Mlit P2 Memo Eng 2013 hlayiso.com

Downloaded from hlayiso.com Province of the EASTERN CAPE EDUCATION NATIONAL SENIOR CERTIFICATE GRADE 12 SEPTEMBER 2013 MATHEMATICAL LITERACY P2 MEMORANDUM MARKS: 150 Symbol Explanation M Method MA Method with accuracy CA Consistent accuracy A Accuracy/Answer C Conversion S Simplification RT/RG/RM Reading from a table/Reading from a graph/Read from map F Choosing the correct formula SF Substitution in a formula J/O Justification/Opinion P Penalty, e.g. for no units, incorrect rounding off etc. R Rounding Off/Reason This memorandum consists of 10 pages.

Downloaded from hlayiso.com 2 MATHEMATICAL LITERACY P2 (SEPTEMBER 2013) QUESTION 1 Question Solution 1.1 1.1.1 Deposit = 392 900 x 0,15  2:M = R58 935  1:A (3) 1.1.2 % used = x  1:M = 14,73%  1:A (2) 1.1.3 P = 400 000 – 58 935 = R341 065  i = 8,75 / 2 = 4,375 / 100 1: M Finding P = 0,04375  n=6x2 1:M Finding i = 12  1: M Finding n A = P (1 + i)n = 341 065 (1 + 0,04375)12  1:SF = 341 065 (1,04375)12 = 341 065 (1,67169815)  1:S = 570 157,7296 = R570 157,73  1:CA (6) 1.1.4 P = 392 900 – 58 935 = R333 965  i = 8,5% + 1% = 9,5 / 100 1: M Finding P = 0,095  1: M Finding i A = P (1 + ni) = 333 965 (1 + 6 x 0,095)  1:SF = 333 965 (1,57)  1:S = R524 325, 05  1:CA (5) 1.1.5 Interest paid = 524 325,05 – 333 965 = R190 360,05  1: M Find interest amount % = 190 360,05 x 100  1:M 524 325,05 1 = 36,3%  Accept 36,31% 1:A Yes, interest paid is less than 40%.  1:O (4) 1.1.6 Monthly payment = 524 325,05  72 = 7 282,29  1:M Service and admin fee = R7 391,29 – 7 1:M 282,29 = R109,00  1:A (3)

Downloaded from hlayiso.com (SEPTEMBER 2013) MATHEMATICAL LITERACY P2 3 1.2 1.2.1 P  = 15n  – 50  OR Profit = 15 x no. of passengers – R 50  A:3 (3) 1.2.2 (A) P = 15n – 50 = 15(2) – 50  1:SF = 30 – 50 = -R20 (loss)  1:A (B) P = 15n – 50 70 = 15n – 50  1:SF 120 = 15n 8= n 1:A (4) 1.2.3 Less than 4 passengers  OR n < 4  OR No profit will be made for less than 4 passengers.  2:A (2) 1.2.4 No. of trips = 8 / 0,5  OR No. of trips = 8 x 60 = 16  = 480 / 30 = 16 1:M 1:A Profit per day = 14 x 15 x 16 – 50 x 16  1:M = 3 360 – 800  1:S = R2 560  1:A (5) [37] QUESTION 2 2.1 2.1.1 C1  and D1  OR 1C  and 1D  2:A (2) 2.1.2 South west  1:A (1) 2.1.3 2 cm = 500 m OR 2 cm : 500 m  1:C 20 mm  = 500 000 mm  2 cm = 50 000 cm  1:C 1 : 25 000  1 : 25 000  1:A (3) 2.1.4 Scale of map = 1 : 25 000 Map distance = 7,6 cm  (Accept 7,4 cm – 7,8 cm) 1:A length Distance in km = 7,6 x 25 000  = 190 000 1:M 100 000 100 000 = 1,9 km  1:A (Accept 1,85 – 1,95 km) (3)

