Mathematical Literacy P2 May June 2022 MG Afr Eng hlayiso.com

Downloaded from hlayiso.com SENIOR CERTIFICATE EXAMINATIONS/ NATIONAL SENIOR CERTIFICATE EXAMINATIONS SENIORSERTIFIKAAT-EKSAMEN/ NASIONALE SENIORSERTIFIKAAT-EKSAMEN MATHEMATICAL LITERACY P2/WISKUNDIGE GELETTERDHEID V2 2022 MARKING GUIDELINES/NASIENRIGLYNE MARKS/PUNTE: 150 Symbol/Kode Explanation/Verduideliking M Method/Metode MA Method with accuracy/Metode met akkuraatheid CA Consistent accuracy/Volgehoue akkuraatheid A Accuracy/Akkuraatheid C Conversion/Herleiding S Simplification/Vereenvoudiging RT Reading from a table/graph/document/diagram/Lees vanaf tabel/grafiek/dokument/diagram SF Correct substitution in a formula/Korrekte vervanging in 'n formule O Opinion/Explanation/Opinie/Verduideliking P Penalty, e.g. for no units, incorrect rounding off, etc./Penalisasie, bv. vir geen eenhede, verkeerde afronding, ens. R Rounding off/Afronding NPR No penalty for correct rounding/Geen penalisasie vir korrekte afronding nie AO Answer only/Slegs antwoord MCA Method with consistent accuracy/Metode met volgehoue akkuraatheid RCA Rounding consistent with accuracy/Afronding met volgehoue akkuraatheid * Asterisk means refer to attached notes These marking guidelines consist of 19 pages. Hierdie nasien riglyne bestaan uit 19 bladsye. Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 2 DBE/2022 NSC/NSS – Marking Guidelines/Nasienriglyne NOTE: • If a candidate answers a question TWICE, only mark the FIRST attempt. • If a candidate has crossed out (cancelled) an attempt to a question and NOT redone the solution, mark the crossed out (cancelled) version. • Consistent accuracy (CA) applies in ALL aspects of the marking guidelines; however it stops at the second calculation error. • Note: Consistent accuracy (CA) does NOT apply in cases of a breakdown. • If the candidate presents any extra solution when reading from a graph, table, layout plan and map, then penalise for every extra item presented. • As a general marking principle, if a candidate has incurred one mistake and there is evidence of sound mathematics thereafter, then that candidate should lose ONE mark only. LET WEL: • As'n kandidaat'n vraag TWEE KEER beantwoord, sienslegs die EERSTE pogingna. • As 'n kandidaat 'n antwoord van 'n vraag doodtrek (kanselleer) en nie oordoen nie, sien die doodgetrekte (gekanselleerde) poging na. • Volgehoue akkuraatheid (CA) word in ALLE aspekte van die nasienriglyne toegepas, dit hou op by die tweede berekeningsfout. • Let wel: Volgehoue akkuraatheid (CA) geld NIE in die geval van 'n afbreuk NIE. • Wanneer 'n kandidaat aflesings vanaf 'n grafiek, tabel, uitlegplan en kaart geneem het en ekstra antwoorde gee, penaliseer vir elke ekstra item. • 'n Algemene nasienbeginsel is dat, indien 'n kandidaat een fout maak en daarna voortgaan met korrekte wiskunde, die kandidaat slegs EEN punt verloor. QUESTION/VRAAG 1 [30 MARKS/PUNTE] – ANSWER ONLY ACCEPTED Q/V Solution/Oplossing Explanation/Verduideliking T/L MP 1.1.1 D  A DRAFT 2A correct option L1 Accept 1:50 000 (2) M 1.1.2 E  A 2A correct option L1 (2) MP 1.1.3 G  A 2A correct option L1 Accept 1 cm = 1 m (2) M *1.1.4 C  A 2A correct option L1 (2) M *1.1.5 F  A 2A correct option L1 (2)  A M 1.2.1 B OR/OF 2A correct option L1 (2 × 240 × 70 + 2 × 240 × 112 + 2 × 112 × 70) mm2 (2)  A M *1.2.2 mm3 OR Cubic millimetres/Kubieke millimeter 2A