EDUCATION
REPUBLIC OF SOUTH AFRICA
PREPARATORY EXAMINATION
2025
MARKING GUIDELINES
MATHEMATICAL LITERACY (PAPER 1) (10601)
10 pages
CODES EXPLANATION
M Method
MA Method with accuracy
CA Consistent accuracy
A Accuracy
Cc Conversion
D Define
J Justification/Reason/Explain
S Simplification
RT/RD/RG/RS Reading from a table/ graph/diagram/map/plan/source
EF Choosing the correct formula
SF Correct substitution in a formula
oO Opinion
P Penalty, e.g. for no units, incorrect rounding-off, etc.
R Rounding-off
NP No penalty for omitting units
NPR No penalty for rounding-off
KEY TO TOPIC SYMBOLS:
F = Finance; DH = Data Handling ; P = Probability
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Maths LIT Grade 12 NSC P1 MEMO September 2025 Gauteng
Mathematical Literacy · Grade 12 · Gauteng Mock Exam · 2025. Memorandum, 11 pages. Read online or download the PDF.
- Subject
- Mathematical Literacy
- Grade
- Grade 12
- Document type
- Memorandum
- Year
- 2025
- Exam period
- Gauteng Mock Exam
- Paper
- 1
- Pages
- 11
- File size
- 2.2 MB
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10601/25
QUESTION 1 ANSWER ONLY FULL MARKS (30 marks)
Q Answer Explanation Topic | Mark
Level
Ll Lidl DYVA 2 A correct answer Fl
Accept exchange rate 2
1.1.2 FYVA 2 A correct answer Fl
Accept tariff 2
1.1.3 EVYA 2 A correct answer Fl
Accept Value Added
Tax 2
1.1.4 GYVA 2 A correct answer Fl
Accept credit 2
L138 BYYA 2 A correct answer Fl
Accept inflation 2
12 L2.1 Western Cape YY RT 2 RT correct Province DHI1 2
1.2.2 Thirteen million and twenty-three 2 A correct answer DHI
thousand eight hundred and thirty three.
VV A 2
1.2.3 13 195 793 — (5 070 287 + 1 773 639+ | 1 MA subtracting all DH1
2 155 489 + 647 154+ 933 276+ correct values
667 632 + 792 815 +295 238) ¥MA 1A correct answer
= 860 263 YA 2
1.2.4 | 647154 Yer 199 ¥MA 1 RT correct values DHI
13 195 793 x
=4.904% VA 1MA percentage
1 A correct answer
NPR 3
12.8 667 632 — 295 238 WRT YMA 1 RT correct values DH1
= 372394 VA 1 MA subtracting correct
values
1A correct answer
Accept -372 394 3
1.2.6 Gauteng Province ¥™“RT 2 RT correct answer DHI
Accept GP 2
10601/25
i3 13,1 Property rates VV RT 2 RT correct answer Fl 2
L322 C=R24,21 +R14,27 YMA IMA adding/ Fl
=R38,48 VA subtracting the correct
OR values
C = 600,03 — 561,55V™ MA 1A correct answer
= 38,48V MA NPR
OR
C= 561,55 — 305 = 256,55 x 15% VWMA
= R38,48Y MA 2
1.33 R219,70 + R561,55 Y~RT YMA IRT both values Fl
=R781,25 IMA
adding/subtracting
OR correct values
R819,73 - R38,48Y RT YMA
= R781,25
2
[30]
QUESTION 2 (29 marks)
Q Answer Explanation Topic Mark
Level
BI DeV.1 R 800+ R100 YMA=R900V A i MA adding correct FI
values
1A correct answer
AO 2:
2.1.2 5 x 270 ¥ RTY MA = R1350 I RT for R270 F2
_ | MA multiplying
OR _ correct values
R1 080 + R270Y RT Y MA=RI 350 | 1 RT for R270
i MA adding correct
values, | :
2.1.3 2160 yRT VMA=8VCA ! RT correct values re
70 i MA dividing correct
values
om 1 CA answer
— v =
0 900 +, 720 1 RT correct values
30 MA =8VCA 1 MA dividing correct
values
OR 1 CA answer
270 x 8VRT YMA =2 160YCA 1 RT correct values
1 MA multiplying
correct values
1 CA answer 3
10601/25
2.1.4(a) | (5; 1350) WRT WA 1 RT correct values Fl
1A correct order 2