Downloaded from hlayiso.com 4 MATHEMATICAL LITERACY P2 (SEPTEMBER 2013) 2.1.5 Time = Distance Speed = 1,9 km  1,5 km/h  = 1,266... h x 60  2:M = 76 min  1:C (Accept 74 min – 78 min) 1:A (4) 2.2 2.2.1 80% of staff = 3 327 + 773 + 1 246 + 1 526  1:M = 6 872  1:A Total staff members = 6 872  1:M 80% = 6 872  1:CA 0,8 = 8 590  1:CA OR 20% of staff = 6 872  4 = 1 718  Total staff members = 6 872 + 1 718 = 8 590  (5) 2.2.2 (P of not approaching an administration clerk) = Total staff members – total administration clerks) Total staff members = 8 590 – 1 526  8 590 = 7 064 1:M 8 590  1:M = 0,822  OR 82,2%  1:CA (3) 2.2.3 Nurses = 3 327 x 360  OR 360 x 3 327  8 590 1 8 590 1 ≈ 139,4º ≈ 139,4º Doctors = 773 x 360  OR 360 x 773  8 590 1 8 590 1 ≈ 32,4º ≈ 32,4º Domestic = 1 246 x 360  OR 360 x 1 246  8 590 1 8 590 1 ≈ 52,2º ≈ 52,2º 5CA Clerks = 1 526 x 360  OR 360 x 1 526  Dividing 8 590 1 8 590 1 correct ≈ 64º ≈ 64º amounts and Others = 1 718 x 360  OR 360 x 1 718  multiplying 8 590 1 8 590 1 answer by ≈ 72º ≈ 72º 360

Downloaded from hlayiso.com (SEPTEMBER 2013) MATHEMATICAL LITERACY P2 5 1:M Label Staff at Leipoldt Hospital Other, 1718 graph 5CA Accurate division Nurses, 3327 of sections 1MA Administration, labelling 1526 each sector or providing a key Domestic, Doctors, 773 1246 (12) [33] QUESTION 3 3.1 3.1.1 Statement is true  1:A Entrant 3 meets the criteria for the height (1,55 m),  but not for the mass (44 kg) and the BMI (underweight)  OR Entrant 5 meets the criteria for the BMI (normal),  but not for the mass (52 kg) and the height (1,52 m)  OR Entrant 7 does not meet any of the criteria for the BMI (overweight),  mass (45 kg) and the height (1,30 m)  OR Entrant 8 meets the criteria for the height (1,55 m) and the mass (61 kg),  but not for the BMI (overweight)  OR Entrant 12 meets the criteria for the height (1,65 m) and the mass (72 kg),  but not for the BMI (overweight)  OR Entrant 14 meets the criteria for the height (1,55 m) and the mass (71 kg),  but not for the BMI (obese).  OR Entrant 15 meets the criteria for the mass (58 kg)  and the BMI (normal),  but not for the height (1,53 m).  1:J OR (height) Entrant 16 meets the criteria for the mass (55 kg)  and 1:J(mass) the BMI (normal),  but not for the height (1,51 m).  1:J(BMI) (4) 3.1.2 8 Entrants  2:A (2)

Downloaded from hlayiso.com 6 MATHEMATICAL LITERACY P2 (SEPTEMBER 2013) 3.1.3 Average (Mean) = 1,56+1,63+1,70+1,59+1,60+ 1,68+1,67+1,56  1:M 8 = 12,99  1:A 8 = 1,62375 = 1,62 m  1:A (3) 3.1.4 Median = 55 ; 56 ; 57 ; 60 ; 60 ; 61; 62 ; 70  1:M = 60 + 60  1:M 2 = 120 2 = 60 kg  1:A (3) 3.1.5 BMI = Mass in kg Height in m2 = 61 1:SF 1,552  = 45 1:S 2,4025  = 25,39021852  Accept 25,39 1:A A person with a BMI of 25 – 29,9 is classified as overweight.  1:O (4) 3.1.6 BMI = Mass in kg x Mass in pounds 1:M 2 Height in m Height in inches2  = 0,4536 x Mass in pounds 0,02542 Height in inches2  1:SF = 703,0814062 x Mass in pounds 1:C to Height in inches2  m ≈ 703 x Mass in pounds 1:S Height in inches2  1:A (5) 3.1.7  Unhealthy lifestyle  2:A  Incorrect eating habits  ONLY TWO (1  No exercises  mark (Accept any relevant answer.) each) (2) 3.1.8  Exercise  2:A  Follow a healthy diet  (1 (Accept any relevant answer.) mark each) (2)