correct unit L1 (2)  C M Length/Lengte = 240 ÷ 1 000 1C conversion factor L1 1.2.3 = 0,24 m  A 1A simplification (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 3 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L MP *1.2.4 Number of rows/Getal rye L1 2 100 mm  A 1A height = 1 A correct denominator 70 mm  A = 30  CA 1CA number of rows (3) M 1.3.1 Mass of the flour (in kg)/Massa van die meel L1 500 C 1C divide by 1 000 = 1 000 1 = kg or/of 0,5 kg A 1A simplification 2 (2)  A M 1.3.2 12 scones/botterbroodjies = 2 eggs/eiers 1A dozen = 12 L1 6 scones/botterbroodjies = 1 egg/eier 30 scones = 2 + 2 + 1 = 5 eggs/eiers  A 1A simplification OR/OF OR/OF  A 12 scones/botterbroodjies = 2 eggs/eiers 1A dozen = 12 30 30 scones/botterbroodjies = 2 12 = 5 eggs/eiers  A 1A simplification OR/OF OR/OF 30  A 30 scones/botterbroodjies = = 2,5 dozen/dosyn 1A dozen = 12 12 1 dozen need 2 eggs/1 dosyn benodig 2 eiers 2,5 dozen/dosyn = 2,5× 2 = 5 eggs/eiers  A 1A simplification (2) M 1.3.3 Radius = 7 cm ÷ 2  MA 1MA dividing by 2 L1 = 3,5 cm OR/OF 35 mm  A 1A radius (2) M 1.3.4 Number of dozen scones/Getal dosyn botterbroodjies L1 500 MA = 1MA dividing by 75 75 = 6,67  S 1S simplification =6  R 1R rounding down (3) A A M *1.3.5 Ten minutes past two in the afternoon. 1A time L1 Tien minute oor twee in die namiddag. 1A afternoon (2) [30] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 4 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 2 [32 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L MP 2.1.1 14:00  A 2A 24-hour time format L1 (2) MP 2A correct number 2.1.2 8 A (2) L2 MP 2.1.3 Bicycle/Fiets RT 2RT bicycle L1 (2) MP 2.1.4(a) Distance/Afstand = 9K + 1K L2 = 10 km  A 2A 10 km 10 Fraction/Breuk  42,2  MCA 1MCA correct order 50   CA 1CA simplification 211 OR/OF OR/OF Distance/Afstand = 1 000 × 10 = 10 000 m  A 2A 10 km 42,2 km = 42 200 m Fraction/Breuk =  MCA 1MCA correct order =  CA 1CA simplification (4)  A MP 2.1.4 The distance is less than a full marathon. L4 (b) Die afstand is minder as 'n vol marathon. OR/OF It is shorter than a standard marathon. 2A explanation Dit is korter as 'n standaard marathon. OR/OF It is a fraction of a full marathon. Dit is 'n breuk van die vol marathon. (2) P 2.1.5 B  A OR/OF 0% 2A correct option L2 (2) MP 2.2.1 Scout House/Verkennerhuis RT 2RT correct place of interest L2 (2) MP *2.2.2 South-east OR SE A 2A correct direction L1 Suidoos OF SO (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 5 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L MP *2.2.3 Nellmapius RT 2RT correct street L2 T (2) MP 2.2.4 St Martin's Church/ St Martin-Kerk RT 2RT correct church L2 (2) MP RT 2.2.5 Irene Library &Hall/Irene Biblioteek & Saal L3 3RT correct place [Accept Hall /Aanvaar Saal] (3) MP 2.2.6 Measured distance/Gemete afstand = 8 cm MA 1MA correct measurement L3 8 cm : 1,9 km MCA 1MCA correct ratio 8 cm : 190 000 cm C 1C converting km to cm Scale/Skaal is 1 : 23 750 S 1S simplified ratio 1 : 24 000 R 1R correct rounding (Maximum distance/ maksimum afstand) Measured distance/Gemete afstand = 8,4cm MA 8,4 cm : 1,9 km MCA 8,4 cm : 190 000 cm C S Scale/Skaal is1 : 22 619,05 1 : 23 000 R OR/OF OR/OF MA C 1MA correct measurement 8,4cm ÷ 100 000 : 1,9 km MCA 1C converting cm to km 1MCA correct ratio 0,000084 km : 1,9km 1S simplified ratio 1: 22 619 S 1: 23 000 R 1R correct rounding Provinces