Maths Lit P1 Gr12 Memo June 2018 English hlayiso.com

Downloaded from hlayiso.com . NATIONAL SENIOR CERTIFICATE GRADE 12 JUNE 2018 MATHEMATICAL LITERACY P1 MARKING GUIDELINE MARKS: 100 SYMBOL EXPLANATION A Accuracy CA Consistent accuracy C Conversion J Justification (Reason/Opinion) M Method MA Method with accuracy P Penalty for no units, incorrect rounding off, etc. R Rounding off RT/RG/RP Reading from a table/Reading from a graph/Reading from a plan/Reading from a RM/RD map/Reading from a diagram S Simplification SF Correct substitution in a formula O Own opinion NPR No penalty for rounding This marking guideline consists of 8 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P1 (EC/JUNE 2018) QUESTION 1 [20 marks] Explanation Marks 1.1.1 Cost for deposit = 1,50 + 0,25 × 2 000  = 1,5 + 5 MA 1 MA (0,25% L1 100 of 2 000) 1CA = R6,50 CA (2) 1.1.2 Minimum = R2,00  2 RT L1 (2) 1.2.1 A= 231,70 – (23,45 + 90 + 23 + 45)  MA 1 MA L1 = 50,25 CA Subtracting values from 231,70 1 CA Value of A (2) 1.2.2 Cost of total data used = 231,7 × 149  MA 1 MA Total L1 1 000 data as a = R34,52 CA fraction of OR 149 1GB × 149 Cost of total data used = × 231,7  MA 1 CA Cost 1 000 = R34,52 CA NPR (2) 1.3.1 Seat 20B  RT 2 RT Seat L1 number (2) 1.3.2 Time for the flight = 13:30 – 12:05 MA 1 MA L1 = 1hr 25 min A Subtracting the times 1A 1 : 25 is incorrect (2) 1.4.1 Bar scale / Graphic scaleA 2 A for any L1 Linear scale  A two scales Word scale A given Fractional or ratio scale A (2) 1.4.2 For every one unit on a drawing or on a map there are 2A L1 400 000 units in reality  A Explanation (2) 1.5.1 Others 1 MA L1 = 2 100 000 - (503 096 + 439 719 + 221 121 + 219 007) MA Subtracting = 717 057  CA the total from 2,1 million 1 CA (2) 1.5.2 Health % of the total= 221 121 × 100  MA 1 MA L1 2 100 000 Fraction of = 10,53% CA correct values × 100% 1 CA NPR (2) [20] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2018) MATHEMATICAL LITERACY P1 3 QUESTION 2 [27 marks] Explanation Marks 2.1 369,50 − 343 1 SF L2 Inflation Rate = × 100  SF 343 26,50 1S = 343 × 100 S 1 CA = 7,73%  CA NPR (3) 2.2.1 25 750 1 A Correct L2 Original Salary = 1,085 MA value 25 750 1 M divided by = R23 732,72  CA 1,085 1 CA (3) 2.2.2 Annual Salary = 25 750 ×12  MA 1 MA L1 = R309 000 A Multiplication of correct values 1 CA (2) 2.3.1 2 500 1 MA Division L1 D=  MA = 50 tickets A 50 of correct values 1 CA (2) 2.3.2 Cost of renting = R3 600  Reading from L1 given information 2A (2) Copyright reserved Please turn over

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P1 (EC/JUNE 2018) 2.3.3 1 A 1st point L2 1 A Line drawn (2) 2.3.4 From graph = Expense line above income 2 RG L3 = Difference R600  RG = Loss  O 1O OR Difference = Income ‒ expense 1M = (60 x 50) ‒ 3600  M Subtraction of expense = -600  S from income correct = Loss  O value 1S 1O (3) 2.3.5 Break-even is the point where cost of renting equals income 2 A L1  A (J) Explanation OR No loss and no profit (2) 2.4 Rent with VAT = 3 600 1 MA Divide by 1,15 L3 3 600 1 M Subtraction Rent without VAT = 1.15 = 𝑅3 130,43  M 1 CA VAT = 3 600 ‒ 3 130,43  M = R469,57  CA 1 MA Fraction OR 15 1 M Multiplication VAT = 115 MA × 3600 M 1 CA = R469,57 CA (3) Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2018) MATHEMATICAL LITERACY P1 5 2.5.1 R1 = 0,46406 CYN 1 MA Division L2 ? = 1 250 using correct 1 250 values ? = 0,46406  MA = R2 693,62  A 1A (2) 2.5.2 Total parts 2 + 3 = 5  MA 1 MA value of 5 L2 2694 1S Value of each part = 5 = R538,80  S 1 CA Wife has one part more; she got R538,80  CA more OR Total parts = 5  MA 3 1 MA value of 5 Wife got = 5 × 2 694 = 𝑅1 616,40 1 Subtraction 2 Husband got = 5 × 2 694 = 𝑅1 077,60 1 CA Wife got 1 616, 40 - 1 077,60  MA = R538,80  CA more OR Total parts 2 + 3 = 5 MA (Allow if 1250 calculated in Value of each part = 5 = CYN 250  S Chinese Yuan) Wife has one part more; she got CYN 250  CA more 1 MA value of 5 1S 1 CA (3) [27] Copyright reserved Please turn over