(b) |6V%VA 2 A correct answer Fl 2
25 Total expenses CA fixed cost from F2
=R 900 YA + 90 (n) ¥ MA 2.1.1
1 A for R900
1 MA for adding
variable cost 2
10601/25
2.1.6 | Income = 100 x R270 ¥ MA CA from 2.1.5 F3
= R27 000 YA (Expenses)
1 MA multiplying correct
Expenses = R 900 + 90 (100) “MCA values
=R9 900 YCA 1A correct answer
1 MCA adding fixed and
Profit = R27 000 — R9 900 ~MCA variable expenses
=RI7 100 YCA together
1CA correct answer
OR 1 MCA subtracting
expenses from income
R270 - R90 YMA =RI80 VA 1 CA answer
«100 x R180 ¥ MCA =R18 000 YCA
Profit = R18 000 —R 900 Y™MCA
=RI17 100 YCA
6
2.2 | 2.2.1] 1" year: 1 MA increasing the F3
12% + 100% = 112% YMA= 1.12 YS percentage
1,12 XR60 000 YM=R 67 200 VA 1S simplification
1M multiplying correct
6 months : =
% — v correct answer
— 6% YA 1A percentage
6% + 100% = 106% = 1,06 VA 1A increased percentage
1,06 x R67 200 Y MCA 1 MCA multiplying
ae of correct values
R71 232 ¥ CA 1 CA answer
OR
1* year :
12% + 100% = 112% YMA= 1.12 YS
6 months :
12% = 6% VA
2
6% + 100% = 106% = 1,06 YA
R60 000 x¥M 1.12 YAx 1.06” MCA
= R71 232YCA
8
2.2.2 | R 71 232 - R60 000YMA = R 11 232 CA from Q2.2.1 F2
VA 1MA subtracting correct
values
1A correct answer 2
[29]
10601/25
QUESTION 3 (28 marks)
Q Answer Explanation Topic | Mark
Level
a1 3.1.1 | 0,741 x 1.000 000 Y™MA IMA multiply by DH2
= 741 000 VA 1000 000
1A correct answer
AO 2
| 3.1.2 | Northern Cape ~“ A 2A correct answer DHI1
2
3.4.3 | Increases ¥ A 1A correct answer DH4
Pass rate of 2024 is higher than 2023 2J reasoning
across all provinces ¥ WJ
OR
All provinces improved VA
from 2023 to 2024. ¥vJ 3
3.1.4 | Discrete WA 1A correct choice DH2
It can be counted VJ 1 J reasoning 2
3.1.5 | Range = Max value — Min value 1 SF correct values DH3
14,3 = 89,7 — S WSF 1S simplification/changing
S=89,7- 143 VS the subject of the formula
=754VA 1A correct answer
3
3.1.6 | Mean = net east YMA IMA mean concept DH3
? 1 S simplification
1MCA changing subject of
600,3+27
85,5 = vs formula
769,5 MA = 600,3 +2 T 1S value of 2 T
769,5 — 600,3 = 2 T YMCA 1 CA answer
2T=169,2 VS
T= 84,6 VCA
5
32 3.2.1 | 1060: 15657 Y¥RT VA 1 RT correct values DH2
1:1477VS 1A correct order
1S answer in unit form
NPR 3
3.2.2 | 783; 824; 837; 865; 911; 926; 946; 1 060; | 2A correct order DH2
1095; 1161Y¥VA
2
10601/25
3.2.3 | Median | CA (arrangement) from DH3
21926 YMA =9IRS YA Q 3.2.2
IMA median concept
1A correct median
= v
QI = BBVA 1A correct Q1
Q3= 1060 “A 1A correct Q3
Min 783A 1A correct min
Max =1 161 “A 1A correct max 5
aca ecneneeseincNanNnE 2 aa
QUESTION 4 (28 marks)
Q Answer Explanation Topic | Mark
Level
4.1 |4.1.1 | R17235+R9 444 YMA=R26679 VA _ | 1 MA adding correct Fl
values
1A correct answer
AO 2
4.1.2 | 2680000 Yt A = R56 666,67 VA 1 MA for monthly gross | F2
Gross wiles 1A correct answer
= R680 000 + R56 666,67 YMCA ee edting banus
= R736 666,67 VCA sea
OR i MA for monthly gross
1A correct answer
R680 000
YMA = R56 666,67 VA 1 MCA multiplying by
13,
Gross salary = R56 666,67 x 13 YMCA_ | | CA answer
= R736 666,71 YCA 4
4.13 | 3° x R680 000 YMA 1 MA multiplying correct | F4
200: values
= R204 000 VCA iG@ARERE
ee 1J identify in maximum
Only R100 000 is tax deductiblevJ ying 3
