Mathematical Literacy Grade 12 P1 2024 Memo (Eng)

NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2024 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification RT Reading from a table/graph/document/diagram SF Correct substitution in a formula O Opinion/Explanation P Penalty, e.g. for no units, incorrect rounding off, etc. R Rounding off NPR No penalty for correct rounding minimum two decimal places AO Answer only MCA Method with constant accuracy This marking guideline consists of 9 pages.

2 MATHEMATICAL LITERACY P1 (EC/JUNE 2024) NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the question, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines. Stop marking at the second calculation error. • NOTE: Consistent accuracy (CA) does NOT apply in cases of a breakdown. • If the candidate presents any extra solution when reading from a graph, and table then penalise for every extra item presented. • As a general marking principle, if a candidate has incurred one mistake and there is evidence of sound Mathematics thereafter, then that candidate should lose ONE mark only. Topics: F – Finance, DH – Data Handling, P – Probability QUESTION 1 [20 MARKS] Ques. Solution Explanation T&L 1.1.1 R10,00 RT 2RT reading from table F L1 (2) 1.1.2 The rate will be paid per full one hour even 2 Opinion if you spend less than one hour  O F L1 (2) 1.1.3 Amount paid: 1M multiplication F L1 75 1A answer x 20  M = R15  A 100 (2) 1.2.1 Discrete A 2 A correct classification DH L1 (2) DH L1 1.2.2 Four hundred and ninety thousand, nine 2 A correct wording hundred and ninety-three A (2) 1A calculating male DH L1 1.2.3 100% − 68% = 32% A percentage 32 ∴ 100 × 490 993 = 157 117,76 CA 1CA simplification 1A answer R ≈ 157 118 A OR 1MA calculating female number Females = 68 x 490 993MA 100 M subtracting correct values = 333 875,24 MA CA simplification = 490 933 – 333 875,24 M = 157 117,76 = 157 118  CA (3) Copyright reserved Please turn over

(EC/JUNE 2024) MATHEMATICAL LITERACY P1 3 1.2.4 68 1M multiplication DH L1 × 490 993 = 333 875,24 ≈ 333 875 M 100 1MAconcept of ratio in correct order 333 875 :490 993 M 1CA simplification 1 : 1,47 A Accept also [using percentages] 68 : 100 1 : 1,47 (3) 1.3.1 B  2A correct option P (2) L1 1.3.2 D A 2A correct option P (2) L1 [20] Copyright reserved Please turn over

4 MATHEMATICAL LITERACY P1 (EC/JUNE 2024) QUESTION 2 [21 MARKS] Ques. Solution Explanation T&L 2.1 7,5 1M multiply by 12 F × 12 M × R32 500 S = R29 250 A 1 simplification 100 L2 1A answer (3) 2.2 Annual salary R32 500 × 12 1MA annual salary F L3 = R390 000 M Taxable income = R390 000 − R29 250 1A taxable income = R360 750A 1SF correct substitution Annual tax = R73 726 + 31% × (R360 750 − R353 100) SF = R73 726 + 0,31 × R7 650 = R73 726 + R2 371,50 = R76 097,50 1MA subtracting correct rebate Less rebate: R76 097,50 − R16 425 M = R59 672,50 Less MTC R59 672,50 − [(R347 + R347 + R234 + R234 + R234) × 12] 1MA subtracting medical tax credit = 𝑅59 672,50 − 𝑅16 752 M Annual tax = R42 920,50 1MCA division by 12 R42 920,50 Monthly tax = M 1CA monthly tax 12 = R3 576,71 CA 1A 15% of salary 15 1O opinion 15% of salary: × R32 500 = R4 875 A 100 Not valid. O (9) Copyright reserved Please turn over

(EC/JUNE 2024) MATHEMATICAL LITERACY P1 5 2.3 R170 734 + 39% × (R817 600 − R641 400) SF S 1SF correct F substitution L2 = R170 734 + R68 718M 1simplification 1M addition = R239 452 (3) 2.4 Lump sum = 80% × R32 500 M 1MA calculating F = R26 000 A 80% L3 1simplification Balance at the end of First Year =R26 000 + 11,5% × R26 000 M = R28 990 A 1M multiplication 1A answer Balance at the end of Second Year = R28 990 + 11,5% × R28 990 = R32 323,85 A 1A answer Balance at the end of Third Year = R32 323,85 + 11,5% × R32 323,85 = R36 041,09 CA 1CA answer OR Balance = R26 000 × 1,115 M × 1,115 M × 1,115 M = R36 041,09 A (6) [21] Copyright reserved Please turn over