need to mark according to  1 mm of their provincial paper. (5) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 6 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L MP 2.2.7 The traffic flow is in the opposite direction. O L4 Die verkeervloei in die teenoorgestelderigting. OR/OF One-way traffic /The arrow shows you can only turn left. 2O opinion Eenrigtingverkeer/ Die pyl wys jy kan slegs links draai OR/OF The driver will be facing oncoming traffic. Die bestuurder sal in aankomende verkeer inry. (2) [32] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 7 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 3[29MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L M 3.1.1 Total length/Totale lengte L2 = 55 cm + 99 cm + 55cm = 209 cm A 1A total length Perimeter/Omtrek= 2(209 cm +149 cm) SF 1SF substitution = 2(358) cm 1CA perimeter = 716 cm CA OR/OF OR/OF Perimeter/Omtrek A SF 1A total length = (149 + 55 + 99 + 55 + 149 + 55 + 99 + 55) cm 1SF substitution = 716 cm CA 1CA perimeter OR/OF OR/OF A SF Perimeter/Omtrek = 2 (149) cm + 2(55+99+55) cm 1A total length 1SF substitution = (298 + 418) cm = 716 cm CA 1CA perimeter (3) 605 M 3.1.2 Radius = = 302,5 mm A 1A radius L2 2 = 30,25 cm C 1C conversion 2 SF Area/Oppervlakte = 3,142 × 30,25 cm  1SF substitution = 2 875,126375 cm 2 CA 1CA simplification OR/OF OR/OF 605 A 1A radius Radius = = 302,5 mm 2 Area/Oppervlakte = 3,142 ×  302,5 mm  SF 1SF substitution 2 2 = 28 512,6375 mm C 1C conversion = 28 751 263,75 ÷ 102 = 2 875,126375 cm 2 CA 1CA simplification NPR (4) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 8 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L P 3.1.3 3 A 1A numerator L2 P= 7 A 1A denominator = 0,4285714286 1CA decimal form CA OR/OF OR/OF M 4 3 A 1M subtracting from 1 P=1– = 1A simplification 7 7 1CA decimal form = 0,4285714286 CA NPR (3) M *3.2.1 Total area/Totale oppervlakte L2 M 1SF substitution of correct = 4 m × 5 m + 3 m × 4 m SF values = 20 m2 + 12 m2 1M adding = 32 m2 NPU (2) M *3.2.2 Area of 1 tile/Opp van 1 teël = 35 cm × 35 cm SF 1 SF substitution L3 TR = 1 225 cm2 = 1 225 ÷ (100)2 m2 C 1C conversion =0,1225 m2 CA 1CA simplification Number of tiles needed/Getal teëls nodig 32 1MCA dividing areas = MCA 0,1225 = 261,2244898 CA 1CA simplification Number to add/Getal om by te tel MCA = 10% × 261,2244898 = 26,12244898 1MCA calculation 10% Total number of tiles/Totale aantal teëls = 261,2244898 + 26,12244898 = 287,3469388 CA 1CA simplification Number of boxes/Getal bokse MCA 287,3469388 1MCA dividing by 4 = = 71,83673469 4  72 boxes CA 1CA rounding up 3 marks area of tile 2 marks number of tiles 2 marks adding 10% tiles or area 2 marks number of boxes Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 9 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne 3.2.2 OR (when rounding consistently up) /OF OR/OF Area of 1 tile/Opp van 1 teël = 35 cm × 35 cm SF 1 SF substitution = 1 225 cm2 = 1 225 ÷ (100)2 m2 C 1C conversion =0,1225 m2 CA 1CA simplification Number of tiles needed/Getal teëls nodig 32 MCA 1MCA dividing areas = 0,1225 CA = 261,2244898  262 1CA simplification Number to add/Getal om by tetel MCA = 10% of 262 = 26,2 1MCA calculation 10% Total number of tiles/Totale aantal teëls = 262 + 26,2 = 288,2  289 CA 1CA simplification MCA 289 1MCA dividing by 4 Number of boxes/Getalbokse = = 72,25 4  73 boxes CA 1CA rounding