4.1.4 | R736 666,67 — R100 000 YRT YM CA from 4.1.2 and 4.1.3 | F2
R636 666,67 YCA 1 RT correct values
IM subtracting donation
OR 1 CA answer
R736 666,71 — R100 000 Y¥RT YM
R636 666,71 ¥CA 3
4.1.5 Bracket 4/4"" Bracket ¥™Y RT CA from 4.1.4 Fl
(Accept rate of tax) 2 RT correct bracket 2
10601/25
4.1.6 18% of taxable income WA 1A correct bracket F4
18% x 95 750 VMA 1 MA multiplying correct
= 17 235 V CA —Rebate values
=17 235 —17 235 YMCA 1 CA answer
=0VCA 1 MCA subtract rebates
«. The claim is valid ¥O 1 CA answer
1 O conclusion
OR
17 235+ 18% VAYMA = R95 750Y CA
R95 750 — R95 750“ MCA
=0YCA
:. The claim is valid ¥O
6
4.2 4.2.1 3 A correct answers P2
(i) CVA
(ii) MYA
(iii) CS VA 3
422 S IVRT= 0,66666 “CA 1 RT numerator p2
5 O7 VR 1 RT denominator
, 1CA answer
IR to one decimal place 4
42.3 |e To cater for different preferences 2 O correct reason P4
VvVO
OR
e Cater for people who might have
allergies ¥YO
(Accept any sensible/logical answer) 2
[29]
10601/25
QUESTION 5 (34 marks)
Q Answer Explanation Topic Mark
Level
5.1 5.1.1 | Car¥ IRT car DH4
50% of the drivers are generating 20 justification
more than R 1 000 ¥VWJ 3
5,12 25 VRT x 300 YMA 1 RT 25% DH2
100 2. *
=75VCA 1 MA multiplying correct
values
OR 1 CA answer
= VRT x 300¥ MA = 225
«300 — 225 =75 ¥ 3
5.1.3 | 100% + 20% = 120%VA 1A for 120% DH3
100 YM x R1 600 Y™MA 1M for correct fraction
120 Pee
= R1 333,33 YCA 1MA multiplying by R1 600
1 CA answer
OR
100% + 20% = 120%”YA
120 _
aan ¥M=1,2
1600 YMA
1,20
= 1 333,33VCA
4
5.1.4 | IQR=Q3- Qi VF F correct formula DH2
= 1200 — 400 VRT RT both values
= 800 YCA 1 CA answer
(Accept range for Q3:
1 200-1 220) 3
5.2 S2el ZAR VA 1 A correct answer F4
« because you get more rupees 2 O for justification
when you exchange ¥ “WO
OR
e 1-Indian rupee exchanges for
less than a | rand 3
10601/25
522
R30 000 %
x 1 Indian rupee YC
RO.21
142 857,1429 vS — 3000 YMCA
139 857.1429
=————= YMCA
12.000
= 11.6547619 YCA
x 11VR
It won't be enough. VJ
OR
Shipping
3 000 x 0,21“ C = R630¥S
Cost of 12 bikes:
12 000 x 0,21“ MCA x 12“ MCA
= R30 240
Total costs:
R630 + R30 240“M
= R30 870YCA
R30 000 will not be enough, there will
be a shortfall of R870. WJ
OR
1 Indian Rupees = 0,21 ZAR
Number of Indian rupees
_ R30000
0,21
142 857,1429 vS
Indian Rupees — 3000
YMCA YMCA
139 857,1429 — (12 x 12 000)
139 857,1429 — 144 000YM
v¥CA
= —4142,8571 Indian rupees
«. It will not be enoughvJ
¥G
1 C conversion
1S simplification
1MCA subtracting 3 000
IMCA dividing by 12 000
1 CA answer
1R rounding down
1 J conclusion
F4
523
¢ Convenience ¥YO
e Time saving VVO
e Reduces travelling cost
(Accept any sensible/logical answer)
2 O answer
2 O answer
F4
10
10601/25
5.3
Cost of 1 kg = R270 +4 YMA
= R67.50 VA
Cost in cents = R67.50 x 100 YC
= 6750 cents VA
Percentage Increase:
£76176 750 VSFVSF x 100
6750
= 0,162% VCA
OR
6761 +100 VC
= R67,61VA x 4kg YMA
= R270,44VA
_ 27044 — 27000 JOSE & TOL
~ 27 000
= 0,162962963% VCA
OR
270 x 100VYC
= 27 000 cents VA
6761 x 4VMA
= 27 044 cents VA
= 27 044-27 000 x 100 “SEY SF
27000
= 0,162962963% YCA
1 MA dividing by 4
1A correct answer
1C conversion
1A correct answer
1SF substitution numerator
1SF denominator
1 CA answer
NPR
FS)
[34]
150
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