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P1 (EC/JUNE 2018) QUESTION 3 [16 marks] Explanation Marks 3.1 1,8 m  RD 2 RD L1 OR 3,6 1 M Divide by 2 Radius = 2  M 1A (2) = 1,8 m A 3.2 C = 𝜋𝑟 1 SF L2 C = 3,142 x 1,8 m  1 CA from 3.1 = 5,66 m  OR 1 SF C = 3,142 x (3,6 m) ÷ 2  1 CA = 5,66 m  NPR (2) 3.3 A + A + A + 0,4 m +1,1 m + 1,75 m = 5,8 M  1 M Addition L1 3A + 3,25 m = 5,8 m 1S 3A = 5,8 m – 3,25 m  S 1 M/A Division 3A = 2,55 m M/A 1 CA 3 3 A = 0,85 m  CA (4) 2 3.4 TA= 𝜋r + (length x breadth) x 2 CA from 3.1 L2 = 3,142 x 1,82 + (5,8 m x 4,9 m) x2  2 SF = 10,18008 m2 + 28,42 m2 x 2  = 10,18008 m2 + 56,84 m2 1S = 67,02 m2  1 CA = 67 m2  1 Rounding off (5) 3.5 5,8 m + 1,8 m 1 M Adding L2 = 7,6 m  x 2  (Value 7,6 m) = 15,2 m  1M (Multiplication by 2) 1 CA (3) [16] Copyright reserved Please turn over

Downloaded from hlayiso.com (EC/JUNE 2018) MATHEMATICAL LITERACY P1 7 QUESTION 4 [11 marks] Explanation Marks 4.1 16  RD 2 RD L1 (2) 4.2 (a) AA = 48 A 2 A Number L1 (2) (b) BB = 65 A 2 A Number L1 (2) 4.3 Q 5  RD 2 RD L1 Award 1 mark for 5Q (2) 4.4 Turn it over once in a clockwise direction in such a way that the left 3A L2 side is now the top side, the bottom side is now the left side and the Explanation top side is now the right-hand side.   (3) [11] Copyright reserved Please turn over

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P1 (EC/JUNE 2018) QUESTION 5 [26 marks] Explanation Marks 5.1.1 18  RM 2 A RM Total L1 number of data values (2) 5.1.2 Willowmore  RM 4 A RM L1 Port Elizabeth  RM (1 Mark for each East London  RM town or city) Aliwal North  RM (4) 5.1.3 14; 14; 15; 15; 15; 16; 16; 17; 17; 17; 17  RM 2 A RM L1 Arranged in ascending order (2) 5.1.4 16  CA 2 CA From 5.1.3 L2 Median (2) 5.1.5 𝑄1 = 15  A and 𝑄3 = 17 A 2 MA for 𝑄1 and L2 Interquartile range = 17 ‒ 15  1 M 𝑄3 = 2  CA 1 M subtraction 1 CA (4) 5.1.6 Mean = 16+18+21+22+27+28+28 = 160  MA 2 MA For L2 7 7 addition and division = 22,86 1 CA = 23  A NPR (3) 5.1.7 28  RM 2 RM L2 (2) 5.1.8 Difference = 28 ‒ 17 MA 1 MA L1 = 11  CA Subtraction 1 CA (2) 5.2.1 Probability is the chances of an event to happen  2A L1 Explanation (2) 5.2.2 P (City or town with temperature less than 170° 𝐶) 1 A for 8 the L2 8 4 numerator =  = 1 CA From 18 9 5.1.1 1A NPR (3) [26] TOTAL: 100 Copyright reserved Please turn over