Grade 12 NSC Mathematical Literacy P1 (English) 2015 Preparatory Examination Possible Answers hlayiso.com

Downloaded from hlayiso.com PREPARATORY EXAMINATION 2015 MEMORANDUM SUBJECT: MATHEMATICAL LITERACY P1 (10601) Symbol Explanation M Method M/A Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG Reading from table/reading from a graph SF Correct substitution in formula O Opinion/Example P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding off 1

Downloaded from hlayiso.com 10601/15 GAUTENG DEPARTMENT OF EDUCATION PREPARATORY EXAMINATION – 2015 MATHEMATICAL LITERACY (First Paper) MEMORANDUM QUESTION 1 [51 MARKS] Solution Explanation L1 L2 L3 Year 1:  M/A Adding R600 4 1.1.1(a) R6 000 + (10% of R6 000) S Simplify M/A Adding R660 = R6 000 + R600  M/A A Answer = R6 600 S Year 2: R6 600 + (10% of R6 600) = R6 600 + R660 M/A = R7 260 Total cost after 2 years = R7 260 A Total amount payable to dad  M/A Multiplying 2 1.1.1(b) correct values = R230 × 36 months M/A  A Answer = R8280 A Answer only full marks 1.1.1(c) Amount saved = R8 280 – R7 260 M/A M/A Subtraction 2 A Answer = R1 020 A Answer only full marks Percentage of Robert’s salary M/A Correct values 3 1.1.2 M/A in fraction = M M Multiply with 100% A/R Answer and = 1,951… % rounding ≈ 2% A/R 2

Downloaded from hlayiso.com 10601/15 1.1.3(a) Profit on rings = Selling Price – Cost Price M/A Subtraction 2 correct values = R6 000 – R3 495 M/A A Answer = R2 505 A Answer only full marks 1.1.3(b) Percentage profit = M/A Correct values 3 and method M/A M Multiply by = M 100% CA Answer = 71,673….% ≈ 71,67% CA 1.2.1 A = R15 500 × M/A M/A Multiplying 2 correct values A Answer = R1 162,50 A 1.2.2(a) UIF contribution = 1% of R15 500 M UIF is 1% 2 M M/A = × R15 500 M/A Multiplication A Answer = R155 A 1.2.2(b) Total UIF paid over by company M/A Multiply by 2 2 A Answer = R155 × 2 M/A CA from 1.2.2(a) = R310 A Answer only full marks 1.2.3 C = R1 230 + R1 162,50 + R500 + R155 + M/A Adding 4 R1 439,60 + R510 correct M/A Values = R4 997,10 A A Answer of C M Subtraction D = R18 900 – R4 997,10 M CA Answer of B = R13 902, 90 CA Answers only full marks 1.2.4 Percentage tax on travel allowance M/A Correct 3 M/A values in fraction = M M Multiply with 100% A Answer =15% A 1.3.1 Cost of one night’s stay M/A 2 Multiplication = R11,38 × $950 M/A A Answer in rand = R10 811 A Answer only full marks 3

Downloaded from hlayiso.com 10601/15 1.3.2 VAT included M/A Multiply with 3 = R10 811 – (R10 811 × ) M/A S Simplification = R10 811 – R9 483,33 S A Answer = R1 327,67 A OR Cost excluding vat = R10 811 × M/A = R9 483,33 Vat = R10 811 – R9 483,33 S = R1 327,67 A 1.3.3 Total cost = R10 811 + City Tax M/A Adding and 3 M/A multiplying = R10 811 + ( ) with correct values S = R10 811 + R108,11 S Simplification A Answer = R10 919,11 A 1.4.1 Cost of hiring venue M Basic fee 2 M R200 × = Basic fee + (R200 × number of guests) number of M M guests OR R8 000 + R200 × number of guests M M 4

Downloaded from hlayiso.com 10601/15 1.4.2 Number of 100 120 140 160 180 200 A One mark for 3 guests Cost The each two 28 000 32 000 36 000 40 000 44 000 48 000 Da Vinci values Hotel (R) correct A A A 1.4.3 A Starting point 6 (0; 8000) A Ending point (200; 48000) A Break even point (100; 28000) A Any 3 other points plotted correctly 1.4.4(a) Accept values between 106 to 110 guests RG Reading from 1 RG Graph 1.4.4(b) Accept values between 170 to 175 guests RG Reading from 2 RG Graph Total 28 23 5

Downloaded from hlayiso.com 10601/15 QUESTION 2 [ 27 MARKS ] Solution Explanation L1 L2 L3 2.1 Time = SF Substitution 3 S Simplification A Answer = SF = 0,333… h S OR ⅓ Time in minutes = 0,333 … × 60 min OR ⅓ × 60 min = 20 min A 2.2.1 Circumference of table M Value of r 3 =2×π×r SF Substitution M A Answer = 2 × 3.142 × 75 SF Answer only full = 471,3 m A marks 2.2.2 Number of guests to be seated at table M/A Fraction 3 = with correct values = M/A A Answer = 8,56 … A ≈ 8 guests R R Rounding 2.2.3 Number of tables needed M/A Division 2 correct = 120 ÷ 8 M/A values A Answer = 15 tables A Answer only full marks 6