Downloaded from hlayiso.com (SEPTEMBER 2013) MATHEMATICAL LITERACY P2 7 3.2 Soccer Gear T-shirts = [263,15 + (263,15 x 0,14)] x 17  OR = 263,15 x 17  = (263,15 + 36,84) x 17 = 4 473,55 x 1,14  = 299,99 x 17  = R5 099,85  = R5 099,83  Shorts = 149,99 x 17 1:M = R2 549,83  1:S Socks = 29,99 x 17 1:A = R509,83  Boots First 10 pairs = [350 – (350 x 0,1)] x 10  OR = 350 x 0,9 x10  1:MA = (350 – 35) x 10 = R3 150  = 315 x 10 = R3 150  1:MA Next 7 pairs = [350 – (350 x 0,15)] x 7  OR = 350 x 0,85 x 7  = (350 – 52,50) x 7 = R2 082, 50  1:M = 297,50 x 7 = R2 082,50  1:A Total = R5 099,83 + R2 549,83 + R509,83 + R3 150 + R2 082,50 = R13 391,99  1:M OR Total = R5 099,85 + R2 549,83 + R509, 83 + R3 150 + R2 082,50 = R13 392,01  1:A Payment for community hall 2 /3 x 450 = 300 x 5  = R 1 500  1:MA Profit = 300 x 35 1:M = 10 500  1:A No, she will not have enough money for the soccer gear. There is still a shortfall of R2 891,99 = R13 391,99 – R10 500.  1:MA OR R2 892,01 = R13 392,01 – 10 500 2:O (15) [40]

Downloaded from hlayiso.com 8 MATHEMATICAL LITERACY P2 (SEPTEMBER 2013) QUESTION 4 4.1 4.1.1 The area of 7 hectares OR 70 000 m2 to be cleaned.  1:A (1) 4.1.2 A = 70 000  1:M 50 = 1 400  1:A B = 70 000  1:M 350 = 200  1:A (4) 4.1.3 l = 70 000 s = 70 000 875  1:M = 80  1:A (2) 4.1.4 70 000 = s x l  OR 70 000  = sl  OR s = 70 000  l OR l = 70 000  s 3:A (3) 4.1.5 The number of learners.  1:A (1) 4.1.6 Number of square meters cleaned by each learner changes as the number of learner changes N u 700 m b 600 e r 500 o 400 f 300 l 4: Any 4 e 200 points a correctly r 100 plotted n 1: Smooth e 0 curve r 100 350 700 1400 1750 3500 s Number of square meters cleaned (5)

Downloaded from hlayiso.com (SEPTEMBER 2013) MATHEMATICAL LITERACY P2 9 4.2 4.2.1 There must be enough space to manoeuvre especially when the disabled person is also the driver of the vehicle.  (Accept any relevant answer.) 2:A (2) 4.2.2 Width of aisle = 0,4 x 2 500 mm 1:MA = 1 000 mm + 2 500 mm  1:M = 3 500 mm  1:A (3) 4.2.3 Area of standard parking bay = l x b = 5 000 mm x 2 500 mm = 12 500 000 mm2 1 000 000  1:C = 12,5 m2  1:A Area of disabled parking bay = l x b = 5 000 mm x 3 500 mm = 17 500 000 mm2 1 000 000 = 17,5 m2  1:A Difference = 17,5 m2 – 12,5 m2 = 5 m2  1:MA OR Area of standard parking bay = l x b = 5 m x 2,5 m  1:C = 12,5 m2  1:A Area of disabled parking bay = l x b = 5 m x 3,5 m = 17,5 m2  1:A Difference = 17,5 m2 – 12,5 m2 = 5 m2  1:MA (4) [25]

Downloaded from hlayiso.com 10 MATHEMATICAL LITERACY P2 (SEPTEMBER 2013) QUESTION 5 5.1 5.1.1 Area of rectangle = Length x Breadth 1 440 cm2 = length x 30 cm  Length = 1 440 cm2 30 cm 1:SF = 48 cm  1:A (2) 5.1.2 Diameter = 30 cm 5 = 6 cm  1:A (1) 5.1.3 Length = 48 / 6 =8 1:MA Breadth = 5 Number of circles = 8 x 5  1:M = 40  1:A (3) .1 5.1.4 Wasted pastry = Area of rectangle – (Area of circle x 40) = 1 440 cm2 – ( r2 x 40)  1:F = 1 440 cm2 – (3,14 x 32 x 40)  1:M = 1 440 cm2 – 1 130,40 cm2  1:S = 309,60 cm2  1:A (4) 5.2 10 dozen = 10 x 12 = 120  1:MA Mince filling = 120 x 0,75 = 90  1:A Chicken filling = 120 – 90 = 30  1:A P(Chicken Filling) = 30 x 29 120 119  1:M = 870 14 280 = 29 476  1:A (5) [15] TOTAL: 150

Downloaded from hlayiso.com