indien die tou wat die twee blokke verbind, horisontaal is:  Magnitude of the normal force increases./Grootte van die normaalkrag neem toe.  Frictional force is directly proportional to the normal force./Wrywingskrag is direk eweredig aan die normaalkrag. (2) [21] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 5 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 5 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 3/VRAAG 3 3.1.1 Total linear momentum of an isolated system remains constant  in magnitude and direction. Totale lineêre momentum van 'n geïsoleerde/geslote stelsel bly konstant in grootte en rigting. (2)  3.1.2 Δx Δx v =  vQ= p Δt Δt 0,05 0,1 =  =  0,5 0,5 = 0,1 m∙s-1  = 0,2 m∙s-1  (5) POSITIVE MARKING FROM 3.1.2/POSITIEWE NASIEN VANAF 3.1.2 3.1.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Ʃpafter/na = mvfP + mvfQ  Ʃpbefore/voor = Ʃpafter/na  = 2m(-0,1) + m(0,2)  0 = 2m(-0,1) + m(0,2)  = 0 (kg∙m∙s-1) = 0 (kg∙m∙s-1) (3) 3.1.4 Conserved/Behoue Ʃpbefore/voor = Ʃpafter/na/The system is isolated/the surface is frictionless./ Total momentum (before) collision is equal to total momentum (after) collision. Die stelsel is geïsoleerd/die oppervlak is wrywingloos. Totale momentum (voor) botsing is gelyk aand die totale momentum (na) botsing. (2) 3.2.1 Product of the net force and the time the net force acts on an object. / Produk van die netto krag en die tyd wat die netto krag op die voorwerp inwerk. OR/OF Impulse is equal to the change in momentum./Impuls is gelyk aan die verandering in momentum. 3.2.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 DOWN AS - / AFWAARTS AS - DOWN AS + / AFWAARTS AS + Fnet/nettoΔt = Δp Fnet/nettoΔt = Δp Fnet/netto(0,05) = 0,6 (10 –15) Fnet/netto(0,05)= 0,6 (-10–15) Fnet/netto = 300 N, upwards Fnet/netto = -300 N, Fnet/netto = 300 N, upwards/ afwaarts Accept/Aanvaar: Fnet/netto = ma Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 6 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 6 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne OPTION 3/OPSIE 3 OPTION 4/OPSIE 4 DOWN AS - / AFWAARTS AS - DOWN AS + / AFWAARTS AS + ∆v ∆v a= a= ∆t ∆t 10-(-15) -10-15 = = 0,05 0,05 = 500m∙s-2 = -500m∙s-2 Fnet = ma Fnet = ma = 0,6 (500) = 0,6 (-500) = 300 N upwards/afwaarts = -300 N = 300 N upwards/opwaarts (5) 3.3 Safety/seat belts/Veiligheidsgordels Airbags/Lugsakke Crumple zones/Frommelsone (Any correct answer/Enige korrekte antwoord) (3) [22] QUESTION 4/VRAAG 4 4.1 The product of the force applied on an object and the displacement in the direction of the force. / Die produk van die krag toegepas op 'n voorwerp en die verplasing in die rigting van die krag. (2) 4.2 W = F∆xcosθ  (Any one/Enige een) = mg∆ycos0° = (250)(9,8)(50)(1) = 122 500 J (3) POSITIVE MARKING FROM 4.2/POSITIEWE NASIEN VANAF 4.2 4.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Pave/gemid = Fvave/gemid  ∆x = (250)(9.8)(25)  v= ∆t = 61 250 W 50 25= ∆t 61 250 Pave/gemid =  ∆t=2s 746 W = 82,1 hp  P=  ∆t 122500 P=  2 P=61250 W 61 250 Pave/gemid =  746 = 82,1 hp  (4 Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 7 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 7 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 4.4.1 The total mechanical energy of an isolated system remains constant./ Die totale meganiese energie van 'n geïsoleerde stelsel bly konstant. OR/OF The sum of the gravitational potential energy and kinetic energy in an isolated system remains constant./Die som van die gravitasie-potensiële energie en kinetiese energie in 'n geïsoleerde stelsel bly konstant. (2) 4.4.2 Greater than  / Groter as (2) NEGATIVE MARKING FROM 4.4.2/NEGATIEWE NASIEN VANAF 4.4.2 4. 