up OR/OF OR/OF C SF CA Area of 1 tile/Opp van 1 teël = (0,35)2 = 0,1225 m2 1C conversion 1 SF substitution Area covered by tiles in a box/ 1CA simplification Opp. wat 'n boks teëls bedek MCA 1MCA multiplying by 4 = 0,1225 m2 × 4 = 0,49 m2 CA 1CA simplification Area to be tiled/Opp wat geteël word MCA 1MCA calculation 10% 32 × 110% = 35,2 CA 1CA simplification Number of boxes needed/Getal bokse nodig 35,2MCA 1MCA dividing areas = 71,8 0,49 72 boxes CA 1CA rounding up Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 10 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L OR/OF OR/OF Area of tile/ Opp van 'n teël = (35cm )2 = 1 225 cm2 A 1A simplification A 1A factor 32 m2 × 1002 = 320 000 cm2 C 1C conversion Number of tiles needed/ Getal teëls nodig MCA 1MCA dividing areas 32 m2 = 320 000 cm2 ÷ 1 225 cm2 = 261,2244898 CA 1CA simplification With extras/ Met ekstras =261,2244898 × 1,1 MCA 1MCA calculation 10% CA = 287,3 =288 tiles /teëls 1CA simplification Number of boxes/ Getal bokse: 288 ÷ 4 MCA 1MCA dividing by 4 = 72 1CA rounded up simplification CA OR/OF OR/OF C MCA Number of tiles/Getal teëls = 4 m ÷ 0,35 11,428 A 1C conversion Number of tiles/Getal teëls = 5 m ÷ 0,35 14,2857 1MCA dividing dimensions 1A simplification Total number of tiles for lounge Totale getal teëls vir woonkamer 1 SF substitution = 11,4285 × 14,285 = 163,2641 SF Number of tiles/Getal teëls = 3 m ÷ 0.35 = 8,5714 Number of tiles/Getal teëls = 4 m ÷ 0,35 = 11,4285 Total number of tiles for dining Totale getal teëls vir eetkamer = 11,4285 × 8,5714 = 97,9582 Total for lounge and dining room Totaal vir woon en eetkamer = 163,2641 + 97,9582 = 261,22 tiles CA 1CA simplification Including extra for cuttings and breakages/ Insluitend ekstra vir sny en breek MCA 1MCA calculation 10% = 261,28 × 110% = 287,408 CA 1CA simplification MCA Total number of boxes/Getal bokse = 287,408..÷ 4 1MCA dividing by 4 = 71,852 ≈ 72 CA 1CA rounding up (9) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 11 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L CA from Q3.2.2 M/F 3.2.3 Bags of tile cement/Sakke teël sement L4 TR 32 A 1A number of bags of cement = = 10,7 ≈ 11 3 Cost of the cement/Sementkoste 1MCA multiplying cost with MCA CA = R99,90 × 11 = R1 098,90 number 1CA cement cost Cost of the grout/Koste van bryvulsel = R89,90 × 4 = R359,60 CA 1CA grout cost Cost of the tiles/Teëlkoste = R143,84 × 72 = R10 356,48 CA 1CA tile cost Total cost/Totalekoste MCA = R10 356,48 + R1 098,90 + R359,60 + R2 500 1MCA adding 4 values = R14 314,98 CA 1CA simplification O Her budget is enough./Haar begroting is genoeg. 1O verification OR/OF OR/OF (using 73 boxes of tiles) Bags of tile cement/Sakke teëlsement = 10,7 ≈ 11 A 32 1A number of bags of cement = 3 Cost (in rand)/Koste in rand MCA 1MCA multiplying cost with = 143,84 × 73 + 99,90 × 11 + 89,90 × 4 + 2 500 number MCA 1CA cement cost CA CA CA = R10 500,32 + R1 098,90 + R359,60 + R2 500 1CA grout cost 1CA tile cost = R14 458,82 CA 1MCA adding 4 values 1CA simplification O Her budget is enough./Haar begroting is genoeg. 