MATHS LIT P2 GR12 MEMO JUNE 2024_English_hlayiso.com_.pdf

Downloaded from hlayiso.com NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2024 MATHEMATICAL LITERACY P2 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method M/A Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT/RG/RD/RM Reading from a table/graph/diagram/map SF Correct substitution in a formula O Opinion/Explanation//Reasoning P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding off NPR No penalty for rounding AO Answer only MCA Method with consistent accuracy RCA Rounding consistent with accuracy This marking guideline consists of 10 pages. Hosted by www.ecexams.co.za

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (EC/JUNE 2024) MARKING GUIDELINES NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled version). • Consistent Accuracy (CA) applies in ALL aspects of the marking guidelines; however, it stops at the second calculation error. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra incorrect item presented. Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2024) MATHEMATICAL LITERACY P2 3 KEY TO TOPIC SYMBOL: F = Finance; M = Measurement; MP = Maps, plans and other representations; P = Probability QUESTION 1 [20 MARKS] ANSWER ONLY FULL MARKS Ques. Solution Explanation Level 1.1.1 The perimeter of a shape is the total distance around 2A correct explanation M the edges defining the outline of that shape. ✓A L1 OR Total distance around the shape. ✓A (2) 1.1.2 370 1C convert cm to m M Length of wall = C 100 1A correct answer L1 = 3,7 m A (2) 1.1.3 P = length + length + height + height CA from 1.1.2 M = 3,7 + 3,7 + 2,1 + 2,1 M 1M adding correct values L1 = 11,6 m CA 1CA correct answer from 1.1.2 (2) 1.2.1 75 1MA dividing correct values M Distance cycled = MA 1A correct answer L1 0,6214 = 120,6952044 NPR ≈ 120,7 km A Accept: 121 km / 120,695 km (2) 1.2.2 Total distance logged: CA from 1.2.1 M = 120,7 km + 114,3 km + 271 km + 148,1 km M 1M adding correct values L1 = 654,1 km CA 1CA correct answer Accept 654,4 km / 654,095 (2) 1.3.1 Pniel ✓RT 2RT reading from map MP (2) L1 1.3.2 5 water points ✓RT 2RT correct answer MP (2) L1 1.3.3 N1 ✓RT 2RT correct answer MP (2) L1 1.3.4 SW or Southwest ✓RT 2RT correct direction MP (2) L1 1.3.5 Helshoogte Pass ✓RT 2RT correct answer MP (2) L1 [20] Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (EC/JUNE 2024) QUESTION 2 [24 MARKS] Ques. Solution Explanation Level 2.1.1 Bar Scale ✓A OR Linear Scale ✓A OR Graphic ✓A 2A identifying correct MP Scale scale L1 (2) 2.1.2 N6 RT and N1 RT 1RT first national road MP 1RT second national L1 road Accept any order (2) 2.1.3 North A 1A first direction MP North East OR NE A 1A second direction L2 (2) 2.1.4 His wife will be crossing the border between two countries 2O opinion MP and therefore needs a passport. ✓O L4 OR His wife will enter another country. ✓O (2) M 1M subtracting correct F 2.1.5 R22,49 – R21,77 values L4 % difference = × 100% M R21,77 A 1M multiplying with 100% = 3,307% CA 1A correct denominator Statement is invalid – it will cost less than 4% O 1CA simplification 1O opinion OR M (R22,49 × 75) – (R21,77 × 75) OR % difference = × 100% M (R21.77 × 75) A 1M subtracting correct values 1 686,75 – 1 632,75 1M multiplying with = × 100% 100% 1 632,75 1A correct denominator = 3,307% CA 1CA simplification Statement is invalid – it will cost less than 4%. O 1O opinion (5) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2024) MATHEMATICAL LITERACY P2 5 2.2.1 Staff working at the gates need to go home. O 2O reason MP L4 OR The wild animals in the park make it unsafe to travel or be in unprotected parts during the night.✓O OR Animals are not visible in the dark, park/camp gates open when people can see the animals. ✓O OR Access control ✓O OR To avoid overcrowding ✓O OR Security reasons ✓O OR So that people travelling from far or within the Kruger National Park, can plan ahead. O OR (2) Accept any other valid reason. 2.2.2 Other camps = 5 1RT number of both camps MP Main camps = 7 RT L2 1CA difference with 1 Difference = 7 – 5 = 2 CA correct camp AO (2) 2.2.3 Distance = speed × time MP RT 1RT distance L3 54 km = 50 km/h × time SF 1SF substitution with 50 km/h Time on gravel road If calculated as 54 km follows do not = S penalise. 