4.3 Mechanical energy on the ground is zero. / Meganiese energie op die (2) grond is nul. 4.4.4 ME top/bo = ME bottom/onder 1 1 any one/enige een ( mvi 2 + mgh) top/bo = ( mv f 2 + mgh) bottom/onder 2 2 1 1 (250)(0) 2 + (250)(9,8)(50) = (250)v f 2 + (250)(9,8)(0)  2 2 v f = 31,30 m∙s (downwards/afwaarts)  -1 (4) [19] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 8 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 8 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 5/VRAAG 5 5.1.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 F1 F2 F =  P=  A1 A 2 A 1000 1000 F2 =   =  1,96 × 10-3 1,96 × 10- 3 4,91× 10- 2 = 510204,08 Pa F2 = 25 051,02 N F P= A F 510204,08 =  4,91× 10- 2 F = 25 051,02 N (4) POSITIVE MARKING FROM 5.1.1/POSITIEWE NASIEN VANAF 5.1.1 5.1.2 Yes/Ja The magnitude of the output force F2 (25 051,02 N) is greater/more than that of the required force of (20 kN). /Die grootte van die uitsetkrag F2 (25 051,02 N) is groter as dié van die vereiste krag van (20 kN). OR/OF 20 kN < 25051,02 N (2) 5.2.1 Stress is the internal restoring force per unit area of a body./ Druk (Spanning) is die interne herstelkrag per eenheidsarea van 'n liggaam. (2) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 9 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 9 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 5.2.2 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 2 F  πd σ= Area = A 4 π(0,03)2 F =  = 4 πd 2  = 706,85 x 10-6 m2 4  4 × 10 3 σ=  F π(0,03) 2 σ=  A  4 4 × 103 σ = 5,66 x 106 Pa σ=  706,85 × 10-6 σ = 5,66 x 106 Pa  OPTION 3/OPSIE 3 OPTION 4/OPSIE 4 Αrea = πr 2 σ= F  Αrea = π(0,015)2 A = 706,86 x 10-6 m2 4 × 103 σ =  π(0,015)2 F σ = 5,66 x 106 Pa σ=  A 4 × 103 Range/Reeks: =  (5657708,63 – 5658842,421) 706,86 × 10 -6 σ= 5,66 x 106 Pa (4) 5.2.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 ∆l ∆l 𝜀=  𝜀=  L L 0188-0,2 188-200 =  =  0,2 0,2 =-0,06 =-0,06 (3) 5.2.4 POSITIVE MARKING FROM 5.2.2 to 5.2.3/POSITIEWE NASIEN VANAF 5.2.2 tot 5.2.3 σ ε  K= 5,66 ×106 =  0,06 = 9,43 x 107 Pa  (3) 5.3 Monograde oil is only suitable for use within a very narrow temperature range. / Monograde oil has one viscosity at all temperatures /Monograad- olie is slegs geskik vir gebruik in 'n baie beperkte temperatuuromvang. Monograad-olie het een viskositeit by alle temperature. (2) [20] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 10 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 10 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 6/VRAAG 6 6.1.1 Reflection/Weerkaatsing (1) 6.1.2 θ1 is equal to θ2 /θ1 is gelyk aan θ2 (1) 6.1.3  The image is of the same size as the object./Die beeld is dieselfde grootte as die voorwerp.  It is formed at the same distance from the mirror as the object./Dit word gevorm op dieselfde afstand vanaf die voorwerp.  It is laterally inverted./Dit is lateraal (sydelings) omgekeerd.  Virtual/Virtueel  The image is upright./Die beeld is regop. (Any two/Enige twee) (2) 6.2.1  The wavelength increases/the speed of light increases./Die golflengte neem toe/die spoed van lig neem toe.  The light ray bends away from the normal/Angle of refraction is greater than the angle of incidence./Die ligstaal buig weg vanaf die normaal/ (2) Brekingshoek is groter as die invalshoek. 6.2.2 The light ray would be reflected back into the water./Die ligstraal sal terug in die water weerkaats (gereflekteer) word. (1) OR/OF Total internal reflection/Totale interne weerkaatsing 6.2.3 air/lug water 50° 50° reflected ray/ incident ray/ geweerkaatste straal invallende straal  treasure box/ skatkis MARKING CRITERIA/NASIENKRITERIA Correct label of reflected ray/Korrekte byskrif van geweerkaatste  straal Correct direction of the reflected ray/Korrekte rigting van die  (3) geweerkaatste straal Incident ray correctly labeled/Korrekte byskrif van invallende  straal [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 11 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 11 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 7/VRAAG 7 7.1.1 Gamma ray/Gammastraal (1) 7.1.2  Highest frequency/shortest wavelength/Hoogste frekwensie/kortste golflengte  Highest energy of the photons/Hoogste energie van die fotone  Highest penetrating ability/Hoogste deurdringvermoë (Any one/Enige een) (1) 7.1.