Downloaded from hlayiso.com 10601/15 2.2.4 Table cloth diameter = 150 + 30 = 180 cm C Conversion 4 SF Substitution Radius = 180 ÷ 100 ÷ 2 = 0,9 m C A Answer U Unit Area of table cloth = π × r2 = 3.142 × (0,9)2 SF = 2,545 … m2 ≈ 2,55 m2 AU 2.3.1(a) Volume of container = π × r2 × h M Value of r 4 M SF Substitution = 3.142 × (15)2 × 50 CA Answer SF C Concersion = 35 347,5 cm3 CA Volume in litre = 35 347,5 ÷ 1 000 = 35,3475 ℓ C 2.3.1(b) Number of glasses to be filled M/A Division 3 correct = 35 347,5 mℓ ÷ 40 mℓ  M/A values A Answer = 883,6875 A R Rounding ≈ 883 glasses R Answer only full marks 2.4(a) Amount of concentrate per child M/A Multiply 3 with correct fraction = mℓ M/A A Answer CA Answer = 220 mℓ A Water = 1 320 mℓ − 220 mℓ = 1 100 mℓ CA 2.4(b) Amount of concentrate per glass M/A Division 2 with correct values = 220 mℓ ÷ 4 M/A A Answer Answer only full = 55 mℓ A marks Total 13 14 7

Downloaded from hlayiso.com 10601/15 QUESTION 3 [27 MARKS] Solution Explanation L1 L2 L3 3.1.1 Friday A A Answer 2 18 December 2015 A A Answer 3.1.2 10:00 − 08:15 M M Subtraction 3 M M Correct notation = 1 hour 45 minutes A A Answer Answer only full marks 3.1.3(a) Casino Lounge RG RG Reading 2 from diagram 3.1.3(b) 3  RG RG Reading 2 from diagram 3.1.3(c) Sun Deck RG RG Reading 2 Mini Golf RG from diagram 3.2.1 1 Unit on the map is equal to 100 000 units E 2 in real life E Explanation 3.2.2 Distance Durban to Portuguese Islands M/A Multiply 3 correct = 2 150 km × 100 000 M/A values A Answer = 215 000 000 cm AU U Unit Answer only full marks 3.2.3 3,7 cm on map = 370 000 000 cm in life A Correct 3 A amount Distance return trip M/A Division correct = 370 000 000 cm ÷ 100 000 M/A values A Answer = 3 700 km A Answer only full marks 3.2.4 South South West OR SSW OR A Answer 2 South Westerly direction A 3.3 Drive in a North Easterly direction on the N14. A 6 A One mark for each Turn right onto Hendrik Potgieter Drive part of route A described Take the N1 and drive south. A Take the M2 and drive east. A Drive north on the N3. A Take the R24 and drive North East to the O.R. Tambo International Airport. A Total 21 6 8

Downloaded from hlayiso.com 10601/15 QUESTION 4 [24 marks] Solution Explanation L1 L2 L3 4.1.1 Number of cabins accommodating four guests M Addition 2 = 17 + 38 + 100 + 16 M CA Answer Answer only full = 171 cabins CA marks 4.1.2 Number of cabins with only double bed M/A 3 M/A Subtraction with = 867 – (28 + 56 + 48 + 177 + 18) correct values S Simplification = 867 – 327 S A Answer Answer only full = 540 cabins A marks 4.1.3 Number of children = 2 199 – 1 921 = 278 A Number of 4 A children M/A M/A Multiply Percentage children = correct 2 values = 12,6421 …% A A Answer R Rounding ≈ 13% R 4.2.1 A = 11 839 – 4 338 M M Subtraction 4 A Answer = 7 501 A M Addition B = 4 429 + 8 474 M A Answer = 12 903 A Answers only full marks 4.2.2 2192; 4429; 5955; 6093; 7501; 8023; 8680 A Ascending 3 A Order A Median Median = 6093 A Wrong values used, penalty of 2 marks 4.2.3 M/A M/A Addition 4 of 3164  4190  6728  4338  4433  8474  4423 correct Mean = scores 7 M/A M/A Division by 7 = A Answer R Rounding = 5107,142 … A down ≈ 5107 South African Residents R 4.2.4 Foreign Travellers departing form Durban M/A Subtraction 2 with correct values = 42 873 – 35 750 M/A A Answer = 7 123 A Answer only full marks Totals 16 8 9

Downloaded from hlayiso.com 10601/15 QUESTION 5 [21 MARKS] 5.1.1 P(female) = RT RT Reading 2 correct values A Answer = A 5.1.2 P(male or under 50) RT Reading 4 RT correct values = M/A M/A Multiply A Answer A Answer = = A Percentage = = 37,5% A 5.2.1 110 km/h RG RG Reading 2 from the graph 5.2.1 Speed above speed limit M Subtraction 2 CA Answer = 110 km/h – 100 km/h M Answer only full = 10 km/h CA marks 5.2.3 89 km/h RG RG Reading 2 from the graph Accept 88 km/h 5.2.4 Quartile 1 = 85 km/h RG RG Reading 2 Quartile 3 = 100 km/h RG from the graph 5.3.1 Length of suit case = 1,2 m × 100 = 120 cm C Conversion 4 C SF Surface area of suit case Substitution = 2(lb + bh + lh) S Simplify A Answer = 2[(120cm × 60cm) + (60cm × 30cm) + (120cm ×30cm)] SF = 2(12 600 cm2) S = 25 200 cm2 A 5.3.2 Volume of suit case SF Substitution 3 = length × breadth × height A Answer U Unit = 120cm × 60cm × 30cm SF = 216 000 cm3 AU Totals 13 4 4 10