# Physical Sciences Grade 12 P2 Western Cape Mock 2018 Memo

> Grade 12 Physical Sciences Paper 2 memorandum from the Western Cape Mock Exam 2018, 14 pages. Read online or download the free PDF.

- Page: https://www.hlayiso.com/library/wp-2018-paper-2-memorandum/c07b8ab9-482e-483c-bfbb-cd8011c06d7c
- Updated: 2026-09-27
- Subject: Physical Sciences
- Grade: Grade 12
- Document type: Memorandum
- Year: 2018
- Exam period: Western Cape Mock Exam
- Paper: 2
- Curriculum: CAPS
- Pages: 14

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## About this document

Physical Sciences · Grade 12 · Western Cape Mock Exam · 2018. Memorandum, 14 pages. Read online or download the PDF.

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## Document text

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                                                        1

                        MEMORANDUM
PHYSICAL SCIENCE                     SEPTEMBER 2018

CW PLC COMMON PAPER 2                      TOTAL: 150

QUESTION 1

1.1    B                                                (2)

1.2    A                                                (2)

1.3    B                                                (2)

1.4    B                                                (2)

1.5    A                                                (2)

1.6    A                                                (2)

1.7    C                                                (2)

1.8    A                                                (2)

1.9    D                                                (2)

1.10   C                                                (2)

                                                        [20]

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                                                                         2

QUESTION 2

2.1   2.1.1   Carboxyl (group)/Karboksiel(groep)                         (1)

      2.1.2   Ketones/Ketone                                             (1)

      2.1.3   Addition/Addisie                                           (1)

2.2   2.2.1   Ethene/Eteen                                               (1)

      2.2.2   4-methyl   hexan-3-one        (no space/geen spasie)

              4-metielheksan-3-oon

              OR/OF

              4-methyl   -3-hexanone

              4-metiel-3-heksanoon                                       (2)

      2.2.3   4-ethyl-2,2-dimethyl   hexane     (no space/geen spasie)

              4-etiel-2,2-dimetielheksaan                                (2)

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                                                                                 3

      2.2.4   But-2-ene/But-2-een OR/OF 2-Methyl prop-1-ene/2-Metielprop-1-een   (1)

2.3           Carbon dioxide/CO2/Koolstofdioksied

              Water/H2O                                                          (2)

2.4   2.4.1

                                                                                 (2)

      2.4.2   ANY ONE/ENIGE EEN:
              Two marks or zero./Twee punte of nul.                              (2)

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                                                      4

2.5   2.5.1   E                                       (1)

      2.5.2   Substitution/halogenation/bromination
              Substitusie/halogenering/brominering    (1)

      2.5.3

                                                      (2)

                                                      [19]

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                                                                                       5

QUESTION 3

3.1.1   Boiling point/kookpunt                                                         (1)

3.1.2   Chain length/kettinglengte   or   molecular mass/molekulêre massa              (1)

3.1.3   Boiling point increases as the chain length / molecular mass of alkane         (1)
        increases

3.1.4   As the molecular mass and chain length of the alkanes increases/Soos die
        molekulêre mass en kettinglengte van die alkane toeneem
        the area for the London force to establish becomes greater/neem die area
        waarin die Londonkragte ingestel word, groter.                                 (3)
        So, the London forces between alkane molecules increases/dus neem die
        sterkte van die Londonkragte tussen die alkaanmolekule toe.
        More energy is therefore needed to overcome the London forces/meer
        energie is nodig om die Londonkragte te oorkom.
3.2.1   Degree of branching/mate van vertakking or all the molecules are straight
        chain/not branched/al die molekule is reguitketting/nie-vertak                 (1)

3.2.2   The intermolecular forces in alkanes are weak London forces/die
        intermolekulêre kragte in alkane is swak Londonkragte,
        And the intermolecular forces in alcohols are strong hydrogen bond/die         (3)
        intermolekulêre kragte in alkohole is sterk waterstofbinding.
        More energy is needed to overcome the intermolecular forces in the
        alcohols/meer energie is nodig om die intermolekulêre kragte in die alkohole
        te oorkom.
3.3.1   ethanol/ethanol                                                                (1)