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 hc c=fλ Ephoton/foton =  λ 3 x 10 =f(5 x 10-12) 8 (6,63 × 10-34 )(3 × 108 ) f = 6 x 1019 =  5 × 10-12 E = hf  = 3,978 x 10-14 J  = 6,63 x 10-34 .6 x 1019  =3,978 x 10-14 J  (3) 7.2.1 Convex/Converging (lens)/Konvekse/Konvergerende (lens) (1) 7.2.2 Virtual/Virtueel (1) 7.2.3 NEGATIVE MARKING FROM 7.2.2/NEGATIEWE NASIEN VANAF 7.2.2 The image is formed at a point where the refracted rays appear to converge when extended./Die beeld word gevorm by 'n punt waar die gebreekte strale lyk asof dit konvergeer wanneer dit verleng word. (2) 7.3 Cameras/Kameras Telescopes/Teleskope Binoculars/Verkykers Corrective lenses for Hypermetropia Long sighted/Farsightedness/ Regstellende lense vir Hipermetropie/versiendheid (1) Magnifying glass/Vergrootglas Projector/Projektor Periscope/Periskoop (Any ONE correct answer/Enige EEN korrekte antwoord) [10] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 12 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 12 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 8/VRAAG 8 8.1 εοΑ C=  d (8,85 × 10 -12 )(1× 10 -2 ) = 3 × 10 -3 = 2,95 × 10-11 F Q C=  V 7,08 × 10 -9  2,95 × 10 -11 = V V = 240 V  (5) 8.2  Filter circuits in power supplies/Tunning circuits/Filtreerstroombane in kragtoevoere  Smoothing circuits/Afvlakkingstroombane  Separation of frequencies between the woofer and tweeter/Verdeling van frekwensies tussen die basluidspreker en diskantluidspreker  Power factor correction/improvement in electrical transmission systems/ Arbeidsfaktorregstelling/verbetering in elektriese transmissiestelsels  Energy storage/Energieberging  Remote sensing/Afstandswaarneming  Signal coupling and decoupling/Seinkoppeling en ontkoppeling  Electronic noise filtering/Elektronies geraasfiltrering  Emergency shutdown for computers/Noodafskakeling van rekenaars  Starting capacitors in motors/Aanskakeling van kapasitors in motors (Any correct THREE/Enige korrekte DRIE) (3) [8] Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 13 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 13 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 9/VRAAG 9 9.1 When 220 V is applied to the machine, 5,3 kJ of energy is consumed every second (to convert electrical energy into light and heat energy). /Wanneer 220 V op die masjien toegepas word, word 5,3 kJ energie elke sekonde verbruik (om elektriese energie in lig- en hitte-energie om te skakel). OR/OF The electric welding machine has a resistance that allows a current of 24,3 A to give a power consumption of 5,3 kW./Die elektriese sweismasjien het 'n weerstand wat 'n stroom van 24,3 A toelaat om 'n kragverbruik van 5,3 kW te gee. (2) 9.2.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 P = I2R V2 5,3 × 103 = 24,32 (R)  P=  R R = 8,98 Ω (218,11)2 5,3 × 10 = 3  R R = 8,98 Ω OPTION 3/OPSIE 3 V R=  I 218,11 =  24,3 = 8,98 Ω (3) 9.2.2 POSITIVE MARKING FROM 9.2.1/POSITIEWE NASIEN VANAF 9.2.1 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 W V 2 P=  Δt W= Δt  R W 5,3 ×103 =  (218,11)2 30 × 60 = (30 × 60)  8,98 W = 9 540 000 J  = 9,54 ×106 J OPTION 3/OPSIE 3 OPTION 4/OPSIE 4 W = I2 R∆t  W = VI∆t  = (24,32)(8,98)(30×60)  = (218,11)(24,3)( 30×60) = 9,54 ×106 J = 9,54 ×106 J (3) Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief ### Page 14 Downloaded from hlayiso.com Technical Sciences/P1/Tegniese Wetenskappe/V1 14 DBE/November 2023 NSC/NSS – Marking Guidelines/Nasienriglyne 9.2.3 OPTION 1/OPSIE 1 OPTION 2/OPSIE 2 Cost/Koste = P×∆t×tariff/tarief Cost/Koste= E.Tarifs/Tarief = (5,3)  (0,5)(0,75) 9540000  = R1,99 = × R0,75  3600000 =R 1,99  (3) [11] QUESTION 10/VRAAG 10 10.1 A device that converts mechanical energy into electrical energy/'n Toestel wat meganiese energie in elektriese energie omskakel (2) 10.2 AC/WS (generator)  (1) - - 10.3 AC generators have slip rings./WS-generators het sleepringe. (1) 10.4.1 The number of turns in the secondary coil is greater than the number of turns in the primary coil. /Die aantal windings in die sekondêre spoel is groter as die aantal windings in die primêre spoel. OR/OF (2) The number of turns in the primary coil is less than the number of turns in the secondary coil./ Die aantal windings in die primêre spoel is minder as die aantal windings in die sekondêre spoel. 10.4.2 VS NS =  VP NP VS 80 =  120 40 VS = 240 V  (3) [9] TOTAL/TOTAAL: 150 Copyright reserved/Kopiereg voorbehou ## Related documents - [Technical Sciences P1 Nov 2023 Eng](https://www.hlayiso.com/library/technical-sciences-p1-nov-2023-eng/2088f626-09b7-4c29-a4f7-117697764619) — Technical Sciences · QP · 2023 · Eng - [TECH SCIENCES P1 GR12 MEMO JUN2023 Afr+English](https://www.hlayiso.com/library/tech-sciences-p1-gr12-memo-jun2023-afr-english/18d5d6dd-0e87-4d04-88a2-beb3fa330a5f) — Technical Sciences · Memo · 2023 · Eng - [Technical Sciences P1 (English) Memo](https://www.hlayiso.com/library/technical-sciences-p1-english-memo/036cde07-8a86-4b6d-a9ba-2a4da6e21b9e) — Technical Sciences · Memo · 2023 · Eng - [Technical Sciences P2 Nov 2023 Afr](https://www.hlayiso.com/library/technical-sciences-p2-nov-2023-afr/f67ab486-0ac8-485a-9541-33ba720f15c1) — Technical Sciences · QP · 2023 · Afr - [Technical Sciences P2 Nov 2023 Eng](https://www.hlayiso.com/library/technical-sciences-p2-nov-2023-eng/195537ab-5377-405c-a9be-2d984068833f) — Technical Sciences · QP · 2023 · Eng - [TECHNICAL SC P1 GR12 QP JUNE 2023 English](https://www.hlayiso.com/library/technical-sc-p1-gr12-qp-june-2023-english/1df8dd81-509c-4d57-8cea-9115bf53a1d0) — Technical Sciences · QP · 2023 · Eng ## More from Grade 12 Technical Sciences - [Gr 12 Tech Sci ATP 2023-24](https://www.hlayiso.com/library/gr-12-tech-sci-atp-2023-24/a7a03e64-2e18-4f50-a7fa-6eb1a25136c7) — ATP - [TECH SCIENCES P1 QP GR12 SEPT 2025 ENG watermark](https://www.hlayiso.com/library/tech-sciences-p1-qp-gr12-sept-2025-eng-watermark/27b1584e-b5e6-4d62-a347-46bc297ca3cc) — QP · 2025 · Eng - [TECHNICAL SCIENCES P2 QP GR12 SEPT 2025 - English watermark](https://www.hlayiso.com/library/technical-sciences-p2-qp-gr12-sept-2025-english-watermark/19067998-88e8-4610-89e9-414e4d58ef86) — QP · 2025 · Eng - [Technical Sciences P1 (English) June 2025 Question Paper](https://www.hlayiso.com/library/technical-sciences-p1-english-june-2025-question-paper/1de11ae2-f4a0-4722-b3eb-af00fb6f3f7c) — QP · 2025 · Eng - [Technical Sciences P2 (Afrikaans) June 2025 Question Paper](https://www.hlayiso.com/library/technical-sciences-p2-afrikaans-june-2025-question-paper/d058d4d6-1a04-4407-8a1c-9187d5e524ea) — QP · 2025 · Afr - [Gr 12 Technical Sciences P1 (English) 2025 Question Paper X05](https://www.hlayiso.com/library/grade-12-technical-sciences-2025-gauteng-mock-exam-question-paper-paper-1-english/76123cf3-7f74-429b-8b49-5386459f55c9) — QP · 2025 · Eng ## Collection - [Grade 12 past papers](https://www.hlayiso.com/grade-12/past-papers) --- Hlayiso: free CAPS and IEB past papers, memos, notes and study guides for South African learners. 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