1O verification OR/OF 3 marks cement cost 1 mark tile cost 1 mark grout cost 2 marks adding costs 1 mark verification Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 12 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L OR/OF OR/OF Bags of tile cement/Sakke sement 1A number of bags of cement 32 = 10,7 ≈ 11 A 3 Budget verification/Begroting verifikasie: 1MCA multiplying cost with MCA CA CA number CA 1CA tile cost R15 000 – [(R143,84  72) + (4  R89,90) + (11  1CA cement cost R99,90) + R2 500] 1CA grout cost MCA = R15 000 – (R10 356,46 + R359,60 + R1 098,90 + 1MCA adding 4 values R2 500) = R15 000 – R14 314,98 1CA simplification = R685,02 CA O 1O verification The budget is enough with R685,02 to spare Die begroting is genoeg met R685,02 oorblywend. (8) [29] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 13 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 4 [30 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T/L MP *4.1.1 Right/Regs RT 2RT correct direction L1 (2) RT MP 4.1.2 K 11 RT 1RT correct row L2 (a) 1RT correct seat (2) MP *4.1.2 Total seats/Totale sitplekke 1A total seats L2  A (b) = 10 + 16 × 5 + 19 + 21 = 130 Ratio/Verhouding = 4 : 130  MCA 1MCA ratio in correct order = 2 : 65  CA 1CA simplification OR/OF OR/OF Total seats/Totale sitplekke 1A total seats  A = 64 + 66 (vacant) = 130 Ratio/Verhouding = 4 : 130  MCA 1MCA ratio in correct order = 2 : 65  CA 1CA simplification (3) CA Q4.1.2 total seats MP 4.1.3 Total vacant seats/Totale oop sitplekke = 66  A 1A total vacant seats L3 Percentage income lost/Persentasie inkomste verloor 66 1MCA percentage =  100%  MCA calculation 130 = 50,76923077  50,77 %  CA 1CA simplification OR/OF OR/OF Percentage income from occupied seats Persentasie inkomste van hierdie sitplekke 64 1CA % occupied seats =  100% ≈ 49,23%  CA 1MCA subtracting from 130  MCA 100% Income lost/Verlore inkomste = 100% – 49,23% 1CA simplification = 50,77%  CA NPR (3) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 14 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T/L  O MP 4.2.1 To allow air inside the tank to escape as the L4 diesel is pumped in OR Release air bubbles formed OR To let air in OR To 2O reason protect the tank from exploding or imploding Om lug wat in die tenk is,uittelaat terwyl diesel ingepomp word OF Lugborrels vry te laat OF Om lug in te laat OF Om te keer dat die tenk ontplof of inplof. (2) M 4.2.2(a) Inner diameter/Binne-middellyn L2 A 1A subtracting double the 5 thickness = 3,22 m – 2× m C 1C converting to m 1 000 = 3,21 m OR/OF OR/OF A C 1A subtracting double the 5 mm + 5 mm = m = 0,01 m thickness Inner Diameter = 3,22 – 0,01 m 1C converting to m = 3,21 m (2) 4.2.2 (b) Inner height/Binne hoogte M  MA 1MA subtracting double the L3 5 thickness = 7,25 m – 2× m 1 000 1CA simplification = 7,24 m  CA  MCA 1MCA finding radius 3,21 2 Volume = 3,142 × ( ) × 7,24 SF 1SF correct values 2 = 3,142 × (1,605) 2 × 7,24 = 58,599622782 m3.  CA 1CA simplification Filling volume/Opvul volume  MCA 1MCA percentage finding = 58,599622782 m3 × 95% = 55,6696416429 m3  CA 1CA capacity Number of litres/Hoeveelheid liter = 1 000 × 55,6696416429 m3 = 55 669,64 ℓ  C 1C to litres (8) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 15 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L  MCA  SF CA from Q4.2.2 M 4.2.3 SA/BO = 2 × 3,142 × (1,61) × (1,61 + 7,25) 1MCA correct radius L4 1SF substitution ≈ 89,64 m2  S 1S simplification Total area to be painted/Totale oppervlakte om te verf = 89,64 m2 – 1 m2  MCA 1MCA subtracting 1 m2 = 88,64 m2 . CA 1CA simplification  MCA Litres needed/Liter nodig = 88,64 ÷ 3 1MCA dividing by 3 = 29,55  CA 1CA simplification Valid O 1O