3.3.2   Propan-1-ol                                                                    (1)

                                                                                       [12]

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QUESTION 4

4.4.1
        2-methylbut-1-ene / 2-metielbut-1-een   (2)

4.1.2   ethanol/etanol                          (1)

4.1.3

                                                (2)

4.1.4   H2O / water                             (1)

4.2.1

                                                (5)

4.2.2   Functional/funksionele                  (1)

                                                [12]

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QUESTION 5

5.1     ONLY ANY TWO OF/SLEGS ENIGE TWEE VAN:
        ● Increase temperature./Verhoog die temperatuur. ✓
        ● Increase concentration of acid./Verhoog die konsentrasie van die suur. ✓       (2)
        ● Add a catalyst./Voeg ‘n katalisator by.

5.2     ONLY ANY TWO OF/SLEGS ENIGE TWEE VAN:
        ● Change in concentration of products/reactants ✓ per (unit) time. ✓
           Verandering in konsentrasie van produkte/reaktanse per (eenheids)tyd.
        ● Rate of change in concentration. ✓✓
          Tempo van verandering in konsentrasie.
        ● Change in amount/number of moles/volume/mass of products or reactants per
           (unit) time.
           Verandering in hoeveelheid/getal mol/volume/massa van produkte of reaktanse
           Per (eenheids)tyd.
        ● Amount/number of moles/volume/mass of products formed or reactants used per
          (unit) time.
          Hoeveelheid/getal mol/volume/massa van produkte gevorm of reaktanse gebruik    (2)
          per (eenheids)tyd.

5.3
5.3.1

         Notes/Aantekeninge
         ● Substitution/Instelling ✓✓
         ● Final Answer/Finale Antwoord ✓

         Accept/Aanvaar:

                                                                                         (3)

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5.3.2

                                                                 (3)

5.3.3   POSITIVE MARKING FROM QUESTION 5.3.2.
        POSITIEWE NASIEN VANAF VRAAG 5.3.2.
        1,2 mol∙dm-3 ✓
                                                                 (1)
        Accept range/Aanvaar gebied: 1,15 to/tot 1,25 mol∙dm-3

5.3.4   ● Concentration of reactants decrease. ✓
          Konsentrasie van reaktanse neem af.
        ● Less particles per unit volume. ✓
          Minder deeltjies per volume.
        ● Less effective collisions per unit time. ✓             (3)
          Minder effektiewe botsings per eenheidstyd.

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                                      9

5.3.5

                                      (5)
                                      [19]

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                                                                                           10

QUESTION 6

6.1     When the equilibrium in a closed system is disturbed, the system will re-instate
        a new equilibrium by favouring a reaction that opposes the disturbance.
        Wanneer die ewewig in 'n geslote sisteem versteur word, stel die sisteem 'n
        nuwe ewewig in deur die reaksie wat die versteuring teenwerk, te bevoordeel.       (2)

6.2.1   INCREASES
           ● Increase in pressure favours the reaction that leads to smaller number
             of moles / volume of gas.
           ● Forward reaction is favoured.

        TOENEEM
          ● Toename in druk bevoordeel die reaksie wat tot die kleiner getal mol /
             volume gas lei.
          ● Voorwaartse reaksie word bevoordeel.                                           (3)

6.2.2   DECREASES
          ● An increase in temperature favours the endothermic reaction.
          ● The reverse reaction is favoured.

        AFNEEM
          ● Die voorwaarste reaksie is eksotermies. 'n Toename in temperatuur
             bevoordeel die endotermiese reaksie.
          ● Die terugwaartse reaksie word bevoordeel.                                      (3)

6.3.1   Marking criteria:
           1. Values from graph / Waardes op grafiek
           2. Calculation of n(O2) / Berekening van n(O2)
           3. Calculation of n(O2) reacted / Berekening van n(O2) gereageer
           4. Ratio / verhouding
           5. Equation of Kc / Vergelyking van Kc
           6. Substitution / Substitusie van waardes
           7. Answer / Antwoord