50 km/h 1S change the formula = 1,08 h = 1h 4 min 48 sec C 1h05min 1C converting time Time he will arrive at the gate is: 17:15 + 1h05min 17:15 + 1:4:48 = 18:20 1CA arrival time = 18:19:48 CA (5) Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (EC/JUNE 2024) 2.2.4 The roads are not so busy / people drive slower / more animals are 2O reason MP visible. ✓O L4 OR It is the scenic route. ✓O OR To experience a sense of adventure. ✓O OR Gravel roads give you more access (short cut) to different parts of the park. ✓O OR The route blends in with nature and gives a more authentic bushveld experience. ✓O OR Accept any other reasonable answer. (2) [24] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2024) MATHEMATICAL LITERACY P2 7 QUESTION 3 [36 MARKS] Ques. Solution Explanation Level 3.1.1 Number of coloured pencils across 1M dividing diameters M = 83 ÷ 6 M 1CA simplification L4 = 13,833333…CA 1R number of pencils ≈ 13 pencils R Number of coloured pencils down = 22 ÷ 16,7 M 1M dividing heights = 1,317365269 1R number of pencils ≈ 1 pencil R Total number of pencils in one container = 13 × 1 1CA number of pencils = 13 pencils CA in one container Number of pencils in 3 containers = 13 × 3 M 1M multiply by 3 = 39 pencils CA 1CA total number of pencils ⸫ Correct O 1O opinion (9) 3.1.2 Probability of taking a purple pencil from a container CA from 3.1.1 P 6 A 1A numerator L2 = A 39 1A denominator = 0,153846153 1R 3 decimal places ≈ 0,154 R (3) 3.2.1 Area of rectangle = length × width 1C convert to mm M (a) = 150 mm × 120 mm C SF 1SF substitution L2 = 18 000 mm2 A 1A area of rectangle (3) (b) Area of circle = π × radius2 CA from 3.2.1 (a) M = 3,142 × 402 A OR 3,142 × 40 × 40 A 1A radius L3 = 5 027,2 mm2 CA = 5 027,2 mm2 CA 1CA area of circle Area without photo = 18 000 mm2 – 5 027,2 mm2 M 1MCA subtracting two = 12 972,8 mm2 areas ≈ 12 973 mm2 CA 1CA rounding to nearest mm2 (4) Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P2 (EC/JUNE 2024) 3.2.2 Surface area of gift box M = 2 (length × width) + 2 (width × height) + 2 (length × height) 1SF substitution L2 = 2 (38,8 × 27,5) + 2 (27,5 × 30,0) + 2 (38,8 × 30,0) SF A 1A correct values = 2 134 + 1 650 + 2 328 S 1S simplification = 6 112 cm2 CA 1CA surface area (4) 3.3.1 Diameter = 31 m × 2 M 1M multiply radius by 2 M = 62 m A 1A correct diameter L2 (2) 3.3.2 Maximum height = 50 m + 31 m MA 1MA adding correct M = 81 m A values L2 1A answer (2) 3.3.3 Circumference = 2 × π x radius 1SF substitution M = 2 × 3,142 × 31 SF 1MA multiply by 2 and L2 = 194,804 × 2 answer = 389,608 m MA NPR (2) 3.3.4 1 750 1M dividing by 25 M Number of households = M 25 1A correct answer L1 = 70 households A (2) 3.4 Volume of 2 cylindrical basins used three times a day 1SF substitution M = π × r2 × h 1M multiplying by 2 and 3 L3 = (3,142 × 302 × 45) × 2 × 3 SF M 1CA volume = 763 506 cm3 CA Litres of water used daily 1C converting to litres 763 506 = × ¾ C 1 000 1CA ¾ litres of water = 572,6295 litres CA OR Volume of 2 cylindrical basins used three times a day = π × r2 × h = (3,142 × 302 × 45) × 2 × 3 SF M 1SF substitution = 763 506 cm3 CA 1M multiplying by 2 and 3 1CA volume of water Litres of water used daily = 763 506 × ¾ = 572 629,5 cm3 1C converting to litres 572 629,5 C 1CA ¾ litres of water = 1 000 = 572,6295 litres CA (5) [36] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2024) MATHEMATICAL LITERACY P2 9 QUESTION 4 [20 MARKS] Ques. Solution Explanation Level 4.1.1 Total number of hours: 1A number of hours on M Friday L4 Friday: 24:00 – 15:30 = 8,5 hours A 1A number of hours for 3 Saturday – Monday = 24 hours × 3 days = 72 hoursA days Tuesday = 10 hours A 1A number of hours on Total number of hours = 8,5 + 72 + 10 day of departure = 90,5 hours MA 1MA adding correct Invalid O values and correct answer. 1O opinion (5) 4.1.2 diameter 10 1A find radius M radius = = = 5 cm A 2 2 L3 Volume of cylinder = 3,142 × radius2 × height 1SF substitution 1 571 cm3 = 3,142 × 52 × height SF 1 571 Height = M 1M change subject of the 78,55 Height = 20 cm CA formula 1CA finding the height (4) 4.1.3 Area of top and bottom surface = 78,55 cm2 × 2 M 1M multiply by 2 F 2 2 = 157,1 cm ÷ 100 C 1C divide by 1002 L3 = 0,01571 m2 S 1S simplification of Total cost = 0,01571 m2 × R144,65 M answer in m2 = R2,27 CA 1M multiply R144,65 1CA answer OR OR 2 2 Area of top = 78,55 cm ÷ 100 C 1C divide by 1002 = 0,007855 m2 S 1S simplification of Cost of wood of top = 0,007855 × R144,65 M answer in m2 = R1,13622575 1M multiply R144,65 Total cost = R1,13622575 × 2 M 1M multiply by 2 = R2,27 CA 1CA answer (5) 4.2.1 Actual length = 3,4 cm × 65 M 1M multiply correct MP = 221 cm A values and correct L2 answer 1A answer (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 10 MATHEMATICAL LITERACY P2 (EC/JUNE 2024) 3 P 4.2.2 Probability = A 1A numerator 7 1A denominator L2 (2) 4.2.3 The main bedroom. A 1A correct room MP Room is facing north. O 1O opinion L4 (2) [20] TOTAL: 100 Copyright reserved Please turn over