verification OR/OF OR/OF A  SF 1A correct radius SA/BO = 2 × 3,142 × (1,61) × (1,61 + 7,25) 1SF substitution ≈ 89,64 m2 1S simplification S Surface Area = 89,64 m2 – 1 m2  MCA 1MCA subtracting 1 m2 = 88,64 m2 CA 1CA simplification Area that can be covered by 30 ℓ /Opp wat met 30 ℓ geverf word  MA 1MA multiplying by 3 30 litres 3 = 90 m2 CA 1CA simplification Less is needed/ Minder word benodig  O 1O verification (8) [30] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 16 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne QUESTION/VRAAG 5 [28 MARKS/PUNTE] Q/V Solution/Oplossing Explanation/Verduideliking T&L  RT MP 5.1.1 Front view OR Back view OR Rear view 2RT view L1 (2) Vooraansig OF Agteraansig M 5.1.2 Width of the bakkie/Bakkie se breedte = 1,86 m  C 1C conversion L2 2D = 3,6 m – 1,86 m = 1,74 m  MA 1MA difference 1,74 D= m  MCA 1MCA dividing by 2 2 = 0,87 m  CA 1CA simplification OR/OF OR/OF C  Width of the garage/Motorhuis se breedte = 3 600 mm 1C conversion 2D = 3 600 mm – 1 860 mm = 1 740 mm  MA 1MA difference 1 740 D= mm  MCA 1MCA dividing by 2 2 = 870 mm  CA 1CA simplification (4) P 5.1.3 Number of choices/Getal keuses = 4 × 2  MA 1MA multiplying L2 =8  CA 1CA number of choices. (2) MP 5.2.1 A map is drawn to scale while a strip chart is not. A L1 'n Kaart word volgens skaal geteken terwyl 'n strook kaart nie. OR/OF 2A statement A map shows the routes in a winding manner while a stip chart shows them as straight lines. 'n Kaart toon die kronkelende roetes terwyl die strook kaart dit in reguitlyne wys. (2) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 17 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L MP *5.2.2 Distance/Afstand (Springbok to/na Gobabis) L2  RT  RT 1RT correct 892 = 892 km + 203 km 1RT adding = 1 095 km  CA 1CA distance in km (3) MP 5.2.3 Noordoewer RT 2RT correct town L2 (2) 5.2.4 Distance Mariental to Keetmanshoop MP (a) Afstand van Mariental na Keetmanshoop L2  RT 1RT distances = 644 – 427 = 217 km A 1A simplification Total distance travelled/Totale afstand afgelê = 140 km + 289 km + 217 km = 646 km.  CA 1CA distance OR/OF OR/OF Distance/ Afstand  RT = 140 km + 289 km + (465 km – 248 km) 1RT distances = 140 km + 289 km + 217 km  A 1A simplification = 646 km  CA 1CA distance (3) Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 18 DBE/2022 SC/NSC/SS/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L  SF S 1SF substitution 5.2.4 Time/Tyd 1 = 140 km ÷ 80 km/h = 1,75 hrs 1S simplification M (b) Time /Tyd 2 = 289 km ÷ 80 km/h = 3,6125 hrs  S 1S simplification L4 Time/Tyd 3 = 217 km ÷ 120 km/h = 1,808333333 hrs S 1S simplification Stoppage time = 3 × 25 min = 75 min = 1,25 hrs  S 1S simplification Travelling time including breaks 1MCA adding time = 1,75 + 3,6125 + 1,808333333 + 1,25  MCA 1CA simplification = 8,420833333 hrs CA 1C converting time = 8 h 25  C Travelling time = 12:25 – 04:00  MA 1MA subtracting = 8 h 25  A 1A total travelling time Letitia’s statement is CORRECT/KORREK  O 1O opinion OR/OF OR/OF Total time taken/Totale tydsduur = 12:25 – 4:00  MA 1MA subtracting = 8 h 25 min A 1A total travelling time Driving time on gravel road/Bestuurstyd op grondpad S 1S total distance 429 km  SF = 1SF substitution 80 km/h = 5,3625 h S 1S simplification Driving time on tarred road/Bestuurstyd op teerpad 217 km = 120 km/h = 1,808333h  S 1S simplification Total time/Totale