                                      SO2             O2            SO3
         Ratio: / Verhouding            2             1               2

         n start:/ aanvanklik           5             3               0

         n change / veranderd         -2,4           -1,2           +2,4

         n equilibrium / ewewig        2,6           1,8             2,4

         c =n/V                        1,3           0,9             1,2

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                                                                                               (7)

6.3.2   More oxygen added (conc of O2 increased)      / Suurstof word by die sisteem
        gevoeg(konsentrasie van O2 neem toe)                                                   (1)

6.3.3   NO CHANGE.       / geen verandering
                                                                                               (1)

6.3.4      ●   Vertical parallel lines show a sudden increase in rate of both forward and
               reverse reactions at 15 minutes
           ●   Horisontal parallel lines showing a constant higher rate for both forward and
               reverse catalysed reactions after time 15 minutes.     /
           ●   Paralelle vertikale wat ‘n toename in beide voorwaartse en terugwaartse
               reaksies toon by 15 minute
           ●   Horisontale paralelle lyne van beide voorwaartse en terugwaartse reaksie
               wat .n verhoogde reaksietempo toon na 15 minute

                                                                                               (2)

                                                                                               [19]

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QUESTION 7

7.1.1   Sulphuric acid is a strong acid OR ionizes completely
        Swawelsuur is ‘n sterk suur OF ioniseer volledig                                    (1)

7.1.2   Proton acceptor/protonakseptor                                                      (1)

7.1.3                                                                                       (1)
        HSO4 −

7.1.4   Sulphate / sulfaat                                                                  (1)

7.2.1   endpoint/endpunt/omslagpunt                                                         (1)

7.2.2   burette/buret                                                                       (1)

7.2.3   decreases/neem af                                                                   (1)

7.2.4   Reaction is between a weak acid and a strong base.     Therefore the salt that is
        formed is basic and undergoes hydrolysis (OH- forms). /Die reaksie is tussen ‘n
        swak suur en ‘n sterk basis. Daarom is die sout wat vorm basies en dit ondergaan
        hidrolise (OH- vorm).                                                               (2)

7.3     n = cV
          = 0,01 x 6
          = 0,06 mol                                                                        (3)

7.3.2   n(NaOH) = m/M
                = 44/40
                = 0,11 mol
        n(H2SO4) = 0,11 x ½
                 = 0,055 mol                                                                (3)

7.3.3   n(H2SO4) left = 0,06 - 0,055
                      = 0,005 mol
              +
        n(H3O ) = 0,005 x 2
                = 0,01 mol
        [H3O+] = n/V = 0,01 / 6
               = 0,00166… mol.dm-3
        pH = -log [H3O+]
           = - log (0,00166..)
           = 2,78
                                                                                            (6)
                                                                                            [21]

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QUESTION 8

8.1   8.1.1    Cℓ2(g) / chlorine gas
               chloorgas                                                                   (1)

      8.1.2    Fe ―› Fe3+ + 3e-                                                            (2)

      8.1.3
               Fe│Fe3+ ║Cl2│Cl- ; Pt(s)                                                    (3)

8.2            Ecell = Ecathode - Eanode
                      = 1,36 – (- 0,06)
                      = 1,42 V                                                             (3)

8.3            smaller than , work done in moving the ions through the electrolyte
               / internal resistance in cell / loss in voltage

               Kleiner as    – werk verrig deur die ione, deur die elektroliet / interne
               weerstand in sel / potensiaalverskil wat verlore gaan
                                                                                           (2)

                                                                                           [11]

QUESTION 9

9.1   Number of moles of electrons transferred = 0,8 mol
      Therefore, number of moles of copper atoms formed = 0,4 mol (ratio 2:1)
      m=nxM
        = 0,4                              x 63,5
        = 25,4 g
                                                                                           (4)

9.2   25,4 g copper was oxidized
      % copper in impure sample = 25,4/28 x 100 = 90,71%
      The copper is not suitable.
                                                                                           (4)

9.3   Silver and platinum both are much weaker reducing agents than copper.                (1)

                                                                                           [9]

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                                              14

QUESTION 10

10.1   10.1.1

                                              (3)

       10.1.2

                                              (1)

10.2   10.2.1
                                              (2)

       10.2.2

                                              (2)

                                              [8]

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