# Physical Sciences Grade 12 P2 Western Cape Mock 2014 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Western Cape Mock Exam 2014 (English), 6 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/wkp-kwod-physc-p2-sept-2014-memo-eng/8f1b68c6-c866-490d-a9d9-9ae6d9caaadf
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2014
- Exam period: Western Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 6

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## About this document

Physical Sciences · Grade 12 · Western Cape Mock Exam · 2014. Memorandum, 6 pages. Read online or download the PDF.

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## Document text

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### Page 1

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         CAPE WINELANDS EDUCATION DISTRICT

                   PHYSICAL SCIENCES P2
                CHEMISTRY MEMORANDUM
                     SEPTEMBER 2014

MARKS: 150
TIME: 3 hours

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QUESTION 1
 1.1 B                                                                             (2)
 1.2 D                                                                             (2)
 1.3 C                                                                             (2)
 1.4 A                                                                             (2)
 1.5 A                                                                             (2)
 1.6 A                                                                             (2)
 1.7 B                                                                             (2)
 1.8 D                                                                             (2)
 1.9 D                                                                             (2)
 1.10 B                                                                        (2)[20]

QUESTION 2
2.1.1 CnH2n+2                                                                             (1)
                                                               H
            H  H    H H                                        |
2.1.2       |   |   | |                                    H H-C-H H 
          H–C—C—C–C-H                    OR               |   |   |
            |   |   | |                                  H–C— C—C-H
            H H-C-H H H                                    |   |   |
                I                                          H H-C-H H
                H                                              I
                                                               H
            2-methylbutane                              2,2-dimethylpropane              (2)

                 H  O H
                 |  ║ |
               H–C— C—C-H
2.1.3            |     |                 functional group whole molecule                 (2)
                 H    H
2.2 The stronger the intermolecular forces, the lower the vapour pressure.
            correct variables   correct relationship
    When IMFs are stronger, it requires more energy to break the IMFs to allow
        molecules to evaporate,     thus fewer molecules evaporate.                       (3)
2.3 (as you go down the table), chain length/molecular size increases, 
     thus strength of Van der Waals IMFs increases  thus vapour pressure decreases (2)
2.4.1 1-butanol has an –OH group  which forms stronger Hydrogen bonding IMFs 
       than the Van der Waals IMFs in pentane                                        (2)
2.4.2 Secondary alcohols are more spheric in shape / have a smaller surface area
       for bonding / molecules cannot get as close to each other  as the more linear
       primary alcohols, thus IMFs are weaker,  thus easier to evaporate.           (2)
2.5 Ethanoic acid  (no positive marking → )                                               (1)
2.6 Ethanoic acid has a lower vapour pressure  than 1-propanol thus stronger IMFs 
    thus more energy will be required to break IMFs.                           (3)[18]

                                                2

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QUESTION 3

3.1 A compound that has one or more double (or triple) bonds between C atoms. (2)
3.2                                                     H      H Br H H H
           H     H       H H H
                                                         |      | l     |    l   l
            |     |       |    l   l
                                                      H – C -- C -- C – C – C – C --H
        H – C -- C ═ C – C – C – C --H
                                          + Br2           |    l     | |    l   l
            |        | |     l   l
                                                         H Br H H H H
           H         H H H H                                                                (3)
3.3 Light/heat                                                                             (1)

3.4.1 Addition (hydrohalogenation)                                                         (1)

3.4.2 Catalyst of strong acid / H2SO4  in (excess water)                                   (1)

3.4.3 (Dilute solution) of strong base (NaOH or KOH)  ( X conc base) , mild heat  (2)

3.4.4 but-2-ene                H H    H                                                    (2)
                                |  |   |  
                              H–C—C═C–C-H
                                |    | |
                                H    H H
3.5.1      ethene                                                                          (1)
3.5.2      addition                                                                    (1)[14]

QUESTION 4
4.1       the change in concentration of reactants or products per unit time.               (1)
4.2.1 concentration                                                                          (1)
4.2.2 reaction rate  (except time)                                                           (1)
4.3.1 5. Repeat the experiment but add 2 ml of HCl and 3ml of distilled water
         6. Repeat the experiment but add 1 ml of HCl and 4ml of distilled water
          HCl volume is changed
          the conc of HCl is changed (water added to keep volume the same)
          the steps indicate a decrease in conc of HCl.                                      (3)
4.3.2 volume of sodium thiosulphate needs to be kept constant / temp constant /
         judgement of when cross disappears needs to be constant (same learner) /
        swirling needs to be the same / stopwatch needs to be started at same time
        in process (any one of the above is correct)                                         (1)
4.4 Sulphur / S.                                                                             (1)
4.5 Experiment 1.                                                                         (1)[9]
                                                  3