6 MATHEMATICAL LITERACY P1 (EC/JUNE 2024) QUESTION 3 [30 MARKS] Ques. Solution Explanation T&L 3.1 Northern Cape A 2A answer DH (2) L1 3.2 Method 1: 𝐴 = 26 850 972 − (3 348 392 + 1 422 384 + 1M addition DH 6 274 046 + 1 965 259 + 634 792 + 2 714 474 + 1A answer L4 1 718 340 + 3 198 146) M A = 5 575 139 A Method 2: 1M multiplication 20,76 × 26 850 972 M 1A rounded off answer 100 = 5 574 261,78 2O explanation ≈ 5574 262 A The difference is caused by rounding off to two decimal places of the percentage.  (6) 3.3 3 198 146 1RT correct values DH RT × 100% M = 11,91% A 26 850 972 1M multiplication L2 1 A answer (3) 3.4 26 850 972 1RT correct values DH Mean = RT M 9 1M division L2 1A answer = 2 983 441,333 A 1R rounding (4) ≈ 2 983 441 R 3.5 Ascending order: 1M arranging in ascending/ DH descending order L2 634 792; 1 422 384; 1 718 340; 1 965 259; 2 714 474; 1MA calculating lower 3 198 146; 3 348 392; 5 575 139; 6 274 046 M quartile 1A simplification 1 422 384+1 718 340 Lower Quartile = MA 1A upper quartile 2 1CA calculating IQR 1A answer = 1 570 362 A (6) 3 348 392 + 5 575 139 Upper Quartile = 2 = 4 461 765,5 A IQR = 4 461 765,5 − 1 570 362 M = 2 891 403,5 ≈ 2 891 404 A Copyright reserved Please turn over

(EC/JUNE 2024) MATHEMATICAL LITERACY P1 7 3.6 titles DH Line graph showing % of voters per province plotting L3 25 all 9 23,37 20 20,76  joining the points Perecntage 15 12,47 11,91 10 10,11 7,32 6,4 5 5,3 2,3 0 EC FS GP KZN MP NC LP NW WC Provinces (4) 3.7 To arrange campaigns O 2O DH To provide enough polling observers during elections O opinion L4 [Any other valid reason] (2) 3.8 P(Cape province) = 11,91% + 2,3% + 12,47% M 1M P addition L2 = 26,68% A 1A answer = 0,267 R 1R rounding OR off 3 348 392 + 634 792 + 3 198 146 P(Cape province) = RT 26 850 972 7 181 330 = 26 850 972 M = 0,267 A (3) [30] Copyright reserved Please turn over

8 MATHEMATICAL LITERACY P1 (EC/JUNE 2024) QUESTION 4 [29 MARKS] Ques. Solution Explanation T&L 4.1.1 7 000 000 A 2A answer F (2) L1 4.1.2 $7 000 000 1M division by 30 F M 1A answer L2 30 = $233 333,33 A 1R rounding off ≈ $233 000 R (3) 4.2.1 5 000 × 19,1305 RT = R95 652,50 M 1RT correct values F 1M multiplication L4 2 000 × 24,3861 = R48 772,20 A 1A answer 1A answer Total = R144 424,70 A 1M multiplication Commission 2,5 × 144 424,7 = R3 610,62 M 1A answer 100 Money deposited (6) R144 424,70 − R3 610,62 = R140 814,08 A 4.2.2 To make profit. O 2O explanation F L4 (2) 4.3.1 5 provinces A 2A answer DH (2) L1 4.3.2 Pie chart A 2A answer DH (2) L1 4.3.3 5 RT 2 RT correct values P × 100 M = 62,5% A 1M multiply by 100 L2 8 RT 1A answer (4) 4.4.1 Income generated from selling packs is equal to 2O explanation F the cost of packs. O (2) L1 4.4.2 Fixed cost A 2A answer F (2) L1 Copyright reserved Please turn over

(EC/JUNE 2024) MATHEMATICAL LITERACY P1 9 4.4.3 Formula for income = 750n M 1M formula for income F Formula for cost = 6 000 + 350n M L4 1M formula for cost Break-even: 750n = 6 000 + 350n M 1M equation 400n = 6 000 1A answer n = 15 packs A (4) [29] TOTAL: 100 Copyright reserved Please turn over