tyd = 5,3265 h + 1,808 hr = 7,170833… hours/uur  CA 1CA simplification time = 7 hours + 0,17083333 × 60 = 7 h 10 min C 1C converting time  Total break time/Totale rustyd = 8 h 25 min – 7 h 10 min = 1 h 15 min  CA 1CA simplification Duration of OR/ Each break/ breaks/Rustye se duur OF Elke rustyd = 3 × 25 min 1h15 min = 75 min = A 3 1A break time = 1h 15 min = 25 min Letitia is CORRECT/KORREK  O 1O opinion OR/OF OR/OF Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 19 DBE/2022 NSC/NSS – Marking Guidelines/Nasienriglyne Q/V Solution/Oplossing Explanation/Verduideliking T&L  SF S 1SF substitution Time/Tyd 1 = 140 km ÷ 80 km/h = 1h 45 min 1S simplification Time /Tyd 2 = 289 km ÷ 80 km/h = 3h 36 min  S 1S simplification Time/Tyd 3 = 217 km ÷ 120 km/h = 1h 48 min S 1S simplification Travelling time/Reis tyd = 1h 45 min + 3h 36 min + 1h 48 min  MCA 1MCA adding time = 7 h 9 min CA 1CA simplification  MA Travelling time /Reis tyd = 12:25 – 04:00 1MA subtracting = 8 h 25 min A 1A traveling time  Total break time/Totale rustyd 1CA simplification = 8 h 25 min – 7 h 9 min = 1 h 16 min  CA Each break/Elke rustyd 1h16 min = 3 ≈ 25 mins S 1S break time Letitia’s statement is CORRECT/KORREK  O 1O opinion DRAFT (11) [29] Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 20 DBE/2022 NSC/NSS – Marking Guidelines/Nasienriglyne NOTES: MATHEMATICAL LITERACY PAPER 2 Level 4 Questions: Calculations must be evident to award the conclusion/opinion mark. When rounding it must be correctly rounded to a minimum of 2 decimal places unless stated otherwise. On higher order (i.e level three to four multi-step calculations) questions no penalty for correct early rounding. QUESTION 1 1.1.4 Accept: B 1.1.5 Accept: E or B 1.2.2 Accept cubic centimeters (i.e. cm3) / Kubieke centimeter 1.2.4 CA only apply if 1 value is correct. That is, either 2 100 or 70 must have been used in a fraction for a max. 2 marks, on condition it is correctly simplified. 1.3.5 Accept, for full marks description:  Ten past two in the afternoon. /Tien oor twee in die namiddag.  Ten past two post meridian. / Tien oor twee meridiaan  Ten past two pm / Tien oor twee nm QUESTION 2 2.2.2 Accept East of South 2.2.3 Accept one of the following street names for full marks:  King.  Pioneer. QUESTION 3 3.2.1 Candidates need not show (20 + 12)m2 3.2.2 Full marks can be awarded for this solution: Lounge: Length = 4m ÷ 0,35 DRAFT = 11,428 ≈ 12 Width = 5m ÷ 0,35 = 14,285 = 15 ⸫ Total tiles = 12 × 15 = 180 tiles Dining: Length = 4m ÷ 0,35 = 11,428 ≈ 12 Width = 3 ÷ 0,35 = 8,571 ≈9 ⸫ Total tiles = 11 × 9 = 108 tiles Hence, total tiles needed = 180 + 108 = 288 Number to add = 288 × 1,1 = 316,8 ≈ 317 ⸫ Number of boxes = 317 ÷ 4 = 79,25 ≈ 80 boxes Copyright reserved/Kopieregvoorbehou Please turn over/Blaai om asseblief

Downloaded from hlayiso.com Mathematical Literacy/P2/WiskundigeGeletterdheid/V2 21 DBE/2022 NSC/NSS – Marking Guidelines/Nasienriglyne QUESTION 4 4.1.1 Accept:  East / Oos or E / O 4.1.2 Accept, for full marks ratio given as: (b)  4:130 or However, if given 4:incorrect 2ndpart. Did not show how incorrect 2nd part was obtained can get max. 2 marks provided it is simplified correctly. Accept answer simplified into unit ratio. QUESTION 5 5.2.2 CA considered only if adding distance from strip chart other than 203km, then (max 2 marks). DRAFT Copyright reserved/Kopieregvoorbehou