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QUESTION 5
5.1 The rate of the forward reaction equals the rate of the reverse reaction              (2)
5.2     Closed                                                                             (1)
5.3.1 turns more orange                                                                   (1)
5.3.2 increases the H+ concentration  which favours the forward reaction                  (2)
5.4                     Kc =       Cr2O72-      
                                [CrO42-]2 [H+]2                                             (2)
5.5 No                                                                                      (1)
5.6 Yellow                                                                                  (1)
                                                               +
5.7 The presence of hydroxide will decrease the conc of H  as they react to form
       water (or increase amount of H2O); according to Le Chatelier’s Principle, this
       will cause the rxn that increases the conc of H+ to be favoured , thus reverse rxn /
       equilibrium shifts to the left.                                                 (3)[13]

QUESTION 6
6.1 Endothermic                                          formulas – if used               (1)
              m 35,9                                       n 0,62
6.2 nNaCl =    =     = 0,62mol _(0,6138mol )          c=     =     = 6,2mol ⋅ dm −3
              M 58,5                                      V   0,1 

               +    −
                          SUBSTITUTION 
    K c = [Na ][Cl ] = (6,2)(6,2) = 38,44 (37,66 if no rounding)                     (6)
6.3 Increase temp. An increase in temp will favour the endothermic rxn which is the
    forward rxn;this will increase the concentration of products, thus KC.                (4)
6.4 Less soluble.                                                                      (1)[12]

QUESTION 7

7.1 NaOH → Na+(aq) + OH-(aq)                 [OH-] = 0,11  (or: conc OH- = conc NaOH)
       Kw = 1x10-14 = [H3O+][OH-]  1x10-14 = [H3O+](0,11)         [H3O+] = 9,09x10-14  ( +→)
      pH = -log[H3O+]  = - log (9,09x10-14) (substitution) = 13,04 
      (Except calculation of pOH and subtracting from 14).                                  (5)
7.2 nNaOH = c x V = 0,11 x 0,0285 = 0,0031 mol  (0,003135 if no rounding off)             (2)
7.3 nacid : nbase = 1:1       nacid = 0,0031 macid in 25cm3 = nxM = 0,0031 x 60 = 0,186g 
       (+→) macid in 100 cm3 = 0,186 x 4 = 0,744g
                                  
                         0,744
       % ethanoic acid =       × 100 = 9,9%  (9,9 – 10 depending on rounding off). (5)[12]
                          7,5

                                                4

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QUESTION 8
8.1 Contact                                                                            (1)
8.2 H2S2O7 / oleum/pyrosulphuric acid / disulphuric acid / fuming sulphuric acid       (1)
8.3 V2O5 / Venadium pentoxide                                                          (1)
8.4 An acid that ionises completely.                                                   (1)
8.5 H2SO4 + 2 H20 → SO42- (aq) + 2 H3O+ (aq) (LHS  RHS bal)                          (3)
8.6 H3O+                                                                               (1)
8.7 ampholite                                                                           (1)
8.8 diprotic                                                                            (1)
8.9.1 oxidising agent                                                                   (1)
8.9.2 Copper was oxidised to Cu-ions  thus lost electrons                            (2)
                                                                                      [13]

QUESTION 9
9.1 Chemical energy to electrical energy.                                            (1)
9.2 Temperature of 25 OC / 298 K  Concentrations of 1 mol•dm-3. 
    NOT Pressure of 1 atm or 101,3 kPa.                                               (2)

9.3 Mg (magnesium)                                                                   (1)

9.4   Mg (s) →      Mg2+ + 2e                  (LHS RHS bal)                       (3)
         formulas – if used
             m 0,96                                  2
9.5 nMg =      =    = 0,04mol        nFe = n Mg ×     = 0,027 
             M   24                                  3

      mFe = n × M = 0,027 × 56 = 1,51g  (1,49 if no rounding off earlier)            (5)

9.6 Eθcell   =   Eθreduction - Eθoxidation    (or other equivalent eqn)

             = - 0,04  - (- 2,37) 

             = 2,33 V.                    YES, bulb will light up                   (5)

9.7 Increase                                                                         (1)

9.8 Decrease  (neg →); an increase in [Mg2+] will inhibit the forward reaction /
    will favour the reaction that decreases [Mg2+]  and thus voltmeter reading will
    decrease                                                                      (2)[20]

                                                5

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QUESTION 10

10.1   bauxite                                                                   (1)
10.2   Electrolytic                                                              (1)
10.3   Cathode                                                                   (1)
10.4   Negative                                                                  (1)
10.5   2 O2-  → O2(g) + 2e-                                                     (2)
10.6 DC.  (neg→) To produce Al (product), the reaction must not be reversed 
     (which is what would happen if power supply was AC).                      (2)[8]

QUESTION 11

11.1 Haber process                                                               (1)

11.2 Reaction rate would be too slow.                                            (1)

11.3 NO                                                                           (1)

11.4    4 NH3 + 5 O2 → 4 NO + 6 H2O (LHS RHS )                                  (2)

11.5 NH4NO3                                                                      (1)

11.6 Can cause “blue-baby” syndrome, stomach cancer; reproductive problems,
     birth defects, endocrine, immune and nervous system malfunctions            (1)

            5
11.7 18,75 =  x 30  x= 8.  thus K = 1 or N:P:K = 5:2:1                     (4)[11]
           x

                                          6

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